To find the approximate area of the shaded region in this figure, we need to subtract the area of the smaller circle from the area of the larger circle. The radius of the larger circle is 6 feet and the radius of the smaller circle is 3 feet.
The formula for the area of a circle is A = πr^2, where π is approximately 3.14 and r is the radius.
So, the area of the larger circle is A = 3.14 x 6^2 = 113.04 square feet.
The area of the smaller circle is A = 3.14 x 3^2 = 28.26 square feet.
To find the area of the shaded region, we subtract the area of the smaller circle from the area of the larger circle:
Area of shaded region = 113.04 - 28.26 = 84.78 square feet (rounded to two decimal places).
Therefore, the approximate area of the shaded region in this figure is 84.78 square feet.
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John bought a computer scanner and supplies for $215.70, which will
allow him to scan images for $0.34 each. A computer center charges
$0.59 to scan each image. How many images must John scan before
his total cost is less than getting scanned images at the computer
center?
John must scan more than 862 images before his total cost is less than getting scanned images at the computer center.
To determine how many images John must scan before his total cost is less than getting scanned images at the computer center, we can set up an equation.
Let's denote the number of images John needs to scan as "x."
The total cost for John to scan x images is given by:
John's total cost = cost of scanner + cost of supplies + cost per image scanned
John's total cost = $215.70 + ($0.34 * x)
The total cost for scanning x images at the computer center is given by:
Computer center's cost = cost per image scanned * x
Computer center's cost = $0.59 * x
We want to find the point at which John's total cost is less than the computer center's cost. In other words, we want to find the value of x for which John's total cost is less than the computer center's cost:
John's total cost < Computer center's cost
$215.70 + ($0.34 * x) < $0.59 * x
Now, we can solve for x:
$215.70 + ($0.34 * x) < $0.59 * x
$215.70 < $0.59 * x - $0.34 * x
$215.70 < $0.25 * x
Divide both sides of the inequality by $0.25:
$\frac{215.70}{0.25} < \frac{0.25 * x}{0.25}$
862.80 < x
Therefore, John must scan more than 862 images before his total cost is less than getting scanned images at the computer center.
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The path that a football takes can be described by the equation h=25t-5t^2, where h is the height of the football at time t, in seconds.After how many seconds will it be 20 meters high?
1 - In order to solve this problem we have to solve the following equation
20 = 25t - 5t²
2 - In order to solve that equation we have to options
1 - Use the quadratic equation
2 - Factor the expression
For this probem we will facor the expression. The first thing that we will do is divide everything by 5, so we get
20/5 = ( 25/5 ) t - (5 / 5 ) t²
which would give us
4 = 5t - t²
Now we subtract 4 and we get
t² - 5t +4 = 0
then
t² - 5t +4 = (t - 4 ) (t - 1 ) = 0
Therefore there are two answers
t = 4
t = 1
Notice that the answer is correct because
h = 25(1) - 5*(1)² = 20
Find the relative maximum and minimum values of f(x,y) = x3/3 + 2xy + y2 - 3x + 1. 3
The critical point (1, -1) represents a relative minimum of f(x, y) with a value of -1/3 and (1, -1) is the only extremum or relative maximum of the function.
To find the relative maximum and minimum values of the function f(x, y) = (\(x^3\))/3 + 2xy +\(y^2\) - 3x + 1, we need to analyze its critical points and classify them using the second partial derivative test.
To find the critical points, we need to compute the partial derivatives of f with respect to x and y and set them equal to zero:
∂f/∂x = \(x^2\) + 2y - 3 = 0
∂f/∂y = 2x + 2y = 0
Solving these equations simultaneously, we find x = 1 and y = -1.
Thus, the critical point is (1, -1).
Next, we need to compute the second partial derivatives and evaluate them at the critical point:
∂²f/∂x² = 2
∂²f/∂y² = 2
∂²f/∂x∂y = 2
Now, we can use the second partial derivative test to classify the critical point.
The discriminant D = (∂²f/∂x²) × (∂²f/∂y²) - \(\left(\frac{{\partial^2 f}}{{\partial x \partial y}}\right)^2\) = (2)(2) - \((2)^2\) = 0.
Since D = 0, the test is inconclusive.
To determine the nature of the critical point, we can examine the function near the critical point.
Evaluating f at the critical point (1, -1), we find f(1, -1) = \((1^3)\)/3 + 2(1)(-1) + \((-1)^2\) - 3(1) + 1 = -1/3.
Hence, the critical point (1, -1) represents a relative minimum of f(x, y) with a value of -1/3.
There are no other critical points to consider, so we can conclude that (1, -1) is the only extremum of the function.
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PLEASE HELP ASAP
Which of the following tables represents a linear relationship that is also proportional? x −3 0 3 y −4 −2 0 x −2 0 2 y 0 3 6 x −3 0 3 y −4 −3 −2 x −3 0 3 y −2 0 2
The table that represents a proportional relationship is given as follows:
x −3 0 3
y −2 0 2
(which is the last option).
What is a proportional relationship?A proportional relationship is defined as follows:
y = kx.
In which k is the constant of proportionality.
From the definition, we have that a proportional relationship is a linear function with an intercept of zero, meaning that when x = 0, y = 0.
The last option is the only option for which the intercept of zero condition is satisfied, hence it is the correct option.
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please guys ano toh answer this
Answer: 15, 18, 21 (next three terms), Rule: Skip counting by 3
What is the rule to finding nth term?First calculate the common difference between the terms, If \(a_{1}, a_{2}, a_{3}, a_{4}.....\) are in sequence, the common difference is calculated by \((a_{2} -a_{1}), (a_{3} -a_{2}), (a_{4} -a_{3}) .......\)
Since, the common difference are equal so its clear that the given sequence is an Arithmetic Expression.
The nth term of the AP is an = a + (n-1)*d
1. Given: 3, 6, 9, 12, .....
Answer: 15, 18, 21 (next three terms)
Rule: Skip counting by 3
2. Given: 3, 5, 7, 9, .....
Answer: 11, 13, 15 (next three terms)
Rule: Skip counting by 1
3. Given: a, (a+b), (a+2b),.....
Answer: (a+3b), (a+4b), (a+5b) (next three terms)
Rule: nth term = a+(n-1)*b = a+nb-b
if we need 4th term, put n=4 so that 4th term= a+4b-b = (a+3b)
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Please help I’ll give brainliest if it’s correct !! :)))
Answer:
A textbook weighs about 1 pound and is about 1 foot long
A car weighs about 1 ton and is about 5 yards long
A mosquito weighs about 2 mg and is about 1 inch long
Step-by-step explanation:
#commonsense lol
Kaitlyn opens an account with an initial deposit of $7,250. The account earns 10% interest compounded annually. What is the amount of interest earned after 18 months if no additional money is deposited or withdrawn?
Answer:
the interest earned amount is $1,114.251
Step-by-step explanation:
The computation of the interest earned is shown below:
But before that the future value is
= Present value × (1 + rate of interest)^number of years
= $7,250 × (1 + 0.10)^1.5
= $7,250 × 1.10^1.5
= $8,634.251
Now the interets earned is
= $8,634.251 - $7,250
= $1,114.251
Hence, the interest earned amount is $1,114.251
The formula K=5/9(F-32)+273.15
converts temperatures from degrees Fahrenheit F to Kelvin K. An object in a laboratory is cooled to 2.5 Kelvin. What is the temperature of the object in degrees Celsius?
The temperature of this object in degrees Celsius is equal to -270.65°C.
What is temperature?Temperature can be defined as a measure of either the degree of hotness or coldness of a physical body (object).
In Science and Mathematics, temperature is measured by using a thermometer and its units include the following:
Kelvin (K) Fahrenheit (°F)Celsius (°C)How to convert the value of temperature from Fahrenheit (°F) to Celsius (°C)?In this exercise, you're required to convert the value of temperature in degree Fahrenheit (°F) to Celsius (°C). Therefore, we would use the following mathematical expression (formula) to perform the conversion:
C = K - 273.15
When t = 2.5 K, we have:
C = K - 273.15
C = 2.5 - 273.15
C = -270.65°C.
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12 and ⅔ divided by 4 and ½
Answer:
do it on a calculater
Step-by-step explanation:
but it equels 2 and 22║27
There are y narts to this question. Yiu war be anked to movide fint 1 answer in each part. In our dataset we obsenve thiee variables that we strangly befieve do not have a relabonhip with wages, but that are correlated with the endoeenour variable riciuct. These variables mee dixt, which denotes the distance between the wroticer's viliage and the closest school, wralh yofene. Which is a dummin variable that takes the value of 1 if the worker regularly brushes hiv/her teeth ithe eovemment provides a free toothbrunh to each citizen and we believe that more educated people tend to brush their teeth more offen, and library, which is a dummy variable that takes the value of 1 if the worker has access to a library in his/her viliage. We estimafe our regression model using TSIS We want to test if our instruments satisfy the relevance requirement. In the 1 st stage of TSLS we estimate the following equation: edue =π0+π1 diat +π2 aralhygiene +π1 hitrary +π4 erper +NH What is the null hypothesis to test for instruments' relevance? A) H0:π1=π2=π3=π4=0. B) H0:π1=π2=π3=0. C) H0:π2=π3=π4=0. D) H0:π2=0 or π3=0 or π4=0. E) HD:π1=0 or π2=0 or π3=0. F) H0:π1=0 or π2=0 or π3=0 or π4=0. Answer:
The null hypothesis to test for instruments' relevance is option D) H0:π2=0 or π3=0 or π4=0.In order to test the relevance of the instrument, the first stage equation's null hypothesis should be stated as: H0: π2 = 0 or π3 = 0 or π4 = 0.The relevance requirement will be fulfilled if we can refute the null hypothesis.
The null hypothesis will not be rejected if the F-statistic is less than 10.0. However, if the F-statistic is greater than 10.0, the null hypothesis will be rejected, indicating that the variables are relevant and that the instrument satisfies the relevance requirement.In summary, to test for instruments' relevance in TSLS, the null hypothesis of the first stage equation is stated as H0: π2 = 0 or π3 = 0 or π4 = 0.
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How do you know if triangles are congruent in SAS?
With the help of the figure we can say that triangles are congruent by SAS Rule
What is Congruence of Triangle?
Triangle congruence: Two triangles are said to be congruent if all three of their corresponding sides are equal and all three of their corresponding angles are equal in size. These triangles can be moved, rotated, flipped, and turned to look exactly the same.
Solution:
By SAS rule, two triangles are said to be congruent if any two sides and the angle included between the sides of one triangle are comparable to the corresponding two sides and the angle included between the sides of the second triangle.
In given figure, sides AB= PQ, BC=QR and angle between AB and BC equal to angle between PQ and QR i.e. ∠B = ∠Q. Hence, Δ ABC ≅ Δ PQR.
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The volume of a cylinder having height one and half of the radius is 12,936 m3 what minimum square cm of paper is needed to cover the curved surface area of the cylinder? The answer should be 1848m2. please solve my question.
Find the square root of the fraction 4/49.
A 2/7
B 7/2
C Cannot be done
Answer:
A
Step-by-step explanation:
2 times 2 = 4
7 times 7 = 49
2/7 = 4/49
Hope this helps!!!
Which situation can be represented by this equation?
7x + 1 = 10x
Answer:
1/3
Step-by-step explanation:
7x + 1 = 10x
1 = 10x - 7x
1 = 3x
1/3 = x
Answer: I just took the test so the answer would be...Brody went to two different amusement parks. The first park charged $7 per hour and gave a 1% discount for showing a student ID. The other park charged $10 per hour. What is x, the number of hours that Brody would have to stay at each park to have to pay the same amount?
Step-by-step explanation: hope this help thx for the points :D
What is the measure of y? 3 27 y Z * A y = [?] Give your answer in simplest form.
Applying the geometric theorem, the measure of y = 9.
What is the Geometric Theorem?The geometric theorem states that, h = √(ab), where h is the altitude of a right triangle, a nd b are the segments formed when the altitude divides the hypotenuse of a right triangle.
Thus:
y = altitude = ?
a = 3
b = 27
Substitute
y = √(3 × 27)
y = √81
y = 9
Therefore, applying the geometric theorem, the measure of y = 9.
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8.88=-2.22(x-7)
what is x
Answer:
x=3Step-by-step explanation:
Let's solve your equation step-by-step.
8.88=−2.22(x−7)
Step 1: Simplify both sides of the equation.
8.88=−2.22(x−7)
8.88=(−2.22)(x)+(−2.22)(−7) (Distribute)
8.88=−2.22x+15.54
Step 2: Flip the equation.
−2.22x+15.54=8.88
Step 3: Subtract 15.54 from both sides.
−2.22x+15.54−15.54=8.88−15.54
−2.22x=−6.66
Step 4: Divide both sides by -2.22.
−2.22x /−2.22
=
−6.66 /−2.22
x=3
do individuals walk at different speeds depending on whether they are departing or arriving at the level of significance? let represent the mean speed of people departing and represent the mean speed of people arriving. part 5 state the null and alternative hypothesis.
By conducting a statistical test, we can determine whether there is sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
H0: μ_departing = μ_arriving
Ha: μ_departing ≠ μ_arriving
To investigate whether individuals walk at different speeds depending on whether they are departing or arriving, we can set up the following null and alternative hypotheses:
Null Hypothesis (H0): The mean speed of people departing is equal to the mean speed of people arriving. In mathematical notation:
H0: μ_departing = μ_arriving
Alternative Hypothesis (Ha): The mean speed of people departing is not equal to the mean speed of people arriving. In mathematical notation:
Ha: μ_departing ≠ μ_arriving
In these hypotheses, μ_departing represents the population mean speed of individuals departing, and μ_arriving represents the population mean speed of individuals arriving.
The choice of significance level (α) will determine the threshold for rejecting the null hypothesis. Commonly used significance levels are 0.05 (5%) or 0.01 (1%).
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Find x 14, 12, 15, x
Answer: 15.4
Step-by-step explanation:
12(12 + 26) = 15(15 + x)
144 + 312 = 225 + 15x
456 = 225 + 15x
456 - 225 = 15x
231 = 15x
231/15 = x
x = 15.4
(15−x)∙4=10
pls pls answer asapppp
(15-12.5)*4=10
x=12.5
There are 52 cards in a standard deck. Thirteen of those cards are spades . The deck is shuffled and a group of 3 cards is dealt . How many different combinations of three spades are possible ?
Answer:1716
Step-by-step explanation:
13 spades is choice 1
13-1=12
12 spades are left in the draw to be taken so 13*12
12-1=11
11 spades are left so 13*12*11
Which point do the graphs of f and g have in common?
f(x) = log2x and
g(x) = log10x.
The point that the graphs of f and g have in common are (1,0)
How to get the points?The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
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Find the value of x in the triangle shown below.
Answer:
20
Step-by-step explanation:
This triangle can be solved using the Pythagorean theorem. 16^2+12^2=x^2. 16^2+12^2=400. If we set 400 equal to x^2, x=20.
Consider the equation -5\cdot e^{10t}=-30−5⋅e
10t
=−30minus, 5, dot, e, start superscript, 10, t, end superscript, equals, minus, 30.
Solve the equation for ttt. Express the solution as a logarithm in base-eee.
t=
Approximate the value of ttt. Round your answer to the nearest thousandth.
t=
The approximate equation is n = (ln 6)/10 and approximate value is n = 0.179.
What is Exponential equation?In mathematics, an exponential function is a function of form f (x) = aˣ, where “x” is a variable and “a” is a constant which is called the base of the function and it should be greater than 0.
Here, given equation; (we are using n in place of t)
-5.e¹⁰ⁿ = -30
On dividing -5 both sides, we get
-5.e¹⁰ⁿ/-5 = -30/-5
e¹⁰ⁿ = 6
Taking 'ln' on both side, we get
10n = ln 6
n = (ln 6)/10
n = 1.791759/10
n = 0.179
Thus, the approximate equation is n = (ln 6)/10 and approximate value is n = 0.179.
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Marco runs 22 miles in four hours. What is his unit rate?
Answer:
5.5
Step-by-step explanation:
Earlier in the assignment, matrix A =student submitted image, transcription available below
But the task doesn't specify if this question means that specific matrix, or just a genreal matrix A.
The questions are:
1) Prove that if A is a diagonally dominant matrix, then A is invertible.
2) Give an example of a 2x2 matrix that is invertible, but not diagonally dominant.
Matrix A serves as an example of a 2x2 matrix that is invertible but not diagonally dominant.
Prove that if A is a diagonally dominant matrix, then A is invertible:
To prove that a diagonally dominant matrix A is invertible, we can use the fact that a matrix is invertible if and only if its determinant is non-zero.
Let's assume A is a square matrix of size n x n. A matrix A is said to be diagonally dominant if the absolute value of each diagonal element is greater than the sum of the absolute values of the remaining elements in its corresponding row.
Mathematically, for each i in the range 1 to n, we have:
|A(i,i)| > ∑ |A(i,j)|, for j ≠ i
To prove that A is invertible, we need to show that det(A) ≠ 0.
Suppose, by contradiction, that det(A) = 0. This means that A is not invertible.
Since A is not invertible, there exists a non-zero vector x such that Ax = 0 (the zero vector).
Let's consider the i-th component of the vector Ax:
(Ax)(i) = ∑ A(i,j) * x(j), for j = 1 to n
Since Ax = 0, we have (Ax)(i) = 0.
Now, let's focus on the absolute value of the diagonal element A(i,i):
|A(i,i) * x(i)| = |A(i,i)| * |x(i)|
Since A is diagonally dominant, |A(i,i)| > ∑ |A(i,j)| for j ≠ i. This implies that:
|A(i,i)| * |x(i)| > ∑ |A(i,j)| * |x(j)|, for j ≠ i
But the left-hand side of the above inequality is zero since (Ax)(i) = 0. However, the right-hand side is non-zero since the absolute values are always non-negative and at least one term on the right-hand side must be non-zero.
This contradiction implies that our assumption, det(A) = 0, is false. Therefore, A must be invertible if it is diagonally dominant.
Give an example of a 2x2 matrix that is invertible but not diagonally dominant:
Let's consider the following matrix A:
A = [1 2]
[2 1]
To check if A is invertible, we can calculate its determinant:
det(A) = (1 * 1) - (2 * 2) = -3
Since the determinant of A is non-zero (det(A) ≠ 0), A is invertible.
Now, let's check if A is diagonally dominant:
|A(1,1)| = 1 > |A(1,2)| = 2
|A(2,2)| = 1 > |A(2,1)| = 2
Since A is not diagonally dominant (the absolute values of the diagonal elements are not strictly greater than the sum of the absolute values of the remaining elements in their corresponding rows), it serves as an example of a 2x2 matrix that is invertible but not diagonally dominant.
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i need help with this fast
find the soluations to (x+3)^2=49
Answer:
x = 4 , − 10
Step-by-step explanation:
What are the next four terms of the arithmetic sequence 122, 111, 100, ...?
Answer:
89, 78, 67, 56
Step-by-step explanation:
The next four terms of the arithmetic sequence is
As we can see that from the given sequence that 11 is deducted from each following number
122, 111, 100, 89, 78, 67, 56
122, (122 - 11), (111 - 11)
So the above represent the next four terms
Consider the rational function f(x)=(x−6)/(x^2+2x+14) .What monomial expression best estimates the behavior of x−6x-6 as x→±[infinity]x→±[infinity]?What monomial expression best estimates the behavior of x2+2x+14x2+2x+14 as x→±[infinity]x→±[infinity]?Using your results from parts (a) and (b), write a ratio of monomial expressions that best estimates the behavior of x−6x2+2x+14x-6x2+2x+14 as x→±[infinity]x→±[infinity]. Simplify your answer as much as possible.
The monomial expressions which best estimates the behavior of the function f(x) = (x - 6)/(\(x^2\) + 2x + 14) are '1/x' and '1' and the required ratio is 1/x.
The behavior of a rational function as x approaches positive or negative infinity can be estimated by analyzing the highest power terms in the numerator and denominator.
For the function f(x) = (x - 6)/(\(x^2\) + 2x + 14), as x approaches infinity, the dominant term in the numerator is x, and in the denominator, the dominant term is \(x^2\).
Therefore, the behavior of the function can be estimated by the monomial expression \(x\)/\(x^2\), which simplifies to 1/x.
For the denominator \(x^2\) + 2x + 14, as x approaches infinity, the dominant term is \(x^2\).
Therefore, the behavior of the denominator can be estimated by the monomial expression \(x^2/x^2\), which simplifies to 1.
Using the results from parts (a) and (b), the ratio of the monomial expressions that best estimates the behavior of (x - 6)/(\(x^2\) + 2x + 14) as x approaches infinity is (1/x)/(1), which simplifies to 1/x.
In summary, as x approaches infinity, the function f(x) = (x - 6)/(\(x^2\) + 2x + 14) behaves like 1/x, and the ratio of the dominant monomial terms in the numerator and denominator is 1/x.
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20x2 y(x2 - y2) and 35xy?(x - y)
lcm
Answer:
Correct option is
HCF of 20 and 35 = 5
HCF of x2yandxy2=xy
HCF of (x2−y2),i.e.,(x−y)(x+y)
and (x−y)=(x−y)
∴ReqdH.C.F=5xy(x−y)
Step-by-step explanation:
hiiii ur so cute