If you blew on balloons and they move, is that a contact or non-contact force? Explain your answer. ​

Answers

Answer 1

It is contact force, as the air you are blowing is making contact with the balloon.

Answer 2

If you blew on balloons and they move, then it is a type of contact force because the air moving inside the balloon is making contact with the balloon,

While on the other hand in the case of non-contact forces there is no contact between the interacting bodies ,

for example, the gravitational force is a very good example of a non-contact force.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

F = ma

In the case of contact forces, there is contact between the interacting bodies; for instance, the gravitational force is a very good example of a non-contact force.

If you blow on balloons and they move, that is an example of a contact force because the air moving inside the balloon is making contact with the balloon.

Thus, the given case is an example of the contact force.

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Related Questions


with the aid of a diagrams, explainthe law of conservation of energy

Answers

According  to laws of Conservation of energy , energy cannot be created nor be destroyed.  



What are examples of energy?

Energy conservation is to practice the less use of energy .

For example, Turning off the electrical appliances when they are not in use , walking should be first priority rather than driving  are examples of energy conservation .

According to the law energy cannot be created nor be destroyed but it can be transfer from one form to another form of energy.

KE+PE=constant  

Energy remains consvered when it is transferred from one form to another form .

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with the aid of a diagrams, explainthe law of conservation of energy

A rigid, 26-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pressure inside the cooker reaches 150 kPa. Initially, this cooker is filled with water at 175 kPa with a quality of 10 percent. determine the exergy.

Answers

The minimum entropy change of the heat-supplying source is -0.87 kJ/K.

Initial entropy of the system

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.

at initial pressure of 175 kPa

S₁ = 1.485  +  (0.1)(5.6865) = 2.0537 kJ/kg K

Final entropy

The entropy at the final state given the new 40-% quality:

pressure inside the cooker = 150 kPa

S₂ = 1.4337  +  (0.4)(5.7894) = 3.7495 kJ/kg K

Mass of the steam at specific volume

m₁ = 0.026/(0.001057   +  0.1 x 1.002643) = 0.257 kg

m₂ = 0.026/(0.001053   +  0.4 x 1.158347)  = 0.056 kg

minimum entropy change of the heat-supplying source

ΔS + S₁  - S₂  + S₂m₂  - S₁m₁  -  sfg(m₂  -  m₁)  > 0

ΔS + 2.0537 -  3.7495 + (3.7495 x 0.056)  -   (2.0537 x 0.257)  - 5.6865( 0.056 - 0.257)  >  0

ΔS > -0.87 kJ/K

Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.

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The complete question is below:

A rigid, 26-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pressure inside the cooker reaches 150 kPa. Initially, this cooker is filled with water at 175 kPa with a quality of 10 percent. determine the exergy.

Heat is now added until the quality inside the cooker is 40 percent. The water is stirred at the same time that it is being heated. Determine the minimum entropy change of the heat-supplying source if 100 kJ of work is done on the water as it is being heated. Use steam tables

A 2.5 kg sledge hammer hit a cement block with a force of 6.0 Newtons.

How does the force the sledge hammer exerted on the cement block compare with the force the cement block exerted on the sledge hammer?

Responses

The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

HURRY HURRY HURRY !!!The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.

Answers

When a 2.5 kg sledgehammer hit a cement block with a force of 6.0 Newtons. The force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.

What are opposite forces?

This refers to forces that act on an object in opposite directions. The net force is gotten by solving for the difference between the two forces.

When the opposing forces are equal or balanced, the net force is zero.  The sledgehammer hits with a force and the cement block is receiving the impart as a stationary object.

Obviously, the force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.

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A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N​

Answers

Explanation:

To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:

Efficiency = (Output Work / Input Work) * 100

Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.

Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.

Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."

Using the velocity ratio, we have the following relationship:

dE / dL = 5

Now, we can calculate the input work (Wi) and the output work (Wo):

Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)

Output Work (Wo) = Load (L) * Distance moved by the load (dL)

Given that the efficiency is 80%, we can rewrite the formula for efficiency as:

0.80 = (Wo / Wi) * 100

Now, let's solve for the effort (E) using the given values:

Load (L) = 200N

Efficiency = 0.80

Velocity Ratio = 5

First, calculate the output work (Wo):

Wo = Load (L) * Distance moved by the load (dL)

Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):

dL = (1/5) * dE

Wo = L * (1/5) * dE

Wo = 200N * (1/5) * dE

Wo = 40N * dE

Next, calculate the input work (Wi):

Wi = Effort (E) * Distance moved by the effort (dE)

Wi = E * dE

Now, substitute the values into the efficiency formula:

0.80 = (Wo / Wi) * 100

0.80 = (40N * dE) / (E * dE) * 100

0.80 = 40 / E * 100

0.80 * E = 40

E = 40 / 0.80

E = 50N

Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.

A ball bearing is projected vertically upwards from the ground with a velocity of 15ms. Calculate the time taken by the ball to return to the ground (g=10ms^2)​

Answers

Answer:

t = 3 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f}=v_{o}-g*t\)

where:

Vf = final velocity [m/s]

Vo = initial velocity = 15 [m/s]

g = gravity acceleration = 10 [m/s²]

t = time [s]

Now replacing we have:

\(0 = 15 -10*t\\10*t=15\\t= 1.5[s]\)

Note: In the equation above the gravity acceleration is negative, because the movement of the ball bearing is pointing againts the gravity acceleration.

The time calculated is only when the ball bearing reaches the highest elevation, and it will take the same time for descending, therefore the total time is:

t = 1.5 + 1.5 = 3 [s]

A 12 volt power supply is connected
to two 30 Ohm resistors in parallel.
What is the voltage drop across the
resistors?
12 V
30 Ω
30 Ω
[?] volts

A 12 volt power supply is connectedto two 30 Ohm resistors in parallel.What is the voltage drop across

Answers

24 volts is the voltage drop across each of the resistors in the parallel configuration.

When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.

Given:

Power supply voltage (V) = 12 V

Resistance of each resistor (R) = 30 Ω

Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the values:

1/R_total = 1/30 Ω + 1/30 Ω

1/R_total = 2/30 Ω

R_total = 15 Ω

Now, we can find the current flowing through the resistors (I) using Ohm's Law:

I = V / R_total

I = 12 V / 15 Ω

I = 0.8 A

Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:

V_drop = I * R

V_drop = 0.8 A * 30 Ω

V_drop = 24 V

Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.

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Calculate the magnitude of electric field strength at a point 3cm from an infinite line of charge of linear density 18 μC/cm situated in a medium of whose Ԑr = 1.5

Answers

Answer:

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

Explanation:

The linear density:

\(\begin{gathered} \lambda=18\mu C\text{ /cm} \\ \\ \lambda=\frac{18*10^{-6}C}{0.01m} \\ \\ \lambda=0.0018\text{ C/m} \end{gathered}\)

Point r = 3 cm = 3/100 m

r = 0.03 m

The electric field strength is calculated below

\(\begin{gathered} E=\frac{\lambda}{2\pi\epsilon_o\epsilon_rr} \\ \\ E=\frac{0.0018}{2\times3.14\times8.85\times10^{-12}\times1.5\times0.03} \\ \\ E=719709237.468\text{ N/C} \\ \\ E=7.2\times10^8\text{ N/C} \\ \end{gathered}\)

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

A runner having mass of 55 kg moving at a speed of 9 m/s rounds a bend with a radius of 18 m. What is the centripetal
acceleration and centripetal force of the runner? (Do all required steps )

Answers

Answer:

centripetal acceleration = 4.5 m/s^2 ; centripetal force = 247.5 N

Explanation:

centripetal acceleration  = v^2 / r = 9^2 / 18 = 4.5 m/s^2

centripetal force = mv^2 / r = 4.5 x 55 = 247.5 N

A non-uniform bar of weight W = 30.0 N is suspended at rest in a horizontal position by two massless cords. The angle phi between cord 2 and the vertical is equal to 40.0o. The bar has a length L = 3.0 m and the distance of its center of gravity from the left-hand end of the bar is 2.2 m.

Answers

Answer:

12.75N

Explanation:

Let's consider the forces acting on the bar:

Weight of the bar (W = 30.0 N): It acts vertically downward, passing through the center of gravity of the bar.

Tension in cord 1 (T1): It acts horizontally and to the left, making an angle of 90° with the bar. Since cord 1 is massless, it does not contribute to the torque.

Tension in cord 2 (T2): It acts at an angle φ = 40.0° with the vertical.

To find the tension in cord 1 and cord 2, we need to set up torque equilibrium equations. The torque of the weight about the point of suspension must be balanced by the torques of the tensions in cords 1 and 2.

Taking the left end of the bar as the reference point (pivot), the torque equilibrium equation can be written as:

Torque due to weight = Torque due to T1 + Torque due to T2

The torque due to the weight is calculated as follows:

Torque due to weight = Weight of the bar * Perpendicular distance between the weight and the pivot point

The torque due to T1 is zero since it acts along the line of action passing through the pivot point.

The torque due to T2 can be calculated as follows:

Torque due to T2 = T2 * Perpendicular distance between the cord and the pivot point

Using the given values:

Weight of the bar (W) = 30.0 N

Length of the bar (L) = 3.0 m

Distance of the center of gravity from the left-hand end of the bar (d) = 2.2 m

Angle between cord 2 and the vertical (φ) = 40.0°

We can calculate the perpendicular distance between the weight and the pivot point as:

Perpendicular distance = L/2 - d

Using these values, we can solve for T2:

30.0 N * (L/2 - d) = T2 * L * sin(φ)

Let's substitute the given values and solve for T2:

30.0 N * (3.0/2 - 2.2) = T2 * 3.0 * sin(40.0°)

T2 ≈ 12.75 N

Therefore, the tension in cord 2 (T2) is approximately 12.75 N.

Suppose the pressure exerted by a cube on the floor is 355Pa,and the weight of the cube is 120.N. What is the area of thecube?

Answers

Answer: Area = 0.34 m

Explanation:

The formula for calculating pressure is expressed as

Pressure = force/area

Area = force/pressure

From the information given,

Pressure = 355

Force = 120

Area = 120/355

Area = 0.34 m

Which of the following is the BEST explanation for why oceans have two different types of currents?

Answers

Answer:

sddww

Explanation:

szsswa

Complete this concept map about types of waves.

Complete this concept map about types of waves.

Answers

Answer:

The answer is within the picture.

Explanation:

Complete this concept map about types of waves.

3% of earth's water is?

Answers

Is earth’s freshwater

Only about 3 percent of Earth’s water is fresh water.

3% of earth's water is?

(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What is the particle's speed at B ?

(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What

Answers

Answer:

Explanation:

according to the graph at B the potential energy of the particle is 2J

therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.

\(E_{k} =1/2mv^{2}\)

2J= 1/2*1/2kg*v^2

8=v^2

v= 2√2 ms-1

2. Write down two examples of work done to store Potential energy.

Answers

Here are two examples of work done to store potential energy i.e. Lifting a weight, and stretching a spring.

1. Lifting a weight: When you lift a weight against the force of gravity, you are doing work to store potential energy in the weight. As you lift the weight, you are increasing its height above the ground, which increases its potential energy. The work you do to lift the weight is equal to the increase in potential energy of the weight.

2. Stretching a spring: When you stretch a spring, you are doing work to store potential energy in the spring. As you stretch the spring, you are increasing its length, which causes the spring to store potential energy. The work done you do to stretch the spring is equal to the potential energy stored in the spring.

In both of these examples, work is done to store potential energy in an object by changing its position or shape. This stored potential energy can be released later to do work on other objects, such as when a weight is dropped or a spring is released.

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When a person wearing a helmet rides a bicycle, the helmet experiences which type of friction?
A. Fluid
B. Static
C. Sliding
D. Rolling

Answers

Answer:

B

Explanation:

Answer:

B.)Static

Hope I helped

In Figure below, m₁=2.00kg and m₂-4.00kg. Consider the pulley to be frictionless. (a) If m₂ is released, what will its acceleration be? (b) What is the tension in the string? m₂ 55 m₂​

Answers

(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².

(b) The tension in the string is approximately -13.08 N.

To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.

(a) Acceleration of m₂:

Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:

Net force = m₁g - m₂g

Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:

m₁g - m₂g = (m₁ + m₂)a

Rearranging the equation to solve for the acceleration, we get:

a = (m₁g - m₂g) / (m₁ + m₂)

Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:

a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)

a = (19.6 N - 39.2 N) / 6.00 kg

a = -19.6 N / 6.00 kg

a = -3.27 m/s²

Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.

(b) Tension in the string:

The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:

Net force = m₂a

Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:

Tension = (4.00 kg)(-3.27 m/s²)

Tension = -13.08 N

Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.

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A child in an inner tube is bobbing up and down in the ocean and notices that after a wave crest passes, four more crests pass in a time of 38.4 s and the distance between the crests is 32 m. If possible, determine the following properties for the wave. (If not possible, enter IMPOSSIBLE.)(a) Period (s)(b) Frequency (Hz)(c) Wavelength (m)(d) Speed ( m/s)(e) Amplitude (m)

Answers

Answer:

Explanation:

Given:

Four more crests pass in a time of 38.4 s and the distance between the crests is 32 m.

We have to determine five terms.

Lets start with one-one basis.

a.  

Period = Time taken by a wave to pass though.

⇒  \(P = \frac{Total\ time}{No.\ of\ waves}\)

⇒ \(P = \frac{38.4}{4}\)

⇒ \(P=9.6 s\)

b.  

Frequency = Reciprocal of time period in Hertz.

⇒ \(f=\frac{1}{T}\)

⇒\(f=\frac{1}{9.6}\)

⇒ \(f=0.104 Hertz\)

c)

Wavelength = Distance between two consecutive trough and crest.

⇒ \(\lambda = 32 m\)

d.

Speed (v) = Product of frequency and wavelength.

⇒ \(v=f\times \lambda\)

⇒ \(v=0.104\times 32\)

⇒\(v = 3.33 ms^-1\)

e)

Amplitude = The maximum displacement or half the distance from crest to trough.

⇒ Here it can't be determined.

⇒ Impossible.

PLEASE HELP!!
What process is illustrated in the figure?

PLEASE HELP!!What process is illustrated in the figure?

Answers

Answer: A

Explanation:

What is not one of the main uses of springs?
A. Car suspension
B. Bike suspension
C. The seasons
D. Clock making

Answers

Hi! I believe the answer is C. or The seasons because all the other options use springs when making cars, bikes, and clocks. I hope this helped. Goodluck :)

Two students are canoeing on a river. While heading
upstream, they accidentally drop an empty bottle overboard. They
then continue paddling for 2 hours, reaching a point 2.5 km
farther upstream. At this point they realize that the bottle is
missing and, driven by ecological awareness, they turn around
and head downstream. They catch up with and retrieve the bottle
(which has been moving along with the current) 4.0 km downstream
from the turnaround point. (a) Assuming a constant paddling effort
throughout, how fast is the river flowing? (b) What would the canoe
speed in a still lake be for the same paddling effort?

Answers

The speed of the river flowing is 3.75 km/h, and the canoe speed in a still lake for the same paddling effort is 3.6 km/h (approximately).

The distance between the two points upstream and downstream is equal to the distance traveled by the empty bottle. Hence, the distance traveled by the bottle = distance traveled by canoeists = 4 km.Total distance traveled = distance upstream + distance downstreamTotal distance traveled = 2.5 + 4 = 6.5 kmTotal time taken = 2 hours upstream + (4/6) hours downstream (since they are covering 4 km in downstream with the current flowing downstream)Total time taken = 3.67 hours upstream + downstreamFrom the definition of speed, the speed upstream is given by:Speed upstream = distance/time upstreamSpeed upstream = 2.5/2Speed upstream = 1.25 km/hSimilarly, the speed downstream is given by:Speed downstream = distance/time downstream Speed downstream = 4/(4/6)Speed downstream = 6 km/hThe speed of the canoe in still water is given by the average of the upstream and downstream speeds:Speed in still water = (1.25 + 6)/2Speed in still water = 3.625 km/h or 3.6 km/h (approximately).

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Aunt Jane weights 45 Newtons. What is her mass?

Answers

Answer:

10.116 Pounds/45 newtons = 10.1164024 pounds/force

Explanation:

Divide the newtons by the rate of acceleration, which will give you the mass of the object. The mass will be in kilograms, because a single newton represents the amount of force needed to move one kilogram one meter. For our example, we will divide 10 N by 2 m/s/s, which give us a mass of 5 kg

radio waves bounce off objects and can be tracked. The photo shows one way this technology is used today

Answers

Doppler radars work by using radio waves that bounce off objects and thus the object can be tracked.

Doppler radars work by emitting a beam of energy from an antenna known as radio waves. The energy they release when they collide with airborne objects scatters in all directions, with some of it returning directly to the radar.

The quantity of energy returned to the radar increases with object size. We can now perceive raindrops in the atmosphere because of this.

The amount of time it takes for the energy beam to be delivered and returned to the radar also gives us the object's distance.

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A tank, in the shape of a cube with each side measuring 2 meters, is half-full of water. Above the water is air that is pressurized to 5 kPa. Calculate the resultant force on one side of the tank due to the air and water (ignore atmospheric pressure) and determine the height of this force above the bottom of the tank.

Answers

Answer:

Explanation:

The tank is half full so height of water level is at 1 m . Centre of gravity of water will be at height of .5 m . Pressure will act at this point .

Pressure = h d g where h is height of centre of mass of water column , d is density of water and g is acceleration due to gravity .

Pressure of water column  = .5 x 10³ x 9.8 = 4.9 k Pa .

Air is pressurized to 5 kPa so

resultant pressure  on one side of the tank due to the air and water

= 4.9 + 5 kPa = 9.9 kPa .

Total force on one face = pressure x area of one face under water

= 9.9 x 10³ x .5 x 2²

= 19.8 kN .

1. Describe how the word ‘scientist’ came to be.
2. Who were the four men that met at Cambridge in 1812 and what were some of their accomplishments? What did they do and discuss at their meetings? Explain and describe.
3. What was the inductive scientific method? Explain. What was the debate surrounding this scientific method? Describe.
4. How did women first get a foot in the door of science? By whom? Explain.
5. What is the heroic part of the Philosophical Breakfast Clubs story? What is the flip side of this story? Explain the details of the ‘flip side.’
6. Snyder ends her talk by saying, “Darwin knew what we seem to have forgotten, that science is not only for scientists.” What do you think that is meant by this? Do you consider yourself to have a basic scientific literacy? Explain and discuss your thoughts.
7. Do you think it’s important that forensics is categorized as a science? Why or why not?

Answers

The word 'scientist' was first coined by William Whewell in the early 19th century. He proposed the term as a replacement for the previous term 'natural philosopher.

What is the word scientist about?

The four men who met at Cambridge in 1812 were Charles Babbage, John Herschel, George Peacock, and Richard Jones. They were all highly accomplished scientists and mathematicians, and they formed a close friendship and intellectual partnership. They discussed a wide range of scientific and philosophical topics, including the nature of knowledge, the role of mathematics in science, and the principles of inductive reasoning. Their meetings laid the foundation for the development of the modern scientific method and helped to establish the field of mathematics as a central component of scientific inquiry.

The inductive scientific method involves making observations and collecting data in order to draw general conclusions or make predictions about a particular phenomenon. It is based on the idea that knowledge can be built up gradually through the accumulation of empirical evidence. The debate surrounding this scientific method focused on the question of whether it was truly objective and reliable, or whether it was inherently biased by the particular observations and assumptions of the scientist conducting the research.

Women first began to make significant contributions to science in the 19th century, largely through the efforts of pioneers such as Mary Somerville and Caroline Herschel. These women often had to overcome significant social and institutional barriers in order to pursue scientific research, but their accomplishments helped to pave the way for future generations of female scientists.

The heroic part of the Philosophical Breakfast Clubs story is the way in which these four men collaborated and supported each other in pursuit of scientific knowledge. They were willing to challenge established ideas and take risks in order to advance their field. However, the flip side of this story is that their exclusive, male-dominated intellectual circle reinforced existing power structures and excluded women and other marginalized groups from participating in the scientific enterprise.

Darwin's statement that "science is not only for scientists" emphasizes the idea that scientific knowledge should be accessible and understandable to everyone, not just those who have specialized training or expertise. In order to fully participate in a democratic society, it is important for individuals to have at least a basic understanding of scientific concepts and methods. Whether or not one considers oneself to have a basic scientific literacy depends on individual experiences and education.

Therefore, It is important that forensics is categorized as a science because it involves the application of scientific principles and methods to the investigation of crimes and other legal matters. By using evidence-based techniques, forensic scientists can provide accurate and reliable information that can be used to make informed decisions in legal proceedings.

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a spring balance has a maximum reading of 10 Newton and the length of the calibrated scale is 20 cm a rectangular metal block measuring 10 cm by 3 cm by 2 cm is hanged on the balance and stretches the string by 15 cm calculate the weight of the block the mass of the Block and the total density of the metal from which the blood is made​

Answers

To calculate the weight of the block, we can use the formula:

Weight = Mass x Gravity

Where gravity is approximately 9.8 m/s^2.

First, we need to find the mass of the block. We can use the formula:

Density = Mass / Volume

The volume of the block is:

Volume = Length x Width x Height

Volume = 10 cm x 3 cm x 2 cm

Volume = 60 cm^3

We don't know the density of the metal, so we can't calculate the mass directly. However, we can use the spring balance reading to find the weight of the block.

The spring balance has a maximum reading of 10 Newtons, which corresponds to a length of 20 cm. When the block is hung on the balance, it stretches the string by 15 cm. The extension of the spring is proportional to the weight of the block, so we can use the following proportion:

Extension of spring / Total length of spring = Weight of block / Maximum weight of spring balance

Substituting the values we have:

15 cm / 20 cm = Weight of block / 10 N

Solving for the weight of the block:

Weight of block = 7.5 N

Now we can find the mass of the block:

Mass = Weight / Gravity

Mass = 7.5 N / 9.8 m/s^2

Mass = 0.765 kg

Finally, we can calculate the density of the metal:

Density = Mass / Volume

Density = 0.765 kg / 60 cm^3

Density = 0.01275 kg/cm^3

So the weight of the block is 7.5 N, the mass of the block is 0.765 kg, and the density of the metal is 0.01275 kg/cm^3.

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Question 5 0/1pts Scalar (dot) product: If=41-1+4k and B-xÎ +27-5X find x so B will be perpendicular to​

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Refer to the photo taken.
Question 5 0/1pts Scalar (dot) product: If=41-1+4k and B-x +27-5X find x so B will be perpendicular to

The
states that price and quantity move in opposite directions.

Answers

The Law of Demand states that price and quantity move in opposite directions.

What does the law of demand mean?

According to the Law of Demand, there is an indirect correlation between a good or service's price and the amount of that good or service that customers are willing and able to purchase. In other words, consumers are less able and willing to purchase an item as its price rises and vice versa.

This connection between a product's price and demand for it in terms of quantity is captured by the Law of Demand. It asserts that the price of a good and the amount desired are negatively) relate

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One ball is dropped at rest from a height of h = 65 m. At the same time, another ball is thrown upward from the ground with initial velocity v2 = 25 m/s. It takes Δt time for them to meet on the way. Defining the positive direction going upward, what is the acceleration of the two balls, a in m/s2?

Answers

If one ball is dropped at rest from a height of h = 65 m.  The acceleration of the two balls is: -9.8 m/s^2 for both balls.

How to find the acceleration?

Let's start by finding the time it takes for the two balls to meet. We know that the ball thrown upward starts from rest, so its initial velocity is 0 m/s. We can use the following kinematic equation:

y = v_i*t + (1/2)at^2

where y is the displacement (in this case, it is the distance between the two balls), v_i is the initial velocity, a is the acceleration, and t is the time. We can set y equal to the initial height of the dropped ball, which is h = 65 m. For the ball thrown upward, the initial position is y = 0.

For the dropped ball:

y = h = 65 m

v_i = 0 m/s

For the ball thrown upward:

y = 0

v_i = 0 m/s

Using the given information, we can solve for t:

h = (1/2)at^2

65 m = (1/2)*(-9.8 m/s^2)t^2

t = sqrt(65 m / (1/2(-9.8 m/s^2))) ≈ 3.64 s

So it takes about 3.64 seconds for the two balls to meet.

Now, we can find the acceleration of the two balls. For the dropped ball, the acceleration is simply the acceleration due to gravity, which is -9.8 m/s^2. For the ball thrown upward, the acceleration is also the acceleration due to gravity, but with a negative sign since it is moving in the opposite direction of gravity. Therefore, the acceleration of the two balls is:

a = -9.8 m/s^2 for both balls

This means that both balls experience the same acceleration due to gravity, regardless of their initial velocities.

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Which of the following best defines effective listening?

Answers

Answer:

The following seems to be the summary including its given phrase.

Explanation:

The willingness to adequately consider the knowledge another speaker provides as well as show interest throughout the subject covered constitutes skills of effective listening. Truly wonderful hearing skills require an individual just to listen fully to the information such that a relevant reading of the information or a piece of evidence can be done.

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