In the picture below, the boy is holding the girl up on a see-saw. What does the girl need to do to make the see-saw balance?Select one:a. Move farther back on her end of the see-saw.b. Move closer to the fulcrum.c. Ask the boy to move back.d. There is no way the see-saw can be balanced.
Answers
Explanation
Step 1
Diagram:
in this case, the torque made by the boy is greater, so
\(200*d_1>160*d_2\)therefore, the make the see-same balanced the girl need have a greater torque
\(T=force\text{ *distance}\)in this case, the force is the weigth of the girl, as she can not change her weigth to have a greater torque,she needs a greater length to the fulcrum, hence
Move farther back on her end of the see-saw.
Related Questions
Determine the amount of power
used in holding a 25 kg box, 1.5
meters above the floor, for 60
seconds.
[?] W
(answer is not 6.13)
Thank you in advance!
![Determine the amount of powerused in holding a 25 kg box, 1.5meters above the floor, for 60seconds.[?]](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/Ut75PY10XMdUvfG7cBfAl6m1H2uBmRvH.png)
Answers
Here is your answer mate,
Question,
\(Determine\: the\: amount\\ \: of\: power\:used\: in\\\: holding\: a\: 25\: kg\: box\:\\ , \: 1.5\: meters \: above\: the\: floor\\\: for\: 60\: seconds\)
Answer,
Power is equal to work done per unit timeWork is force × displacement SI UNIT OF WORK Newton meterSI UNIT OF POWER Watt\(\)
Solution,
\(\)
Given,
\(MASS \: IS\: 25\: KG\: \\ and \: HEIGHTIS\: 1.5m\: \)
\(\)
WORK DONE (done against gravity) =
mass×acceleration due to gravity ×height
WORK = 25× 10× 1.5
\(\: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \)= 375 Nm
\(\)
Now
POWER =
\( \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\frac{work}{time} \)
POWER
\(\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= \frac{375}{60} Watt \)
\(\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =6.25\)
\(Therfore\: your \: answer\: is\: 6.25\)
\(\)
Check this,
\(Acceleration\: due\: to \: gravity\\\: can\: be\: 9.8\: m/s²\: \\As\: nothing\: mentioned\\\: in\: question\: \\I \: took \: it \: as \: 10\)
\(\)
Have a good day
The net force on an object is
Answers
Answer:
Net Force. when all combinations of force acting on an object. Force. A push or pull
So it's the third answer
( the combination of all forces acting on it )
Explain how to construct an electromagnet.
Answers
Be careful!
What does the elasticity (stretchiness) of the resistance band determine?
Answers
The resistance band's elasticity (stretchiness) dictates how easily it can be stretched or can be flexible.
What does the resistance band's elasticity determine?It is the proportion of tensile stress to strain, where strain is the amount of deformation and tensile stress is the tension force applied to a surface area (amount of stretch of the resistance band).
Instead than requiring you to hold additional weight per se, resistance bands function by providing an external resistance force that can be imposed. They are flat, occasionally looping bands that might be thin or thick.
Both rubber bands and springs have a unique quality. The stretch distance affects how hard a band pulls back. The spring constant, denoted by the symbol k (in units of N/m), is a proportionality constant.
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The average speed of molecules of a 0.1 mole nitrogen gas in a container is 5103
m/s.
a/ Determine the total translational kinetic energy of the gas.
b/ Compute the energy as heat providing to the gas so that the average speed of its molecules increases to
double.
Answers
Answer: (a) The total translational kinetic energy of the gas is \(35 \times 10^{7} J\).
(b) The energy as heat providing to the gas so that the average speed of its molecules increases to double is \(8.7 \times 10^{7} J\).
Explanation:
Given: Average speed of molecules = \(5 \times 10^{3}\) m/s
Moles = 0.1 mol
(a) As the give gas is nitrogen so its mass is 28 g/mol.
Formula to calculate translational kinetic energy is as follows.
Total translational K.E = \(\frac{1}{2}mv^{2}\)
where,
m = mass
v = velocity
Substitute the values into above formula as follows.
\(Translational K.E = \frac{1}{2}mv^{2}\\= \frac{1}{2} \times 28 \times (5 \times 10^{3})^{2}\\= 35 \times 10^{7} J\)
(b) As the energy is directly proportional to the square of velocity. So, when average speed of molecules increases to double then relation between energy and velocity will be as follows.
\(E \propto (2v)^{2}\\or, E \propto 4v^{2}\\v^{2} \propto \frac{E}{4}\)
This means that velocity gets one-fourth times the energy of its molecules.
Therefore, energy will be calculated as follows.
\(Energy = \frac{35 \times 10^{7}}{4}\\= 8.7 \times 10^{7} J\)
Therefore, we can conclude that
(a) The total translational kinetic energy of the gas is \(35 \times 10^{7} J\).
(b) The energy as heat providing to the gas so that the average speed of its molecules increases to double is \(8.7 \times 10^{7} J\).
(1,-5) perp to y=⅛×+2
Answers
The slope of a line perpendicular to y = 1/8x + 2 is -8.
The equation of a line in point-slope form is y - y1 = m (x - x1), where m is the slope and (x1, y1) is a point on the line.
What is line in point-slope form?The point-slope form of a line is given by y - y1 = m (x - x1), where (x1, y1) is a point on the line and m is the slope of the line.
In this equation, y1 and x1 are the coordinates of a point on the line, and m is the slope of the line.
So, given a point on the line, and the slope, you can use this form to write the equation of the line.
So, the equation of the line through point (1, -5) and perpendicular to y = 1/8x + 2 is y + 5 = -8(x - 1) => y = -8x + 13.
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The water level in identical bowls, A and B, is exactly the same. A contains only water; B contains floating ice as well as water. When we weigh the bowls, we find that Group of answer choices
Answers
Answer:
We know that the density of the ice is smaller than the density of the water (and this is why the ice floats in water).
Dw > Di
Da is the density of the water and Di is the density of the ice
Since in Bowl A we have a volume V, only of water, then the mass of the bowl A is:
Dw*V.
Now, in the bowl B we have a combination of water and ice, suppose that Vw is the volume of water and Vi is the volume of ice, and we know that:
Vw + Vi = V.
Then the mass in this second bowl is:
Dw*Vw + Di*Vi = Dw*(V - Vi) + Di*Vi = Dw*V + (Di - Dw)*Vi
and we know that Dw > Di, then the left term is a negative term, then the mass of bowl B is smaller than the mass of bowl A.
A 11.1 kg block of steel is pushed at a constant speed across
a Teflon surface. What is the normal force on the block?
(Answer to one decimal place with no units.)
Answers
The normal force on the block of steel of mass 11.1Kg at constant speed is 108.8 N.
Mass of steel block = 11.1 Kg
Normal force on the block = Force exerted by the surface on the block
= mass × acceleration due to gravity
= m × g
Taking the value of g as 9.8 m/s
= 11.1 × 9.8
= 108.78 N
By converting the answer to one decimal place, round the value to
= 108.8 N
Thus, the normal force on the block of steel by the Teflon surface round to one decimal place is 108.8 N.
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What is the mass of a cylinder of silicon (in units of grams) that is 4.00 cm in diameter and 10.55 cm long?
Answers
Answer:
309.02g
Explanation:
According to the information given in this question, the cylinder has the following:
Mass = ?
Length/height = 10.55cm
Diameter = 4.00cm
Volume of a cylinder = πr²h
Where; π = pie (3.142 or 22/7)
r = radius (cm)
h = height
Note that, radius = diameter/2
Hence, radius (r) = 4.00/2
r = 2.00cm.
V = πr²h
V = 22/7 × 2² × 10.55
V = 22/7 × 42.2
V = 928.4/7
V = 132.628cm³
Density = mass/volume
Hence, mass = density × volume
Where density of silicon is 2.33g/cm³
Mass = 2.33g/cm³ × 132.628cm³
Mass = 309.02g
If an object is moving and the sum of all the vector forces on it is zero, then the object will:
accelerate at a constant rate
come to rest
move at a constant speed
none of the previous
Answers
If an object is moving and the sum of all the vector forces on it is zero, then the object will move at a constant speed. The correct option is c.
What is vector force?A force's magnitude and direction are both represented by a force vector. This contrasts with expressing the force's magnitude alone, which is known as a scalar quantity.
Typically, a vector is represented by an arrow that points in the direction of the force and has a length proportionate to the strength of the force.
Therefore, the correct option is c, move at a constant speed.
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A train 350 m long is moving on a straight track with a speed of 84.1 km/h. The engineer applies the brakes at a crossing, and later the last car passes the crossing with a speed of 15.8 km/h. Assuming constant acceleration, determine how long the train blocked the crossing. Disregard the width of the crossing.
Answers
Answer:
t = 25.0 s
Explanation:
Assuming that the engineer applies the brakes just over the crossing, the train moves exactly 350 m at a constant acceleration, with a final speed (when the last car of the train leaves the crossing) of 15.8km/h.Since we know the initial and final speeds, and the horizontal distance traveled (the length of the train) we can use the following kinematic equation to get the acceleration:\(v_{f}^{2} - v_{o}^{2} = 2*a* \Delta x (1)\)
Since we need to find the time in seconds, it is advisable to convert vf and vo to m/s first, as follows:\(v_{o} = 84.1 km/h*\frac{1h}{3600s} *\frac{1000m}{1km} = 23.4 m/s (2)\)
\(v_{f} = 15.8 km/h*\frac{1h}{3600s} *\frac{1000m}{1km} = 4.4 m/s (3)\)
Replacing (2) and (3) in (1), since Δx =350m, we can solving for a:\(a = \frac{(4.4m/s)^{2} - (23.4m/s)^{2}}{2*350m} = -0.76 m/s2 (4)\)
In order to get the time, we can simply use the definition of acceleration, and rearrange terms:\(t =\frac{v_{f}-v_{o}}{a} = \frac{(4.4m/s)-(23.4m/s)}{-0.76m/s2} = 25.0 s (5)\)
a 1.0kg water balloon falls downward and experiences a 4.9n air resistance as it approaches the ground. What is the acceleration of the water ballon when it experiences this air resistance
Answers
Given that,
Mass of a water balloon, m = 1 kg
It comes downward an experience a 4.9 N air resistance as it approaches the ground.
To find,
The acceleration of the water balloon when it experiences this air resistance.
Solution,
Let the acceleration be a.
The net force acting on it will be :
\(F_{net}=mg+F_r\\\\=1\times 10+(-4.9)\\\\=5.1\ N\)
The force is also given by :
F = ma
\(a=\dfrac{F}{m}\\\\a=\dfrac{5.1}{1}\\\\=5.1\ m/s^2\)
So, the acceleration of the water balloon is \(5.1\ m/s^2\).
The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the ballon when it experiences the air resistance, we use the formula below.
Formula:
ma = mg-F'............... Equation 1Where:
m = mass of the ballon'a = acceleration of the ballonF' = air resistanceg = acceleration due to gravity.Make a the subject of the equation
a = (mg-F')/m................. Equation 2From the question,
Given:
m = 1 kgF' = 4.9 Ng = 9.8 m/s²Substitute these values into equation 2
a = [(9.8×1)-4.9)/1a = (9.8-4.9)/1a = 4.9/1a = 4.9 m/s²Hence, The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².
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If the boat in the preceding example travels with the same speed of 20 km h¹¹ relative to the water and is to travel due north, in what direction should it travel?
Answers
If the boat is now to travel due north relative to the Earth, we need to find the direction it should travel relative to the water, taking into account the effect of the river's velocity.
Since the boat is traveling with a speed of 20 km/h relative to the water, and the water is flowing with a velocity of 8 km/h in a direction of 60 degrees south of east, we can use vector addition to find the boat's resultant velocity relative to the Earth.
Let's define the x-axis as east and the y-axis as north. The velocity of the water is then:
Vw = 8 km/h at an angle of 240 degrees (60 degrees south of east)
We can convert this to vector form:
Vw = (-4 km/h, -6.93 km/h)
The velocity of the boat relative to the water is:
Vb = 20 km/h at an angle of 0 degrees (due north)
We can convert this to vector form:
Vb = (0 km/h, 20 km/h)
To find the resultant velocity, we can add these two vectors:
Vr = Vb + Vw
Vr = (0 km/h - 4 km/h, 20 km/h - 6.93 km/h)
Vr = (-4 km/h, 13.07 km/h)
The direction of this vector is given by:
tan θ = (13.07 km/h) / (-4 km/h)
θ = -73.74 degrees
Since we defined the x-axis as east, the direction of the boat's velocity relative to the water is 73.74 degrees east of north.
To find the direction the boat should travel relative to the water to move due north, we need to subtract this angle from 90 degrees:
90 degrees - 73.74 degrees = 16.26 degrees
Therefore, the boat should travel in a direction of 16.26 degrees west of north relative to the water to move due north relative to the Earth.
Select all correct statements.
Select one or more:______.
a. E field lines created by static charges never form loops.
b. Any B field lines always form loops (or extend to infinity). Net flux of B field for any closed surface is always zero.
c. E field lines induced by changing B field always form loops.
d. A changing B field always creates E field.
Answers
Explanation:
B.
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duduusuwubbdysysdhvvduususu
assignment questions
Answers
Answer:
which on a is the question
By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect the earth's rotational effects
Answers
Answer:
\(Weight\ loss=1.6321N\)
Explanation:
From the question we are told that:
Weight \(W=85.9kg\)
Altitude \(h= 6.33 km\)
Let
Radius of Earth \(r=6380km\)
Gravity \(g=9.8m/s^2\)
Generally the equation for Gravity at altitude is mathematically given by
\(g_s=9.8(\frac{6380}{6380+6.33})^2\)
\(g_s=9.781m/s^2\)
Therefore
Weight at sea level
\(W_s=9.8*85.9\)
\(W_s=841.82N\)
Weight at 6.33 altitude
\(W_a=9.781*85.9\)
\(W_a=840.2N\)
Therefore
\(Weight loss=W_s-W_b\)
\(Weight loss=841.82-840.2\)
\(Weight loss=1.6321N\)
They create a heat engine where the hot reservoir is filled with water and steam at equilibrium, and the cold reservoir is filled with ice and water at equilibrium. What is the Carnot efficiency for their heat engine if the pressure is constant at 1.0 atmospheres?
Answers
Answer:
The efficiency of Carnot's heat engine is 26.8 %.
Explanation:
Temperature of hot reservoir, TH = 100 degree C = 373 K
temperature of cold reservoir, Tc = 0 degree C = 273 K
The efficiency of Carnot's heat engine is
\(\eta = 1-\frac{Tc}{T_H}\\\\\eta = 1 -\frac{273}{373}\\\\\eta = 0.268 =26.8 %\)
The efficiency of Carnot's heat engine is 26.8 %.
Help answer this please
Answers
Answer:
1. Atomic number
2. element symbol
3. element name
4. atomic mass
5 and 6 are the same as the diagram above... just rewrite using data
An objects motion changes
Answers
Answer:
uh finish the question please lol.
A 35.0 g bullet strikes a 5.3 kg stationary wooden block and embeds itself in the block. The block and bullet fly off together at 7.1 m/s. What was the original speed of the bullet? (WILL GIVE BRAINLIEST)
Answers
Answer:
= 1200m/s or 1.2 x \(10^{3}\) m/s
Explanation:
a rocket leaving the lanch pad is ana exmaple of which law
Answers
Answer:
Newton's Third Law
The boat goes forward, you go backward! A rocket can lift off from a launch pad only when it expels gas out of its engine. The rocket pushes on the gas, and the gas in turn pushes on the rocket.
Explanation:
Newton's Third Law
The boat goes forward, you go backward! A rocket can lift off from a launch pad only when it expels gas out of its engine
Explanation:
A rectangular block weighting 320N has dimensions 4metre by 10metre what is the greater pressure and the least pressure it can be exerted on the ground
Answers
The pressure exerted by a rectangular block on the ground is 8 Pascal (Pa) when its weight is 320 N and its dimensions are 4 meters by 10 meters. The greatest pressure occurs when the block is vertically placed at 20 Pa, while the least pressure occurs when it is horizontally placed at 8 Pa.
To calculate the pressure exerted by the rectangular block on the ground, we need to consider the formula for pressure:
Pressure = Force / Area
Given that the weight of the block is 320 N and the dimensions of the block are 4 meters by 10 meters, we can calculate the area of the block in contact with the ground. In this case, it is the length multiplied by the width of the block.
Area = length * width
Area = 4 meters * 10 meters
Area = 40 square meters
Now, we can calculate the pressure exerted by the block on the ground:
Pressure = 320 N / 40 square meters
Pressure = 8 N/m^2 (Pascal)
Therefore, the pressure exerted by the rectangular block on the ground is 8 Pascal (Pa).
To determine the greatest pressure and the least pressure that can be exerted on the ground, we need to consider the orientation of the block.
The greatest pressure occurs when the block is placed vertically on one of its smallest faces. In this case, the entire weight of the block (320 N) is concentrated on a smaller area.
The area in contact with the ground is given by the length multiplied by the width of the smallest face.
Area = 4 meters * 4 meters = 16 square meters
Greatest Pressure = 320 N / 16 square meters = 20 \(N/m^2\)(Pascal)
The least pressure occurs when the block is placed horizontally on one of its largest faces. In this case, the weight of the block is distributed over a larger area.
The area in contact with the ground is given by the length multiplied by the width of the largest face.
Area = 4 meters * 10 meters = 40 square meters
Least Pressure = 320 N / 40 square meters = 8 \(N/m^2\)(Pascal)
Therefore, the greatest pressure that can be exerted on the ground is 20 Pascal (Pa), and the least pressure is 8 Pascal (Pa).
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effort distance of a lever should be increased to lift the havier load give reason
Answers
The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.
The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.
In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.
By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.
By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.
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A 52 kg and a 95 kg skydiver jump from an airplane at an altitude of 4750 m, both falling in the pike position. Assume all values are accurate to three significant digits. (Assume that the density of air is 1.21 kg/m3 and the drag coefficient of a skydiver in a pike position is 0.7.) If each skydiver has a frontal area of 0.14 m2, calculate their terminal velocities (in m/s). 52 kg skydiver m/s 95 kg skydiver m/s How long will it take (in s) for each skydiver to reach the ground (assuming the time to reach terminal velocity is small)
Answers
Answer: 52 kg skydiver: 9.09 m/s and 522.55 s
95 kg skydiver: 12.3 m/s and 386.2 s
Explanation: Drag Force is an opposite force when an object is moving in a fluid.
For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.
Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:
\(F_{G}=F_{D}\)
\(mg=\frac{1}{2}C \rho Av_{T}^{2}\)
\(v_{T}=\sqrt{\frac{2mg}{\rho CA} }\)
where
m is mass in kg
g is acceleration due to gravitational force in m/s²
ρ is density of the fluid in kg/m³
C is drag coefficient
A is area of the object in the fluid in m²
Calculating:
The 52kg skydiver has terminal velocity of:
\(v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 9.09
The 95kg skydiver's terminal velocity is
\(v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 12.3
The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.
The time each one will reach the floor will be:
52 kg at 9.09 m/s:
\(t=\frac{4750}{9.09}\)
t = 522.5
95 kg at 12.3 m/s:
\(t=\frac{4750}{12.3}\)
t = 386.2
The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.
Giving 50 points exactly 50 point and making brainles and if answered wrong I will report and get you kicked out
Draw a picture showing how Heat is added, released, and transferred from one object to another. Also, draw a picture explaining how sublimation or deposition works. please you can draw in your book and take a picture and post it
Answers
Answer:
i hope this helps i did'nt quiet understand the secound one. I hope youcan see my picture well .
Explanation:
sincerily, MEMC3891
3. Now use the brown knob at the opening of the hose to adjust the angle at which water comes out. When water comes out at an angle (instead of going straight up), water does not shoot as high as before. Explain your observations qualitatively.
Answers
Answer:
Due to brown knob which controls its angle.
Explanation:
When water comes out at an angle instead of going straight up, water does not shoot as high as before because its speed is controlled by the brown knob in order to throw water in another angle. If we adjust the brown knob present at the opening of hose pipe in a straight angle the water shoot very high because water moves with high pressure and no barrier is present between its way.
Match the technology that uses radio waves to the field in which it is used.
research
communication
broadcasting
medicine
navigation
Correct!
AM and FM stations
CB radios
magnetic resonance imaging
global positioning system
radio telescopes
Answers
Hi
Please help on question asap if the answer is correct I'll rate you five stars a thanks and maybe even brainliest!
When two light bulbs are connected in series, the resistance in the circuit is increase compared to that with one lightbulb. The increased resistance opposes the flow of current so far fewer electrons pass per second , transferring less energy. The lightbulbs are therefore not as bright as In a circuit with same voltage but only one bulb.
However, when Two lightbulbs are connected in parallel, each loop behaves like a separate circuit . The resistance in each branch is the same as if there were just one light bulb in the whole circuit.there is the same current in each branch of the circuit ,so the bulbs Will light up with the same brightness as a single bulb circuit. The energy stored in the battery will decrease twice as quickly and battery will run out faster than I series circuit.
6) explain the advantages and disadvantages of arranging components in series or parallel.
Answers
Advantages of Components Arranged in Series:
1. Increased resistance: Connecting components in series increases the overall resistance in the circuit. This can be advantageous in situations where you want to limit the flow of current or control the amount of power being dissipated.
2. Voltage sharing: In a series circuit, the total voltage of the power supply is divided among the components. This can be useful when you want to ensure that each component receives a specific voltage.
3. Current consistency: The current remains the same throughout the series circuit, which can be beneficial when you need to ensure a consistent current flow through multiple components.
Disadvantages of Components Arranged in Series:
1. Reduced brightness or performance: As mentioned in the question, when light bulbs are connected in series, the increased resistance reduces the flow of current, resulting in dimmer bulbs or reduced performance in other electrical devices.
2. Single point of failure: If one component in a series circuit fails, it can disrupt the entire circuit and cause all components to stop functioning.
Advantages of Components Arranged in Parallel:
1. Brightness and performance: When components such as light bulbs are connected in parallel, each component receives the full voltage, resulting in brighter bulbs and better performance in other devices.
2. Redundancy: In a parallel circuit, if one component fails, the other components can continue to function independently. This provides redundancy and ensures that the failure of one component does not affect the others.
3. Increased current capacity: Parallel arrangement allows the circuit to handle higher currents, which can be useful in situations where high power or heavy loads are required.
Disadvantages of Components Arranged in Parallel:
1. Increased complexity: Parallel circuits require more wiring and connections, which can make the circuit more complex and harder to manage.
2. Higher cost: Parallel circuits may require more components and wiring, resulting in higher costs for materials and installation.
It's important to consider the specific requirements and constraints of the application when deciding whether to arrange components in series or parallel. Each configuration has its advantages and disadvantages, and the choice depends on factors such as desired current flow, voltage distribution, and reliability.I
Two ropes are tied to a fixed nail. The tension in the ropes is 10N and 20N respectively, while the angle between them is 120degree. Calculate the magnitude and direction of the reaction to the nail.
Answers
Answer:
\( \sqrt{10 { }^{2} + 20 { }^{2} - 2 \times 10 \times 20 \cos(60) } \)
that's the Resultant of the 2 forces... if that will help... but I guess I need the graph of 5he question to answer more and give you the full mark xd
kicked the ball in the air with an initial velocity of 12m/s at an angle of 40° above the horizontal. If the ball travels a horizontal distance of 15m , how long will it fly in the air?
Answers
The soccer ball rose 5.24 meters in the air.
VO =?, max H =?, range = 25m, angle A = 40°
Projectile motion is being used in this situation. Range = vo2 * sin 2A / g is the formula for range. calculating the initial velocity vo's square and its original value.
Range is equal to vo2*sin2A/g.
VO2 * SIN (2 * 40°) / 9.8 m/s = 25 m
vo2 = sin 80° / 9.8 m/s / 25 m
2 vo = 15.77 m/s and 2 vo = 248.8 (m/s) respectively.
The ball's starting speed is 15.77 m/s.
The height of the object, max H, can be calculated as follows: max H = vo * (sin A) * 2g max H = 248.8 (m/s) * (sin 40°) * 19.6 m/s * 2g max H = 5.24 meters
The soccer ball rose 5.24 meters in the air.
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