In the problem 8^3 - 10 × 5 - 4

Answer:you have to subtract first and then add the 2.50 and that’s your answer

Step-by-step explanation:

Answer:

C=-3t+30

Step-by-step explanation:

C=-3t+30

SOLUTION

TO DETERMINE

84 as a product of primes.

Use index notation to write the number

EVALUATION

Here the given number is 84

We prime factorise the given number

84 = 2 × 2 × 3 × 7

Number of 2's = 2

Number of 3's = 1

Number of 7's = 1

Rewriting the given number in index form we get

━━━━━━━━━━━━━━━━

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The difference between face value and place value of 5 in 2,10,519

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2. if one bee drinks 1ml honey then how much honey 1000 bees will drink??

Answer:

Step-by-step explanation:

One

Sin(x) = 15/24 = 0.625

x = sin-1(0.625)

x = 38.68

Two

Cos(x) = 8/11

Cos(x) = .727

x = cos-1(.727)

x =  43.34

Three

Tan(x) = 20/37

Tan(x) = 0.5405

x = tan-1(0.5405)

x = 28.39

Four

Cos(x) = 18/23

Cos(x) = .7826

x = cos-1(0.7826)

x = 38.50

Answer:

c. 502.65 in³

Step-by-step explanation:

For a cylinder:

V = πr²h

r = d/2 = 8 in. / 2 = 4 in.

V = 3.14159 × (4 in.)² × 10 in.

V = 502.65 in.³

Answer & Step-by-step explanation:

The problem says that the circles represents the sum of the two rectangles. So, in order to find the circle on the left side, we are going to have to add together (4x + 3y) and (2x - y).

(4x + 3y) + (2x - y)

4x + 3y + 2x - y

Combine like terms.

So, the answer for the circle on the left is 6x + 2y

Now, let's find the bottom right rectangle. To do so, we are going to subtract (x + 4y) from (4x + 5y).

(4x + 5y) - (x + 4y)

4x + 5y - x - 4y

Combine like terms.

So, the answer for the bottom right rectangle is 3x - y

Now, let's find the bottom circle. We can do this by adding together (3x - y) and (2x - y).

(3x - y) + (2x - y)

3x - y + 2x - y

Combine like terms.

So, the answer for the bottom circle is 5x - 2y

Answer:

4>-3

Step-by-step explanation:

-3 is a negative number. Negative numbers are less than positive numbers. In this inequality the positive number is being shown as greater than, meaning it is the correct choice.

Step-by-step explanation:

4>-3

The area inside the loop of the limacon given by the polar equation r = 7 - 14sin(θ) is 294π square units.

To find the area inside the loop of the limacon given by the polar equation r = 7 - 14sin(θ), we need to evaluate the integral for half of the area and then double the result.

The curve of the limacon has a loop when 0 ≤ θ ≤ π, so we integrate from 0 to π. The area can be calculated as follows:

A = 2 ∫₀^π 1/2 r² dθ

Using the equation for r given, we can substitute and simplify:

A = 2 ∫₀^π 1/2 (7 - 14sin(θ))² dθ

A = 2 ∫₀^π 1/2 (49 - 196sin(θ) + 196sin²(θ)) dθ

A = ∫₀^π (98 - 392sin(θ) + 392sin²(θ)) dθ

Using the trigonometric identity 1 - cos(2θ) = 2sin²(θ), we can simplify further:

A = ∫₀^π (98 - 392sin(θ) + 196 - 196cos(2θ)) dθ

A = ∫₀^π (294 - 392sin(θ) - 196cos(2θ)) dθ

Integrating with respect to θ:

A = [294θ + 392cos(θ)sin(θ) + 98sin(θ)]₀^π

Evaluating at the limits of integration, we get:

A = [294π + 0 + 0] - [0 + 392cos(0)sin(0) + 98sin(0)]

A = 294π - 0 - 0 = 294π

Therefore, the area inside the loop of the limacon r = 7 - 14sin(θ) is 294π square units.

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A & D are complex conjugates because the sum of A and D is a real number. Also, A & D are complex conjugate because the product of A and D is a real number.

Options A and D are the correct answer

The complex conjugate of a complex number is the number obtained by changing the sign of its imaginary part. The complex conjugate is written with a bar over the complex number, like this:

z = a + bi

z* = a - bi

where a and b are real numbers and i is the imaginary unit, which is defined as the square root of -1

For example, the complex conjugate of the complex number 3 + 4i is 3 - 4i.

The complex conjugate has several important properties. For example, the product of a complex number and its complex conjugate is always a real number:

(a + bi)(a - bi) = a²+ b²

Also, the sum of a complex number and its complex conjugate is always a real number:

(a + bi) + (a - bi) = 2a

These properties are useful for simplifying expressions involving complex numbers.

Let's examine the points on the graph:

A = -2 + 3i

B = 2 + 3i

C = 3 + 2i

D =  -2 - 3i

A x D = ( -2 + 3i) x (-2 - 3i) = (-2)²- (3i)² = 4- (-9) = 13

A + D = ( -2 + 3i) +  (-2 - 3i) = -2-2 + 3i-3i = -4

Thus, points A and D are complex conjugates because the sum and product of A and D are real numbers

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The Interval that is the approximate 95% confidence interval is 0.094 to 0.146

The Interval can be calculate as below:

α = 12%= 0.12  represent the proportion estimated

\(SE\) = 0.013 represent the standard error

The confidence interval for the true proportion is given by:

α ± \(z_{\alpha/2 } SE\)

And for 95% of confidence the critical value is \(z_{\alpha/2 }\) =1.96 and when we subtitute the value to the formula we got:

0.12± 1.96 x 0.013 =(0.094, 0.146)

The Interval that is the approximate 95% confidence interval is 0.094 to 0.146

Hence, the Interval that is the approximate 95% confidence interval is 0.094 to 0.146

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To show that images is an orthogonal subset of r4, we need to show that any two vectors in images are orthogonal to each other. Let's assume that u and v are two vectors in images.

This means that there exist some vectors x and y in R4 such that u = Px and v = Py, where P is the projection matrix onto the subspace images.

Now, let's consider the dot product of u and v:
u · v = (Px) · (Py) = xTPTPy
Since P is a projection matrix, it is idempotent (i.e., P2 = P) and symmetric. Thus, P is an orthogonal projection matrix, which means that it projects vectors onto a subspace that is orthogonal to its complement. Therefore, we have:
u · v = xTPTPy = xTP2y = xTPy = (Px) · y = 0
since y is in the complement of images. Thus, we have shown that any two vectors in images are orthogonal to each other, and so images is indeed an orthogonal subset of R4.

To find a fourth vector images such that images forms an orthogonal basis in R4, we can use the Gram-Schmidt process. Let's assume that u1, u2, and u3 are three linearly independent vectors in images. We can then use the following formula to find a fourth vector v:
v = w - (w · u1)u1 - (w · u2)u2 - (w · u3)u3
where w is any nonzero vector in R4 that is not in the subspace spanned by images. This formula ensures that v is orthogonal to u1, u2, and u3.
As for the extent to which p4 is unique, it depends on the subspace being projected onto. If we project onto a subspace that is spanned by a set of linearly independent vectors, then the projection matrix P is unique. However, if the subspace is not spanned by a set of linearly independent vectors, then there are infinitely many possible projection matrices that could be used.

To answer your question, we first need to show that the given set of vector images forms an orthogonal subset in R4, and then find a fourth vector to make it an orthogonal basis. Finally, we will discuss the uniqueness of P4.
Step 1: Show that the given set of vector images is an orthogonal subset in R4.
To do this, we need to ensure that every pair of vectors in the set has a dot product of 0. For the sake of illustration, let's assume that the given set of vector images is {v1, v2, v3}. We will then verify that:
v1 · v2 = 0
v1 · v3 = 0
v2 · v3 = 0
If all these dot products are 0, then the set of vector images is an orthogonal subset in R4.
Step 2: Find a fourth vector to form an orthogonal basis in R4.
To find the fourth vector, v4, we need it to be orthogonal to all other vectors in the set. So we need to satisfy the following conditions:
v1 · v4 = 0
v2 · v4 = 0
v3 · v4 = 0
Using the above conditions, we can find the components of v4. Once we have v4, the set {v1, v2, v3, v4} forms an orthogonal basis in R4.
Step 3: Discuss the uniqueness of P4.
To what extent is P4 unique? P4 is unique up to the choice of the orthogonal basis. In other words, while the orthogonal basis itself may not be unique (since it can be formed by different combinations of orthogonal vectors), the subspace P4 that it spans remains the same.
In summary, we have shown that the given set of vector images forms an orthogonal subset in R4, found a fourth vector to form an orthogonal basis, and discussed the uniqueness of P4.

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The z-score when x=108 is 3.1034. The z-score tells you that x=108 is 3.1034 standard deviations to the left of the mean.

Z-score is used in statistics to compare a score to a normal distribution. The z-score is a measure of how far away from the mean a value is in standard deviation units.

To find the z-score when x = 108, we use the formula:

z = (x - μ) / σ

where x = 108, μ = 153, and σ = 14.5.

Substituting these values, we get:

z = (108 - 153) / 14.5 = -3.1034

So the z-score when x = 108 is -3.1034.

The z-score tells us how many standard deviations away from the mean a particular value is. In this case, since the z-score is negative, we know that x = 108 is to the left of the mean.

The absolute value of the z-score tells us how many standard deviations away from the mean the value is. In this case, the absolute value of the z-score is approximately 3.1034, which means that x = 108 is approximately 3.1034 standard deviations to the left of the mean.

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Answer:

Break up the decimal.

Step-by-step explanation:

4 + 0.30 + 0.07.

Answer:

6/10

Step-by-step explanation:

30/50=3/5

3/5=3/5

15/25=3/5

3/5*2/2=6/10

Given:

A TV with a cash price of $245.00 and a down payment of $4.90.

So, the amount financed =

So, the answer will be option D. $240.10

Answer:

Step-by-step explanation:

Given the inequality cosθ>−sinθ, to get the value of \(\theta\) that falls within the range π/2≤θ<3π/2, the following steps must be followed;

Step 1;

Divide both sides by cosθ;

cosθ/cosθ>−sinθ/cosθ

1>−sinθ/cosθ

1>-tanθ

Step 2;

Multiplying both sides by -1

-1<tanθ

tanθ>-1

θ>\(tan^{-1} -1\)

θ>-45°

Since tan is negative in the second and 4th quadrant;

In the second quadrant θ>180-45

θ>135°

θ>3π/4

in the 4th quadrant, θ>360-45

θ>315°

θ>9π/4

The only value that falls within the range is at when θ>3π/4  

The work done by F in moving the particle once counterclockwise around the given curve is zero.

To find the work done by a vector field F in moving a particle around a closed curve C, we use the line integral:

W = ∮C F · dr

In this case, F = (2x - 5y)i + (5x-2y)j, and the curve C is the circle with center (4, 4) and radius 4.

To evaluate the line integral, we need to parameterize the curve C. We can use the parametric equations for a circle:

x = 4 + 4cos(t)

y = 4 + 4sin(t)

where t ranges from 0 to 2π.

Next, we need to find the differential vector dr along the curve C:

dr = dx i + dy j

Taking the derivatives of x and y with respect to t, we get:

dx = -4sin(t) dt

dy = 4cos(t) dt

Substituting dx and dy into the line integral formula, we have:

W = ∮C F · dr

= ∫(0 to 2π) [(2(4 + 4cos(t)) - 5(4 + 4sin(t))) (-4sin(t)) + (5(4 + 4cos(t)) - 2(4 + 4sin(t))) (4cos(t))] dt

Simplifying the expression inside the integral, we get:

W = ∫(0 to 2π) [-20sin(t) + 40cos(t) - 20sin(t) + 20cos(t)] dt

= ∫(0 to 2π) (20cos(t) - 40sin(t)) dt

Integrating the terms, we have:

W = [20sin(t) + 40cos(t)] (from 0 to 2π)

= (20sin(2π) + 40cos(2π)) - (20sin(0) + 40cos(0))

= (0 + 40) - (0 + 40)

= 0

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our answer is 7+52={059}


Using complementary counting, we count all of the license plates that do not have the desired property. In order to not be a palindrome, the first and third characters of each string must be different.

we count all the license plates that don't contain the specified property using complimentary counting. The first and third letters of each string must be distinct in order for it to not be a palindrome. As a result, there are 26.26.25 three-letter non-palindromes and 10.10.9 three-digit non-palindromes. Since there are a total of 10^3.26^3, the likelihood that a license plate will not contain the necessary property is 10.10.9, 26.26.25/10^3.26^3 =45/52. We deduct this from 1 to get our probability.      

which is 1-45/52=7/52. Therefore, 7+52=059 is the answer

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The equation of the hyperbola that satisfies the given conditions is x^2 / 4 - y^2 / 16 = 1. This equation represents a hyperbola with its center at the origin (0, 0), foci at (0, ±8), and vertices at (0, ±2).

To find the equation of a hyperbola given its foci and vertices, we can start by determining the key properties of the hyperbola. The foci and vertices provide important information about the shape and orientation of the hyperbola.

Given:

Foci: (0, ±8)

Vertices: (0, ±2)

Center:

The center of the hyperbola is located at the midpoint between the foci. In this case, the y-coordinate of the center is the average of the y-coordinates of the foci, which is (8 + (-8))/2 = 0. The x-coordinate of the center is 0 since it lies on the y-axis. Therefore, the center of the hyperbola is (0, 0).

Transverse axis:

The transverse axis is the segment connecting the vertices. In this case, the vertices lie on the y-axis, so the transverse axis is vertical.

Distance between the center and the foci:

The distance between the center and each focus is given by the value c, which represents the distance between the center and either focus. In this case, c = 8.

Distance between the center and the vertices:

The distance between the center and each vertex is given by the value a, which represents half the length of the transverse axis. In this case, a = 2.

Equation form:

The equation of a hyperbola with the center at (h, k) is given by the formula:

((x - h)^2 / a^2) - ((y - k)^2 / b^2) = 1

Using the information we have gathered, we can now write the equation of the hyperbola:

((x - 0)^2 / 2^2) - ((y - 0)^2 / b^2) = 1

Simplifying the equation, we have:

x^2 / 4 - y^2 / b^2 = 1

To find the value of b, we can use the distance between the center and the vertices. In this case, the distance is 2a, which is 2 * 2 = 4. Since b represents the distance between the center and either vertex, we have b = 4.

Substituting the value of b into the equation, we get:

x^2 / 4 - y^2 / 16 = 1

Therefore, the equation of the hyperbola that satisfies the given conditions is:

x^2 / 4 - y^2 / 16 = 1

This equation represents a hyperbola with its center at the origin (0, 0), foci at (0, ±8), and vertices at (0, ±2).

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x 's measure is already given

x=20°

Answer:

∡x = 20°

∡y = 160°

∠z = 160°

Step-by-step explanation:

Angles on a straight line sum to 180°

⇒ ∠z + 20° = 180°

⇒ ∠z = 180° - 20°

⇒ ∠z = 160°

The central angle measure equals the corresponding arc measure.

⇒ ∡x = 20°

⇒ ∡y = ∠z = 160°

Answer:

Step-by-step explanation:

You are given a couple of points:

  (years, heigh) = (6, 7) and (9, 16)

and asked to write a linear equation that they satisfy. In general, you need to find the slope using the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (16 -7)/(9 -6) = 9/3 = 3

__

The point-slope form of the equation for a line can be used with this information.

  y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)

Using the given points, you can write either of the equations ...

  y -7 = 3(x -6) . . . . . using the first point

  y -16 = 3(x -9) . . . . . using the second point. This matches choice B.

__

Either of the point-slope equations can be rearranged to give the slope-intercept equation.

  y -16 = 3(x -9)

  y = 3x -27 +16 . . . . eliminate parentheses, add 16

  y = 3x -11 . . . . . This matches choice C.

__

Additional comment

The first choice has the right slope, but uses a point not on the line (10, 6).

The last choice has the wrong slope and the wrong y-intercept.

Answer: 12 balls i think

Answer:

answer is 12

Step-by-step explanation:

i took the quiz.

The correct answer is option  A: The random variable is discrete. A decibel is a unit of measure used to quantify the loudness or intensity of sound.

From 0 dB (the quietest level of sound) to 140 dB (the loudest level of sound), it is measured on a logarithmic scale (the highest level of sound).

The decibel level of a siren is normally between 110 and 120 dB, which is regarded to be within or close to the threshold of human hearing.

The decibel level of a siren is measured on a logarithmic scale, making it a discrete variable. This indicates that it is measured in whole numbers rather than fractions of a decibel.

For instance, a siren's decibel level can be 110 dB, 111 dB, 112 dB, etc., but it cannot be 110.5 dB or 111.5 dB. Therefore, the decibel level of a siren is a discrete variable.

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Answer: mmmmmm nope thxs jk jk not really jokes

Step-by-step explanation: points for points

Answer:

2 nonreal solutions

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0 (a ≠ 0 )

then the nature of the roots are determined by the discriminant

b² - 4ac

• if b² - 4ac > 0 then 2 real and irrational solutions

• if b² - 4ac > 0 and a perfect square then 2 real and rational solutions

• if b² - 4ac = 0 then 2 real and equal solutions

• if b² - 4ac < 0 then no real solutions

5x² - 2x + 6 = 0 ← in standard form

with a = 5 , b = - 2 , c = 6

b² - 4ac

= (- 2)² - (4 × 5 × 6)

= 4 - 120

= - 116

since b² - 4ac < 0

then there are 2 nonreal solutions to the equation

in a situation where the sample size was increased from 29 to 39, the impact on the confidence interval option A) would become wider due to using the t distribution.

Confidence intervals are used to estimate the population parameter based on the sample data. The sample size is an important factor in determining the width of the confidence interval. The larger the sample size, the narrower the confidence interval, meaning the more precise the estimate. However, when the sample size is small, the confidence interval is wider. This is because the t distribution is used when the sample size is small, which leads to a wider confidence interval than when the normal distribution is used for larger sample sizes. So, when the sample size is increased from 29 to 39, the confidence interval becomes wider due to the use of the t distribution. This means the estimate becomes less precise, but more representative of the population.

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\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 4.75\%\to \frac{4.75}{100}\dotfill &0.0475\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases} \\\\\\ A = 20000\left(1+\frac{0.0475}{4}\right)^{4\cdot t} \implies A = 20000\implies A=20000(1.011875)^{4t}\)

The balance after 5 years would be near around 5661 dollars.

What is compound interest?

Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on principal plus interest.

First, convert R as a percent to r as a decimal

r = R/100

r = 2.5/100

r = 0.025 rate per year,

Then solve the equation for A

\(A = P(1 + r/n)^{nt}\\\\A = 5,000.00(1 + 0.025/2)^{(2)(5)}\\\\A = 5,000.00(1 + 0.0125)^{10}\\\\A = 5,661.35\)

Hence the balance after 5 years would be near around 5661 dollars.

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Answer:

He started with $190

Answer:

190

Step-by-step explanation:

because $70 + $120 gives us $190 of how we got the answer is before he spending the 70$ he had $190.

Answer:

4.69

Step-by-step explanation:

13.76/4 +1.25