If f(x)= x2 + 7; Find x if f(x)= 23

Answer: 0.88 lbs.

Step-by-step explanation:

12/30 = 0.4 (she needs to lose 0.4 kg everyday)

0.4 x 2.2 = 0.88 lbs

Answer:

B. Divide both sides by 26

Explanation:

When doing a one step equation you basically want to get the x alone. To do that you need to divide 26x by 26.

26x = 74

26 26

x = 2.8

When the base of a triangle is fixed at 2.218 millimeters, the area will be 0.1098 mm².

It should be noted that the area of a triangle is calculated as:

Area of triangle = (1/2)×base×height

= (1/2) × 2.218 mm × 0.099 mm

= 1.109 mm × 0.099 mm

= 0.109791 mm²

≈ 0.1098 mm²

Therefore, the area is 0.1098 mm².

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The base of a triangle is fixed at 2.218 millimeters. Determine the number of

significant figures of the area of the triangle with each given height of 0.099mm.

By utilizing the methods, we can make valid and meaningful comparisons between several population means while appropriately controlling for errors and maintaining statistical power.

When comparing several population means, it is not feasible or appropriate to perform a bunch of two-sample t-tests for several reasons.

Increased Type I Error Rate: When conducting multiple hypothesis tests, there is an increased chance of making a Type I error, which is rejecting a null hypothesis when it is actually true. The more tests we perform, the greater the likelihood of observing statistically significant results by chance alone. This phenomenon is known as multiple comparisons problem or familywise error rate inflation. Performing multiple t-tests without adjusting for multiple comparisons can lead to an inflated overall Type I error rate.

Increased Chance of False Positive Results: Conducting multiple t-tests without appropriate adjustments increases the chance of obtaining false positive results. With each additional test, the probability of incorrectly concluding a significant difference between means due to random variation alone increases. This can lead to spurious findings and misleading interpretations.

Lack of Control for Experiment-Wide Error: Conducting multiple t-tests does not provide a control for the overall experiment-wise error rate. When comparing several population means simultaneously, it is essential to control the overall Type I error rate to maintain the desired level of statistical significance.

Loss of Statistical Power: Conducting multiple tests without appropriate adjustments can lead to a loss of statistical power. Power refers to the ability to detect a true effect when it exists. When multiple t-tests are performed, the individual sample sizes for each comparison may become smaller, reducing the power to detect true differences between population means.

To address these issues and appropriately compare several population means, various statistical techniques are available. Some common approaches include:

Analysis of Variance (ANOVA): ANOVA allows for simultaneous comparison of means across multiple groups. It tests the null hypothesis that all means are equal and provides an overall F-test to determine if there are significant differences between the groups. ANOVA takes into account the variation within and between groups, providing a more comprehensive analysis compared to multiple t-tests.

Multiple Comparison Procedures: If ANOVA reveals a significant overall difference, multiple comparison procedures, such as Tukey's Honestly Significant Difference (HSD) test or the Bonferroni correction, can be used to identify specific pairwise differences between means while controlling for the experiment-wise error rate.

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Answer:

The common continuous interval will be (0,∞).

Step-by-step explanation:

Given that,

The numerator = 12+√x

The denominator = √12+x

We know that,

For the numerator,

Any function under square root should be greater than and equal to the zero.

\(x\geq 0\)

So, the continuous interval is (0, ∞)

For the denominator,

\(\sqrt{12+x}>0\)

\(12+x>0\)

\(x>-12\)

The interval for the continuous and non zero function is,

(-12, ∞)

We need to calculate the continuous interval

Using given quotient

\(\dfrac{12+\sqrt{x}}{\sqrt{12+x}}\)

The continuous interval of numerator and  denominator are (0, ∞) and (-12, ∞).

Hence, The common continuous interval will be (0,∞).

The conditions for working with t are random sampling, normality, Independence, Sample size, Equal variances.

When working with confidence intervals and hypothesis testing, there are several conditions that need to be met in order to ensure the validity of the results. These conditions typically apply to the sample data being used and may differ depending on the specific statistical method being used. Here are some common conditions to consider when working with t:

It's important to keep in mind that these conditions are not always necessary or sufficient for ensuring the validity of statistical results. They are general guidelines that can be useful in many situations, but the specific conditions required will depend on the particular statistical method being used and the research question being addressed.

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Answer:

Try 34697

If it's correct can I get the Brainlest

The value of given differential equation \(y' = y - x\) with the initial condition \(y(0) = 1.5\), on the interval \(0 \leq x \leq 1.5\), is \(y(1.5) = y_4 = 5.4296875\).

The differential equation we are given is \(y' = y - x\), with the initial condition \(y(0) = 1.5\). We are asked to approximate the solution on the interval \(0 \leq x \leq 1.5\) with a step size of \(h = 0.5\), and we want to achieve an accuracy of \(e = 0.0001\).

We start by calculating the first two values, \(y_0\) and \(y_1\), using the formula:

\(y_1 = y_0 + h \cdot f(x_0, y_0)\)

Here, \(h\) represents the step size, \(f(x, y)\) represents the derivative \(y'\) in terms of \(x\) and \(y\), and \((x_0, y_0)\) is the initial condition.

Using the given values, we can calculate \(y_1\) as:

\(y_1 = 1.5 + 0.5 \cdot (1.5 - 0) = 2.25\)

Next, we calculate \(y_2\) using the same formula:

\(y_2 = y_1 + h \cdot f(x_1, y_1)\)

Substituting the values \(x_1 = 0.5\) and \(y_1 = 2.25\), we get:

\(y_2 = 2.25 + 0.5 \cdot (2.25 - 0.5) = 3.375\)

Similarly, we can calculate \(y_3\) and \(y_4\) as:

\(y_3 = 3.375 + 0.5 \cdot (3.375 - 1) = 4.3125\)

\(y_4 = 4.3125 + 0.5 \cdot (4.3125 - 1.5) = 5.4296875\)

So, the value of \(y\) at \(x = 1.5\) is \(y(1.5) = y_4 = 5.4296875\).

Using Euler's method with a step size of \(h = 0.5\) and an accuracy of \(e = 0.0001\), the solution to the given differential equation \(y' = y - x\) with the initial condition \(y(0) = 1.5\), on the interval \(0 \leq x \leq 1.5\), is \(y(1.5) = y_4 = 5.4296875\).

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The new coordinates of the point (5, 2) after rotating counterclockwise about the origin through an angle of 5 degrees are approximately (4.993, 2.048).

To find the new coordinates of the point (5, 2) after rotating counterclockwise about the origin through an angle of 5 degrees, we can use the rotation formula:

x' = x * cos(theta) - y * sin(theta)

y' = x * sin(theta) + y * cos(theta)

Where (x, y) are the original coordinates, (x', y') are the new coordinates after rotation, and theta is the angle of rotation in radians.

Converting the angle of rotation from degrees to radians:

theta = 5 degrees * (pi/180) ≈ 0.08727 radians

Plugging in the values into the rotation formula:

x' = 5 * cos(0.08727) - 2 * sin(0.08727)

y' = 5 * sin(0.08727) + 2 * cos(0.08727)

Evaluating the trigonometric functions and simplifying:

x' ≈ 4.993

y' ≈ 2.048

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1. The day of the week 100 days from today can be determined by calculating the remainder when dividing 100 by 7 and adding it to the current day of the week.

The day of the week 100 days from today, assuming today is Tuesday, will be Sunday.

There are 7 days in a week, so after every 7 days, the day of the week repeats. Therefore, to find the day of the week 100 days from today, we need to calculate the remainder when dividing 100 by 7.

100 ÷ 7 = 14 remainder 2

Adding this remainder to the current day (Tuesday) gives us:

Tuesday + 2 = Thursday

So, 100 days from today will be Thursday. However, if we want to find the day of the week, we need to consider that Tuesday is the second day of the week (with Sunday being the first day). Adding the remainder 2 to Tuesday:

Tuesday + 2 = Thursday

Therefore, the day of the week 100 days from today will be Sunday.

The day of the week 100 days from today, assuming today is Tuesday, will be Sunday.

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Yes, a transformation can involve the addition, subtraction, multiplication, or division of or by a constant. In fact, these operations are commonly used in mathematical transformations.

For example, adding a constant to each value in a set of data is a common way to shift the entire set of values up or down. Multiplying each value in a set of data by a constant is a common way to stretch or shrink the data. Subtraction and division can also be used in transformations, depending on the context. However, it is important to note that not all transformations involve these operations.

Some transformations may involve more complex operations, such as exponentiation or logarithmic transformations. So, the short answer is yes, but the long answer is that it depends on the specific transformation being used.

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To find the break-even point, we need to find the point where the cost function and revenue function intersect, since at that point the profit will be zero.

So, we set the cost function equal to the revenue function:

180x + 8400 = 210x

Simplifying:

30x = 8400

x = 280

Therefore, the break-even point is at x = 280. To find the coordinates, we need to plug this value into either the cost or revenue function:

c(280) = 180(280) + 8400 = 50400

r(280) = 210(280) = 58800

So the break-even point is (280, 50400).
To find the coordinates of the break-even point, we need to determine the value of x when the cost of production (c(x)) is equal to the revenue (r(x)). In other words, we need to solve the equation c(x) = r(x).

Step 1: Set c(x) equal to r(x)
180x + 8400 = 210x

Step 2: Rearrange the equation to solve for x
210x - 180x = 8400
30x = 8400

Step 3: Divide both sides by 30 to find x
x = 8400 / 30
x = 280

Step 4: Find the break-even revenue by plugging x into either the cost or revenue function (we'll use r(x))
r(280) = 210 * 280 = 58800

So, the coordinates of the break-even point are (280, 58800), where 280 represents the number of cell phones produced and 58800 is the revenue generated.

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'X' is the input while the 'C' is the output. Because the value of 'C' depends on the value of 'x', then C would be the dependent variable, and 'C' the independent variable.

Answer:

2a-6

Step-by-step explanation:

Answer:

Monique is correct

Step-by-step explanation:

The actually temperature decrease = 30 - (-5) = 35*F

Monique is correct

This is NOT a function. This is due to the fact that two of the points share the same x-points (1, 3) and (1, 2), which does not abide to the vertical line test.

The value of a/b is  \(\sqrt{6}\) / 2

The area of mathematics known as mensuration is concerned with measuring geometric shapes and their various characteristics, such as length, volume, shape, surface area, lateral surface area, etc. In fundamental mathematics, learn about mensuration.

Measurement of agricultural fields, floor areas required for purchase/selling transactions. Measurement of volumes required for packaging milk, liquids, solid edible food items. Measurements of surface areas required for estimation of painting houses, buildings, etc.

According to the question:-

Side of an equilateral triangle equals a/3.

Therefore, the equilateral triangle's area is equal to (1/2)(a/3)2 sqrt (3) / 2 = a2 [sqrt (3)/ 36].

Hexagonal side equals b / 6.

The area is thus 6 (1/2) (b/6)^2 sqrt (3) / 2 

= b^2 [ 3 sqrt (3) / 72] = b^2 [sqrt (3) / 24]

So

sqrt (3) / 36 a2 = sqrt (3) / 24 b2

So

A2 / B2 = [Sqrt(3)/24] / [Sqrt(3)/36]

a^2 / b^2 = [ 36 / 24 ]

a^2/ b^2 = 3/2

A/ B = Sqrt(3) / Sqrt(2)

=Sqrt(6) / 2

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Answer:

-4n-5=0 n=-5/4

Step-by-step explanation:

Answer:

-4n-5

Step-by-step explanation:

have a good day and also for question like this use (mathpapa)

Answer:

acc to ques....perimeter of figure= 3a^2+15a+9

let missing dimension be x

= x+10a-2+a^2-7+5a=3a^2+15a+9

x+15a+a^2-9=3a^2+15a+9

x=2a^2+18

Answer:

a = -6

Step-by-step explanation:

-5a-9+a=15

Combine like terms

-5a+a  -9 = 15

-4a  -9 = 15

Add 9 to each side

-4a -9+9 = 15+9

-4a = 24

Divide by -4

-4a/-4 = 24/-4

a = -6

Answer:

a = -6

Step-by-step explanation:

1. Combine like terms: -4a – 9 = 15

2. Use the additive property of equality to add 9 to both sides: -4a = 24

3. Use division property of equality to divide -4 on both sides: a = -6

Answer:

D) 0

Step-by-step explanation:

Recall that slope is rise over run...

Specifically: m= (y2 - y1)/(x2 - x1)

Since all the y values are constant (3) in the table, this signifies that the slope is 0.

For example:

(3 - 3)/(-7 - 0) = 0

Therefore, the answer is D) 0.

θ^ is said to be (the most) efficient only if var(θ^) is the minimum within the group of all linear unbiased estimators for θθ. Therefore, the option d.

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It is critical to open a compass with over half the way in order for the arcs formed to meet for perpendicular bisector.

A perpendicular bisector would be a line that cuts a line segment in half and forms a 90-degree angle at the intersection point. In other words, a perpendicular bisector separates a line segment now at midpoint, forming a 90-degree angle.

Now, consider an example;

When you wish to build a perpendicular line on a line segment, like line AB, you do the following;

A line AB appears to be bisected perpendicularly as a result. The arcs would not have met if the compass is opened less than half way down line AB.

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The total  square kilometers in the given 5 square gigameters represented in scientific notation is written as 5.0×10^12 square kilometers.

One square gigameter is equal to,

(1.0×10^6 km)^2 = 1.0×10^12 square kilometers.

This implies,

5 square gigameters is equal to,

5 × ( 1.0×10^12 square kilometers )

= 5.0×10^12 square kilometers.

Expressing the answer in scientific notation we get,

5.0×10^12 square kilometers.

Therefore, the number of square kilometers are in 5 square gigameters in scientific notation is equal to 5.0×10^12 square kilometers.

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The above question is incomplete , the complete question is:

A gigameter is 1.0×10^6 kilometers. How many square kilometers are in 5 square gigameters?

Write your answer in scientific notation.

Answer:

$25.46

Step-by-step explanation:

The formula for f(x) an exponential function  is f(x) =1760(2.71828)^(0.01732x).

Let f(x) be an exponential function such that f(-1) = 220 and f(40) = 704.

The exponential function is of the form

f(x) = abx,

where a is the initial value, b is the base, and x is the exponent. We can use these values to solve for a and b.

Let's first solve for b. We have:

f(40) = ab

40 = 704

Dividing both sides by 220, we get:

f(40) / f(-1) = (ab40) / (ab-1)

= 704 / 220

Simplifying the left side, we get:

b41 = 704 / 220

= 8

Dividing both sides by b, we get:

b40 = 8 / b

Now, we can substitute this into our equation for f(40):

f(40) = ab

40 = a(8 / b)

= 8a / b

Next, we can solve for a using the value of f(-1):

f(-1) = ab-1 = 220

Substituting in b40 = 8 / b, we get:

ab-1 = 220

a(8 / b)-1 = 220

a(b / 8) = 220

Multiplying both sides by 8/b, we get:

ab = 220(8/b)

= 1760/b

Now, we can substitute both of these values into our equation for f(x):

f(x) = ab

x = (1760/b)

(bx) = 1760(x / 40)

So the formula for f(x) is

f(x) = 1760(2.71828)^(0.01732x).

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The line passes through the origin and if it has a constant of variation of 3, so it represents a direct variation , Option A is the correct answer.

When a quantity increases and the other quantity also increases , then those two quantities are said to be in direct variation.

It is asked in the question that which option depicts whether On a coordinate plane, a line goes through points (0, 0) and (1, 3) , represents a direct variation

As it is mentioned in the question that the line passes through the origin and if it has a constant of variation of 3, so it represents a direct variation.

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Answer:

a

Step-by-step explanation: