In testing an automobile tire for proper alignment, a technician marks a spot on the tire 0.220 m from the center. He then mounts the tire in a vertical plane and notes that the radius vector to the spot is at an angle of 30.0° with the horizontal. Starting from rest, the tire is spun rapidly with a constant angular acceleration of 1.90 rad/s2. (Assume the spot's position is initially positive, and assume the angular acceleration is in the positive direction).A) What is the angular speed of the wheel after 1.30 s?
B) What is the tangential speed of the spot after 1.30 s?
C) What is the magnitude of the total acceleration of the spot after 1.30 s?
D) What is the angular position of the spot after 1.30 s?
Answers
Answer:
a) The angular speed of the wheel after 1.30 seconds is \(2.47\,\frac{rad}{s}\), b) The tangential speed of the spot after 1.30 seconds is \(0.543\,\frac{m}{s}\), c) The magnitude of the total acceleration of the spot after 1.30 seconds is \(1.406\,\frac{m}{s^{2}}\), d) The angular position of the spot is 2.130 radians (122.011°).
Explanation:
a) Given that tire accelerates at constant rate, final angular speed can be predicted by using the following formula:
\(\omega = \omega_{o} + \alpha \cdot \Delta t\)
Where:
\(\omega\) - Final angular speed, measured in radians per second.
\(\omega_{o}\) - Initial angular speed, measured in radians per second.
\(\alpha\) - Angular acceleration, measured in radians per square second.
\(\Delta t\) - Time, measured in seconds.
Given that \(\omega_{o} = 0\,\frac{rad}{s}\) (starts at rest), \(\alpha = 1.90\,\frac{rad}{s^{2}}\) and \(\Delta t = 1.30\,s\), the final angular speed is:
\(\omega = 0\,\frac{rad}{s} + \left(1.90\,\frac{rad}{s^{2}} \right) \cdot (1.30\,s)\)
\(\omega = 2.47\,\frac{rad}{s}\)
The angular speed of the wheel after 1.30 seconds is \(2.47\,\frac{rad}{s}\).
b) The tangential speed of the spot is the product of the distance between the center of the wheel and spot. That is:
\(v = r \cdot \omega\)
Where r is the distance between the center of the wheel and spot. The tangential speed of the spot after 1.30 seconds is:
\(v = (0.220\,m)\cdot \left(2.47\,\frac{rad}{s} \right)\)
\(v = 0.543\,\frac{m}{s}\)
The tangential speed of the spot after 1.30 seconds is \(0.543\,\frac{m}{s}\).
c) The magnitude of the total acceleration of the spot is the magnitude of the vectorial sum of radial and tangential accelerations (both components are perpendicular to each other), which is determined by the Pythagorean theorem, that is:
\(a = \sqrt{a_{r}^{2} + a_{t}^{2}}\)
Where \(a_{r}\) and \(a_{t}\) are the radial and tangential accelerations.
\(a = r\cdot \sqrt{\omega^{4} + \alpha^{2}}\)
If \(r = 0.220\,m\), \(\omega = 2.47\,\frac{rad}{s}\) and \(\alpha = 1.90\,\frac{rad}{s^{2}}\), then, the resultant acceleration is:
\(a = (0.220\,m)\cdot \sqrt{\left(2.47\,\frac{rad}{s} \right)^{4}+\left(1.90\,\frac{rad}{s^{2}} \right)^{2}}\)
\(a \approx 1.406\,\frac{m}{s^{2}}\)
The magnitude of the total acceleration of the spot after 1.30 seconds is \(1.406\,\frac{m}{s^{2}}\).
d) Let be 30° (0.524 radians) the initial angular position of the spot with respect to center. The final angular position is determined by the following equation of motion:
\(\omega^{2} = \omega_{o}^{2} + 2\cdot \alpha \cdot (\theta - \theta_{o})\)
Final angular position is therefore cleared:
\(\theta - \theta_{o} = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)
\(\theta = \theta_{o} + \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)
Given that \(\theta_{o} = 0.524\,rad\), \(\omega_{o} = 0\,\frac{rad}{s}\), \(\omega = 2.47\,\frac{rad}{s}\) and \(\alpha = 1.90\,\frac{rad}{s^{2}}\), the angular position of the spot after 1.30 seconds is:
\(\theta = 0.524\,rad +\frac{\left(2.47\,\frac{rad}{s} \right)^{2} - \left(0\,\frac{rad}{s}\right)^{2}}{2\cdot \left(1.90\,\frac{rad}{s^{2}} \right)}\)
\(\theta = 2.130\,rad\)
\(\theta = 122.011^{\circ}\)
The angular position of the spot is 2.130 radians (122.011°).
In the rotational motion of an object, the angular acceleration is always towards the center, and the further discussion is as follows:
Rotational motion:The tangential acceleration of the object keeps changing its direction as the object rotates, always directed toward the tangent of the circle passing through the position of the object.
Radius of the spot, r = 0.220
minitial angle from the horizontal, θ = 30°
angular acceleration, α = 1.9 rad/s²
(a) from the first equation of motion we get:
ω = ω₀ + αt where
ω is the final angular speed
ω₀ is the initial angular speedand
t is the time = 1.3sω = 1.9×1.3 rad/sω = 2.47 rad/s
(b) tangential speed (v) is given by:
v = r×ωv = 0.220×2.47 m/sv = 0.5434 m/s
(c) The instantaneous tangential acceleration is given by:
\(a_t\) = rω²so the resultant acceleration will be:
\(a=\sqrt{a_t^2+\alpha^2}\\\\a =\sqrt{r^2\omega^4+\alpha^2}\\\\a= \sqrt{(0.220)^2(2.47)^4+(1.9)^2}\\\\a = 1.4 \ \frac{m}{s^2}\)
(d)
The angular displacement is given by:
θ = θ₀t + ¹/₂αt²θ₀ = 30° = 0.524
rad θ = 0.524×1.3 + ¹/₂×1.9×1.3²θ = 2.286 radθ = 131°
Following are the solution for points:
For a)
The angular speed is 2.47 rad/s
For b)
The tangential speed is 0.5434 m/s
For c)
Total acceleration is 1.4 m/s²
For d)
The final angular position is 131°
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Related Questions
What other angle would give the same RANGE as 25 degrees?
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a ball is projected with initial velocity 40m/s at angle of 27° from a building 60meters high.find total time the ball is in the air
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Answer:
projectile motion
total time of flight= 2V° Sintheta / g
answer is 3second
Hope This would help you!
PLS ANSWER WILL MARK BRANLIEST!!!!!!!!!!!!
Describe the life cycle of a star before it collapses into a black hole.
Describe the life cycle of a star before it becomes a black dwarf.
What is the likely outcome of our sun? *
The sun will supernova and become a black hole.
The sun will swell, encompassing the inner planets and collapses into a dwarf star.
The sun will become a pulsar.
How Do You Know?
P.S. the how do you know is only for the last question
Answers
1) describe the life cycle of a star before it collapses into a black hole.
1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.
2) describe the life cycle of a star before it becomes a dwarf.
ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.
3) what is the likely outcome of our sun?
ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.
Explain how a balloon can become positively charged when rubbed with a cloth
Answers
For more static electricity information and experiments, see the list of Web Resources and Further Reading sections.
One of the waste products of a nuclear reactor is plutonium-239 . This nucleus is radioactive and decays by splitting into a helium-4 nucleus and a uranium-235 nucleus , the latter of which is also radioactive and will itself decay some time later. The energy emitted in the plutonium decay is and is entirely converted to kinetic energy of the helium and uranium nuclei. The mass of the helium nucleus is , while that of the uranium is (note that the ratio of the masses is 4 to 235).
(a) Calculate the velocities of the two nuclei, assuming the plutonium nucleus is originally at rest.
(b) How much kinetic energy does each nucleus carry away
Answers
Answer:
a) \( v_{U-235} = 2.68 \cdot 10^{5} m/s \)
\(v_{He-4} = -1.57 \cdot 10^{7} m/s\)
b) \( E_{He-4} = 8.23 \cdot 10^{-13} J \)
\( E_{U-235} = 1.41 \cdot 10^{-14} J \)
Explanation:
Searching the missed information we have:
E: is the energy emitted in the plutonium decay = 8.40x10⁻¹³ J
m(⁴He): is the mass of the helium nucleus = 6.68x10⁻²⁷ kg
m(²³⁵U): is the mass of the helium U-235 nucleus = 3.92x10⁻²⁵ kg
a) We can find the velocities of the two nuclei by conservation of linear momentum and kinetic energy:
Linear momentum:
\( p_{i} = p_{f} \)
\( m_{Pu-239}v_{Pu-239} = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} \)
Since the plutonium nucleus is originally at rest, \(v_{Pu-239} = 0\):
\( 0 = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} \)
\( v_{He-4} = -\frac{m_{U-235}v_{U-235}}{m_{He-4}} \) (1)
Kinetic Energy:
\( E_{Pu-239} = \frac{1}{2}m_{He-4}v_{He-4}^{2} + \frac{1}{2}m_{U-235}v_{U-235}^{2} \)
\( 2*8.40 \cdot 10^{-13} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} \)
\( 1.68\cdot 10^{-12} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} \) (2)
By entering equation (1) into (2) we have:
\( 1.68\cdot 10^{-12} J = m_{He-4}(-\frac{m_{U-235}v_{U-235}}{m_{He-4}})^{2} + m_{U-235}v_{U-235}^{2} \)
\( 1.68\cdot 10^{-12} J = 6.68 \cdot 10^{-27} kg*(-\frac{3.92 \cdot 10^{-25} kg*v_{U-235}}{6.68 \cdot 10^{-27} kg})^{2} +3.92 \cdot 10^{-25} kg*v_{U-235}^{2} \)
Solving the above equation for \(v_{U-235}\) we have:
\( v_{U-235} = 2.68 \cdot 10^{5} m/s \)
And by entering that value into equation (1):
\(v_{He-4} = -\frac{3.92 \cdot 10^{-25} kg*2.68 \cdot 10^{5} m/s}{6.68 \cdot 10^{-27} kg} = -1.57 \cdot 10^{7} m/s\)
The minus sign means that the helium-4 nucleus is moving in the opposite direction to the uranium-235 nucleus.
b) Now, the kinetic energy of each nucleus is:
For He-4:
\(E_{He-4} = \frac{1}{2}m_{He-4}v_{He-4}^{2} = \frac{1}{2} 6.68 \cdot 10^{-27} kg*(-1.57 \cdot 10^{7} m/s)^{2} = 8.23 \cdot 10^{-13} J\)
For U-235:
\( E_{U-235} = \frac{1}{2}m_{U-235}v_{U-235}^{2} = \frac{1}{2} 3.92 \cdot 10^{-25} kg*(2.68 \cdot 10^{5} m/s)^{2} = 1.41 \cdot 10^{-14} J \)
I hope it helps you!
A steel ball (mass = 50 grams) and a plastic ball of the same dimensions (mass = 10 grams) are dropped from the same height at the same time. Which of the following will occur? (ASSUME NO AIR RESISTANCE)
a. the plastic ball will hit the ground before the steel ball hits the ground
b. the steel ball will hit the ground before the plastic ball hits the ground
c. the steel ball and the plastic ball will hit the ground at the same time
Answers
2 B (a) Define frequency in terms of revolution
Answers
Number of revolutions completed by the body in one second is called frequency of revolution.
What can light and sound both vary in which one of these ?
Volume
Intensity
Number or prespective?
Answers
Answer:
intensity
Explanation:
b. example, The sun is very bright and intense. and sounds can be very loud.
Discuss the circuits.
Name all the
components. What
will happen to bulb
B1 if the bulb B2 is
replaced with
connecting wire in
each circuit?
Answers
The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.
Circuits are basically the pathways that allow the flow of electric current. These circuits have different components. In this context, there are two circuits, the series circuit, and the parallel circuit. The series circuit has bulbs connected in a sequence where current flows through each bulb in turn. In contrast, the parallel circuit has bulbs connected to different branches. The current flows through each bulb separately.In a series circuit, the components are a power source, resistors, and wires. A power source can be a battery or a generator that is connected in a sequence with resistors and wires. The bulbs B1 and B2 are connected in series. If bulb B2 is replaced with a connecting wire, then the circuit will become incomplete, and bulb B1 will not light up. This is because in a series circuit, if one component is disconnected, the entire circuit becomes open, and the current stops flowing. Thus, if bulb B2 is replaced with a wire, the current will bypass the bulb, and the circuit will become incomplete. In a parallel circuit, the components are a power source, resistors, and branches. The bulbs B1 and B2 are connected in parallel. If bulb B2 is replaced with a connecting wire, the circuit will still work. This is because in a parallel circuit, each bulb has its branch, and the current flows through each bulb separately. Thus, if bulb B2 is replaced with a wire, the current will still flow through bulb B1, and it will light up.For more questions on the series circuit
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Someone is whirling a hammer that has a mass of 8.5 kg in the air that is tied to a Chain 1.5 m long in a circle that makes 1 revolution in 2 seconds a. What is the centripetal acceleration f the hammer B what is the tension of the Chain
Answers
Explanation
What is the difference between positive and negative acceleration
Answers
Answer:
An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion
Explanation:
An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion
Answer:
Positive acceleration is speeding up and negative acceleration is slowing down.
Explanation:
A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rider together is 85 kg, what is the net force acting on the bicycle? (Hint: first, calculate acceleration) Acceleration = Fnet =
Answers
Answer:
42.5km/s^2
Explanation:
Fnet=m⋅a
We know that
\(a=\frac{v-u}{t}\)
Here,
v=4m/s, u=0m/s, t=8s
\(a=\frac{4m/s-0m/s}{8s} =0/5m/s^2\)
Also, we have m=85kg
Fnet=85 kg⋅0.5 m/s2=42.5N
Acceleration = (change in speed) / (time for the change)
Acceleration = (4 m/s) / (8 seconds)
Acceleration = 0.5 m/s²
Force = (mass) x (acceleration)
Force = (85 kg) x (0.5 m/s²)
Force = 42.5 Newtons
Answer:
\(\sf\longmapsto42.5 N\)
Explanation:
We would need to use Newton's second law ofmotion, which states that-
\(\sf \longmapsto \: F _{net} = m•a \)
We know that,
\(\sf \longmapsto \: a = \frac{v - u}{t} \)
Here,v = 4 m/s, u = 0 m/s, t = 8 s
\(\sf \longmapsto \: a = \frac{4 \: m/s - 0 \: m/s}{8s} = 0.5 \: m / {s}^{2} \)
Also, we have
m = 85 kg
\(\sf \longmapsto \: F _{net} = 85 \: kg \: • \: 0.5 m / {s}^{2} \: \: = 42.5 \: N\)
A copper block of mass 0.75 g is removed from a furnace and quickly transferred into a glass beaker of mass 300.0 g containing 200.0 g of
water. The temperature of the water rises from 12 0 °C to 27 0 °C. What was the temperature of the furnace?
Answers
The furnace has a temperature of 585 degrees Celsius.
Temperature is an expression denoting hotness or coolness on any scale, including Fahrenheit and Celsius. According to temperature, heat energy will naturally move from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature).
Agriculture, food production, and medical care—for both humans and animals—all rely largely on
A ball is thrown up with a speed of 30 m/s and caught when it comes back down. You can ignore air resistance.
Where will the ball's instantaneous VELOCITY be 0 m/s?
A. At the top of its path
B. Just before it is caught at the end of it's path
C. Half way to the top of it's path
D. Just after leaving the throwers hand
Answers
Answer:
The answer is B have a great day hope I helped
12
Select the correct answer.
What creates an electric force field that moves electrons through a circuit?
ОА.
energy source
B.
load
O c.
metal wires
OD.
resistance
Answers
Answer:
A
Explanation:
Can you help me with all 14 of this?
Answers
Answer: Can't see the graph clearly.
The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
Answers
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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If an object is placed 15cm in of front of a concave mirror of radius Curvature 20cm. Determine the position of the image formed
Answers
The image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.
Given that,
Object distance, u = -15 cm
The radius of curvature of the concave mirror, R = 20 cm
Focal length, f = R/2 = -10 cm (negative for concave mirror)
Let v is the distance between mirror and the formed image. Using mirror's formula to find it as :
\($\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$\)
\($\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$\)
\($\frac{1}{v}=\frac{1}{(-10)}-\frac{1}{(-15)}$\)
\($v=-30 \mathrm{~cm}$\)
So, the image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.
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Compute your average velocity in the following two cases:
a. You walk 73.2 m at a speed of 1.22 m/s and then run 73.2 m at a speed of 3.05 m/s along a straight track.
b. You walk for 1.00 minat a speed of 1.22 m/s and then run for 1.00 min at 3.05 m/s along astraight track.
c. Graph x versus t for both cases and indicate how the average velocity is found on the graph.
Answers
The average velocity in the following cases are 1.743m/s and 1.22m/s.
Calculation of Average VelocityTo find the average velocity is given by:
V = \(\frac{total distance (d)}{time taken (t)}\)
(a) From the question we are given:
d1 = 73.2m,
d2 = 73.2m,
v1 = 1.22m/s
v2 = 3.05m/s
We need to calculate the time taken to complete each of the distance using the formula:
t = \(\frac{total distance}{speed}\)
t1 = 73.2/1.22 = 60s
t2 = 73.2/3.05 = 24s
The average velocity is the total distance divided by the total time:
Average velocity (V) = (d1 + d2) / (t1 + t2)
V = 146.4 m / 84 s
Therefore, V = 1.743 m/s (to 3 significant figures)
(b) From the question we are given:
t1 = 1min = 60s,
t2 = 1min = 60s,
v1 = 1.22m/s
v2 = 3.05m/s
We need to calculate the distance covered for each of the time using the formula:
d1 = velocity * time = v1 * t1 = 1.22 * 60 = 73.2m
d2 = velocity * time = v2 * t2 = 3.05 * 60 = 183m
The average velocity is the total distance divided by the total time:
Average velocity (V) = (d1 + d2) / (t1 + t2)
V = (73.2 + 183)/ (60 + 60)
V = 256.2/120 = 2.135m/s
Therefore, the average velocity (V) is 2.135m/s (to 3 significant figures)
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how do you convert micrometer to killometer
Answers
Answer:
1 x 10^-9 kilometers
Hope this helps
Have a good day :)
Explanation:
Which of the following statements regarding work and retirement is true?
Answers
The statement regarding work and retirement that is true is that most older Americans say they would prefer to enter retirement gradually.
What is retirement?Retirement is defined as the time in an individuals life that such leaves the Labour market or the workforce.
In some countries such as the United States of America, most elderly citizen prefer taking retirement process slowly.
Therefore, the statement regarding work and retirement is that retirement is a gradual process which one starts to process while actively in service
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You do 32 joules of work using a pair of scissors. The scissors do 25 joules of
work cutting a piece of fabric. What is the efficiency of the scissors?
Answers
Answer:
Efficiency = 65%
Explanation:
The formula of Efficiency applied to any circumstance is:
Efficiency = Useful Energy / Energy applied
Then replacing the values given its:
Efficiency = 25 J / 32 J
Efficiency = 0.65
0.65 written as percentage is 65%, then:
Efficiency = 65%
As you do 32 joules of work using a pair of scissors and the scissors do 25 joules of work cutting a piece of fabric, the efficiency of the scissors is 78.125%.
What is efficiency?
Efficiency is the proportion of work done by a machine or throughout a process to the overall amount of energy or heat used.
The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.
Mathematically,
efficiency of a machine = (work output/work input)×100%
Given parameters:
Input work to the pair of scissors= 32 joules.
Output work from the pair of scissors= 25 joules.
Hence,
The efficiency of a machine = (work output/work input)×100%
= ( 25 joule/32joule)×100%
= 78.125%
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The total mechanical energy of a system as a function of time is shown in the graph. Which of the following statements is true regarding the system?
A
The system should be classified as a closed system because the total mechanical energy lost from t = 3 s tot = 5s was gained from
t = 6 s to t = 9 s.
B
The system should be classified as an open system because mechanical energy can be added and removed from the system.
с
The system should be classified as an open system because the curve in the graph is symmetrical.
D
The system should be classified as a closed system because the system's total mechanical energy does not change from t = 0s to t = 10 s.
Answers
Answer: B
Explanation: A system is a closed system only if mechanical energy is constant. Because the graph showed the mechanical energy decreased before increasing again, it is not constant, even though the energy is equal at the end of the graph.
An electric iron is Mark 120 volts and 500 Watts to units consumed by it in using it for 24 hours will be
Answers
An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I
Using the above formula, we can find the current drawn by the electric iron as follows:I = P/VI = 500/120I = 4.17 ATherefore, the power consumed by the electric iron in 24 hours is:P = VI x tP = 120 x 4.17 x 24P = 120 x 100.08P = 12010.56 watt-hoursTo convert watt-hours to kilowatt-hours, we divide by 1000: Energy consumed = 12010.56 / 1000Energy consumed = 12.01 kWhHence, the units consumed by the electric iron in 24 hours is 12.01 kilowatt-hours.For such more question on Voltage
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Texas has 4,015,000 beef cows in 2013. If one cow produced approx 209g of methane per day. How much methane was produced by the beef cows in Texas in 2013
Answers
Answer:
306,284,275,000
Explanation:
If 209g was made by 1 cow you would multiply 209 by 4,015,000 and if you are trying to find how much was made in a year get that number and multiply it by 365.
What is the magnitude of the electric field at a point 0.0075 m from a 0.0035
C charge?
Use E-
kq
and k - 9.00 x 10° N.m²/C2.
A. 1.9 x 1010 N
B. 4.2 x 10' N
O c. 5.6 x 1011 N
D. 5.5 x 1012 N
Answers
Explanation:
E = 9×10^9 × 0.0035 /(0.0075)²
= 9×10^9 × 3.5×10`³/(7.5×10`³)²
= 31.5×10^6 /(56.25 ×10^-6)
= 0.56 × 10^12
= 5.6 × 10^11 N/C (option C)
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?
Answers
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point , the heat of fusion of the substance is 548 joules .
What is heat of fusion ?Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.
Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.
q = m×∆Hf
q: Total change in heat energy (in Joules)
∆Hf: Heat of fusion of substance (in Joules per gram)
m: Mass of substance (in grams)
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/ Assignment 01 Science teachers think practical science is a good thing. a. Agree b. Disagree c. Uncertain
Answers
It is reasonable to conclude that science teachers generally agree that practical science is beneficial. Therefore, option (A) is correct.
Practical science refers to hands-on activities, experiments, and applications of scientific concepts in real-world settings. Science teachers, who are experts in their field and experienced in teaching science, understand the importance of practical science in facilitating students' understanding, engagement, and application of scientific principles.
Practical science allows students to develop critical thinking, problem-solving, and inquiry skills, as well as promoting a deeper understanding of scientific concepts. It also fosters curiosity, creativity, and a passion for science, making it an effective and essential component of science education.
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A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you. Which direction does the force on the wire point?
A. Down
B. Up
C. Left
D. Right
Answers
Explanation:
To determine the direction of the force on the wire, we can use the right-hand rule for the cross product of two vectors. The force on the wire is given by:F = I * L x Bwhere I is the current, L is the length of the wire, and B is the magnetic field.
If we point our right-hand thumb in the direction of the current (to the right), and our fingers in the direction of the magnetic field (away from us), then our palm will point in the direction of the force.
So, using the right-hand rule, we can see that the force on the wire will be directed downward. Therefore, the correct answer is A. Down.How will the positions of the police car and the truck compare when they have the same speed and why?
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Answer:
Two cars of equal weight and braking ability are travelling along the same road but combined with other factors it could mean the difference between life.