If it took 7 seconds for the cannonball to reach the ground, what would its vertical speed be as it is striking the ground?​

Answer:

5.3 m

Explanation:

Your friend is 1800 mm tall, and you want them to fill half the frame (79 mm / 2 = 39.5 mm).

The film is 116 mm behind the lens.  Using similar triangles:

x / 1800 = 116 / 39.5

x = 5286

Rounded to two significant figures, your friend should stand 5.3 meters away.

Answer:

O exothermic, because energy is released into the surrounding

Explanation:

From the diagram the energy of the reactant is higher than the energy of the product, thereby making it exothermic. If you study diagram well, exothermic reaction means that the reactions releases energy into the surroundings.

Answer:

3.88 × 10^-4 m

Explanation:

Given that a  person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?

The total weight = 614 + 85

The total weight = 699N

Let the total area of contact = A

Pressure = Force / A

Substitute all the parameters into the formula

900000 = 699 /A

A = 699 / 900000

A = 7.77 × 10^-4 m

The area of contact between each tire and the ground will be = A/2

That is, 7.77 / 2 = 3.88 × 10^-4 m

Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.

Answer:

The magnitude scale used in astronomy is logarithmic, meaning that each increase in magnitude represents a decrease in brightness by a factor of approximately 2.512. Therefore, if Star A has a magnitude of 1.0 and is 60 times brighter than Star B, we can calculate the magnitude of Star B as follows:

Brightness ratio = 2.512^(magnitude difference)

60 = 2.512^(magnitude of A - magnitude of B)

Taking the logarithm base 2.512 of both sides:

log base 2.512(60) = magnitude of A - magnitude of B

Solving for the magnitude of B:

magnitude of B = magnitude of A - log base 2.512(60)

magnitude of B = 1.0 - log base 2.512(60)

Calculating the value:

magnitude of B ≈ 1.0 - 2.799

magnitude of B ≈ -1.799

Therefore, the magnitude of Star B is approximately -1.799.

Explanation:

Using the magnitude equation, we deduced that given star A has a magnitude of 1.0 and is 60 times brighter than star B, the magnitude of star B comes out to be approximately 4.4. This computation confirms that the larger the magnitude, the fainter the star.

To find the magnitude of star B given that star A is 60 times brighter, we first need to understand the concept of magnitude in astronomy. In general, in the magnitude system, each difference of 1 in magnitude corresponds to a difference in brightness by a factor of about 2.512 (which is the fifth root of 100). This is represented in the equation m2 = m1 - 2.5 log(b2/b1), where m1 and m2 are the magnitudes of the two stars, and b1 and b2 are their brightness levels.

Given that star A has a magnitude of 1.0 (m1) and is 60 times brighter than star B (b2/b1), we can plug these values into the equation to get m2 = 1.0 - 2.5 log(1/60). Solving this equation, star B's magnitude comes out to be approximately 4.4. Hence, it is evident from this calculation that a larger magnitude signifies a fainter star, which aligns with the core concept of the magnitude scale in astronomy.

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The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.

The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.

The force on a charged particle in an electric field can be calculated using the formula:

F = q * E

Where F is the force, q is the charge of the particle, and E is the electric field.

Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:

F = (-6 C) * (24 N/C)

F = -144 N

The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.

The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.

Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.

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Time = t = 6.62 s

Explanation:

Given data:

Height = h = 215 m

Initial velocity =  = 0 m/s

gravitational acceleration = g = 9.8 m/s²

Time = t = ?

According to the second equation of motion

As the initial velocity is zero, the first term of right-hand side of the above equation is equal to zero.

                                       t² = 2h/g

                                        t = square root 2h/g

                                        t = square root 2x215/9.8

                                        t = 6.62 s

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

Explanation:

Answer:

The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.

Explanation:

The magnetic force was much stronger on Wednesday than on Tuesday because the magnetic force is stronger closer to the magnets. Therefore claim 3B is more convincing.

Magnetic force can be described as a consequence of electromagnetic force which is caused due to the motion of charges. A moving charge surrounds itself with a magnetic field and the force that arises due to interacting magnetic fields.

The magnetic force between two moving charges is the effect exerted upon either charge by a magnetic field generated by the other. The magnetic force depends on the charge, the motion of each of the objects, and the separation between them.

The magnitude of the force is determined by the cross product of velocity and the magnetic field is equal to q.[v × B]. The resultant force can be described as perpendicular to the direction of the velocity and the magnetic field.

Therefore, the magnetic force was much stronger closer to the magnets.

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The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².

What is the moment of inertia?

This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².

From the question:

Mass,M =4.2kg

Radius, R=32Cm

The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:

moment of inertia, I =1/2MR²

I =\(\frac{1}{2}\) * 4.2 * 32²

  =2,150.4 kgm²

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The radiation that is least damaging to humans is non-ionizing radiation.

Non-ionizing radiation refers to the type of radiation that does not have enough energy to remove tightly bound electrons from atoms or molecules, thus not causing significant damage to biological tissues.

Examples of non ionizing radiation include radio waves, microwaves, visible light  and low energy ultraviolet (UV) radiation. while excessive exposure to any form of radiation can have adverse effects, non-ionizing radiation is generally considered to be less harmful compared to ionizing radiation, which includes X-rays and gamma rays.

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Answer:

1)     R₁ > R₃ > R₂ correct B , 2) the wire that dissipates the most is wire 2

Explanation:

1) The resistance of a wire is given by the expression

          R = \(\rho \ \frac{l}{A}\)

where ρ is the resistivity of the material, l the length of the wire and A the area of ​​the wire

The area is given by

          A = π r² = π d² / 4

we substitute

         R = (ρ 4 /π)  \(\frac{l}{d^2}\)

the amount in parentheses is constant for this case

let's analyze the situation presented, to find the resistance of each wire

* indicate l₁ = l₂ and d₂ = 2 d₁

the resistance of wire 1 is

          R₁ = (ρ 4 /π)  \(\frac{l_1}{d_1^2}\)  

the resistance of wire 2 is

          R₂ = (ρ 4 /π) \frac{l_2}{d_2^2}

          R₂ = (ρ 4 /π)   \(\frac{l_1}{ (2 d_1)^2}\)

          R₂ = (ρ 4 /π ) \(\frac{l_1}{d_1^2}\)   ¼

          R₂ = ¼ R₁

* indicate that d₂ = d₃    and  l₃ = 2 l₂

           R2 = (ρ 4 /π)  \(\frac{l_2}{d_2^2}\)

the resistance of wire 3 is substituting the indicated condition

           R3 = (ρ 4 /π 2)  \frac{l_3}{d_3^2}

            R3 = (ρ 4 /π)   \(\frac{2 \ l_2}{d_2}\)

            R3 = 2 R₂

let's write the relations obtained

          R₁ = (ρ 4 /π)  \(\frac{I_1}{ d_1^2}\)

          R₂ = ¼ R₁

          R₃ = 2 R₂

let's write everything as a function of R1

           R₁ =(ρ 4 /π)   \(\frac{l_1}{d_1^2}\)

           R₂ = ¼ R₁

           R₃ = ½ R₁

the resistance of the wire in decreasing order is

           R₁ > R₃ > R₂

2) The power dissipated by a wire is

           P = V I

the voltage is

           V = I R

            I = V / R

substituting

          P = V² / R

therefore the power dissipated by each wire is

wire 1

           P₁ = V² / R₁

wire 2

           P₂ = V² / R₂

           P₂ = \(\frac{V^2}{ \frac{1}{4} R_1}\)

           P₂ = 4 P₁

wire 3

           P₃ = V² / R₃

           P₃ = \(\frac{V^2}{ \frac{1}{2} R_1}\)

           P₃ = 2 P₁

Therefore, the wire that dissipates the most is wire 2

Answer: In the absence of thrust, the lunar lander moves downward toward the surface of the moon. At this point, the only force acting on the lunar lander is gravity, which is directed toward the center of the moon. Because the net force is in the downward direction, the lunar lander moves downward.

Explanation:

The earliest time at which the force of the spring shown below is zero will be 0.45 seconds.

A metal spring is moved from its position of stability when stretched or squeezed. As a result, it feels a restorative force that pulls the spring back to its earliest position. The spring force is the name given to this force. It is a type of contact force present in elastic materials.

The spring force is given as,

F = k(x - x₀)

If the value of the deflection of the spring is zero. Then the force in the spring will be zero.

If (x - x₀) = 0, then force is written as,

F = k × 0

F = 0

From the diagram, the time when the spring force is zero will be 0.45 seconds and 1.35 seconds.

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Given data:

One long, narrow resistor and short wide resistor.

The expression for the resistance is given by,

Here, ρ is the resistivity that depends on material, L is the length, and A is the area of cross-section.

The expression for the voltage drop according to Ohm's law is,

The ratio of voltage drop will be,

Here, suffix 1 shows long narrow resistor and suffix 2 shows wide short resistor.

The current will also be same as the resistors are in series I₁=I₂.

From above equation we can observe that V₁ will have more voltage drop than V₂ as L₁/A₁ is more for long narrow resistor and A₂/L₂ will be less for short and wide resistor.

Kinetic energy will be 600J. According to law of conservation energy: All the energy in a system will simply change the state, and no more nor less energy will be created or lost during the operation of the system. In this case, then all 600J of energy will be transformed during the operation of car.

kinetic energy, Chemical compounds' bonds contain energy. Chemical reactions have the potential to release chemical energy, frequently in the form of heat; these kinds of reactions are referred to as exothermic. Some of the energy from reactions that need heat input to continue may be stored as chemical energy in newly formed bonds.

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The data related to the given exoplanets is, Proxima Cen b - 1.27, GJ 667c - 2.54, Trappist 1e - 0.69, Ross 128 b - 1.4.

All of the planets in our solar system orbit the sun. Exoplanets are planets that revolve around other stars.

It is extremely difficult to directly observe exoplanets using telescopes. They are hidden because the star they orbit is so bright.

Researchers have been searching for extrasolar planets for a very long time.

Since 1917, there has been conjecture that an exoplanet could be orbiting the white dwarf Van Maanen 2, however this conjecture has remained untested due to outdated technologies.

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When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

C. A. B.

Explanation:

Credit to Lainey in the comments for the answer!

Answer:

1] C

2] A

3] B

Explanation:

The examples of elements with similar properties in the same group are fluorine, chlorine, bromine and iodine.

The groups in periodic table is the same as vertical columns in the periodic table

These groups represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties.

Examples of elements found in the same group with similar chemical properties include;

group 7 elements.

The valence electron of elements found in the group 7 of periodic table is negative 1 (-1).

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We need to do a dimensional analysis of the dimensions of force.

We need to have into account what the following symbols represent:

In the case of force, we look into the table and we notice that the dimension column says:

The negative exponent can be brought down as follows:

This means that any force has units of "mass" multiplied by "length" divided by "time squared". In the International System (SI) this unit is equivalent to Newtons (N). Newtons in the international system is equivalent to:

Where:

We notice that "kg" is mass, "m" is length, and "s" is time. Therefore, these units are consistent with the dimensions of the units of force.

When doing a dimensional analysis we need to substitute the dimensions we are using to get equivalent dimensions. For example:

These units are Joule divided by meters. Now, we substitute the dimensions of Joules and the dimensions of meters:

We can cancel out the length "L":

We notice that the units are equivalent to the units of force:

Therefore, Joules divided by meters is Newtons.

Answer: D. 6.1 m/s^2

Explanation:

An example of a point source water pollutant is a sewer pipe draining directly into a river.

According to the United States Environmental Protection Agency, a  point source pollution is defined as;  “any single identifiable source of pollution from which pollutants are discharged, such as a pipe, ditch, ship or factory smokestack.”

Hence, an example of a point source water pollutant is a sewer pipe draining directly into a river. The pollution is coming from an easily identifiable source which is a sewer pipe connected to a river directly.

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Answer:

A.gasses can change volume, and liquids cannot

Explanation:

if you pour a glass of water you don't have to worry about it expanding such that it overflows. however if you air up a ballon you may notice that it becomes lager the warmer it gets and smaller the cooler it gets

Answer:

The most common oxidation numbers for a given element

Assuming constant acceleration, if v is the final velocity of the ball, then

v ² - (16 m/s)² = 2 (-2 m/s²) (4 m)

v ² = 240 m²/s²

v ≈ 15.5 m/s

Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

T = 2,548

What is tension?

Tension occurs due to the direction of pull on the object and along the length of the given rope.

It's S.I. unit is Newton

Tension formula can be represented as

T = mg + ma

T = 200 (9.8 + 1.3 m/s²)

T = 200 (12.74)

T = 2,548

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Answer:

P1 = 45,174 Pa

P2 = 90,348 Pa

W = 2,259 J

Q = 2,259 J

ΔS = 0

Explanation:

We can use the ideal gas law, PV = nRT, to solve this problem. Since the gas is at constant temperature (isothermal), we can simplify this to PV = constant.

Given that there are two moles of oxygen gas in a volume of 0.1 m^3 at 273 K, we can calculate the initial pressure as follows:

P1V1 = nRT

P1 = nRT/V1

P1 = (2 mol)(8.31 J/mol.K)(273 K)/(0.1 m^3)

P1 = 45,174 Pa

Next, we compress the gas reversibly to half of its original volume (i.e. V2 = 0.05 m^3) at constant pressure. We can use the same equation, PV = constant, and the fact that the pressure is constant to solve for the final pressure:

P1V1 = P2V2

P2 = P1V1/V2

P2 = (45,174 Pa)(0.1 m^3)/(0.05 m^3)

P2 = 90,348 Pa

Now, we can calculate the work done during the compression process using the equation:

W = -PΔV

where ΔV is the change in volume (i.e. V2 - V1 = -0.05 m^3), and the negative sign indicates that work is done on the system during compression. Substituting the values, we get:

W = -(45,174 Pa)(-0.05 m^3)

W = 2,259 J

Finally, we can calculate the heat added to the system using the first law of thermodynamics:

ΔU = Q - W

where ΔU is the change in internal energy (which is zero since the temperature is constant), Q is the heat added to the system, and W is the work done on the system (which is negative). Solving for Q, we get:

Q = ΔU + W

Q = 0 J + 2,259 J

Q = 2,259 J

Since the temperature is constant, the heat added to the system is equal to the change in enthalpy:

ΔH = Q = 2,259 J

We can also calculate the change in entropy using the equation:

ΔS = nCv ln(T2/T1)

where Cv is the molar heat capacity at constant volume (which is given as 22.1 J/K.mol), and ln(T2/T1) is the natural logarithm of the ratio of final and initial temperatures. Since the temperature is constant, ΔS = 0.

Therefore, the final answers are:

P1 = 45,174 Pa

P2 = 90,348 Pa

W = 2,259 J

Q = 2,259 J

ΔS = 0

Answer:

they died lol XD Gang op.....