Answer:
KE = 1.05 x105 Joules
Explanation:
KE = 4 * (1.04653 x 105 J) = 4.19 x 105 Joules.
An Olympic swimming pool is 50 meters long. You swam from one end
to the other four times.
a. How many meters did you swim?
Answer:
200 meters
Explanation:
50 meters × 4 times = 200 meters
The total number of meters you swim is 200 meters if the Olympic swimming pool is 50 meters long.
What is the distance?Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
An Olympic swimming pool is 50 meters long. You swam from one end to the other four times.
Let x be the total number of meters you swim.
x can be found using:
x = 50 + 50 + 50 + 50
x = 50×4
x = 200 meters
Thus, the total number of meters you swim is 200 meters if the Olympic swimming pool is 50 meters long.
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In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by a chain. (Neglect the weight of the chain.) The block is initially accelerating at 4.0 m/s.
How much force is being exerted by the chain?
Answer:
2,800 n
Explanation:
hope this helps, have a nice day/night! :D
The force of 2812.5 N is being exerted by the chain.
What is force?An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
Given that:
Mass of the hunk of anorthosite moon rock : m = 500.0 kg.
Acceleration of the hunk: a = 4.0 m/s².
Acceleration due to gravity in moon = 1.625 m/s².
So, required force = 500.0(4.0 +1.625) n = 2812.5 N.
The force of 2812.5 N is being exerted by the chain.
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What is the internal energy of a substance?
Answer:
Internal energy is the microscopic energy contained in a substance, given by the random, disordered kinetic energy of the molecules. In addition it includes the potential energy between these molecules, and the nuclear energy contained in the atoms of these molecules
Answer:
Internal energy, in thermodynamics, the property or state function that defines the energy of a substance in the absence of effects due to capillarity and external electric, magnetic, and other fields.
Explanation:
The temperature of a body is measured using the resistance of a wire. To calibrate the device the following measurements were taken (ohms is the unit of electrical resistance).
Resistance in melting ice 240 ohms.
Resistance in boiling water 250 ohms.
a. What is the change in resistance for a change in temperature of 1 Degree Celcius?
b. The wire is placed into some hot water and the resistance is mesured to be 246 ohms. What is the temperature of the water?
Answer:
A)250-240
=10+960
=970
How does convection play a role in tornadoes?
Answer: The mesocyclone
Explanation: The unsaturated air, if moved upward, will be cooler than the surrounding air and it will sink. ... This convective action (that is, the circulation of air as a result of heat transfer) produces the huge clouds commonly associated with thunderstorms and tornadoes.
Hopes this help um pls mark me as brainliest
Find the acceleration if the force is 10 N and the mass is 5 kg.
Explanation:
Hey there!
Given;
F = 10N
Mass = 5kg
Acceleration due to gravity (a)= 9.8m/s^2
We know that;
F = m*a
Put all values and solve for "m".
10 = m*9.8
Simplify it.
\(m = \frac{10}{9.8} \)
Therefore, m= 1.0204kg.
Hope it helps...
A block of mass 0.5kg is pulled to the right with an applied force 3N at an angle 30 degrees above horizontal as shown. Ignoring friction, the acceleration of the block is...
A. 1.8
B. 3
C. 5.2
D. 6
The answer is C, 5.2
A 500-turn coil of wire 2. 0 cm in diameter is in a magnetic field that increases from 0. 00 T to 0. 30 T in 20 ms. The axis of the coil is parallel to the field. What is the emf of the coil?
The magnetic flux through the coil is given by:
Φ = BAcosθ
where B is the magnetic field, A is the area of the coil, and θ is the angle between the magnetic field and the normal to the plane of the coil. Since the axis of the coil is parallel to the field, θ = 0 and the equation simplifies to:
Φ = BA
The rate of change of magnetic flux is given by:
dΦ/dt = d(BA)/dt = A(dB/dt)
Plugging in the given values, we get:
A = πr^2 = π(1.0 cm)^2 = 3.14 × 10^-4 m^2
dB/dt = (0.30 T - 0.00 T)/(20 ms) = 1.5 × 10^4 T/s
Therefore, the emf induced in the coil is:
emf = -N(dΦ/dt) = -500 × 3.14 × 10^-4 m^2 × 1.5 × 10^4 T/s = -0.235 V
Note that the negative sign indicates that the emf is induced in a direction that opposes the change in magnetic flux.
Using complete sentences, explain why graphs are so important to scientists.
Answer: It keeps them organized
Explanation: ... ew
Design your own roller coaster
Answer:
roller coaster is very nice to see
a ball rolls off a table, with an initial horizontal velocity of 0.75 meters per second. the table is 0.90 meters tall. how far from the base of the table does the ball hit?.
The ball hits the ground 1.18 meters away from the base of the table.
1. Determine the time it takes for the ball to fall from the table to the ground. Since the only force acting on the ball is gravity, we can use the equation h = (1/\(2)gt^2\), where h is the height, g is the acceleration due to gravity (approximately 9.8 \(m/s^2\)), and t is the time.
Plugging in the values, we have 0.90 = (1/2)(9.\(8)t^2\). Solving for t, we get t ≈ 0.43 seconds.
2. Calculate the horizontal distance covered by the ball during the time it takes to fall. We can use the equation d = vt, where d is the distance, v is the initial horizontal velocity, and t is the time.
Substituting the given values, we have d = (0.75 m/s)(0.43 s) ≈ 0.32 meters.
3. Finally, determine the horizontal distance from the base of the table where the ball hits the ground. This distance is equal to the horizontal distance covered by the ball plus the distance from the edge of the table to the base.
If we assume the ball rolls off the table's edge without any horizontal displacement, then the total distance from the base would be 0.32 meters.
However, if there is a horizontal displacement, we need more information to calculate the exact distance from the base of the table where the ball hits.
Therefore, without additional information regarding any horizontal displacement, we can conclude that the ball hits the ground approximately 1.18 meters away from the base of the table.
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A hiker travels 12 km in a direction of 50 degrees west of north. What are the north and west components of this displacement?
The north and west components of this displacement are 9.19 km and -7.71 km respectively.
North component of the displacement
The north component of the displacement is calculated as follows;
Dy = D sinθ
Dy = 12 km x sin50
Dy = 9.19 km
West component of the displacementDx = D x cosθ
Dx = - 12 km x cos(50)
Dx = -7.71 km
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Which one of the following statements is false?
Select one:
a. Air resistance and friction both oppose an object's motion
b. Friction opposes motion and can be reduced with lubrication
c. Air resistance is greater the faster the object is travelling
d. Air resistance only occurs when the wind is blowing
e. To keep a boat moving a driving force is needed to overcome water resistance
The statement which is false is as follows:
Air resistance only occurs when the wind is blowing.Thus, the correct option for this question is D.
What is Friction?Friction may be defined as a type of force that resists the sliding or rolling of one solid object over another through the surface that acts on it.
Friction is a force that takes place as the resistance of motion when one object rubs over another. Friction force always opposes the motion along with air resistance.
Friction can also be somehow reduced with the impact of lubrication over the rubbing surface. It is true that air resistance is greater the faster the object is traveling.
Air resistance does not depend on the blowing of the wind. It does not mean that if there is no wind blowing, the air resistance is negligible.
Therefore, the correct option for this question is D.
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People should be more concerned about the global water budget than the local water budget.
True
Answer:
true
Explanation:
because global helps local
True or false? An object that is accelerating is always speeding up or slowing down.
Answer:
True
Explanation:
If acceleration points in the same direction as the velocity, the object will be speeding up. And if the acceleration points in the opposite direction of the velocity, the object will be slowing down.
how did clair patterson determine the age of earth
Answer:
Patterson isolated lead from fragments of a meteorite that had struck Earth thousands of years ago, and determined the age of the fragments by analyzing proportions of the lead isotopes. The meteorite is assumed to have been formed at the same time as the rest of the solar system, including Earth
Explanation:
A cube of wood 20 cm on each side is placed in a tub of water and is found to sink so that only 6 cm of the block is above the water. What is the density of the wood
The density of the cube of wood placed in the tub of water is determined as 700 kg/m³.
Specific gravity of the woodThe specific gravity of the wood is the fraction of the entire wood volume below water surface.
Height below water surface = 20 cm - 6 cm = 14 cm
S.G = 14 cm/20 cm
S.G = 0.7
Density of the woodThe density of the wood is calculated with respect to density of water.
S.G = ( density of wood) / (density of water)
0.7 = (density of wood) / (1000 kg/m³)
density of wood = 0.7 x 1000 kg/m³
density of wood = 700 kg/m³
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the chemical compositions of jupiter and saturn are most similar to those of:
Which type of chemical reaction results in the absorption of energy? a. combustionb. exothermicc. replacementd. endothermic
The absorption of energy occurs in endothermic reactions. The correct option is D.
What is an endothermic reaction?The type of chemical reaction that results in the absorption of energy is endothermic. In an endothermic reaction, energy is absorbed from the surroundings, resulting in an increase in the internal energy of the system.
This means that the products of the reaction have more energy than the reactants, and the reaction requires an input of energy to proceed.
Examples of endothermic reactions include the reaction of baking soda and vinegar, the melting of ice, and the reaction of ammonium nitrate and water.
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A ladder carried by a fire truck is 20. 0 m long. The ladder weights 3600 N and its center of gravity is at its center. The ladder is pivoted at one end (A) about a pin (Figure 1); ignore the friction torque at the pin. The ladder is raised into position by a force applied by a hydraulic piston at C. Point C is 8. 0 m from A, and the force F⃗ exerted by the piston makes an angle of 40 ∘ with the ladder
To solve this problem, we can analyze the forces acting on the ladder using the principle of torque equilibrium. The torque equilibrium condition states that the sum of the torques acting on an object must be zero for rotational equilibrium.
Let's assume the counterclockwise direction is positive for torques. Considering the forces acting on the ladder, we have:
Weight of the ladder: The weight acts downward at the center of gravity, which is at the center of the ladder. Since the weight is acting at the center of gravity, it does not create any torque.
The force exerted by the hydraulic piston (F⃗): The force is applied at point C and makes an angle of 40° with the ladder. We need to calculate the torque created by this force.
To calculate the torque, we use the equation:
Torque = Force * Perpendicular Distance
The perpendicular distance between the force and the pivot point A is 8.0 m, as given in the problem.
The torque exerted by the hydraulic piston = F * d * sinθ
where F is the magnitude of the force, d is the perpendicular distance, and θ is the angle between the force and the ladder.
Now, let's substitute the given values into the equation:
Torque exerted by the hydraulic piston = F * 8.0 m * sin(40°)
Since the ladder is in equilibrium, the sum of the torques must be zero. Therefore, the torque exerted by the hydraulic piston should be equal and opposite to the torque exerted by the ladder's weight.
The torque exerted by the ladder's weight = 0 (since it acts at the center of gravity)
Therefore, we can set up the equation:
The torque exerted by the hydraulic piston = Torque exerted by the ladder's weight
F * 8.0 m * sin(40°) = 0
Solving for F:
F = 0 / (8.0 m * sin(40°))
F = 0
This means that the force exerted by the hydraulic piston must be zero for the ladder to be in equilibrium. However, in practical situations, a force would be required to lift and hold the ladder in position. This calculation assumes idealized conditions without considering external factors such as friction, structural constraints, or additional forces.
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What elements or compounds make up the majority of the atmospheres of the gas giants?.
Elements make up the majority of the atmospheres of the gas giants are hydrogen and helium.
What are gas giants?Gas giants are large planets composed primarily of gases such as hydrogen and helium, and have relatively small rocky cores. The gas giants of our solar system, Jupiter, Saturn, Uranus, and Neptune, together form a group known as the Jupiter planets.
Four gas giants in the solar system lie in the outskirts of Mars and the asteroid belt beyond their orbits. But the worlds are quite different from each other. Jupiter and Saturn are considerably larger than Uranus and Neptune, and each pair of planets (Jupiter and Saturn vs. Uranus and Neptune) have slightly different compositions.
The gas giant is a giant planet composed primarily of hydrogen and helium. Gas giants are also called failed stars because they contain the same basic elements as stars.
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The tires of a car make 62 revolutions as the car reduces its speed uniformly from 90.0 km/h to 59.0 km/h. The tires have a diameter of 0.86 m.(A) What was the angular acceleration of the tires? (B) If the car continues to decelerate at this rate, how much more time is required for it to stop? (C) If the car continues to decelerate at how far does it go? Find the total distance.
A) Angular acceleration = -2.47 rad/s²
B) 23.54 seconds
C) The total distance covered = 294.23m
Explanations:The number of revolutions = 62
Angular distance, θ = 62 x 2π
θ = 62 x 2 x 3.142
θ = 389.608 radians
Diameter, d = 0.86 m
Radius, r = d/2 = 0.86/2
r = 0.43m
Initial velocity, v₁ = 90 km/h = 90 x (1000/3600)
v₁ = 25 m/s
Angular velocity, w₁ = v₁ / r
w₁ = 25/0.43
w₁ = 58.14 rad/s
Final velocity, v₂ = 59 km/h = 59 x (1000/3600)
v₂ = 16.39 m/s
Angular velocity, w₂ = v₂ / r
w₂ = 16.39 / 0.43
w₂ = 38.12 rad/s
Using the equation of motion:
\(\begin{gathered} w^2_2=w^2_1\text{ + 2}\alpha\theta \\ 38.12^2=58.14^2\text{ + 2}\alpha(389.608) \\ 38.12^2-58.14^2=\text{ }779.216\alpha \\ 779.216\alpha\text{ = }-1927.1252 \\ \alpha\text{ = }\frac{-1927.1252}{779.216} \\ \alpha\text{ = }-2.47rad/s^2 \end{gathered}\)Angular acceleration = -2.47 rad/s²
B) Amount of time required for the car to stop if it continues to decelerate at this rate
Initial angular speed, w₁ = 58.14 rad/s
When the car stops, final angular speed, w₂ = 0 rad/s
Using the equation of motion below:
\(\begin{gathered} w_2=w_1+\text{ }\alpha t \\ 0\text{ = 58.14 + (-2.47)t} \\ -2.47t\text{ = -58.14} \\ t\text{ = }\frac{-58.14}{-2.47} \\ t\text{ = }23.54\text{ seconds} \end{gathered}\)C) The total distance
Use the equation of motion below:
\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ a\text{ = }\alpha r \\ a\text{ = (-2.47)(0.43)} \\ a\text{ = }-1.0621m/s^2 \end{gathered}\)\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ S\text{ = }25(23.54)+0.5(-1.0621)(23.54)^2 \\ S\text{ = }588.5-294.27 \\ S\text{ = }294.23\text{ m} \end{gathered}\)The total distance covered = 294.23m
The density of an object is dependent upon the object’s mass and ---
Answer:Volume
Explanation:
Density = mass/ Volume
Answer:
Volume
Explanation:
The eliptical orbit of a satellite about its primary is shown below. Select all of the quantities that remain constant at the labelled locations (A,B,C,D). D a The tidal force on the satellite Ob. The kinetic energy of the satellite c. The mechanical energy of the satellite d. The work done by the force of gravitational attraction on the satellite D. The angular momentum of the site Of The gravitational potential energy of the satellite d
The angular momentum of the satellite remains constant at the labeled locations (A, B, C, D).
How do quantities change in orbit?
Let's analyze the quantities that remain constant at the labeled locations (A, B, C, D):
A. The tidal force on the satellite: This force depends on the gravitational gradient and the satellite's position relative to the primary. Since the position changes along the elliptical orbit, the tidal force is not constant. Therefore, it does not remain constant at any labeled location.
B. The kinetic energy of the satellite: The kinetic energy of the satellite changes as it moves along its elliptical orbit. It is highest at the perigee (closest point to the primary) and lowest at the apogee (farthest point from the primary). Therefore, it does not remain constant at any labeled location.
C. The mechanical energy of the satellite: The mechanical energy of the satellite is the sum of its kinetic energy and gravitational potential energy. Since both of these quantities change along the elliptical orbit, the mechanical energy is not constant at any labeled location.
D. The work done by the force of gravitational attraction on the satellite: The work done by the force of gravitational attraction is given by the change in gravitational potential energy. As the satellite moves along its elliptical orbit, the distance from the primary changes, causing the gravitational potential energy to vary.
Therefore, the work done by the force of gravitational attraction is not constant at any labeled location.
E. The angular momentum of the satellite: The angular momentum of the satellite remains constant throughout its motion if no external torques act upon it. This is known as the conservation of angular momentum. Therefore, the angular momentum remains constant at all labeled locations (A, B, C, D).
F. The gravitational potential energy of the satellite: The gravitational potential energy of the satellite changes as it moves along its elliptical orbit. It is highest at the apogee and lowest at the perigee. Therefore, it does not remain constant at any labeled location.
In summary, the quantities that remain constant at the labeled locations (A, B, C, D) are:
The angular momentum of the satellite.
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The ______________ is all the surroundings of a living organism.
genetics
environment
temperature
heredity
some music has a slow-moving pulse and some music has a fast-moving pulse. the speed at which the pulse moves in music is known as its
The speed at which the pulse moves in music is known as its tempo. Tempo is measured in beats per minute (BPM) and is the speed of the underlying pulse of a piece of music.
Tempo is the speed at which a piece of music is played. It is measured in beats per minute (BPM), and it affects the overall mood of a piece of music. The tempo of a piece of music is typically determined by the composer, but it may also be affected by the performer's interpretation. Different types of music have different tempos; for example, a ballad may have a slow tempo, while a dance tune may have a fast tempo.
The speed at which the pulse moves in music is known as its tempo. Tempo can vary significantly between pieces and is often indicated in a piece's score with the terms allegro (fast), moderato (moderate) or largo (slow).
In music, the pulse refers to the beat that you can feel in the music. It is the underlying rhythm that keeps the music moving forward. The pulse is usually created by the drums or other percussion instruments in the music, but it may also be created by other instruments or by the vocals. Different types of music have different pulses; for example, a ballad may have a slow-moving pulse, while a dance tune may have a fast-moving pulse.
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What is the equation of the line of best fit for natalie's data?
enter the correct answer in the box by replacing mand b in the equation. round each number to the
nearest tenth.
Answer:
where the numbers at ?
Explanation
A hockey player skates across a rink of length 75m in 8.9 seconds. What is the average speed of the hockey player? The hockey player is moving at a speed of 9.5 m/s. If it takes him 2 seconds to come to a stop under constant acceleration, how far does he travel while stopping?
The average velocity is given by
\(v=\frac{d}{t}\)Where d is the distance covered and t is the time taken.
For the given case, we have
d = 75 m
t = 8.9 s
\(v=\frac{d}{t}=\frac{75}{8.9}=8.43\; \frac{m}{s}\)Therefore, the average speed of the hockey player is 8.43 m/s
The hockey player is moving at a speed of 9.5 m/s.
A bullet of mass 50 g travelling with a speed of 15ms penetrates into a
bag of sand and is uniformly brought to rest in 0.05s.
Find
(a) How for the bullet will penetrate into the bag of sand?
(b) The Average force exerted by the sand ?
Answer:
a) The bullet will penetrate 0.375 meters into the bag of sand.
b) The average force exerted by the sand is 15 newtons.
Explanation:
The statement is incorrectly written. The correct form is presented below:
A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.
a) How far the bullet will penetrate into the bag of sand?
b) The average force exerted by the sand?
b) The average force exerted by the sand on the bullet (\(F\)), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:
\(F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}\) (1)
Where:
\(m\) - Mass of the bullet, measured in kilograms.
\(v_{o}\), \(v_{f}\) - Initial and final speeds of the bullet, measured in meter per second.
\(\Delta t\) - Impact time, measured in seconds.
If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(\Delta t = 0.05\,s\), then the average force exerted by the sand is:
\(F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}\)
\(F = -15\,N\)
The average force exerted by the sand is 15 newtons.
a) The distance travelled by the bullet (\(\Delta s\)), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:
\(\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }\) (2)
If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(F = -15\,N\), then the distance travelled by the bullet is:
\(\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}\)
\(\Delta s = 0.375\,m\)
The bullet will penetrate 0.375 meters into the bag of sand.
Three charges, qA is +6.0 μC, qB is –5.0 μC, and qc is +6.0 μC, are located at the corners of a square with each side length at 5.0 cm as shown in the diagram. Calculate the electric field at point D.
The net electric field at point D is determined as 3.95 x 10⁷ N/C.
Electric field at D due to charge A
E = kq/r²
where;
r is the distance between A and Dq is charge AE(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)
E(AD) = 2.16 x 10⁷ i N/C
Electric field at D due to charge B
E = kq/r²
where;
r is the distance between A and Bq is charge Br² = 5² + 5²
r² = 50
r = √50
r = 7.07 cm
E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)
E(BD) = 9 x 10⁶ N/C
in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i N/C
in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j N/C
Electric field at D due to charge CE = kq/r²
where;
r is the distance between C and Dq is charge CE(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)
E(CD) = 2.16 x 10⁷ j N/C
Net electric field in x directionEi = 2.16 x 10⁷ i N/C + 6.36 x 10⁶ i N/C
Ei = 2.796 x 10⁷ i N/C
Net electric field in y directionEj = 2.16 x 10⁷ j N/C + 6.36 x 10⁶j N/C
Ej = 2.796 x 10⁷ j N/C
Resultant electric field at DE = √Ei² + Ej²
E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]
E = 3.95 x 10⁷ N/C
Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.
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