if the pressure exerted by a gas at 25°c in a volume of 0.049 l is 4.23 atm, how many moles of gas are present?

Answer:

The first person to "measure gravity" is sir Issac newton

The overall concentration of wastes in all downstream locations will be higher due to the increased pollution load.

However, based on the information given, it is not possible to determine which location downstream from the drainage pipe has the highest concentration of biodegradable wastes. However, it can be assumed that the concentration of pollutants in the water will increase as the distance from the drainage pipe increases.

If the wastewater flowing out of the drainage pipe is no longer monitored and the flow of pollutants into the stream doubles, the concentration of biodegradable wastes and other pollutants in the water will increase significantly. This can have harmful effects on the environment and the organisms that depend on the stream for survival. It is important for pollution sources to continue monitoring and regulating their wastewater discharge to prevent these negative impacts.
To determine the highest concentration of biodegradable wastes in the downstream locations, consider the following:

1. At 10-20 m downstream from the drainage pipe: This location is closest to the drainage pipe, so the concentration of biodegradable wastes is likely to be the highest here because there hasn't been much opportunity for dilution or decomposition.

2. At 20-30 m downstream from the drainage pipe: As you move further downstream, the concentration of biodegradable wastes may decrease due to dilution and decomposition processes.

3. At 30-50 m downstream from the drainage pipe: This location is farthest from the drainage pipe, and biodegradable wastes have had more time to disperse, dilute, and decompose, leading to a lower concentration of pollutants.

Now, if the wastewater flowing out of the drainage pipe is no longer monitored, and the flow of pollutants into the stream doubles, the highest concentration of biodegradable wastes will still likely be at the 10-20 m downstream location.

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The overall concentration of wastes in all downstream locations will be higher due to the increased pollution load.

However, based on the information given, it is not possible to determine which location downstream from the drainage pipe has the highest concentration of biodegradable wastes. However, it can be assumed that the concentration of pollutants in the water will increase as the distance from the drainage pipe increases.

If the wastewater flowing out of the drainage pipe is no longer monitored and the flow of pollutants into the stream doubles, the concentration of biodegradable wastes and other pollutants in the water will increase significantly. This can have harmful effects on the environment and the organisms that depend on the stream for survival. It is important for pollution sources to continue monitoring and regulating their wastewater discharge to prevent these negative impacts.
To determine the highest concentration of biodegradable wastes in the downstream locations, consider the following:

1. At 10-20 m downstream from the drainage pipe: This location is closest to the drainage pipe, so the concentration of biodegradable wastes is likely to be the highest here because there hasn't been much opportunity for dilution or decomposition.

2. At 20-30 m downstream from the drainage pipe: As you move further downstream, the concentration of biodegradable wastes may decrease due to dilution and decomposition processes.

3. At 30-50 m downstream from the drainage pipe: This location is farthest from the drainage pipe, and biodegradable wastes have had more time to disperse, dilute, and decompose, leading to a lower concentration of pollutants.

Now, if the wastewater flowing out of the drainage pipe is no longer monitored, and the flow of pollutants into the stream doubles, the highest concentration of biodegradable wastes will still likely be at the 10-20 m downstream location.

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Answer:

The answer is choice (3)

Explanation: Land materials do require more energy than water to raise their temperature by one degree, hence why water gets heated a lot easier than something like wood.

Answer: C. Inherited traits carry the instructions for individual genes.

Explanation: bejewels I know stuff. ☆ - ~ hope this helps

Answer:

Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory. The motion of falling objects, as covered in Problem-Solving Basics for One-Dimensional Kinematics, is a simple one-dimensional type of projectile motion in which there is no horizontal movement. In this section, we consider two-dimensional projectile motion, such as that of a football or other object for which air resistance is negligible.

Explanation:

B the dropped ball

Answer: \(0.708\ mA\)

Explanation:

Given

\(E_o=20\ V/m\)

\(\omega =10^7\ s^{-1}\)

Cross-sectional area \(A=0.40\ m^2\)

Current density is given by

\(J=\epsilon_o \dfrac{dE}{dt}\)

Displacement current

\(\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A\)

The required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

Given data:

The intensity of electric field is, \(E_{0}=20 \;\rm V/m\).

The angular frequency of electric field is, \(\omega=1.0 \times 10^{7} \;\rm s^{-1}\).

The cross-sectional area of space is, \(A =0.40 \;\rm m^{2}\).

In the given problem, the instantaneous electric field is given by \(E = E_{0} \times cos(\omega t)\)

So, the expression for the current density is,

\(J= \epsilon_{0} \times \dfrac{dE}{dt}\)

Here, \(\epsilon_{0}\)  is the permittivity of free space. Solving as,

\(J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)\)

And the expression for the maximum displacement current is,

\(I = J \times A\)

And the maximum displacement current is possible only when, J is positive and J will be positive for  \(sin(\omega t)=-1\).

Then solving as,

\(I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A\)

Thus, we can conclude that the required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

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Answer:

2.5m/s^2

Explanation:

Since there is no friction, the only force acting on the box is the applied force

We can now use the equation Fnet = ma

and we can rearrange for a

a = Fnet/m

now input the values

a = 50N/20kg

a = 2.5 m/s^2

Explanation:

SO2 is the best answer

please give brainliest and helpful

Answer: SO2

Explanation:

Earth has a definite orbit within the solar system whose the orbit is mainly a result of the mass of the Sun.

An orbit is defined as the regular, repeating path that one object in space takes around another while an object in an orbit is called a satellite which may be natural, such as the Earth or the Moon. According to the height of satellites from the earth, these orbit are classified as

Most of the weather and some communications satellites will tend to have a high Earth orbit which is farthest away from the surface. The main difference between orbit and orbitals is that the former is defined as a fixed path of electron revolutions, whereas the latter is defined as an uncertain region with a high probability of finding an electron.

Therefore, the Earth has a definite orbit within the solar system whose the orbit is mainly a result of the mass of the Sun.

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Discovery Statement:

I discovered that my note-taking skills needed improvement when I attended a lecture by a guest speaker who spoke very quickly and used complex technical terms that were unfamiliar to me. I found it challenging to keep up with the speaker's pace and understand the content at the same time. As a result, I struggled to take accurate and organized notes, and ended up with a confusing and incomplete set of notes. When I reviewed my notes later, I realized that I had missed important points and failed to capture the essence of the lecture. This experience made me realize that I need to improve my note-taking skills, especially in situations where the content is complex and the speaker is fast-paced.

My intention is to implement the following five note-taking strategies immediately to improve my skills:

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See transcribed text below

MINDTAP

try: Transform Your Note-Taking

ms Journal Entry Transform your note taking

3

Q Search this course

0

Q

Question 1 of 1

Think back on the last few lectures you have attended. How would you rate your note-taking skills? As you complete this exercise, think of areas that need improvement.

1. Discovery Statement

First, recall a recent incident in which you had difficulty taking notes. Perhaps you were listening to an instructor who talked fast. Maybe you got confused and stopped taking notes altogether. Or perhaps you went to review your notes after class, only to find that they made no sense at all. Describe this incident in more detail, noting how it was challenging for you.

I discovered that...

X

2. Intention Statement

Now review this chapter to find at least five strategies that you can use right away to help you take better notes. In the space below, sum up each of those strategies in a few words, and note the title of the article where these strategies are explained.

2 Action Statement

Q Search

LM

A-Z

b

بین

9:19 PM

3/3/2023

Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters

Explanation:

Answer:

$480 a year

Explanation:

Answer:ur mom

Explanation:because

ANSWER:

a. AB

STEP-BY-STEP EXPLANATION:

The greatest distance occurs when the speed is increasing and also takes less time to reach that speed.

According to the graph, the highest speed is 8 m/s and it reaches it in 3 seconds, therefore, it is where the greatest distance is given.

Therefore, the segment of greater distance is the segment AB

Frequency is perceived by humans as pitch; The sound intensity is the amplitude; Humans can only hear a specific range of sound, usually from 20 Hz to 20,000 Hz; The factors that go into a sound are its intensity, frequency and overtones (which are like interference, or background noises).

It's "Pitch" on edge.

Answer:

4.5 sec

Explanation:

Initial velocity u = 4 m/s

Final velocity v = 13 m/s

Acceleratiin a = 2 m/s^2

Using v = u + at

Where t is time

13 = 4 + 2t

13 - 4 = 2t

9 = 2t

t = 9/2 = 4.5 sec

Answer:

4.5 s

Explanation:

The initial velocity (u) = 4 m/s, the final velocity (v) = 13 m/s and the acceleration (a) = 2 m/s²

To calculate the time it takes the rabbit to go from 4.0 m/s to 13.0 m/s, we use the formula:

v = u + at

Substituting values to get:

13 = 4 + 2t

Subtracting 4 from both sides:

13 - 4 = 4 + 2t - 4

9 = 2t

Therefore, 2t = 9

Dividing through by 2

2t / 2 = 9 / 2

t = 4.5 s

Therefore it takes the rabbit 4.5 seconds to go from 4.0 m/s to 13.0 m/s

yes it does

well i hope this helps

The distance between the 7th and the tenth second is 29.4 m.

We know that we can have to formulate the information that has been given here so as to obtain a proper progression and this would help us to get the common difference of the progression that we are looking at.

Now we know that the progression would look something like; 4.9, 14.7, 24.5 ....

We can see that this is an arithmetic progression that has a common difference of 9.8.

U7 = a + (n - 1)d

a = first term

n = Number of terms

d = common difference

U7 = 4.9 + (7 - 1) 9.8

= 63.7

U10 = 4.9 + (10 - 1) 9.8

U10 = 93.1

Between the 7th and 10th seconds, we have;

93.1 - 63.7

= 29.4 m

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The inductive resistance when a 1 henry inductor is used in an ac circuit with a frequency of 300Hz is 1884 ohm.

What is inductive resistance?

It is the opposition offered by the inductor in an AC circuit to the flow of ac current. It is represented by XL and measured in ohms. Inductive reactance is mostly low for lower frequencies and high for higher frequencies. It is, however, negligible for steady DC current.

How to calculate inductive resistance?
Given, L = 1 Henry

frequency 300Hz

XL?
Inductive resistance

XL = 2 * phi * frequency * L

2 * 3.14 * 300 * 1

XL = 1884ohm

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Answer:

I got 2508 J

Explanation:

q=mct

125-95

= 30 * 4.18 * 20

= 2508

The length of the room is 96 ft.

Let L be the length of the room and W be the width of the room.

Since the length is twice its width, L = 2W.

Its area A = LW

= 2W × W

= 2W²

If each side were increased by 1 foot, then its new area is A' = (L + 1)(W + 1)

= (2W + 1)(W + 1)

= 2W² + 3W + 1

Since the room would contain 145 ft more if each side were increased by 1 foot, then its new area is A' = A + 145 = 2W² + 3W + 1

2W² + 145 = 2W² + 3W + 1

145 = 3W + 1

3W = 145 - 1

3W = 144

W = 144/3

W = 48 ft.

Since its length L = 2W, substituting W = 48 into the equation, we have

L = 2(48)

L = 96 ft

So, the length of the room is 96 ft.

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Answer:

metal conducts heat faster than wood. which means the metal conducted heat away from your hand (or whatever it is) faster than wood.

Explanation:

just because they feel warm/cold doesn't always mean that it is warm/cold. if they both were sitting at room temp for a long time, then both will eventually reach the temp of the room. even though they are the same temp the metal will feel colder than the wood because of the thermal conductivity of the metal compared to the wood.

The different thermal conductivities of metal and plastic are important in the design of the bowl is metal conducts heat faster than Plastic. which means the metal conducted heat away from your hand (or whatever it is) faster than Plastic.

Thermal conductivity can be defined as the degree to which heat is transmitted through the cross-section of the unit of an object, where the temperature exits directly across the surface.

Electrical conductivity is a measure of how much energy (moving charge) can pass through objects under the influence of a used electric field. Thermal conductivity measures how heat (heat moving energy) can pass through objects below temperature differences.

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0.33 m/s is the minimum speed of the ball at the bottom of its swing (point b) in order for it to reach point a, which is 1.0 m above the bottom of the swing.

distance=1 m

v=?

time= 3 second

velocity =distance/time

velocity=1/3

velocity=0.33 m/s

When describing how quickly something moves or how much its location changes over time, the scalar variable speed can be utilized. It is frequently abbreviated to "s." By dividing the entire distance traveled by the period's duration, the average speed of an object is determined.

The unit of measurement for speed is time divided by distance. Although the unit of speed most frequently employed in daily life is the kilometer per hour (kph), the meter per second (m/s) is the SI unit of speed.

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Answer:

hello! Jaesuk~Sakai here!

Explanation:

The four group 3 elements are scandium, yttrium, lanthanum and actinium. “lanthanide” refers to the elements between lanthanum and lutetium. That term does not encompass scandium and yttrium. Scandium and yttrium act pretty much identically to lanthanides.

happy to help!!

Remember to always stay happy no matter what happens! ^^

One batch of cookies need 1/2 pounds or 0.21 Kg. Thus, 12 batches of cookies need 2.61 kg of butter.

Mass of a substance is the measure of its total amount. Mass of a substance can be expressed in g, Kg, pounds, lbs etc. Each units can be interchanged with certain relations.

One pound of mass = 0.435 Kg.

Thus, 1/2 pound = 0.435/2 = 0.21 kg.

Given that one batch of cookies need 1/2 pounds or 0.21 Kg. Hence, the amount of butter need to prepare 12 batch of cookies is :

= 12 × 0.21 Kg = 2.61 kg.

Therefore, the mass of butter required for 12 batches of cookies is 2.61 Kg.

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Answer:

Frequency

Explanation:

A period is the number of revolutions in a minute.

\( Period = \frac {time}{number \; of \; oscillations}\)

Also, frequency can be defined as number of oscillation per unit time.

Mathematically, frequency is given by the formula;

\( Frequency = \frac {number \; of \; oscillations}{time}\)

Thus, we can deduce that frequency of an oscillation is the inverse of the period (time) of oscillation.

Mathematically, period is expressed as;

\( Period = \frac {1}{frequency}\)

This ultimately implies that, an object's period of oscillation can always be used to solve for frequency.

a) On a wet basis, the molar composition of the gas is approximately 0.813 mol propane, 0.055 mol n-butane, and 0.132 mol water. The ratio of mol H₂O to mol dry gas is 0.162 mol H₂O/mol dry gas.

b) The required air feed rate is approximately 65.9 kmol/h. If the combustion were only 65% complete, the required air feed rate would increase to approximately 101.4 kmol/h.

a) To calculate the molar composition on a wet basis, we convert the weight percentages to mole fractions using the molar masses of propane, n-butane, and water. The molar composition is determined by dividing the weight percentage by the respective molar mass and normalizing the values to sum up to 1. The ratio of mol H₂O to mol dry gas is determined by dividing the mol water by the sum of mols of propane and n-butane.

b) To calculate the required air feed rate, we use the stoichiometry of the combustion reaction between butane and air. The balanced equation shows that 1 mol of butane reacts with 13.5 mol of air. Considering the 25% excess air requirement, we multiply the stoichiometric air requirement by 1.25. If the combustion is only 65% complete, the remaining butane requires additional air to achieve complete combustion. Therefore, the required air feed rate increases to account for the unreacted butane.

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Answer:

a,c,d I thought these are the true statements about these graph