In a diagnostic x-ray procedure, 5.00×1010 photons are absorbed by tissue with a mass of 0.600 kg. The x-ray wavelength is 2.00×10^-2 nm.What is the total energy absorbed by the tissue (in Joules)?What is the equivalent dose in rem?

The height above the earth where the balloon has a speed of 7.40 m/s is 1587.4 m, calculated as m = 4.90  102 kg, W = 9.70  104 J, initial velocity = 0, final velocity = 7.40 m/s.

The height above the earth where the balloon has a speed of 7.40 m/s can be calculated as follows: Mass of the balloon, m = 4.90 × 102 kg Work done by the nonconservative forces, W = 9.70 × 104 J Initial velocity, u = 0Final velocity, v = 7.40 m/s Let the height above the earth where the balloon has a speed of 7.40 m/s be h. Kinetic energy at height h = Work done by nonconservative forces at height h i.e.,12mv2 = W Here, m = mass of the balloon, v = velocity of the balloon at height h Putting the given values, we get1/2 × 4.9 × 102 × (7.4)2 = 9.7 × 104We get h as, h = 1587.4 m Hence, the height above the earth where the balloon has a speed of 7.40 m/s is 1587.4 m.

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The fundamental force that is most responsible for beta decay is the weak force. This force is responsible for the transformation of a neutron into a proton, electron, and antineutrino.

During beta decay, a neutron emits a W- boson which then decays into a proton, electron, and antineutrino. This results in the conversion of a neutron into a proton, with the electron and antineutrino carrying away the excess energy and momentum. In nuclear physics and particle physics, the weak interaction, which is also often called the weak force or weak nuclear force, is one of the four known fundamental interactions, with the others being electromagnetism, the strong interaction, and gravitation. The Standard Model of particle physics provides a uniform framework for understanding electromagnetic, weak, and strong interactions. An interaction occurs when two particles (typically, but not necessarily, half-integer spin fermions) exchange integer-spin, force-carrying bosons.

So, The fundamental force that is most responsible for beta decay is the weak force.

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The impulse acting on the ball during the contact is 42 kg*m/s. The magnitude of the average force on the floor from the ball is approximately 2100 Newtons.

The impulse acting on the ball during the contact with the floor is equal to the change in momentum of the ball. The momentum of the ball before the impact is,

p₁ = mv₁ = 1.2 kg * 25 m/s = 30 kgm/s

The momentum of the ball after the impact is:

p₂ = mv₂ = 1.2 kg * (-10 m/s) = -12 kgm/s

The change in momentum is:

Δp = p₂ - p₁ = -12 kgm/s - 30 kgm/s = -42 kg*m/s

The average force on the floor from the ball can be calculated using the impulse-momentum theorem, which states that the impulse on an object is equal to the change in its momentum, and the average force is equal to the impulse divided by the duration of the contact:

F = Δp / Δt

where Δt is the duration of the contact.

We have already calculated the change in momentum to be 42 kg*m/s. The duration of the contact is given as 0.020 s.

Therefore, the average force on the floor from the ball is:

F = 42 kg*m/s / 0.020 s ≈ 2100 N

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The deceleration of the car is observed as 2 m/s^2.

The term deceleration has to do with the decrease of velocity with time.

Given that;

v = 65 km/h or 18 m/s

u = 126 km/h to or 35 m/s

t = 8.5 s

a = ?

v = u - at

18 - 35 = -8.5a

a = 18 - 35/-8.5

a = 2 m/s^2

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car's maximum cornering speed on a rainy day when the coefficient of static friction has been reduced by 50% is 27.58 m/s

Car's maximum speed at dry Sunny day,

Vs = √μrg = 39 m/s

Speed at rainy day, μ becomes 0.5μ

Vr = √(0.5*μ*r*g) =√(0.5) * (39) = 27.57716

Vr = 27.58 m/s

An object experiences static friction when a force is applied to it; as a result, the object resists the applied force and stays at rest until static friction is removed. In kinetic friction, the frictional force opposes an object's motion. An item is kept at rest by the force of static friction. The phrase "static friction" can be defined as "the friction people perceive when they attempt to move a stationary object on a surface, but without actually causing any relative motion in between  surface and the body it is on. A force acting in opposition to the direction of a moving body on the surface is felt.

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If vg represents the voltage across the current source in the circuit, a) vg as a function of time can be expressed as vg(t) = R * (16 - 16e^(-5t)). b) The initial value of vg is 0 volts.

a. To find vg as a function of time when \(ig = 16 - 16e^(-5t\)) A, we need to consider the relation between voltage and current in the circuit. Since vg is the voltage across the current source, we can use Ohm's Law to find the relationship between voltage and current.

Ohm's Law states that V = IR, where V is the voltage, I is the current, and R is the resistance. Assuming a resistor R is connected in series with the current source, we can find the voltage vg as a function of time: vg(t) = R * ig(t)

Now, substitute the given current function \(ig(t) = 16 - 16e^(-5t)\):
vg(t) = R * (16 - 16e^(-5t))

b. To find the initial value of vg, we need to evaluate vg(t) at t = 0: \(vg(0) = R * (16 - 16e^(-5 * 0))\)
Since e^0 = 1, the expression simplifies to: vg(0) = R * (16 - 16 * 1)
vg(0) = R * (16 - 16)
vg(0) = 0 V

The initial value of vg is 0 volts.

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Answer:

the answer is 600/5 km/h

can u Brainiless me Please

Answer:

5

Explanation:

100 newtons pulling a 500 newton object has the mechanical advantage of 5 since it pulled 5x its weight

the expression is simple: 500/100= 5 (5 is the mechanical advantage)

pls mark me brainliest if this is right lol ty

1a.) To find the average angular acceleration from t = 0 to t = 3 s, we need to calculate the change in angular velocity over that time interval and divide it by the time taken.

The formula for average angular acceleration is:

Average angular acceleration (α_avg) = (Δω) / (Δt)

The angular velocity function:

ω(t) = -21t² + 101

We need to find the change in angular velocity (Δω) from t = 0 to t = 3 s. Plugging these values into the function, we get:

ω(3) = -21(3²) + 101 = -189 + 101 = -88 rad/s

ω(0) = -21(0²) + 101 = 101 rad/s

Therefore, Δω = ω(3) - ω(0) = -88 rad/s - 101 rad/s = -189 rad/s

The time interval is Δt = 3 s - 0 s = 3 s

Plugging the values into the formula for average angular acceleration:

α_avg = (Δω) / (Δt) = (-189 rad/s) / (3 s) = -63 rad/s²

Therefore, the average angular acceleration of the object from t = 0 to t = 3 s is -63 rad/s².

1b.) To determine the angular acceleration of the object at t = 3 s, we need to differentiate the angular velocity function with respect to time (t). Taking the derivative of ω(t) = -21t² + 101, we get:

ω'(t) = dω/dt = -42t

Plugging in t = 3 s:

ω'(3) = -42(3) = -126 rad/s²

Therefore, the angular acceleration of the object at t = 3 s is -126 rad/s².

2.) To find the change in angular velocity for the first 3 seconds of motion, we need to integrate the angular acceleration function over the time interval [0, 3]. The formula for change in angular velocity is:

Δω = ∫(a(t) dt)

The angular acceleration function:

a(t) = 61t² + 21t - 5

Integrating a(t) with respect to t:

∫(a(t) dt) = ∫(61t² + 21t - 5 dt) = (61/3)t³ + (21/2)t² - 5t

Plugging in the limits of integration t = 0 and t = 3:

Δω = [(61/3)(3³) + (21/2)(3²) - 5(3)] - [(61/3)(0³) + (21/2)(0²) - 5(0)]

= (61/3)(27) + (21/2)(9) - 15

Calculating the value:

Δω = 549 + 94.5 - 15 = 628.5 rad/s

Therefore, the change in angular velocity for the first 3 seconds of motion is 628.5 rad/s.

3a.) To find the angular speed of the wheel at t = 2.00 s, we need to integrate the angular acceleration function over the time interval [0, 2]. Since the angular acceleration is constant, we can directly use the formula:

Angular speed (ω) = ω₀ + αt

Where ω₀ is the initial angular speed, α is the angular acceleration, and t is the time.

The wheel starts at rest, ω₀ = 0.

The angular acceleration (α) is given as 4.00 rad/s².

Plugging in the values:

ω = ω₀ + αt = 0 + 4.00 rad/s² * 2.00 s = 8.00 rad/s

Therefore, the angular speed of the wheel at t = 2.00 s is 8.00 rad/s.

3b.) The tangential speed (v) of point P on the wheel can be calculated using the formula:

Tangential speed (v) = r * ω

Where r is the radius of the wheel and ω is the angular speed.

Given that the radius (r) is 2.00 m and the angular speed (ω) is 8.00 rad/s, we have:

v = 2.00 m * 8.00 rad/s = 16.00 m/s

Therefore, the tangential speed of point P is 16.00 m/s.

3c.) The centripetal acceleration (a_c) of point P can be calculated using the formula:

Centripetal acceleration (a_c) = r * α

Where r is the radius of the wheel and α is the angular acceleration.

Given that the radius (r) is 2.00 m and the angular acceleration (α) is 4.00 rad/s², we have:

a_c = 2.00 m * 4.00 rad/s² = 8.00 m/s²

Therefore, the centripetal acceleration of point P is 8.00 m/s².

3d.) The magnitude of the total acceleration (a_total) of point P can be calculated using the formula:

Total acceleration (a_total) = √((tangential acceleration)² + (centripetal acceleration)²)

Since the wheel starts at rest, the tangential acceleration is zero. Therefore, the formula simplifies to:

Total acceleration (a_total) = centripetal acceleration (a_c)

Using the previous result, the centripetal acceleration of point P is 8.00 m/s².

Therefore, the magnitude of the total acceleration of point P is 8.00 m/s².

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(i) A plane wave has a small uncertainty in position and large uncertainty in momentum. A plane wave is a simple type of wave in which the wavefronts are flat or plane. It has an infinite extent in space. This means that the wave is completely spread out in space. Since a plane wave is completely spread out in space, it is not localized in position. Hence, the uncertainty in position is very small.

The momentum of a plane wave is directly proportional to its frequency. Since the plane wave has a single frequency component, it has a very specific momentum value. Hence, the uncertainty in momentum is very large.(ii) Relative to a plane wave, a wave packet has a larger uncertainty in position and smaller uncertainty in momentum.

A wave packet is a type of wave that is localized in space. It is the sum of several plane waves with different frequencies and phases. This results in a wave that is concentrated in a small region of space.The wave packet has a specific position in space. However, since it is a combination of different frequencies, it has a range of momentum values. Hence, the uncertainty in position is larger.

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Answer:

Below

Explanation:

ESE = 1/2 k d^2

        = 1/2 *  10 N/m * .1 m = .5 J

Answer:

141.152 miles per hour  is the speed of the plane in miles per hour

Explanation:

Speed of plane = Total distance travelled/total time taken -

v = D/t

Substituting the given values in the above equation, we get

v = 467/3.3 miles /hour

v = 141.152 miles per hour

141.152 miles per hour  is the speed of the plane in miles per hour

The values of all sub-parts have been obtained.

(1).  The maximum factored load the beam can withstand is 45.2 kN/m.

(2).  The moment resistance of the cross-section is 291735.65 Nm.

(3).  The factored moment demand is 27939.6 Nm

1) To draw the governing shear and bending moment diagram for the factored load, we need to first calculate the maximum factored load that the beam can withstand.

The maximum factored load on the beam is given by:

Dead Load = 20 kN/m + 15 kN

                   = 35 kN/m.

Live Load = 2 kN/m + 1 kN

                = 3 kN/m.

Total Factored Load = 1.2 x Dead Load + 1.6 x Live Load

                                  = 1.2 x 35 kN/m + 1.6 x 3 kN/m

                                  = 45.2 kN/m.

The maximum factored load the beam can withstand is 45.2 kN/m.

The shear force and bending moment diagrams for the given factored load can be obtained as shown below:

Shear Force Diagram:

Bending Moment Diagram:

2) To calculate the moment resistance of the cross-section, we can use the formula:

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

Where, σst = yield stress of tension steel [σst = fy / γst],

γst = safety factor for tension steel [γst = 1.15A']

A' = area of tension steel, [A'' = b(d - a)].

Where,

b = width of the beam [b = 600 mm],  

d = total height of the beam [d= 1000 mm],

a = effective depth of tension steel [a = 920 mm]

f'c = compressive strength of concrete [f'c = 25 MPa],

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

MR = (400 / 1.15) x 10 x (1000 - 920/2) + 0.85 x 25 x 590 x (1000 - 920/2)

MR = 291735.65 Nm

The moment resistance of the cross-section is 291735.65 Nm.

3) To check if this cross-section is adequately designed to resist the factored bending moment (LRFD), we need to calculate the factored moment demand and compare it with the moment resistance.

The factored moment demand is given by:

MF = ϕ x Mu

Where,ϕ = resistance factor = 0.9, Mu = factored bending moment

Mu = 1.2 x Dead Load x L2 / 8 + 1.6 x Live Load x L2 / 8 + 1.2 x (Dead Load + Live Load) x L2 / 2

   = 1.2 x 35 x 152 / 8 + 1.6 x 3 x 152 / 8 + 1.2 x 38 x 152 / 2

   = 31044 Nm

MF = ϕ x Mu

     = 0.9 x 31044

    = 27939.6 Nm

The factored moment demand is 27939.6 Nm, which is less than the moment resistance of the cross-section, i.e., 291735.65 Nm.

Therefore, this cross-section is adequately designed to resist the factored bending moment.

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Answer:

I don't know ???

sorry

Answer: 20 N

Explanation: Net force is the sum of all forces acting on an object. For example, in a tag of war, when one team is pulling the tag with a force of 100 N and the other with 80 N, the net force would be 20 N at the direction of the first team (100 N - 80 N = 20 N).

Answer:

open the dictionary/glossary. it will give you the definitions of the words there.

Explanation:

Answer:

i think it goes like this

Explanation:

The rock sitting on the cliff that is 25 m high has the gratest gravitational potential energy.

Potential energy is defined as the energy of an object by virtue of it's location. Mathematically, it is written as:

PE = mgh

Where

To determine the rock with the grater potential energy, we shall determine the potential energy of both rock assuming they have the same mass. Details below:

For rock sitting at 25 m high:

PE = mgh

PE = 10 × 9.8 × 25

PE = 2450 J

For rock sitting at 12 m high:

PE = mgh

PE = 10 × 9.8 × 12

PE = 1176 J

From the above calculation, we have:

Thus, we can conclude that the rock sitting at 25 m high, has the gratest potential energy.

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On planets like Venus, Earth, and Mars do not see as many craters because most of them have been eroded away by wind, rain or volcanic activity. We do not see any craters Jupiter, Saturn, Uranus, and Neptune because there is no visible solid surface for the meteors to hit.

Craters heavily dominate the surfaces of Mercury and the Earth's Moon because both the bodies lack water on their surfaces that would erode impact craters with time. They also lack an atmosphere which could disintegrate meteoroids before they impact the surface.

As smaller planets have less gravitational pull as compared to large planets therefore impactors will strike at lower speeds. Greater is the mass of the impactor, greater is the size of crater. Craters are often circular.

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The Momentum Principle states that the rate of change of momentum of a system is equal to the net external force acting on the system.

Momentum is a physical concept that describes an object's tendency to maintain its current state of motion, either in speed or direction, unless acted upon by an outside force. Momentum is a vector quantity, meaning it has both magnitude (or speed) and direction. It is the product of an object's mass and velocity and is often represented by the symbol "p."

In the case of the mass m falling near the Earth, the only external force acting on the system is the gravitational force, which is equal to mg, where g is the acceleration due to gravity. Thus, the Momentum Principle gives dpy/dt = mg. This can be rewritten as dvy/dt = g, where vy is the vertical velocity of the mass m.
On the other hand, the Angular Momentum Principle states that the rate of change of angular momentum of a system is equal to the net external torque acting on the system. Since the mass m is falling in a straight line, there is no torque (or rotational force) acting on the system, and hence the Angular Momentum Principle does not apply.

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Answer:

C-30m/s that my answer

Answer:

About 59.83 kg

Explanation:

The formula for kinetic energy is \(KE = \frac{1}{2}mV^2\), where KE = Kinetic Energy in Joules (J), m = mass in kilograms (kg), and V = Velocity in meters per second (m/s).

In this problem, we are given the Kinetic Energy amount as 193 Joules and the Velocity as 2.54 m/s. Let's plug it into our equation

Now, let's solve this equation.

Step 1: Simplify both sides of the equation.

Step 2: Divide both sides by 3.2258.

The angular momentum of an object depends on: the rate at which that the object rotates, the mass of the object, the shape of the object and the axis of rotation.

The definition of angular momentum is: the characteristic of any rotating object determined by the product of inertia and angular velocity.

It is a property of a rotating body determined by the product of the rotating object's moment of inertia and angular velocity. It is a vector quantity, so along with magnitude, direction must also be taken into account.

It depends on: the rate at which that the object rotates, the mass of the object, the shape of the object and the axis of rotation.

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Answer:

Mass,Velocity and Acceleration

Explanation:

Hope this helps and its different for everyone for me it was A,B and C what was it for you

For Question 6:

The formula for momentum to express the conservation of momentum of two objects in a collision is:

m1 • v1 + m2 • v2 = m1 • v1' + m2 • v2'

m1 and m2 are the masses so

63v1 + 55v2 = 63v1' + 55v2'

v1 and v2 represent the velocities before the collision, so

(63)(0) + (55)(0) = 63v1' + 55v2'

v1' and v2' represent the velocities after the collision, so

(63)(0) + (55)(0) = (63)(3.3) + (55)v2' <-- We're looking for v2'

0 + 0 = 207.9 + 55v2'

-207.9 = 55v2'

-3.78 m/s = v2'

The answer is negative because the 55kg skater is moving to the left.

For Question 7:

The formula for momentum is p = m • v

so we have:

3.9 = .15v

26 m/s = v

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

The broken pieces of the plates overlie a ductile layer known as asthenosphere.

Plate tectonics is a scientific hypothesis that explains the movement of Earth's lithosphere. Plate tectonics also explains the formation of mountains, volcanoes, and the occurrence of earthquakes. The Earth's lithosphere is composed of the Earth's crust, both continental and oceanic, and the uppermost part of the mantle. The lithosphere is divided into several plates that fit together like a puzzle. These plates are in constant motion, driven by the motion of molten rock in the Earth's mantle.

The plate boundaries can interact with one another in various ways. Divergent plate boundaries are where new lithosphere is created as the plates move apart. At convergent plate boundaries, one plate is forced beneath another. Transform plate boundaries are where plates slide past each other in a sideways movement.

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It has the same magnitude but the opposite sign.

The substances (2S, 3S)-dibromopentane and (2R, 3R)-dibromopentane are two enantiomers of the same chemical.

The stereoisomers known as enantiomers rotate plane polarized light and are mirror images of one another. The specific rotation of the compound, which is measured in degrees, is how much the plane polarized light rotates.

The particular rotational amplitude of enantiomers is identical, but the sign is different. The reason for this is that one enantiomer rotates plane polarized light to the left, while the other rotates it to the right.

The amount or measurement of an object is called magnitude.

Enantiomers are pair of compounds that are non-superimpossible mirror images to each other.

According to its definition, it refers to the shift in the orientation of plane-polarized monochromatic light per unit of distance and concentration.

These are light waves that vibrates in only one plane and in one direction.

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Answer:

Distance = 1256 m

Displacement = 0

Explanation:

Distance :

Distance may be defined as the actual length between two points along its path.

It is a scalar quantity and its value can be positive or zero.

Displacement :

Displacement is defined as the shortest length between two point , i.e. between the initial point and the final point.

It is a vector quantity and it has values which can be either positive or negative or zero.

From the question, the diameter of the circular track is, r = 200 m

∴ Distance travelled by an athlete is = circumference of the circular track

                                                            = 2πr

                                                            = 2 x 3.14 x 200

                                                            = 1256 m

 Displacement = 0  (since the original point coincides with the final point).