If a room causes reverberations, it has poor acoustics.TrueFalse

It take 1.33 second to a Dalmatian to accelerate from rest to its top speed.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

given parameters:

initial speed, u = 0

final speed, v =16.5 m/s.

distance covered, s = 11 meters.

We have to find: time t = ?

We know that:

s = ut +(v-u)t/2

⇒ 11 = 0 + (16.5 -0)t/2

⇒ t = 22/16.5 second = 1.33 second.

So,  it take 1.33 second to a Dalmatian to accelerate from rest to its top speed.

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Answer:

the answer is the area around a star where a planet can orbit A Star without the harmful effect of radiation

Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.

Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:

Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.

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Answer:

Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.

Explanation:

Answer:

The distance is \(r_2  =  0.24 \  m\)

Explanation:

From the question we are told that

       The  distance from the conversation is \( r_1    =  24.0 \ m\)

       The  intensity of  the sound at your position is  \(\beta _1 =  40 dB\)

        The  intensity at the sound at the new position is  \(\beta_2 =  80.0dB\)

Generally the intensity in  decibel is  is mathematically represented as

      \(\beta  =  10dB log_{10}[\frac{d}{d_o} ]\)

The intensity is  also mathematically represented as

      \(d =  \frac{P}{A}\)

So

    \(\beta  =  10dB *  log_{10}[\frac{P}{A* d_o} ]\)

=>   \(\frac{\beta}{10}  =  log_{10} [\frac{P}{A (l_o)} ]\)

From the logarithm definition

=>    \(\frac{P}{A  *  d_o}  =  10^{\frac{\beta}{10} }\)

=>      \(P =  A (d_o ) [10^{\frac{\beta }{ 10} } ]\)

Here P is the power of the sound wave

 and  A is the cross-sectional area of the sound wave  which is generally in spherical form

Now the power of the sound wave at the first position is mathematically represented as

               \(P_1 =  A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]\)

Now the power of the sound wave at the second  position is mathematically represented as

               \(P_2 =  A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]\)

Generally  power of the wave is constant at both positions  so  

    \(A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]  = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]\)

      \(4 \pi r_1 ^2   [10^{\frac{\beta_1 }{ 10} } ]  = 4 \pi r_2 ^2   [10^{\frac{\beta_2 }{ 10} } ]\)

        \(r_2 =  \sqrt{r_1 ^2 [\frac{10^{\frac{\beta_1}{10} }}{ 10^{\frac{\beta_2}{10} }} ]}\)

       substituting value

        \(r_2 =   \sqrt{ 24^2 [\frac{10^{\frac{ 40}{10} }}{10^{\frac{80}{10} }} ]}\)

        \(r_2  =  0.24 \  m\)

The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.

Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.

Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.

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Tension in the left cable is 4395.9 N.

Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.

Here,

The total mass of the riders is given, m = 330 kg

Let the tension in the left cable be T₁ and that in the right cable be T₂.

From the figure,

T₁ cos 15 = T₂ cos 26

T₁ = T₂ cos 26/cos 15

Also,

T₁ sin15 + T₂ sin 26 = mg

Substituting values,

(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8

0.241 T₂ + 0.438 T₂ = 3234

0.679 T₂ = 3234

T₂ = 4762.8 N

Therefore, Tension in the left cable, T₁ = 0.930x 4762.8

         T₁ = 4395.9 N

Hence, The tension in the left cable is 4395.9 N

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Your question was incomplete. Attaching the image here.

Answer:

Increases with time via the relationship:

velocity = acceleration * time = g * t

Explanation:

Since the object is falling under the constant acceleration due to gravity, its velocity is increasing with time. Such relationship can be described via the equation:

velocity = acceleration * time = g * t

Where the direction of the acceleration due to gravity (g) (pointing downwards) is in the same direction of that of the object's velocity.

The statement that describes the net force on an object is the sum of all forces acting on an object (option A).

Net force is sum of all forces acting on an object in a single plane.

When a force is applied to a body, not only is the applied force acting, there are many other forces like gravitational force, frictional force and the normal force that balances the other force.

The sum of all these forces acting on the object whether in the same or opposite direction is regarded as the net force.

Therefore, the statement that describes the net force on an object is the sum of all forces acting on an object.

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Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

Answer: in kilowatt, 40,000 upon 1000 kilowatt, which is equal to 40 kilowatts.

Explanation: Here a car accelerates from rest to a velocity of 20 m/s In 10 seconds. And we have to find the power of the engine during this acceleration. So here we will use the work-energy theorem according to which work done is equal to the car's kinetic energy change. So work done by the engine is equal to half M V f squared minus V I square Mars is 2000. Could you? VF is the final velocity, which is 20 m/s, Initial Velocity VI is zero. So we get worked and equal to four into 10 to the power five jewels. Now power will be equal to work done by time. So work done is the 90s 10 seconds. So power is 40 1000 And in kilowatt, 40,000 upon 1000 kilowatt, which is equal to 40 kilowatts. So this is the correct option and this completes the solution. 

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Answer:

Explanation:

d = ½at²

d = ½(F/m)t²

d = ½(980/500)5²

d = 24.5 m

Answer:

Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).

Explanation:

Convert velocity to the standard units (meters per second):

\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).

Convert mass to standard units (kilograms):

\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).

When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:

\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).

The y-component of the vector is approximately 14.67 meters.

To find the y-component of the vector, we need to use trigonometry. Given that the vector has a magnitude of 34 meters and an angle of 26 degrees, we can break down the vector into its x and y components.

Step 1: Identify the known values:

Magnitude of the vector (r) = 34 meters

Angle (θ) = 26 degrees

Step 2: Determine the y-component using trigonometry:

The y-component can be found using the formula:

y = r * sin(θ)

Step 3: Calculate the y-component:

Substituting the known values into the formula:

y = 34 * sin(26 degrees)

y ≈ 14.67 meters

Therefore, the y-component of the vector is approximately 14.67 meters.

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Answer:

5000 grams

Explanation:

recall that 1 kg is equivalent to 1000 grams

hence 5 kg = 5 x 1000 grams = 5000 grams

Answer:

The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N

Explanation:

Forces on block 4.3 kg are:

63N to the right and R21 (contact force from the 6.3 kg block) to the left

Net force on 4.3 kg block is: 63 N - R21

Forces on the 6.3 kg block are:

R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.

So net force on the 6.3 kg block is: R12 - 11 N

According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").

Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:

a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2

solve for R by cross multiplication

6.3 (63 - R) = 4.3 (R - 11)

396.9 - 6.3 R = 4.3 R - 47.3

369.9 + 47.3 = 10.6 R

444.2 = 10.6 R

R = 444.2 / 10.6

R = 41.90 N

According to Gauss' equation, the total flux of an electric field in a confined surface is directly proportional to the charge enclosed.

1)To determine the outward electric flux through the rounded "side" of the cylinder, we can use Gauss's law. We choose a cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The electric field due to the sphere is spherically symmetric, so the electric field lines are parallel to the cylinder's axis and perpendicular to its sides.

E = (1/4πϵ0) (Q/r^2)

where r is the distance from the origin (center of the sphere) to the point on the Gaussian surface.

The area element of the Gaussian surface is dA = 2πRdz, where dz is an element of length along the cylinder's axis. The electric flux through the top and bottom surfaces of the Gaussian surface is then given by:

Φ = ∫E⋅dA = E ∫dA = E(2πR)L

Substituting the expression for the electric field, we have:

Φ = (Q/2ϵ0r^2)(2πRL)

Therefore, the outward electric flux through the rounded "side" of the cylinder is:

Φ = (Q/ϵ0)(R/Lr^2)

2)To determine the electric flux upward through the circular cap at the top of the cylinder, we use a flat Gaussian surface with radius R and height r, centered at the top of the cylinder. The electric field due to the charged sphere is perpendicular to the Gaussian surface, so the electric flux through the top cap is simply the flux through the flat Gaussian surface. The electric field at any point on the Gaussian surface is given by Coulomb's law as:

E = (1/4πϵ0) (Q/R^2)

The area element of the Gaussian surface is dA = πR^2, so the electric flux through the top cap is given by:

Φ = ∫E⋅dA = E ∫dA = EπR^2

Substituting the expression for the electric field, we have:

Φ = (Q/ϵ0)(R/r^2)

3)To determine the electric flux downward through the circular cap at the bottom of the cylinder, we use a similar flat Gaussian surface with radius R and height r, centered at the bottom of the cylinder. The electric flux through the bottom cap is also given by:

Φ = (Q/ϵ0)(R/r^2)

4)Adding the results from parts 1-3, we have the total outward electric flux through the closed cylinder as:

Φ_total = Φ_side + Φ_top + Φ_bottom

= (Q/ϵ0)(R/Lr^2) + 2(Q/ϵ0)(R/r^2)

Simplifying this expression, we have:

Φ_total = (Q/ϵ0) [(2R/r^2) + (R/Lr^2)]

5)According to Gauss's law, the total outward electric flux through a closed surface is proportional to the total charge enclosed within that surface. In this case, the closed surface is the cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The charge enclosed within this surface is simply the charge of the sphere, which is +Q. Therefore, we expect the total outward electric flux through the closed cylinder to be:

Φ_total = Q/

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Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

The pilot's total velocity is 116.3 knots in the direction of 62.3⁰.

The pilot's total velocity is calculated by applying the principle of relative velocity.

The total velocity is also the resultant velocity and the magnitude of the pilot's total velocity is calculated by applying Pythagoras theorem as follows;

R = √ (V₁² + V₂²)

R =  √ (54² + 103²)

R = 116.3 knots

The direction of the velocity vector is calculated as follows;

tan θ = (103 knots) / (54 knots)

θ = tan⁻¹ (103/54)

θ = 62.3⁰

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In hydrogen atom the electronic transition from n= ∞ to n=1 corresponds to largest energy emission.

Electronic transition is the jump of an electron from one energy level to another energy level .

E = hc/λ

h= plank constant =6.62*10^(-34)

c=speed of light

λ= wavelength of emited electron .

Thus , we can conclude that the electronic transition from infinity to n=1 (ground state) corresponds to largest energy emission .

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A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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The mass rate of change of the space probe is approximately 28.49 kg/s .

To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = ma

In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:

F = (Δ m /Δt) * v

where;

Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:

F_net = m * g - (Δ m /Δt) * v

Plugging in the values and solving for delta m / delta t, we get:

2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s

Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s

Δm / Δt ≈ 28.49 kg/s

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S.A of sphere = 4πr²

r = 2m

S.A = 4π *4

S.A = 50.26m²

The surface area is 50.26m²

The surface area exists as the amount of space surrounding the outside of a three-dimensional shape.

The surface area of a solid object exists as a measure of the total area that the surface of the object settles.

The surface area of a figure (in square units) exists the number of unit squares it brings to cover the entire surface without gaps or overlaps. If a three-dimensional figure includes flat sides, the sides are named faces. The surface area exists as the total of the areas of the faces.

A radius of a circle or sphere exists in any of the line segments from its center to its perimeter, and in additional modern usage, it exists also its length.

S.A of sphere = 4πr²

r = 2m

S.A = \(4\pi *4\)

S.A = 50.26m²

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Answer:

This is due to variation bin air pressure at the two different altitudes, so air rushes out through the eustachian tube to hit the eardrum and back when u reach the ground

Answer:

the correct answer is D,  acceleration of gravity

Explanation:

In a projectile launch problem it is described by the expressions

        v = v₀ - g t

         v² = v₀² - 2 g y

        y = v₀ t - ½ g t²

By examining these equations we can see that acceleration is the magnitude that appears constant in all expressions.

 This acceleration is the acceleration of gravity with a value of g = 9.8 m/s² and directed towards the center of the Earth

therefore the correct answer is D

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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The scenario that is an example of the transfer of thermal energy by conduction is D. Warm water ascends inside a tea pot as cooler water sinks.

Conduction is the transfer of heat through a material without the bulk motion of matter. In the case of a tea kettle, the heat source (such as a stove) heats the metal of the kettle, which then conducts the heat to the water inside the kettle.

The hot water molecules transfer their thermal energy to the cooler water molecules through direct contact, which causes the cooler water to become denser and sink while the warmer water becomes less dense and rises.

This creates a convection current, which further distributes the thermal energy within the water.

Option A describes the transfer of thermal energy by radiation, where electromagnetic waves (such as infrared light) transfer energy from the source to the eggs without any direct contact.

Option B describes the transfer of thermal energy by convection, where the cooler water in the pool sinks to the bottom and is replaced by warmer water rising to the surface.

Option C describes the transfer of thermal energy by radiation and convection, where the hot sidewalk radiates heat to the surrounding air, which then rises and is replaced by cooler air.

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