Answer:
Yes, it is possible.
It is called humidity. The quantity is reduced as the temperature go down. That’s why it condenses in a fridge or in a air conditioner unit. To create vapor there is various ways such as heating (evaporation) or fogging of liquid water. It will stop when the vapor pressure is reached and it depends of the temperature. The vapor pressure of water is 101.32 kPa at 100°C, which is the atmospheric pressure at sea level. It means that at that pressure and that temperature and above the water is totally converted in gas in the boiling process.
8) What is the average value of acceleration due to gravity on the polar region of the earth?
ANSWER: About 9.832 m/s raised to a power 2
Explanation:
In combination , the equational bulge and the effects of the surface centrifugal force due to rotation that means sea level gravity increases from about 9.780 m/s raised to a power 2 at the equator to about 9.832m/s raised to a power 2 at the poles , so an object will weigh approximately 0.5% more at the poles than the equator
A solid cube just gets completely immersed in water when
a 0.5 kg mass is placed on it. If the mass is removed, the cube
is 5 cm above the water level. What is the length of each side of the cube?
(Density of water =1 kg/L
A. 8 cm
B. 10 cm
C. 20 cm
D. 6 cm
If possible can you also explain the answer.
Thank you!
Answer:
B. 10 cm
x^3 = 1 L
1 L = 1000 cm^3 (since 1 L = 1000 cm^3)
x^3 = 1000 cm^3
A satellite is in a circular orbit about the earth \(M_{E} = 5.9 x 10^{24} kg).\) The period of the satellite is \(1.38 x 10^{4}\) What is the speed at which the satellite travels? V = [Blank] [Units]
The gravitational force acting on satellite at an altitude R causes the centripetal acceleration it required.
Thus, (2R) 2 GMm = 2Rmv 2
What is the speed of a circularly orbiting earth satellite?
The required speed to do this—known as the circular satellite velocity—is around 8 kph, or 17,500 mph in more commonly used quantities. See how gravity affects the orbits of the Earth, Moon, and International Space Station in this additional PhET interactive.
While elliptically circling the planet, a satellite will accelerate as its height (or distance from the world) decreases and decelerate as its height (or distance from the earth) increases.
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Charge of uniform density (40 pC/m2) is distributed on a spherical surface (radius = 1.0 cm), and a second concentric spherical surface (radius = 3.0 cm) carries a uniform charge density of 60 pC/m2. What is the magnitude of the electric field at a point 2.0 cm from the center of the two surfaces?
Answer:
E = K Q / R^2 by Gauss' Law where Q is the charge enclosed by the surface of revolution and R is the distance from the enclosed charge
Since Q = d 4 pi r^2 where d is the charge density and r the radius of the inner sphere
E = K / R^2 * (4 d pi r^2) = 4 K pi d (r / R)^2 = 4 K pi d * 1/4
E = 9 * 10E9 * 3.14 * 40 * 10E-12 = 1.13 N / C
25. The length of a bow is L. When it vibrates in the fundamental mode with a length of 2 L, the frequency is f. Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is,
(i) 3fo
(iv) √3f
(ii) 6fo
(v) √6fo
(iii) f/3
Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)
When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.
In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.
When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.
Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.
If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.
Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)
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a quality of the substance that never changes and can be used to identify the substance
A boy and a girl stand facing each other at a roller skating ring then push off each other. If the girl has a mass of 30 kg and moves backward at 5m/s, what is yhe velocity of the boy skater if his mass is 50kg?
Solve using GUESCA method.
The velocity of the boy skater if the mass is 50kg is 3 m/s.
The GUESCA method stands for Given, Unknown, Equation, Substitution, Calculation, and Answer. Let's use this method to solve the problem.
Given:
Mass of the girl (m₁) = 30 kg
Velocity of the girl (v₁) = -5 m/s (negative sign indicates backward direction)
Mass of the boy (m₂) = 50 kg
Velocity of the boy (v₂) = unknown (to be calculated)
Unknown:
Velocity of the boy (v₂)
Equation:
According to the law of conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction. Mathematically, it can be expressed as:
(m₁ * v₁) + (m₂ * v₂) = 0
Substitution:
Plugging in the given values, we have:
(30 kg * -5 m/s) + (50 kg * v₂) = 0
Calculation:
Simplifying the equation, we get:
-150 kg·m/s + 50 kg·v₂ = 0
Rearranging the equation to solve for v₂, we find:
50 kg·v₂ = 150 kg·m/s
v₂ = 150 kg·m/s / 50 kg
v₂ = 3 m/s
Answer:
The velocity of the boy skater is 3 m/s.
Using the GUESCA method, we identified the given and unknown quantities, wrote the relevant equation, substituted the values, performed calculations, and obtained the answer.
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Wavelength is a measurement of ___________ , while period is a measurement of ___________ . *
Speed; time
Time; speed
Distance; time
Time; distance
Distance; speed
Speed; distance
distance ; time
Explanation:
wavelength is in metres [m]
period is in seconds [s]
A car's bumper is designed to withstand a 5.04 km/h (1.4-m/s) collision with an immovable object without damage to the body of the car. The bumper cushions the shock by absorbing the force over a distance. Calculate the magnitude of the average force on a bumper that collapses 0.255 m while bringing a 830 kg car to rest from an initial speed of 1.4 m/s.
Answer:
the magnitude of the average force on the bumper is 3189.8 N
Explanation:
Given the data in the question;
In terms of force and displacement, work done is;
W =\(F^>\) × \(x^>\)
W = \(Fxcos\theta\) ------- let this be equation 1
where F is force applied, x is displacement and θ is angle between force and displacement.
Now, since the displacement of the bumper and force acting on it is in the same direction,
hence, θ = 0°
we substitute into equation 1
W = \(Fxcos(\) 0° \()\)
W = \(Fx\) ------- let this be equation 2
Now, using work energy theorem,
total work done on the system is equal to the change in kinetic energy of the system.
\(W_{net\) = ΔKE
= \(\frac{1}{2}\)mv² - \(\frac{1}{2}\)mu² --------- let this be equation 3
where m is mass of object, v is final velocity, u is initial velocity.
from equation 2 and 3
\(Fx\) = \(\frac{1}{2}\)mv² - \(\frac{1}{2}\)mu²
we make F, the subject of formula
F = \(\frac{m}{2x}\)( v² - u² )
given that mass of car m = 830 kg, x = 0.255 m, v = 0 m/s, and u = 1.4 m/s
so we substitute
F = \(\frac{830}{(2)(0.255)}\)( (0)² - (1.4)² )
F = 1627.45098 ( 0 - 1.96 )
F = 1627.45098 ( - 1.96 )
F = -3189.8 N
The negative sign indicates that the direction of the force was in opposite compare to the direction of the velocity of the car.
Therefore, the magnitude of the average force on the bumper is 3189.8 N
6. The radius of a ball is (5.2 + 0.2) cm. The percentage
error in the volume of the ball is;
Explanation:
It is given that, the radius of a ball is \((5.2\pm 0.2)\ cm\).
We need to find the percentage error in the volume of the ball. The volume of a sphere is : \(V=\dfrac{4}{3}\pi r^2\)
The percentage error is given by :
\(\dfrac{\Delta V}{V}=3\dfrac{\Delta r}{r}\times 100\)
We have, \(\Delta r=0.2\) and r = 5.2
So,
\(\dfrac{\Delta V}{V}=3\times \dfrac{0.2}{5.2}\times 100\\\\\%=11\%\)
So, the percentage error in the volume of the ball is 11%
What effect does the finite of the black paper have on the field?
The effect of black papper on the field is that the black paper have a form of chimney effect. Thid is because the black paper heat up the space between the field and the body in order to allow an upward air current like a chimney. This air current adds to the cooling of the field.
Black paper absorb heat from the surrounding and generate it to current flow in the field.
What is a Field?A field refer to a egion in which each point has a physical quantity like time or gravitational or space which are connected and associated with the region.
Therefore, the black paper allow air current flow.
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how do wind turbines work?
Answer:
Wind turbines work on a simple principle: instead of using electricity to make wind—like a fan—wind turbines use wind to make electricity. Wind turns the propeller-like blades of a turbine around a rotor, which spins a generator, which creates electricity.
The picture shows two solutions of salt water. Which solution is more concentrated (has a higher concentration)?
Question 15 options:
The first solution is more concentrated
The second solution is more concentrated
The solutions have the same concentration.
In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated
When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.
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What is a blockchain? Select one: K a. None of these b. A consensus network that enables a new payment system and a completely digital money c. A shared public ledger on which the entire Bitcoin network relies ed. It is the first decentralized peer-to-peer payment network that is powered by its users with no central authority or middlemen
Forces at Time 1
Forces at Time 2
The arrows represent forces. Choose all that are correct when comparing the bicyclist at Time
1 and Time 2.
A. The bicyclist is moving faster at Time 2.
B. The bicyclist is moving faster at Time 1.
C. The bicyclist is applying more force on the pedals at Time 2.
D. The bicyclist is applying more force on the pedals at Time 1.
The bicyclist is applying more force on the pedals at Time 2. Option C
What is the image?If we look at the image that have been shown, we can be able to see that the force that is acting have been shows by the arrows that have been used to label the movement of the cyclist in the image that is shown here.
We can see that the forward arrow at the time 2 is seen to be larger than the forward arrow that is shown for time 1. The implication of this is that the cyclist is cycling harder and applying more force at time 2 than at time 1.
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The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route.
The given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.
During a pick-stage cart, the first bad you load into the vehicle is always placed on the bottom, while subsequent bags are arranged on top of the first bag, all inside the vehicle.
At any point on your route, any bad you tend to open becomes the last bag you load into the vehicle because the first bag is far below the bottom.
Thus, we can conclude that the given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.
"Your question is not complete, it seems to be missing the following information";
The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route. False/True
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What is the term for the force that holds protons and neutrons together in the nucleus of
an atom?
a electromagnetism
b. gravity
c. the strong force
d the weak force
(a) If two sound waves, one in a gas medium and one in a liquid medium, are equal in intensity, what is the ratio of the pressure amplitude of the wave in the liquid to that of the wave in the gas? Assume that the density of the gas is 2.27 kg/m3 and the density of the liquid is 972 kg/m3. The speed of sound is 376 m/s in the gas medium and 1640 m/s in the liquid. (b) If the pressure amplitudes are equal instead, what is the ratio of the intensities of the waves (of the one in the liquid to that in the gas)?
Answer:
(a) The ratio of the pressure amplitude of the waves is 43.21
(b) The ratio of the intensities of the waves is 0.000535
Explanation:
Given;
density of gas, \(\rho _g\) = 2.27 kg/m³
density of liquid, \(\rho _l\) = 972 kg/m³
speed of sound in gas, \(C_g\) = 376 m/s
speed of sound in liquid, \(C_l\) = 1640 m/s
The of the sound wave is given by;
\(I = \frac{P_o^2}{2 \rho C} \\\\P_o^2 = 2 \rho C I\\\\p_o = \sqrt{2 \rho CI}\)
Where;
\(P_o\) is the pressure amplitude
\(P_o_g= \sqrt{2 \rho _g C_gI} -------(1)\\\\P_o_l= \sqrt{2 \rho _l C_lI}---------(2)\\\\\frac{P_o_l}{P_o_g} = \frac{\sqrt{2 \rho _l C_lI}}{\sqrt{2 \rho _g C_gI}} \\\\\frac{P_o_l}{P_o_g} = \sqrt{\frac{2 \rho _l C_lI}{2 \rho _g C_gI} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ \rho _l C_l}{ \rho _g C_g} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ (972)( 1640)}{ (2.27)( 376)} }\\\\\frac{P_o_l}{P_o_g} = 43.21\)
(b) when the pressure amplitudes are equal, the ratio of the intensities is given as;
\(I = \frac{P_o^2}{2 \rho C}\\\\I_g = \frac{P_o^2}{2 \rho _g C_g}-------(1)\\\\I_l = \frac{P_o^2}{2 \rho _l C_l}-------(2)\\\\\frac{I_l}{I_g} = (\frac{P_o^2}{2 \rho _l C_l})*(\frac{2\rho_gC_g}{P_o^2} )\\\\\frac{I_l}{I_g} = \frac{\rho _gC_g}{\rho_lC_l} \\\\\frac{I_l}{I_g} = \frac{(2.27)(376)}{(972)(1640)}\\\\ \frac{I_l}{I_g} = 0.000535\)
you observe that a negatively charged plastic pen repels a charged piece of magic tape. you then observe that the same piece of tape is repelled when brought near a small metal sphere. you are wearing rubber soled shoes, and you touch the metal sphere with your hand. after you touch the metal sphere, you observe that the tape is attracted to the metal sphere. which of the following statements could be true. list all that apply, sep
The correct statements are options given below:
(The complete question is attached below)
According to the statement there is a force of repulsion between the two objects. Remember that two objects must have the same charge so that they repel each other.In this way if the tape is repelled by a plastic pen that is negatively charged, this allows us to appreciate that the tape is also negatively charged. Now if the tape repels the sphere, therefore the sphere is also negatively charged.Under these considerations the correct answers would be
2. Sodium ions from the salt water on your hand moved onto the sphere
4. The excess negative charge from the sphere spread out all over your body
6. Electrons from the sphere moved into the salt water on your skin, where they reacted with sodium ions
7. After you touched it, the metal sphere was very nearly neutral.
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Help me with these question and please explainnn
Explanation:
1. Impulse = change in momentum
J = Δp
J = mΔv
In the x direction:
Jₓ = mΔvₓ
Jₓ = (0.40 kg) (30 m/s cos 45° − (-20 m/s))
Jₓ = 16.5 kg m/s
In the y direction:
Jᵧ = mΔvᵧ
Jᵧ = (0.40 kg) (30 m/s sin 45° − 0 m/s)
Jᵧ = 8.49 kg m/s
The magnitude of the impulse is:
J = √(Jₓ² + Jᵧ²)
J = 18.5 kg m/s
The average force is:
FΔt = J
F = J/Δt
F = 1850 N
2. Momentum is conserved.
m₁u₁ + m₂u₂ = (m₁ + m₂) v
In the x direction:
(1000 kg) (0 m/s) + (1500 kg) (-12 m/s) = (1000 kg + 1500 kg) vₓ
vₓ = -7.2 m/s
In the y direction:
(1000 kg) (20 m/s) + (1500 kg) (0 m/s) = (1000 kg + 1500 kg) vᵧ
vᵧ = 8 m/s
The magnitude of the final speed is:
v = √(vₓ² + vᵧ²)
v = 10.8 m/s
3. Momentum is conserved.
m₁u₁ + m₂u₂ = (m₁ + m₂) v
In the x direction:
(0.8 kg) (18 m/s cos 45°) + (0.36 kg) (9.0 m/s) = (0.8 kg + 0.36 kg) vₓ
vₓ = 11.6 m/s
In the y direction:
(0.8 kg) (-18 m/s sin 45°) + (0.36 kg) (0 m/s) = (0.8 kg + 0.36 kg) vᵧ
vᵧ = -8.78 m/s
The magnitude of the final speed is:
v = √(vₓ² + vᵧ²)
v = 14.5 m/s
Explaining How Temperature Affects the Speed of a Wave
Does sound travel faster in a warm room or a cold room?
Explain your answer
Answer:
Warm Room
Explanation:
Sound, like any wave, is a transfer of energy from one particle to another.
As temperature rises, each particle will have more energy; they will collide into other particles more often.
As the frequency of collisions increase, the speed of which the sound wave is transferred increases.
Một chất điểm khối lượng m=200g chuyển
động chậm dần với vận tốc biến đổi theo qui luật
v=30 – 0,4t2 (SI). Lực hãm tác dụng vào chất điểm
lúc t = 5 giây là
A. 8 N B. 0,8 N C. 4 N D. 0,4 N
1. Which distance is the greatest?
O 7000 meters
O 99.99 meters
O 4.5 x 10³ meters
O 9.0 x 10² meters
Answer:
7000 meters
Explanation:
obviously 99.99 is less than 7000
10 cubed is 10 × 10 × 10, 1000, × 4.5 is 4500, which is less than 7000
10 squared is 100, which × 9 is only 900, which is also less than 7000
have a good day
what is the value of Stephen's constant ?
thankyou ~
As you will see in a later chapter, forces are vector quantities, and the total force on an object is the vector sum of all forces acting on it.In the figure below, a force F1 of magnitude 5.90 units acts on a box at the origin in a direction = 31.0° above the positive x-axis. A second force F2 of magnitude 5.00 units acts on the box in the direction of the positive y-axis. Find graphically the magnitude and direction (in degrees counterclockwise from the +x-axis) of the resultant force F1 + F2.Two forces act on a box. Force vector F1 acts up and right on the right side of the box at an acute angle above the horizontal. Force vector F2 acts vertically upwards on the top side of the box.
We are asked to determine the sum of the two vectors F1 and F2. To do that we will use the following triangle:
Therefore, substituting the magnitudes of the vectors the triangle is:
Now, to determine the magnitude of the resultant force "R" we will use the cosine law:
\(c^2=a^2+b^2-2ab\cos\theta\)Where:
\(\begin{gathered} c=\text{ opposite side to the 120\degree angle} \\ a,b=\text{ other sides of the triangle} \end{gathered}\)Now, we substitute the values:
\(R^2=5^2+5.9^2-2(5)(5.9)\cos(121)\)Solving the operations we get:
\(R^2=90.25\)Now, we take the square root to both sides:
\(\begin{gathered} R=\sqrt{90.25} \\ R=9.5 \end{gathered}\)Therefore, the magnitude of the sum of vectors is 9.5
Now, we determine the angle:
We need to determine angle "y". To do that we will determine the angle "x" using the sine law:
\(\frac{\sin A}{a}=\frac{\sin B}{b}\)Where:
\(\begin{gathered} a=\text{ side opposite to angle A} \\ b=\text{ ide oppoite to angle B} \end{gathered}\)Now, we plug in the known values:
\(\frac{\sin x}{5}=\frac{\sin121}{9.5}\)Now, we multiply both sides by 5:
\(\sin x=5\frac{\sin121}{9.5}\)Solving the operations:
\(\sin x=0.45\)Now, we take the inverse function of the sine:
\(x=\sin^{-1}(0.45)\)Solving the operations:
\(x=26.83\)Now, we have that since F1 is a vertical force then the sum of angles "x" and "y" must add up to 90:
\(x+y=90\)Now, we substitute the value of angle "x":
\(26.83+y=90\)Now, we subtract 26.83 from both sides:
\(\begin{gathered} y=90-26.83 \\ y=63.17 \end{gathered}\)Therefore, the angle of the sum of vectors is 63.17°.
No no no no. no no no no
1. A male African elephant can grow up to 14 feet tall and have a mass as large as 7,000 kg. What would
be the weight in Newtons of a male African elephant on the moon?
The weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.
To calculate the weight of a male African elephant on the moon, we need to use the formula:
Weight = mass × acceleration due to gravity
The mass of the elephant is given as 7,000 kg. However, the acceleration due to gravity on the moon is approximately 1/6th (0.1667) of the acceleration due to gravity on Earth, which is approximately 9.8 m/s².
Weight on the Moon = 7,000 kg × 0.1667 × 9.8 m/s²
Weight on the Moon = 7,000 kg × 1.6386 m/s²
Weight on the Moon ≈ 11,470.2 Newtons
Therefore, the weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.
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Could a solar powered spacecraft generate any electricity passing through Earth's umbral shadow?
Answer:
A solar powered spacecraft could not operate in the umbral shadow but could operate in penumbral shadow.
Write 1,000,000w
1,000m
0.001 cm using scientific notation
Answer:
1×10^6 w
1×10^3 m
1×10^(-3) cm
If an elevator accelerates upward at 10 ms−2 , what is the average blood pressure in the brain? What is the average blood pressure in the feet? If the elevator accelerates downward with the same acceleration, what is the average blood pressure in the brain and feet? take g = 10
The average blood pressure in the brain will be higher than the average blood pressure in the feet. the average blood pressure in the brain will be lower than the average blood pressure in the feet.
When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain and feet of a person changes.
Similarly, when the elevator accelerates downward with the same acceleration, the blood pressure in the brain and feet of a person changes.
Let's discuss them one by one:Blood Pressure When Elevator Accelerates Upward at \(10 ms^{-2}\)
When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain of a person increases, while the blood pressure in the feet of a person decreases.
This happens due to the gravitational force acting on the body.
Since the gravitational force on the head is greater than the gravitational force on the feet, the blood pressure in the brain increases while the blood pressure in the feet decreases.
Therefore, the average blood pressure in the brain will be higher than the average blood pressure in the feet.
Blood Pressure When Elevator Accelerates Downward at \(10 ms^{-2}\) When the elevator accelerates downward at \(10 ms^{-2}\), the blood pressure in the brain of a person decreases, while the blood pressure in the feet of a person increases.
This also happens due to the gravitational force acting on the body. Since the gravitational force on the head is less than the gravitational force on the feet, the blood pressure in the brain decreases while the blood pressure in the feet increases.
Therefore, the average blood pressure in the brain will be lower than the average blood pressure in the feet.
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