In this activity, you are tasked with designing an airbag for a company that creates airbags for automobiles. You must design the driver’s front airbag for a specific car model so it will protect the driver as effectively as possible. For this car, the airbag must have a volume of 58 liters when fully inflated. To provide an adequate cushion for the driver’s head, the air pressure inside the airbag should be 4.4 psi. This pressure value is in addition to the normal atmospheric pressure of 14.7 psi, giving a total absolute pressure of 19.1 psi, which equals 1.30 atmospheres.

Answer:

Repeated SN2 reactions occur leading to the formation of a racemic mixture

Explanation:

S-2-iodooctane is a chiral alkyl halide with an asymmetric carbon atom. The presence of an asymmetric carbon atom implies that it can rotate plane polarized light and thus lead to optical isomerism. The two configurations of the compound are R/S according to the Cahn-Prelong-Ingold system.

However, when S-2-iodooctane is treated with sodium iodide in acetone, repeated SN2 reactions occur since the iodide ion is both a good nucleophile and a good leaving group. Hence a racemic modification is formed in the system with time hence we end up with (±)- Iodooctane.

750 x 14,0067 u = 10,505.025 g

Explanation:

Find number of moles in each reactant

SO2 moles=83/64 mol

H2S moles=83/34 mol

SO2 : H2S

8 : 16

1 : 2

(83/64) mol : (83/64)×2 mol

we need (83/32) moles of H2S to fully react with SO2

no of H2S moles needed to fully react with SO2> no of H2S moles involved in the reaction

83/32 mol> 83/34 mol

so we can see that H2S is the Limiting reagent

we should calculate no of product moles created from the reaction according to

Limiting reagent

H2S : S8

16.:3

1. :3/16

(83/34): 83/34×3/16

Molar mass of S8

=32×8

=256gmol-1

Maximum mass of S8 produced from the reaction;

n=m/M

m=(249/544)×256

=117.17 g

The percent yield of PbI2 is 27.20%. This means that in the experimental reaction, only 27.20% of the theoretically expected amount of PbI2 was obtained.

To calculate the theoretical yield of PbI2, we need to determine the limiting reactant. The limiting reactant is the one that is completely consumed and determines the maximum amount of product that can be formed.

First, we need to convert the volumes of the solutions to moles using the equation Molarity (M) = moles/volume (L).

For Pb(NO3)2:

moles of Pb(NO3)2 = (0.738 M) × (0.605 L) = 0.44679 moles

For KI:

moles of KI = (0.847 M) × (0.337 L) = 0.28516 moles

Next, we determine the stoichiometric ratio between Pb(NO3)2 and PbI2 from the balanced equation. It is 1:1, meaning that 1 mole of Pb(NO3)2 produces 1 mole of PbI2.

Since Pb(NO3)2 is the limiting reactant with 0.44679 moles, the theoretical yield of PbI2 is also 0.44679 moles.

To calculate the mass of PbI2, we need to use its molar mass. The molar mass of PbI2 is 461 g/mol.

Mass of PbI2 = (0.44679 moles) × (461 g/mol) = 205.59 g

Therefore, the theoretical yield of PbI2 is 205.59 g.

To calculate the percent yield of PbI2, we need the experimental yield, which is given as 55.9 g.

Percent yield = (Experimental yield / Theoretical yield) × 100

Percent yield = (55.9 g / 205.59 g) × 100 = 27.20%

The percent yield of PbI2 is 27.20%. This means that in the experimental reaction, only 27.20% of the theoretically expected amount of PbI2 was obtained.

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There are approximately 0.16 moles of gas present in the lungs.

To solve this problem, we can use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas:

PV = nRT

where R is the gas constant.

First, we need to convert the temperature to Kelvin:

T = 37°C + 273.15 = 310.15 K

Next, we can plug in the given values:

P = 1.0 atm

V = 4.0 L

T = 310.15 K

We also need to find the value of R, which depends on the units we are using for pressure, volume, and temperature. In this case, we are using atmospheres, liters, and Kelvin, so we can use the value:

R = 0.08206 L·atm/K·mol

Now we can rearrange the ideal gas law to solve for the number of moles:

n = PV/RT

n = (1.0 atm)(4.0 L)/(0.08206 L·atm/K·mol)(310.15 K)

n = 0.1638 mol

Therefore, there are approximately 0.16 moles of gas present in the lungs.

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The element with 20 protons has the atomic number of 20 and the element is calcium. The mass number if it contain 24 neutrons is 44. Hence the nuclear symbol of the ion is \(_{20}^{44}\textrm{Ca}\).

Calcium is 20th the element in periodic table and it is an alkali metal classified to s-block elements. The atomic number of an element is the number of its protons. For a neutral atom the number of electrons and protons are equal.

Calcium have 20 electrons and 20 protons. Hence the atomic number of Ca is 20. Mass number of an atom is the sum of number of number of protons and number of neutrons. Hence, mass number of calcium is 20 + 24 = 44. The nuclear symbol of Ca is thus \(_{20}^{44}\textrm{Ca}\).

An atom forms positive ions called cations when it loses electrons. When an atom gain electron it forms a negative ion called the anion. When Ca loses two electrons it forms Ca²⁺ ions. Hence, it is a cation and the number of electron in the ion is 20- 2= 18.

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Answer:

PbBr2 + LiNO3

And goodluck

The amount of energy required to change 20g of water to steam is +150 KJ/mol. The standard heat of vaporization of water is 7.5 KJ/mol.

The amount of energy required to convert a liquid to a vapour at constant temperature and pressure is known as latent heat. The heat of fusion is the energy required to convert a solid to a liquid, and the heat of sublimation is the energy required to convert a solid to a gas.

Given:

q = 150 KJ/mol.

m = 20gram

The standard heat of vaporization of water is calculated by given formula

Hv = q / m

Where,

Hv is heat of vaporization of water

q is heat energy

m is mass

By substituting given value in equation we get,

Hv = 150 / 20

= 7.5 KJ/mol

Thus, the standard heat of vaporization of water is 7.5 KJ/mol.

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Answer:

True is the answer okkkkkkkkkkkkkkkk

Answer:

True

Explanation:

For example, Potassium is represented by K which stands for Kalium in Latin.

The following is involved in bonding between atoms is electron

There are four type of chemical bonds essential for life to exist and it is ionic bond, covalent bond, hydrogen bond, and Vander wall interaction and all of these are different kind of bond to play various role in biochemical interaction and the electron on the outermost energy level of the atom are called valence electron and the valence electron are involved in bonding one atom yo another

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Answer:

552 g of LiNO₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mass of LiNO₃ =?

Next, we shall determine the number of mole of LiNO₃ in the solution. This can be obtained as follow:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mole of LiNO₃ =?

Molarity = mole /Volume

4 = mole of LiNO₃ / 2

Cross multiply

Mole of LiNO₃ = 4 × 2

Mole of LiNO₃ = 8 moles

Finally, we shall determine the mass of of LiNO₃ needed to prepare the solution. This is can be obtained as follow:

Mole of LiNO₃ = 8 moles

Molar mass of LiNO₃ = 7 + 14 + (16×3)

= 7 + 14 + 48

= 69 g/mol

Mass of LiNO₃ =?

Mole = mass /Molar mass

8 = Molar mass of LiNO₃ /69

Cross multiply

Molar mass of LiNO₃ = 8 × 69

Molar mass of LiNO₃ = 552 g

Thus, 552 g of LiNO₃ is needed to prepare the solution.

Salt hydrates are an important class of PCMs. An inorganic salt hydrate (hydrated salt or hydrate) is an ionic compound in which the ions attract a number of water molecules, which are then trapped inside the crystal lattice. A hydrated salt has the generic formula MxNy. nH2O.

Answer:

1. PEP is a feedback inhibitor of phosphofructokinase.

4. PEP inhibition of phosphofructokinase yields a sigmoidal velocity versus substrate curve.

6. The binding of PEP to one phosphofructokinase subunit causes a conformation change that affects the ability of the substrate to bind to the other subunits.

Explanation:

Phosphofructokinase-1, PFK-1, is an allosteric enzymes composed of four protein subunits.

Allosteric enzymes are enzymes that function through non-covalent binding of allosteric modulators which may be activators or inhibitors. They produce a characteristic velocity versus substrate sigmoidal curve. PFK-1 has a separate binding site for its substrate, fructose-6-phosphate and it's allosteric modulators: ATP, ADP or phosphoenolpyruvate, PEP.

The enzyme can exist in two conformations, the T-state (tense) or the R-state (resting). Binding of substrate causes a conformational change from T-state to R-state, whereas binding of allosteric inhibitors returns it to the T-state.

PEP, the product of step 9 in glycolysis, is an allosteric inhibitor of PFK-1. When it binds to the the allosteric site, it leads to conformational changes in PFK-1 from the R-state to the T-state which reduces the enzymes ability to bind the substrate. These changes are responsible for the sigmoidal velocity/substrate curve in allosteric enzymes.

Therefore, the true statements from the options above are 1, 4, 6.

Options 2,3 and 5 are wrong because PEP is a negative effector of PFK-1, thus its binding reduces the affinity of PFK-1 for its substrate. Also, PFK-1 being an allosteric enzyme has separate binding sites for its substrate and its modulators. Thus, there is no competition for active site binding by substrate and modulators.

The number of moles of CO2 produced is 0.021 moles

If the estimated volume of the balloon is wrong then the amount of glucose reacted must be more than is stated.

The respiration equation represents the chemical process of aerobic cellular respiration, which occurs in the mitochondria of cells and is the primary way in which cells generate energy in the form of ATP (adenosine triphosphate).

The equation of the reaction is;

C6H12O6 + 6O2 → 6CO2 + 6H2O + ATP

We know that;

Number of moles of glucose = 10 g/180 g/mol

= 0.056 moles

PV = nRT

n = PV/RT

n = 1 * 0.55/318 * 0.082

n = 0.021

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Answer:

Its D and E

Explanation:

i took the test and the other guy who answered gave u half of the answer

hope this helps

pls mark brainliest

The information which can be inferred about the Sun according to the graph include:

This is defined as a pictorial representation of data in an organized manner.

From the graph, we can infer that the Sun has an intermediate temperature and is less brighter than most stars.

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The number of particles of copper produced when 3.85 grams of Copper (II) Chloride is consumed is approximately \(1.728 * 10^2^2\) particles.

To determine the number of particles of copper produced when 3.85 grams of Copper (II) Chloride is consumed with excess aluminum, we need to use stoichiometry and the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between Copper (II) Chloride (CuCl2) and aluminum (Al) is:

\(3CuCl_2 + 2Al\) -> \(2AlCl_3 + 3Cu\)

From the balanced equation, we can see that for every 3 moles of\(CuCl_2\)consumed, 3 moles of Cu are produced.

First, we need to calculate the number of moles of \(CuCl_2\) in 3.85 grams. To do this, we divide the mass of\(CuCl_2\) by its molar mass. The molar mass of \(CuCl_2\) can be calculated by summing the atomic masses of its constituent elements: Cu (63.55 g/mol) and Cl (35.45 g/mol).

Molar mass of\(CuCl_2\) = 63.55 g/mol (Cu) + (2 * 35.45 g/mol) (Cl) = 134.45 g/mol

Number of moles of CuCl2 = 3.85 g / 134.45 g/mol ≈ 0.0287 mol

Since the stoichiometry of the reaction states that 3 moles of CuCl2 produce 3 moles of Cu, we can conclude that 0.0287 mol of CuCl2 will produce 0.0287 mol of Cu.

Finally, to calculate the number of particles (atoms or molecules) of copper produced, we multiply the number of moles of Cu by Avogadro's number, which is approximately \(6.022 * 10^2^3\)particles/mol.

Number of particles of Cu = 0.0287 mol * \(6.022 * 10^2^3\) particles/mol

Therefore, the number of particles of copper produced when 3.85 grams of Copper (II) Chloride is consumed is approximately \(1.728 * 10^2^2\)particles.

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The production of ammonia will be favored at high pressure and low temperature.

The term exothermic reaction has to do with a reaction in which the forward reaction is favored at lower temperatures.

Now looking at the reaction coordinate and the equation of the reaction, we know that the production of ammonia will be favored at high pressure and low temperature.

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Answer:

The correct option is D

Explanation:

Firstly, let's define the periodicity of these terms and then draw  conclusion from there.

Ionization energy is the amount of energy required to remove an electron from a gaseous atom in it's ground state. This property increases across a group in the periodic table.

Electronegativity is the measure of the property/tendency of an atom to attract an electron. This property also increases across a period. Thus, elements that have high electronegativity also have a high ionization energy.

Atomic radius is however the distance between the central nucleus to the outermost electron. This property decreases across the period. Thus, as electronegativity and ionization energy increases, atomic radius decreases.

From the above, it can be deduced that the correct option is d

Answer:high,small

Explanation:

I have the same test and I got it right

Answer:.

Explanation: Matter must have Mass and Volume to be considered matter!

Answer:

0.9 g (approximately)

Explanation:

Metal conductivity generally goes down or resistivity goes up with temperature goes up.

The new volume of the gas is 56.6 liters when the temperature is raised to 325 K and the pressure is lowered to 1.2 atm.

PV = nRT

Where R is the ideal gas constant. Since the number of moles is constant in this problem, we can simplify the ideal gas law to:

P1V1/T1 = P2V2/T2

Where the subscripts 1 and 2 refer to the initial and final states of the gas, respectively.

We can now plug in the given values for the initial state of the gas:

P1 = 2.3 atm

V1 = 25 L

T1 = 299 K

And the given values for the final state of the gas:

P2 = 1.2 atm

T2 = 325 K

We can then solve for V2:

P1V1/T1 = P2V2/T2

(2.3 atm)(25 L)/(299 K) = (1.2 atm)V2/(325 K)

V2 = (2.3 atm)(25 L)(325 K)/(1.2 atm)(299 K)

V2 = 56.6 L (rounded to three significant figures)

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Answer:

green gemstone

Explanation:

hope this helps someone

Like hydrogen fluoride (HF), water (H2O) is a polar covalent molecule. A water molecule has two poles: a positive charge on the hydrogen pole (side) and a negative charge on the oxygen pole due to the unequal sharing of electrons between the atoms and the asymmetrical form of the molecule (side).

The water molecule is referred to as electrically polar. Water molecules (H2O) have one oxygen atom, two hydrogen atoms, and polar covalent connections between them. Although a water molecule has no net charge, its polarity results in a slight positive charge on hydrogen and a slight negative charge on oxygen, which helps explain why water has attractive properties.

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Sure, what's the questions and I can get it for you, and if need further assist you.

To convert acetone (propanone) to propanal, you can use a two-step process involving reduction and oxidation reactions. Here's a general outline of the process:

1. Reduction of Acetone to Isopropanol:

First, you need to reduce acetone to isopropanol (2-propanol) using a reducing agent. Common reducing agents for this step include sodium borohydride (NaBH₄) or lithium aluminum hydride (LiAlH₄).

Reaction conditions:

- Acetone + NaBH₄ (or LiAlH₄) → Isopropanol

- Solvent: usually an alcohol (e.g., methanol or ethanol) or an ether (e.g., THF)

- Temperature: room temperature or slightly above

2. Oxidation of Isopropanol to Propanal:

Next, oxidize isopropanol to propanal using an appropriate oxidizing agent. A common oxidizing agent for this step is pyridinium chlorochromate (PCC), which selectively oxidizes primary alcohols to aldehydes without over-oxidizing to carboxylic acids.

Reaction conditions:

- Isopropanol + PCC → Propanal

- Solvent: an aprotic polar solvent (e.g., dichloromethane)

- Temperature: room temperature

- Avoid strong oxidizing agents like potassium permanganate (KMnO₄) or chromium trioxide (CrO₃) because they can over-oxidize the isopropanol to propionic acid.

The reagents are H2, Pd/C at step 1 and H2, Lindlar's cat at step 3. The reactants are 1.1) NaNH2, 1.2) 1-bromo-2 methylpropane, 2.1) NaNH2, 2.2) 2 butanone, and 2.3) H+.

When the base H2, Pd/C reagent reacts with any NaNH2, an acidic proton is initially abstracted, leaving carbon with a negative charge that will be counterbalanced by any plus. Now, this alliance will attack the chemical one bromo three methylpropane from the back, releasing a negative. And substance B is created. NaNH2 and Compound B will react. There is acidic hydrogen compound B present, and NaNH2 will eliminate it. 2 Butane reacts with hydrogen that is acidic  to produce Compound C which further reacts with reagent H2, Lindlar's cat to produce final product.

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Answer:

I dunno,  what is the answer

Explanation:

Answer:

Is this question multiple choice if it is i can most likely answer it!

Explanation: