i believe Newton's 1st law is

Answer:

ke=648J

Explanation:

ke=1/2mv²

m=9kg

v=12m/s

1/2(9)(12)²

=648J

With the use of first and third equation of motion, the distance covered by a T-Rex is 30.51 m

When a body is in linear motion, the body is moving in a straight line. some of the parameters to consider are:

Given that a T-Rex move from 0 m/s to 9 m/s in 6.78 seconds, the distance covered can be found by calculating the acceleration.

Let us use equation 1

V = U + at

9 = 0 + 6.78a

a = 9 / 6.78

a = 1.33 m/\(s^{2}\)

Now let us use equation 3

\(v^{2}\) = \(u^{2}\) + 2as

\(9^{2}\) = 2 x 1.33 x S

81 = 2.655S

S = 81/2.655

S = 30.51 m

Therefore, the distance covered by a T-Rex is 30.51 m.

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If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force is always perpendicular to velocity, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

A negatively charged particle moves in the plane of the paper in a region where the magnetic field is perpendicular to the paper (represented by the small × ’s—like the tails of arrows). The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.

If the fundamental frequency of the harmonic is 7 Hz, the frequency at which it is created depends on the harmonic being referred to.

Frequency of harmonics

If the fundamental frequency of a harmonic is 7 Hz, then the frequency at which the harmonic is created depends on the harmonic series being used.

The frequency of the nth harmonic in a harmonic series is equal to n times the fundamental frequency. Therefore, the first five harmonics of a harmonic series with a fundamental frequency of 7 Hz would be:

First harmonic (fundamental): 7 Hz

Second harmonic: 2 x 7 Hz = 14 Hz

Third harmonic: 3 x 7 Hz = 21 Hz

Fourth harmonic: 4 x 7 Hz = 28 Hz

Fifth harmonic: 5 x 7 Hz = 35 Hz

So, the frequency at which the harmonic with a fundamental frequency of 7 Hz is created depends on which harmonic is being referred to.

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Answer:

= weather

Explanation:

The rotational kinetic energy (in J) of Jupiter in its orbit around the Sun is 1.613 × 10³⁵ J

Rotational kinetic energy is kinetic energy due to rotation about an axis.

The rotational kinetic energy is given by K = 1/2Iω² where

So, We have that the rotational kinetic energy of Jupiter is

K = 1/2Iω²

K = 1/2(MR²)(2π/T)²

K = 1/2(MR²)(4π²/T²)

K = 2π²MR²/T²

Substituting the values of the variables into the equation, we have that

K = 2π²MR²/T²

K = 2π² × 1.898 × 10²⁷ kg × (7.78 × 10¹¹ m)²/(3.74976 × 10⁸ s)²

K = 2π² × 1.898 × 10²⁷ kg × 60.5284 × 10²² m²/14.0607 × 10¹⁶ s²

K = 2π² × 114.8829 × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²

K = 229.7658π² × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²

K = 16.3410π² × 10³³ kgm²/s²

K = 161.2791 × 10³³ kgm²/s²

K = 1.612791 × 10³⁵ kgm²/s²

K ≅ 1.613 × 10³⁵ J

So, the  rotational kinetic energy is 1.613 × 10³⁵ J

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Ghosts are the souls of people who have died cannot be tested experimentally.

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Answer:

lithium atom

Explanation:

If you search up lithium atom the same atom will come out.

Sorry if it's wrong.

Answer:

C

D

Explanation:

Without falling off the merry-go-round, the guy can stand up to a distance of roughly 1.42 m from the axis of rotation.

This equation demonstrates how the square of the angular velocity and the moment of inertia are inversely related to the kinetic energy of a spinning rigid body.

The sources of the centrifugal force are:

F = m r ω²

The formula for static friction's force is

F_friction = μ_s N

The weight of a man is equal to the normal force N, which is determined by:

N = m g

The centrifugal force equals the static friction force at the point where the man is about to slide, hence we have:

F = F_friction

m r ω² = μ_s N

Substituting N = m g, we get:

r = (μ_s g) / ω²

Substituting μ_s = 0.35, g = 9.81 m/s², and ω = 2.5 rad/s, we get:

r = (0.35 x 9.81 m/s²) / (2.5 rad/s)² ≈ 1.42 m

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Answer:

The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.

Explanation:

your welcome

The equation for finding speed is given by v = (x₂ - x₁) / (t₂ - t₁), where x is the displacement and t is the corresponding interval. The speed of the walking dude remains constant at 2 m/s.

To find the speed of Walking Dude, using  v = (x₂ - x₁) / (t₂ - t₁), insert the values for x and t.

For t = 0 and 2 seconds, the displacement is x = 0 and 4 meters respectively. So,

v = (4 - 0) / (2 - 0) = 4 m/s

For t = 2 and 4 seconds, the displacement is x = 4 and 8 meters respectively. So,

v = (8 - 4) / (4 - 2) = 2 m/s

For t = 4 and 6 seconds, the displacement is x = 8 and 12 meters respectively. So,

v = (12 - 8) / (6 - 4) = 2 m/s

For t = 6 and 8 seconds, the displacement is x = 12 and 16 meters respectively. So,

v = (16 - 12) / (8 - 6) = 2 m/s

Thus, the speed of Walking Dude remains constant at 2 m/s during the entire time period.

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1. The magnitude (in N) of the electric force that one particle exerts on the other is 6.68×10⁻⁸ N

2. The force is repulsive

Colulomb's law states as follow:

F = Kq₁q₂ / r²

Where

With the above formula, we can determine the force as illustrated below:

The following data were obtained from the question:

F = Kq₁q₂ / r²

F = (9×10⁹ × 7.24×10⁻⁹ × 3.78×10⁻⁹) / (1.92)²

F = 6.68×10⁻⁸ N

Thus, the magnitude of the force that one particle exert on the other is 6.68×10⁻⁸ N

The force is repulsive since the charges on each particle has the same sign

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There are 90 phones of volume, 10-7 W/m2 of sound intensity, and 0.0314 watts of source power.

A straightforward frequency analysis compares the values of the fields you provide and generates a report listing each value for those fields along with the frequency at which each value occurs.

The rate at which a sound power wave repeats itself, also known as frequency or pitch, is measured in cycles per second. Bullfrog calls and cricket chirps have lower frequencies than drum beats and whistles, respectively.

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Answer:

μ = 0.498

Explanation:

I manage to find the picture of this problem. In the attached picture you can also see the forces involved in this case.

We know according to newton's law that the static friction force is:

Fs = μ * N

However, as you can see in the picture, the Normal force is equals to the weight, in this case the weight of the painter and also the ladder, therefore:

N = Fy

and the force of the friction is:

Fs = Fx

Therefore the coefficient is:

μ = Fx/Fy  (1)

Now, let's write the equations in x and y, to solve this.

For the "x" axis:

Fx - Fw = 0 -----> Fx = Fw   (2)

Fw is force of the wall, while Fx is the force friction in the x axis (base of the ladder).

for the "y" axis:

Fy - W1 - W2 = 0

W1 = mg (ladder)

W2 = Mg (painter)

replacing we have:

Fy = W1 + W2

Fy = mg + Mg ----> Fy = g(m + M)    (3)

To get the force that the wall is exerting we need to calculate the torque around the foot of the ladder so:

τ = rF sinθ

However, the angle in the wall and the ladder is 90° so:

τ = rF sin90°

τ = rF   (4)

replacing (4) with the forces we have:

rFw = rW1 + rW2

4Fw = 1.5mg + 2.1Mg

Fw = 1.5mg + 2.1Mg/4   (5)

Finally, with this expression, we can replace it in (1) to get the coefficient of friction:

μ = Fx/Fy

μ = 1.5mg + 2.1Mg / 4g(m + M)     gravity cancels out so:

μ = 1.5m + 2.1M / 4(m + M)

Replacing the data we finally have:

μ = (1.5 * 2) + (2.1 * 55) / 4 (55 + 12)

μ = 133.5 / 268

The coefficient of static friction between the ladder and the floor is 0.5.

From the image:

\(n=F_{GY},F_s^{max}=F_{GX}\\\\F_s^{max}=\mu_sn\\\\F_{GX}=\mu_sF_{GY}\\\\sum \ of\ horizontal\ force\ is\ 0:F_{GX}-F_W=0;F_{GX}=F_W\\\\sum \ of\ vertical\ force\ is\ 0:F_{GY}-mg-Mg=0;F_{GY}=g(m+M)\\\\\\Total\ torque\ at\ point\ A(foot\ of\ ladder)=0, hence:\\\\mg(1.5)+Mg(2.1)-F_W(4)=0\\\\mg(1.5)+Mg(2.1)=F_W(4)\\\\mg(1.5)+Mg(2.1)=F_{GX}(4)\\\\mg(1.5)+Mg(2.1)=\mu_sF_{GY}(4)\\\\mg(1.5)+Mg(2.1)=\mu_sg(m+M)(4)\\\\\mu_s=\frac{mg(1.5)+Mg(2.1)}{4g(m+M)} \\\\\)

\(\mu_s=\frac{12(1.5)+55(2.1)}{4(12+55)} \\\\\mu_s=0.5\)

Hence, the coefficient of static friction between the ladder and the floor is 0.5.

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The weight of the aluminum foil is 26.20 N

To find the weight of the aluminum foil when it is unrolled, we need to find its volume.

The volume V = lwt where

So, V = lwt

= 22 m × 0.30 m × 0.15 × 10⁻³ m

= 0.99 × 10⁻³ m³.

So, its weight W = ρV where

So, W = ρV

W = 26460 N/m³ × 0.99 × 10⁻³ m³

W = 26195.4 × 10⁻³ N

W = 26.1954 N

W ≅ 26.20 N

So, the weight of the aluminum foil is 26.20 N

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Answer:

Each connection requires 50 centimeters of wire, which is equal to 0.5 meters of wire. Therefore, for eight connections, the electrician would need:

8 * 0.5 = 4 meters of wire

Therefore, the correct answer is option D, 4 m.

:

The ball passes through half the maximum height on the way up and down at approximately 1.28 seconds.

To determine the maximum height reached by the baseball and the times at which it passes through half the maximum height on the way up and down, we can use the equations of motion for vertical motion.

Maximum height (hmax):

The initial velocity (u) is 12.5 m/s and the acceleration due to gravity (g) is -9.8 m/s^2 (negative because it acts downward). The maximum height reached by the ball can be calculated using the equation:

hmax = (u^2) / (2g)

Substituting the given values:

hmax = (12.5^2) / (2 * 9.8) ≈ 8.04 meters

Therefore, the maximum height reached by the ball is approximately 8.04 meters.

Time at half maximum height (t1/2, up and t1/2, down):

The time taken for the ball to reach half the maximum height on the way up and on the way down will be the same. We can calculate this time using the equation:

t1/2 = (u - v) / g

Where v is the final velocity, which is 0 m/s at the highest point of the trajectory.

t1/2 = (12.5 - 0) / 9.8 ≈ 1.28 seconds

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( a ) The magnitude of the impulse given to the meteor is 2,480,000 kg.m/s at 22⁰ from original position.

( b ) The magnitude of the force applied to the meteor is 55,111.1 N.

The magnitude of the impulse given to the meteor is calculated from the change in momentum of the meteor.

Mathematically, the formula for Impulse is given as;

J = ΔP

J = m (vf - vi )

where;

The magnitude of the impulse given to the meteor is calculated as follows;

J = ( 310, 000 kg ) ( 27 m/s - 35 m/s )

J = ( 310, 000 kg ) ( -8 m/s )

J = -2,480,000 kg.m/s

| J | = 2,480,000 kg.m/s

The magnitude of the force applied to the meteor is calculated as follows;

F = ma = J / t

where;

F = ( 2,480,000 kg.m/s ) / ( 45 s )

F = 55,111.1 N

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Answer:

The energy stored is 1.4 x 10^-9 J.

Explanation:

Side of square, L = 10 cm = 0.1 m

Distance, d = 2 mm = 0.002 m

Electric field, E = 4000 V/m

The energy stored in the capacitor is

\(U = 0.5 C V^2\)

The capacitance is given by

\(C = \frac{\varepsilon o A}{d}\\\\So \\\\U = 0.5\frac{\varepsilon o A}{d}\times E^2 d^2\\\\U = 0.5\times 8.85\times 10^{-12}\times 0.1\times 0.1\times 4000\times 4000\times 0.002\\\\U = 1.4\times10^{-9} J\)

Answer:

Substitute the numbers for YOUR problem this is NOT the answer.

Explanation:

By using Specific heat capacity, 741.76 x \(10^4\)heat energy is needed to raise the temperature.

The amount of heat required to increase the temperature of 1 gram of a substance by 1 degree Celsius (°C) is known as the specific heat capacity.

The importance of specific heat capacity may be summed up as the quantity of energy needed to heat or cool an item of a given mass by a certain amount.

Given:

Mass of vat, mvat = 20kg

Mass of water, mwater = 3kg

ΔT = 90 – 10 = 80℃

Specific heat capacity of iron, Ciron = 450J/kg

Specific heat capacity of water, Cwater = 4186J/kg

To find:

Heat energy required, Q = ?

Formula:

C = Q / (m ΔT)

Calculations:

Q = mCΔT

Q = Qempty + Qwater

Q = (20 x 450 x 80) + (3 x 4186 x 80)

Q = 172.464 x \(10^4\)J

Result:

Heat energy required is 172.464 x \(10^4\)J

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Given:

The masses of the balls, m₁=1 kg

m₂=2 kg

The height of 1 kg ball, h₁=6 m

The height of 2 kg ball, h₂=3 m

To find:

Which of the given statements are true?

Explanation:

From the law of conservation of energy, the energy can neither be created nor be destroyed. As the air resistance is negligible, the initial potential energy of the balls will be equal to their kinetic energy when they reach the ground.

Thus, the kinetic energy of the balls when they reach the ground is given by,

Where m is the mass of the balls, h is their respective height, and g is the acceleration due to gravity.

Thus the kinetic energy of mass m₁ is,

The kinetic energy of mass m₂ is,

The velocities of the balls will be given by the equation of kinetic energy.

Thus,

Where v is the respective velocities of the balls when they reach the ground.

On rearranging the above equation, the velocities will be given by,

On substituting the known values, the velocity of the mass m₁ is

The velocity of the mass m₂ is,

Thus the balls will have the same kinetic energies when they reach the ground. But the 1 kg ball will have a greater velocity than the 2-kg ball.

The time interval the ball takes is dependent on the height only and not on the mass. Thus the balls will not reach the ground at the same time.

Final answer:

Thus the correct answer is options are option B and option D.

here's your correct answer.. please copy it..

Answer:

Below

Explanation:

Change in v = 5-2 = 3 m/s

Change in momentum =  m * change in v = 1 * 3 = 3  kg m/s

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

The initial velocity after leaving the table is the same as it was before leaving the table (nothing is present to produce discontinuties in the velocity).

Before leaving the table the vertical velocity was zero and is zero when it leaves the table.

The horizontal velocity is constant with no forces present to change the velocity.

Answer:

Explanation:

yes because they relied on the sun and burned wood, straw, and dried dung when the sun failed them

Answer:

Explanation:

The thermal efficiency of a Power cycle \(\eta = \dfrac{Q_H -Q_c}{Q_H}\)

where;

\(\eta = 50\% = 0.5\)

\(Q_H = Heat \ flow \ from \ higher \ temperature\)

\(Q_c = Heat \ flow \ from \ lower \ temperature\)

\(0.5 = \dfrac{Q_H -Q_c}{Q_H}\)

\(0.5 Q_H = Q_H - Q_c\) --- (1)

\(Q_c = 0.5 Q_H\)         ---- (2)

The coefficient of performance is:

\(COP_R = \dfrac{Q_c}{Q_H -Q_c}\)

let replace the value of \(Q_c = 0.5 Q_H\)   in the above equation then;

\(COP_R = \dfrac{0.5Q_H}{Q_H -0.5 Q_H}\)

\(COP_R = \dfrac{0.5Q_H}{0.5 Q_H}\)

\(COP_R = 1\)

The

On the other hand,  the heat pump

\(COP_{HP} = \dfrac{Q_H}{Q_H -Q_c}\)

By replacing equation (1) into the above equation; we have:

\(COP_{HP} = \dfrac{Q_H}{0.5Q_{H}}\)

\(COP_{HP} = \dfrac{1}{0.5}\)

\(COP_{HP} =2\)

t