I NEED HELP ON THIS ASAP!!!!

The coordinates of the midpoint of the given segment is; (-15, 4)

For any specific line segment, it is well known that the midpoint is defined as the halfway between its two endpoints. The expression that is used to find the x-coordinate of that midpoint is expressed as: [(x)1 + (x)2]/2, which denotes the average of the x-coordinates. Similarly, the expression that is used to find the y-coordinate of that midpoint is expressed as: [(y)1 + (y)2]/2, which is the average of the y-coordinates.

We are given the coordinates of the endpoints of the line as;

K(-11, 2) and L(-19, 6)

Thus;

Midpoint Coordinate = (-11 - 19)/2, (2 + 6)/2

= (-15, 4)

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The specific solution depends on the given matrix A.

To find a basis for each of the subspaces r(AT), N(A), r(A), and N(AT), we first need to understand what each of these terms represents:

1. r(AT) - the row space of the transpose of matrix A
2. N(A) - the null space of matrix A
3. r(A) - the row space of matrix A
4. N(AT) - the null space of the transpose of matrix A

To find a basis for each of these subspaces, follow these general steps:

1. For r(A) and r(AT), row reduce the matrix A and its transpose AT to their row echelon forms. The non-zero rows in the reduced matrices will form a basis for the row spaces.

2. For N(A) and N(AT), set up the homogenous system of linear equations (Ax = 0 and ATx = 0), where x is the vector of variables. Then, solve the systems using Gaussian elimination, and find the general solutions. The general solutions will provide the basis vectors for the null spaces.

Note that specific solutions depend on the given matrix A. The process outlined above will help you find the basis for each of the subspaces r(AT), N(A), r(A), and N(AT) once you have the matrix A.

The correct question should be :

What is the matrix A for which you would like to find the basis for each of the subspaces r(AT), N(A), r(A), and N(AT)?

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Answer:

=42+115x

10x

Step-by-step explanation:

3(7/5x+ 4) – 2( 3/2- 5/4)

=21/5x+12-2(6/4-5/4)

=21/5x+12-2×1/4

=21/5x+12-1/2

=21/5x+24/2-1/2

=21/5x+23/2

=42/10x+115x/10x

=42+115x

10x

Answer:

Step-by-step explanation:

The volume of a cylinder is

\(V=h\pi r^2\\ \\ h=8,\ r=4\\ \\ V=8\pi (4^2)\\ \\ V=8(16)\pi \\ \\ V=128\pi \units^3\)

Answer:

  (B) 146 feet

Step-by-step explanation:

You want to know the maximum height of a pebble whose height is described by p(t) = -16t² + 48t + 110.

We can write the equation in vertex form as follows:

  p(t) = -16(t² -3t) +110

  p(t) = -16(t² -3t +2.25) +110 +16(2.25)

  p(t) = -16(t -1.5)² +146

This shows the vertex of the quadratic curve to be (1.5, 146).

The maximum height of the pebble is 146 feet.

Answer:

container A

Step-by-step explanation:

In Container A, we can plot the points (0,60) adn (2, 35)

The slope is :

\(m_A = \frac{y_2-y_1}{x_2-x_1} \\\\= \frac{35-60}{2-0} \\\\= \frac{-25}{2}\\ \\m_A = -12.5\\\)

For container B, the slope is:

\(m_B = \frac{y_2-y_1}{x_2-x_1} \\\\= \frac{32-54}{3-1} \\\\= \frac{-22}{2}\\ \\m_B = -11\\\)

The negative sign of the slope indicates the direction of the slope

\(|m_A| = 12.5\\\\|m_B| = 11\)

12.5 > 11

The slope of container A is steeper than container B

Therefore, the water is draining out of container A at a faster rate than container B

The probability of obtaining a head on the next toss of a coin after obtaining two heads from two tosses is still 1/2 or 50%.

This is because each coin toss is an independent event, and the outcome of one toss does not affect the outcome of another toss. Therefore, the fact that two heads have been obtained in the previous two tosses does not change the probability of obtaining a head on the next toss, which is always 1/2 or 0.5 for a fair coin.

Probability is the likelihood of an event occurring. The values are between 0 and 1. The closer it is to 1, the greater the probability.

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Answer:

43.5F

Step-by-step explanation:

All you need to do is subtract 15.70 from 59.20

Answer:Z

cos x dx = sin x + C

Z

sec2 x dx = tan x + C

Z

sec x tan x dx = sec x + C

Z

1

1 + x2

dx = arctan x + C

Z

1

√

1 − x2

dx = arcsin x + C

8.1 Substitution

Needless to say, most problems we encounter will not be so simple. Here’s a slightly more

complicated example: find

Z

2x cos(x

2

) dx.

This is not a “simple” derivative, but a little thought reveals that it must have come from

an application of the chain rule. Multiplied on the “outside” is 2x, which is the derivative

of the “inside” function x

2

. Checking:

d

dx sin(x

2

) = cos(x

2

)

d

dxx

2 = 2x cos(x

2

),

so Z

2x cos(x

2

) dx = sin(x

2

) + C.

Even when the chain rule has “produced” a certain derivative, it is not always easy to

see. Consider this problem:

Z

x

3

p

1 − x

2 dx.

There are two factors in this expression, x

3

and p

1 − x

2, but it is not apparent that the

chain rule is involved. Some clever rearrangement reveals that it is:

Z

x

3

p

1 − x

2 dx =

Z

(−2x)

−

1

2

(1 − (1 − x

2

))p

1 − x

2 dx.

This looks messy, but we do now have something that looks like the result of the chain

rule: the function 1 − x

2 has been substituted into −(1/2)(1 − x)

√

x, and the derivative

Step-by-step explanation:Z

cos x dx = sin x + C

Z

sec2 x dx = tan x + C

Z

sec x tan x dx = sec x + C

Z

1

1 + x2

dx = arctan x + C

Z

1

√

1 − x2

dx = arcsin x + C

8.1 Substitution

Needless to say, most problems we encounter will not be so simple. Here’s a slightly more

complicated example: find

Z

2x cos(x

2

) dx.

This is not a “simple” derivative, but a little thought reveals that it must have come from

an application of the chain rule. Multiplied on the “outside” is 2x, which is the derivative

of the “inside” function x

2

. Checking:

d

dx sin(x

2

) = cos(x

2

)

d

dxx

2 = 2x cos(x

2

),

so Z

2x cos(x

2

) dx = sin(x

2

) + C.

Even when the chain rule has “produced” a certain derivative, it is not always easy to

see. Consider this problem:

Z

x

3

p

1 − x

2 dx.

There are two factors in this expression, x

3

and p

1 − x

2, but it is not apparent that the

chain rule is involved. Some clever rearrangement reveals that it is:

Z

x

3

p

1 − x

2 dx =

Z

(−2x)

−

1

2

(1 − (1 − x

2

))p

1 − x

2 dx.

This looks messy, but we do now have something that looks like the result of the chain

rule: the function 1 − x

2 has been substituted into −(1/2)(1 − x)

√

x, and the derivative

 We found the PMF f(x),  calculated the probability of selecting exactly one defective unit, and  determined the probability of selecting more than one defective unit.

To find the probability mass function (PMF) f(x) for the number of defective units, we need to determine the probability of each possible outcome.

Let's assume that the total number of units tested is n. Since it is mentioned that 2% of the units are defective, the probability of selecting a defective unit is 0.02.

The PMF f(x) can be calculated using the binomial distribution formula:
\(f(x) = C(n, x) * (0.02)^x * (0.98)^(n-x)\)

To find p(x=1), we substitute x=1 into the PMF formula:
\(f(1) = C(n, 1) * (0.02)^1 * (0.98)^(n-1)\)

This represents the probability of selecting exactly one defective unit when testing a batch of pedometers.

Similarly, to find p(x>1), we need to sum up the probabilities for x=2, x=3, and so on, up to x=n:
\(p(x>1) = f(2) + f(3) + ... + f(n)\)
This represents the probability of selecting more than one defective unit when testing a batch of pedometers.

To sketch the histogram, we can plot the values of x on the x-axis and the corresponding probabilities f(x) on the y-axis. Each bar's height represents the probability of selecting that many defective units.

In conclusion, we found the PMF f(x), calculated the probability of selecting exactly one defective unit, and  determined the probability of selecting more than one defective unit.

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Answer:

its 1/2

Step-by-step explanation:

Answer:

math

Step-by-step explanation:

You can take LCM and then can add to see what's the sum.

The sum result of given expressions is given by: \(\dfrac{5}{y+5}\)

You can take LCM and then can add to see whats the sum.

\(\begin{aligned}\dfrac{3y}{y^2 + 7y + 10} + \dfrac{2}{y+2} &= \dfrac{3y}{(y+2)(y+5)} + \dfrac{2}{y+2}\\&= \dfrac{3y + 2(y+5)}{(y+2)(y+5)}\\&= \dfrac{5y+10}{(y+2)(y+5)}\\&= \dfrac{5(y+2)}{(y+2)(y+5)}\\&= \dfrac{5}{y+5}\\\end{aligned}\)

Thus, the sum of given expressions is given by:

\(\dfrac{5}{y+5}\)

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To find the average value of the function f(x, y) = 8x + 5y over the given triangle, we need to calculate the double integral of f(x, y) over the region and then divide it by the area of the triangle.

The vertices of the triangle are (0, 0), (2, 0), and (0, 7). We can set up the integral as follows:

∬R f(x, y) dA = ∫₀² ∫₀ᵧ (8x + 5y) dy dx

Integrating with respect to y first, the inner integral becomes:

∫₀ᵧ (8x + 5y) dy = 8xy + (5y²/2) |₀ᵧ = 8xᵧ + (5ᵧ²/2)

Now integrating with respect to x, the outer integral becomes:

∫₀² (8xᵧ + (5ᵧ²/2)) dx = (4x²ᵧ + (5ᵧ²x)/2) |₀² = (8ᵧ + 10ᵧ² + 20ᵧ)

To find the area of the triangle, we can use the formula for the area of a triangle: A = (1/2) * base * height.

The base of the triangle is 2 and the height is 7.

A = (1/2) * 2 * 7 = 7

Finally, to find the average value, we divide the double integral by the area of the triangle:

Average value = (8ᵧ + 10ᵧ² + 20ᵧ) / 7

Simplifying this expression gives:

Average value = (8 + 10ᵧ + 20ᵧ) / 7 = (8 + 10(7) + 20(7)) / 7 = 142/7 = 20 2/7

Therefore, the correct answer is not listed among the options provided.

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P(|X-Y|≤1) = P(X=Y) + P(|X-Y| = 1) = 6/25 + 6/25 = 12/25 Answer: a) c=1/25; b) P(X=0 and Y=2)=2/25;

a) The probability mass function (PMF) is given as;f X,Y
​
(x,y)={ c∣x+y∣
0
​
if x,y∈{−2,−1,0,1,2}
otherwise. ​
For a joint PMF, the sum of probabilities across all x and y must be equal to 1. Therefore;∑∑f X,Y
​
(x,y)=1
The sum of the probabilities when (x,y) is not an element of {−2,−1,0,1,2} is zero, and there are 25 other possibilities. When |x+y| = 0, there are four possibilities: (0, 0), (−1, 1), (1, −1) and (2, −2).∑∑f X,Y
​
(x,y)=4c+4c+4c+3c+4c+3c+2c+2c+2c+1c+1c+0+1c+2c+3c+4c+3c+4c+4c+4c+0+4c+4c+4c=25

c=1
Hence, the value of the constant c is; c=1/25
b) For P(X = 0 and Y = 2), there is only one possibility, and that is when X = 0 and Y = 2. Therefore;P(X = 0 and Y = 2) = f X,Y
​
(0,2) = c|0+2| = c×2 = 2/25
c) The marginal distribution of X is given as;f X
​
(x)=∑yf X,Y
​
(x,y)
The possible values of X are -2, -1, 0, 1, 2. The probabilities are as follows:

For x = -2, f X
​
(-2) = (0+0+0+0+1)c = c
For x = -1, f X
​
(-1) = (0+0+0+1+2)c = 3c
For x = 0, f X
​
(0) = (0+0+1+2+1)c = 4c
For x = 1, f X
​
(1) = (0+1+2+1+0)c = 4c
For x = 2, f X
​
(2) = (1+2+1+0+0)c = 4c
Hence, the marginal distribution of the random variable X is given by;f X
​
(-2) = 1/25, f X
​
(-1) = 3/25, f X
​
(0) = 4/25, f X
​
(1) = 4/25, f X
​
(2) = 4/25
d) To evaluate P(|X-Y|≤1), we consider the cases where |X-Y| = 0 or 1. When |X-Y| = 0, this means that X = Y. Therefore;P(X = Y) = ∑xP(X = x and Y = x) = f X,Y
​
(−2,−2)+f X,Y
​
(−1,−1)+f X,Y
​
(0,0)+f X,Y
​
(1,1)+f X,Y
​
(2,2)
= (1+2+1+1+1)c = 6c = 6/25
When |X-Y| = 1, there are four possible pairs; (−1,0), (0,−1), (0,1) and (1,0).P(|X-Y| = 1) = ∑i∑jP(X = i and Y = j) where i and j are any two of −1, 0, 1
= f X,Y
​
(−1,0)+f X,Y
​
(0,−1)+f X,Y
​
(0,1)+f X,Y
​
(1,0)
= (0+0+2+2+2)c = 6c = 6/25

c) The marginal distribution of X is given by; f X
​
(-2) = 1/25, f X
​
(-1) = 3/25, f X
​
(0) = 4/25, f X
​
(1) = 4/25, f X
​
(2) = 4/25; d) P(|X-Y|≤1)=12/25

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Answer: Let's be honest, no one knows the answer. Unless you want to pay coursehero $9.95/mo for an answer and step-by-step explanation, you're toast.

Some of my answers are absolutely amazing, and actually helpful. But some of my answers are not.

A lot of the time, Brainly's "Expert Verified Answers" are very incorrect, and even if you report it, Brainly does not care.

So, if Brainly ITSELF can't answer a question properly, well,

Simply put, your grade is toast.

And if Brainly deletes this absolutely wonderful fantastic answer, that just means that they are acknowledging that these "Expert Verified Answers" are not as "expert" as they may think they are.

:|

Answer:

What do you need help with?

Step-by-step explanation:

Answer:

Eat dino nuggies

Step-by-step explanation:

The incorrect statement about the intersecting triangles is A. CG ≅ FG.

With intersecting triangles, it is not always guaranteed that segments like CG and FG will be congruent. The lengths of CG and FG will depend on the specific configuration of the chords and their intersection point G.

However, CE/EG = FD/DG statement is TRUE. This is a consequence of the Intersecting Chords Theorem. When two chords intersect inside a circle, the products of their segments are equal.

Since ∠CEG ≅ ∠FDG intersect inside a circle, the corresponding intercepted arcs create equal angles at the intersection point. Therefore the statement is true.

ΔCEG ~ ΔFDG is also true because we know that the triangles share an angle and have proportional sides.

The answer above is in response to the full question below;

In the diagram of circle A shown below , chords CD and EF intersect at G, and chords CE and FD and drawn

Which statements is not always true?

a. CG ≅ FG    

b. CE/EG = FD/ DG

c. ∠CEG ≅ FDG  

d. ΔCEG ~ ΔFDG

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Step-by-step explanation:

Here,

y= 2x

and x € (1,2,3)

now,

when x=1 , when x=2 , when x= 3

y=2x y= 2x y=2x

= 2×1 = 2×2 = 2×3

= 2 = 4 = 6

Therefore, y = (2,3,6)

Answer:

2 because the initial value is y-intercept

39 subjects were tested in this simple one-way ANOVA.

The df for F distribution is (treatment df, error df)

Using given information

Treatment df = 7

Error df = 31

Total df= 7+31 = 38

Again, total df = N-1, N= number of subjects tested

Then, N-1 = 38

=> N= 39

One-way ANOVA is typically used when there is a single independent variable or factor and the goal is to see whether variation or different levels of that factor have a measurable effect on the dependent variable.

The t-test is a method of determining whether two populations are statistically different from each other, and ANOVA determines whether three or more populations are statistically different from each other.

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The radius of convergence is 0, and the interval of convergence is the single point x = 0.

To obtain the radius of convergence and interval of convergence of the series we can use the ratio test.

\(\[ \sum_{n=1}^{\infty} \frac{2 \cdot 4 \cdot 6 \cdots (2n)}{3 \cdot 5 \cdot 7 \cdots (2n+1)}x^{2n+1} \]\)

The ratio test states that if \(\( L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \)\), then the series converges if \(\( L < 1 \)\) and diverges if \(\( L > 1 \). If \( L = 1 \)\), the test is inconclusive.

Let's calculate the limit:

\(\[ L = \lim_{n \to \infty} \left| \frac{\frac{2 \cdot 4 \cdot 6 \cdots (2(n+1))}{3 \cdot 5 \cdot 7 \cdots (2(n+1)+1)}x^{2(n+1)+1}}{\frac{2 \cdot 4 \cdot 6 \cdots (2n)}{3 \cdot 5 \cdot 7 \cdots (2n+1)}x^{2n+1}} \right| \]\)

Simplifying the expression:

\(\[ L = \lim_{n \to \infty} \left| \frac{(2n+2)(2n+1)x^{2n+3}}{(2n+1)(2n)x^{2n+1}} \right| \]\)

\(\[ L = \lim_{n \to \infty} \left| \frac{(2n+2)x^2}{x^2} \right| \]\)

\(\[ L = \lim_{n \to \infty} 2(n+1) = \infty \]\\\)

Since the limit is infinity, the series diverges for all values of  x , except when x = 0 and hence the radius of convergence is 0, and the interval of convergence is the single point x = 0.

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Answer:

2

Step-by-step explanation:

BIDMAS
(Brackets, Indices, division, multiply, add, sub)
so lets do the bracket first
(3^2+5)
We treat this as another question so we do 3^2 which is 9, 9+5=14
30 - 2(14)
we then multiply
30-28
finally subtract = 2

Answer:

2

Step-by-step explanation:

\(30-2(3^2+5)\\=30-2(9+5)\\=30-2(14)\\=30-28\\=2\)

Remember PEMDAS (Parentheses, Exponents, Multiplication/Division left to right, Addition/Subtraction left to right)

Check the picture below.

Answer:

√48/75, I think.

Step-by-step explanation:

Not quite sure.

Answer:

\(\sqrt{\frac{46}{75} }\)

Step-by-step explanation:

\(\sqrt{1 \times 46 \div 75}\)

Simplify.

\(\sqrt{\frac{46}{75} }\)

We can perform a change of units to see that 280 square centimeters is equivalent to 0.028 square meters.

We want to perform a change of units between square centimeters and meters.

Remember the relation:

100cm = 1m

Now we can square both sides of that equation, then we will get:

(100 cm)^2  = (1m)^2

10,000 cm^2 = 1m^2

Then if we have a measure in square centimeters, to transform it into square meters we need to divide that measure by 10,000.

Then:

280 cm^2 = (280/10,000) m^2 = 0.028 m^2

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Answer:

Step-by-step explanation:

https://www.numerade.com/questions/write-the-equation-for-the-graph-that-is-shown-check-your-book-to-see-graph-3/

Ted can mow the lawn in 5 minutes by using his power mower. Galen takes 15 minutes to mow the same lawn using a push-type mower.

Let's calculate the amount of work done by Ted in 1 minute.WORK = 1/5Let's calculate the amount of work done by Galen in 1 minute.WORK = 1/15

Let's calculate the amount of work done by both of them working together in 1 minute. WORK = 1/5 + 1/15 Simplify, LCM of 5 and 15 = 15 So, 3/15 + 1/15 = 4/15Hence, working together Ted and Galen can mow the lawn in 15/4 or 3.75 minutes or 3 minutes and 45 seconds.

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Step-by-step explanation:

\(\large\underline{\sf{Solution-}}\)

\(\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)\)

Let assume that

\(\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)\)

We know,

\(\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}\)

So, using this, we get

\(\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)\)

Now, we use Method of Substitution, So we substitute

\( \red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}\)

So, above expression can be rewritten as

\(\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)\)

\(\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)\)

\(\rm\implies \:y = 2z\)

\(\bf\implies \:y = 2 {tan}^{ - 1}x\)

So,

\(\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x\)

Thus,

\(\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)\)

\(\rm \:  =  \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)\)

\(\rm \:  =  \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)\)

\(\rm \:  =  \: 2 \times \dfrac{1}{1 + {x}^{2} } \)

\(\rm \:  =  \: \dfrac{2}{1 + {x}^{2} } \)

Hence,

\( \purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}\)

Hence, Option (d) is correct.