if air that had a temperature of 20°c and 8.6 g/kg of water vapor is cooled to 5°c and 5g/kg of water vapor, then warmed to 25°c, what will be its water vapor content?

Answer:

Three stages of falling

There are three stages as an object falls through a fluid:

at the start, the object accelerates downwards due to the force of gravity

as the object's speed increases, frictional forces such as air resistance or drag increase

at terminal velocity, the weight of the object due to gravity is balanced by the frictional forces, and the resultant force is zero

Explanation:

Answer:

Fossil fuels come from dead animals and dead plants from millions years ago.

I hope I helped.

Answer:

It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.  

Answer:

It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.

haha ctrl + v go brrrrrrrrrrrrrr

Answer:

False

Explanation:

The expression for the direction of the car's average acceleration in terms of x and y coordinates is given by a = \((a_x^2 + a_y^2)^{1/2}\).

The direction of the car's average acceleration can be calculated in terms of x and y coordinates. To calculate the magnitude of the car's acceleration, the Pythagorean theorem is used, which states that \(a^2 = a_x^2 + a_y^2\). In this case, \(a_x\) represents the acceleration in the x direction, while \(a_y\) represents the acceleration in the y direction. Therefore, the magnitude of the car's acceleration can be expressed as follows: a = \((a_x^2 + a_y^2)^{1/2}\)

The direction of the car's average acceleration can be calculated in terms of x and y coordinates. The acceleration in the x and y directions can be calculated by taking the derivatives of the velocity components in those directions with respect to time. Once these components are known, they can be used to calculate the magnitude and direction of the car's acceleration. To calculate the magnitude of the car's acceleration, the Pythagorean theorem is used, which states that \(a^2 = a_x^2 + a_y^2\).

In this case, a_x represents the acceleration in the x direction, while \(a_y\) represents the acceleration in the y direction. Therefore, the magnitude of the car's acceleration can be expressed as follows:

a = \((a_x^2 + a_y^2)^{1/2}\)

The direction of the car's average acceleration is given by the angle θ, where \(tan(\theta) = a_y / a_x\). This angle can be calculated using the inverse tangent function, or arctan. Once the angle is known, it can be used to determine the direction of the acceleration in relation to the x and y axes. If the angle is positive, the acceleration is in the first or third quadrant of the coordinate plane, while if it is negative, the acceleration is in the second or fourth quadrant.

The direction of the car's average acceleration can be calculated in terms of x and y coordinates by finding the magnitude of the acceleration using the Pythagorean theorem and then calculating the angle using the inverse tangent function. The angle can be used to determine the direction of the acceleration in relation to the x and y axes.

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Answer: Slow moving feather

The parked car has 0 velocity since it is stationary. The momentum of the car is 0 because momentum = mass*velocity.

On the other hand, the feather is moving, so its velocity is some positive value. Even if it's a small velocity value and the mass of the feather is small, the two will multiply to some positive momentum which is larger than 0.

So the feather has larger momentum compared to the parked car.

Answer:

A.) Time = 0.625 hrs = 37.5 minutes

B.) Speed required = 133.33km/hr

Explanation:

Given the following :

Total race distance = 100km

Total time required = 1 hour = 60 minutes

Average speed after traveling 50km = 80km/hr

80km/hr : This means it will take one hour to cover a distance of 80km

Therefore, time taken to cove first 50km at that average speed equals :

1 hour = 80 km

t hours = 50km

80t = 50

t = 50/80

t = 5/8 hours

t = 0.625hours

t = 0.625 * 60 = 37.5minutes

B)

Average speed required to complete the race in 1 hour = 100km/hr

Time used to complete first 50km = 0.625 hour

Time remaining: (1 - 0.625) hour = 0.375

Speed required = Distance left / time left

Speed required = 50 / 0.375

Speed required = 133.33km/hr

The universe may indeed have an end one day according but it is yet to be shown in science.

While there is certainly no way a person will live long enough to know if the universe will end or not, nevertheless certain scientific calculations are helpful.

From astronomical calculations, the universe is anticipated to have existed for about 13.8 million years. Thus, the universe may indeed have an end one day according but it is yet to be shown in science.

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Answer:

My teacher said 36m when I asked her

Explanation:

HOPE THIS HELPS!!

Answer: Ionisation is the process of an atom gets a negative or a positive charge by gaining or losing electrons. The result is an ion.

Explanation: Thats why

Answer:

depends both on the density and temperature of the cloud.

(a) The moment of inertia of the wheel is 22.8 kg·m².

(b) The magnitude of the frictional torque is 3.67 N·m.

(c) The total number of revolutions of the wheel during the entire interval of 67.1 s is approximately 4.83 revolutions.

(a) To find the moment of inertia of the wheel, we can use the formula for torque:

Torque = Moment of inertia * Angular acceleration

The total torque is 36.1 N·m and the angular acceleration is the change in angular speed divided by the time, we have:

36.1 N·m = Moment of inertia * (9.8 rad/s - 0 rad/s) / 6.20 s

Simplifying the equation:

Moment of inertia = (36.1 N·m * 6.20 s) / 9.8 rad/s

Moment of inertia = 22.8 kg·m²

Therefore, the moment of inertia of the wheel is 22.8 kg·m².

(b) After the applied force is removed, the wheel comes to rest, indicating that the torque due to friction is acting in the opposite direction to oppose the wheel's motion. We need to find the magnitude of this frictional torque.

The frictional torque can be found using the equation:

Torque = Moment of inertia * Angular acceleration

Since the wheel comes to rest, its final angular speed is 0 rad/s, and the time taken for it to come to rest is 60.9 s. Therefore, the angular acceleration can be calculated as:

Angular acceleration = (0 rad/s - 9.8 rad/s) / 60.9 s

Plugging in the values:

Angular acceleration = -0.161 rad/s²

Now we can find the frictional torque:

Torque = 22.8 kg·m² * (-0.161 rad/s²)

The magnitude of the frictional torque is 3.67 N·m.

(c) The total number of revolutions can be calculated by finding the total angle rotated by the wheel in radians and converting it to revolutions.

During the first 6.20 s, the wheel rotates from 0 rad/s to 9.8 rad/s. The total angle rotated can be found using the equation:

θ = 0.5 * (initial angular speed + final angular speed) * time

θ = 0.5 * (0 rad/s + 9.8 rad/s) * 6.20 s

θ = 30.38 rad

During the next 60.9 s, the wheel comes to rest, so the total angle rotated is 0 rad.

Therefore, the total angle rotated by the wheel in 67.1 s is 30.38 rad.

To convert this to revolutions, we divide by 2π radians, since there are 2π radians in one revolution:

Number of revolutions = 30.38 rad / (2π rad/rev)

Number of revolutions ≈ 4.83 revolutions

Therefore, the total number of revolutions of the wheel during the entire interval of 67.1 s is approximately 4.83 revolutions.

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Answer:

Neil Armstrong

Explanation:

Answer:

Neil Armstrong.

Explanation:

. PLEASE GIVE BRAINLIEST.

You have a balloon containing 1.4 L of gas in it at standard temperature and pressure. the answer is option (e) \(1 L/6.02 \times 10^{23 }\) mole, since it represents the conversion factor from moles to the volume of one molecule of gas at STP.

To convert the given volume of gas (1.4 L) to moles, we need to use the ideal gas law equation, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

At standard temperature and pressure (STP), the temperature is 273 K and the pressure is 1 atm. Therefore, we have:

P = 1 atm
V = 1.4 L
n = ?
R = 0.0821 L*atm/mol*K
T = 273 K

Using the ideal gas law equation, we can solve for n:
n = PV/RT
\(n = (1 atm) \times (1.4 L) / (0.0821 L \times atm/mol \times K \times 273 K)\)
n = 0.0559 mol

Now, we need to choose the correct conversion factor to convert the calculated number of moles to the answer choices provided. Option (a) is the conversion factor for the volume of one mole of gas at STP, so it is not the correct choice.

Option (b) is Avogadro's number, which is the number of particles (molecules or atoms) in one mole of substance, so it is also not the correct choice. Option (c) is the reciprocal of the conversion factor in (a), so it is not the correct choice.

Option (d) is the reciprocal of the conversion factor in (a), but it is written in a different form, so it is also not the correct choice.

The correct conversion factor is option (e), which is the volume of one molecule of gas at STP. This option is obtained by rearranging the Avogadro's number and the volume of one mole of gas conversion factors:

\(1\; mole = 6.02 \times 10^{23}\; molecules\)
1 mole = 22.4 L (at STP)
\(1 \;molecule = 22.4 L / 6.02 \times 10^{23}\)
\(1\; molecule = 3.72 \times 10^{-23} L\)

Therefore, the answer is (e) \(1 L/6.02 \times 10^{23}\) mole, since it represents the conversion factor from moles to the volume of one molecule of gas at STP.

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Complete Question:

You have a balloon containing 1.4 L of gas in it at standard temperature and pressure. Which conversion factor would you use to convert this number to moles?

a. 22.4L/1 mole

b. 6.02 * 1023 L/1 mole

c. 1L/22.4 mole

d. 1 mole/224L

e. 1L/6.02 x 1023 mole

It produces oceanic crust,

Answer:

CO2 + H2O + O2

Explanation:

The correct statement that identifies the products of photosynthesis is C6H12O6 + O2. In photosynthesis, carbon dioxide, water, and light are used to produce glucose and oxygen.

Photosynthesis is a biological process that converts light energy, usually from the Sun, into chemical energy in plants, algae and certain types of bacteria. The photosynthesis formula is usually depicted as: 6CO2 + 6H2O + light energy = C6H12O6 + 6O2. This means that the correct statement that identifies the products of photosynthesis is C6H12O6 + O2. In this reaction, carbon dioxide (CO2), water (H2O) and light are used to produce glucose (C6H12O6) and oxygen (O2). The glucose is used by the plant for energy and growth while oxygen is a byproduct released into the atmosphere.

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When a 68.5 kg football player gliding on smooth ice at 1.80 m/s throws a 0.440 kg football, his speed afterward depends on the ball's velocity relative to the ground or relative to the player. By applying the conservation of momentum, the player's final velocity can be determined in each case.

a) To calculate the player's speed afterward when the ball is thrown at 14.5 m/s relative to the ground, we can use the principle of conservation of momentum.

The initial momentum of the system (player + ball) is given by:

Initial momentum = (mass of player) × (initial velocity of player) + (mass of ball) × (initial velocity of ball)

Initial momentum = (68.5 kg) × (1.80 m/s) + (0.440 kg) × (0 m/s)  [since the ball is initially at rest]

The final momentum of the system is given by:

Final momentum = (mass of player) × (final velocity of player) + (mass of ball) × (final velocity of ball)

Since momentum is conserved, we can equate the initial and final momenta:

Initial momentum = Final momentum

(68.5 kg) × (1.80 m/s) = (68.5 kg) × (final velocity of player) + (0.440 kg) × (14.5 m/s)

Now we can solve for the final velocity of the player.

b) To calculate the player's speed afterward when the ball is thrown at 14.5 m/s relative to the player, we need to consider the velocity of the ball with respect to the player. Since the ball is thrown straight forward, its velocity relative to the player is 14.5 m/s.

Using the same principle of conservation of momentum, we can again equate the initial and final momenta:

(68.5 kg) × (1.80 m/s) = (68.5 kg) × (final velocity of player) + (0.440 kg) × (-14.5 m/s)  [negative sign indicates opposite direction]

Now we can solve for the final velocity of the player in this scenario.

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Time with program duration at a constant amount of acceleration: 1 to 4 seconds. In mechanics, acceleration is the price you pay for exchanging the speed of an object for time.

Acceleration is a vector quantity. The direction of acceleration of an object is given by the direction of the net force acting on it. Acceleration is the name we give to any method of adjusting speed. If you think of velocity as velocity and path, then there is the simplest way to acceleration: change alternate velocity or alternate path - or both.

Acceleration (a) is the exchange of the ratio (Δv) for the change in time (Δt) expressed by the equation a = Δv/Δt. There are three styles of ascent motion: uniform acceleration, non-uniform acceleration, and medium acceleration. . Uniform acceleration, non-uniform acceleration, and medium acceleration are three types of improved motion. Uniform time acceleration refers to the motion in which an object moves in a straight line, jumping with the speed at equal time intervals.

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In one hour, 500x10^3 ft-lbr of work is done. 0.189 kW is the average power in kilowatts.

To find the average power in kilowatts when 500,000 ft-lbf of work is done in one hour, we'll first convert the work from foot-pounds to joules and then use that value to find the average power in kilowatts.

= 1 ft-lb

= 1.356 J

500,000 ft-lbf of work is equivalent to:-

= 500,000 ft-lbf x 1.356 J/ft-lb

= 678,000 J

Now, we'll use this value to find the average power in kilowatts:

= (work,J) ÷ (time,s)

= (average power in watts)

= 1 hr = 3600 sec,

= 678,000 J / 3600 seconds

= 189 W

Finally, we'll convert the average power in watts to kilowatts:

= (average power in W) / 1000

= (average power in kW)

= 189 W / 1000

= 0.189 kW

Hence, the average power in kilowatts when 500,000 ft-lbf of work is done in one hour is 0.189 kW.

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Answer:

I guess that you want to calculate the averae time that passes since you "fire" the laser, and you see the reflection.

We know that:

Distance = Time*Speed

Distance/speed = time.

In this case we have:

Distance = 385,000km

Speed = 3x10^8m/s

First, there are two corrections:

1) The distance to the moon is traveled two times, so the actual distance would be:

Distance = 2*385,000km = 770,000km

2) Both quantities should be written in the same units, so we can write the speed in kilometers:

We know that:

1km = 1000m

Then 3x10^8 m/s = (3x10^8/10^3) km/s = 3x10^(8 - 3) km/s = 3x10^5 km/s

Now we can solve the equation:

Time = 770,000km/(300,000 km/s) = 2.57 seconds.

a b c d

A V=V+gt

dhehehdhehdhshehehehehehe

Answer:

karishma tanna

Explanation:

it is correct

Karishma Tanna was declared as the winner.

Answer:

B

Explanation:

Answer is B because the ball passes at 10 to 30

True. Warm air expands faster, leading to a more rapid decrease in air pressure with height than in cold air.

True. In a warm air column, the air molecules have higher kinetic energy and move more vigorously. This increased motion leads to greater expansion of the air column and a more rapid decrease in air pressure with height. As the warm air rises, it expands and becomes less dense, causing the pressure to decrease at a faster rate. In contrast, in a cold air column, the air molecules have lower kinetic energy and move more slowly.

The reduced motion results in less expansion of the air column and a slower decrease in air pressure with height. Therefore, air pressure decreases more rapidly with height in a warm air column compared to a cold air column.

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The minimum possible coefficient of static friction between the bike tires and the ground is 0.734.

The minimum possible coefficient of static friction is that at which the moving object is on the verge of the stopping state.

Radius of the curve, (R) = 20 m.

Velocity of the cyclist, (v) = 12 m/sec

g = 9.81 m/s²

On a circular curve, the cyclist will experience the centrifugal force(F) which acts outwards. This force is,

F = mv²/R

This centrifugal force(F) is balanced by the static friction force(Fₓ). Which is,

Static friction force = mg × coefficient of static friction(Ц)

mv²/R = mg × coefficient of static friction(Ц)

coefficient of static friction(Ц) = v²/gR

= (12×12)/(9.81×20)

= 0.734

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The moon pulls each kilogram with water in the Kamali River with a force of 5.19 x 10-5 N, or strength or energy used or brought to bear.

The term "force" has a clear definition in science. It is quite acceptable to refer to a force of this level as a push or perhaps a pull. An object does not "have in it" or "contain" a force. One thing is subject to a force from another. There is no distinction between living and non-living things in the concept of a force.

r3 = 105 kilometers x 10 m 3 x 108m

1 kmF=G.M.mp2

6.67 x 10-11 N kg 2. m2 X 7 × 1022 kg X 1 kg\s(3 x 108 m) (3 x 108 m) 2\s5.19 x 10-5 N

A push that has the potential to accelerate something is called a force. A physical push could be used to move a large furniture item around a room. It might be less concrete, like depressing a gas pedal in such a car. J

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Answer:

12

Explanation:

600/50 is 12 so the answer is twelve

Answer:

The correct answer is "\(12\times 10^{-6} \ C\)".

Explanation:

Given that,

\(Q1=+4.0\times 10^{-6} \ C\)

and,

\(Q2=+2.0\times 10^{-5} \ C\)

or,

     \(=20\times 10^{-6} \ C\)

then,

The total charge will be:

⇒ \(Q =Q1+Q2\)

       \(=(+4.0\times 10^{-6}) +(20\times 10^{-6})\)

       \(=24.0\times 10^{-6} \ C\)

hence,

After separation, the charge on each sphere will be:

⇒ \(q=\frac{Q}{2}\)

       \(=\frac{24.0\times 10^{-6}}{2}\)

       \(=12\times 10^{-6} \ C\)

Answer:

Yes, one of them made a mistake

Explanation:

Even though, the two values obtained in the measurements are close, the student that reported 3.01 m made a mistake.

A meter rule that is calibrated in meters (m) will only have an accuracy of 0.1 m, hence can be read as 3.0 m, 3.1 m, 3.2 m, 3.3 m and so on. A meter rule that is calibrated in meters cannot provide accuracy of up to 0.01 m, hence the student that reported 3.01 m could not have been sure of the .01 added as it couldn't have been read on the meter rule.

NOTE: A meter rule (popularly known as ruler) is an instrument that is used in the measurement of the length of an object. It can be calibrated in centimeter, inch or meter.