Imagine an isolated positive point charge Q (many times larger than the charge on a single proton). There is a charged particle A (whose charge is much smaller than charge Q) at a distance from the point charge Q. On which of the following quantities does the magnitude of the electric field created by charge Q at particle A's position depend?a) the amount of the charge on the point charge Qb) the specific location of the charged particle A (while the distance between Q and A is fixed)c) the specific location of the point charge Q (while the distance between Q and A is fixed)d) the type of the charge on the charged particle Ae) the relative orientation between Q and A (while the distance between Q and A is fixed)f) the distance between the point charge Q and the charged particle Ag) the amount of the charge on the charged particle A

Newton's Laws of motion are: an object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line. The acceleration of an object is determined by its mass and the amount of force applied. When one object applies a force to another, the second object applies an equal and opposite force to the first.

Sir Isaac Newton contributed to physics and mathematics in a variety of ways. At the age of just 23, he created the theories of gravitation in 1666. In the "Principia Mathematica Philosophiae Naturalis," published in 1686, he presented his three laws of motion.

Newton revolutionised science by formulating his three laws of motion. Planets move in elliptical orbits as opposed to circles because of Newton's laws and Kepler's laws.

Newton's Laws of motion are

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Explanation:

180 million km = 10 min

? = 1 min

180 million x 10 = 1,800,000,000 km

180 million km = 600s

? = l s

108,000,000,000km

Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.

Explanation:

Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time

Explanation:

Answer:

ac = ω²R = 3.5²(1.5) = 18.375 ≈ 18 m/s²

The pressure after the temperature has risen to 40.0 °C, assuming that there are no appreciable leaks or changes in volume is 4.35×10⁵ Pa

From the question given above, the following data were obtained:

The pressure the temperature has risen to 40 °C can be obtained as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

Volume = contant

P₁ / T₁ = P₂ / T₂

4.00×10⁵ / 288 = P₂ / 313

Cross multiply

P₂ × 288 = 4.00×10⁵ × 313

Divide both sides by 288

P₂ = (4.00×10⁵ × 313) / 288

P₂ = 4.35×10⁵ Pa

Thus, the pressure at 40 °C is 4.35×10⁵ Pa

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Answer:

Its true

Explanation:

Explanation:

Q= mc∆T

∆T= 5-24=- 19

Q= 0.5*4186*-19

Q= -39767 J

negative sign show heat releases

Answer:

A. True, I think

Explanation:

Answer:

a is the answer

Explanation:

Answer:

\(1140\:\mathrm{J}\)

Explanation:

Work is given by \(W=F\Delta x\), where \(F\) is force and \(\Delta x\) is displacement.

Plugging in given values, we get:

\(W=95\:\mathrm{N}\cdot12\:\mathrm{m}=\fbox{$1140\:\mathrm{J}$}\).

If you were to visit another planet, your mass would be the same as on Earth, but your weight would be different.

This is because mass is a measure of the amount of matter in an object, and it does not change regardless of the location of the object. However, weight is a measure of the force of gravity acting on an object, and it is determined by the mass of the object and the strength of the gravitational field it is in.

Therefore, if you were to visit another planet with a different gravitational field than Earth's, your weight would be different even though your mass would remain the same.

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The elasticity and Poisson's ratio for this metal is 0.232.

What is ratio?

The realation between two numbers which shows how much bigger one quantity is than another.

Sol-

As per the given question

P=190KN

d=16 mm

Lo=50mm

X=50.1349-50=0.1349mm

Y=15.99-16=-0.01mm

The formula-

E=ó/€

Ó=P/A

A=r/4 d^2 =π/4(16)^2=201.062 mm

ó={190(1000)}201.062=944.982 Mpa

E=944.982/0.002698=350.253 GPa

€y=-0.000625

v=0.232(answer)

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Answer: 25230800 Joules

Explanation: We can treat the copper tank and the water inside as two different objects since they have different specific heats. We will utilize Q=Mcdelta(t) in this problem where M is mass, c is specific heat, and delta t is the change in temperature.

Since we are treating the copper and water separately we can make a Mcdelta(t) for each one of them. This gives us Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t)). The delta t will be the same because both the copper and water are at 15 celsius. Now we just do some calculations.

Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t))

Q=(20)(385)(55-15)+(150)(4200)(55-15)

Q=30800+25200000

Q=25230800 J

This number may seem absurdly high but there is 150 kg of water being heated up which is 150 liters(A LOT!).

Hope this helps!

The speed of the car traveling 58 meters in 20 seconds is 2.9 m/s.

Speed is the rate of chnage of distance. The S.I unit of speed is meter per seconds (m/s).

To calculate the speed of the car, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

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The width of the outer core is 1,350 miles.

Earth's outer core is a fluid layer about 2,200 km thick, composed of mostly iron and nickel that lies above Earth's solid inner core and below its mantle.

The outer core, about 2,200 kilometers (1,367 miles) thick, is mostly composed of liquid iron and nickel.

The width of the outer core is calculated as follows;

Δx = (3991 mi ) - (32 mi + 1821 mi + 788 mi)

Δx = 1,350 mi

Thus, from the data given, the width of the outer core is 1,350 miles.

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The acceleration of the car is 0.5 meters per seconds square.

Given the following data:

Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.

To find the acceleration of the car, we would use the third equation of motion;

Mathematically, the third equation of motion is given by the formula;

\(V^2 = U^2 - 2aS\\\\0 = 30^2 - 2a(900)\\\\0 = 900 - 1800a\\\\1800a = 900\\\\a = \frac{900}{1800}\)

Acceleration, a = 0.5 \(m/s^2\)

Therefore, the acceleration of the car is 0.5 meters per seconds square.

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An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.

To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.

The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.

The force experienced by the wire due to the magnetic field is F = B * I * L.

Given:

Current (I) = 8.0 A

Magnetic field (B) = 60 mT = 60 * 10^(-3) T

Length of the wire (L) = 40 cm = 40 * 10^(-2) m

Substituting the given values into the equation, we get:

F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)

Simplifying the expression, we find:

F = 0.192 N

Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.

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it is a form of mechanical energy, this is not a characteristic of electrical potential energy. Hence option A is correct.

Electrical potential energy is the energy that is held in a system of charges as a result of their arrangements or positions. It is connected to a charge in an electric field and results from the interaction of charges.

The relative locations of the charges and how they interact with the electric field determine the potential energy. Electrical potential energy is not regarded as a type of mechanical energy, though. The energy connected to the motion or location of an object is referred to as mechanical energy.

Both kinetic energy (energy of motion) and potential energy (energy resulting from position or configuration) are included in it; however, electrical potential energy belongs to the potential energy category rather than the mechanical energy category.

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Answer: Iron and steel are two separate metallic elements.

Explanation:

The following are the differences between magnetic properties of iron and steel.:

1. Iron get magnitized quickly under the influence of magnetic field whereas the steel magnitized slowly.

2. The iron looses its magnitism when magnetic field is removed but steel retains the magnitism for long when magnetic field is removed.

Answer:

औडंठः की दुनिया कार्टून दर्शन होली है और यह बियर का अच्छा विकल्प है। विकल्प है। यो कुरा मेरो आफ्ना लागि विचार र त्यहाँको बडेमाको बिल्डिङ भित्र म जिन्दगी एक यात्रा हो कहाँबाट शुरु भइ कहाँ पुगेर अन्त हुन्छ

The time taken for the sprinter to reach the final velocity is 5.68 s.

What is velocity?

This can be defined as the ratio of displacement of a body to time. The S.I unit of velocity is m/s.

The time taken for the sprinter to reach its final velocity can be calculated using the formula below.

Formula

Where:

make t the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The time taken for the sprinter to reach the final velocity is 5.68s

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Explanation:

a. the total time taken for the journey is 50sec.

b. u=0, v=10m/sec, t=20sec.

a=(v-u)/t = (10-0)/20 = 10/20 = 0.5 m/s².

hope this helps you to solve the problem.

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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The direction in which the 25 kg mass will move is to the Left. The correct option is A.

This is because the force pulling to the left is greater than that to the right.

The velocity of the mass after 1 second will be 0.4 m/s

The velocity of the mass after 2 seconds will be 0.8 m/s

The net force o the mass of 25 kg is given below:

Net force = 20 N - 10 N

Net force = 10 N

The velocity of the mass is given by the formula below:

Velocity = net force * time / mass

velocity after 1 second = 10 * 1 / 25

velocity after 1 second = 0.4 m/s

velocity after 2 seconds = 10 * 2 / 25

velocity after 2 seconds = 0.8 m/s

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The angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].

The velocity of a particle when moving in the circular path.

Let speed of the bug with respect to ground is u.

Speed of bag with respect to ring will be

v = u - (- Rω) =

Then, u = v- Rω...............(1)

Angular momentum of ring and bug will remain conserved.

Initial  momentum: L ring + Lbug =0

Final  momentum:  -2m₁ R²ω + m₂uR =0...............(2)

Using equation (1) and (2), the angular velocity expression will be

ω =[m₂v / {(2m₁ +m₂)R}] in positive z direction

Thus, the angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].

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We can find the angular acceleration as follows:

Answer:

B. t = 0.250s

Explanation:

A. An image with the sketch of the bat emitting a sound, which reflects on a surface and return to the bat is attached below.

B. In order to calculate the time that the pulse emitted by the bat, return to the bat, you first calculate the time that pulse takes to arrive to the object.

You use the following formula:

\(x=vt\)      (1)

x: distance to the object = 43m

t: time = ?

v: speed of sound beat = 343 m/s  

You solve the equation (1) for t:

\(t=\frac{x}{v}=\frac{43m}{343m/s}=0.125s\)

The time on which the bat hears the echo is twice the value of t, that is:

\(t'=2(0.125s)=0.250s\)

The time on which bat heart the echo of its sound, from the moment on which bat emitted it, is 0.250s

The magnitude of the tension in the rope is 12.2625 N, and the rope is being pulled horizontally to the left by the wind force..

What is tension?

Tension is the force transmitted through a string, rope, cable or wire when it is pulled tight by forces acting on it from opposite ends. It is a force that is directed along the length of the string, rope, cable or wire and is always directed away from the object that is creating the tension.

When an object is suspended from a rope or cable, the tension in the rope or cable must be equal to the weight of the object in order for the object to remain stationary or move at a constant velocity. If the tension is less than the weight of the object, the object will fall, and if the tension is greater than the weight of the object, the object will rise.

Tension plays an important role in many areas of physics and engineering, such as in the design of suspension bridges, elevator systems, and the motion of satellites in orbit.

To find the tension in the rope and the rope's angle from the vertical, we can start by drawing a free body diagram of the object:

       Tension (upwards)

                   |

                   |

                   |

                   |

        Weight (downwards)

                   |

                   |

                   |

                   |

Wind force (to the right)

where Tension is the tension in the rope, Weight is the weight of the object, and Wind force is the horizontal force due to the wind.

The object is in equilibrium, so the net force on it is zero. We can write two equations based on the forces in the vertical and horizontal directions:

Vertical equilibrium:

             Tension - Weight = 0

                Tension = Weight

Horizontal equilibrium:

   Wind force = Tension * sin(theta)

where theta is the angle between the rope and the vertical.

We can solve these equations for the tension and theta:

Weight = m * g = 1.25 kg * 9.81 m/s^2 = 12.2625 N

Tension = Weight = 12.2625 N

sin(theta) = Wind force / Tension = 18.3 N / 12.2625 N = 1.492

Since sin(theta) is greater than 1, there is no solution for theta. This means that the rope is not making an angle with the vertical, and is instead being pulled directly to the left by the wind force.

Therefore, the magnitude of the tension in the rope is 12.2625 N, and the rope is being pulled horizontally to the left by the wind force.

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The rate energy is consumed this statement describes power.

Hence, Option C is correct answer.

Power is related to energy by that it is the rate at which energy is transferred.

It is a measure of the rate at which work is done.

According to the definition of power, Power is the amount of energy transferred or converted or consumed per unit time.

SI unit of power is watt.

By definition, 1 watt is equal to one joule of work done per second. So if P represents power in watts, E is the change in energy (number of joules) and t is the time taken in seconds then:

P=\(\frac{E}{t}\)= \(\frac{1 Joule}{1 Second}\)= 1 Watt.

Thus from the above conclusion we can say that, The rate energy is consumed describes power.

Hence, Option C is correct answer

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