How would you measure the melting point of a solid that melts above 100 °c?.

Answers

Answer 1

From the Question, the melting point of a solid that melts above \(100^oC\) can be measured by:

The melting point of solids can be measured by using electrically heated apparatus.These are used for even higher melting points.

Also, by using Kjeldahl flask method we can determine the melting point of solids up to \(200 ^oC\)

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Related Questions

Based on Mount Wilson Observatory
1. How are astronomical observational patterns used to determine the history of the universe?
2. Why was Mt. Wilson or Mt. Palomar Observatories used to observe and collect data about space, and why are mountains used?
3. What is NASA Mission Statement?
4. Describe three aspects of spectrometry? It’s application to astronomy.
1.___________________________________________________________
2.___________________________________________________________
3.___________________________________________________________
5. Why is studying space important for humans on earth, and do you think human space travel will be worth the risk and costs?

Answers

1. Astronomical observational patterns are used to determine the history of the universe by studying the light emitted or absorbed by celestial objects. Scientists analyze the patterns in the electromagnetic spectrum, such as the distribution of wavelengths, intensity, and spectral lines, to gather information about the composition, temperature, motion, and evolution of celestial bodies.

What is Astronomical observational ?

Astronomical observational refers to the act of observing celestial objects and phenomena in the field of astronomy. It involves the use of telescopes, detectors, and other instruments to collect data and study various aspects of the universe.

2. Mount Wilson and Mount Palomar Observatories were used to observe and collect data about space due to several reasons. Firstly, the locations of these observatories provide advantages for astronomical observations.

3. The NASA Mission Statement is: "To pioneer the future in space exploration, scientific discovery, and aeronautics research." This mission statement reflects NASA's commitment to advancing human knowledge, technological innovation, and exploration beyond Earth's boundaries. NASA aims to push the boundaries of scientific understanding, develop and test new technologies, explore the cosmos, and inspire the next generation of scientists and engineers.

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When towing a trailer on a 65-MPH posted highway, if it is safe, you may travel at the posted 65mph. true or false

Answers

True. If it is safe, you may travel at the posted 65mph when towing a trailer on a 65-MPH posted highway.
True. When towing a trailer on a highway with a posted speed limit of 65-MPH, you may travel at the posted 65-MPH if it is safe to do so.

Always ensure proper control and stability while towing, and adjust your speed as necessary for road conditions and traffic. This Ministry is primarily responsible for the development and maintenance of National Highways (NHs). The Ministry keeps on receiving proposals from various State Governments/Union Territories (UTs) for the declaration of State roads as new National Highways (NHs). The Ministry considers the declaration of some State roads as new NHs from time to time based on the requirement of connectivity, inter-se priority, and availability of funds.

The declaration of State roads as new NHs is considered based on well-established principles; the criteria for State roads for declaration as new NHs include roads running through the length/breadth of the country, connecting adjacent countries, National Capitals with State Capitals / mutually the State Capitals, major ports, non-major ports, large industrial centers or tourist centers.

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Final answer:

It is generally true that you can travel at the posted speed limit when towing a trailer, if it is safe to do so. However, some jurisdictions may impose lower speed limits for vehicles towing trailers. Safety and local traffic laws should always be prioritized.

Explanation:

The answer to your question, 'When towing a trailer on a 65-MPH posted highway, if it is safe, you may travel at the posted 65mph' is generally true. However, it is important to note that specific laws and regulations may vary depending on the jurisdiction or state you are in. Some jurisdictions may impose a lower speed limit for vehicles towing trailers regardless of the general speed limit. Safety must always be your primary concern, making sure the trailer is properly hitched, and the load is balanced to prevent swaying or instability at high speeds. It would be best to research the specific traffic rules and regulations in the area you plan on towing to ensure that you are abiding by all laws.

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A car's bumper is designed to withstand a 5.04-km/h (1.4-m/s) collision with an immovable object without damage to the body of the car. The bumper cushions the shock by absorbing the force over a distance. Calculate the magnitude of the average force on a bumper that collapses 0.255 m while bringing a 890-kg car to rest from an initial speed of 1.4 m/s.

Answers

Answer:

3420.39 N

Explanation:

Applying,

Fd = 1/2(mv²-mu²)................. Equation 1

Where F = force on the bumber, d = distance, m = mass of the car, v = final velocity, u = initial velocity.

make F the subject of the equation

F = (mv²-mu²)/2d............... Equation 2

From the question,

Given: m = 890 kg, v = 0 m/s (to rest), u = 1.4 m/s, d = 0.255 m

Substitute these values into equation 2

F = [(890×0²)-(890×1.4²)]/(2×0.255)

F = -1744.4/0.51

F = -3420.39 N

The negative sign denotes that the force in opposite direction to the motion of the car.

The mass of the earth is 6x10^24 kg and that of the moon is 7.4x10^22 kg. If the radius of the moon is 1740 km, then find the value of g if the earth is compressed into the size of moon.​

Answers

Answer:

In the surface of the moon, gravitational acceleration is 1.63 m/s*2.

Explanation:

An object of mass M will accelerate gravitationally at a distance R if it is at the following distance:

g = G*M/R^2

Where the gravitational constant is G.

G = 6.67*10^(-11) m^3/(kg*s^2)

At the surface of a moon, the distance between its surface and its center will be equal to its radius, since a moon's mass is concentrated at its center, thus:

R = 1740 km

It's important to remember that we need meters in order to work:

1 km = 1000 m

so:

1740 km = (1740)*1000 m = 1740000 m

R =  1740000 m

Basically, the mass consists of:

M = 7.4x10^22 kg

Incorporating all that into the gravitational acceleration equation, we get:

g = (6.67*10^(-11) m^3 / (kg*s^2))*(7.4x10^22 kg) / ( 1740000 m)^2

g = 1.63 m / s^2

In the surface of the moon, gravitational acceleration is 1.63 m / s*2.



On a keyboard, you strike middle C, whose frequency is 256. 0 Hz. Find the period of one vibration of this tone

Answers

The period of one vibration of the tone will be 0.00390625 seconds.

Period of wave

The period (T) of a waveform is the time it takes for one complete cycle or vibration. It is calculated as the inverse of the frequency (f) of the waveform.

So, if the frequency of middle C is 256.0 Hz, then the period of one vibration of this tone is:

T = 1/f

T = 1/256.0 Hz

T = 0.00390625 seconds

Therefore, the period of one vibration of middle C is approximately 0.00390625 seconds.

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A man drops a cup from cretain height which breaks in to pieces what's energy changes are involved?

Answers

There are various energy changes that occur when a guy drops a cup from a specific height. The cup's elevation above the ground gives it potential energy.

This potential energy is transformed into kinetic energy, the energy of motion, as it descends. The kinetic energy is transmitted to the cup as it falls to the ground, breaking it into pieces. This process involves the conversion of kinetic energy into thermal energy from the collision and friction of the shattered pieces with the ground as well as potential energy of the broken pieces. When a cup breaks, energy is released in the form of sound waves, which are then transmitted from the cup to the surrounding air.

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ممكن حل بسرعة
please help ​

 please help

Answers

Answer:

I could help but i dont speak or understand a word of Arabic im so sorry.

Explanation:

please help me answer!! why can't you cry in space? thanks!! ​

Answers

Your eyes make tears but they stick as a liquid ball.

Answer:

we can't cry in space like we do earth.... because there is no gravity... due to which the tears not fall down..instead they make a liquid clump...near eyes

A certain element has 31 protons and 38 neutrons. What is the atomic mass 1 pol of the element? (Enter answer as a whole number with units of amu).*​

Answers

Answer:

87

Explanation:

the melting point of a mineral generally _____ with increasing pressure (or depth).

Answers

The melting point of a mineral generally increases with increasing pressure (or depth).

This relationship can be explained through the concept of phase equilibrium. At higher pressures, the stability of the solid phase is enhanced, meaning that more energy is required to break the bonds and convert the solid into a liquid. As pressure increases, the atomic structure of the mineral becomes more compact and dense, making it more resistant to melting.

In Earth's mantle, for example, minerals that make up the rocks experience greater pressures as depth increases. The increased pressure leads to a higher melting point for these minerals, so they remain solid even at elevated temperatures. This pressure-temperature relationship contributes to the formation of Earth's layered structure, with solid rock at greater depths despite increasing temperature.

However, it is essential to note that other factors, such as the composition of the mineral and the presence of impurities, can also influence the melting point. For instance, the melting point of a mineral may decrease when it is mixed with other minerals, even under high pressures.

In conclusion, the melting point of a mineral generally increases with increasing pressure (or depth) due to the enhanced stability of the solid phase and the more compact atomic structure at higher pressures. This relationship plays a crucial role in Earth's layered structure and the behavior of minerals in various geologic environments.

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A 0.3-kg object with half the density of human fatty tissue is placed in water. Ignoring the atmospheric pressure, what percentage of the mass will be submerged

Answers

Ignoring the atmospheric pressure, 45 percentage of the mass will be submerged if a 0.3-kg object with half the density of human fatty tissue is placed in water.

How does the weight of the displaced water compare to the buoyant force acting on a submerged object?

The weight of the fluid displaced determines the buoyant force acting on a submerged item. By comparing an object's mass in air and its effective mass when submerged in water (density = 1 gramme per cubic centimetre), this concept can be used to determine the volume and, consequently, the density of an irregularly shaped object.

Percentage of the mass will be submerged will be equal to (density of object /density of fluid)*100%

Density of object is 0.45kg/L

Density of fluid is 1kg/L

Percentage of the mass will be submerged will be 0.45/1 *100% i.e. 45%

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katherine johnson’s skill in what field led to nasa’s first moon voyage?

Answers

Answer: Katherine Johnson's knowledge of (mathematics) was instrumental in the return of the Apollo astronauts from the Moon to Earth.

Which statement best describes the overall function of the human respiratory system? A. The heart pumps blood containing carbon dioxide into the lungs, where it is absorbed. B. Oxygen is transferred into the blood, which circulates the gas throughout the body. C. Oxygen is taken into the lungs and exchanged for carbon dioxide, which is exhaled. D. Carbon dioxide is taken into the lungs and exchanged for oxygen, which is absorbed.

Answers

Answer:

C

Explanation:

During respiration, oxygen diffuses into the lung (carbon dioxide diffuses out), gets into the blood, and is transported around the body. The hemoglobin of the blood distributes the oxygen to the various cells and carbon dioxide from these cells diffuses into the blood. The blood travels back to the lung where the carbon dioxide is exchanged for oxygen once again. The carbon dioxide is eventually exhaled out of the nose.

The correct option is C.

in a double-slit experiment, the slit separation is 2.0 mm , two wavelengths of 910 nm and 650 nm illuminate the slits, the screen is placed 2.2 meters away from the slits. at what distance from the central maximum on the screen will a dark fringe from one pattern first coincide with a dark fringe from the other?

Answers

The distance from the central maximum on the screen is approximately 1.455 m or 2.145 m, depending on the wavelength.

What is the distance from the central maximum on a screen?

The distance from the central maximum on the screen to the first dark fringe on either side is given by:

y = (m + 1/2)λL/d

where:

m = 0 (for the central maximum) or ±1, ±2, ±3,... (for the fringes on either side)

λ = the wavelength of light

L = the distance from the slits to the screen

d = the slit separation

For the first dark fringe from one pattern to coincide with a dark fringe from the other, we need the path difference between the two waves to be equal to λ/2. This occurs when m is an odd integer.

Using the given values, we can calculate the distance y as:

For the 910 nm wavelength:

m = 1

y = (1 + 1/2)(910 × 10^-9 m)(2.2 m)/(2.0 × 10^-3 m) = 1.455 m

For the 650 nm wavelength:

m = 3

y = (3 + 1/2)(650 × 10^-9 m)(2.2 m)/(2.0 × 10^-3 m) = 2.145 m

Therefore, the distance from the central maximum on the screen to the point where a dark fringe from one pattern coincides with a dark fringe from the other is approximately 1.455 m or 2.145 m, depending on the wavelength.

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Two objects in a closed system collide. After the collision, one object has lost speed, but the other object has gained speed. Explain what has happened. A. Total momentum in a closed system is conserved. B. Gravitation potential energy converts to kinetic energy. C. Kinetic energy converts to gravitational potential energy. D. Mass is conserved

Answers

A. Total momentum in a closed system is conserved

the law of momentum conservation states that The total amount of momentum before the collision is the same as the total momentum after the collision. Regardless of the change of momentum of each object.

A superconducting solenoid (coil) is used to generate a magnetic field of 10 T. If the solenoid winding has 2000 turns/m, what is the required current in the solenoid?
Answer

a. 3979 A
b. 2000 A
c. 4 mA
d. 398 A
e. 25m A

Answers

A superconducting solenoid is a coil made of superconductive wire that can generate a magnetic field when an electric current is passed through it. To find the required current in the solenoid, we can use the formula for the magnetic field of a solenoid:

B = μ₀ * n * I

where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ Tm/A), n is the number of turns per meter, and I is the current.

We are given the following values:

- Magnetic field (B) = 10 T
- Number of turns per meter (n) = 2000 turns/m

We need to find the current (I). Rearranging the formula for I, we get:

I = B / (μ₀ * n)

Now, plug in the given values:

I = 10 T / (4π × 10⁻⁷ Tm/A * 2000 turns/m)

I ≈ 3979 A

Hence, the required current in the solenoid to generate a magnetic field of 10 T is approximately 3979 A, which corresponds to option (a).

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Francium-233 has a half-life of 22 minutes.A Geigor counter gives a reading of 58 counts per minute (cpm) from a sample of francium-233.What will the reading be 22 minutes later?You can ignore background radiation

Answers

Answer:

The reading of the Geiger counter, 22 minutes later = 29 counts per minute (cpm)

Explanation:

Half life is defined as the time taken for the amount ( or activity) of a substance to reduce to half its original value.

As stated in the question, the half life of Francium-233 is 22 minutes, \(t_{1/2} = 22 minutes\). This means that it takes 22 minutes for the activity of Francium-233 to reduce to half of its original value.

The original activity of Francium-233 =  58 counts per minute (cpm)

By the end of 22 minutes, the activity measured by the counter would have halved.

Activity of Francium-233 after 22 minutes = 58/2

Activity of Francium-233 after 22 minutes = 29 counts per minute (cpm)

Treatment for dissociative identity disorder typically starts with ____.
a. identifying one's "true" personality c. labeling the disorder for the client
b. working through traumatic memories d. finding the most appropriate medication

Answers

Treatment for dissociative identity disorder typically starts with working through traumatic memories. The correct option is b.

The initial step in the treatment of dissociative identity disorder typically involves addressing and processing traumatic memories.When starting treatment for dissociative identity disorder (formerly known as multiple personality disorder), it is commonly necessary to focus on working through the traumatic memories. This disorder is frequently linked to a background of significant trauma, such as childhood abuse or neglect. The primary objective of therapy is to assist individuals with dissociative identity disorder in integrating their multiple identities and fostering a unified sense of self. This process often entails confronting and processing the traumatic experiences, which aids in healing and integration.Therefore ,option b is correct.

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The lowest tone to resonate in a pipe of length l that is closed at one end but open at the other end is 200 hz. which one of the following frequencies will not resonate in that pipe?

Answers

The frequency of 400 Hz is not possible.

Given that:

Frequency = 200 Hz

Length = l

Let's suppose, the given frequencies are,

600 Hz, 1000 Hz, 1400 Hz, 1800 Hz, and 400 Hz respectively.

To determine the possible resonance frequencies, we need to calculate the fundamental frequency.

Now using the formula of fundamental frequency for pipe

Where, n = odd number

F = nv / 4L

To calculate the first overtone, use the above formula.

n = 3

F = nv/4L = 3 x v / 4L = 3 x 200 = 600 Hz

For the second overtone, Use the same formula.

n = 5,

F = nv / 4L = 5 x 200 = 1000 Hz

For the third overtone, use the formula

n = 7,

F = nv / 4L = 7 x 200 = 1400 Hz

For the fourth overtone, use the formula.

n = 9,

F = nv/ 4L = 9 x 200 = 1800Hz

Hence, The frequency of 400 Hz is not possible.

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As we look at larger and larger scales in the universe, we find A) an equal amount of visible and dark matter.
B) smaller and smaller masses.
C) a larger and larger percentage of the matter is dark.
D) a larger and larger percentage of the matter is visible.
E) almost exclusively visible matter.

Answers

As we look at larger and larger scales in the universe, we find that C) a larger and larger percentage of the matter is dark.

Dark matter refers to matter that does not interact with light or other forms of electromagnetic radiation, making it invisible or "dark" in terms of our current observational techniques. Its presence is inferred through its gravitational effects on visible matter and the structure of the universe.

Observations at different scales, such as the rotation of galaxies, the motion of galaxy clusters, and the distribution of cosmic microwave background radiation, have indicated the existence of dark matter. These observations suggest that dark matter makes up a significant portion of the total matter in the universe.

While visible matter, including stars, galaxies, and other objects we can directly observe, does exist, it constitutes only a small fraction of the total matter in the universe. The majority of matter, around 85% based on current estimates, is believed to be dark matter.

As we look at larger scales, such as galaxy clusters and the cosmic web, the dominance of dark matter becomes more apparent. It plays a crucial role in the formation and evolution of large-scale structures in the universe, providing the gravitational scaffolding for the visible matter to coalesce and form galaxies.

Therefore, option C) a larger and larger percentage of the matter is dark is the correct answer.

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Ms. Lachance has to pick up her daughter from the airport and is running late. As she pulls her car out of the driveway and starts to drive down the road, she takes off as fast as her car will go. When she does this her coffee cup, which she left on the hood by accident flies into the windshield making it hard for her to see. Using Newton’s first law, explain why the coffee spilt all over the windshield.

Answers

Answer:

the gravity was pulling the cup to the front of the window even though the wind was pushing it the other way.

Explanation: the gravity must be strong

By using the Newton's first law of Motion, it can be explained why the coffee spilt all over the windshield. This is because there is gravitational force which acts upon it and it pushes the substances in the downward direction towards the Earth.

What is Newton's first law of motion?

Newton's first law of Motion states that a body remains in the same state of rest or uniform motion in a straight line unless and until an external force is applied on it. This means that a body will not start moving by itself until and unless an external force acts on it.

In this case, lachance's daughter is trying to pick her coffee cup, the coffee cup at the windshield is spilt which makes it difficult for her to see. This is because, there is the gravitational force or gravity which is pulling the coffee cup to the front of the window even though the wind was pushing it in the other way.

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Newton’s second law of motion states that an object’s acceleration depends on its mass and on the net force acting on it.

true
false

Answers

Answer:motion

Explanation:

What makes it hard to measure circular objects?

2. Which is harder to measure, the circumference or the diameter? Why?

Answers

Measuring circular objects can be challenging due to several factors:a) Lack of defined edges, b) Curvature, c) Precision 2) Circumference of circle is relatively difficult to measure. because of Accessibility, Curvature considerations,  Precision requirements

Measuring circular objects can be challenging due to several factors:a) Lack of defined edges: Unlike measuring straight objects with clear endpoints, circular objects do not have well-defined edges. This can make it difficult to determine where exactly to begin and end the measurement.

b) Curvature: The curved shape of circular objects introduces additional complexities. Measuring a curved surface accurately requires specialized tools or techniques, as traditional linear measurement methods may not be suitable.

c) Precision: Circular objects often have smaller dimensions compared to their overall size, making precise measurements crucial. Minor errors in measurement can have a significant impact on the calculated values, leading to inaccuracies.

The circumference of a circle is generally harder to measure compared to its diameter. Here's why: a) Accessibility: The circumference is an external measurement that requires accessing the outermost points of the circle. Depending on the size and nature of the object, it may be challenging to physically reach all points along the circumference for measurement.

b) Curvature considerations: The curvature of the circle poses challenges when attempting to measure the entire circumference accurately. The measuring instrument or method must be capable of following the curve precisely, ensuring consistent contact throughout the measurement process.

c) Precision requirements: The circumference measurement requires high precision due to the circular object's shape and the potential for small variations. Even slight errors in measurement can lead to significant discrepancies when calculating other parameters such as area or radius.

In contrast, the diameter of a circle is relatively easier to measure. It can be determined by measuring the distance between any two points on the circle that pass through its center

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the density of mercury is 13.5 g/ml and the density of water is 1.00 g/ml . if a mercury barometer reads 803 mmhg , what is the barometric pressure in centimeters of water ( cmh2o )?

Answers

The barometric pressure in centimeters of water (cmH₂O) if a mercury barometer reads 803 mmHg and the density of mercury is 13.5 g/mL and the density of water is 1.00 g/mL is 1033.25 cmH₂O.

1. Convert 803 mmHg to cmH₂O using the conversion factor 1 mmHg = 1.36 cmH₂O.

803 mmHg × 1.36 cmH₂O/mmHg = 1092.08 cmH₂O.

2. Determine the pressure due to the mercury column using the density of mercury and the height of the mercury column. The height of the mercury column is the same as the pressure reading in mmHg.

Pressure = density × gravity × height. 13.5 g/mL × 9.81 m/s² × (803 mmHg ÷ 760 mmHg/atm) × (1 atm/101325 Pa) = 101.47 kPa.

3. Determine the pressure due to the air above the mercury column. This is the difference between the atmospheric pressure and the pressure due to the mercury column.

Atmospheric pressure = 1 atm = 101.325 kPa.

Pressure due to air = atmospheric pressure − pressure due to mercury column.

Pressure due to air = 101.325 kPa − 101.47 kPa = −0.145 kPa.

4. Convert the pressure due to air to centimeters of water using the conversion factor 1 cmH₂O = 0.098 kPa. −0.145 kPa × (100 cmH2O/0.098 kPa) = −148.47 cmH2O.5.

Add the pressure due to the mercury column and the pressure due to the air to get the barometric pressure in cmH₂O.

Barometric pressure = pressure due to mercury column + pressure due to air.

Barometric pressure = 1092.08 cmH₂O + (−148.47 cmH₂O) = 943.61 cmH₂O.

However, since the pressure due to the air is negative, the actual barometric pressure is higher than the calculated value.

The correct answer is 1092.08 cmH₂O − 148.47 cmH₂O = 943.61 cmH₂O + 1090.86 cmH₂O = 1033.25 cmH₂O.

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arrange the solar system objects from least massive to most massive

Answers

Dwarf planets are the least massive objects in the solar system.  Small moons and asteroids are next, followed by larger moons. The terrestrial planets are more massive than the smaller objects, but less massive than the gas giants. The gas giants are the most massive objects in the solar system, with Jupiter being the largest by far.

1. Dwarf planets: Dwarf planets are the smallest objects in the solar system, and they're not quite large enough to be considered full planets. There are five recognized dwarf planets in our solar system: Pluto, Ceres, Eris, Makemake, and Haumea. Pluto is the most famous of these, and it's only about two-thirds the size of our Moon.

2. Small moons and asteroids: After dwarf planets, the next smallest objects in the solar system are small moons and asteroids. These can range in size from just a few meters across to a few hundred kilometers. Many asteroids are actually smaller than some of the moons in the solar system, but they're generally less massive due to their lower density.

3. Larger moons: As we move up in size, we get to the larger moons in the solar system. Some of these, like Jupiter's moon Ganymede, are actually larger than some dwarf planets. The larger moons tend to be quite dense, which means they have a lot of mass packed into a relatively small space.

4. Terrestrial planets: Next up are the terrestrial planets: Mercury, Venus, Earth, and Mars. These planets are made of rock and metal, and they're generally smaller than the gas giants. However, they're still quite massive compared to the smaller objects in the solar system. Earth is the most massive of the terrestrial planets, but it's still only about one-third the mass of Saturn's moon Titan.

5. Gas giants: Finally, we have the gas giants: Jupiter, Saturn, Uranus, and Neptune. These planets are massive, and they're made mostly of gas and ice. Jupiter is by far the most massive planet in the solar system, and it's actually more massive than all the other planets, moons, asteroids, and comets in the solar system combined.


- Dwarf planets are the least massive objects in the solar system.
- Small moons and asteroids are next, followed by larger moons.
- The terrestrial planets are more massive than the smaller objects, but less massive than the gas giants.
- The gas giants are the most massive objects in the solar system, with Jupiter being the largest by far.

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Dados los vectores a ⃗=6m y b ⃗=8m encontrar su resultante cuando Forman ángulo recto de 90° Son paralelos de igual sentido Son paralelos de sentido contrario

Answers

Answer:

I will answer in English, and i will give some representation for each case:

We have a = 6m and b = 8m.

If they are perpendicular, we have that:

a = (6m, 0) b = (0, 8m)

The adition is:

a + b = (6m, 8m).

If they are parallel, we have;

a = (6m, 0)

b = (8m, 0)

a + b = (6m + 8m, 0) = (14m, 0 )

If they are parallel but opposite:

a = (6m, 0)

b = (-8m, 0)

a + b = (6m - 8m,0) = (-2m, 0)

!! HELP PLEASE !! As seen from above, a 73.9 kg water skier is pulled by a 105 N force at a 22.5° angle, while the water creates a 74.8 N force pulling directly backward. What is the x-component of the total force on the skier?​

Answers

Answer: The x-component of the total force 97N

Explanation:

Given the following :

Mass (M) of skier = 73.9 kg

Pull force on the skier = 105N

Angle of pull = 22.5°

The direct backward force directly pulling the skier = 74.8N

the x-component of the total force on the skier

The horizontal component of the force = Magnitude of the pulling force × cosine of the angle of pull (FCosΘ)

FCosΘ = 105cos22.5°

105cos22.5 = 105 × 0.9238795

= 97.007350

= 97N

The backward force acting directly backward = 74.8N

Therefore, net x - component of the total force equals ;

97N - 74.8N = 22.2N

When a body changes we know that its momentum changes.​

Answers

Answer:

ok

Explanation:

Answer:

The change of movement depends on the force that acts and the length of time it acts.

Using the graphs on your notes, how are wavelength and frequency related to sound waves? Make sure to use proper terminology in your response.

Answers

The higher the frequency of sound waves the shorter their wavelength. This presumes that sound waves in air have almost a constant speed of around 330 m/s

determine the force of gravitational attraction between a 78 kg boy sitting 2 meters away from a 65 kg girl. circle your answer and include units

Answers

Answer:

The force of gravitational attraction is 8.454 x 10⁻⁸ N.

Explanation:

Given;

mass of the boy, m₁ = 78 kg

mass of the girl, m₂ = 65 kg

distance between the boy and the girl, r = 2 meters

The force of gravitational attraction is given as;

\(F = \frac{Gm_1m_2}{r^2}\)

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

r is the distance between two masses, m₁ and m₂

\(F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11})(78 \times 65)}{2^2}\\\\F = 8.454 \times 10^{-8} \ N\)

Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.

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