Answer:
The power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W
Explanation:
Given;
three identical resistors connected in series
let the first resistor = R₁
let the second resistor = R₂
let the third resistor = R₃
Rt = R₁ + R₂ + R₃
Since the resistors are identical, thus, R₁ = R₂ = R₃ = R
Rt = 3R
Power is given as;
P = IV = V² / R
\(P = \frac{V^2}{R_t} = \frac{V^2}{3R} \\\\3P = \frac{V^2}{R} ------equation(i)\)
If the 3 identical resistor connection were changed to parallel, then the equivalent resistance in the circuit will be;
\(\frac{1}{R_t} = \frac{1}{R_1} +\frac{1}{R_2} + \frac{1}{R_3} \\\\But, R_1 = R_2 = R_3\\\\\\frac{1}{R_t} = \frac{1}{R} +\frac{1}{R} + \frac{1}{R} \\\\\frac{1}{R_t} =\frac{3}{R} \\\\R_t = \frac{R}{3} \\\\P = \frac{V^2}{R_t} = \frac{3V^2}{R} \\\\P_{parallel} = \frac{3V^2}{R} ---------equation (ii)\\\\From \ equation \ (i), 3P_{series} = \frac{V^2}{R}, Substitute \ this \ into \ equation \ (ii)\\\\P = 3(\frac{V^2}{R} )\\\\P = 3(3P)\\\\P_{parallel} = 9P_{series}\\\\P_{parallel} = 9(45)\\\\\)
\(P_{parallel} = 405 \ W\)
Therefore, the power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W
Your lab partner tosses you a ball. As she throws the ball up in the air it follows this arc. Where is potential energy the lowest? Select all that apply.
A. point A
B. point B
C. point C
D. point D
E. They are all the same
Answer: c
Explanation:
Answer:
answer c
Explanation:
what is the mechanica advantage of alever then can lift 100 Newton with an input force of 20 Newton
Answer:
Explanation:
To calculate the mechanical advantage of a lever, we use the formula:
Mechanical Advantage = Output Force / Input Force
In this case, the output force is 100 Newton and the input force is 20 Newton, so:
Mechanical Advantage = 100 N / 20 N
Mechanical Advantage = 5
Therefore, the mechanical advantage of the lever is 5. This means that for every 1 Newton of input force applied to the lever, the lever will produce 5 Newtons of output force. So, in this case, an input force of 20 Newtons applied to the lever would produce an output force of 100 Newtons.
QUICK HELP ILL MARK U BRAINLIEST
_____can be used to calculate how much energy is being wasted or lost. I
Answer:
Microscope
Explanation:
what is the shape of the path that light takes
what evidence do you have?
A good easy question for a science minded person!! 20 points for whoever answer
Which of the following best describes an inverse-square relationship
A. A camera flashbulb produces a sudden burst of light.
B. Daylight on Mars is dimmer than daylight on Earth.
C. When you blow out a candle the room darkens
D. Installing compact fluorescent bulbs to lower your electric bill
Answer:
the answer is the first letter in the alphabet
In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.36 m. The mug slides off the counter and strikes the floor 1.00 m from the base of the counter.(a) With what velocity did the mug leave the counter?m/s(b) What was the direction of the mug's velocity just before it hit the floor?° (below the horizontal)
(a) Velocity with which the mug leaves the counter is approximately 5.02 m/s.
(b) The direction of velocity of mug just before it hits the floor is downwards, since mug is falling under influence of gravity.
What is velocity?Velocity is a quantity that designates how fast and also in what direction a certain point is moving.
(a) As we know, PE = m g h
\(\mathrm{PE = mgh }\)
\(\mathrm{= (m)(9.81 m/s^2)(1.36 m) }\)
= 13.4mJ
\(\mathrm{KE =\frac{1}{2} mv^2}\)
PE = KE
\(\mathrm{mgh = \frac{1}{2}mv^2}\)
\(\mathrm{v = \sqrt{2gh}}\)
\(\mathrm{v = \sqrt{2 \times 9.81 \times 1.36 m}}\)
v = 5.02 m/s
Therefore, the velocity with which the mug leaves the counter is approximately 5.02 m/s.
(b) The direction of the velocity of mug just before it hits the floor is downwards, since mug is falling under the influence of gravity. Velocity vector has a vertical component that points downwards and horizontal component that is parallel to counter.
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The image depicts two bar magnets immersed inof that contains small needle-In particles ofIron.What is the BEST Interpretation of the patterncreated by the iron particles?A The pattern of iron particles is created by thenorth pole of one magnet facing the south poleof the other magnetB. The pattern of kroparticles is created by thesouth pols of one magnet facing the south poleof the other magnet because south poles attracteach otherC. The pattern of iron particles is created by therepulsion of like magnetic poles, we cannotdetermine if the poles are north or southpolarizationD. The pattern of fron particles is created by thenorth pole of one magnet facing the north poleof the other magnet because north poles attracteach other.
option A is correct
The pattern of iron particles is created by the
north pole of one magnet facing the south pole
of the other magnet
as the lines of force emerges from north and ends at south
a)A person standing on the edge of a high cliff throws a ball straight up with an initial velocity of 15.0 m/s. The ball misses the edge of the cliff as it falls back to earth. Calculate the position and velocity of the ball at 1.50 s after it is thrown, neglecting the effects of air resistance.
He employs kinematic equations to address this issue. The main equations we'll employ are Time-dependent positions: y = y0 + v0t + 1/2at2. The ball has a downward velocity of 0.175 m/s at 1.50 seconds.
Explanation-These equations allow us to determine the location and speed of the ball 1.50 seconds after it is thrown:
Position:
y = y0 + v0t + 1/2at^2
y = 0 + 15.0 m/s * 1.50 s + 1/2 * (-9.81 m/s^2) * (1.50 s)^2
y = 11.0 m
The ball is thus 11.0 m above the point of throw at 1.50 seconds after being thrown.
Velocity:
v = v0 + at
v = 15.0 m/s + (-9.81 m/s^2) * 1.50 s
v = 0.175 m/s
Does a ball continue to slide down a steep cliff with a downward acceleration that is equal to?The acceleration of an item in free fall is -9.8 m/s/s. (The minus symbol represents a downward acceleration.) For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.
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How do I find max spring potential energy? I am given a position time graph and mass.
To find the maximum spring potential energy the following formula should be used U = 1/2 kx^2.
How to calculate the maximum potential energy of a spring?To find the maximum potential energy of a spring, you need to know two things: the spring constant (k) and the maximum displacement (x) from its equilibrium position.
The formula for calculating the potential energy stored in a spring is:
U = 1/2 kx^2
where U is the potential energy, k is the spring constant, and x is the displacement from equilibrium.
Therefore you need to determine the maximum displacement (x) from its equilibrium position. This can be done by measuring the distance between the spring's stretched or compressed position and its original position when it's at rest.
Once you know the maximum displacement (x), you can plug that value and the spring constant (k) into the equation to calculate the maximum potential energy stored in the spring.
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this is a multi-part question. once an answer is submitted, you will be unable to return to this part. a curve in a speed track has a radius of 1200 ft and a rated speed of 120 mi/h. a racing car starts skidding on the curve when traveling at a speed of 180 mi/h.
the centripetal acceleration needed for a car to navigate the curve at the rated speed of 120 mph is 25.8 ft/s². Skidding on the curve at 180 mph requires a minimum coefficient of static friction of 0.84.
We can calculate the centripetal acceleration required for a vehicle to negotiate the curve at the rated speed of 120 mi/h.
Centripetal acceleration is given by the formula:
a = v² / r
where a is the centripetal acceleration, v is the velocity of the vehicle, and r is the radius of the curve.
Substituting the given values, we have:
a = (120 mi/h)² / (1200 ft)
First, we need to convert the velocity from miles per hour to feet per second:
120 mi/h = 176 ft/s
Substituting this value and the radius of the curve, we get:
a = (176 ft/s)² / (1200 ft) = 25.8 ft/s²
Therefore, the centripetal acceleration required for a vehicle to negotiate the curve at the rated speed of 120 mi/h is 25.8 ft/s².
If the racing car starts skidding on the curve when traveling at a speed of 180 mi/h.
To determine the minimum coefficient of static friction required to prevent skidding on the curve at a speed of 180 mi/h.
v² / r = μ * g
g is the acceleration due to gravity (32.2 ft/s²).
Substituting the given values, we have:
(180 mi/h)² / (1200 ft) = μ * 32.2 ft/s²
First, we need to convert the velocity from miles per hour to feet per second:
180 mi/h = 264 ft/s (approximately)
Substituting this value and the radius of the curve, we get:
(264 ft/s)² / (1200 ft) = μ * 32.2 ft/s²
Simplifying, we get:
μ = (264 ft/s)² / (32.2 ft/s² * 1200 ft) = 0.84 (approximately)
Therefore, the minimum coefficient of static friction required to prevent skidding on the curve at a speed of 180 mi/h is 0.84.
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Calculate the average time for the tablet pieces to dissolve in room temperature water. Record the average time in Table D. Trial 141.00Trial 244.00Trial 341.00 What is the average time it took for the tablet pieces to dissolve in room temperature water? seconds
The average time it took for the tablet pieces to dissolve in room-temperature water is 42.00 seconds.
Room temperature refers to the typical temperature range that is comfortable for humans in an indoor environment. It is generally considered to be between 68°F (20°C) and 77°F (25°C). However, the exact definition of room temperature can vary depending on the context and the standards of a particular region or industry. In scientific experiments or industrial settings, room temperature may be defined more precisely and may range from 20°C to 25°C, or even narrower ranges such as 22°C to 24°C.
To calculate the average time it took for the tablet pieces to dissolve in room temperature water, we need to add up the times from all three trials and divide by the number of trials (3):
(41.00 + 44.00 + 41.00) / 3 = 42.00 seconds
Therefore, the average time it took for the tablet pieces to dissolve in room-temperature water is 42.00 seconds.
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The wave functions for states of the hydrogen atom with orbital quantum number l=0 are much simpler than for most other states, because the angular part of the wave.
a. True
b. False
The vertical displacement of the wave is measured from the what? And what is the term for vertical displacement?
Explanation:
The vertical displacement of the wave is measured from the
equilibrium to the crest and is called the frequency.
crest to the trough and is called the amplitude.
trough to the trough and is called the wavelength.
equilibrium to the crest and is called the amplitude.
HØPÊ ĮŤ ÌŠ helpful
mark mE aS bRillAnT ♠ cart is sliding across a horizontal floor. It has a mass of 25 kg and a force of 250 N. Using Newton's second law, a = F ÷ m, what is the acceleration of the cart?
0.1 m/s2
5 m/s2
10 m/s2
25 m/s2
Answer:
10m/s2
Explanation:
250/25=10
Which of the following is NOT true about the mass of an object?
A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.
Answer:
B) Mass is a measurement of force
Explanation:
Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.
What is refractive index?
\( \huge \mathbb \red{HEY \: THERE ♡}\)
Refractive Index:The ratio of the sine of angle of incidence to the sine of angle of refraction in case of lens for light of a given colour and given pair of media is constant. Note** It is also called Snell's Law of Refraction. \( \mathsf \orange{\frac{sine \: i}{sine \: r} = constant}\)\( \huge \mathbb\pink{HOPE \: IT \: HELPS}\)
According to Coulomb's law, rank the interactions between charged particles from highest potential energy to lowest potential energy.
a. 1+ charge and 1- charge seperated by 200pm
b. 1+ charge and 1+ charge seperated by 100pm
c. 1+ charge and 1- charge seperated by 100pm
d. 2+ charge and 1- charge seperated by 100pm
According to Coulomb's law, rank the interactions between charged particles from highest potential energy to lowest potential energy.
Highest potential energy to lowest potential energy.
b. 1+ charge and 1+ charge seperated by 100 pm
a. 1+ charge and 1- charge seperated by 200 pm
c. 1+ charge and 1- charge seperated by 100 pm
d. 2+ charge and 1- charge seperated by 100 pm
\(\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘\)
L 2.5.2 Test (CST): The Brain and the Body
Question 4 of 10
The
lobes are important for decision making and judgment.
A. frontal
B. temporal
O c. parietal
D. occipital
SUBMIT
Answer:
I believe it's A frontal. Hope this can help
The frontal lobes are important for decision-making and judgment. The correct answer is A.
What are frontal lobes?The frontal lobes are located at the front of the brain and are involved in a variety of cognitive functions, including reasoning, problem-solving, planning, decision-making, and judgment. The prefrontal cortex, which is located in the frontal lobes, is especially important for these functions.
In addition, the frontal lobes are involved in the control of voluntary movements, speech production, and the regulation of emotions and social behavior. Damage to the frontal lobes can lead to a variety of cognitive and behavioral deficits, including difficulty with decision-making and judgment, impaired impulse control, and changes in personality.
The temporal lobes are located on the sides of the brain and are involved in the processing of auditory information, as well as memory formation and recognition of faces and objects. The parietal lobes are located at the top and back of the brain and are involved in the processing of sensory information from the body, such as touch and proprioception. The occipital lobes are located at the back of the brain and are primarily involved in the processing of visual information.
Therefore, The correct answer is A i.e Frontal lobes are important for decision-making and judgment.
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a) a drone flies 150 m to southwest (directly between south and west), then flies 85 m directly south, and finally flies 550 m in the direction 35 degrees north of east. Use the analytical method to find the resultant displacement of the drone (magnitude and direction)
you can help with a
The resultant of the displacement is 336.5m
What is resolution of vectors?The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.
For the first displacement;
The vertical component = - 150 sin45 = -106.1 m
The horizontal component = - 150 cos 45° = -106.1 m
For the second displacement;
The vertical displacement = - 85sin90 = -85
The horizontal component = 0
For the third displacement;
The vertical displacement = 550 sin55 = 450.5
The horizontal displacement = 550 cos 55 = 315.5
Sum of vertical component = 450.5-85-106.1 = 263.4
sum of horizontal component = 315.5 -106.1 = 209.4
Using Pythagorean theorem
R = √ 263.4² + 209.4²
R = √113227.92
R = 336.5m
The resultant angle = tan^-1( 263.4/209.4)
= tan^-1(1.26)
= 51.56°
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Radioactive nuclei decay to become unstable. Is this true or false?
The unstable nuclei undergo radioactive decay. The nucleus decay in form of emitting the radiations or changing into the different chemical element.
Thus, the nucleus decay takes place till the nuclei become stable.
Hence, given statement is false.
Which part of the diagram indicates the amplitude of the wave?
The left vertical line part of the diagram indicates the amplitude of the wave.
The amplitude of a wave or vibrating body is defined as the maximum displacement or distance generated by a point on the wave or body compared to its position of equilibrium. It is the same as the length of the vibration path divided by half.
The wave's amplitude is shown by the left vertical line in the figure, which depicts the highest displacement or distance that a spot on a wave or moving body can make compared to its equilibrium position. So the left vertical line part of the diagram indicates the amplitude of the wave.
The figure of the question is attached.
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HELPPpPpPpPpPp!!!! ASAP !!!
Answer:
50 N
Explanation:
A mass attached to a vertical spring has position function given by
ANSWER:
a) -11.4 in/s
b) -29.3 in/s^2
STEP-BY-STEP EXPLANATION:
We have the following function corresponding to the position at a given time:
\(s(t)=5\sin (3t)\)If we differentiate this function with respect to time, we obtain the velocity function, like this:
\(\begin{gathered} v(t)=s^{\prime}(t) \\ s^{\prime}(t)=\frac{d}{dt}(s(t)) \\ \frac{d}{\mathrm{d}t}(5\sin (3t))=15\cos (3t) \\ v(t)=15\cos (3t) \end{gathered}\)We calculate the velocity by replacing t = 5, just like this:
\(\begin{gathered} v(t)=15\cos (3\cdot5)=15\cos (15) \\ v(t)=-11.4\text{ in/s} \end{gathered}\)If we differentiate the function again, we obtain the acceleration function, as follows:
\(\begin{gathered} a(t)=v^{\prime}(t) \\ v^{\prime}(t)=\frac{d}{dt}(v(t)) \\ \frac{d}{dt}(15\cos (3t))=-45\sin \mleft(3t\mright) \\ a(t)=-45\sin (3t) \end{gathered}\)We calculate the acceleration by replacing t = 5, just like this:
\(\begin{gathered} v(t)=-45\sin (3\cdot5)=-45\sin (15) \\ v(t)=-29.3in/s^2 \end{gathered}\)Two masses of 3 kg and 5 kg are connected by a light string that passes over a smooth polley as shown in the Figure.
QL
Determine:
i. the tension in the string,
ii. the acceleration of each mass, and
iii. the distance each mass moves in the first second of motion if they start from rest
i. \(T = 36.8\:\text{N}\)
ii. \(a = 2.45\:\text{m/s}^2\)
iii. \(x = 1.23\:\text{m}\)
Explanation:
Let's write Newton's 2nd law for each object. We will use the sign convention assigned for each as indicated in the figure. Let T be the tension on the string and assume that the string is inextensible so that the two tensions on the strings are equal. Also, let a be the acceleration of the two masses. And \(m_1 = 3\:\text{kg}\) and \(m_2 = 5\:\text{kg}\)
Forces acting on m1:
\(T - m_1g = m_1a\:\:\:\:\:\:\:(1)\)
Forces acting on m2:
\(m_2g - T = m_2a\:\:\:\:\:\:\:(2)\)
Combining Eqn(1) and Eqn(2) together, the tensions will cancel out, giving us
\(m_2g - m_1g = m_2a + m_1a\)
or
\((m_2 - m_1)g = (m2 + m_1)a\)
Solving for a,
\(a = \left(\dfrac{m_2 - m_1}{m_2 + m_1}\right)g\)
\(\:\:\:\:= \left(\dfrac{5\:\text{kg} - 3\:\text{kg}}{5\:\text{kg} + 3\:\text{kg}}\right)(9.8\:\text{m/s}^2)\)
\(\:\:\:\:= 2.45\:\text{m/s}^2\)
We can solve for the tension by using this value of acceleration on either Eqn(1) or Eqn(2). Let's use Eqn(1).
\(T - (3\:\text{kg})(9.8\:\text{m/s}^2) = (3\:\text{kg})(2.45\:\text{m/s}^2)\)
\(T = (3\:\text{kg})(9.8\:\text{m/s}^2) + (3\:\text{kg})(2.45\:\text{m/s}^2)\)
\(\:\:\:\:= 29.4\:\text{m/s}^2 + 7.35\:\text{m/s}^2 = 36.8\:\text{N}\)
Assuming that the two objects start from rest, the distance that they travel after one second is given by
\(x = \frac{1}{2}at^2 = \frac{1}{2}(2.45\:\text{m/s}^2)(1\:\text{s})^2 = 1.23\:\text{m}\)
How large must the coefficient of static friction be between the tires and road if a car is to round a level curve of radius 125 m at a speed of 95km/h
Answer:
673km
Explanation:
URGENT HELP NEEDED!!!
Two train cars are moving towards each other. The loaded car has a mass of 134,000 kg, and is moving north at a speed of 2.9 m/s. The unloaded car has a mass of 22,600 kg, and is moving south at a speed of 0.8 m/s. When the cars collide, they lock together, and move as a single unit. What is the velocity of the cars after they join together?
2.4 m/s north
2.1 m/s north
2.4 m/s south
2.1 m/s south
To solve this problem, we need to apply the principle of conservation of momentum, which states that the total momentum of a system remains constant if there is no external force acting on it.
The initial momentum of the loaded car moving north is:
p1 = m1 * v1 = 134,000 kg * 2.9 m/s = 388,600 kg*m/s (north)
The initial momentum of the unloaded car moving south is:
p2 = m2 * v2 = 22,600 kg * (-0.8 m/s) = -18,080 kg*m/s (south)
Note that we have used a negative velocity for the unloaded car, as it is moving in the opposite direction to the positive direction we have chosen (north).
When the cars collide, they lock together and move as a single unit. The final momentum of the joined cars is:
p = (m1 + m2) * v
where v is the final velocity of the joined cars.
Since the momentum is conserved, we can set the initial and final momenta equal:
p1 + p2 = (m1 + m2) * v
Substituting the values we have calculated:
388,600 kgm/s - 18,080 kgm/s = (134,000 kg + 22,600 kg) * v
370,520 kg*m/s = 156,600 kg * v
v = 2.366 m/s (north)
Therefore, the velocity of the cars after they join together is 2.4m/s north.
Note that this answer is between the initial velocities of the two cars, which makes sense since the collision causes the cars to slow down and move together in the north direction.
What is Energy in physics?
Answer:
Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.
Explanation:
Hope this helps!
What is the force required to accelerate 1 kilogram of mass at 1 meter per second per second.
1 Newton
1 pound
1 kilometer
1 gram
Answer:
it's answer is 1 newton
what is the light synthesis ?
Answer:
Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. ... During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
Explanation:
thank me later
4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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