if an object measures to be 80 centimeters in length, then it is equivalent to ____​

Answer:

what

Explanation:

The voltage increase is Vf-VI (Positive because the voltage increases as we move across the resistor). Therefore, the correct option is (e) +IR in the first case and -IR in the second case.

As per the given problem, the voltage change if you cross a resistor R opposite the direction of the current I is Vf-Vi (where Vi is the voltage where the current leaves the resistor and Vf is the voltage where the current enters the resistor.)Let us suppose that the current I moves from left to right through the resistor.

The electrons are moving in the opposite direction. So they are moving from right to left. The conventional current (I) goes from left to right. The voltage drop across the resistor is thus VI-VF. (Negative because the voltage decreases as we move across the resistor).

The voltage change if you cross a resistor R in the same direction as the current I is Vf-Vi (in this case Vi is the voltage where the current enters the resistor and Vf is the voltage where the current leaves the resistor.)Here, the current flows from left to right through the resistor. This time, electrons are also flowing from left to right.

The voltage increases as we move across the resistor from left to right (with the current). Therefore, the voltage increase is Vf-VI (Positive because the voltage increases as we move across the resistor).

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The amount of thermal energy required to raise the temperature of 20 gallons of water from 60 °F to 120 °F is approximately:

To calculate the amount of thermal energy required to raise the temperature of water, we can use the specific heat capacity of water and the equation:

Q = m * c * ΔT

Where:

Q is the thermal energy

m is the mass of water

c is the specific heat capacity of water

ΔT is the change in temperature

Given:

Volume of water (V) = 20 gallons

Density of water (ρ) = 8.34 pounds per gallon (approximate value)

Specific heat capacity of water (c) = 1 BTU/(lb·°F)

Change in temperature (ΔT) = (120 °F - 60 °F) = 60 °F

First, we need to convert the volume of water to mass:

Mass (m) = Volume (V) * Density (ρ)

m = 20 gallons * 8.34 lb/gallon

m ≈ 166.8 pounds

Now we can calculate the thermal energy in British Thermal Units (BTU):

Q = m * c * ΔT

Q = 166.8 lb * 1 BTU/(lb·°F) * 60 °F

Q ≈ 10,008 BTU

To convert BTU to joules (J), we use the conversion factor 1 BTU = 1055.06 J:

Q_joules = Q_BTU * 1055.06 J/BTU

Q_joules ≈ 10,008 BTU * 1055.06 J/BTU

Q_joules ≈ 10,558,562.08 J

To convert joules to calories (cal), we use the conversion factor 1 cal = 4.184 J:

Q_calories = Q_joules / 4.184 J/cal

Q_calories ≈ 10,558,562.08 J / 4.184 J/cal

Q_calories ≈ 2,525,445.88 cal

Therefore, the amount of thermal energy required to raise the temperature of 20 gallons of water from 60 °F to 120 °F is approximately:

10,008 BTU

10,558,562.08 joules

2,525,445.88 calories

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Answer:

sound waves are used to send signals because they...

Answer:

^ correct

Explanation:

Option A on edge 2020

The average specific heat capacity of the liquid in this temperature is 2506 J/kg/C

The specific heat capacity, or massic heat capacity, of a substance is calculated using thermodynamics as the heat capacity of a sample of the substance divided by the mass of the sample.A substance's specific heat capacity may be substantially higher when heated in an open vessel that permits expansion than when heated in a closed vessel that prevents expansion, especially when the substance is a gas (specific heat capacity at constant pressure) (specific heat capacity at constant volume).

the amount of heat input to the liquid is 65W x 120s = 65(J/s) x 120s = 7800J

then we have that

Q = \(m\times c \times \delta t\) so that

c = (\(\frac{Q}{m\times\delta t}\)) = \(\frac{7800J}{0.78kg * 3.99C}\) = 2506 J/kg/C

if some of the energy heated the container or surroundings, then less energy actually went into heating the liquid; if less energy caused the 3.99C temp increase, the specific heat must be less, so the value we just calculated is an overestimate.

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125M far does it travel during this time interval.

The ball slows down halfway through and reaches zero velocity at the top. The ball's acceleration is the same throughout the throw. Towards Earth, he is 9.8 m/s2. The direction of travel of the ball remains upwards. The average velocity is a scalar, so the answer does not include a direction.

Projectile instantaneous velocity at maximum altitude is zero. Gravity gives the ball the same acceleration-deceleration when it rises as it does when it descends and accelerates so the time to reach the maximum height is the same as the time to return to the starting position. increase. Acceleration is zero if there is no change in the object's velocity. at the highest point.

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This indicates that the pendulum clock on Venus will operate at a frequency that is roughly 97.3% of that on Earth.

A basic pendulum's period is determined by the length of the pendulum and the acceleration caused by gravity. On Venus, the gravity-related acceleration is 8.87 m/s2, which is lower than the gravity-related acceleration on Earth (9.81 m/s2). As a result, the pendulum will oscillate more slowly on Venus than it will on Earth. We must apply the method above, which accounts for both the length of the pendulum and the acceleration brought on by gravity, to get the precise time period on Venus. We just need to account for the difference in the acceleration caused by gravity since the length of the pendulum is constant on both worlds. As a result, the pendulum clock will operate more slowly.

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The transformation of Polaroid in recent years has been characterized by a shift from analog instant photography to embracing digital technologies and modernizing its product offerings. This transformation has allowed Polaroid to adapt to the changing market and cater to the needs and preferences of today's consumers.

In recent years, Polaroid has introduced a range of digital instant cameras that combine the nostalgic appeal of instant photography with the convenience and versatility of digital imaging. These cameras typically feature built-in printers that produce instant prints, capturing the essence of Polaroid's iconic instant photography experience. Additionally, Polaroid has embraced the smartphone era by developing products like the Polaroid Lab, which allows users to turn digital photos from their smartphones into classic Polaroid-style prints.

Furthermore, Polaroid has expanded its product lineup to include various accessories, such as portable printers and film formats compatible with both analog and digital devices. By embracing digital technologies while staying true to its instant photography heritage, Polaroid has successfully repositioned itself in the market, appealing to a new generation of photography enthusiasts seeking a blend of nostalgia and modern functionality.

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Answer:

extension = 0.9 m

Explanation:

The formula relating force to extension for a spring is given as follows:

\(\boxed{F = kx}\),

where:

• F = force applied on spring

• k = spring constant

• x = extension of spring

From the above formula:

\(\frac{F}{x} = k = \mathrm{constant}\)

This means that, for a spring, the ratio \(\frac{F}{k}\) is a constant value. Therefore, we can say:

\(\frac{F_1}{x_1} = \frac{F_2}{x_2}\)

Substituting 2.0N and 0.30m for F₁ and x₁ respectively, and 6N for F₂, in the above equation, we can solve for x₂:

\(\frac{2.0}{0.3} = \frac{6.0}{x_2}\)

⇒ \(x_2 \times \frac{2.0}{0.3} = 6.0\)          [Multiplying both sides of the equation by x₂]

⇒ \(x_2 = 6.0 \div \frac{2.0}{0.3}\)

⇒ \(x_2= \bf 0.9 m\)

Therefore, the extension of the spring when 6N force is applied is 0.9 m.

The extension of the spring when the force applied becomes 6 N is 0.9 m.

The force constant or spring constant of the spring is calculated as follows;

F = kx

k = F/x

where;

k = (2 N) / (0.3 m) = 6.67 N/m

The extension of the spring when the force applied on the spring becomes 6 N is calculated as follows;

x = F/k

x = (6 N) / (6.67 N/m)

x = 0.9 m

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An object's density influences whether it will float or sink in another material. If an object is less dense than the liquid it is placed in, it will float. If an object is denser than the liquid in which it is immersed, it sinks.

The density of a substance is a measure of how tightly it is packed. It is stated in terms of mass per unit volume. Density is represented by the symbol D, and the density formula is: = m/V, where is the density, m is the object's mass, and V is its volume. A material's density is defined as its mass per unit volume. The most frequent density symbol is, however the Latin letter D can also be used. Mathematically, density is defined as mass divided by volume.

Here,

The density of a thing influences whether it will float or sink in another substance. If an object is less dense than the liquid in which it is placed, it will float. If an object is more dense than the liquid it is immersed in, it will sink.

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Answer:

what is the question? there isn't one

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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The gravitational force on an object at a point in space a distance R above the Earth's surface can be calculated using the equation: F = (G × M × m) / R²where F is the gravitational force, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object, and R is the distance from the center of the Earth to the object.

The Earth's radius is used to determine the distance from the Earth's surface to the object, so R = 6,371 km. The mass of the Earth is approximately 5.97 × 10²⁴ kg, and the gravitational constant is approximately 6.67 × 10⁻¹¹ N m²/kg². So, using these values and assuming the mass of the object is 1 kg:

F = (6.67 × 10⁻¹¹ N m²/kg² × 5.97 × 10²⁴ kg × 1 kg) / (6,371,000 m)²= 9.81 N This result is the same as the acceleration due to gravity on the Earth's surface, which is 9.81 m/s². This means that an object at a distance R above the Earth's surface experiences the same gravitational force as an object on the Earth's surface, but it has a different weight due to the reduced acceleration due to gravity.

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Answer:

Atoms are so much smaller than the wavelength of visible light that the two don't really interact.

Explanation:

To put it another way, atoms are invisible to light itself.

Visible light has a wavelength that ranges from 400 to 700 nm. Atoms, in contrast, typically have a diameter of between 0.1 and 0.3 nm. The size difference is greater than a thousand times, even with straightforward calculations.

Over 500,000 times of magnification are possible using an electron microscope, which is sufficient to observe a great deal of information inside cells.

The electron microscope comes in a variety of varieties. Atoms and nanoparticles can be observed with the use of a transmission electron microscope.

In a chemical reaction, atoms cannot be formed or destroyed, since they are indivisible units. The mass and chemical characteristics of each atom of a specific element are the same.

Therefore, the atom's structure is invisible to visible light.

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The gravitational force that exerts on the outer out in space is 1.73 ×\(10^{-7}\)N.

Gravitational force:

The force of gravity or gravitational force pulls objects with mass towards each other. The gravitational force between two objects can be calculated as a function of the product of their masses (M and m), the square of the distance between them(r), and the universal gravitational constant.

The formula is:

F = G Mm/r²

Let us assume that g = 10 m/s².

M = 11000/ 10 = 1100kg

m = 3400/10 = 340kg

The distance was given:

r = 12m

We can look up a value of G:

G = 6.674 ×\(10^{-11}\) m³ / kgs²

F = 6.674 \(10^{-11}\) ( 1100 × 340)/ 12²

  = 17333.86 ×\(10^{-11}\)

  = 1.73×\(10^{-7}\)N

Therefore the gravitational force is 1.73 ×\(10^{-7}\)N.

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Answer:

The resultant displacement of the airplane in 4 hours is 212.8 km.

Explanation:

The components of the airplane's velocity and wind's velocity are:

Airplane:

\( v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h \)

\( v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h \)

Wind:

\( v_{w_{x}} = 0 \)

\( v_{w_{y}} = v_{w} = -30 km/h \)

Now, to know the new velocity of the airplane we to find the result vector:

\( v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h \)

\(v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h\)  

Now, the magnitude of the new speed of the airplane is:

\( v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h \)

Finally, after 4 hours the resultant displacement of the airplane is:

\( x = v*t = 53.20 km/h*4 h = 212.8 km \)

Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.

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Answer:

Metal B

Explanation:

Metallic bonds melt at high temperatures. Metal B has the highest melting point of the 4 metals given.

The linear acceleration of the system is a = g (1 - μk) / 3

Tension force in the vertical section of the string is T = M g

Tension force in the horizontal section of the string is 2 M g (1 - μk).

Minimum value of μs is 3 μs + μk ≥ 1

a. The system is in equilibrium when the tension force in the string balances the weight of block A. Therefore: T - M g = M a

where T is the tension force in the string, g is the acceleration due to gravity, and a is the linear acceleration of the system.

The system of block B is subject to a friction force opposing its motion to the right. Therefore: T = 2 M g - μk N

where N is the normal force exerted by the table on block B.

The normal force N is equal in magnitude to the weight of block B, since the block is not accelerating in the vertical direction. Therefore:

N = 2 M g

Substituting N into the equation for T:

T = 2 M g - μk (2 M g)

T = 2 M g (1 - μk)

Substituting this expression for T into the equation for the acceleration: (2 M g) (1 - μk) - M g = M a

Simplifying: a = g (1 - μk) / 3

Therefore, the linear acceleration of the system is: a = g (1 - μk) / 3

b. The tension force in the vertical section of the string is equal in magnitude to the weight of block A. Therefore: T = M g

c. The tension force in the horizontal section of the string can be found by considering the torque equation for the pulley. The torque due to the tension force on the pulley is equal to I α, where α is the angular acceleration of the pulley. Since the pulley is in equilibrium, we have α = 0, and the torque due to the tension force is zero. Therefore, the tension force in the horizontal section of the string is also equal to T, which we found to be equal to 2 M g (1 - μk).

d. The minimum value of μs such that the blocks will not move is given by the condition:

μs ≥ a / g

where a is the linear acceleration of the system.

Substituting the expression for a that we found earlier: μs ≥ (1 - μk) / 3

Multiplying both sides by 3 and adding μk to both sides: 3 μs + μk ≥ 1

Therefore, the minimum value of μs is: μs ≥ (1 - μk) / 3 or equivalently: 3 μs + μk ≥ 1

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Mechanical waves are (A) a ringing telephone and (B) ripples on a pond

Mechanical waves are waves that require a medium in order to travel through, meaning they cannot travel through a vacuum. They cause oscillations or vibrations of particles within that medium.

Based on this definition, the mechanical waves among the given options are:

B) Ripples on a pond: These waves are created by disturbances in water, causing energy to be transferred from particle to particle in the water, making it a mechanical wave.

A) A ringing telephone: When you hear a phone ringing, the sound waves are created by the vibration of a diaphragm that causes vibrations in the air molecules, resulting in a mechanical wave.

FM radio (C) and green light (D) are not mechanical waves. FM radio waves are a type of electromagnetic waves that can travel through a vacuum, while green light is a part of the electromagnetic spectrum that behaves as a transverse wave, also not needing a medium to travel through.

In conclusion, mechanical waves require a medium to propagate, whereas electromagnetic waves do not. Among the given options, A and B are mechanical waves, while C and D are not.

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Answer:

Climate scientists compare the tree growth records to local weather records. For locations where a good statistical match exists between tree growth and temperature or precipitation during the period of overlap, the ring widths can be used to estimate past temperature or precipitation over the lifetime of the tree.

A supermassive black hole's host galaxy can be dramatically impacted in a number of ways. First, due to its powerful gravitational attraction, the galaxy's structure may be disturbed by its influence on the orbits of neighboring stars and gas.

Additionally, the falling debris might cause the creation of an accretion disc surrounding the black hole, which would release strong radiation jets and energetic particles. The interaction of these jets with the surrounding gas can lead to the birth of new stars, changing the galaxy's pace of star formation. Furthermore, the energy generated by these processes has the potential to eject gas from the galaxy, altering its overall gas composition and possibly suppressing star formation.

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Answer:

the answer is A. A school crossing guard raises a stop sign that weigh 10 N

Only the school crossing guard who raises a stop sign that weighs 10 N does the work.

Work done in physics is defined as the dot product of force and displacement caused by it. Mathematically -

W = F.x

W = |F| |x| cos Ф

where Ф is the angle between force and displacement

Given are the various situations from which we have to select the situation in which work is done.

A specific amount of displacement is needed for the work to be done. Similarly, the displacement and the force vectors should not have 90 degree angle between them. If any of this is zero than -

W = F × 0 = F × x × cos(90) = 0

It is only in case A that the guard applies a force equal to the weight of the stop sign and displacement is in the same direction. While in other three cases, either displacement is zero (C) or the angle between displacement and force is 90 degrees (B & D).

Therefore, we can conclude that, only the school crossing guard who raises a stop sign that weighs 10 N does the work.

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Option C is correct. A person moves away from a stationary sound source, the sound perceived by the person will be of the lower pitch and longer wavelength.

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometers, and other units since it is a distance measurement.

The relationship between the wave's wavelength, frequency, and speed is given as

wavelength = speed of light / frequency

As the person moves away from a stationary sound source, then the value of pitch is decreasing. On the other hand, sound needs a longer wavelength to travel.

Hence Option C is correct.

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Compared to a cluster containing type O and B stars, a cluster with only type F and cooler stars will be less luminous and have a lower surface temperature.

Type O and B stars are much hotter and brighter than type F and cooler stars. They have surface temperatures over 10,000 K and are several hundred times more luminous than the Sun. On the other hand, type F and cooler stars have surface temperatures ranging from 6,000 K to less than 3,500 K and are much less luminous than O and B stars.

Therefore, a cluster containing only type F and cooler stars will not shine as brightly and will have a lower surface temperature compared to a cluster with type O and B stars.


Stellar clusters are groups of stars that are gravitationally bound and formed from the same molecular cloud. Stars within these clusters can be of various types, based on their surface temperatures and luminosities, which are classified using the Morgan-Keenan (MK) system. Type O and B stars are hotter, more massive, and more luminous than type F and cooler stars.

Type O and B stars have shorter lifespans due to their higher mass and faster rate of nuclear fusion, while type F and cooler stars have longer lifespans. When a cluster is young, it may have a mix of various star types, including O and B stars. However, as the cluster ages, the O and B stars will exhaust their nuclear fuel and end their lives, leaving behind the longer-lived F and cooler stars.

Therefore, a cluster with only type F and cooler stars indicates that it has evolved for a longer time compared to a cluster containing type O and B stars, making it an older cluster.

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Answer:

need i help with 1-7 please

Answer:his tension is 262 N

Explanation:1) Call T the tension of the rope2) Split T into its horizontal and vertical components.3) Horizontal component of the tension, Tx = T cos(55°)4) Vertical component of the tension, Ty = T sin (55°)5) Force equilibrium in the vertical direcction:∑Fy = 0Ty + normal force - weight of the sled = 0Call N the normal forceTy + N - 56 kg * 9.8 m/s^2Ty + N = 56 kg * 9.8 m/s^2Ty + N = 548.8NT sin(55) + N = 548.8N6) Force equilibrium in the horizontal directionconstant velocity => ∑Fx = 0Tx - Fx = 0Tcos(55) - Fx = 07) Fx is the friction force.The friction force and the normal force are related by the kinetic friction coefficient.Call μk the friction coefficientFx = μk N=> Tcos(55) - μk N = 0Tcos(55) - 0.45N = 08)  Solve the system of two equations:Eq (1) T sin(55) + N = 548.8Eq (2) T cos(55) - 0.45N = 0Eq(1) 0.819T + N = 548.8Eq(2) 0.574T - 0.45N = 0The solution of the system is T = 262.01 N and N = 334.21 NThen T ≈ 262N

(a) The wood has the greater buoyant force on it.

To explain further, the buoyant force acting on an object submerged or floating in a fluid is equal to the weight of the fluid displaced by the object. The buoyant force opposes the weight of the object and determines whether it floats or sinks.

In this case, the wood is floating on water, which means it displaces a volume of water equal to its own volume. The iron, on the other hand, is totally submerged in water, displacing a volume of water equal to its own volume.

Since the volume of the wood (36.50 cm³) is less than the volume of the iron (50 cm³), it means that the wood displaces less water than the iron. Therefore, the buoyant force acting on the wood is smaller than the buoyant force acting on the iron.

Hence, the wood experiences a smaller buoyant force compared to the iron, making the answer (a) the correct option.

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