In a hypothesis test for a mean in one population, where you have H subscript 0 colon space mu space equals space 40 comma space H subscript A colon space mu space not equal to space 40 and the population standard deviation is sigma space equals space 12, what are the critical value(s) of the sample mean x with bar on top if your sample size is 36 and the significance level alpha = 0. 05?


Group of answer choices

The equation for traveling x miles in the cab can be written as:

Cost = $0.60 + $0.14 * x. The cab charges $0.88 for a ride of 2 miles. And the cab charges $1.72 for a trip of 8 miles.

a. The equation for traveling x miles in the cab can be written as:

Cost = $0.60 + $0.14 * x

b. To find the number of miles for a cab ride that costs $0.88, we can set up the equation:

$0.88 = $0.60 + $0.14 * x

Subtracting $0.60 from both sides, we get:

$0.88 - $0.60 = $0.14 * x

$0.28 = $0.14 * x

Dividing both sides by $0.14, we find:

x = $0.28 / $0.14

x = 2 miles

Therefore, the cab charges $0.88 for a ride of 2 miles.

c. To calculate the cost of a trip of 8 miles, we can substitute x = 8 into the equation:

Cost = $0.60 + $0.14 * 8

Cost = $0.60 + $1.12

Cost = $1.72

Therefore, the cab charges $1.72 for a trip of 8 miles.

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Answer:

2532.6

Step-by-step explanation:

Because in the question it says up to 37,800 and 6.7% of that is $2532.6

1) The amplitude c+ is c+l

2) The expectation value is 0

3) The uncertainty ΔSX is √(3/7) c+.

Now, we know that any wave function can be written as a linear combination of two spin states (up and down), which can be written as:

Ψ = c+ |+> + c- |->

where c+ and c- are complex constants, and |+> and |-> are the two orthogonal spin states such that Sx|+> = +1/2|+> and Sx|-> = -1/2|->.

Hence, we can write the given wave function as:Ψ = c+|+> + i/√7|->

Now, we know that the given wave function has been defined in Sx basis, and not in the basis of |+> and |->.

Therefore, we need to write |+> and |-> in terms of |l> and |r> (where |l> and |r> are two orthogonal spin states such that Sy|l> = i/2|l> and Sy|r> = -i/2|r>).

Now, |+> can be written as:|+> = 1/√2(|l> + |r>)

Similarly, |-> can be written as:|-> = 1/√2(|l> - |r>)

Therefore, the given wave function can be written as:Ψ = (c+/√2)(|l> + |r>) + i/(√7√2)(|l> - |r>)

Therefore, we can write:c+|l> + i/(√7)|r> = (c+/√2)|+> + i/(√7√2)|->

Comparing the coefficients of |+> and |-> on both sides of the above equation, we get:

c+/√2 = c+l/√2 + i/(√7√2)

Therefore, c+ = c+l

The amplitude c+ is a real number and is equal to c+l

The expectation value of the operator Sx is given by: = <Ψ|Sx|Ψ>

Now, Sx|l> = 1/2|r> and Sx|r> = -1/2|l>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= -i/√7(c+l*) + i/√7(c+l)= 2i/√7 Im(c+)

As c+ is a real number, Im(c+) = 0

Therefore, = 0

The uncertainty ΔSX in the state |Ψ> is given by:

ΔSX = √( - 2)

where = <Ψ|Sx2|Ψ>and2 = (<Ψ|Sx|Ψ>)2

Now, Sx2|l> = 1/4|l> and Sx2|r> = 1/4|r>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= 1/4(c+l* + c+l) + 1/4(c+l + c+l*) + i/(2√7)(c+l* - c+l) - i/(2√7)(c+l - c+l*)= = 1/4(c+l + c+l*)

Now,2 = (2i/√7)2= 4/7ΔSX = √( - 2)= √(1/4(c+l + c+l*) - 4/7)= √(3/14(c+l + c+l*))= √(3/14 * 2c+)= √(3/7) c+

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The set of all 3 x 3 nonsingular matrices with the standard operations is a vector space. A set is a vector space when it satisfies the eight axioms of vector spaces. The eight axioms that a set has to fulfill to be considered a vector space are:A set of elements called vectors in which two operations are defined.

Vector addition and scalar multiplication. Axiom 1: Closure under vector addition Axiom 2: Commutative law of vector addition Axiom 3: Associative law of vector addition Axiom 4: Existence of an additive identity element Axiom 5: Existence of an additive inverse element Axiom 6: Closure under scalar multiplication Axiom 7: Closure under field multiplication Axiom 8: Distributive law of scalar multiplication over vector addition The given set of 3 x 3 nonsingular matrices satisfies all the eight axioms of vector space operations, so the given set is a vector space.

The given set of all 3 x 3 nonsingular matrices with the standard operations is a vector space as it satisfies all the eight axioms of vector space operations, so the given set is a vector space.

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Answer:

y - 3y^2 + 4y^2 - 12y

y^2 - 11y

Step-by-step explanation:

9514 1404 393

Answer:

  1) 5.25

  2) 95.74°

Step-by-step explanation:

1) The angle bisector divides the triangle into proportional segments.

  DC/BD = CA/BA

We know that BD+DC = 9, so we can fill in the above equation with known values to get ...

  DC/(9-DC) = 7/5

  5·DC = 7(9 -DC) . . . . cross multiply

  12·DC = 63 . . . . . add 7·DC

  DC = 63/12 = 5.25

__

2) Angle BAC can be found using the Law of Cosines.

  a² = b² +c² -2bc·cos(A)

  cos(A) = (b² +c² -a²)/(2bc) = (7² +5² -9²)/(2·7·5) = -7/(70) = -1/10

  A = arccos(-1/10) ≈ 95.739°

The measure of ∠BAC is about 95.74°.

_____

Additional comment

The circumcircle is irrelevant to the questions asked here.

Answer: 3,4,5,6,52,72,86,105

Step-by-step explanation: when solving the range you find the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

Answer:

C. X: Convex

    Y: Concave

Step-by-step explanation:

Got 100 on Quiz. Rear view mirrors use convex mirror. Dental instruments often use concave mirrors.

The correct option is C. X : Convex and Y: : Concave.

A mirror is a surface that makes the light bounding off from the surface.

The mirror produces real image or in some cases virtual image.

There are two types of mirrors.

Plane mirrors and Spherical mirrors.

Plane mirrors form a virtual image. The image formed is of the same size and shape.

There are two types of spherical mirrors.

Concave mirror and convex mirror.

Convex mirror is the diverging mirror and concave mirror is the converging mirror.

Convex mirror is used in side view mirrors in cars.

Concave mirrors are used in dental instruments.

Hence the correct option is C.

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Answer:

according to the figure the width should have the same dimensions e.g if one is 94 the other should be 94 too

Hence , the price of the system $295 .

Let the price of the system be "x" .

It is given that in the first week her savings were $8 less than 2/5 the price of the system which can be represented by equation

First week savings =  (2/5)x -8

It is also given that in the second week, she saved 50 cents more than 1/2 the price of the system which can be represented by equation

Second week savings = (1/2)x +0.5

savings + short = price of system

(2/5)x -8 + (1/2)x +0.5 + 37 = x

 (2/5)x +  (1/2)x + 29.5 = x

   4x + 5x/ 10 + 29.5 = x

     9x/10+ 29.5 = x

       0.9x + 29.5 = x

          29.5 = x - 0.9x

           29.5 = 0.1x

           $ 295 = x

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Answer:

x*y/a-b

Step-by-step explanation:

Answer:

v = 33.8 m/s

Step-by-step explanation:

Given that,

The initial velocity of the truck, u = 0

Acceleration of the truck, a = 3.6 m/s²

Time, t = 9.4 s

We need to find the car's final velocity. Let v is the final velocity.

Using equation of kinematics as follows :

v = u +at

Since, u = 0

\(a=3.6\times 9.4\\\\v=33.8\ m/s\)

Hence, the final velocity of the car is 33.8 m/s.

The function f can be implemented using a single 4-to-1 multiplexer and two inverters.

A 4-to-1 multiplexer is a digital logic component that selects one of four input signals based on the select lines. It has four data inputs (D0, D1, D2, D3), two select lines (S0, S1), and one output (Y). By properly connecting the inputs and select lines, we can realize the desired function f.

To implement the function f using a single 4-to-1 multiplexer and two inverters, we need to carefully assign the input signals and select lines to achieve the desired behavior. The truth table of the function f will guide us in determining the appropriate connections.

First, we can use the inverters to complement the required inputs if needed. Then, we can connect the complemented and uncomplemented inputs to the select lines of the multiplexer. The output of the multiplexer will be the result of the function f.

By carefully selecting the input assignments and connections, we can effectively implement the function f using a single 4-to-1 multiplexer and two inverters. This approach offers a compact and efficient solution for realizing the desired logic function.

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The quadratic residues for the given integers are as follows: a) For the integer 3, the quadratic residues are 0 and 1.

b) For the integer 5, the quadratic residues are 0 and 1.

c) For the integer 13, the quadratic residues are 0, 1, 3, 4, 9, and 10.

d) For the integer 19, the quadratic residues are 0, 1, 4, 5, 6, 7, 9, 11, 16, and 17.

In number theory, a quadratic residue of an integer n is an integer x such that there exists an integer y satisfying x^2 ≡ y (mod n), where "≡" denotes congruence.

To find the quadratic residues of a given integer, we can calculate the square of each integer between 0 and n-1 (inclusive) and check if the result is congruent to a residue modulo n.

For example, let's consider the integer 13. We calculate the squares of integers from 0 to 12:

0^2 ≡ 0 (mod 13)

1^2 ≡ 1 (mod 13)

2^2 ≡ 4 (mod 13)

3^2 ≡ 9 (mod 13)

4^2 ≡ 3 (mod 13)

5^2 ≡ 12 (mod 13)

6^2 ≡ 10 (mod 13)

7^2 ≡ 10 (mod 13)

8^2 ≡ 12 (mod 13)

9^2 ≡ 3 (mod 13)

10^2 ≡ 9 (mod 13)

11^2 ≡ 4 (mod 13)

12^2 ≡ 1 (mod 13)

From these calculations, we can see that the quadratic residues of 13 are 0, 1, 3, 4, 9, and 10.

Similarly, we can apply this process to the other given integers (3, 5, and 19) to determine their quadratic residues.

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Answer:

The rate of snowfall can be computed as inches of snow per hour.

rate = 10 inches / (1.25 hours).

The denominator is the improper fraction 5/4.  To divide by 5/4, you multiply numerator bky 4/5...REMEMBER?

4/5 OF TEN EQUALS 8; THE RATE IS   8 inches/HOUR.

Step-by-step explanation:

The price of the two pencils is Rs.100 (expensive) and Rs.60 (cheaper).

Let the price of the expensive pencil be = x

And the price of the cheaper one be = y.

According to the question:

The difference between the price of 2 = 40

Therefore,

x- y =40

Total amount = 1800.

The number of Expensive pencils that can be bought = 1800/x.

The number of Expensive pencils that can be bought = 1800/y.

According to the question,

1800/y -1800/x = 15 (the number of extra pencils)

= (1800x -1800y)/xy = 15

= 1800x -1800y =15xy

= 1800 (x-y) =15xy

Substituting x-y as 40

1800 x 40 =15xy

xy = 4800.

We know that x-y =40

Therefore, x = y+ 40

xy = 4800

(y+40) y = 4800

\(y^{2}\) + 40 y = 4800

Using the quadratic equation formula,

y = 52.111 or y = -92.111

Thus, the cost of the cheaper pencil (y)= Rs. 52.111

The cost of the expensive pencil (x) = 52.111 + 40 = Rs 92.111

Therefore the cost of two pencils is =   Rs. 52.111 and Rs 92.111.

Answer:

Multiply the second equation by -1, then add the equations together.

Step-by-step explanation:

x+2y=200  

x- y= 50

Multiply the second equation by -1 to eliminate the x

Answer:

I think the answer is A.

But I am not sure.

Answer:

9

Step-by-step explanation:

15 percent of 50 is 9

hope this helps

Answer:

negative,positive,zero,undefined slope

Answer: 25 meters

Step-by-step explanation:

✓625 = 25

Answer:25

Step-by-step explanation:A square has equal length on all its sides, so the area of square is

Length x Length = 625

Which is

Length ^2 = 625

We want the number that when it times it’s self it’s 625

It can be done by square root of 625 which is 25. So the length of side is 25.

Or look at the prime factorization of 625 ( or just factors) and what number they can make up

Which is 5x5x5x5 = 625

They can make up

5^2 x 5^2 = 25 x 25 that is the “same” number

So the length is 25

Answer:

B) 12p - 10

Step-by-step explanation:

J = 3p

A = 2(3p) = 6p

S = 3p - 10

add together:

3p + 6p + 3p - 10 = 12p - 10

When we reverse the digits of a two-digit number, it forms another two-digit number. So, let's say that the tens digit of the original number is x and the ones digit is y.

Therefore, the original number is 10x + y and the reversed number is 10y + x. Given that the reversed number is 27 less than the original number, we have the equation:10x + y - 27 = 10y + xSimplifying and rearranging this equation, we get:9x - 9y = 27x - y = 3x - y = 3Since the sum of the digits of the original number is 3, we know that either x = 0 and y = 3 or x = 3 and y = 0. However, a two-digit number cannot have a tens digit of 0. Therefore, x = 3 and y = 0. The original number is 30.

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Answer:

Step-by-step explanation:

Write in standard form.

2 x  −  3 y  =  − 21

Write in standard form.

3 x  +  y  =  23

answered: faith1993

Standard form means, move the variables to the left-hand-side and leave the constant all by herself on the right-hand-side, usually sorting the variables, so"x" goes first.

now, there's a denominator, we can do away with it, by simply multiplying both sides by the denominator, so let's do so,

answered: evelynalper08

The standard form of an equation of a line is written as:

Ax + By = C  

where A, B and C are constants.

y = –2/3x + 7  

2/3x + y = 7

(2/3x + y = 7)3

2x + 3y = 21

The standard form of an equation of a line is written as:

Ax + By = C  

where A, B and C are constants.

y = –2/3x + 7 2/3x + y = 7(2/3x + y = 7)32x + 3y = 21

Y= -2/3*x+7 | *3

3y= - 2x+21    | +2x

3y+2x=21  this is the correct answer

You multiply everything by 3 which equals 3y=2x+21 then you switch 21 and 3y which equals -21=2x-3y. Hope this helps

1 Answer. The equation in standard form is 23x−y=7 .

Step-by-step explanation:

answered: Guest

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

\frac{2}{5}=\frac{x-18}{x}

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

Answer:

17/4

Step-by-step explanation:

Solution:

Your problem → 2((1/8)+ 4) - ((3/6)*8)

2((18)+4)-((36)⋅8)

=2⋅(1/8)+4-((36)⋅8)

=2⋅(1+4×8)/8-((36)⋅8)

=2⋅(1+32)/8-((36)⋅8)

=2⋅(33/8)-((36)⋅8)

=2⋅(33/8)-((36)⋅8)

=(33/4)-((36)⋅8)

=(33/4)-(36⋅8)

=(33/4)-(12⋅8)

=(33/4)-12⋅8

=(33/4)-4

=(33/4)-4

=(33-4×4)/4

=(33-16)/4

=17/4

=4.25 (in decimal)

The maximum area that can be enclosed with 480 yards of fencing. is 28,530.5 square yards.

Let the length of the rectangular pen be denoted by L and its width be denoted by W.

From the problem statement, we know that the total length of fencing available is 480 yards. We can express this as an equation:

2L + W + 2 = 480

where the additional 2 is for the fence across the width.

Simplifying this equation, we get:

2L + W = 478

We want to find the maximum area that can be enclosed with this amount of fencing. The area of a rectangle is given by:

A = L × W

We can use the equation 2L + W = 478 to solve for one of the variables in terms of the other. For example, we can solve for W:

W = 478 - 2L

Substituting this expression for W into the equation for the area, we get:

A = L × (478 - 2L)

Simplifying this expression, we get:

A = 478L - 2L^2

To find the maximum area, we need to take the derivative of this expression with respect to L, set it equal to zero, and solve for L.

dA/dL = 478 - 4L

Setting this equal to zero and solving for L, we get:

478 - 4L = 0

L = 119.5

Substituting this value of L back into the equation for W, we get:

W = 478 - 2(119.5) = 239

Therefore, the dimensions of the rectangular pen that maximize the area are:

Length = 119.5 yards

Width = 239 yards

And the maximum area that can be enclosed with 480 yards of fencing is:

A = L × W = 119.5 × 239 = 28,530.5 square yards.

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Answer:

11+n

Step-by-step explanation:

eleven increased by a number

11+n

hope it helps

In the event that linear regression is required, we have two options: (1) change the delay column 2) ignore them.

A variable's value can be predicted using linear regression analysis based on the value of another variable. The dependent variable is the one you want to be able to forecast. The independent variable is the one you're using to make a prediction about the value of the other variable.

Given,

You want to run a regression to predict the probability of a flight delay, but there are flights with delays of up to 12 hours that are really messing up your model.

I immediately think of grouping delays into ranges such as those under 40 minutes, those between 40 minutes and 2 hours, those between 2 hours and 10 hours, and those above 10 hours. But doing so requires the use of a classification model, such as logistic regression. We frequently consider whether there will be a delay rather than how long it might last when thinking about delays. In the event that linear regression is required, we have two options: (1) change the delay column 2) ignore them.

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To ensure the sample is representative of the population as a whole, try to use some random samples.

A sample refers to a small quantity that is examined to get the knowledge of how the whole product/population will be.

Now, we need feedback from our clients. To ensure that our sample is representative of the population as a whole, we should include clients with different attributes.

Like, choosing 10 clients all living in the same place, same gender, and same age group will be the worse sample.

The best way to do this is to select samples randomly, ensuring that our sample includes people with different ages, gender, height, disabilities(if any) and statuses, etc.

So, A randomized sample is the best for ensuring that the sample is representative of the population as a whole.

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