I understand the first question but I have no idea how the two diagrams are incorrect. I also need help with questions 4,5,6, and 7

Answer:

i think u times them im not sure but then divide

Explanation:

Answer:

The horizontal distance of the package fall before landing is (30 m/s)*(time to fall 200 m). Furthermore the velocity of the package just before it hits the ground is - g*t is the vertical component

30 m/s is the horizontal component.

t is the time required to fll H = 200 m, which is

sqrt(2H/g)

You do the numbers

Answer:

max

Explanation:

because its right 90/7

Answer:      780080

Explanation: BY FORMULA OF K.E

                           K.E=  1/2 MV^2

                                 =  1/2 (1990)(28)^2

                                 =   780080 JOULE

The potential energy of the lemming when it lands is 0.9108672 J.

To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

Given:

Mass of the lemming (m) = 0.0780 kg

Height of the cliff (h) = 5.36 m

First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:

PE = mgh

PE = 0.0780 kg * 9.8 m/s² * 5.36 m

PE = 0.413616 J

Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.

Given:

Velocity of the lemming (v) = 4.84 m/s

Calculating the kinetic energy, we have:

KE = (1/2) * 0.0780 kg * (4.84 m/s)²

KE = 0.9108672 J

According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.

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Answer:2.33 m/s

Explanation:

Given

4 kg mass is moving towards North at \(u_1=5\ m/s\)

and 6 kg mass is moving towards the west at \(u_2=2\ m/s\)

They collide inelastically i.e. stick together

Conserving momentum in the horizontal direction(west)

\(\Rightarrow 4\times 0+6\times 2=(4+6)v_x\quad \quad\ (v_1=\text{velocity of combined mass in west direction})\\\Rightarrow v_x=\dfrac{12}{10}=1.2\ m/s\)

Conserving momentum in the vertical direction(North)\(\Rightarrow 4\times 5+6\times0=(4+6)v_y\quad \quad\ (v_y=\text{velocity of combined mass in North direction})\\\Rightarrow v_y=\dfrac{20}{10}=2\ m/s\)

Net velocity is the vector sum of two velocities whose magnitude is given by

\(\left | v\right |=\sqrt{v_x^2+v_y^2}\\\left | v\right |=\sqrt{1.2^2+2^2}=2.33\ m/s\)

The velocity of 4 kg mass will be the same as the combined mass because both the mass are moving together.

Given that the distance from the wire is r = 30 cm = 0.3 m

The magnitude of the magnetic field is

We have to find the magnitude of the current.

The formula to find the magnitude of the current is

Substituting the values, the current will be

Thus, the magnitude of current is 60 A

Answer:

towards the center of the circle

(which appears to be the last option in your list of possible answers)

Explanation:

The centripetal force points always towards the center of the circle described by the object moving.

The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.

The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.

Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Option D is correct: The rod gained electrons.

EXPLANATION WHY ABC INCORRECT

Options A and C are incorrect because they both suggest that the rod has lost or gained protons, which is not possible through rubbing. Protons are tightly bound within the atomic nucleus and cannot be transferred by rubbing. Similarly, option B is incorrect because it suggests that the rod has lost electrons, whereas the question explicitly states that the rod has become positively charged, which can only happen if it gains positive charge or loses negative charge.

A plastic rod becomes positively charged when rubbed against a cloth due to the loss of negatively charged electrons. The rod does not lose or gain protons.

When a plastic rod is rubbed against a cloth, it becomes positively charged due to the transfer of electrons from the rod to the cloth. In terms of the given choices, B. The rod lost electrons is the correct statement. Electrons have a negative charge, therefore when they are removed from an object, it becomes positively charged. Contrary to some misconceptions, protons do not transfer during this process because they reside in the nucleus of an atom, which is a comparatively stable and inaccessible region.

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The answer is OPTION B : 73.7 N

Answer:

B

Explanation:

Answer:

\(\boxed {\tt Use \ more \ subjects \ and \ trials}\)

Explanation:

The scientist is measuring the effectiveness of fertilizers on plants.

In her experiment, she tests multiple fertilizers on one plant. This procedure is not very efficient. She only used one plant, which is not a good practice. She should use many plants and use many trials, to ensure the best results.

To improve her procedure, the scientist should use more trials and test subjects.

The calculated value of speed of sound be 400 m/s.

An echo is a sound produced when sound waves are reflected off of a surface and returned to the listener. It is the sound that has been reflected, and it reaches the listener after the original sound has passed.

Given parameters:

The student's  distance to the wall is = 300 m.

The time delay between clap an echo is 1.5 seconds.

In this time, sound waves goes to the wall and hits back to the student's ear.

So, total distance covered by the sound wave: d= 2 × 300 m = 600 m.

Hence,  the speed of sound be - 600 m/1.5s = 400 m/s.

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Answer:

The speed of the plane after it decelerates is 50 m/s

Explanation:

Motion with Constant Acceleration

When an object gains or losses velocity in time, it acquires acceleration. If this value is constant, we can calculate the final velocity (or speed in scalar terms) as:

\(v_f=v_o+at\)

Where vf is the final speed, vo is the initial speed, a is the constant acceleration, and t is the time the acceleration is acting.

The plane is originally traveling at vo=80 m/s and it slows down at a constant rate of \(a=-0.25\ m/s^2\) during t=120 seconds. Note we have added the negative sign to the acceleration because the plane is slowing down, i.e., the acceleration is against the speed.

Thus, the final speed is:

\(v_f=80-0.25*120\)

\(v_f=80-30=50\)

\(v_f = 50\ m/s\)

The speed of the plane after it decelerates is 50 m/s

Answer:

Explanation:

In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.

So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.

Answer:

The fields are at right angles to each other and to the direction of the wave.

Explanation:

Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

(1) The acceleration of the car is determined as 17.42 m/s².

(2) The acceleration of the crate is determined as 8.89 m/s².

The acceleration of the car is calculated from the net force acting on the car.

∑F = ma

F - Ff = ma

F - μW = ma

where;

m = W/g

m = (9320)/(9.8)

m = 951.02 kg

2(9320) - 0.222(9320) = 951.02a

16,570.96 = 951.02a

a = 17.42 m/s²

F - μW = ma

F - μmg = ma

302 - 0.75(18.6 x 9.8) = 18.6a

165.29 = 18.6a

a = 8.89 m/s²

Thus, the acceleration of the car is determined as 17.42 m/s².

The acceleration of the crate is determined as 8.89 m/s².

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The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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Torque = 2.05 x 10²⁸ Nm

Energy = 3.54 x 10³³ J

Average power = 1.02 x 10²⁸ W

(a) Torque (τ) is the rotational effect of a given force.  

It is given by

τ = I x α          -------------(i)

Where;

I = rotational inertia of the object

α = angular acceleration of the object.

In this case, the object is the Earth. Therefore,

I = 9.71 x 10³⁷ kg m²

α = ω / t

Where;

ω = angular velocity of earth = 2π rad / day

Since

1 day = 24 hours and 1 hour = 3600seconds

1 day = 24 x 3600 seconds = 86400seconds

=> ω = 2π rad / 86400seconds

=> ω = 7.29 × 10⁻⁵ rad/s

t = 4 days = 4 x 24 x 3600 seconds = 345600 seconds

=> α = ω / t

=> α = 7.29 × 10⁻⁵ / 345600

=> α = (7.29 × 10⁻⁵) / (3.456 x 10⁵)

=> α = (7.29 × 10⁻⁵⁻⁵) / (3.456)

=> α = (7.29 × 10⁻¹⁰) / (3.456)

=> α = 2.11 × 10⁻¹⁰ rad/s²

Now substitute the values of I and α into equation (i)

τ = 9.71 x 10³⁷ x 2.11 × 10⁻¹⁰

τ = 9.71 x 10²⁷ x 2.11

τ = 20.5 x 10²⁷ Nm

τ = 2.05 x 10²⁸ Nm

(ii) The energy (rotational energy) E is given by;

E = \(\frac{1}{2}\) x I x ω

E = \(\frac{1}{2}\) x 9.71 x 10³⁷ x 7.29 × 10⁻⁵

E = 35.4 x 10³² J

E = 3.54 x 10³³ J

(iii) The average power P, is given by;

P = E / t

P = 3.54 x 10³³ / 345600

P = 1.02 x 10²⁸ W

Answer:

10.28 Kg

Explanation:

Given:

                         \(M_{iron} =7.70 Kg\\\rho_{iron}=7.86 x 10^-3 kg/m^3\\\rho_{silver}=10.50 x 10^3 kg/m^3\)

we know that

                        \(\rho=\frac{m}{V}\\V=\frac{m}{\rho}\)

So,

                       \(\frac{m_{iron}}{\rho_{iron}} =\frac{m_{silver}}{\rho_{silver}}\\ \frac{7.70}{7.86*10^3} =\frac{m_{silver}}{10.50*10^3}\\ m_{silver}=10.28 kg\)

The mass of the silver sculpture is 10.28 kg.

Given that the mass of iron is 7.70 kg and the density of the iron is 7.86 ✕ 103 kg/m3. The density of the silver is 10.50 ✕ 103 kg/m3.

The density of the iron is given below.

\(\rho_i = \dfrac {m_i}{V_i}\)

Where m_i is the mass and V_i is the volume of the iron.

\(\rho_i = \dfrac {7.70}{7.86\times 10^3}\)

The density of the silver is given below.

\(\rho_s = \dfrac {m_s}{V_s}\)

Where m_s is the mass and V_s is the volume of the silver.

\(\rho_s = \dfrac {m_s}{10.5\times 10^3}\)

The sculpture is identical to the iron sculpture, hence their density will be equal.

\(\rho_i =\rho_s\)

\(\dfrac {7.70}{7.86\times 10^3} = \dfrac {m_s}{10.5 \times 10^3}\)

\(m_s = 10.28 \;\rm kg\)

hence we can conclude that the mass of the silver sculpture is 10.28 kg.

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Answer: positive

Explanation:

Gravity can be defined as the force with which the body is attracted towards the center of the earth, or towards any other body. If the force acting on the body is in the direction of displacement then the word done by the applicable force is positive. This causes the free fall of the ball under the influence of gravity is also positive.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

gpe gained = 60J

Explanation:

gravitational potential energy  =  mass * gravity * height

gpe =  2 kg * 10 N * 3 m

gpe = 60J

We have that the absolute pressure at the bottom of the tank is mathematically given as

Pabs=209.21Kpa

Question Parameters:

A 3-m-diameter vertical cylindrical tank is filled

with water to a depth of 11 m.

Generally the equation for the Absolute Pressure  is mathematically given as

Pabs=Patm+pgh

Therefore

Pabs=101.3e3+(1000*9.81*11)

Pabs=209.21Kpa

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The head loss doubles when the average velocity is doubled.

The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).

Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.

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Answer: Start by writing down the problem in your own words using as much detail as possible. Be as specific as possible in your description.

Explanation:

Answer:

Krypton – Mass Number – Neutron Number – Kr 2020-11-21 by Nick Connor Krypton is a chemical element with atomic number 36 which means there are 36 protons and 36 electrons in the atomic structure. The chemical symbol for Krypton is Kr.

Atomic Number: 36

Element: Krypton

Element Category: Noble Gas

Symbol: Kr

Explanation:

Answer:

your answer is in an image here

imageshare.best/image.php?id=JS9NDO

Explanation:

copy and paste in browser

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Accuracy refers to how close a measurement is to the true or accepted value. Precision refers to how close measurements of the same item are to each other.

Precision and accuracy are two indices of observational error. Precision is how near a collection of measurements is to its true value, whereas accuracy is how close the measurements are to one other. Precision, in other terms, is a description of random errors and a measure of statistical variability.

If you weigh a body weighing 20 kg and obtain 17.4,17,17.3, and 17.1, your weighing scale is exact but not particularly accurate. If your scale returns values of 19.8, 20.5, 21.0, and 19.6, it is more accurate but not particularly precise.

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The velocity of the punk at time t = 1.5 s is equal to 2.47 m/s.

The object will have two velocities during the projectile motion, one is horizontal velocity and the other is vertical velocity. The horizontal velocity of the object is constant throughout the projectile motion but the vertical velocity is changed in the projectile motion.

Given that the velocity vector is making an angle θ with a horizontal table, θ = 35°

The vertical component of the velocity of the puck can be determined as:\(u_x = u Sin 35^o = 3.60 \times 0.573 =2.06 m/s\)

The horizontal component of the velocity of the puck can be determined as:

\(u_y = u cos 35^o = 3.60 \times 0.82=2.95 m/s\)

Given the acceleration aₓ = -0.360 m/s² and a y = -0.980 m/s²

The final vertical components of the velocity of the punk are:

\(v_x = u_x + a_xt\)

\(v_x = 2.95 - (0.360) (1.5)\\v_x = 2.41 m/s\)

and, the horizontal velocity of the punk is:

\(v_y = u_y +a_yt\\v_y = 2.06 - (0.980) (1.5)\\v_y = 0.59 m/s\)

The velocity of the punk can be determined as:

\(v = \sqrt{v_x^2 + v_y ^2}\\ v =\sqrt{(5.80)^2 + (0.35)^2}\\ v = 2.47 m/s\)

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