in which condition the acceleration due to garvity is zero​

Answers

Answer 1

Answer:

When the object is infinitely far away from the planet, or when the planet's mass is zero (which is much less likely).

Explanation:

Using the formula for gravitational force:

Fg = GMm/r^2

Using Newton's 2nd law, F=ma, we can rewrite this equation as

mg = GMm/r^2

cancel m from both sides

g = GM/r^2

the acceleration due to gravity is zero when the mass of the planet is zero, or the object is an infinite distance away from the planet. G is a constant.


Related Questions

This model shows DNA, chromosomes, and genes. If B is a cell and C is the nucleus, what is A?

Answers

Based on the information, we can infer that A. represents a Mitochondria.

What is a mitochondria?

Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.

Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.

Note: This question is incomplete. Here is the complete information:

Attached image

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This model shows DNA, chromosomes, and genes. If B is a cell and C is the nucleus, what is A?

How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s

Answers

ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

What is the difference between chronic and acute stress?

Acute stress is long-term, while chronic stress is short in duration.
Acute stress is short-term, while chronic stress endures over time.
Chronic stress varies by geographic location, while acute stress is universal.
Chronic stress is not harmful, while acute stress has negative consequences.

Answers

Answer:

The correct difference between chronic and acute stress is:

Acute stress is short-term, while chronic stress endures over time.

Explanation:

Acute stress refers to the immediate and temporary response of the body to a specific stressful event or situation. It is often characterized by a rapid increase in heart rate, heightened alertness, and the release of stress hormones like adrenaline. Acute stress is a normal and natural response to perceived threats or challenges, and once the stressor is removed or resolved, the body returns to its normal state.

On the other hand, chronic stress is long-term and persists over an extended period. It is typically caused by ongoing or recurring stressors, such as work pressures, financial difficulties, relationship problems, or chronic health conditions. Chronic stress can have a cumulative and prolonged impact on physical and mental well-being. It may lead to a range of health issues, including cardiovascular problems, weakened immune system, digestive disorders, anxiety, depression, and burnout.

Chronic stress is considered detrimental to overall health, while acute stress, when experienced in moderation, can actually be beneficial as it can enhance performance and help individuals deal with immediate challenges. It is important to manage chronic stress effectively through stress-reducing techniques, self-care practices, and seeking support when needed to prevent its negative consequences on health and well-being.

when i roll a ball down the ramp, does it have kinetic energy ?

Answers

Answer:

Explanation:

Yes, when a ball rolls down a ramp, it possesses kinetic energy. Kinetic energy is the energy associated with an object's motion. As the ball rolls down the ramp, it gains speed and its motion increases, resulting in an increase in its kinetic energy. The amount of kinetic energy the ball has depends on its mass and velocity.

Hope this answer your question

Please rate the answer and

mark me ask Brainliest it helps a lot

Answer:

Yes, when a ball rolls down a ramp, it possesses kinetic energy.

Explanation:

Kinetic energy is the energy associated with an object's motion. As the ball rolls down the ramp, it gains speed and its motion increases, resulting in an increase in its kinetic energy. The amount of kinetic energy the ball has depends on its mass and velocity.

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A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).

Question 9 options:

a)

-21 N


b)

-241.0 m/s2


c)

-21.0 m/s2


d)

-8.2 m/s2


e)

8.2 m/s2

Answers

The acceleration of the falling obeject of mass 2.55 kg is  -8.2 m/s². And the right option is d) -8.2 m/s².

What is acceleration?

This can be defined as the rate of change of velocity.

To calculate the acceleration of the object, we use the formula below.

Formula:

a = (R-mg)/m............. Equation 1

Where:

a = Acceleration of the objectm = Mass of the objectR = Air resistanceg = Acceleration due to gravity.

Note: Taking forces acting upward to be positve and downward force to be negatove,

From the question,

Given:

R = 4 Nm = 2.55 kgg = 9.8 m/s²

Substitute these values into equation 2

a = [4-(2.55×9.8)]/2.55a = -20.99/2.55a = -8.2 m/s²

Hence, The acceleration of the object is -8.2 m/s².

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Do you think antiseptic creams and lotions play an important part in our day
to day life? ​

Answers

Answer:

no, otherwise they just cause a side effect on our lives

yes, it keeps your skin from getting burnt when you play out side so much.

2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m

Answers

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Brainliest if correct Question 6 of 10
According to the law of conservation of energy, which statement must be
true?
A. There is only one form of energy.
B. Energy that is transformed is neither destroyed nor created.
C. The total energy in a system can only increase over time.
D. Energy can change only from nuclear to chemical

Answers

Answer:

B. Energy that is transformed is neither destroyed nor created.

Explanation:

Hope this helped! :)

A sample of an ideal gas has a volume of 0.0100 m^3, a pressure of 100 x 10^3 Pa, and a temperature of 300K. What is the number of moles in the sample of gas?

Answers

Answer:

Explanation:

pV = nrT

n = PV/RT

n = (100*10^3)(.01)/(300*0.082057)

n = 40.62 moles

A lightbulb manufacturer makes bulbs with different "color temperatures," meaning that the spectrum of light they emit is similar to a blackbody with that temperature. Assuming the emitting areas of the filaments in two bulbs with color temperatures of 2,000 K and 4,000 K are the same, which of the two is the brighter?

Answers

Answer:

The bulb with higher temperature(4000 K) will be brighter

Explanation:

From the question we are told that

     The color temperature  for first bulb is  \(T_1 = 2000K\)

        The color temperature  for second bulb is  \(T_2 = 4000K\)

Generally the emission power of black body radiation is mathematically represented as

     \(E = \sigma T^4\)

Where  \(\sigma\) is the Stefan-Boltzmann constant  with a value \(\sigma = 5.67 * 10^{-8} W m^{-2} K^{-4.}\)

Now for \(T_1 = 2000K\)

      \(E_1 = 5.67*10^{-8} * (2000)^4\)

       \(E_1 = 907.2 \ W/m^2\)

At  \(T_2 = 4000K\)

       \(E_2 = 5.67*10^{-8} * 4000\)

        \(E_2 = 14515.2 \ KW/m^2\)

Looking at the result we got we see that  the emission power  for the higher temperature bulb is higher, this means that its power to emit in the visible spectrum range would be higher  

So the bulb with higher temperature will be brighter

       

Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

Answers

It’s A trust me thank you………….

A police car is traveling due east at a speed of 15.0 m/s relative to the earth. You are in a convertible following behind the police car. Your car is also moving due east at 15.0 m/s relative to the earth, so the speed of the police car relative to you is zero. The siren of the police car is emitting sound of frequency 500 Hz. The speed of sound in the still air is 340 m/s.
a.) What is the speed of the sound waves relative to you?
b.) What is the wavelength of the sound waves at your location?
c.) What frequency do you detect?

Answers

Answer:

A.) 355 m/s

B.) 0.71 m

C.) 500Hz

Explanation:

Given that a police car is traveling due east at a speed of 15.0 m/s relative to the earth. You are in a convertible following behind the police car. Your car is also moving due east at 15.0 m/s relative to the earth, so the speed of the police car relative to you is zero. The siren of the police car is emitting sound of frequency 500 Hz. The speed of sound in the still air is 340 m/s

a.) What is the speed of the sound waves relative to you?

Since the car is moving away from the observer, the relative velocity will be:

Relative velocity = 340 + 15

Relative velocity = 355 m/s

b.) What is the wavelength of the sound waves at your location?

Using the wave speed formula

V = frequency × wavelength

Make wavelength the subject of formula.

Wavelength = Velocity / frequency

Wavelength = 355/500

Wavelength = 0.71 m

c.) What frequency do you detect?

Fo = Fs ( C + V ) / ( C + v )

Fo = Fs

That is, the frequency of the observer will be equal to the frequency of the source.

Therefore, Fo = 500Hz

Show your work
A 2.0 kg block rests on a level surface. The coefficient of static friction is µs = 0.50, and the coefficient of kinetic friction is µk = 0.30. A horizontal force, F, is applied to the block. As F is increased, the block begins moving.

a)Find the minimum force, F, required for the block to just start to move.
b)Find the force, F, required for the block to continue to move at a constant velocity.
c)Explain what happens to the motion of the block if a force is applied greater than those found above.

Answers

a. The minimum force required to start moving the block is 9.8 N

b.  The force required to continue moving the block at a constant velocity is 5.88 N.

c. If a force greater than 9.8 N is applied, the block will start moving and continue to move until the applied force is less than 5.88 N.

How to calculate?

a. Force = μs * N

N = m * g = 2.0 kg * 9.8 m/s^2 = 19.6 N

Force = μs * N = 0.50 * 19.6 N = 9.8 N

b. Force = μk * N = 0.30 * 19.6= 5.88 N N

c. In conclusion, If a force greater than 5.88 N is applied, the block will accelerate. If a force less than 5.88 N is applied, the block will decelerate and eventually stop if the force becomes less than the force of static friction (9.8 N).

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Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1360 N. Assume that the player's foot is in contact with the ball for 5.85 times 10^{-3} s. (Show your work)
please

Answers

Answer:

7.59Ns

Explanation:

Given parameters:

Force  = 1360N

Time of contact  = 5.85 x 10⁻³s

Unknown:

Impulse  = ?

Solution:

The impulse of the ball is given as:

        Impulse  = Force x time

       Impulse  = 1360 x 5.85 x 10⁻³ = 7.59Ns

Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up a frictionless hill, with a slope of 15.80, with a constant force in the direction of the incline, such that there is a total acceleration of 2.53 m/s2 for the system

Answers

Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of

tan(θ) = 15.80   →   θ ≈ 86.38°

The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of

F = P - (M + m) g sin(θ) = (M + m) a

(see the attached free body diagram)

where

P = magnitude of the push

g = 9.80 m/s²

a = 2.53 m/s²

and M and m are the given masses.

Then the system requires a push of

P = (M + m) (a + g sin(θ))

P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

P ≈ 233 N

If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is

F = T - M g sin(θ) = M a

where

T = tension in the rope

Then

T = M (a + g sin(θ))

T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

T ≈ 175 N

Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up

An object of mass 3.0 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the object in the +x direction. The Force-time graph is shown below. What is the net impulse delivered by the applied force?

Answers

Answer:

120

Explanation:

because it is horizontal

An object of mass 3.0 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the object in the +x direction. The Force-time graph is shown below. The net impulse delivered by the applied force is 102 joule.

What is force ?

A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Force is used to describe a body's tendency to modify or change its state as a result of an external cause. When force is applied, the body can also alter its size, shape, and direction. kicking a ball, pushing and pulling on the door, or kneading dough are a few examples.

We know the Impulse = Area of the Graph

= ( 6 × 4) + 0.5 × 2 × 6

= 30 sec

For First 4 sec

Acceleration = 6 ÷ 3

= 2 m/sec²

S = 0.5 × 2 × 4²

= 16 m

Therefore, work Done = 6 × 16

= 96 J

Then, Average force

= ( 6 - 0 ) ÷ 2

= 3 N

Acceleration = 1 m/sec²

S = 0.5 × 1 × 2²

= 2 m

Work = 3 × 2

= 6 J

Total Work = 96 + 6

= 102 J

Thus, The net impulse delivered by the applied force is 102 joule.

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An electrical space heater has a resistance of 69 Ω and draws 2.92 A of current. How much power does it use?

Answers

ANSWER:

588.32 watts

STEP-BY-STEP EXPLANATION:

Given:

Resistance (R) = 69 Ω

Current (I) = 2.92 A

We can calculate the power as follows:

\(\begin{gathered} P=I^2\cdot R \\ \\ \text{ We replacing:} \\ \\ P=2.92^2\cdot69 \\ \\ P=588.32\text{ W} \end{gathered}\)

The power used is 588.32 watts

You are a passenger in a truck that gets stuck in mud. You and the driver use a tree branch as a lever to lift up the truck. You apply an effort force of 600 N to the branch. The back of the truck weighs 2400 N. What is the mechanical advantage of the branch-lever?​

Answers

The truck's cargo weighs 2400 N. The department has a mechanical advantage of 4.

What do mechanical talents entail?

Combining hard and soft abilities in areas like arithmetic, computing, design, and interaction make up the talents required for mechanical engineering. Because they operate in a variety of fields, such as the manufacturing, science, and automotive manufacturing, engineers in the mechanical technology profession have one of the broadest scopes.

What three categories of mechanical are there?

Longitudinal, transversal, as well as pressure waves are the three different forms of physical phenomena. They differ based on how the medium's atomic constituents behave when the stage's energy goes through. Wind farms that are powered by steam, water, winds, gas, or hydrocarbons are a few examples of this. Other sources of energy are frequently produced through machinery.

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H3C- CH2-CH2-CH2-CH3name formula HC/// C-CH2-CH3name formula

Answers

1.

The number of the carbon atom is five. All the carbon atom is single-bonded.

The formula name of the above is Pentane.

The number of the carbon atom is four. All the carbon atom is single-bonded except one triple bond at the first place.

The formula name of the above is 1-butyne.

Please help me with the highlighted part! I dont know the answer.

Please help me with the highlighted part! I dont know the answer.

Answers

Diamond, graphite and fullerenes (substances that include nanotubes and 'buckyballs' , such as buckminsterfullerene) are three allotropes of pure carbon. In all three allotropes, the carbon atoms are joined by strong covalent bonds, but in such different arrangements that the properties of the allotropes are very different.

Because of their distinctive structural makeup, graphite and diamond are distinct materials. Both have extremely high melting points due to their giant covalent structures. Diamond is incredibly strong and hard due to the four covalent links that each carbon atom in the mineral has with other carbon atoms. However, because each carbon in graphite is connected to three other carbons, it forms in layers.

Even though graphite is used to make pencils, despite the fact that each carbon atom only has three bonds, the layers are actually highly strong and have delocalized "free" electrons between them. Graphite appears soft because these electrons act as a lubricant between layers, allowing them to slide over one another. Graphite conducts electricity due to the free electrons. Diamond does not carry electricity because it lacks these free electrons.

There are more than three allotropes of carbon. These include diamond, graphite, graphene, carbon nanotubes, fullerenes, and carbon nanobuds.

Diamond

In a three-dimensional array, four additional carbon atoms are covalently attached to each carbon atom in a diamond. In essence, a diamond is one enormous molecule.

Graphite

The carbon atoms in graphite are bonded together in sheets of connected hexagons that resemble chicken wire. In essence, each sheet is a single molecule.

Each carbon atom in a sheet establishes solid covalent bonds with three other carbon atoms. The only forces keeping the sheets packed together are the modest intramolecular forces.

Graphene

In the form of a single sheet of graphite that is only one atom thick, graphene is made up entirely of carbon.

Nanocarbon tubes

Graphene sheet wrapped into a cylindrical tube of carbon atoms is how a carbon nanotube looks. Each atom connected to three other atoms, and the tube is one atom thick.

C60 and buckminsterfullerene

A single sheet of carbon atoms that has been folded into a spherical is what makes up buckminsterfullerene. Three additional atoms are connected to each carbon atom. With a carbon atom at each of the 20 hexagonal and 12 pentagonal corners, sixty carbon atoms are arranged in the shape of a ball.

There are numerous other known carbon balls, such as C70, C76, C84, and C540. They are collectively referred to as "buckyballs" or "fullerenes" and have varying amounts of pentagons and hexagons.

Nanocarbon buds

An allotrope of carbon called carbon nanobuds has fullerene-like "buds" that are covalently bonded to the sidewalls of carbon nanotubes.

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A person has a mass of 1000 g and an acceleration of 20 M/S/S what is the force on the person

Answers

Answer:

The answer is 20 N

Explanation:

The force acting on an object can be found by using the formula

force = mass × acceleration

From the question

mass = 1000 g = 1 kg

acceleration = 20 m/s²

We have

force = 20 × 1

We have the final answer as

20 N

Hope this helps you

60.96-mile distance in kilometers

Answers

Answer:

98.105610 Kilometers

Explanation:

Rounded to 8 digits

Answer:

98.11 km

Explanation:

60.96 mi (5280ft/mi)(12 in/ft)(2.54 cm/in)(1 m/ 100cm)(1 km/1000 m) = 98.10561024 km

however, reporting this precision to the nearest hundred millionth of a kilometer is silly as we only know the mile dimension to the nearest hundredth of a mile.

A hundredth of a mile is 5280/100 = 52.8 ft or just over 16 m

It would only be a little bit of a presumption to give our precision to the nearest 10 meters as I have done.

This also fits neatly into the significant digits rule. Both the original dimension and the converted dimension have four significant digits.

Six identical elements are connected in a battery whose internal resistance is 6Ω. Resistors R₁=14Ω and R₂ are connected to the battery, the total resistance of the external circuit is R=7Ω and the current flowing in it is 4 A. Determine the resistance of the second resistor and the internal EDS of the elements .

Six identical elements are connected in a battery whose internal resistance is 6. Resistors R=14 and

Answers

Answer:

Using Ohm's Law, we can calculate the voltage of the battery as V = IR = (4 A)(7 Ω) = 28 V.

The total resistance of the circuit is R = R₁ + R₂ + r, where r is the internal resistance of each element.

We know that R₁ = 14 Ω and R = 7 Ω, so we can solve for R₂:

R₂ = R - R₁ = 7 Ω - 14 Ω = -7 Ω

This is a negative resistance, which doesn't make sense physically. However, it indicates that there is an error in the problem or the calculations.

To find the internal EDS of the elements, we can use the equation:

V = ε - Ir

where V is the voltage of the battery, ε is the internal EDS of each element, I is the current flowing in the circuit, and r is the internal resistance of each element.

We know that V = 28 V, I = 4 A, and r = 6 Ω, so we can solve for ε:

ε = V + Ir = 28 V + (4 A)(6 Ω) = 52 V

Therefore, the internal EDS of each element is 52 V.

A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?

Answers

Answer:

85

Explanation:

soln

given that;

frequency=17Hz

wavelength=5m

speed?

formula for wavelength is;

wavelength= speed/frequency

then ; making v the subject formula

we have that v=wavelength*frequency

v=17*5=>85ms

Jacobie wanted to test the projectile motion of a pumpkin. His hypothesis was if the pumpkin had a larger mass, then the higher he could throw it, because the larger pumpkins would have more force. He bought three orange pumpkins and tested them all on the same day. His results are shown at right. Does the data support his hypothesis?

Answers

The data does not support his hypothesis because the heaviest mass travelled the least distance.

How does mass affect the height travelled by an object?

The weight of an object is the force of gravity acting on the object and the force of gravity increases with increase in the mass of the object.

W = mg

where;

m is the mass of the objectg is acceleration due to gravity

Based on law of conservation of energy;

P.E = K.E

mgh = ¹/₂mv²

h = ( v² ) / ( 2g )

The height travelled by an object increases with increase in speed of the object and heavier objects will have greater speed, hence travel greater height.

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The complete question is below:

Jacobie wanted to test the projectile motion of a pumpkin. His hypothesis was if the pumpkin had a larger mass, then the higher he could throw it, because the larger pumpkins would have more force. He bought three orange pumpkins and tested them all on the same day. His results are shown at right. Does the data support his hypothesis?

5kg = 10meters

10kg = 5 meters

15kg = 1 meter

while keeping your gaze forward, a rabbit runs in front of you from left to right. which of the following structures is involved in the visual pathway to see the rabbit when it's to your right, just before it disappears out of sight?

Answers

From the retina to the brain, structures in the visual pathway relay visual information.

What is meant by visual pathway?

Structures in the visual pathway transmit visual data from the retina to the brain. Many abnormalities of the visual field are brought on by lesions in that pathway.

Beginning with the retina, whose ganglion cell axons comprise the optic nerve, the basic visual pathway is made up of a relay system. The nasal fibers of the contralateral nerve join the temporal fibers of the opposite nerve as the optic nerve fibers from each eye hemidecussate in the optic chiasm (OC).

A visual feeling is conveyed from the retina to the brain along the visual pathway. This consists of a cornea, a lens, nerve fibers that transmit visual perceptions from the retina to the optic nerve, and a lens and cornea that focus images on the retina.

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A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.

Answers

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Identify the following compounds as polar covalent or nonpolar covalent: HBr, Cl2, and H2O.

Answers

Answer:

HBr- polar covalent

Cl2 - nonpolar covalent

H2O - polar covalent

Explanation:

Covalent bonds are chemical bonds that holds atoms of elements in such a way that electrons are shared between the atoms. However, based on the electronegativity differences between elements, compounds can either be polar covalent or nonpolar covalent.

Polar covalent bonds are formed when electrons are unevenly shared between two atoms based on difference in their electronegativities i.e. the more electronegative atom pulls more of the electrons. For example, in the case of HBr and H2O, Bromine and Oxygen atoms are more electronegative, hence, they pull more electrons making the electron sharing unequal, hence, a POLAR COVALENT BOND forms.

Non polar covalent bonds, contrarily, occurs when electrons are shared equally or evenly. This is so because the atoms of the elements involved have the same electronegativity. For example, Cl2 contains two atoms of Chlorine (Cl), which has the same electronegativity, hence, electrons between the two atoms are shared equally to form a NONPOLAR COVALENT BOND

HBr is polar covalent, Cl₂ - nonpolar covalent and H₂O is polar covalent in nature.

What is a polar covalent bond?

When atoms with differing electronegativities share electrons in a covalent link, the result is a polar covalent bond.

Consider the molecule of hydrogen chloride (HCl). In order to generate an inert gas electron configuration, each atom in HCl requires one extra electron.

Covalent bonds are chemical bonds that keep atoms of different elements together while sharing electrons.

Compounds can be polar covalent or nonpolar covalent depending on the electronegativity variations between components.

When electrons are unevenly divided between two atoms due to differences in their electronegativities, polar covalent connections are created.

The more electronegative atom draws more electrons. In the case of HBr and H2O, for example, the Bromine and Oxygen atoms are more electronegative,

Therefore they draw more electrons, causing the electron sharing to be uneven, resulting in the formation of a polar covalent bond.

Hence HBr is polar covalent, Cl₂ - nonpolar covalent and H₂O is polar covalent in nature.

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A mass of 240 grams oscillates on a horizontal frictionless surface at a frequency of 2.5 Hz and with amplitude of 4.5 cm.
a. What is the effective spring constant for this motion?
b. How much energy is involved in this motion?

Answers

Answer:

(a) The spring constant is 59.23 N/m

(b) The total energy involved in the motion is 0.06 J

Explanation:

Given;

mass, m = 240 g = 0.24 kg

frequency, f = 2.5 Hz

amplitude of the oscillation, A = 4.5 cm = 0.045 m

The  angular speed is calculated as;

ω = 2πf

ω = 2 x π x 2.5

ω = 15.71 rad/s

(a) The spring constant is calculated as;

\(\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\k = m\omega ^2\\\\where;\\\\k \ is \ the \ spring \ constant\\\\k = (0.24) \times (15.71)^2\\\\k = 59.23 \ N/m\)

(b) The total energy involved in the motion;

E = ¹/₂kA²

E = (0.5) x (59.23) x (0.045)²

E = 0.06 J

To test the performance of its tires, a car
travels along a perfectly flat (no banking) circular track of radius 96.6 m. The car increases
its speed at uniform rate of
at ≡((d |v|)/dt) = 4.87 m/s^2
until the tires start to skid.
If the tires start to skid when the car reaches
a speed of 21.1 m/s, what is the coefficient of
static friction between the tires and the road?
The acceleration of gravity is 9.8 m/s^2

Answers

The coefficient of  static friction between the tires and the road is 1.987.

What is Static friction?

Radius of the track, r =  516 m, Tangential Acceleration =  3.89 m/s^2 and Speed,v =  32.8 m/s

The radial Acceleration is given by, Now the total acceleration is The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of  static friction is, From (1) and (2), Substituting the values, we get friction is 1.987.

Therefore, The coefficient of  static friction between the tires and the road is 1.987.

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