how would you go about designing a circuit with an applied voltage of 24v and a resistor of 1k ohms such that voltage starts out at 0v and reaches 24v in 2 seconds?

The purification of a wide range of materials involves the use of distillation, a significant commercial procedure.

The purification of a wide range of materials involves the use of distillation, a significant commercial procedure. However, it would definitely be helpful to clarify the terms that describe the procedure and related qualities before we start a discussion of distillation.

Although you may be familiar with several of these terms, you might not be aware of their precise definitions. Let's start by outlining the procedure for changing a material from its condensed phase to its gas phase. This process is known as sublimation for solids and vaporization for liquids. Both procedures call for heat.

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Answer:

4 balls

Explanation:

First, we find out how many tennis balls are there altogether.

There are 8 cans and each can has 3 tennis balls.

Total numberThese balls are shared with 6 players. So we divide the total quantity by 6 to find out how many tennis balls each player gets.

Each player = 24 ÷ 6 = 4

of balls = 8 x 3 = 24

The reason a prototype is necessary before committing to a purchase in this scenario is that the robot might be very expensive.

In Engineering, a prototype can be defined as a rudimentary (early) model, release, or sample of a particular product, so as to avail the developers and manufacturers an opportunity and ability to test a concept, functionality, or process within it.

This ultimately implies that, the main purpose of the prototype of a robot is to determine and show whether or not the robot and all of its features are in tandem with the design specifications and market requirements.

In this context, we can reasonably infer and logically deduce that the government requested for a full scale model of the robot before it would purchase one because it is most likely to be very expensive.

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Complete Question:

Tyler is developing a robot that can be sent into war zones to ensure that any mines have been detonated before soldiers are sent into the area. The government is requiring a full-scale model of this robot before it is willing to purchase one.

What explains why a prototype is necessary before committing to a purchase in the following scenario?

Here's an example code in C++ to declare a two-dimensional array of integers named "arr" with 3 rows and 10 columns:

int arr[3][10];

This will create a two-dimensional array with 3 rows and 10 columns, where each element is an integer. You can access or modify individual elements of the array using their row and column indices. For example, to assign the value 5 to the element in the second row and fourth column, you can use the following code:arr[1][3] = 5;

Note that in C++, arrays are indexed starting from 0, so the first row is indexed as 0, the second row as 1, and so on. Similarly, the first column is indexed as 0, the second column as 1, and so on.

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A gravitational force of 4.93 10-12 N in the positive x-direction is applied by the copper sphere to the steel sphere.

Along the line connecting the centres of the two objects, the force is applied. Coulomb's law has an undesirable effect if the two charges have opposing signs. This indicates that there is an attractive force acting on the particles.

\(F = G * m1 * m2 / r^2\)

\(m = rho * (4/3) * pi * r^3\)

r = 65 mm = 0.065 m

a = 3.7r = 0.241 m

b = 2.1r = 0.137 m

c = 0.6r = 0.039 m

m_copper = rho_copper \(* (4/3) * pi * r^3\)

\(= 8,960 kg/m^3 * (4/3) * pi * (0.065 m)^3\)

= 0.0138 kg

m_steel = rho_steel \(* (4/3) * pi * r^3\)

= \(7,860 kg/m^3 * (4/3) * pi * (0.065 m)^3\)

= 0.0119 kg

F = G  m_copper  m_steel / \(r^2\)

= \(6.674 × 10^-11 N·(m/kg)^2 * 0.0138 kg * 0.0119 kg / (0.065 m)^2\)

\(= 4.74 × 10^-11 N\)

u = (0.241 - 0.137)i + 0j + 0k

= 0.104i + 0j + 0k

So the gravitational force F can be expressed as:

\(= 4.74 × 10^-11 N\)

\(= 4.74 × 10^-11 N\)

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Answer:

The following description of the problem is provided.

Explanation:

It is not safe to stand on the top step of a stepladder, even if someone is holding the base. The top step is not designed to bear weight and can lead to instability, causing the ladder to tip over.

It is crucial to follow the ladder's safety guidelines and use it as intended, ensuring all steps are used and the ladder is properly stabilized to prevent accidents and injuries.

When someone holds the base of a stepladder, it can provide some additional stability, but it does not make standing on the top step safe. The top step of a stepladder is not designed to bear weight, and it can be dangerously unstable. Even with someone holding the base, there is still a risk of the ladder tipping over, leading to a fall or injury. To ensure safety, it is important to follow the ladder's guidelines, which typically recommend using all steps and maintaining proper stability, such as securing the ladder against a sturdy surface or using

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Answer:

Airplanes have a small little jet on the back allowing them to get in the air but they have these big engines on the side allowing them to maintain their spot in the air

Explanation:

To draw the shear and moment diagrams for the loaded cantilever beam, first identify the loading conditions and support reactions. Next, plot the shear force (V) and bending moment (M) along the length of the beam.

At x = 0.28L, the shear force V is equal to the point load P, as there are no other loads acting on the beam at this location. The moment at x = 0.28L is given by M = PL, where P is the point load and L is the length of the cantilever beam.

At x = 0.73L, the shear force V is equal to the product of P and L, as this is the location where the cantilever is fully supported by the point load. The moment at x = 0.73L cannot be determined without additional information.

In summary, the shear and moment diagrams for the loaded cantilever beam can be constructed by plotting the shear force and bending moment along the length of the beam, and evaluating these values at the given locations (0.44L and 0.56L) to answer the questions.

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Answer:

A

Explanation:

Answer:

i believe tungsten is stronger than titanium !

Answer:

146494 kw

Explanation:

Given data:

Turbine inlet pressure ( p1 ) = 16 MPa

Turbine inlet temperature ( T1 ) = 560°C

condenser pressure : P3 = 8Kpa

Extracted steam at pressure ( P2 ) = 1 MPa

mass flow rate of steam ( m ) = 120 kg/s

a) The net power developed

= 146494 kw

note: values of    h1, h2,  y, Wp   are all calculated values not included in the solution to make the solution less cumbersome.

Answer d

Explanation:

The cutting operation is a crucial part of sheet metal working. Cutting has function to separate large sheet into smaller sheets and also to create holes in the part. It is taken by shearing between two form cutting edges.

From the scenario, we are informed that

The shear strength of work material (τs) = 50,000 lb/in²

The rake angle of tool (α) = 20°

Cutting speed =100 ft/min

The chip thickness before cut (t1) = 0.015 in

The width of cut (b) = 0.150 in

The chip thickness ratio (r) = 0.50

Firstly, we determine the shearplane angle use this formula below

θ = tan⁻¹ (\(\frac{r cos \alpha }{1-rsin\alpha }\))

θ = tan⁻¹ (\(\frac{0.50 cos 20}{1-0.50 sin 20}\))

θ = tan⁻¹ \(\frac{0.47}{0.83}\)

θ = tan⁻¹ 0.56

θ = 102.31°

hence, the shearplane angle is 102.31°.

To determine the shear force, we can use this formula:

Fs = τs(b)(t1)/sin θ

Fs = 50,000(0.150)(0.015)/sin 102.31

Fs = 112.5/0.97

Fs = 115.98 lb

So, the shear force is 115.98 lb

Then, we calculate the value, of cutting force andthrust force using this formula:

Fc = Fs x cos (ζ-α)/cos(θ+ζ-α)

Where, ζ = 90° + α - 2θ

Hence, ζ = 90° +  20° - 2(102.31°) = -94.62°

Thus, we substitute into formula

Fc = 115.98 x cos (-94.62°-20)/cos(102.31° -94.62° - 20°) = 115.98 x 0.43 = - 50.22 lb

So, the cutting force is 50.22 lb

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An external fan should be used to supply air to the condenser to simulate driving conditions is not true statement.

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The given statement that says personal and fatigue allowances can include amounts for the effects of lighting, heat and humidity, and noise is true. Read on to learn more.

The statement is accurate. Personal and fatigue allowances refer to the amount paid to employees who work in conditions that may cause personal discomfort or stress. This is intended to compensate the worker for the discomfort caused by factors such as heat, light, humidity, and noise.

This is particularly true in cases where such discomfort is unavoidable, for example in hazardous areas such as construction sites and manufacturing plants.

The personal and fatigue allowances are usually paid to compensate for the consequences of working in such environments, which can include hearing loss, vision impairment, respiratory problems, or other illnesses resulting from extended exposure to specific environmental factors.

Therefore, personal and fatigue allowances can include amounts for the effects of lighting, heat and humidity, and noise. The primary goal of such allowances is to promote a safe and healthy working environment, and to ensure that employees can work comfortably and productively, without experiencing undue stress or discomfort, that could have an adverse effect on their work performance.

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Answer:

oa

Explanation:

Answer:

safety factor

Explanation:

i got it correct on the test

Answer:

Please check the photo (solve)

Electric current in metal wires is carried by free electrons. due to any variations.

Electrical charge travels through a conductor when a potential difference is put across it, and electrical current is a measure of how much electrical charge passes through a conductor in a given amount of time.

Electrons and protons are both present in an atom in equal numbers. So, in general, atoms are electrically neutral. There will be an attractive force acting between the electrons and protons because they are attracted to one another due to the positive charges of the core nucleus's protons and the negative charges of the circling electrons. A variety of electrons organise themselves in distinct circling shells that are spaced apart from the nucleus in an atom.

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Keeping all variables the same except for the one being tested is an example of a fair test.

A fair test is a controlled experiment where only one variable is changed at a time in order to isolate the results. This allows for more accurate conclusions to be drawn about the relationship between the independent variable (the one being tested) and the dependent variable (the one being measured).

In a fair test, all other variables are kept constant to ensure that any changes in the dependent variable are due to the independent variable and not other factors. This is important in scientific experiments to ensure that the results are valid and can be replicated. So, the correct answer to the question is: a fair test.

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Answer:

Part 1

1) 0.252 kg/s

2) 457.06 K

3) 63.45%

4) 17.96 kJ

5) 44.85%

Part 2

1) 65.92 kJ

2) 57.62 kJ/kg

Explanation:

1) The mass flow rate

The flow velocity is given by the Bernoulli relation;

\(U =\sqrt{ \dfrac{\Delta P}{\rho } }\)

Where:

ΔP = The difference in pressure = 50 - (-2) = 52 kPa

ρ = Density of air = 1.225 kg/m³

\(U =\sqrt{ \dfrac{52,000}{1.225 } } = 206.03 m/s\)

The volume flow rate, V = U × A

Where:

A = Cross sectional area of the of the inlet = 10 cm² = 0.001 m²

Therefore, V = 0.001 × 206.03 = 0.206 m³/s

The mass flow rate = ρ × V = 1.225 × 0.206 = 0.252 kg/s

2) The minimum outlet temperature

P₁v₁/T₁ = P₂v₂/T₂

v₁ = v₂

∴ P₁/T₁ = P₂/T₂

T₂ = P₂T₁/P₁ = 151.325*300/99.325 = 457.06 K

3) The isentropic efficiency no heat loss

h₁ = 300.4 kJ/kg

\(h_{(out \ actual)}\) = 401.3 kJ/kg

\(h_{(out \ isentropic)}\) = 441.9 + (457.06 - 440)/(460 - 440)*(462.3 - 441.9) = 459.30 kJ/kg

The isentropic efficiency, \(\eta _{S}\), is given by the expression;

\(\eta _{S} = \dfrac{h_{in} - h_{(out \ actual)}}{h_{in} -h_{(out \ isentropic)} } = \dfrac{300.4 - 401.3}{300.4 - 459.3} = 0.6345\)

Therefore, the isentropic efficiency, \(\eta _{S}\) in percentage = 63.45%

4) Where there is an heat loss of 30 kJ/kg, we have;

\(h_{(out \ actual \ new)}\)  = \(h_{(out \ actual)}\) - Heat loss = 401.3- 30 = 371.3 kJ/kg

The work done = (371.3 - 300.04)*0.252= 17.96 kJ/s

The new isentropic efficiency is given by the relation;

\(\eta _{S, new} =\dfrac{300.4 - 371.3}{300.4 - 459.3} = 0.4485\)

Therefore, the isentropic efficiency, \(\eta _{S, new}\), in percentage = 44.85%

Part 2

1) Turbine mass flow rate = 0.252 kg/s

From

T₂ = P₂T₁/P₁ = 101.325*800/151.325= 535.67 K

h₁ = 822.2 kJ/kg

\(h_{(out \ actual)}\) = 503.3 kJ/kg

\(h_{(out \ isentropic)}\) = 544.7 + (535.67 - 520)/(540 - 520)*(544.7 - 524.0) = 560.92 kJ/kg

The maximum work, \(W_{max}\), is given by the expression;

\(W_{max}\) = Mass flow rate×(h₁ - \(h_{(out \ actual)}\))

\(W_{max}\) = (822 - 503.3)*0.252 = 65.92 kJ/s

2) The heat lost, \(h_{loss}\), is given by the relation;

\(h_{loss}\) = \(h_{(out \ isentropic)}\)  - \(h_{(out \ actual)}\) = 560.92  - 503.3 = 57.62 kJ/kg.

Answer:

The answer is below

Explanation:

The mining auxiliary operations in underground mining involve various activities that are important for a successful mining operation particularly in the areas of productive operating conditions.

The activities involved in the auxiliary operations in underground mining include the following: ventilation, haulage, drainage, power supply, lighting, delivery of compressed air, water, supplies to the working sections, and communications.

Answer:

See attachment for chart

Explanation:

The IPO chart implements he following algorithm

The expressions in bracket are typical examples

Input

Input Number (5, 4.2 or -1.2) --- This will be passed to the Processing module

Processing

Assign variable to the input number (x)

Calculate the square (x = 5 * 5)

Display the result (25) ----> This will be passed to the output module

Output

Display 25

Answer:The three main repetition structure structures in Java

Explanation:

(a) The local acceleration term in the equation of motion (LA) for the x-direction is given by -2Hσ²e^(kz)cos(kx - σt).

(b) The advective acceleration term in the equation of motion (AA) for the x-direction is zero.

The given fluid velocity components in Cartesian coordinates are u = 2Hσe^(kz)cos(kx - σt) and v = 0, w = 2Hσe^(kz)sin(kx - σt), where x represents the horizontal coordinate, z represents the vertical coordinate, and t represents time.

In order to find the expressions for the local acceleration term (LA) and the advective acceleration term (AA) in the equation of motion for the x-direction, we differentiate the x-component of velocity twice with respect to time.

In summary, the local acceleration term (LA) in the x-direction is given by -2Hσ²e^(kz)cos(kx - σt), while the advective acceleration term (AA) in the x-direction is zero.

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Answer:

yes it is very hard you should find a reccomended doctor to aid in your situation. But in the meantime how about you give me that lil brainliest thingy :p