By combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.
What is laundry bluing ?
Laundry bluing is a product adds a trace amount of blue dye to white fabric during laundering to improve its appearance.
Bluing products in higher concentrations can darken jeans and other blue cloth.
The blue overpowered the yellow to reflect white (at least the appearance of white to the human eye).
Blue and yellow are complementary colors that combine to reflect white, Fabrics.
Here,
Yellow light is a combination of red and green light. So combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.
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Ball 1, with a mass of 110 g and traveling at 15 m/s, collides head on with ball 2, which has a mass of 340g and is initially at rest.
What is the final velocity of the ball 2 if the collision is perfectly elastic?
What is the final velocity of the ball 2 if the collision is perfectly elastic?
What is the final velocity of the ball 1 if the collision is perfectly inelastic?
What is the final velocity of the ball 2 if the collision is perfectly inelastic?
The final velocity of the ball 2 if the collision is perfectly elastic is 5.87 m/s.
The final velocity of the ball 2 if the collision is perfectly elastic 7.12 m/s.
The final velocity of the ball 1 if the collision is perfectly inelastic 4.4 m/s
The final velocity of the ball 2 if the collision is perfectly inelastic 4.4 m/s
Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].
according to conservation law of momentum,
momentum before collision is equal to momentum after collision.
for elastic collision,
m₁v₁ +m₂v₂ = m₁v₁' + m₂v₂'
for inelastic collision,
m₁v₁ +m₂v₂ = (m₁+ m₂)v
where,
mass of the ball 1 m₁ = 110g = 0.11 kg
mass of the ball 2 m₂ = 340 g = 0.34kg
initial velocity of ball 1 v₁ = 15 m/s
initial velocity of ball 2 v₂ = 0 m/s
final velocity of ball 1 v₁' = ?
final velocity of ball 2 v₂' = ?
velocity of both ball v = ?
for elastic collision,
m₁v₁ +m₂v₂ = m₁v₁' + m₂v₂'
putting all the values,
0.11× 15 = 0.11v₁' + 0.34v₂'
1.65 = 0.11v₁' + 0.34v₂' _______1)
According to conservation energy in elastic collision,
1/2m₁v₁² + 1/2m₂v₂² = 1/2m₁v₁'² + 1/2m₂v₂'²
1/2×0.11×15² = 1/2×0.11×v₁'² + 1/2×0.34×v₂'²
12.37 = 0.055×v₁'² + 0.17×v₂'²______2)
Solving this simultaneous equation we get,
v₁' = 5.87 m/s
v₂'= 7.12 m/s
for inelastic collision,
m₁v₁ +m₂v₂ = (m₁+ m₂)v
0.11×18 + 0 = (0.11 + 0.34 )v
v = 4.4 m/s
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Which energy resource makes up part of the blue segment of the graph shown here?
A. hydroelectric
B. natural gas
C. wind
D. geothermal
Non-renewable energy comes from sources that will run out or will not be replenished in our lifetimes—or even in many, many lifetimes. Most non-renewable energy sources are fossil fuels: coal, petroleum, and natural gas.
Answer: B. natural gas
1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
5. [6.67/10 Points] DETAILS
MY NOTES
ASK YOUR TEACHER
N/C
(a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the
magnitude of the electric field only.)
6.00 μC
1.50 μC -2.00 μC
3.00 cm
Submit Answer
PREVIOUS ANSWERS
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(b) If a charge of -6.13 µC is placed at this point, what are the magnitude and direction of the force on it?
magnitude
N
direction
SERCP11 15.3.P.018. 2/5 Submissions Used
2.00 cm →
As the charge is negative, the force, which has a magnitude of 33.05 N, is directed to the left, against the electric field.
What is the electric field's intensity at a specific distance from the point charge E?E is a symbol for the magnitude of the electric field at a specific distance from a point charge. At twice the distance from the point charge, what is the electric field's strength? The field's strength is E/2 at twice the distance. The field's strength is still equal to E at a distance that is twice as great.
E = k*q/r²
r1 = 2.00 cm
r2 = 1.00 cm + 3.00 cm = 4.00 cm
r3 = 1.00 cm
Using these distances, we can calculate the electric field due to each charge:
E1 = kq1/r1² = (9.0 x 10⁹ Nm²/C²) * (1.50 x 10⁻⁶ C) / (0.02 m)² = 168.75 N/C (to the right)
E2 = kq2/r2² = (9.0 x 10⁹ Nm²/C²) * (-2.00 x 10^⁻⁶ C) / (0.04 m)² = -112.50 N/C (to the left)
E3 = kq3/r3² = (9.0 x 10⁹ Nm²/C²) * (6.00 x 10⁻⁶ C) / (0.01 m)² = 5.40 x 10⁶ N/C (to the right)
E = E1 + E2 + E3 = 168.75 N/C - 112.50 N/C + 5.40 x 10⁶ N/C = 5.39 x 10⁶ N/C (to the right)
F = q*E
F = (-6.13 x 10 C) * (5.39 x 10⁶ N/C) = -33.05 N
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A object spins through an angular displacement of 10 radians and has an angular acceleration of 2.3 rad/sec-squared. Assuming it began spinning from rest, over what time interval did the acceleration occur?
Answer:
The acceleration of the object occurred at 2.95 s
Explanation:
Given;
initial angular velocity of the object, ω = 0
angular acceleration, α = 2.3 rad/s²
angular displacement of the object, θ = 10 radians
The time of the motion is given by the following kinematic equation;
θ = ω + ¹/₂αt²
θ = 0 + ¹/₂αt²
θ = ¹/₂αt²
\(t^2 = \frac{2 \theta}{\alpha}\\\\t = \sqrt{\frac{2 \theta}{\alpha}}\\\\t = \sqrt{\frac{2 *10}{2.3}}\\\\t = 2.95 \ s\)
Therefore, the acceleration of the object occurred at 2.95 s
Air trapped inside a single-piston-cylinder exerts a pressure of 760 mmHg. If its volume is increased by 20% at a constant temperature, the pressure exerted would be equal to
he change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is 745 mmHg.
What is the change in the pressure of the air trapped in the cylinder?The change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is calculated from Boyle's law equation as follows:
The Boyle's law equation is given as follows:
P₁V₁ = P₂V₂
where;
P₁ is the initial pressure
V₁ is the initial volume
P₂ is the final pressure
V₂ is the final volume
From the data given,
P₁ = 760 mmHg
V₁ = V
P₂ = ?
V₂ = V + 0.2 V
V₂ = 1.02 V
P₂ = 760 * V / 1.02 V
P₂ = 745 mmHg
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If it takes 0.8 s for your voice to be heard at a distance of 272 m, what is the temperature of the air?
V = 331 + 0.59 Tc
v= d/t = 272 / 0.8 = 340 m/s
340 = 331 + 0.59 Tc
340 - 331 = 0.59 TC
9 = 0.59 Tc
9/0.59 = Tc
Tc = 15.25°C
A.) A gemstone of mass 1.8 kg compresses a scale's spring by 2.6 cm.
Determine the spring constant.
B.) How much would the spring in the previous question compress if a 5.2 kg mass was placed on the scale?
Explanation:
Given that,
Mass, m = 1.8 kg
Compression, x = 2.6 cm
We know that,
Force on spring = weight
So,
\(mg=kx\)
Where
k is spring constant
\(k=\dfrac{mg}{x}\\\\k=\dfrac{1.8\times 9.8}{2.6\times 10^{-2}}\\\\k=678.46\ N/m\)
(2) If m = 5.2 kg
\(x=\dfrac{mg}{k}\\\\x=\dfrac{1.8\times 9.8}{678.46}\\\\x=2.6 \ cm\)
Hence, this is the required solution.
Say an impulse is applied opposite the go-kart's direction of travel. What happens to
the go-kart if its momentum + impulse = 0?
The go kart stops comes to a stop.
The go kart slows down but keeps moving.
The go kart speeds up.
There is no change in the speed of the go kart.
If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.
Option A is correct.
What is meant by impulse?impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.
If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.
Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.
As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.
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You apply a net force on a soccer ball of 15 N. If the acceleration it has is 5 m/s2 what is the mass of the ball?
Answer:
3 kgExplanation:
The mass of the ball can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
We have
\(m = \frac{15}{5} = 3 \\ \)
We have the final answer as
3 kgHope this helps you
A 682-kg elevator starts from rest and moves upward for 3.10 s with constant acceleration until it reaches its cruising speed, 1.80 m/s.
(a) What is the average power of the elevator motor during this period? (Answer in horsepower)
(b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with
constant speed.) (answer in horsepower)
a) the average power of the elevator motor during this period is 0.1696 hp
b) The power during an upward trip with constant speed is 16.13 horsepower.
To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.
Given:
Mass of the elevator (m) = 682 kg
Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²
Time taken for acceleration (t) = 3.10 s
(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:
d = 0.5 * a * t^2
= 0.5 * 0.5806 m/s² * (3.10 s)^2
= 1.0153 m
Next, we can calculate the work done (W) by the elevator motor:
W = m * a * d
= 682 kg * 0.5806 m/s² * 1.0153 m
= 391.55 J
Now, to find the average power (P), we divide the work done by the time taken:
P = W / t
= 391.55 J / 3.10 s
= 126.36 W
To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.
Therefore, the average power of the elevator motor during this period is:
P = 126.36 W / 745.7
= 0.1696 hp
(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.
The force of gravity (Fg) can be calculated using:
Fg = m * g
= 682 kg * 9.8 m/s²
= 6683.6 N
The power (P) required is given by the formula:
P = Fg * v
= 6683.6 N * 1.80 m/s
= 12030.5 W
To convert the power to horsepower:
P = 12030.5 W / 745.7
= 16.13 hp
Therefore, the power during an upward trip with constant speed is 16.13 horsepower.
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An electric heater rated 500 W operates 24 hours/ day. what is the cost of energy to operate it for 20 days at Rs. 2.00 per kWh ?
Answer:
Rs. 480.00
Explanation:
1kW = 1000W
therefore 500W = 0.5kW
20 × 24hrs = 480hrs in total.
0.5kW × 480hrs = 240kWh
if rs. 2 for 1kWh
then, 240kWh × 2 = Rs. 480.
Answer :
Cost of energy = Rs. 480Step-by-step explanation :
Given that, An electric heater rated 500 W operates 24 hours/ day.
We need to find the cost of energy to operate it for 20 days at Rs. 2.00 per kWh.
Power = 500 W = 500/1000 = 0.5 kW
Enegry consumed in one day :-
→ Enegry = P × t
→ Enegry = (0.5 kW) × 24 h
→ Enegry = 12 kWh
Ennegry consumed in 20 days will be:
→ Enegry = 12 × 20
→ Energy = 240 kWh
So,
→ Cost of enegry = 240 × 2
→ Cost of enegry = Rs. 480
Hence,
Cost of energy to operate it for 20 days at Rs. 2.00 per kWh is Rs. 480Mr Smith is working in a muddy garden. When he picks up a paving stone his feet sink deeper into the mud. Explain why his feet sink into the mud more when he picks up the paving stone. Write about pressure in your answer
because he is carrying more mass and as the ground is muddy his feet goes in due to the pull of gravity
What are 3 things you could you do this week to help you connect better with kids in
your classes?
Answer:
In my physics class, something that helps connect better with kids is keeping connected with them always make sure to ask if they understand what you're teaching if they are following because sometimes most kids are to afraid to admit that they are lost, another way to connect with kids is maybe posting surveys to be able to check in with each student especially during this hard times :)
Explanation:
1. start with fun activities.
2. Encourage single-tasking.
3. Designate a learning playing field.
when light propagates through two adjacent materials that have different optical properties, some interesting phenomena occur at the interface separating the two materials. for example, consider a ray of light that travels from air into the water of a lake. as the ray strikes the air-water interface (the surface of the lake), it is partly reflected back into the air and partly refracted or transmitted into the water. this explains why on the surface of a lake sometimes you see the reflection of the surrounding landscape and other times the underwater vegetation. these effects on light propagation occur because light travels at different speeds depending on the medium. the index of refraction of a material, denoted by n, gives an indication of the speed of light in the material. it is defined as the ratio of the speed of light c in vacuum to the speed v in the material, or Part B What is the minimum value that the index of retraction can havo? ► View Available Hint(s) Figure 1 of 1 0 +1 incident ray reflected ray between 0 and 1 interface Submit refracted ray normal An example of reflection and refraction of light is shown in the figure. (Figure 1)An incident ray of light the interface with the lower material. The reflected ray travels back in the upper material, while the refr. material. Experimental studies have shown that the incident, reflected, and refracted rays and the norm plane. Moreover, the angle that the reflected ray makes with the normal to the interface, caled the ang inach har mase hetween the light ray and the normal to the inte
The index of refraction of light has a minimum value of 1 when it passes through two nearby materials with dissimilar optical properties. At the boundary between the two materials.
First, the various indices of refraction (in various media) must be taken into consideration. For instance, the refractive index of light in a vacuum is one (because vacuum = c). The "optical density" of a medium is determined by its refractive index value: Since transparent mediums other than a vacuum diffuse light more slowly than those that are not, n > 1 in all of them. Examples of common values include those of air (1,003), water (1,33), glass (1,46–1,66), or diamond (2.42). There is a minimum and a maximum value for the refractive index, and we may determine the minimum value using the following. The angle of refraction at which the refracted beam vanishes and all light is reflected is known as the limit or minimum angle, abbreviated as lim. Snell's rule allows us to determine the limit angle (the smallest angle we would need to have to know the minimal index of refraction), since the maximum value of the angle of refraction, from which everything is reflected, is max = 90o:
n 1x sin (lim) = n 2 sin (lim) = n 2 / n 1 = 1 with max = 90o
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The complete question is -
When light propagates through two adjacent materials that have different optical properties, some interesting phenomena occur at the interface separating the two materials. For example, consider a ray of light that travels from air into the water of a lake. As the ray strikes the air-water interface (the surface of the lake), it is partly reflected back into the air and partly refracted or transmitted into the water. This explains why on the surface of a lake sometimes you see the reflection of the surrounding landscape and other times the underwater vegetation.
These effects on light propagation occur because light travels at different speeds depending on the medium. The index of refraction of a material, denoted by n , gives an indication of the speed of light in the material. It is defined as the ratio of the speed of light c in vacuum to the speed v in the material, orn=cv. What is the minimum value that the index of refraction can have?
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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150 ml
Water at 22 °C
Iron at
125 °C
What is a possible
temperature of the
system after the iron
has been added to
the beaker?
A. 147 °C
B. 52°C
C. 125 °C
D. 19 °C
The possible temperature of the system after the iron has been added to the beaker is 52°C.
option B.
What is equilibrium temperature?A system is said to be in thermal equilibrium when there is no temperature difference between system and surroundings. Temperature, as you know, measures how hot or cold a body is with respect to a standard object.
When a system ( cold and hot body) reaches thermal equilibrium or equilibrium temperature, the heat lost by the hot body will be equal to the heat gained by the cold body.
heat gained by the water = heat lost by the iron
The equilibrium temperature will be greater than the initial temperature of the cold body but less than the final temperature of the hot.
Thus, the only possible answer for the equilibrium temperature of mixture is 52⁰C.
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What was your train of thought as you navigated the picture of the candle?
Answer:
Where is the picture
Explanation:
WHERE IS THE PICTURE
What is wrong with the following momentum value: 25 kg*m/s
Answer:
25N/s or 25kg*m/s^2
Explanation:
It is written wrong because the unit of momentum is kgm/s^2 or N/s
Consider a concave spherical mirr or that has focal length f = +19.5 cm.
a) What is the distance of an object from the mirror's vertex if the image is real and has the same height as the object? Follow the sign rules.
The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
What is concave mirror?A concave mirror has a reflective surface that is curved inward and away from the light source.
Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.
Object distance of the concave mirrorApply mirrors formula as shown below;
1/f = 1/v + 1/u
where;
f is the focal length of the mirrorv is the object distanceu is the image distancewhen image height = object height, magnification = 1
u/v = 1
v = u
Substitute the given parameters and solve for the distance of the object from the mirror's vertex
1/f = 1/v + 1/v
1/f = 2/v
v = 2f
v = 2(19.5 cm)
v = 39 cm
Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
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the forebrain is associated with
a. the emotional brain
b. the radical brain
c. the rational brain
d. the sensory brain
Answer: B: the rational brain
Explanation:
Apex have a nice day gen z only
The forebrain is associated with emotional processing, rational thinking, and sensory integration. The correct options are a, c, and d.
The forebrain is the largest and most complex part of the brain, located at the front and top of the brain.
The emotional brain:
The forebrain, particularly the limbic system, is involved in processing emotions and regulating emotional responses. Structures within the forebrain, such as the amygdala and hypothalamus, play crucial roles in emotional processing.The rational brain:
The forebrain, specifically the cerebral cortex, is responsible for higher cognitive functions, including reasoning, problem-solving, and decision-making.The cerebral cortex is highly developed in humans and plays a key role in rational thinking and executive functions.The sensory brain:
The forebrain, particularly the thalamus, plays a critical role in relaying and modulating sensory information. The thalamus acts as a sensory relay station, receiving sensory signals from various parts of the body and directing them to the appropriate areas of the cerebral cortex.Thus, the correct options are a, c, and d.
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Pleaseee I need help!!
Answer:
R1=3.333 Ohms
R2=10 Ohms
R3=16.666 Ohms
Explanation:
30 total
30=R1+R2R3
30=1(x):3(x):5(x)
x=3.3333
R1=3.333 Ohms
R2=10 Ohms
R3=16.666 Ohms
the very act of observing a particle has a dramatic effect on its behaviour why do you think this is the case
Answer:
Explanation:
In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.
So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.
At the football game is a crowd goes wild and does the wave what kind of wave is this an example of
The given example of a wave in the football game is of 'transverse wave'. The transverse wave is a wave in which points oscillates along the path at the right angle to the direction of travelling wave.
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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Please help me solve this! :)
21. The dog's total displacement is given by the vector sum,
(0, 2 km) + (5 km, 0) + (0, -7 km) = (5 km, -5 km)
where (a, b) denotes a vector with a as its x-component and b as its y-component. This displacement has magnitude
√((5 km)² + (-5 km)²) = √50 km ≈ 7.1 km
and points due southwest.
22. The description here is quite confusing. In which direction is Spiderman running? Is he, for instance, in or on the back of the train and running toward the front? Or is he running on the ground and the train is approaching him?
It's hard to tell whether the train's speed is relevant. If both Spiderman and GG are standing on the train, then no. Otherwise, you have to account for relative velocities.
23. Using the same notation as in (21), the whale's resultant displacement t seconds after making the turn is
(0, 15 m/s) (8 s) + (-15 m/s, 0) t = ((-15 m/s) t, 40 m)
The magnitude of this displacement is given to be 180 m, so
√((-15 m/s)² t ² + (40 m)²) = 180 m
Solve for t :
√((225 m²/s²) t ² + 1600 m²) = 180 m
(√((225 m²/s²) t ² + 1600 m²))² = (180 m)²
(225 m²/s²) t ² + 1600 m² = 32,400 m²
(225 m²/s²) t ² = 30,800 m²
t ² = (30,800 m²) / (225 m²/s²)
t ² ≈ 136.889 s²
t = 11.7 s
A dwari planet is a:
small rocky object that orbits the Sun and is usualy found in a bet beiween me orbits of Mars and Jupiter.
small object made of ice and dust thai orbits the Sun and forms a coma as i approaches the Sun.
round object that orbits the Sun but lacks the abity to clear the neghborhood around is orbit.
meteoroid thai bums up in Earth's amosphere, producing a streak of light.
Answer:
round object that orbits the Sun but lacks the ability to clear the neighborhood around is orbit.
Explanation:
It is true that a dwarf planet is a round object that orbits the Sun but lacks the ability to clear the neighborhood around its orbit.
Due to the size of a dwarf planet, it does not possess enough gravitational attraction or force to clear the orbit around it or other bodies.
One of the notable dwarf planets is Pluto. It was formerly thought to be planet but it has since been delisted.
Pluto's orbit lies beyond that of Neptune.
1. What is the distance covered by a T-Rex that goes from 0 m/s to 9 m/s in 6.78 seconds? (10
points)
With the use of first and third equation of motion, the distance covered by a T-Rex is 30.51 m
Linear MotionWhen a body is in linear motion, the body is moving in a straight line. some of the parameters to consider are:
Distance coveredSpeedVelocityAccelerationE.T.CGiven that a T-Rex move from 0 m/s to 9 m/s in 6.78 seconds, the distance covered can be found by calculating the acceleration.
Let us use equation 1
V = U + at
9 = 0 + 6.78a
a = 9 / 6.78
a = 1.33 m/\(s^{2}\)
Now let us use equation 3
\(v^{2}\) = \(u^{2}\) + 2as
\(9^{2}\) = 2 x 1.33 x S
81 = 2.655S
S = 81/2.655
S = 30.51 m
Therefore, the distance covered by a T-Rex is 30.51 m.
Learn more about Linear Motion here: https://brainly.com/question/12721831
Unit conversion
The choices are in units
A,GA,MA,uA,kA,mA,nA,pA. Pick one the units
Answer:
1.234567 kA
Explanation:
The prefix k stands for kilo-, or 10³. The prefix m stands for milli-, or 10⁻³. The sum shown is ...
1.234 kA + 0.000567 kA = 1.234567 kA
You are moving a wagon with a friend's help you push on the left side of the wagon with 25 of force while your friend pulls from the right side of the wagon with a force of 15N,
What is the net force?
Answer:
10N to the left side towards you
Explanation:
The net force is the resultant force that acts on a body.
Force is a push or pull on a body.
Push to left side = 25N
Pull to the right = 15N
Net force = Push to left side - Pull to the right = 25N - 15N
Net force = 10N to the left side towards you
The net force is therefore 10N to the left side towards you