Answer:
Graphing the momentum against the change in moment yields a linear relationship.
Explanation:
This is an impulse experiment,
I = ∫ F .dt
where the force and time of the collision are measured, therefore if we assume an average force the integral reduces to
I = F t
Furthermore, the momentum is equal to the change in moment of the ball, this change in moment can be found using the energy relations measuring the height of the ball and calculating its speed, in the two intervals for the descent and for the exit, possibly the heights are different so the moment change is different from zero.
Starting point. Higher
Em₀ = U = mgh
Lower end point, just before hitting the scale
\(Em_{f}\) = K = ½ m v²
in the path in the air there is no friction
Em₀ = Em_{f}
m g h = ½ m v²
v = \(\sqrt{2gh}\)
this height is different for the descent and ascent of the ball, so we have two moments
Δp = \(p_{f}\) - p₀
Δp = m (v_{f} -v₀)
therefore we have the relationship
I = Δp
Graphing the momentum against the change in moment yields a linear relationship.
i forgot to add the number before
it’s 75 for the water
Answer:
Explain
Explanation:
PLS HELP
A marble rolls off a table with a horizontal velocity of 8 m/s and the cliff has a height of
2.71 m. How far does the marble land from the base of the table? Round your answer to
two decimal places.
Sources of error could have come from friction that may result in energy losses during the collision, The gliders may not be perfectly elastic, which means that some energy may be lost during the collision
are these errors random or systematic errors?
Sources of error could have come from small amounts of friction, and glider 2 could have not been totally at rest. These errors are systematic errors.
Are these errors random or systematic?
Answer:
The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.
The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.
Explanation:
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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Will ice melt faster in salt, sugar or water?
Answer:
Water because the salt will just make it colder and the sugar won't do anything
As the book fell through the air and eventually hit the ground,
A. potential energy was destroyed and kinetic energy was create
B. sound energy was created
C. both potential energy and kinetic energy were destroyed
D. the energies of the system were converted from one form to
another
As the book fell through the air and eventually hit the ground, the energies of the system were converted from one form to another.
Option D is correct.
What is energy?Energy is described as the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
The forms of energy includes:
Chemical energy.
Electrical Energy.
Mechanical Energy.
Thermal energy.
Nuclear energy.
Gravitational Energy.
In conclusion, When the book fell through the air and hit the ground, the potential energy it possessed due to its position above the ground was converted into kinetic energy as it accelerated towards the ground.
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Two students are at the beach studying nature and see a pod of dolphins swimming by. student 1 decides the best way to study them is by diving under the water while student 2 observes from above the water. the two students hear sounds from dolphins that are in the water and jumping above the surface the same distance from the students. based on the information below, which dolphin would the studen hear first?
v=f * A
jumping dolphin frequency: 1200 Hz
wavelength: 0.285 m
swimming dolphin
frequency: 1800 Hz
wavelength: 0.833 m
show the work
which sound reaches the shore first? Use the numbers you have calculated to support your answer.
Answer:
abdulaziz Sharif mamad
who wants to be study partnerssss for math?
Sure, that sounds great! What kind of math are we studying? Do you have any specific topics you want to focus on?
What is topic?A topic is a subject or issue that forms the basis of a discussion, paper, speech, or other form of communication. It is typically used to focus the ideas and facts presented in the communication, making it easier for the audience to understand and remember. It can be an essay, a research paper, a presentation, or any other type of communication that is intended to present and discuss a particular idea. By choosing a specific topic, the author is able to narrow down the scope of the discussion and focus on the main ideas more efficiently.
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7. State condition of equilibrium when a borly is acted upon by a number of parallel forces. A uniform metal tube of length 5cm and mass 9 kg is suspended horizontally by two vertical wire attaches at 50cm and 150cm respectively from the ends of the tuber Find the tension in each wire. in tril Solution -
According to the question the tension in each wire is 1.96 N.
What is tension?Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.
The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.
The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.
Therefore, the tension in each wire is:
T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)
= 1.96 N
Therefore, the tension in each wire is 1.96 N.
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Hello,I am a grade 10 student and I am looking for some help on physics equations (acceleration, time distance, etc). I am also looking in to calculating speed, distance and time. I am studying for an exam and I have a preparation worksheet.
ANSWER:
1.3 times faster
STEP-BY-STEP EXPLANATION:
Given:
Distance ostrich = 56 m
Time ostrich = 14.5 s
Initial velocity = 0 m/s
To calculate the final velocity of the ostrich we use the following formula:
\(\begin{gathered} d=0.5(v_f+v_i)\Delta t \\ \\ \text{ we solve for }v_f \\ \\ 56=0.5(0+v_f)14.5 \\ \\ 56=7.25v_f \\ \\ v_f=\frac{56}{7.25}=7.7\text{ m/s} \end{gathered}\)Now, we calculate the average velocity of the ostrich, like this:
\(\begin{gathered} v_o=\frac{v_i+v_f}{2}=\frac{0+7.7}{2} \\ \\ v_o=3.9\text{ m/s} \end{gathered}\)We calculate the time it would take the ostrich to travel 100 meters with the following formula:
\(\begin{gathered} d=0.5(v_{f}+v_{i})\Delta t \\ \\ \text{ we replacing} \\ \\ 100=0.5\left(0+7.7\right)\Delta t \\ \\ \Delta t=25.9\text{ sec} \end{gathered}\)now we calculate the time of the cheetah knowing that it takes 5.7 seconds less:
\(\begin{gathered} t_c=t_o-5.7 \\ \\ t_c=25.9-5.7=20.2\text{ sec} \end{gathered}\)Now, we can calculate the final velocty of the cheetah using the following formula:
\(\begin{gathered} d=0.5(v_{f}+v_{i})\Delta t \\ \\ \text{ we replacing} \\ \\ 100=0.5\left(v_f+0\right)20.2 \\ \\ v_f=\frac{100}{10.1} \\ \\ v_f=9.9\text{ m/s} \end{gathered}\)Now we calculate the average velocity, like this:
\(\begin{gathered} v_c=\frac{v_i+v_f}{2}=\frac{0+9.9}{2} \\ \\ v_c=4.95\text{ m/s} \end{gathered}\)we calculate the ratio between the two to know how many times the cheetah is faster:
\(r=\frac{4.95}{3.9}=1.3\)Therefore, the cheetah is 1.3 times faster than the ostrich.
Ackee
Ackee is a unique fruit in that it has a lot of fat, a very unusual feature for a fruit. This
has caused many persons to think that eating it may be unhealthy.
False statements like "eating ackees will increase a man's risk of prostate cancer" are
still being made, even by health professionals. On the contrary, the fruit is not only
delicious, but also a very healthy food choice.
The scientific name for our national fruit, ackee, is Blighia Sapida. Ackee was named
after Captain William Bligh, an English sailor who took the fruit from Jamaica to
England, in 1793. It is originally from West Africa. Jamaica is the only place where
the fruit is extremely popular among locals and tourists. However, it has been
introduced into most of the other Caribbean islands (for example, Trinidad, Grenada,
Antigua and Barbados) as well as Central America and Florida.
The Pan American Health Organization states that the ackee is a good source of
healthy fats and an excellent source of good fats in the Jamaican diet.
Traditionally, ackee is cooked with salt fish to produce an often oily meal.
Unfortunately, the type of oil used in cooking ackee and salt fish often contains
unhealthy fats. These 'bad' fats or excess salt in the salt fish may be responsible for the
view that ackee is bad for you. The ackee itself is a very healthy food. Today, there
are many ways to prepare healthy and tasty ackee dishes, without using cooking oils
that may be harmful.
Ackee contains no cholesterol or unhealthy fat, and I have not found any scientific
evidence to suggest that ackee causes prostate cancer.
It is important to distinguish between the health benefits of the ackee fruit itself and the potential negative health effects of the oil used in cooking it with salt fish.
Ackee is actually a healthy fruit that contains good fats, including omega-3 and omega-6 fatty acids, which are important for heart health and brain function. It is also a good source of protein, dietary fiber, vitamins, and minerals, including vitamin C, calcium, and potassium.
However, it is true that the oil used to cook ackee with salt fish can be unhealthy, depending on the type of oil used. Traditional cooking methods often involve using oils high in saturated or trans fats, which can contribute to heart disease and other health problems. To make ackee dishes healthier, it is recommended to use healthier cooking oils, such as olive oil or coconut oil, and to limit the amount of salt fish used in the dish.
Overall, ackee is a healthy and delicious fruit that can be enjoyed as part of a balanced diet. However, it is important to be mindful of how it is prepared and cooked to ensure that it is not combined with unhealthy ingredients that can detract from its nutritional value.
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If a constant force of 917 N is exerted on a scooter for 6 s, thenwhat is the change in momentum?
a 6 kg-m/s
b 5502 kg-m/s
c 917 kg-m/s
d 153 kg-m/s
Answer: 917
Explanation:
The change in momentum if a constant force of 917 N is exerted on a scooter for 6s is 5502kg-m/s.
How to calculate momentum?Momentum is the tendency of a body to maintain its inertial motion. It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities.
Force = mass x (velocity/time)
Force = (mass x velocity)/time
Force = momentum/time
According to this question, a constant force of 917 N is exerted on a scooter for 6s. The change in momentum is calculated as follows:
917N = p/6
p = 5502kg-m/s
Therefore, 5502kg-m/s is the change in momentum of the scooter.
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Help with (iii) and (iv) please:
A train consists of an engine and three trucks with masses and resistances to motion as shown in
Fig. 1. There is also a driving force of 37 000 N. All the couplings are light, rigid and horizontal.
(i) Show that the acceleration of the train is 0.3 ms2.
(i) Draw a diagram showing all the forces acting on truck Z in the line of its motion.
Calculate the force in the coupling between trucks Y and Z.
[3]
[4]
With the driving force removed, brakes are applied, so adding a further resistance of 11 000 N to
the total of the resistances shown in Fig. 1.
(iii) Calculate the new acceleration of the train.
(iv) Calculate the new force in the coupling between trucks Y and Z if the brakes are applied
(A) to the engine,
(B) to truck Z
In cach case state whether the force is a tension or a thrust.
[2]
[6]
(i) The total force acting on the train is the driving force minus the total resistance to motion. The total resistance to motion is the sum of the resistances of the three trucks. Therefore, the total force acting on the train is:
F = 37,000 N - (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s² = 37,000 N - 25,740 N = 11,260 N
The acceleration of the train is given by the formula:
a = F / (m1 + m2 + m3) = 11,260 N / (1,200 kg + 900 kg + 600 kg) = 0.3 m/s²
Therefore, the acceleration of the train is 0.3 m/s².
(ii) The forces acting on truck Z are the driving force, the force in the coupling between trucks Y and Z, and the resistance to motion of truck Z. The diagram showing all the forces acting on truck Z in the line of its motion is:
Driving force ≥ Truck Z ≤ Force in coupling Y and Z ≤ Resistance to motion of truck Z
(iii) With the driving force removed and brakes applied, the total resistance to motion is the sum of the resistances of the three trucks and the additional resistance due to the brakes. Therefore, the total resistance to motion is:
R = (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s²+ 11,000 N = 25,740 N + 11,000 N = 36,740 N
The total force acting on the train is the total resistance to motion. Therefore, the acceleration of the train is:
a = F / (m1 + m2 + m3) = 0 / (1,200 kg + 900 kg + 600 kg) = 0 m/s²
Therefore, the new acceleration of the train is 0 m/s².
(iv) When the brakes are applied to the engine, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z. Therefore, the force in the coupling between trucks Y and Z is:
F = 600 kg ² 9.8 m/s² + 11,000 N = 5,880 N + 11,000 N = 16,880 N
The force in the coupling between trucks Y and Z is a tension.
When the brakes are applied to truck Z, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z plus the resistance to motion of the engine and the trucks in front of truck Y. Therefore, the force in the coupling between trucks Y and Z is:
F = (600 kg + 900 kg + 1,200 kg) ₓ9.8 m/s² + 11,000 N = 17,640 N + 11,000 N = 28,640 N
The force in the coupling between trucks Y and Z is a thrust.
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You and your friend each drive 100.0 km. You travel at 30.0 km/h. Your friend travels at 45 km/h. How long will your friend be waiting for you at the end of the trip?.
Answer:
See below
Explanation:
100 km / 45 km/hr = 2.222 hr
100 km / 30 km/hr =3.3333 hr
Difference = 1.111 hr = 1 hr 6 2/3 min
Identify a true statement about children from lower-socioeconomic status (SES) families.
Select one:
a.
Lower-SES children have smaller vocabulary in comparison with higher-SES children.
b.
Lower-SES children exhibit fewer behavioral difficulties than do higher-SES children.
c.
Lower-SES children have more volume in the frontal cortex than do higher-SES children.
d.
Lower-SES children exhibit less aggression in comparison with higher-SES children.
Find the applied voltage of a telephone circuit that draws 0.017A through a resistance Of 5,000 ohms
A system consists of a 5.00-kg object moving down along the y-axis at a speed of 25.0 m/s, as well as an 8.00-kg object . The system has a net momentum of 35 kg∙m/s in the direction of the +y axis. What is the velocity of the 8.00-kg object? Express the direction of its velocity as a counterclockwise angle to the +x-axis.
The velocity of the object is -11.25 m/s while the direction of the angle is 66 degrees.
What is the momentum?We know that the momentum has to do with the product of the velocity and the mass of the object. Let us note that the mass of the object is a scalar quantity but the velocity of the object is a vector quantity. As such, momentum of the object is a constant.
Let us recall that the total momentum of the object is a constant and this is what we call the law of the conservation of the linear momentum of the object as we can see here.
Thus we know from the law that;
(5 * 25) + (8 * v) = 35
125 + 8v = 35
8v = 35 - 125
v = 35 - 125/8
v = -11.25 m/s
Thus, the angle can be obtained by the use of the formula;
Tan-1 ( 25.0 /11.25 )
= 66 degrees
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Calculate how fast the ball would be moving at the instant it leaves the projectile launcher of the spring is compressed by 3.75 cm. Use a value of k = 500 N/m for the spring constant, 10 g for the mass of the ball, and 75 g for the effective mass of the ball holder. Show your work.
Answer:
V = 8.34m/s
Explanation:
Given that
1/2ke^2 = 1/2mv^2 ......1
Where e = 3.75cm = (3.75/100)m
e = 0.0375m
K = 500 N/m
m = 10g = 10/1000
= 0.01kg
Substitute the values into equation 1
0.5×500×(0.0375)^2 = 0.5×0.01×v^2
250×0.001395 = 0.005v^2
0.348 = 0.005v^2
v^2 = 0.348/0.005
v^2 = 69.6
V = √69.6
V = 8.34m/s
The ball launches at the speed of V = 8.34m/s
A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its displacements and determine its resultant displacement vector by use of the diagram.
Answer:
Explanation is given
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Which branch of science studies how sound waves move through the air?
A. Life science
B. Physical science
C. Space science
D. Earth science
Answer:
B is the correct answer
Explanation:
just bc I said so:)
An object, initially at rest, is subject to an acceleration of 45 m/s^2. How long will it take that object to travel 1000m? Round to one decimal place.
Answer:
6.7 seconds
Explanation:
d=(1/2)at^2
equation
1000=(1/2)45t^2.
substitute
2000=45t^2.
multiply by 2 for both sides
44.44=t^2.
divide both sides by 45
6.7=t
take the square root of both sides
A rather unbalanced goat jumps off a the air. Evan is dressed in his parachuting outfit, 2.0-m high. How much gravitational potential cliff. The goat has a mass of 50kg and the which brings his mass to a total of 90.0 kg. The energy does the girl gain? cliff is 450 m high. What is the kinetic aircraft takes the group to a height of 5000.00 m m= 36 kg before the jump. How much GPE does Evan gain Given: h: 2.0m Asked 5P6 energy of the goat just before it hits the ground?
There are multiple questions in your prompt, so let's break them down one by one.
How much gravitational potential energy does the goat gain?
The gravitational potential energy gained by the goat can be calculated using the formula:
GPE = mgh
where m is the mass of the goat, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.
Substituting the given values, we get:
GPE = 50 kg x 9.8 m/s^2 x 450 m
GPE = 220500 J
Therefore, the goat gains 220500 J of gravitational potential energy.
How much gravitational potential energy does Evan gain?
The gravitational potential energy gained by Evan can be calculated using the same formula as above:
GPE = mgh
where m is the mass of Evan (including his parachute gear), g is the acceleration due to gravity, and h is the height of the jump.
Substituting the given values, we get:
GPE = 90 kg x 9.8 m/s^2 x 2.0 m
GPE = 1764 J
Therefore, Evan gains 1764 J of gravitational potential energy.
How much kinetic energy does the goat have just before it hits the ground?
The conservation of energy principle tells us that the total energy of the system (in this case, the goat) remains constant. So, the kinetic energy gained by the goat just before it hits the ground is equal to the gravitational potential energy it had at the top of the cliff. Therefore, the kinetic energy of the goat just before it hits the ground is:
KE = GPE = 220500 J
Note that we have assumed that there is no loss of energy due to air resistance or other factors during the goat's fall.
How much GPE does Evan gain given: h = 2.0 m
We have already calculated the gravitational potential energy gained by Evan earlier. Using the same formula, we get:
GPE = mgh
GPE = 90 kg x 9.8 m/s^2 x 2.0 m
GPE = 1764 J
What is the kinetic energy of the aircraft at a height of 5000.00 m?
We cannot calculate the kinetic energy of the aircraft with the given information. The kinetic energy of an object depends on its mass and velocity, but we only have information about its height. If we assume that the aircraft is stationary at a height of 5000.00 m, then its kinetic energy would be zero.
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The graph below shows the heating curve for a substance as it changes from solid to gas.
a. Answer the questions in the table below.
The melting point of the substance in the heating curve is 20°C.
1) The melting point of the substance is the temperature at the point where, the substance is having a phase change from solid state to liquid. So, the temperature at point B, 20°C is its melting point.
2) The boiling point of the substance is the temperature at the point where, the substance is having a phase change from liquid state to gaseous state. So, the temperature at point D, 90°C is its boiling point.
3) The point A is where the substance is at solid state.
4) The substance is at liquid state at the point C.
5) The substance is at gaseous state at the point E.
6) At point B, solid state is changing to liquid state.
7) At point D, liquid state is changing to gaseous state.
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If the error in the angle is 0.50, the error in sin 90o is
At the given erro in angle, the error in the measurement of sin 90 degrees would be 0.001.
Percentage errorThe percentage error of any measurement is obtained from the ratio of the error to the actual measurement.
The error of sin 90 degrees is calculated as follows;
sin 90 = 1
error in measurement = sin(90 - 0.5)
error in measurement = sin(89.5) = 0.999
Error in sin 90 degreesError in sin 90 degrees = 1 - 0.999
Error in sin 90 degrees = 0.001
Thus, at the given erro in angle, the error in sin 90 degrees would be 0.001.
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how does the force of gravity affects an objects acceleration
Answer:
When objects fall to the ground, gravity causes them to accelerate.
Explanation:
Gravity causes an object to fall toward the ground at a faster and faster velocity the longer the object falls.
Two objects rest on a uniform surface. A person pushes both with equal force. If the first object starts to move faster than the second, what can be said about their masses?
Question 10 options:
The mass of the first object is less than that of the second object.
No inference can be made because mass and force are not related to each other.
The mass of the first object is equal to the mass of the second object.
The mass of the first object is greater than that of the second object
Answer: The mass of the first object is less than that of the second object.
Explanation:
ΣF = ma
a = ΣF/m
Thus, given two objects acted on by the same ΣF, a is inversely proportional to m. If a is larger, m must be smaller and vice-versa.
A force directed 51.8° below the positive x-axis has an x component of 4.93 lb. Find its y component.
y= 6.26 lb.
Explanation:1. Draw the vector of the force to better visualize and understand the problem.Check attached image 1.
2. Find an expression for the force in the y axis.Using the trigonometric functions, we need to find a function that relates the angle, opposite side and adjacent side of the drawn triangle. The function that does this is the tangent.
Let theta (θ) be the angle given by the problem.
Let "y" be the missing y component.
Tangent (θ) = Opposite side (y) / Adjacent side (x)
\(Tan(tetha)=\frac{y}{x}\)
3. Solve the equation for y by multiplying both sides by x.\(Tan(tetha)*x=y\)
4. Substitute the information given by the problem and calculate y.\(Tan(51.8)*(4.93)=y\\ \\y=6.26\)
5. Express the result.
y= 6.26 lb.
use the formula P=IV to detine how much current is a 120-watt light bulb is connected to a 120-V outlet
Answer:
1 A
Explanation:
P = IV
120 W = I (120 V)
I = 1 A
An airplane flying at 119 m/s is accelerated uniformly at the rate of 0.5 m/s2 for 10
seconds. What is its final speed?
Answer:
124m/s
Explanation:
v=u+at
v=119+(0.5×10)
v=119+5
v=124m/s
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A thin 2.50 kg box rests on a 5.50 kg board that hangs over the end of a table, as shown in (Figure 1).
How far can the center of the box be from the end of the table before the board begins to tilt?
Based on the principle of moments. the distance from the end of the table should the box be placed before the board begins to tilt is 8.6 cm.
What distance from the end of the table should the box be placed before the board begins to tilt?The distance from the end of the table should the box be placed before the board begins to tilt is determined from the principle of moments as follows:
sum of clockwise moments = sum of anticlockwise momentsThe block is 30 cm on the table and 20 cm outside it.
The downward force acting on the left-hand side of the box = 3/5 x 5.50 = 3.3kg.
This force acts at the center of gravity, 15 cm or 0.15 m away.
Therefore, anticlockwise moments o the left side = 3.3 x 0.15 = 0.495 J
Also, the clockwise moment on the right side = Force * distance
Force = 2/5 x 5.5 = 2.2 N
Distance from the center of gravity = 10 cm or 0.10 m away.
the clockwise moment on the right side due to the board = 2.2 x 0.1 = 0.22.
The moment due to the box with a weight of 2.5 kg at a distance of x meters will be:
the total clockwise moment on the right side = 0.28 + 2.5 * x.
When the board is just about to tilt:
0.495 = 0.28 + 2.5 * x
2.5x = 0.495 - 0.28
x = 0.086 m or 8.6 cm
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