If you take an aluminum can and crush it, how does the density of the metal in the can compare before and after the change?

The electric potential due to these charges at a point P is 2.1 x 10⁷ Nm/C.

Apply Pythagoras theorem to determine the distance between these two points.

y² = 3² + 4²

y² = 25

y = √25

y = 5 m

\(V_y = \frac{kQ}{r} \\\\V_y = \frac{9\times 10^9 \times (-8.8 \times 10^{-3})}{5} \\\\V_y = -1.584 \times 10^{7} \ Nm/C\)

\(V_x = \frac{kQ}{r} \\\\V_x = \frac{9\times 10^9 \times 6.1 \times 10^{-3}}{4} \\\\V_x = 1.373 \times 10^{7} \ Nm/C\)

\(V = \sqrt{V_y^2 + V_x^2} \\\\V = \sqrt{(-1.584 \times 10^7 )^2\ + \ (1.373 \times 10^7)^2} \\\\V = 2.1 \times 10^7 \ Nm/C\)

Thus, the electric potential due to these charges at a point P is 2.1 x 10⁷ Nm/C.

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A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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Answer is zero

Plz mark me brainlist

Explanation:

Outside two infinite parallel plates with opposite charge the electric field is zero, and that can be proved with Gauss's law using any possible Gaussian surface imaginable

To draw a position-time graph, we consider the variable time as independent, and the variable position as a dependent, in other words, time is the horizontal axis and position is the vertical axis.

Now we plot the given values.

At last, we unite the points using a line.

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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Answer: B

Explanation:

Answer:

B

Explanation:

its just like someone telling you to do something and when your done them what happened the conclusion

The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Answer:

Emotional and Social Development

During the preschool years, your little one is learning to read emotional cues and is getting better at relating to other people, according to the New York University Child Study Center 1⭐

⭐This is a verified and trusted source

New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. He can empathize with others and make friends with other children his own age. By his fifth birthday, your preschooler often seeks friends of the same gender and shows a preference for playing with other children, rather than adults. Your preschooler also engages in pretend play and can probably tell the difference between reality and fantasy, according to the American Academy of Pediatrics.

Physical Development

There's a big difference between a 2-year-old and a 5-year-old. During the preschool years, your child develops in many physical ways. She goes from toddling around unsteadily to being able to jump, stand on one foot, walk up and down stairs and walk backward, according to the New York University Child Study Center 1⭐

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New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. By the time she's 5, your little one should also be able to ride a tricycle, build a block tower, paint on paper, skip, throw a ball, dress and undress and begin drawing recognizable objects, adds the University of Illinois Extension.

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The time takes the kid to remain in the air is 0.735 s.

Time is the duration of an events. The s.i unit of time is seconds.

To calculate how long the kid will be in the air, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the time is 0.735 s.

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To solve this we are going to use the angular momentum, to calculate de distance of the red spot. The momentum is not going to change, so the initial total momentum has to be the same as the final total momentum

Both momentums are the same, so now we can equal both expressions

What is common among all the graphs is that they all show an object that is moving.

In the distance time graph, we have the distance on the vertical axis and we have the time on the horizontal axis and the shape of the plots may differ depending on the nature of the motion of the objects.

Graphs of distance vs time help us to examine motion by showing how an object has moved over time. All objects shown on a distance vs. time graph are shifting positions over time, regardless of the graph's specific shape or slope, and the graph reveals information about the direction and speed of their motion.

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Answer:

37500 N

Explanation:

F = ma

F = 7500 (5 m/s^2) = 37500 N

Answer:

Explanation:

My perdiction was correct. I predicted in Part A that the Kinetic Energy would increase. In Part B I predicted that the potential energy would decrease due to the kinetic energy increasing.

Calculate the horizontal component of the velocity. The horizontal component of the velocity is given by:

v_x = v * cos(theta)

where v is the original speed of the arrow and theta is the angle of projection.In this case, v = 2 m/s and theta is unknown. Solving for theta, we get:

theta = arccos(v_x / v)

theta = arccos(2 / 2) = 45 degrees

Calculate the vertical component of the velocity. The vertical component of the velocity is given by:

v_y = v * sin(theta)

In this case, v = 2 m/s and theta = 45 degrees. Solving for v_y, we get:

v_y = 2 * sin(45 degrees) = 1.414 m/s

Calculate the time of flight. The time of flight is given by:

t = 2 * v_y / g

In this case, v_y = 1.414 m/s and g = 10 m/s^2. Solving for t, we get:

t = 2 * 1.414 / 10 = 0.283 seconds

Calculate the height of the arrow. The height of the arrow is given by:

y = v_y * t - 0.5 * g * t^2

In this case, v_y = 1.414 m/s, t = 0.283 seconds, and g = 10 m/s^2. Solving for y, we get:

y = 1.414 * 0.283 - 0.5 * 10 * 0.283^2 = 0.303 meters

Therefore, the angle of projection is 45 degrees and the height of the arrow is 0.303 meters.

Answer:

To solve this problem, we can use the equations of motion for projectile motion:

- Vertical displacement: Δy = v₀sinθt - 1/2gt²

- Vertical velocity: v = v₀sinθ - gt

- Time of flight: T = 2v₀sinθ/g

- Horizontal displacement: Δx = v₀cosθt

where v₀ is the initial speed, θ is the angle of projection, g is the acceleration due to gravity (9.81 m/s²), t is the time of flight, and Δy and Δx are the vertical and horizontal displacements, respectively.

First, we can find the maximum height by using the equation for vertical displacement:

Δy = v₀sinθt - 1/2gt²

At the maximum height, the vertical velocity is zero, so we can find the time of flight by setting the vertical velocity equation to zero:

v = v₀sinθ - gt = 0

Solving for t, we get:

t = v₀sinθ/g

Substituting this into the equation for vertical displacement, we get:

Δy = v₀sinθ(v₀sinθ/g) - 1/2g(v₀sinθ/g)²

Simplifying, we get:

Δy = (v₀²sin²θ)/(2g)

Substituting the given values, we get:

Δy = (23²sin²25)/(2*9.81) ≈ 29.4 m

So the maximum height is approximately 29.4 meters.

Next, we can find the time of flight using the equation for time of flight:

T = 2v₀sinθ/g

Substituting the given values, we get:

T = 2*23*sin25/9.81 ≈ 3.5 s

So the time of flight is approximately 3.5 seconds.

Finally, we can find the horizontal displacement using the equation for horizontal displacement:

Δx = v₀cosθt

Substituting the given values, we get:

Δx = 23*cos25*3.5 ≈ 64.3 m

So Kelly needs to be approximately 64.3 meters away to catch the ball.

Answer:

1. The force of the car engine.

Explanation:

We shall see the effect and role played by each force, one by one, as follows:

1. The force of car engine:

The engine produces a force through combustion that is converted to mechanical work through the shaft. This work is then transmitted to the wheels of the car that cause the motion in the car and increase its kinetic energy.

2. Air Resistance:

It is the opposing force of air that tries to reduce the motion of the car and as a result, reduce its kinetic energy.

3. Frictional Force between road and tire:

It is also the opposing force of air that tries to reduce the motion of the car and as a result, reduce its kinetic energy.

4. Gravity:

Gravity pulls everything towards the center of Earth so it does not have much significant role in horizontal motion like this.

Hence, the force of the car engine did the work that increased the car's kinetic energy.

Answer:

convection currents

Explanation:

ANSWER:

13.6 m/s

STEP-BY-STEP EXPLANATION:

The speed of the impact would be the resulting velocity between the initial velocity (which according to the statement is a vertical velocity) and the horizontal velocity.

Now we know the vertical and horizontal components of velocity we can find the resultant by means of the Pythagorean theorem. Using Pythagoras we can say that:

Therefore, the impact speed is 13.6 m/s

Answer:

No. Touching a live electric current is never a good idea.

Answer:

false you would electrocute yourself

Explanation:

!!!!!!!!!!!     LOGICAL     !!!!!!!!!

Answer:

the net force is 40 N to the left.

Explanation:

To find the net force, we need to subtract the force going to the right from the force going to the left:

Net force = 60 N - 20 N

Net force = 40 N to the left

Therefore, the net force is 40 N to the left.

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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kg m/s

Explanation

Momentum is defined as the amount of motion occurring in something that is moving, or the force that drives something forward to keep it movin, it is the product of the mass of a particle and its velocity

on the SI systems the untis would be

so, replacing

therefore, the answer is

kg m/s

I hope this helps you

The amount of damping force that allow shortest possible time is called​ critical damping of the system.

Critical damping is the threshold between overdamping and underdamping  at which the oscillator returns to the position of equilibrium quickly as possible.

Critical damping is frequently desired because such a system returns to and maintains equilibrium quickly. Furthermore, a constant force applied to a critically damped system moves the system to a new equilibrium position as quickly as possible without overshooting or oscillating around the new position.

Critical damping thus provides the rapid approach to zero amplitude for a damped oscillator.

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