Information:



A jet of steam at 100℃ is directed for a short time on to a large block of ice at 0℃. Some of the steam condenses to form water and some ice is melted. The condensed steam forms 0. 40 kg of water at 0℃.



Questions:



1. Calculate the heat given out by this steam in changing to water without change in temperature. [Take the specific latent heat of vaporization of water as 2 200 kJ/kg].



2. Calculate the heat given out by this water as it cools to the temperature of the ice. [Take the specific heat capacity of water to be 4. 2 kJ/(kg K). ]

Answer:

b

Explanation:

The second option is the correct answer to the question. The complete question is attached

In the beginning, the cart started from rest and moved to the right. The movement represents positive acceleration

In the middle, there is no change in velocity hence no acceleration. This means that the value of acceleration is zero

A the end, the cart had a negative acceleration which brings the cart to rest.

Acceleration refers to the change in velocity with time. Usually when there is no change in velocity acceleration is zero. The value can also be positive or negative depending on the velocity.

When there is an increase in velocity, the result is positive acceleration but in a situation when there is a decrease in velocity the result is negative acceleration. At the peak pf negative acceleration the result is to put the object accelerating to a stop.

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Answer:

time

Explanation:

power = work done ÷ time

The combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, The source strength is required to simulate flow around the body is (m)= 94.2 kg.

Force is a physical appearance that happen on a object of some amount of masses and then it changes it form and move a bit that called the force. It is a vector quantity. It can be measured in Newton, Dyne.

To calculate the source strength is required to simulate flow around the body we are using the formula here is,

v= m/2*π*b

Or, m= 2*π*b*v

Here we are given,

b=  The thickness of a certain body has the shape of a half-body = 2*r = 2* 0.5 = 1 m

v = The velocity of the object. = 15 m/s.

We have to calculate the values of the source strength is required to simulate flow around the body = m kg

Now we put the values in above equation we get,

m= 2*π*b*v

Or, m= 2*π*1*15

Or, m= 94.2 kg

so we can say that , The source strength is required to simulate flow around the body is (m)= 94.2 kg

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Answer:

the net force or resultant force

The given statement is true. We need direction to get to someplace, because without direction, instructions to get someplace would not make sense.

Direction is the way that you need to travel to get from one place or object to another place or object. It's usually measured in terms of compass directions: East, West, North, and South. Direction is the most important thing you need to know when you're lost.

Direction is used to find out where things are in relation to other things. Occasionally, direction is vague, as if we talk about things being in the common direction. For geographic purposes, direction is more specific. Direction can describe position, like in the sentence Ani sits to the right of Budi.

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My day is alright! I just finished school for the day.. and I’m excited for the weekend! How was your day?

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s\)

v₂ = 4.2 m/s

b)

We will use the law of conservation of momentum here:

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)\)

v₂ = 5 m/s

Answer:

Fortunately, the potential for higher energy efficiency is great. ... For example, landlords of rental residential buildings are not motivated to pay for ... it over time, and the timeframes in which specific technologies can be expected to ... especially for small firms, and many industries prefer to expend their human and financial.    

4 Energy Efficiency | America's Energy Future: Technology. this is a site

Explanation:

Answer:

the car industry is one of the most important industry in the world as it aid easy transportation of goods and man.

Explanation:

cars and other automobiles have aid easy movement of people and goods from one place to another as it is more efficient (does not waste time as compared to traditional means of transportation.)and reliable.

Answer:

5.2 s

Explanation:

From the question given above, the following data were obtained:

Velocity = 7.5 m/s

Displacement = 39 m up

Time =?

The time taken for the cable cab to get to 39 m can be obtained as follow:

Velocity = Displacement / Time

7.5 = 39 / time

Cross multiply

7.5 × time = 39

Divide both side by 7.5

Time = 39 / 7.5

Time = 5.2 s

Thus, the time taken for the cable cab to get to 39 m up is 5.2 s

A particle in uniform circular motion requires a net force acting towards the center of the circle. So option A is correct.

The net force acting on a particle moving in a circular path is always directed towards the center of the circle. The motion of a particle in a circular path is characterized by the direction of its velocity and acceleration at each instant in time. These two vectors are always perpendicular to each other.The magnitude of the net force required to keep a particle in uniform circular motion depends on the mass of the particle and its velocity, as well as the radius of the circular path it is following. This force is referred to as the centripetal force and is always directed towards the center of the circle.The centripetal force is provided by some other object, such as a string or a gravitational field, which acts to pull the particle towards the center of the circle. Without this force, the particle would continue to move in a straight line tangent to the circle, rather than in a circular path.Therefore option A is correct.

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One second later its speed in meters per second is approximately a. 40 m/s.

Given that a heavy object is moving upward at 50 meters per second, we need to determine its speed one second later. To do this, we will consider the effects of gravity on the object's motion.

Gravity exerts a force on the object which causes it to decelerate. On Earth, the acceleration due to gravity is approximately 9.8 meters per second squared (m/s²) acting downwards. As the object is moving upwards, the gravitational force will reduce its speed by 9.8 m/s every second.

After one second, the object's speed will be reduced by 9.8 m/s. Therefore, the new speed can be calculated as follows:

Initial speed - deceleration due to gravity = New speed
50 m/s - 9.8 m/s = 40.2 m/s

Based on the available options, the closest approximation to the object's speed after one second is 40 m/s (option a).

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Answer:

Its not just a mere formula . It tells a hell lot about charges .

q = ne . As you know , q stands for charge and e stands for charge on an electron . As for n , it represents an integer.

This whole q=ne thing represents quantisation of charge. The formula tells us that charge is quantized ( in the form of small packets)

Every body on this small earth has a charge which has to be an integral multiple of ‘e’ . So , we represent charge on a body(q) as

q=ne.

Hence the formula .

I hope you got what I want to say .

Thanks for reading .

The Geiger-Marsden experiment was a series of experiments conducted by Ernest Marsden and Hans Geiger in 1909 that helped to explain the structure of atoms.

The experiment involved firing alpha particles at a thin sheet of gold foil and measuring the angles at which the particles were deflected.

The results of the experiment were unexpected: some of the alpha particles were deflected at large angles, and a few even bounced back in the direction from which they had come. This result could not be explained by the existing Thomson model of the atom, which proposed that atoms were made up of a positively charged "pudding" with negatively charged electrons scattered throughout.

The Bohr-Rutherford model of the atom, proposed by Niels Bohr and Ernest Rutherford, was able to explain the results of the Geiger-Marsden experiment. According to this model, atoms have a small, dense, positively charged nucleus at the center, with negatively charged electrons orbiting around it in specific energy levels.

The deflection of the alpha particles in the Geiger-Marsden experiment could be explained by the presence of the positively charged nucleus, which caused the alpha particles to deflect or bounce back when they came close to it. This led to the development of the modern atomic model, which includes the concept of energy levels and the specific arrangement of electrons within an atom.

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A gold leaf electroscope's cap develops a negative charge when a negatively charged rod is brought close to it; the case is then grounded, creating a negative charge in the leaf. Option D is correct.

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

Similar charges repel each other, whereas dissimilar charges attract each other.

The term "neutral" refers to an item that has no net charge. A charge is something experienced as a force in the electric and magnetic fields.

When a negatively charged rod is brought near the cap of a gold leaf electroscope whose case ad then is earthed, then the leaf has an induced negative charge.

Hence option D is correct.

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Answer:

20 cm and 180° of angular displacement

Explanation:

In this case, the displacement of a tip in an one hand clock is always twice the length of the hand, therefore:

D = 2 * L

D = 2 * 10

D = 20 cm

Now, we should note that from 12:15 am to 12;45 pm, the clock covers around 12.5 revolutions, and from here can calculate the angular distance:

AD = 12.5 * 360° = 4500°

And the angular displacement (A data you need to complement the displacement of the tip), is half a revolution so, if a revolution covers 360 ° then:

α = 1/2 * 360 = 180°

Hope this helps

Answer:

blue

Explanation:

blue is the only color being reflected, meaning it's the only one that will be visible

Identification of compounds can benefit from density. It is also a useful feature since it connects (or acts as a conversion factor between) a substance's mass and volume. Volume and mass are extended (or extrinsic) qualities of matter that are quantity dependent.

The force of an air mass acting on the earth's surface is known as atmospheric pressure. Remember that wind currents are created when the densities of two separate air masses differ.

Our wind currents are driven by the atmospheric pressure density, and denser air exerts a higher pressure than less dense air. Compared to the cold and dry air, the warm and humid air is less dense. The less dense air will then float on top of the thicker air in certain regions.

Therefore, Warm air masses rise while cold air masses descend because they are less dense.

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The strength of an electric field in which a charged particle of 3.0 X 10-9 C is 0.05m from the test charge is \(\[3.6 \times 10^8 \, \text{N/C}\]\).

The strength of an electric field can be calculated using the formula:

Electric field strength (E) = Force (F) / Test charge (q)

In this case, we are given the charge of the test particle (\(\[q = 3.0 \times 10^{-9} \, \text{C}\]\)) and the distance from the test particle to the charge creating the electric field (r = 0.05 m).

The force between two charges can be calculated using Coulomb's Law:

Force \(\[(F) = \frac{{k \cdot q_1 \cdot q_2}}{{r^2}}\]\)

where k is the electrostatic constant \(\[(k \approx 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2)\]\), q1 and q2 are the charges, and r is the distance between them.

In this scenario, we have a single charge creating the electric field, so q2 = 1 C (unit test charge). Substituting the given values into the formula, we get:

\(\[(F) = \frac{{k \cdot q_1 \cdot q_2}}{{r^2}}\]\)

\(\[F = \frac{{(8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2) \cdot (3.0 \times 10^{-9} \, \text{C}) \cdot (1 \, \text{C})}}{{(0.05 \, \text{m})^2}}\]\)

Simplifying the equation gives us:

F ≈ 1.0792 N

Now, we can calculate the electric field strength:

E = F / q

\(\[E = \frac{{1.0792 \, \text{N}}}{{3.0 \times 10^{-9} \, \text{C}}}\]\)

E ≈ 359,733,333 N/C

Rounded to the appropriate number of significant figures, the strength of the electric field is approximately\(\[3.6 \times 10^8 \, \text{N/C}\]\).

Therefore, the correct answer is \(\[3.6 \times 10^8 \, \text{N/C}\]\)

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According to given statement, the velocity of the second hockey puck after the collision is approximately -23 m/s.

To find the velocity of the second hockey puck after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Before the collision, the first hockey puck has a mass of 0.17 kg and is traveling to the right at 15 m/s. The second hockey puck has a mass of 0.11 kg, and we need to find its velocity after the collision.

The momentum of an object is calculated by multiplying its mass by its velocity. So, the momentum of the first hockey puck before the collision is:

Momentum of first hockey puck before collision = mass of first hockey puck x velocity of first hockey puck
Momentum of first hockey puck before collision = 0.17 kg x 15 m/s
Momentum of first hockey puck before collision = 2.55 kg·m/s

Since the first hockey puck comes to rest after the collision, its final momentum is zero:

Momentum of first hockey puck after collision = 0 kg·m/s

According to the principle of conservation of momentum, the total momentum before the collision (2.55 kg·m/s) is equal to the total momentum after the collision (0 kg·m/s). Therefore, we can set up an equation:

Total momentum before collision = Total momentum after collision

(0.17 kg x15 m/s) + (0.11 kg x velocity of second hockey puck) = 0 kg·m/s

Now we can solve for the velocity of the second hockey puck after the collision:

0.17 kg x 15 m/s + 0.11 kg x velocity of second hockey puck = 0 kg·m/s
2.55 kg·m/s + 0.11 kg x velocity of second hockey puck = 0 kg·m/s

To isolate the velocity of the second hockey puck, we can subtract 2.55 kg·m/s from both sides of the equation:

0.11 kg x velocity of second hockey puck = -2.55 kg·m/s

Then, divide both sides of the equation by 0.11 kg to solve for the velocity:

velocity of second hockey puck = -2.55 kg·m/s / 0.11 kg
velocity of second hockey puck ≈ -23.18 m/s

The velocity of the second hockey puck after the collision is approximately -23 m/s.

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Answer:

the correct answer to your problem I believe would be B

The black car has a speed of 10 m/s

The red car has a speed of - 7.9 m/s

The both cars meet at time = 4s

The position time graph shows the rate at which the position of a body is changing with time. The position of the body is plotted on the vertical axis and the time taken is plotted on the horizontal axis.

We can know how fast the object is going by taking the slope of the position time graph. This is known as the speed of the object. If we look keenly as the graph as we have it we can see that;

1) Speed of the black car = 10 - 0/ 1 - 0 = 10 m/s

2) Speed of the red car = 25 - 80/ 7 - 0 = -7.9 m/s

3 ) The both cars meet at time = 4s

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If the environmental lapse rate (ELR) of the atmosphere surrounding a rising parcel of air is greater than the dry adiabatic rate (DAR) of 10°C/1000m, certain conditions and phenomena can be inferred.

When the ELR is steeper than the DAR, it indicates a condition of instability in the atmosphere.

This means that the surrounding air cools at a faster rate than a rising parcel of air would if it were undergoing adiabatic cooling.

As a result, the parcel of air becomes warmer compared to its surroundings, making it less dense and causing it to continue rising.

The steep ELR exceeding the DAR signifies an environment conducive to the development of convective processes such as thunderstorms, cumulus clouds, and other forms of unstable atmospheric phenomena.

The increased lapse rate creates an environment where the parcel of air continues to rise and can reach higher altitudes, potentially leading to the formation of significant weather events and atmospheric instability.

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If you move a magnet at the same speed through a coil with fewer loops, the magnetic field passing through each loop will be stronger.

This is because the magnetic flux is distributed over fewer loops, so the magnetic field per unit area is greater.

As a result, the induced current in the coil will be greater since the rate of change of the magnetic flux is directly proportional to the magnitude of the induced electromotive force.

Therefore, the induced voltage in the coil will be larger in the coil with fewer loops than in the coil with more loops, assuming that all other factors are the same.

However, the overall power output of the coil may not necessarily be greater, as this will depend on other factors such as the resistance of the coil and the load connected to it

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Answer:

\(\vec v_0=30.99 \ m/s\)

Explanation:

Refer to the attached image.

Here is a link to another projectile problem that gives some useful information, https://brainly.com/question/32300395. Although, this problem was a special case where we could use the range formula. So, here’s a bit of information about when it’s applicable to use the range formula.

You can use the range formula only if these two things apply:

1. The projectile lands at the same height originally fired from

2. The projectile isn't fired horizontally, (i.e. θ≠0° )