In the equation:
2h2 + o2 + 2h2o

a. 1 l of hydrogen reacts with 2 l of oxygen
b. 1 l of hydrogen reacts with 22.4 l of oxygen.
c. 22.4 l of hydrogen react with 1 l of oxygen
d. 2 l of hydrogen react with 1 l of oxygen

Answers

Answer 1

In the equation 2h2 + o2 + 2h2o, the two hydrogen molecules (H2) react with one oxygen molecule (O2) to form two molecules of water (H2O). This reaction is known as combustion and it requires a certain ratio of hydrogen to oxygen in order for the reaction to take place.

Here correct answer is D)

In this equation, the ratio of hydrogen to oxygen is 2:1. This means that for every one liter of hydrogen, two liters of oxygen are needed in order for the reaction to take place.

In answer to the questions, a) one liter of hydrogen would react with two liters of oxygen, b) one liter of hydrogen would react with 22.4 liters of oxygen, c) 22.4 liters of hydrogen would react with one liter of oxygen, and d) two liters of hydrogen would react with one liter of oxygen.

This equation is a great example of the law of conservation of mass, as the total number of atoms on each side of the equation remain the same

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Related Questions

What is the molar concentration (molarity) of a solution made by dissolving 0.340 moles of CaCl2 (s) in just enough water to form 1.7 liters of solution
a. 5.0 M b. 0.20 M c. 0.58 M d. 0.34 M

Answers

Option (b) is the correct answer. The molar concentration (molarity) of a solution made by dissolving 0.340 moles of CaCl₂ (s) in just enough water to form 1.7 liters of the solution is 0.20 M.

This can be determined using the formula:

Molarity = moles of solute/liters of solution.

In this case, 0.340 moles of CaCl₂ (s) is dissolved in 1.7 liters of solution, so the molarity is:

0.340 / 1.7 = 0.20 M.

Molarity is an important concept in chemistry. It is a measure of the number of moles of a substance dissolved in one liter of solution. In the case of this question, the molarity of the solution is 0.20 M, which means that there are 0.20 moles of CaCl₂ (s) dissolved in one liter of the solution.

In chemistry, molarity is often used to determine the concentration of a solution. The higher the molarity, the higher the concentration of the solute in the solution. For example, a 0.58 M solution of CaCl₂ (s) would be more concentrated than a 0.20 M solution.


To summarize, the molarity of the given solution is 0.20 M.

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A radioactive isotope has an activity of 9.60 mCi. After 3.75 hours the activity is 7.39 mCi. What is the half-life of the isotope

Answers

For a radioactive isotope has an activity of 9.60 mCi.  , the half-life of the isotope is mathematically given as

t0.5 = 23893 s

What is the half-life of the isotope?

Generally, the equation for the half-life  is mathematically given as

t0.5=T*0.693

Where

A = A0 e^(-t/T)

t/T = lnA0/A

3.75 hours/T=ln 9.60/7.39

T = 34478.5 s

Therefore

t1/2 = TX0.693

t0.5 = 23893 s

In conclusion, the half life

t0.5 = 23893 s

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salt is often used to melt ice on roads during the winter because it lowers the freezing/meltingpoint of water. when salt dissolves in water, individual na and cl- ions break away from thesalt crystal and become surrounded by water molecules. why would this cause ice to melt?

Answers

When the salt is dissolved in water, the melting point of ice is lowered by the presence of salt in the water and encourages it to melt.  it separates into Na+ and Cl- ions.

These ions disintegrate the hydrogen bonds holding together the water molecules that give ice its solid structure. The ice melts and transforms into liquid water when the ions break the hydrogen bonds, which lowers the energy of the water molecules. The ice will melt at a lower temperature than it would without the salt because the freezing point of water is lower when ions are present. The salt also causes the ice's surface tension to break down and lowers the energy required for the molecules to move, both of which promote melting. Consequently, the melting point of ice is lowered by the presence of salt in the water and encourages it to melt.

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The Liquified Petroleum Gas (LPG) has the composition of 60% Propane (C 3
​ H 8
​ ) and 40% Butane (C 4
​ H 10
​ ) by volume: (a) Find the wet volumetric and gravimetric analysis of the products of combustion when the equivalence ratio (Φ)=1.0. (b) What is the stoichiometric air to fuel ratio for the LPG.

Answers

(a) To find the wet volumetric and gravimetric analysis of the products of combustion when the equivalence ratio (Φ) is 1.0, we need to consider the stoichiometry of the combustion reaction for propane (C₃H₈) and butane (C₄H₁₀).

The balanced combustion reaction for propane can be represented as:
C₃H₈ + (5/2)O₂ → 3CO₂ + 4H₂O

And the balanced combustion reaction for butane can be represented as:
C₄H₁₀ + (6.5)O₂ → 4CO₂ + 5H₂O

Since LPG is composed of 60% propane and 40% butane by volume, we can calculate the wet volumetric and gravimetric analysis based on these proportions.

Wet volumetric analysis:
For the wet volumetric analysis, we consider the volume of the products of combustion relative to the volume of the LPG consumed.

Propane (C₃H₈):
The stoichiometric coefficient of propane in the combustion reaction is 3. Therefore, for every mole of propane burned, we will have 3 moles of CO₂ and 4 moles of H₂O formed.

Butane (C₄H₁₀):
The stoichiometric coefficient of butane in the combustion reaction is 4. Therefore, for every mole of butane burned, we will have 4 moles of CO₂ and 5 moles of H₂O formed.

Considering the initial composition of 60% propane and 40% butane by volume, we can calculate the volumetric composition of the products of combustion:

Volumetric composition of CO₂:
(0.6 * 3) + (0.4 * 4) = 3.6

Volumetric composition of H₂O:
(0.6 * 4) + (0.4 * 5) = 4.6

Therefore, the wet volumetric analysis of the products of combustion is 3.6 parts CO₂ to 4.6 parts H₂O.

Wet gravimetric analysis:
For the wet gravimetric analysis, we consider the mass of the products of combustion relative to the mass of the LPG consumed.

Using the molar masses of the compounds involved in the combustion reaction:
Molar mass of CO₂ = 44 g/mol
Molar mass of H₂O = 18 g/mol

Gravimetric composition of CO₂:
(0.6 * 3 * 44 g/mol) + (0.4 * 4 * 44 g/mol) = 158.4 g

Gravimetric composition of H₂O:
(0.6 * 4 * 18 g/mol) + (0.4 * 5 * 18 g/mol) = 74.4 g

Therefore, the wet gravimetric analysis of the products of combustion is 158.4 grams CO₂ to 74.4 grams H₂O.

(b) The stoichiometric air to fuel ratio for LPG can be determined based on the balanced combustion equations for propane and butane.

For propane (C₃H₈):
C₃H₈ + (5/2)O₂ → 3CO₂ + 4H₂O

The stoichiometric coefficient for propane is 1, which means we need 5/2 moles of O₂ for every mole of propane.

For butane (C₄H₁₀):
C₄H₁₀ + (6.5)O₂ → 4CO₂ + 5H₂O

A steel cylinder with a moving piston on top is filled with helium (He) gas. The force that the piston exerts on the gas is constant, but the volume inside the cylinder doubles, pushing the piston up.

Which is the cause for the change?

A. The helium atoms increased in size.
B. The density of the helium atoms decreased.
C. The temperature increased.
D. The pressure decreased.

Answers

Answer: B. The density of the helium atoms decreased.

Explanation:

T or F? Kinetic energy is energy that performs

Answers

Answer:

false

Explanation:

Answer:

True

Explanation:

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

Which statement best describes the distances between planets in the solar system?

1. It has varying distances with no specific pattern.
2. It stays the same for all planets in the solar system.
3. It increases the farther you move from the sun.
4. It decreases the farther you move from the sun.

Answers

Answer:

4

Explanation: it has less gravity

The distances between planets in the solar system increases the farther one move from the sun. The correct option is 3.

What is a solar system?

The Solar System is comprised of the Sun as well as the objects that orbit it. It was composed by the gravitational collapse of a massive interstellar molecular cloud nearly 4.6 billion years ago.

The Sun encompass the vast majority of the system's mass, along with Jupiter holding the maximum of the remaining mass.

Astronomical units (AU) are a crucial unit of measurement in the solar system.

One AU is the distance between the Sun and Earth's orbit, which is approximately 93 million miles.

An accurate representation of the Solar System shows that the planets' orbits become farther apart as their distance from the Sun increases.

Thus, the correct option is 3.

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1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).

What was the temperature of the iron before it was heated?

55 °C
55 °C

35 °C
35 °C

45 °C
45 °C

20 °C

Answers

Answer:

45 °C.

Explanation:

From the question given above, the following data were obtained:

Heat (Q) = 1125 J

Mass (M) = 250 g

Final temperature (T₂) = 55 °C

Specific heat capacity (C) = 0.45 J/gºC

Initial temperature (T₁) =?

The initial temperature of the iron can be obtained as illustrated below:

Q = MC(T₂ – T₁)

1125 = 250 × 0.45 (55 – T₁)

1125 = 112.5 (55 – T₁)

Divide both side by 112.5

1125/112.5 = 55 – T₁

10 = 55 – T₁

Collect like terms

10 – 55 = –T₁

–45 = –T₁

Multiply through by –1

45 = T₁

T₁ = 45 °C

Therefore, the initial temperature of the iron is 45 °C

a chemistry student adds a quantity of an unknown solid compound to of distilled water at . after minutes of stirring, all of the has dissolved. the student then drains off the solution and evaporates the water under vacuum. a precipitate is left behind. the student washes, dries and weighs the precipitate. it weighs .

Answers

Based on the information given, it seems that the unknown solid compound was soluble in water at room temperature.

After stirring for some time, all of the compound dissolved in the distilled water. The solution was then drained off and the water was evaporated under vacuum. This caused the compound to precipitate out of the solution and form a solid. The solid was then washed, dried, and weighed to determine its mass. It's possible that this process was used to isolate and purify the compound from impurities or other substances in the original sample. The final weight of the precipitate will depend on the initial quantity of the unknown solid that was added to the distilled water.

A chemistry student added an unknown solid compound to distilled water at a specific temperature. After a certain period of stirring, the compound completely dissolved. The student then separated the solution and evaporated the water under vacuum. This process resulted in a precipitate, which the student washed, dried, and weighed. The weight of the precipitate was recorded, helping to identify the unknown compound and its properties through this experimental procedure.

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How and why masks work (3 paragraphs)

Answers

Is this a real question ?

an air mattress is filled with 0.55 moles of air. the air inside the mattress has a temperature of 295 K and an absolute pressure of 3.5 kilopascals , what is the volume of the air mattress

Answers

Answer:

Explanation:Using the equation, PV=nRT, you can solve this problem.

P= 3.5 kPa V=? n= 0.55 moles of air T= 295K R= 8.314 (L kPa/mol K)

We use the constant rate of 8.314 because we are using kilopascals in this problem.

Using simple algebra we get-

V = (0.55 moles)(8.314 L kPa/mol k)(295 K) / 3.5 kPa

Using the calculator, we would get the answer of 385.4132857 L.

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 liters.

1.37 gram of cupric oxide on reduction with hydrogen gas gives 1.098gram of copper and in next experiment 1.17 gram of copper produce 1.476gram of copper oxide illustrate this satisfy law of definite proportion

Answers

Answer: This satisfies the law of definite proportion or constant proportion and it can be proven below.

Explanation:

The law of constant or definite proportion states that all pure samples of the same compound no matter how they are made; are made up of the same elements combined in the same proportion by mass. The can be verified by finding the ratio of copper to oxygen in the both experiment listed above.

In the first experiment:

1.37 g of cupric oxide contains 1.098 g copper therefore oxygen = 1.37 − 1.098

=0.272 g

The ratio of copper to oxygen is=

1.098 ÷ 0.272

= 4:1

In the SECOND or next experiment:

1.476 g of cupric oxide contains 1.17 g copper Therefore oxygen = 1.476−1.17

=0.306g

The ratio of copper to oxygen is =

=1.176 ÷ 0.306

=3.8:1

Which is approximately≃4:1.

In conclusion, despite the different methods of the experiments, composition of copper of copper in the two different samples are the same and the cupric oxide obtained from different sources contain the same elements ( copper and oxygen) combined in the SAME ratio.

write balanced equations for each of the processes described below. (use the lowest possible coefficients. omit states-of-matter.)

Answers

1.  Balanced equation for the combustion of propane: \(C_3H_8 + 5O_2\ - > 3CO_2 + 4H_2O.\)

2. Balanced equation for the reaction between hydrochloric acid and sodium hydroxide:\(HCl + NaOH\ - > NaCl + H_2O.\)

3. 3. Balanced equation for the decomposition of calcium carbonate upon heating: \(CaCO_3\ - > CaO + CO_2.\)

1. \(C_3H_8 + 5O_2\ - > 3CO_2 + 4H_2O.\)

This reaction shows that propane\((C_3H_8)\) reacts with oxygen\((O_2)\) from the air to produce carbon dioxide\((CO_2)\) and water\((H_2O)\) in a balanced chemical equation.

2. \(HCl + NaOH\ - > NaCl + H_2O.\)

This reaction demonstrates that hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to produce sodium chloride (NaCl) and water \((H_2O)\) in a balanced chemical equation.

3. \(CaCO_3\ - > CaO + CO_2\).

This reaction illustrates that when calcium carbonate\((CaCO_3)\) is heated, it decomposes to produce calcium oxide (CaO) and carbon dioxide \((CO_2)\) in a balanced chemical equation.

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--The complete Question is, Write balanced equations for each of the processes described below:

1. Combustion of propane (C3H8) in air to produce carbon dioxide and water.

2. Reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) to produce sodium chloride (NaCl) and water (H2O).

3. Decomposition of calcium carbonate (CaCO3) upon heating to produce calcium oxide (CaO) and carbon dioxide (CO2). --

If you want a solution that is 0.100m in ions, how many grams of Na2SO4 must you dissolve in 125g of water

Answers

Total, 1.78 grams of sodium sulfate must be dissolved in 125g of water to obtain a solution that is 0.100 M in ions.

To calculate the number of grams of Na₂SO₄ that must be dissolved in 125g of water to obtain a solution that is 0.100 M (molar) in ions, we need to consider the molar mass of Na₂SO₄ and the volume of the resulting solution.

Given;

Desired concentration = 0.100 M

Mass of water = 125g

Calculate number of moles of water using by its molar mass.

Molar mass of water (H₂O) = 2(1.01 g/mol) + 16.00 g/mol = 18.02 g/mol

Number of moles of water = Mass of water / Molar mass of water = 125g / 18.02 g/mol ≈ 6.94 mol

Determine the volume of the resulting solution in liters using the density of water.

Density of water ≈ 1g/mL ≈ 1g/cm³

Volume of water = Mass of water / Density of water

= 125g / 1g/mL = 125 mL = 0.125 L

Calculate the desired number of moles of Na₂SO₄ using the desired concentration and volume of the solution.

Desired concentration = Number of moles of Na₂SO₄ / Volume of solution

Number of moles of Na₂SO₄ = Desired concentration × Volume of solution = 0.100 M × 0.125 L = 0.0125 mol

Determine the mass of Na₂SO₄ using its molar mass.

Molar mass of Na₂SO₄ = 22.99 g/mol (Na) × 2 + 32.06 g/mol (S) + 16.00 g/mol (O) × 4 = 142.04 g/mol

Mass of Na₂SO₄ = Number of moles of Na₂SO₄ × Molar mass of Na₂SO₄= 0.0125 mol × 142.04 g/mol = 1.78 grams

Therefore, approximately 1.78 grams of Na₂SO₄ must be dissolved in 125g of water to obtain a solution that is 0.100 M in ions.

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URGENT! Please help! Hi, I have to do a titration lab report using the Royal Society of Chemistry online titration lab. Please help me answer the following questions using the observation table I think?

URGENT! Please help! Hi, I have to do a titration lab report using the Royal Society of Chemistry online
URGENT! Please help! Hi, I have to do a titration lab report using the Royal Society of Chemistry online

Answers

Answer:

I'm sorry, but I cannot see the observations or the data table you mentioned in your question. However, I can still provide you with some general guidance on how to approach the calculations and answer the questions based on the given information.

4. To calculate the concentration of the NaOH solution, you need to know the mass of NaOH used and the volume of the solution. The formula to calculate concentration is:

Concentration (in mol/L) = (Mass of NaOH (in grams) / molar mass of NaOH) / Volume of solution (in L)

Make sure to convert the mass of NaOH to moles by dividing it by the molar mass of NaOH. The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).

5. The balanced equation for the neutralization reaction between NaOH and HCl is:

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

(aq) represents an aqueous solution, and (l) represents a liquid.

6a. To calculate the average concentration of HCl in the sample from site B, you need to know the volumes and concentrations of the NaOH and HCl solutions used in the titration. Use the formula:

Concentration of HCl (in mol/L) = (Volume of NaOH solution (in L) * Concentration of NaOH (in mol/L)) / Volume of HCl solution (in L)

Multiply the volume of NaOH solution used by its concentration to find the amount of NaOH used. Then, divide this amount by the volume of HCl solution used to find the concentration of HCl.

6b. To determine the pH of the water at site B, you need to know the concentration of HCl from the previous calculation. The pH can be calculated using the formula:

pH = -log10[H+]

Since HCl is a strong acid, it dissociates completely into H+ ions. Therefore, the concentration of H+ ions is equal to the concentration of HCl. Take the negative logarithm (base 10) of the H+ concentration to find the pH.

To check if the water is safe, compare the calculated pH value to the range provided (pH 4.5-7.5). If the pH falls within this range, the water is considered safe for plant and animal reproduction in an aquatic environment.

6c. Use a similar calculation as in 6a to determine the average concentration of HCl in the sample from site C.

6d. Use the concentration of HCl from 6c to calculate the pH using the formula in 6b. Follow the same procedure to check if the water is safe based on the pH range.

7. To find the most current pH value for the Grand River, you can search for the latest data from reliable sources such as environmental agencies, research institutions, or government websites. Compare this pH value to the pH values obtained in the experiment to assess the difference between them.

Remember, without the specific data and observations, the calculations and comparisons provided here are only general guidelines. It's important to use the actual data from your experiment to obtain accurate results and conclusions.

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Which answer correctly states how a balanced chemical equation obeys the Law of Conservation of Mass?
Responses

The number of reactants must be equal to the number of products.

The formulas of the reactants must be the same as the formulas of the products.

The products must be the combination of the reactants.


The number of atoms of each element must be the same for the reactant and product sides.

Answers

Answer:

The formulas of the reactants must be the same as the formulas of the products.

Explanation:

Determine the enthalpy for this reaction: Ca(OH)2(s) CO2(g)→CaCO3(s) H2O(l).

Answers

Answer:   This is an acid-base reaction (neutralization): Ca(OH) 2 is a base, CO 2 is an acid. ; White, odorless powder. [Note: Readily absorbs CO2 from the air to form calcium carbonate.]

Explanation:

Answer:

-113.2 kJ/mol

Explanation:

(-1207-285.8)-(-981.1-393.5)= -133.2

(Products)-(Reactants)= Answer

what is a mixture of elements and compounds

what is a mixture of elements and compounds

Answers

The substance in the image above would be classified as a mixture of elements (option E).

What is a compound and mixture?

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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3. Which best explains the flow of energy in an internal combustion engine?
O
A. Work is converted into energy stored in chemical bonds.
B. The expansion of gases is used to do work.
C. Heat is converted into work to power the engine.
D. An increase in pressure is converted into heat and work.
Check Answer

Answers

An increase in pressure is converted into heat and work, explains the flow of energy in an internal combustion engine. Gasoline is ignited and consumed within an internal combustion engine (ICE) by the engine itself.

The engine then partially transforms the energy from combustion into work. The engine is composed of a fixed cylinder and a rotating piston. There are three main types of internal combustion engines in use today: the spark ignition engine, which is mainly used in automobiles; the diesel engine, which is used in heavy machinery and industrial systems and has an advantage over the more compact and lighter ones due to improvements in cycle efficiency.

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G What two carbonyl compounds are needed to synthesize each of the following compounds, using a Robinson annulation? Part A A line-angle formula shows a ring with six vertices and a double bond between the second (clockwise) and the third vertices. An oxygen atom is double-bonded to the first vertex. A COCH3 group, whose first (from left to right) carbon is double-bonded to an oxygen atom, is attached to the fourth vertex

Answers

According to a given scenario in the question, A cyclic ketone, such as cyclohexanone, and an,-unsaturated carbonyl molecule, such as acrolein, are needed to perform a Robinson annulation to create

4-methylcyclohexane-1-carboxaldehyde.

A strong base, such as sodium ethoxide, is used to treat the cyclic ketone in the Robinson annulation in order to produce an enolate ion. The -carbon of the enolate and the -carbon of the unsaturated carbonyl compound subsequently create a new carbon-carbon bond as a result of the enolate ion's nucleophilic addition to the,-unsaturated carbonyl molecule. The desired product, in this case, 4-methylcyclohexane-1-carboxaldehyde, is produced by protonating the ensuing intermediate.

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--The complete Question is, What two carbonyl compounds are required to carry out a Robinson annulation to synthesize 4-methylcyclohexane-1-carboxaldehyde? --

BRAINLIEST
How many DIFFERENT elements are involved in the equation shown below?

BRAINLIESTHow many DIFFERENT elements are involved in the equation shown below?

Answers

Answer:

5

Explanation:

The elements contained in this equation are:

Na

Cl

H

S

O

How many mL of 3,0 M HNO₂ can be completely
neutralized by 75 mL of 1.5 M Mg(OH)2 solution?

Answers

Answer: approximately 18.75 mL of 3.0 M HNO₂ solution can be completely neutralized by 75 mL of 1.5 M Mg(OH)₂ solution.

Explanation:

To determine the volume of 3.0 M HNO₂ solution that can be neutralized by 75 mL of 1.5 M Mg(OH)₂ solution, we can set up an equation based on the stoichiometry of the balanced chemical equation.

The balanced chemical equation for the neutralization reaction between HNO₂ and Mg(OH)₂ is:

2 HNO₂ + Mg(OH)₂ → Mg(NO₂)₂ + 2 H₂O

From the equation, we can see that it takes two moles of HNO₂ to react with one mole of Mg(OH)₂.

First, let's calculate the number of moles of Mg(OH)₂ present in 75 mL of 1.5 M solution:

Number of moles of Mg(OH)₂ = Volume (in L) × Concentration (in mol/L)

= 75 mL × (1 L / 1000 mL) × 1.5 mol/L

= 0.1125 mol

Since the stoichiometry ratio is 2:1 (HNO₂:Mg(OH)₂), we can conclude that 0.1125 moles of Mg(OH)₂ can neutralize 0.1125/2 = 0.05625 moles of HNO₂.

Now, let's determine the volume of 3.0 M HNO₂ required to contain 0.05625 moles:

Volume (in L) = Number of moles / Concentration (in mol/L)

= 0.05625 mol / 3.0 mol/L

≈ 0.01875 L

Finally, we convert the volume from liters to milliliters:

Volume (in mL) = Volume (in L) × 1000

≈ 0.01875 L × 1000

≈ 18.75 mL

in an aqueous solution, classify these compounds as strong acids, weak acids, strong bases, weak bases, or other.

Answers

Weak acids;

\(CH_{3} COOH\\HF\\H_{2} CO_{3}\)

Weak base;

\((CH_{3}) _{3} N\\NH_{3}\)

Strong acid;

\(HCl\\HNO_{3}\)

Strong base;

LiOH

\(Ba(OH)_{2}\)

Other;

NaCl

What is a weak acid?

We know that a weak acid is an acid that does not dissociate completely in solution. On the other wand, a weak base is a base that does not dissociate completely in solution.

A strong acid is the kind of acid that would be completely dissociated when we dissolve it in aqueous solution while a strong base is a base that would dissociate completely if we dissolve it in solution.

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in an aqueous solution, classify these compounds as strong acids, weak acids, strong bases, weak bases,

Using the following electronegativity values:
C 2.5 CI 3.0 H 2.1 O 3.5 select from the following group the molecule that fits the given statement:
a) CH3CHO b) CO2 c) CH3CI
d) C2H6
e) none

Answers

\(CH_{3}CHO\) molecule shows the smallest number of lone pairs in its lewis structure.

The structure is attached below.

A is the correct answer.

A Lewis Structure is a greatly condensed illustration of a molecule's valence shell electrons. It is used to display how the electrons are positioned around particular molecules' atoms. When two atoms are bonded together, electrons are depicted as 'dots' or as a line.

Lewis structures, often referred to as Lewis dot formulas, electron dot structures, or Lewis electron dot structures, are diagrams that depict the interactions between the atoms in a molecule as well as any lone pairs of electrons that may be present.

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The complete question is:

select from the following group the molecule that fits the given statement: This molecule shows the smallest number of lone pairs in its lewis structure.

a) CH3CHO

b) CO2

c) CH3CI

d) C2H6

e) none

Using the following electronegativity values:C 2.5 CI 3.0 H 2.1 O 3.5 select from the following group
Using the following electronegativity values:C 2.5 CI 3.0 H 2.1 O 3.5 select from the following group
Using the following electronegativity values:C 2.5 CI 3.0 H 2.1 O 3.5 select from the following group

Rising greenhouse gases. Climate change. Rising energy costs. Declining fossil fuels reserves. With the arguments against fossil fuels continuing to pile up it is no wonder people have latched onto nuclear power as an attractive solution....

1. What is nuclear fission? ________________________________________________________________________________
2. What is nuclear fusion? ________________________________________________________________________________
3. What happens when the energy from splitting an atom is released all at once? _____________________________________
4. What element is used in nuclear power plants as fuel? ________________________________________________________
5. What dangerous byproduct is produced by nuclear power plants? _______________________________________________
6. Describe THREE benefits of using nuclear power: ___________________________________________________________, _____________________________________________________, and __________________________________________
7. What is the function of the cooling towers of the nuclear reactor shown below? _____________________________________

Answers

Answer:

Nuclear Fission is a nuclear reaction or a Radioactive decay progress in which the necleus of an atom splits into two or more smaller, lighter neclei

hydrogen gas and nitrogen gas react to form ammonia gas. what volume of ammonia would be produced by this reaction if 1.01 l of hydrogen were consumed? also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits.

Answers

The volume of ammonia that would be produced by the reaction if 1.01 l of hydrogen were consumed is 0.673L.

The balanced chemical equation for the reaction is:

N₂ + 3H₂(g) -> 2NH₃(g)

From the equation, we can see that 3 moles of hydrogen react with 1 mole of nitrogen to produce 2 moles of ammonia.

First, we need to calculate the number of moles of hydrogen present in 1.01 L. We can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Assuming standard temperature and pressure (STP), which is 0°C (273.15 K) and 1 atm (101.325 kPa), the ideal gas law becomes:

n = PV/RT

n = (1 atm)(1.01 L)/(0.0821 L·atm/mol·K)(273.15 K)

n = 0.045037 mol

Next, we can use the mole ratio from the balanced chemical equation to calculate the number of moles of ammonia produced:

(2 mol NH₃ / 3 mol H₂) x 0.045037 mol H₂ = 0.0300 mol NH₃

Finally, we can use the ideal gas law again to calculate the volume of ammonia produced:

V = nRT/P

V = (0.0300 mol)(0.0821 L·atm/mol·K)(273.15 K)/(1 atm)

V = 0.673 L

Therefore, 0.673 L of ammonia would be produced if 1.01 L of hydrogen were consumed in the reaction.

The answer is rounded to 3 significant digits.

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when 2-pentanone is treated with naoh, two products are formed. draw the structure of the product that contains one chiral center.

Answers

When 2-pentanone (also known as methyl propyl ketone) reacts with NaOH (sodium hydroxide), it undergoes nucleophilic addition and subsequent dehydration to form two possible products: 3-pentanol and 2-pentene. The product that contains one chiral center is 3-pentanol.

How does Aldol Condensation give different products?

The product that contains one chiral center is formed by Aldol condensation.

1. 2-pentanone is deprotonated by NaOH, resulting in the formation of an enolate ion.
2. The enolate ion attacks another molecule of 2-pentanone at the carbonyl carbon, creating a new carbon-carbon bond.
3. A hydroxide ion from NaOH then protonates the oxygen of the newly formed alkoxide ion.
4. The product formed is a β-hydroxy ketone, which contains one chiral center.

The structure of the product containing one chiral center is:

  O
  ‖
H3C-C-CH2-CH(OH)-CH3

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Consider that Fe3+ is a d5 metal center. If it is surrounded by weak-field ligands in an octahedral configuration, how many electrons are in the lower three and upper two metal orbitals, respectively.
A. 3,2
B. 2,3
C. 5,0
D. 1,4

Answers

The correct answer is 3, 2. If Fe3+ is surrounded by weak-field ligands in an octahedral configuration, there will be 3 electrons in the lower three metal orbitals and 2 electrons in the upper two metal orbitals. So, the correct option is A.

An octahedral complex is a complex where the coordination sphere of a central metal ion is composed of six ligands that are located at the corners of an imaginary octahedron. The octahedral arrangement of six ligands is the most common coordination mode. The configuration of the eight corners of an octahedron is made up of six ligands, with the metal center located at the center.

The d5 electron configuration for Fe3+ is t2g3eg2, which is filled according to Hund’s rule with the lower-energy orbitals being filled first. According to the weak-field ligand hypothesis, the t2g orbitals will be relatively unaffected in energy, whereas the eg orbitals will be significantly raised in energy.

As a result, the three electrons in the t2g orbitals will occupy the lower-energy orbitals, while the two electrons in the eg orbitals will occupy the higher-energy orbitals. As a result, there will be 3 electrons in the lower three metal orbitals and 2 electrons in the upper two metal orbitals. The correct option is A. 3, 2.

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A weather map of Chicago with a high pressure system and warm front. Based on the weather map, what might the upcoming weather be like in Chicago? Warm, dry, clear skies Warm, humid, possible thunderstorms Cold, dry, clear skies Cool, humid, possible thunderstorms.

Answers

A weather map of Chicago with a high pressure system and warm front, so the upcoming weather be Warm, dry, clear skies in Chicago.

What is high pressure of air?

High pressure of air tries to compress the gas from upper atmosphere to lower atmosphere.

When any gas has high pressure then it sinks towards the land from the upper atmosphere, and at the upper part air gets cool and form water vapor. When air comes towards the land then, it becomes warm and dry as it doesn't participate in the formation of precipitate. Due to which we are able to see clear sky at the dry days.

Hence, option (1) is correct i.e. Warm, dry, clear skies are the upcoming weather.

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Answer:

A. Warm, dry, clear skies

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A weather map of Chicago with a high pressure system and warm front. Based on the weather map, what might

Make a He atom with a mass of 4. How many protons did you put in the nucleus?

Make a Li atom with a mass number of 7. How many electrons did you place in the outermost orbital (ring)?

Make a N atom with a mass number of 14. How many neutrons are in the nucleus?

Make a B atom with a mass number of 11. How many electrons did you put in the second orbital (ring)?

Answers

Answer:

He has two protons

Li electron has one electron in its outermost orbital.

Number of neutrons of nitrogen = seven neutrons

The second shell of boron: 3 electrons.

Explanation:

An atom is composed of electrons, protons and neutrons. The number of neutrons is determined by subtraction of the atomic number from the mass number.

The electronic configuration is already known for each of atoms in these questions according to standard tables.

Answer:

1.) Make a He atom with a mass of 4. How many protons did you put in the nucleus?

2

2.) Make a Li atom with a mass number of 7. How many electrons did you place in the outermost orbital (ring)?

1

3.) Make a N atom with a mass number of 14. How many neutrons are in the nucleus?

7

4.) Make a B atom with a mass number of 11. How many electrons did you put in the second orbital (ring)?

3

Explanation:

Did it on Edgenuity and got it correct (2020).

Make a He atom with a mass of 4. How many protons did you put in the nucleus? Make a Li atom with a mass
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