Answers
Answer:
There is no change in temperature until the phase transition is complete, at which point the temperature changes. Latent heat is measured in joules per kilogram of body weight. The process of vaporizing water requires much more energy; it would need 2256 kJ to convert 1 kilogram of liquid water at the standard boiling point (100oC at atmospheric pressure) to steam (water vapor).
Explanation:
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Related Questions
2 A car rounding a bend travels in an arc of a circle.
a What provides the centripetal force?
b Is a larger or a smaller centripetal force required if
(i) the car travels faster,
(ii) the bend is less curved,
(iii) the car has more passengers?
Answers
Answer:
a) the centripetal force causing the cat to turn in a circular path is due to friction between the car's tyres and the surface of the road.
b)
1) a larger centripetal force is required if the car travels faster
2) a larger centripetal force is needed when the bend is less curved.
3) when a car has more passengers, the mass of the car increases, therefore, a larger force is required to move the car.
Explanation:
The friction between the car's tire and the surface provides centripetal force and if the car travels faster, the bend is curved, or the car has more passengers it requires a larger centripetal force.
What is Centripetal force?When an object is moving in a curve path then a force is acting radically in the object this force is called centripetal force, this force helps to maintain the object in the curve e.g. if a car is moving in a well, so the centripetal force is responsible, so the car is not falling. The SI unit used to represent centripetal force is Newton.
A. The friction between the car's tire and the curve surface is responsible for providing the centripetal force, and it also depends on the car's speed.
B. If a car is traveling faster than a larger centripetal force is required to maintain the curve path of the car, means if the friction between the tire and surface decreases the centripetal force also decreases.
When the bend is less curved, the radius of the curve increase and thus require more centripetal force.
When people in the car increase then the mass of the car also increases so due to this the gravitation force is now more on the car so more centripetal force I required to maintain the curve path of the car.
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Can the potential of a non uniform charged sphere be the same as that of a point charge? Explain in details
Answers
No. The potential of a non-uniform charged sphere cannot be the same as that of a point charge.
Non-uniform charged sphere as a point chargeThe potential at any point in space is determined by the distribution of charge within the system, and a non-uniform charged sphere has a different charge distribution than a point charge.
A point charge has all of its charges concentrated at a single point, while a non-uniform charged sphere has charge distributed throughout its volume.
As a result, the electric field and potential will be different for these two systems, even if they have the same total charge. Therefore, the potential of a non-uniform charged sphere cannot be the same as that of a point charge.
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Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the twelve cube edges). If the cube can only be loaded in axial tension such that the force is uniformly applied over - and is normal to - a cube face, what is the lowest possible positive length change the cube can experience under this tension
Answers
The question is incomplete. The complete question is :
Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the twelve cube edges). If the cube can only be loaded in axial tension such that the force is uniformly applied over - and is normal to - a cube face, what is the lowest possible positive length change the cube can experience under this tension? The applied tensile force is 102 KN. The unloaded cube edge length is 56 mm. The glass fibers have an elastic modulus of 200 GPa. The epoxy has an elastic modulus of 38 GPa. The cube is comprised of 18 vol% epoxy (the balancing vol % is glass fiber). Hint: The loading axis is intentionally unspecified. Answer Format: Lowest possible length increase (change of length) under tension.
Solution :
Given :
\($E_{glass fibre}$\) = 200 GPa
\($V_{glass fibre} = 82\%$\)
\($E_{epoxy}$\) = 38 GPa
\($V_{epoxy} = 82\%$\)
Edge length = 56 mm
Cube is loaded in axial tension such that the force is uniformly applied over a cube face.
\($E_{\text{composite}}=\frac{E_{glass fibre} \times E_{epoxy}}{(E_{glass fibre .E_{epoxy}})+(E_{fibre}.V_{glass fibre})}$\)
\($E_{composite} = \frac{200 \times 38}{(200 \times 0.18)+(38\times 0.82)}$\)
\($=113.16 $\) GPa
Applied stress \($=\frac{\text{applied load}}{\text{area}}$\)
\($\sigma=\frac{102 \times 10^3 \ N}{56 \times 56 \times 10^{-6} \ m^2}$\)
= 32.5 MPa
By Hooke's law
\($\sigma = E . \epsilon$\)
\($\sigma = E. \frac{\Delta l}{l}$\)
\($\Delta l = \frac{\sigma}{E}\times l$\)
Length change, \($\Delta l =\frac{32.5 \times 10^6 \ Pa}{113.16 \times 10^9 \ Pa}\times 56 \times 10^{-2} \ m$\)
\($\Delta l = \frac{32.5 \times 56}{113.16} \times 10^{-3} \ mm$\)
= 0.016 mm
Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of uniform height
. The mass of each object is a multiple of the base mass
: object 1 has mass 4.60
, object 2 has mass 2.21
, and object 3 has mass
. When the objects are at the bottom of the steps, define the total gravitational potential energy of the three-object system to be zero.
Each answer requires the numerical coefficient to an algebraic expression that uses some combination of the variables , , and , where is the acceleration due to gravity. Enter only the numerical coefficient. (Example: If the answer is 1.23 , just enter 1.23)
Image showing three masses, 1, 2, and 3, and three steps, each of height D. The three masses are shown at the base of the steps. Arrows indicate that mass 1 is placed on the top step at height 3 D, mass 2 is placed on the middle step at height 2 D, and mass 3 is placed on the bottom step at height D.
If the objects are positioned on the steps as shown, what is gravitational potential energy ,system of the system?
If you redefine the reference height such that the total potential energy of the system is zero, how high ℎ0 above the bottom of the stairs is the new reference height?
Now, find a new reference height ℎ′0 (measured from the base of the stairs) such that the highest two objects have the exact same gravitational potential energy.
Answers
a) The gravitational potential energy of the system of three masses at the given positions is 188.36md.
(b) The redefined reference height is h₀ = 0.55d.
(c) The new reference height measured from the base is h₀' = 0.96d.
What is the gravitational potential energy of the system?
(a) The gravitational potential energy of the system of three masses at the given positions is calculated as;
total gravitational potential energy = P.E(mass 1) + P.E(mass 2) + P.E(mass 3)
T.G.P.E = m₁gh₁ + m₂gh₂ + m₃gh₃
where;
mass of object 1, m₁ = 4.6mmass of object 2, m₂ = 2.21mmass of object 3, m₃ = mh₁ = 3dh₂ = 2dh₃ = dT.G.P.E = (4.6m x 9.8 x 3d) + (2.21m x 9.8 x 2d) + (m x 9.8 x d)
T.G.P.E = 135.24md + 43.32md + 9.8md
T.G.P.E = 188.36md
(b) The redefined reference height is calculated as follows;
0 = (4.6m x 9.8 x h₀) + (2.21m x 9.8 x (h₀ - d) + (m x 9.8 x (h₀ - 2d)
0 = 45.08mh₀ + 21.66mh₀ - 21.66md + 9.8mh₀ - 19.6md
0 = 45.08h₀ + 21.66h₀ - 21.66d + 9.8h₀ - 19.6d
0 = 76.54h₀ - 41.26d
76.54h₀ = 41.26d
h₀ = 41.26d/75.54
h₀ = 0.55d
(c) The new reference height measured from the base such that the highest two objects have the exact same gravitational potential energy is calculated as follows;
m₂gh₂ = m₁gh₁
2.21m x 9.8 x h₂ = 4.6m x 9.8 x h₁
21.66mh₂ = 45.08mh₃
21.66h₂ = 45.08h₁
h₁ = 21.66h₂/45.08
h₁ = 0.48h₂
h₀' = 0.48 x (2d)
h₀' = 0.96d
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A stone is thrown vertically upwards with a speed of 20 m/s. How high will it go before it begins to fall? (g = 9.8 m/s²)
Answers
Answer:
20.41 meters
Explanation:
We can solve this problem using the equations of motion.
When the stone is thrown upwards, its initial velocity (u) is +20 m/s (positive because it's in the upward direction) and its acceleration (a) is -9.8 m/s² (negative because the acceleration due to gravity is in the downward direction). We want to find the maximum height (h) that the stone reaches before it begins to fall back down.
The equation that relates these quantities is:
v² = u² + 2as
where v is the final velocity (which is zero when the stone reaches its maximum height), s is the displacement (which is equal to the maximum height we want to find), and the other variables are as described above.
Solving for s, we get:
s = (v² - u²) / 2a
Since v is zero, we can simplify this to:
s = u² / 2a
Substituting the given values, we get:
s = (20 m/s)² / (2 x -9.8 m/s²) = 20.41 m
Therefore, the stone will reach a maximum height of 20.41 meters before it begins to fall back down.
PLEASEEEEEEE HELPPPPPPPPP
Follow these directions:
Let your partner hold a ruler or meter stick in his/her hand vertically between the thumb and index finger, making sure he/she holds the meter stick so that the zero mark is between his/her fingers with the 1 cm mark above it. Your friend should hold the meter stick toward the top end, while your fingers are open at the bottom end of the ruler, ready to catch it between your index finger and your thumb . You should not be touching the meter stick or ruler.
Have your partner release the meter stick or ruler. As soon as you see the ruler released, snap your fingers shut and catch it.
Record in a data table the centimeter mark that was closest to your fingers.
Repeat this procedure several times, and average your results.
Change centimeters to meters.
Then calculate your reaction time by using the formula above and 9.8 m/s2 for g.
Compare your reaction time with that of your partner. Write out your comparison and possible reasons for differences.
Answers
We can see here that carrying out the experiment and comparing your reaction time with that of your partner, we see that if one person has a faster reaction time, possible reasons could be faster reflexes or better anticipation of when the ruler will be released.
What is reaction time?Reaction time is the interval of time that elapses between the presentation of a stimulus and the initiation of a response. It is the time it takes for an individual to process and react to a stimulus, such as a sound, sight, or touch.
Carrying the experiment, we assume that the data table is gotten thus:
Trial Centimeter Mark
1 20
2 17
3 21
4 19
5 18
To change centimeters to meters, divide the average centimeter mark by 100. So, the average centimeter mark is
(20+17+21+19+18)/5 = 19 cm,
which is equal to 0.19 meters.
To calculate reaction time, we can use the formula:
t = √(2d/g)
where t is the reaction time, d is the distance traveled by the ruler, and g is the acceleration due to gravity (9.8 m/s^2).
Assuming the distance traveled by the ruler is equal to the distance between the top of the ruler and the point where it was caught by the fingers, we can calculate the reaction time as follows:
t = √(2 x 0.19 / 9.8) = 0.197 seconds ≈ 0.2 seconds.
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A boat can travel 2.30 m/s in still water. If the boat points its prow directly across a stream whose current is 1.80 m/s , what is the magnitude of the velocity of the boat relative to the shore?
Answers
Answer:
A boat can travel 2.30 m/s in still water. (a) If the boat points its prow directly across a stream whose current is. ... (a) What is the velocity (magnitude and direction) of the boat relative to the shore? ... The boat's velocity with respect to the shore, , is the sum of its velocity with respect to the water
Explanation:
what happens to the resistance of two resistors when connected in series circuit
Answers
Answer:
increases as more components are added.
The components of a 15 meters per second velocity at an angle of 60 above the horizontal are
Answers
The components of a 15 meters per second velocity at an angle of 60 above the horizontal are 13.05 m / s and 0.435 m / s
Resolving the velocity into its horizontal and vertical components, it makes a right angled triangle.
Hypotenuse = V = 15 m / s
θ = 60°
Opposite side = components = \(V_{y}\)
Adjacent side = Horizontal component = \(V_{x}\)
In a right angled triangle,
sin θ = Opposite side / Hypotenuse
cos θ = Adjacent side / Hypotenuse
sin 60° = \(V_{y}\) / V
\(V_{y}\) = 15 * 0.87
\(V_{y}\) = 13.05 m / s
cos 60° = \(V_{x}\) / V
\(V_{x}\) = 0.5 * 0.87
\(V_{x}\) = 0.435 m / s
Therefore,
The horizontal component, \(V_{x}\) = 0.435 m / sThe vertical component, \(V_{y}\) = 13.05 m / s.To know more about components of velocity
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What is the net force on a truck if the force of friction is 31 N and the force of the engine is 79 N?
48 N backword
79 N forward
48 N forward
110 N forward
Answer and I will give you brainiliest
Answers
Answer: C) 48 N forward
===================================================
Explanation:
Subtract the two forces, since they are working opposite one another.
79-31 = 48
The net force is 48 newtons forward. The truck is moving forward since the engine's force (79 N) is larger than the force of friction (31 N).
The force of friction cannot exceed the engine's force because friction only slows down an object, and does not push the object backward. In other words, if the object was stationary, then the ground isn't pushing the object backwards assuming you're on a level flat ground.
Every mass exerts a gravitational force on every other mass.
a. True
b. False
Answers
Answer:
A
Explanation:
newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses
why was bowling one of the first racially integrated sports
Answers
Answer:
bowling was one of the first racially integrated sports because bowling alleys were primarily located in urban areas. Racial integration was inevitable since it was promoted by US Armed Forces during 1940s and its image as sport for the common man made it a choice of activity for Americans!!
Explanation:
Read the quotation from "Some Keep the Sabbath Going to Church
And instead of tolling the Bell, for Church,
Our little Sexton - sings.
What is the most likely reason for the poet to oppose the phrases "tolling the Bell" and "sings" in these lines?
The poet is expressing her belief that the second, more natural option is far more desirable than the first option.
The poet is hinting that religious worship should be considered a gloomy and serious activity
The poet is suggesting that those who worship in nature are more formal than those who worship in church.
The poet is contrasting her attitude about religion with her feelint about the natural world, which remains largely
unappreciated
Answers
Answer: the poet is expressing her belief that the second, more natural option is far more desirable than the first option
Explanation:
Answer:
a-The poet is expressing her belief that the second, more natural option is far more desirable than the first option.
Explanation:
NEED ANSWER FAST!!!!!
When metal strips are place in a liquid, bubbles are observed to form around the metal. When the gas from these bubbles is collected in a balloon, the balloon rises.
what can be concluded in this experiment
A- the gas is poisonous
b- the gas is hydrogen
c- if the balloon is touched with a match, the collected gas will explode
d- the gas is lighter than air
e- the gas is hot because the liquid boiled
Answers
Answer:
option d - "the gas is lighter than air"
Explanation:
Based on the given experiment, the most likely conclusion is that the gas collected in the balloon is lighter than air, which causes the balloon to rise. Therefore, option d - "the gas is lighter than air" is the correct answer.
It is not possible to conclude whether the gas is poisonous, hydrogen, or hot because these properties cannot be determined solely from the given experiment. Additionally, it is not safe to assume that the collected gas will explode when touched with a match, as this would depend on the specific properties of the gas collected.
The answers to the fill in the blank plz
Answers
Answer:
not too sure but i think it is : force - multiplied by -mass
give a strong idea to protect , purify and the beautify of the Dal lake
Answers
Answer:
Water in dal lake is test for any heavy metals and pollutant, sewage and drainage system are also monitored for the same.
Explanation:
Dal lake is located in Srinagar that is the state capital of Kashmir and is known for recreation and tourism purposes. The area covers about 18 km sq. and forms a part of natural wetlands. The lake is prone to pollution and has recently undergone restoration measures. To address the problems of eutrophication algae and large-scale microplankton have been removed from the water. The government of India has taken various measures to check the pollution by setting up a committee to monitor the proper use of allotted funds.En 2.0 s, una particula con aceleración constante a lo largo del eje x se mueve desde x =10 m
hasta x =50 m. La rapidez al final del recorrido es de 10 m/s. ¿Cuál es la aceleración de la partícula?
Answers
The (BLANK) island were where Darwin made many important observations.
Answers
Answer:
I know theirs South American coast he was there a lot
What is a black hole's escape velocity?
Answers
The simplest definition of a black hole is an object that is so dense that not even light can escape its surface. If we squished the Earth's mass into a sphere with a radius of 9 mm, the escape velocity would be the speed of light. Just a wee-bit smaller, and the escape velocity is greater than the speed of light.
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what is meant by reticlinear propatigation of light?
Answers
Answer:
The property of light going in a straight lines in a homogenous straightforward medium is known as rectilinear engendering of light.
Answer:
the property of light travelling in a straight lines in a homogenous transparent medium
Explanation:
Force varies directly with pressure. A force of 22,000 newtons acts on an object, causing 110 N/m² of pressure. The
force decreases to 18,000 newtons. What is the new amount of pressure caused by the force?
○ 45 N/m²
90 N/m²
O 75 N/m²
60 N/m²
Answers
The final amount of pressure caused by the force is 90 N/m².
Initial amount of force, F₁ = 22 x 10³ N
Initial amount of pressure produced, P₁ = 110 N/m²
Final amount of force exerted, F₂ = 18 x 10³ N
Pressure is defined as the amount of force acting on an object per unit area of the object.
So, we can say that the force and pressure are directly proportional.
F ∝ P
So, F₁/P₁ = F₂/P₂
Therefore, the final amount of pressure caused by the force is,
P₂ = F₂P₁/F₁
P₂ = 18 x 10³x 110/22 x 10³
P₂ = 18/0.2
P₂ = 90 N/m²
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a. When throwing a ball vertically upward, my hand moves through a distance of about 1.0 m before the ball leaves my hand. The 0.80 kg ball reaches a maximum height of about 20 m above my hand. while the ball is in my hand after the ball leaves my hand
Answers
The required, it experiences a downward force due to gravity and a force due to air resistance.
What is the projectile motion?Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.
Here,
When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.
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Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
Answers
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Hooke’s Law Problem:
A ball of mass m = 2.60 kg, starting from rest, falls a vertical distance h = 55 cm before striking a vertically coiled spring, which compresses an amount BY = 15 cm. Determine the spring stiffness constant of the spring. Assume the spring has negligible mass, and ignore air resistance. Measure all distances
from the point where the ball first touches the uncompressed
spring (y=0 at this point).
Answers
The spring stiffness constant of the spring is 1276.44 N/m.
We know that Hooke’s Law is given by, F = -kx, where F is the force applied to an object, x is the displacement caused by the force, and k is the spring constant.
Therefore, the spring stiffness constant of the spring is given by k = -F / x.Let us first determine the potential energy of the ball, which will be equal to the kinetic energy of the ball when it strikes the spring. We can use the formula, PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the vertical distance fallen by the ball.
Therefore, the potential energy of the ball is given by,PE = mgh= 2.60 kg × 9.81 m/s² × 0.55 m= 14.38 JNow, the ball will transfer all its potential energy to the spring, which will store it as potential energy in the form of elastic potential energy. Therefore, the elastic potential energy stored in the spring is given by, PE = (1/2)kx², where x is the compression of the spring.
Therefore, we have,PE = (1/2)kx²
= (1/2)k (0.15 m)²
= 0.01125 k J
Setting the two expressions for PE equal to each other, we get,1
4.38 J = 0.01125 k JK
= (14.38 J) / (0.01125 J/k)
= 1276.44 N/m
Therefore, the spring stiffness constant of the spring is 1276.44 N/m.
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Suppose an empty grocery cart starts at a rest and rolls downhill in a parking lot. The cart has a maximum speed of 2.2km/s when it hits the side of the store and comes to rest 1.5 min later. If an unbalanced force of 65 N stops the cart, what is the mass of the grocery cart?
Answers
Answer: i dont know
Explanation:
E
The force of magnitude Fx acting in the x-direction on a 3.5 kg particle varies in
time as shown in the figure. Calculate the impulse of this force. Answer in units of
N-s.
Answers
Answer: 42 N-s
Explanation: The area under the curve is equal to the impulse, so you take the area of the two triangles and add it to the area of the rectangle.
Area of a triangle: 1/2bh
Area of a rectangle: bxh
2(1/2x2x7)=14+(4x7)=42 N-s
The force of magnitude F acting in the x-direction on a 3.5 kg particle varies in time as shown in the graph given in question, the impulse of this force is 42 N-s.
What is impulse?The integral of a force, F, over the time period which it acts, t, is referred to as the impulse. Impulse is a vector quantity because force is one as well. When an item receives an impulse, its linear momentum also changes in the opposite direction in an analogous vector.
S.I unit of impulse is Newton-second (Ns).
From the graph given in question area under the curve is equal to the impulse, so take the area of the two triangles and add it to the area of the rectangle.
Area of a triangle = 1/2bh
Area of a rectangle = bxh
total area,
impulse = 2(1/2x2x7)
= 14+(4x7)
= 42 N-s
Impulse of the force is 42 N-s.
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A rollar coaster moves over the creast at location 1 at 10 m/s. HOw fast is it going at location 4? Neglect friction and air resistance.
Answers
The velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
Roller coasters are fascinating machines that deliver an exhilarating experience by defying gravity and physics. Roller coaster physics is a significant concept to comprehend before riding a roller coaster or designing one. The laws of physics govern the motion of a roller coaster, including its velocity, acceleration, and potential energy.
A roller coaster moves over a crest at location 1 with a speed of 10 m/s. The question is how fast it's going at location 4, considering the neglect of friction and air resistance. To solve this, we'll need to consider the conservation of energy law.
The total energy of the roller coaster remains constant throughout the ride, and we can convert between potential and kinetic energy.Using the conservation of energy formula, which is: E1 = E2Where E1 is the total energy of the roller coaster at the crest and E2 is the total energy of the roller coaster at location 4.
Both E1 and E2 comprise kinetic energy (KE) and potential energy (PE). So,E1 = KE1 + PE1E2 = KE2 + PE2Since the roller coaster has no friction and air resistance, we can assume that PE1 = PE2 because the height of the roller coaster doesn't change. The energy is converted from potential energy at the crest to kinetic energy at location 4.
We can now use the formula for kinetic energy:KE = (1/2) mv²Where m is the mass of the roller coaster and v is its velocity. Both E1 and E2 can be written in terms of KE, so: E1 = (1/2) mv₁²E2 = (1/2) mv₂².
Substitute the values into the conservation of energy formula: E1 = E2(1/2) mv₁² = (1/2) mv₂²
Simplifying the equation gives:v₂² = v₁²×(h₁ / h₂)
where h₁ is the height of the crest and h₂ is the height of location 4.
To calculate the velocity, we need to take the square root of both sides:v₂ = v₁×√(h₁ / h₂)
Therefore, the velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
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Compare sound and earthquake waves
Answers
When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.
How do sound waves and earthquakes compare?
The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.
In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.
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A uniform meter stick has its center of mass at 50 cm mark. A mass of 50 gram is hung at 20 cm mark of the meter stick. An unknown mass is hung at 70 cm mark. The system is balanced at the fulcrum at 50 cm mark as shown in the figure. Find the unknown mass M.
Question 2 options:
85 gram
100 gram
33.33 gram
14.29 gram
75 gram
Answers
Hi there!
We can use a summation of torques to find the unknown mass:
∑F = R · F (distance from fulcrum × force in this instance)
Since there are masses on both sides, we can set their torques equal to each other since they must balance:
∑F = 0
R₁F₁ = R₂F₂
F = weight of mass, or Mg
50(g)(50 - 20) = M(g)(70 - 50)
Cancel out the g's, or acceleration due to gravity:
50(30) = M(20)
Solve:
1500 = M(20)
1500/20 = M = 75 grams
What does it mean if something is Periodic?
Answers
Answer:
In the context of chemistry and the periodic table, periodicity refers to trends or recurring variations in element properties with increasing atomic number. Periodicity is caused by regular and predictable variations in element atomic structure
Explanation: