If a baseball lands with a speed of 80 miles/hr after traveling with an acceleration of -6 miles/hr/sec for 5seconds, what was the initial speed at which the ball was hit?

Answer:

Below

Explanation:

Find acceleration first

vf = vo + at     (starts from rest so vo = 0)

8 = 0 + at    

8 = at

d = vo t + 1/2 a t^2     (substitute 8 in for 'at')

200 = 0 t  + 1/2 (8) t

200 / 4 = t = 50 seconds for front of train to pass her at 8 m/s

  acceleration = change in velocity / change in time = 8 / 50 = .16 m/s^2

Back of train has to travel 120 meters at initial v = 8 m/s  and accelerating  at .16 m/s^2   :

  d = vo t + 1/2 a t^2

 120 = 8 t + 1/2 ( .16 ) t^2

           .16t^2 + 8t - 120 = 0      Quadratic Formula shows t = 13.25 s

vf = vo  + a t

vf = 8 m/s  + .16 m/s^2 ( 13.25 s) = 10.1 m/s

Answer:

"time as adjusted to achieve longer evening daylight in summer by setting the clocks an hour ahead of the standard time"

Explanation:

by definition.

A car with a mass of 950 kg is moving at 20 m/s when that collision with another car with a mass of 1000 kg that is moving at 15 m/s. The speed of each car prior to the collision was 2.05 m/s.

A collision, also referred as an impact, seems to be the abrupt, violent coming together in close proximity of two bodies. Examples include two pool cues, a tennis club and a ball, as hammer but a nail hammer, and two transport vehicles when they are linked.

The forces involved in a collision are equal in size and directed in the opposite direction, and they accelerate both objects. Each object accelerates equally in collisions with things of equal mass.

Momentum

m1V1 = 950 Kg * 20 m/s

= 19000 Kg*m/s

momentum = m2V2

= 1000kg*15m/s

= 15000 Kg*m/s

momentum before = (19000–15000)kg-m/s

= 4000kg-m/s

momentum after = ( 950 + 1000)V3

momentum after = momentum before

= V3

= 4000/1950

= 2.05 m/s

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The required angle of principle maxima when wavelength and diffraction grating are given is calculated to be 15.07°.

The wavelength is given as 780 nm = 780 × 10⁻⁹ m

It is given that the diffraction grating contains 3300 lines per centimetre.

Distance between the slits d = 1 cm/3300 lines = 10⁻² m/3300 lines = 3×10⁻⁶ m

The angles of principle maxima are to be found out.

We know that,

d sin θ = m λ

where,

d is the distance between slits

θ is the angle with respect to the path of the incident light

m is the order of interference

sin θ = m λ/d

θ = sin⁻¹(m λ/d) =  sin⁻¹[(1× 780 × 10⁻⁹)/(3×10⁻⁶)] = sin⁻¹ (26× 10⁻²) = sin⁻¹(0.26) = 15.07°

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The amount of work done in dragging a 100 kg block with a velocity of 10 ms⁻¹ for 10 seconds is 5.0 x 10³ J.

The formula for work done can be given as follows:

Work done = force x distance moved in the direction of force

Hence, the amount of work done in dragging a 100 kg block with a velocity of 10 ms⁻¹ for 10 seconds is 5.0 x 10³ J.

Fictional force, f = μR = 0.5 × 1000 = 500 N (where R = normal reaction = weight of the block = mg)

Force acting on the block to drag it, F = ma = 100 × 10 = 1000 N (where a = acceleration = change in velocity/time = 10/10 = 1 m/s²)

Net force acting on the block, F' = F - f = 1000 - 500 = 500 N

The distance moved in the drection of force in 10 seconds = 10 × 10 = 100 m

Therefore, work done = F' × distance moved in the direction of force = 500 × 100 = 50,000 J = 5.0 x 10³ J.

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The magnitude and direction of vector B if it has no X-component is 2m along negative y direction.

Given the magnitude of vector A is 8m

The direction of vector A is negative x-axis = -8i

The magnitude of vector product of two vectors A and B is = 16m

The direction of vector (A x B) is along z-axis = (A X B) = 16k

We know that from product of vectors i x j = k

So, B must be pointing in the -y direction which means:

B = -lBlj

Then, A X B = (8 x B)(i x j) = 16k

B = 2m

Hence the magnitude and direction of vector B if it has no X-component is 2m along negative y direction.

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complete question: The vector product of vectors and B has magnitude 16.0 m? and is in the +z-direction. If vector A has magnitude 8.0 m and is in the -x-direction, what are the magnitude and direction of vector B if it has no X-component?

Explanation:

The molecule in the can of soda will begin to lose their kinetic energy and become more order. In short, the entropy of the molecules in the can will begin to reduce drastically.

Therefore, the molecules in the can will have a lower average kinetic energy.

The time between the emission of the pulse and the detection of the echo is approximately 0.3669 seconds.

The time between the emission of the pulse and the detection of the echo, we need to consider the round trip travel time of the radio signal.

The round trip travel time consists of two parts: the time taken by the signal to travel from the spacecraft to the surface of the Moon and back, and the time taken for the reflection to reach the spacecraft again.

The time for the signal to travel from the spacecraft to the Moon's surface and back, we can use the formula:

Time = Distance / Speed

Given that the spacecraft is 55 km high, we consider the distance to be twice that value (round trip). Thus, the distance is 2 × 55 km = 110 km = 110,000 meters.

The speed of the radio signal in a vacuum is the speed of light, which is approximately 299,792,458 meters per second.

Time = Distance / Speed

Time = 110,000 meters / 299,792,458 meters per second

Time ≈ 0.3669 seconds

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Answer:

it'll stay the same unless there's rain

To find the magnitude of a vector with components a_x = 10 m and a_y = 5.0 m, you can follow these steps:

1. Identify the components of the vector: In this case, the components are a_x = 10 m and a_y = 5.0 m.

2. Use the Pythagorean theorem to find the magnitude: The magnitude of a vector can be found using the formula: magnitude = √(a_x²+ a_y²).

3. Plug in the values of the components: magnitude = √((10 m) ²+ (5.0 ²).

4. Calculate the magnitude: magnitude = √(100 m² + 25m ²). = √(125 m²).

5. Simplify the result: magnitude = √(125 m²) = 5√5 m.

So, the magnitude of the vector with components a_x = 10 m and a_y = 5.0 m is 5√5 m.  

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Applying V = u + at

The units have to line up. 30 km/h times 1000 m/km times 1 hr/3600 s equals 8.333 m/s.

V = 8.333 + 3.5 * 6.8

V = 32.133 m/s²

The rate of something moving in one direction is called its velocity. Velocity may be used to gauge both the speed of a rocket launching into space and the speed of a car traveling north on a busy freeway.

The first derivative of position relative to time is velocity. There is a straightforward formula that combines rate, distance, and time to calculate velocity.

The following method is the most typical approach to get the constant velocity of an item travelling straight ahead:

The rate or speed is given by the formula r = d/t

r (sometimes denoted as v for velocity)

d is the traveled distance.

t - The amount of time needed to finish the movement.

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Answer:

The electron cloud has a very small mass, but it makes up most of the space of the atom. The electrons have a negative charge, and the protons have a positive charge. Due to the charges in the atom, that is how the atom stays together, by attraction of the electric charges present in the atom.

Answer:

The electron cloud has a very small mass, but it makes up most of the space of the atom. The electrons have a negative charge, and the protons have a positive charge. Due to the charges in the atom, that is how the atom stays together, by attraction of the electric charges present in the atom.

I hope it's helpful!

Answer:

The time the pilots have to take evasive action is approximately 36.699 seconds

Explanation:

The direction of the planes = Towards each other

The speed of each plane, v₁, v₂ = 721 km/h

The initial distance between the two planes, d = 14.7 km

The relative velocity of the two planes, v = v₁ + v₂

v = 721 km/h + 721 km/h = 1,442 km/h

The time it will take the planes to meet, t = d/v

∴ t = 14.7 km/(1,442 km/h) = (21/2,060) h × 60 min/hr × 60 s/min ≈ 36.699 s

The time it will take the planes to meet = The time the pilots have to take evasive action, t ≈ 36.699 seconds.

Answer:

Explanation:

According to snell's law the incident normal and refracted ray at the point of incidence all lie in the same plane

Given

incident angle i= 60°

refracted angle r= ?

index of refraction u= 1.53.

Applying the formula

\(u= \frac{sine (i)}{sine( r)}\)

solving for r

\(1.53=\frac{ sine (60)}{ sine( r)}\\\1.53= \frac{0.866}{ sine( r)} \\\ sine( r)= \frac{0.866}{1.53} \\\sine(r)= 0.566\\\r= sine^-0.566\\\r= 34.47\)

r= 34.47°

Answer: Food chain: cheese a product of the sun.

Explanation:

Food chain: The energy taken from the sun through photosynthesis enables plants to exist and grow.

The animal like cow takes chemical energy from plants by eating plants product.

The cow is able to produce the milk because of the energy that has been taken from the plant.

Since the cheese came out from the milk, we can therefore conclude that the food is initially a product of the sun.

Answer:

The answer is true I guess!!!

This is because the more you go up to less air it is and the pressure also gets less!!!!!!!!

Explanation:

I HOPE THAT I WAS HELPFUL TO YOU!

Answer:

You will be able to tell whether the unknown cell is from an animal or from a plant through the knowledge of difference between plants and animal cells.

Explanation:

A cell can be defined as the simplest bit of living matter which exhibits a variety of shapes and sizes and that can exist independently.

When a slide of an unknown cell is studied under a microscope, different cell structures would be observed which would be used to conclude if the cell on the slide is a plant or animal cell.

The following features are observed in a plant cell:

--> cellulose cell wall is present

--> Chloroplast is present

--> A large central vacuole is present

--> Centriole is absent

The following features are observed in animal cell:

--> Cellulose cell wall is absent

--> Chloroplast is absent

--> Small vacuoles is present

--> Centriole is present

The difference between a plant and an animal cell can be seen from the features above and a clear knowledge of this will help the student tell whether the unknown cell is from an animal or from a plant.

Answer: Ted and Tim

Explanation:

The football players Ted and Tim have the same momentum, which is 120 kg m/s. Hence, option C is correct.

The momentum is the result of a particle's velocity and mass. Force and motion, meaning it has both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on a particle equals the time rate of increase of momentum.

The impulse, which is the product of the force and the intervals (the impulse), is equal to the difference in momentum, according to Newton's 2nd law, if a steady force operates on a particle for a specific amount of time. On the other hand, a particle's momentum is the amount of time needed for a consistent action to fight it to rest.

As per the given information in the question,

The momentum of Ted is,

p = 60 × 2 = 120 kg m/s

The momentum for Todd is,

p = 80 × 1.7 = 136 kg m/s.

The momentum of Tom is,

p = 90 × 1.5 = 135 kg m/s and,

The momentum for Tim is,

p = 100 × 1.2

p = 120 kg m/s.  

After comparing the momentum of all the players, Ted and Tim have similar momentum.

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The objects with a speed higher v = 7668 m/s than that number are likely to go into orbit. (Y & Z)

The orbital speed of an astronomical body or object (e.g. planet, moon, artificial satellite, spacecraft, or star) is the speed at which it orbits around either the barycenter or if one object is much more massive than the other bodies in the system, its speed relative to the centre of mass of the most massive body.

The term can be used to refer to either the mean orbital speed, i.e. the average speed over an entire orbit, or its instantaneous speed at a particular point in its orbit.

Maximum (instantaneous) orbital speed occurs at periapsis (perigee, perihelion, etc.), while minimum speed for objects in closed orbits occurs at apoapsis (apogee, aphelion, etc.).

In ideal two-body systems, objects in open orbits continue to slow down forever as their distance to the barycenter increases.

g = v^2 / r

so v = square root ( r x g )

v = 7668 m/s will be the minimum speed needed to go into orbit.

Based on that, objects with a speed higher than that number are likely to go into orbit. (Y & Z)

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Answer:

0.900

Explanation:

joules" (and any subsequent words) was ignored because we limit queries to 32 words.

Answer:

See image

Explanation:

Plato

Hello!

We can use the kinematic equation:
\(a = \frac{v_f - v_i}{t}\)

a = acceleration (m/s²)

vf = final velocity (45 m/s)
vi = initial velocity (25 m/s)

t = time (5 sec)

Plug in the givens:
\(a = \frac{45-25}{5} = \frac{20}{5} = \boxed{4 m/s^2}\)

Option b. I and II only.During the process of freezing, energy is released (statement I), and the heat transfer is greater than zero (statement II).

I. H2O(l) > H2O(s) + energy:

This statement is true. When water freezes, it transitions from a liquid state (H2O(l)) to a solid state (H2O(s)). The process of freezing is exothermic, meaning it releases energy. The energy released during freezing is known as the latent heat of fusion.

II. Q > 0:

This statement is also true. The symbol "Q" represents the heat transfer during a process. In the case of freezing water, heat is transferred out of the system (water) into the surroundings. Since freezing is an exothermic process, Q, the heat transfer, is greater than zero.

III. Molecular attractions are weakened:

This statement is false. When water freezes, the molecular attractions between water molecules become stronger, not weaker. As the temperature decreases, the kinetic energy of the water molecules decreases, and they arrange themselves in a more ordered structure. This leads to the formation of hydrogen bonds, which are stronger than the intermolecular forces present in liquid water.

In conclusion, statements I and II are true about freezing water. Statement III, however, is false. During the process of freezing, energy is released (statement I), and the heat transfer is greater than zero (statement II). Additionally, the molecular attractions between water molecules become stronger, not weaker, as the water transitions from a liquid to a solid state.

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Answer:

lacerations

Explanation:

Answer:

B. lacerations

Explanation:

A P E X!

Answer:

The upstroke is a mechanism that helps to raise the plunger and downstroke helps to help lower the plunger. On the up-stroke of the plunger, the lower valve opens and the upper valve is closed. Whereas, on the downstroke, the lower valve closes and the upper one opens.

Answer:

An independent variable is a variable that stands alone and isn't changed by the other variables you are trying to measure.

A dependent variable is something that depends on other factors.

Answer:

T_{A} = 294 N ,    T_{B}  = 254.6 N    

Explanation:

Let's apply the condition of static equilibrium, in attached we can see a diagram of the problem. Let's apply each axis

X axis

         \(T_{B}\) - T_{Ax} = 0

Y axis y

        T_{Ay} - W = 0

Let's use trigonometry to find the components of the stress Ta

The angle is measured with respect to the horizontal

       cos 30 = T_{Ax} / T_{A}

       sin 30 = T_{Ay} / \(T_{A}\)

       T_{Ax} = T_{A} cos 30

       T_{Ay} = T_{A} sin 30

let's substitute

       T_{B} = T_{A} cos 30

       T_{A}  sin 30 = m g

let's calculate

       T_{A} = m g / sin 30

       T_{A} = 15 9.8 / sin 30

       T_{A} = 294 N

       T_{B} = 294 cos 30

       T_{B}  = 254.6 N