if the outside air pressure decreases, the reading on a tire gauge connected to a tire also decreases.T/F
Answers
True. The outside air pressure can have a direct impact on the reading of a tire gauge connected to a tire. Tire gauges are used to measure the amount of air pressure in a tire, which is crucial for maintaining proper tire health and overall vehicle performance.
When the outside air pressure decreases, it can cause the air pressure within the tire to decrease as well. This means that if a tire gauge is connected to the tire, the reading on the gauge will also decrease. Conversely, if the outside air pressure increases, the reading on the tire gauge will also increase as the air pressure within the tire increases.
It is important to regularly check tire pressure with a tire gauge and adjust it as needed to ensure safe and efficient driving. Changes in outside air pressure can impact tire pressure, so it is recommended to check tire pressure regularly, especially during temperature changes or changes in altitude. By regularly monitoring tire pressure, drivers can avoid potential safety risks and also improve fuel efficiency.
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Related Questions
what does the high power objective do on a microscope
Answers
The high power objective on a microscope is used to provide a higher level of magnification for the detailed examination of specimens.
The high-power objective is one of the multiple objective lenses found on a microscope. It typically has a higher magnification power, often ranging from 40x to 100x or more. When the high-power objective is selected, it brings the specimen into sharp focus at a closer distance. This allows for the observation of finer details and structures that may not be visible with lower magnification objectives. However, higher magnification also means a smaller field of view and reduced depth of field. To compensate for this, a fine adjustment knob is often used to precisely focus the image. The high-power objective is commonly used in advanced biological and medical research, as well as in educational settings where a more detailed examination of microscopic specimens is required.
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An electric dipole of dipole moment 'p' is placed in the position of stable equilibrium in a uniform field of intensity 'E'. The torque required to rotate, when the dipole makes an angle Ө with the initial position is pE cos Ө pE sin Ө p cos Ө p tan Ө
Answers
Answer:
Torque by electric dipole = pEcos thita
Two protons enter a region of the transverse magnetic field. What will be the ratio of the time period of revolution if the ratio of energy is 2√2 : √3 ?
Answers
Given:
ratio of energy is 2√2 : √3
Apply:
\(T=2\pi\sqrt[\frac{}{}]{\frac{mr}{qBv}}\)Where:
q = charge of proton
v= speed of proton
r= radius of circular path
T= time period of revolution
Kinetic energy (K)
K= 1/2mv^2
From both equations:
Tα1/k
K1:K2 = 2√2 : √3
T1:T2 = √3:2√2
Answer: √3:2√2
A nearsighted woman can see clearly only objects within a 1.4 m of her eye. To see distant objects, she should wear eyeglasses of what power?
Answers
The nearsighted woman should wear eyeglasses with a power of about -0.714 diopters
A nearsighted woman who can only see objects clearly within 1.4 meters of her eye requires corrective lenses to improve her distance vision. To determine the power of the eyeglasses she needs, we can use the formula:
Power (P) = 1 / Focal length (f)
In this case, the focal length (f) is the distance at which she can see clearly, which is 1.4 meters. To convert this to meters, we have:
f = 1.4 m
Now, we can calculate the power of the eyeglasses:
P = 1 / 1.4 m = 0.714 diopters
The nearsighted woman should wear eyeglasses with a power of approximately -0.714 diopters to see distant objects clearly.
The negative sign indicates that the lenses should be concave, which is typical for correcting nearsightedness.
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when two charged capacitors are connected in parallel with one another, which two fundamental physical laws are employed to reveal the final parameters of the problem?
Answers
The final parameters of the problem are the conservation of charge and the definition of capacitance.
According to the conservation of charge, the total charge in the system before and after the capacitors are connected in parallel must be the same. Therefore, the total charge stored by the capacitors is the same before and after the connection.
According to the definition of capacitance, the capacitance of the equivalent parallel combination of the capacitors is the sum of the individual capacitances. Therefore, the final capacitance of the parallel combination can be calculated as the sum of the capacitances of the individual capacitors.
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How does the mass of an object affects its gravitational force?*answer in a full sentence pls * (PLS HELP ME )
Answers
Answer:
Here you go..
hope it helps..!
Explanation:
So since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force, so as the mass of either object increases, the force of gravitational attraction between them also increases.
1. battery, light bulb, switch, all connected in seriesDirections: Create a circuit diagram for each item.
Answers
ANSWER and EXPLANATION
When the components of a circuit are connected in series, they are connected along a single electrical path with each component having the same current flowing through it.
To draw the circuit diagram, use the appropriate symbol for each object. Let us draw it now:
That is the circuit diagram.
Look at the diagram below that shows information about the sun, Earth, and moon. Use that information to calculate and compare the gravitational forces between the Earth and the Sun, and the Earth and the Moon.
Answers
i. The gravitational force between the earth and sun can be obtained as follow:
Mass of earth (M₁) = 5.987×10²⁴ KgMass of sun (M₂) = 1.989×10³⁰ KgDistance apart (r) = 1.5×10¹¹ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 5.987×10²⁴ × 1.989×10³⁰) / (1.5×10¹¹)²
F = 3.53×10²² N
Thus, the gravitational force between the earth and sun is 3.53×10²² N
ii. The gravitational force between the earth and moon can be obtained as follow:
Mass of earth (M₁) = 5.987×10²⁴ KgMass of moon (M₂) = 7.347×10²² KgDistance apart (r) = 3.844×10⁸ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 5.987×10²⁴ × 7.347×10²²) / (3.844×10⁸)²
F = 1.99×10²⁰ N
Thus, the gravitational force between the earth and moon is 1.99×10²⁰ N
How do i compare the gravitational forces?Gravitational force between the earth and sun (G₁) = 3.53×10²² NGravitational force between the earth and moon (G₂) = 1.99×10²⁰ NComparison =?Comparison = G₁ / G₂
G₁ / G₂ = 3.53×10²² / 1.99×10²⁰
G₁ / G₂ = 177
Cross multiply
G₁ = G₂ × 177
Thus, we can say that the gravitational force between the earth and sun is 177 times bigger than the gravitational force between the earth and moon
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Which two actions could you take to weaken an electromagnet?
A. Use a wooden core instead of a steel core.
B. Replace a 9 V battery with a 3 V battery.
O C. Decrease the length of the connecting wires in the circuit.
D. Increase the number of wraps of wire around the core.
E. Include an ammeter in the circuit.
Answers
Answer:
a and b
Explanation:
first one breaks it and second one directly makes it weaker
Answer:
A and B
Explanation:
took the test
When charging objects by induction which of the following must be true
A. A path to ground is not needed when using a positive source
B. The objects being charged must be conductors
C. The objects takes on the same charge as it's source
D. The source loses some of its charge
Answers
Answer:
C
Explanation:
because that's how science works
If the magnitude of the electric field of an infinite plane of charge at point 10.0 m from the plane e = 100.0 n/c, what is the surface charge density?
Answers
The correct answer to the given question is that the surface charge density σ = 200ε₀C/m².
The electric field due to an infinite uniformly charged insulating sheet at any point in space around it is given by E=σ/2ε₀, provided that the point is not lying on the sheet itself. The quantity of charge per units of a two-dimensional surface area is known as surface charge density. It gauges the amount of electric charge that has collected on a surface. Its symbol is, and the SI system's unit is the Coulombs per square meter, or Cm-2.
Therefore, the surface Charge density= 2 * 100 N/C = 200ε₀C/m².
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You find 6.21 g of diamonds. You measure that the diamonds have a volume of 1.77 ml. What is the
density of diamonds, and where would the diamonds fit into your density column?
Answers
Answer:
3.51 g/mL
Explanation:
Density can be found using the equation: density = mass / volume.
In this case, mass is given in grams (g) and volume is given in milliliters (mL).
You can find the density of the diamonds by plugging the given values into the formula and simplifying.
Density = mass (g) / volume (mL)
Density = 6.21 g / 1.77 mL
Density = 3.51 g/mL
To what subnet does the ip address 10.1.100.50 belong if a subnet mask of 255.255.0.0 is used?
Answers
The IP address 10.1.100.50 belongs to the subnet 10.1.0.0 when a subnet mask of 255.255.0.0 is used.
When the subnet mask 255.255.0.0 is applied, it indicates that the first two octets (10.1) are the network address, and the last two octets (100.50) are available for host addresses within that network. This subnet mask allows for a larger number of host addresses compared to a subnet mask with a higher number of network bits.
By matching the network portion of the IP address with the network address derived from the subnet mask, we can determine the subnet to which the IP address belongs. In this case, the subnet is 10.1.0.0.
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What is one way homeostasis benefits living organisms?
it maintains balance.
It reduces air pollution.
It increases food consumption
It regulates atmospheric temperature
Answers
Answer:
it maintains balance, it keeps body temperatures , heart rate and all other bodily functions regulated to keep the organism stable when the environment is not.
Answer:
What the other guy said.
Explanation:
Yeah I'm doing this so he can have brainliest.
A gold wire with a circular cross-section has a mass of 1.10 g and a resistance of 0.720 Ω. At 20°C, the resistivity of gold is 2.44 ✕ 10−8 Ω · m and its density is 19,300 kg/m3.
How long (in m) is the wire?
m
What is the diameter (in mm) of the wire?
mm
Answers
The diameter of the wire is 0.42 mm. The length of the wire is 1.07 m.
The resistance of the gold wire can be calculated using the formula:
R = (ρL) / A
V = m / ρ
V = 1.10 g / (19,300 kg/m³)
V = 5.70 ✕ \(10^{-8\) m^3
Next, we can calculate the length of the wire:
L = (RA) / ρ
L = (0.720 Ω)(πd²/4) / (2.44 ✕ \(10^{-8\) Ω · m)
L = (0.720 Ω)(πd²/4) / (2.44 ✕ \(10^{-8\) Ω · m)
L = 7.41 ✕ \(10^{-3\) d²
Substituting the value of V into the equation above gives:
7.41 ✕ \(10^{-3\) d² = 5.70 ✕ \(10^{-8\)
Solving for d, we get:
d = 0.42 mm
Finally, we can use the length equation to calculate the length of the wire:
L = 7.41 ✕ \(10^{-3\) d²
L = 7.41 ✕ \(10^{-3\) (0.42 mm)²
L = 1.07 m
Resistance refers to the opposition that occurs when current flows through a conductor. It is an inherent property of a material that opposes the flow of electricity. Resistance is measured in ohms and is represented by the symbol Ω. The resistance of a conductor depends on several factors such as the material, the length of the conductor, its cross-sectional area, and the temperature.
Resistance is an important concept in electrical circuits as it affects the flow of current and voltage across a circuit. A higher resistance means a lower current and a higher voltage drop across the circuit. In electronic devices, resistors are used to control the flow of current and limit the voltage. Different materials have different resistivity, which is a measure of their resistance to the flow of electricity. Materials such as copper, aluminum, and gold have low resistivity and are commonly used in electrical wiring. Resistance plays a crucial role in determining the efficiency and performance of electrical and electronic devices.
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If two objects have the same volume but one has a greater mass, the one with greater mass
Answers
Explain more. I can't understand
Help out pls
Determine the force required to accelerate a 2-kilogram ball to an acceleration of 9.8 m/s2
Determine the acceleration of a 2-kilogram ball if a force of 25 newtons is applied
Answers
Answer:
Explanation:
F = ma = (2 kg)(9.8 m/s²) = 19.6 N
a = F/m = 25 N / 2 kg = 12.5 m/s²
which of the following best represents force?
1-a push or a pull acting on a object.
2-a push or a pull always causing acceleration.
3-a push or a pull action without an object.
4-a push or a pull always causing motion
Answers
Answer:
1 -a push or a pull acting on a object.
Explanation:
force is a push or pull acting upon an object as a result of its interaction with another object.
A unit of mass is ??
Answers
Answer: kilogram
Further explaining: in science is used to measure weight of an object and used for accreditation.
Hope this helps!
The differences between microwaves and infrared radiation are due to differences in their _____.
A 25 V battery is connected into a circuit with two resistors in series. One resistor has resistance 5.0 Ω and the other has resistance 7.5 Ω. What is the voltage drop across the 7.5 Ω resistor?
Answers
Answer:
15 V
Explanation:
From the question,
For series connection: (i) Both resistor have a common current flowing through the (ii) The combined resistance = R1+R2
Rt = R1+R2.................. Equation 1
Given: R1 = 5 ohms, R2 = 7.5 ohms.
Rt = 5+7.5 = 12.5 ohms.
Applying Ohm's law,
V = IRt................... Equation 2
Where V = Voltage, I = current.
make I The subject of the equation
I = V/Rt.............. Equation 3
Given: V = 25 V, Rt = 12.5 ohms.
Substitute into equation 3
I = 25/12.5
I = 2 A.
Now,
Voltage drop across the 7.5 ohms resistor = R2×I
Voltage drop across the 7.5 ohms resistor = 7.5×2
Voltage drop across the 7.5 ohms resistor = 15 V
You are pulling on a rope attached to the outer radius of a pulley with a moment of inertia I = 2.85 kg-m^2 as shown. The tension force of you on the pulley is 266.3 N. A pack of mass 23.4 kg is attached to the pulley's inner radius as shown. If the inner radius of the pulley is 0.43 m and the outer radius is 0.66 m, what is the magnitude of the linear acceleration of the pack? If instead of using a pulley with two radii, you were to replace the two radii pulley with a simple pulley of one radius: how would using the simple pulley instead of the two radii pulley affect the difficulty of holding the pack at rest over the edge? It will be easier to hold the pack. Not enough information to tell. There will be no difference. It will be harder to hold the pack.
Answers
The magnitude of the linear acceleration of the pack can be calculated using the following equation:a = (T - Fr) /m where a is the magnitude of the linear acceleration of the pack,T is the tension force of you on the pulley,Fr is the frictional force, and m is the mass of the pack.Substitute the given values to the formula:a = (T - Fr) / ma = (266.3 - Fr) / 23.4.
The frictional force can be determined using the moment of inertia of the pulley.I = mr²I = 2.85 kg-m²m = I / r²m = 2.85 / 0.43²m = 15.57 kgFr = maFr = 15.57 × aa = (266.3 - 15.57a) / 23.4Solve for a by multiplying both sides by 23.4:23.4a = 266.3 - 15.57a23.4a + 15.57a = 266.3a = 266.3 / 39.97a = 6.66 m/s².
Therefore, the magnitude of the linear acceleration of the pack is 6.66 m/s².If instead of using a pulley with two radii, you were to replace the two radii pulley with a simple pulley of one radius, it will be harder to hold the pack.
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Calculate the wavelength of the sound wave that are produced by tuning fork marked C - 264 Hz. Take the speed of sound in air as 343 metres per second
Can someone help me with this question
Answers
formula
v = fλ
v = velocity
f=frequency
λ = wavelength
Speed (meters/second) = Wavelength (meters) x Wave Frequency (hertz) (1/seconds)
343 meters/second = x meters times 264 hertz (1 /second)
x (wavelength) = 343/264 = 343 ÷ 264 =
1.29924242 meters
1.3 meters = wavelength = answer
https://www.scienceworld.ca/resource/sound-vibration-vibration-vibration
Hertz (1 Hz = 1 vibration per second)
The number of vibrations per second is known as the frequency, measured in Hertz (1 Hz = 1 vibration per second).
These vibrations enter the outer ear and cause the eardrum to vibrate too
accessiblemediacentertechadaptcom
12. A golf club applies 17,793 N of force to a golf ball and it travels 219.55 m. How much work was done on
the ball?
Answers
The work done on the ball is 1.08 kWh
According to the Definition of work
W= F.s
According to the question,
F = 17,793 N
s= 219.55 m
Work = 3906453.15 J
1 kWh = \(3.6*10^6 J\)
3906453.15 J = \(\frac{3906453.15}{3.6*10^6}\)= 1.08 kWh
Therefore, the Work done on the golf ball is 1.08 kWh
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Can someone help me with 13
Answers
I would be happy to help you with whatever question or concern you may have. However, I'm not sure what you mean by "13". If you could please provide more context or clarify your question, I will do my best to assist you.
In the meantime, I would like to offer some general advice that may be helpful. If you are struggling with something, whether it be a problem, a task, or an emotional issue, it's important to remember that asking for help is a sign of strength, not weakness. No one has all the answers, and seeking assistance from others can often provide new perspectives and solutions that you may not have considered on your own.
Additionally, it's important to be patient with yourself and to not give up too easily. Many challenges require time, effort, and persistence to overcome. Don't be discouraged if progress seems slow or if setbacks occur along the way. Keep focused on your goal and take things one step at a time.
Finally, don't be afraid to take breaks and practice self-care. Sometimes stepping away from a problem for a little while can provide much-needed perspective and rejuvenation. Whether it's taking a walk, practicing mindfulness, or engaging in a hobby, make sure to prioritize your mental and physical health.
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A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons.
Answers
On a level ice surface, a 55-kilogram skater glides over it while being subject to a friction force of 11 newtons. The skater's acceleration is -0.2 m/s^2.
The force of friction acting on the skater can be calculated as follows:
friction = μ * N
where
μ = coefficient of friction between the ice and skates (assumed to be constant)
N = normal force, which is equal to the weight of the skater
N = m * g
where
m = mass of the skater (55 kg)
g = acceleration due to gravity (9.8 m/s^2)
By substituting the values, we get:
friction = μ * m * g = 11 N
Finally, the net force acting on the skater can be calculated as follows:
net force = friction = -11 N (opposite direction to motion)
The acceleration of the skater can be calculated using Newton's second law of motion:
a = F / m
= -11 N / 55 kg
= -0.2 m/s^2
The acceleration of the skater is -0.2 m/s^2.
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Note: The correct question would be as bellow,
A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons. Find the coefficients of static and kinetic friction between the skates and the ice.
In a melting profile for dna, the absorbance at 260 nm increases as result of the disruption of the dna structure. what is the fundamental physical basis for the absorbance increase?
Answers
In a melting profile for DNA, the absorbance at 260 nm increases as a result of the disruption of the DNA structure. Denaturation is the fundamental physical basis for the absorbance increase
As a result of denaturation, many of the weak connections or bonds (such as hydrogen bonds) that give proteins their highly organized structure in their native (natural) state are broken. Most denatured proteins are insoluble and have a looser, more erratic structure.
Denaturation is the term used to describe how a protein unfolds or fragments, changing its typical three-dimensional structure. A protein's polypeptide chains may become disordered or unfurl due to chemical reaction, heat, or agitation, rendering the molecule normally non-functional. Egg whites are a perfect example of a denaturation that has been denaturized.
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A circuit is constructed with four resistors, one inductor, one battery and a switch as shown. The values for the resistors are: R1 = R2 = 46 ohms, R3 = 90 ohms, and R4 = 109 ohms. The inductance is L = 287 mH and the battery voltage is V = 12 V. a.) What is VL,max(closed), the magnitude of the maximum voltage across the inductor during the time when the switch is closed? b.) What is VL,max(open), the magnitude of the maximum voltage across the inductor during the time when the switch is open?
Answers
a) The magnitude of the maximum voltage across the inductor, VL,max(closed), during the time when the switch is closed can be calculated using the formula VL,max(closed) = L * (I0 / t), where L is the inductance of the inductor, I0 is the initial current through the inductor when the switch is closed, and t is the time taken for the switch to close.
b) The magnitude of the maximum voltage across the inductor, VL,max(open), during the time when the switch is open can be calculated using the formula VL,max(open) = L * (I0 / R_eq), where L is the inductance of the inductor, I0 is the initial current through the inductor when the switch is opened, and R_eq is the equivalent resistance of the circuit when the switch is open.
a) When the switch is closed, the inductor charges up and the current through the inductor increases with time. The maximum voltage across the inductor, VL,max(closed), occurs when the current through the inductor reaches its maximum value, I0, after time t.
According to the formula VL,max(closed) = L * (I0 / t), the maximum voltage across the inductor is directly proportional to the inductance of the inductor (L) and the initial current through the inductor (I0), and inversely proportional to the time taken for the switch to close (t).
b) When the switch is open, the inductor discharges and the current through the inductor decreases with time. The maximum voltage across the inductor, VL,max(open), occurs when the current through the inductor reaches its minimum value, which is typically zero, after the switch is opened.
According to the formula VL,max(open) = L * (I0 / R_eq), the maximum voltage across the inductor is directly proportional to the inductance of the inductor (L) and the initial current through the inductor (I0), and inversely proportional to the equivalent resistance of the circuit when the switch is open (R_eq).
The equivalent resistance can be calculated by combining the resistors R1, R2, R3, and R4 in the circuit using appropriate circuit analysis techniques, such as Kirchhoff's laws.
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Joule is equal to:
Awatt x metre
B.watt x second
C. Newton x Metre
D. Both b and c
Answers
Answer:
The answer is ( D) i. e both b and c.
a rectangular current loop carries current i and has 20 turns. what is the magnitude of the magnetic dipole moment?
Answers
To calculate the magnitude of the magnetic dipole moment of a rectangular current loop with 20 turns and current i, you can use the following formula: Magnetic Dipole Moment (µ) = n × i × A where n is the number of turns (20), Therefore, the magnitude of the magnetic dipole moment of the rectangular current loop is 20iA.
The magnitude of the magnetic dipole moment of a rectangular current loop can be calculated using the formula:
M = NIA
Where N is the number of turns in the loop, I is the current flowing through the loop, and A is the area of the loop.
In this case, the current loop has 20 turns and carries current i. The area of a rectangular loop is given by A = L x W, where L is the length of the loop and W is its width.
Since the dimensions of the loop are not provided, we cannot calculate the area directly. However, we can still find the magnitude of the magnetic dipole moment by using the formula:
M = NIA = 20iA
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A hockey puck is set in motion across a frozen pond. if friction and air resistance are ignored, how much force is required to keep the puck sliding at constant velocity? *
Answers
A hockey puck is set in motion across a frozen pond, if friction and air resistance are ignored, zero newton force is required to keep the puck sliding at constant velocity .
What is a friction?The force preventing solid surfaces, fluid layers, and sliding material components from moving in the same direction is known as friction. Friction between two surfaces causes kinetic energy to be converted into thermal energy when they move in relation to one another (that is, it converts work to heat). The utilization of friction produced by rubbing pieces of wood together to start a fire serves as an example of how this attribute can have dramatic effects. When a viscous fluid is agitated, for instance, kinetic energy is transformed into thermal energy. Wear, which can result in component damage or performance degradation, is another significant effect of various types of friction. Tribology is a field of study that includes friction.
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