it is not good to burn agricultural waste ​

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Answer 1
I agree why would you do that.

Related Questions

Challenge Exercises: The following exercises are of a greater difficulty than the earlier ones, though still matched to our course objectives. These exercises are not intended to prepare you for test questions, instead they expose you to more complex, real-world scenarios. You may struggle more with these questions than the Routine exercises. Remember your problem solving strategies! Read carefully and repeatedly. What words are familiar in the problem statement? What terms have been defined in the class, versus what is being provided to you within the exercise itself? Who can you work with for assistance? 8. The power generated by a stationary cyclist depends on both the resistance on the fly-wheel and the cadence (i.e. how fast the cyclist is pedaling). A University of Calgary study looked at fixed levels of exertion and drew curves for the relationship between resistance and cadence. Let's examine the relationship between resistance and cadence at a fixed activity level (i.e. perceived level of exertion). The article cites that they used a Hill function of the form (R+a) · (v + b) = b(Ro + a), where R is the resistance and Ro is the maximal resistance (both in Newtons), v is the cadence (in revolutions per minute), and a and b are other constants. (a) For the lowest activity level used in the study, the maximal resistance was 75 Newtons. Also, when resistance dropped to 0, cadence was 180 rpm; when resistance was 10 Newtons, cadence dropped to 100 rpm. Use this data to find values of the constants a and b. (b) Including the constants from part (a), express the formula from the article explicitly in the form of R as a function of v. (c) What is the long-term behavior of R? Is this behavior meaningful in context?

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a) Given that the Hill function is (R+a) · (v + b) = b(Ro + a)Here, R = resistance, Ro = maximal resistance, v = cadence, a, b are constantsGiven, maximal resistance, Ro = 75 Newtons,Resistance, R = 0, cadence, v = 180 rpmResistance, R = 10 Newtons, cadence, v = 100 rpmWe have to calculate a and b.For R = 0, v = 180, 10a + 180b = 75b, and b = (10a/−100 + 9/2)For R = 10, v = 100, 20a + 100b = 750 − 75

a.Substitute the value of b in the above equation.20a + 100(10a/−100 + 9/2) = 750 − 75a20a − 10a + 450 = 750 − 75a10a = 300a = 30Substitute the value of a in the equation (10a/−100 + 9/2) = b(10/−100 + 3/2)b = 15/16Therefore, the value of a is 30 and the value of b is 15/16. Hence, we got the value of a and b.b) Here the Hill function is (R+a) · (v + b) = b(Ro + a)Substituting the value of a and b in the equation, we get (R + 30) (v + (15/16)) = (15/16)(75+30)R + 30 = (15/16)105R = (105(v + (15/16)) − 2475)/15R = (7(v + (15/16)) − 165)/15

Therefore, the formula for R as a function of v is given by R = (7(v + (15/16)) − 165)/15.c) Long-term behavior of R is the value of R when v approaches infinity. Thus, the limiting value of R when v approaches infinity is Ro, i.e. 75 Newtons. Thus, the long-term behavior of R is that as the cadence increases, the resistance approaches its maximal value. This behavior is meaningful in the context of a stationary bicycle since maximal resistance represents the level of physical resistance that a cyclist may face.

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Explain type 1 and type 1a relay node in LTE-A?

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In the context of LTE-A (Long-Term Evolution Advanced), Type 1 and Type 1a relay nodes are different deployment options for relay nodes in the LTE network. Relay nodes are used to extend the coverage and improve the performance of the network by relaying signals between the base station and user equipment (UE).

Type 1 Relay Node:

A Type 1 relay node in LTE-A operates in half-duplex mode, which means it can either transmit or receive data at a given time but not both simultaneously. It has two separate sets of antennas: one for receiving signals from the base station (downlink) and another for transmitting signals to the UE (uplink). This type of relay node introduces a relay-specific interface called the Relay Physical Interface (R-PHY) to connect with the base station.

The Type 1 relay node receives downlink signals from the base station, decodes them, and then re-encodes and retransmits them to the UE. Conversely, it receives uplink signals from the UE, decodes them, and re-encodes and retransmits them to the base station. Due to the half-duplex operation, it cannot receive and transmit simultaneously, which can result in increased latency and reduced throughput compared to other relay types.

Type 1a Relay Node:

A Type 1a relay node is an enhanced version of the Type 1 relay node, specifically designed to improve performance. It operates in full-duplex mode, allowing simultaneous transmission and reception. It achieves this by utilizing advanced self-interference cancellation techniques, which cancel out the interference caused by the transmitted signal, allowing the relay to receive signals while transmitting.

The Type 1a relay node also utilizes the Relay Physical Interface (R-PHY) to communicate with the base station. By supporting full-duplex operation, it can provide better throughput and lower latency compared to the Type 1 relay node. This makes it more suitable for scenarios where higher data rates and improved performance are desired.

Both Type 1 and Type 1a relay nodes can be deployed in LTE-A networks to extend coverage and improve performance in areas with challenging propagation conditions or limited backhaul connectivity. The choice between the two types depends on the specific requirements of the network deployment and the desired trade-offs between performance and complexity/cost.

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What kind of model is shown below? Qin = W + Qout A. Physical model B. Mathematical model C. Computer model D. Experimental model

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Answer: mathematical model

Explanation: just took the test

The requried model  Qin = W + Qout A, Mathematical model. Option B is correct.

What is the equation model?

An equation model is a type of mathematical model that uses equations to describe the behavior of a system or phenomenon. In an equation model, mathematical expressions are used to represent the relationship between different variables that are involved in the system. These variables can represent physical quantities, such as force, velocity, and temperature, or abstract concepts, such as market demand, population growth, and economic indicators.

Here,
The equation Qin = W + Qout is a mathematical model, as it is a mathematical representation of the input (Qin), output (Qout), and work done (W) in a thermodynamic system. A mathematical model uses mathematical concepts and equations to describe and predict the behavior of a system or phenomenon.

Thus, the requried model  Qin = W + Qout A, Mathematical model. Option B is correct.

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an nacl solution is prepared by dissolving 90.0 g nacl in 250.0 g of water at 25°c. what is the vapor pressure of the solution if the vapor pressure of water at 25°c is 23.56 torr?

Answers

According to the statement, the vapor pressure of the solution is 21.08 torr.

To solve this problem, we need to calculate the mole fraction of NaCl in the solution and use it to calculate the vapor pressure of the solution.

First, let's calculate the moles of NaCl and water:

moles NaCl = 90.0 g / 58.44 g/mol = 1.54 mol

moles water = 250.0 g / 18.015 g/mol = 13.88 mol

Next, let's calculate the mole fraction of NaCl:

mole fraction NaCl = moles NaCl / (moles NaCl + moles water) = 1.54 mol / (1.54 mol + 13.88 mol) = 0.1007

Now, we can use the following equation to calculate the vapor pressure of the solution:

P solution = X water × P water

where P water is the vapor pressure of pure water and X water is the mole fraction of water in the solution. Since the mole fraction of NaCl is 1 - X water, we can rearrange the equation to solve for P solution:

P solution = (1 - X NaCl) × P water

Plugging in the values, we get:

P solution = (1 - 0.1007) × 23.56 torr = 21.08 torr

Therefore, the vapor pressure of the solution is 21.08 torr.

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A car of mass 1500 kg is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s.


a. The source of centripetal force on the car is (1) the weight of the car, (2) the normal force on


the car, or (3) the static friction force.


b. What is the magnitude of the centripetal acceleration of the car?


c. What is the magnitude of the centripetal force on the car?


d. What is the minimum coefficient of static friction between the car and the curve?


I’m

Answers

a. The source of centripetal force on the car is (3) the static friction force. b. The magnitude of the centripetal acceleration of the car is 8 m/s².

a. (2) The normal force on the car provides the centripetal force.b. The magnitude of the centripetal acceleration is given by a = v²/r = (20 m/s)² / (50 m) = 8 m/s². c. The magnitude of the centripetal force is given by F = m * a = (1500 kg) * (8 m/s²) = 12,000 N.

d. The minimum coefficient of static friction can be found using the formula μs = (centripetal force / weight) = (12,000 N / 1500 kg * 9.8 m/s²) ≈ 0.82.

a. The centripetal force is the force that keeps an object moving in a circular path. In this case, the normal force on the car provides this force since it acts perpendicular to the surface of the road and inward toward the center of the circle.

b. The centripetal acceleration is given by the formula a = v²/r, where v is the velocity and r is the radius of the circular path. Plugging in the given values, we find a = (20 m/s)² / (50 m) = 8 m/s².

c. The centripetal force is related to the centripetal acceleration by the formula F = m * a, where m is the mass of the car. Substituting the given values, we get F = (1500 kg) * (8 m/s²) = 12,000 N.

d. The minimum coefficient of static friction can be determined by equating the centripetal force to the maximum static friction force. The formula for static friction is given by Ff ≤ μs * N, where Ff is the frictional force, N is the normal force, and μs is the coefficient of static friction. Rearranging the equation, we have μs ≥ (Ff / N). Since the centripetal force is the maximum static friction force, we can substitute the values to find μs = (12,000 N / (1500 kg * 9.8 m/s²)) ≈ 0.82.

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Helping the community!!

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WoAh that’s kind bro

What is the name of the idea that all bodies in the solar system formed from a dominantly hydrogen/helium cloud?

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The name of the idea that all bodies in the solar system formed from a dominantly hydrogen/helium cloud  Nebular Hypothesis

The sun and its orbiting planets make up the solar system, in which everything is bound together with the force of gravitation. Each planet travels around the sun along an orbit unique to that planet.

The distance between the planets is used to categorize them. The two categories of planets of the solar system based on their distance from the sun are

- Inside planets which consist of Mercury, Venus, Earth, and Mars 

- Outside planets which consist of Jupiter, Saturn, Uranus, Neptune

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How do I solve this problem Determine the weight of the tram. The cable at left exerts a 30,000 N force. (The tram is attached to the cable so the tension in the left cable is not necessarily equal to the tension in the right cable.)

How do I solve this problem Determine the weight of the tram. The cable at left exerts a 30,000 N force.

Answers

Free body diagram:

Here, T_1 is the tension in the left cable (T_1=30000 N; given), T_2 is the tension in the right cable, W is the weight of the tram.

The force equation in horizontal direction is given as,

\(T_1=T_2\sin (75\degree)\)

Therefore, the tension in right cable T_2 is given as,

\(T_2=\frac{T_1}{\sin(75\degree)}\)

Substituting all known values,

\(\begin{gathered} T_2=\frac{30000\text{ N}}{\sin (75\degree)} \\ \approx31058.28\text{ N} \end{gathered}\)

The force equation in the vertical direction is given as,

\(W=T_2\cos (75\degree)\)

Substituting all known values,

\(\begin{gathered} W=(31058.28\text{ N})\times\cos (75\degree) \\ \approx8038.47\text{ N} \end{gathered}\)

Therefore, the weight of the tram is 8038.47 N.

How do I solve this problem Determine the weight of the tram. The cable at left exerts a 30,000 N force.

how much heat (cal) is required to raise the temperature of 12.7 g of water from 18.3 ∘c to 55.0 ∘c?

Answers

It takes 1950.12 J of heat to increase the temperature of 12.7 g of water from 18.3 °C to 55.0 °C.

What is heat transfer?

Heat transfer is the process through which internal energy from one material is transferred to another.

The amount of heat required to raise the temperature of a substance can be calculated using the equation:

q = m c ΔT

where q is the amount of heat, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For water, the specific heat capacity is 4.184 J/g°C.

So, to raise the temperature of 12.7 g of water from 18.3 °C to 55.0 °C, the amount of heat required can be calculated as follows:

q = 12.7 g × 4.184 J/g°C × (55.0 °C - 18.3 °C)

q = 12.7 g × 4.184 J/g°C × 36.7 °C

q = 1950.12 J

So, 1950.12 J of heat is required to raise the temperature of 12.7 g of water from 18.3 °C to 55.0 °C.

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Why cant Analog Thermometers measure temperature below 0 °C?

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Answer:

Alcohol thermometers are used rather than mercury thermometers in very cold regions because alcohol has a lower freezing point than mercury.

3. Since Aspeon is not expected togrow, Emily believes that the following equations can be used in the valuation analysis: (1) S=[EBIT−kd(D)](1−ks)
(2) V=S+D
(3) P=(V−D0)/n0
(4) n1=n0−D/P
(5) VL=VU+TD

Answers

The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:

1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.

2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.

3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.

4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.

5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.

These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.

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1) Andrew wanted to watch his dog run to see how fast he can to see what 1 point
his speed was. When his dog started running, he measured the distance of
17 meters in 9 seconds. What was his dog's speed?*

Answers

Answer:

Andrew's dog's speed was 1.89 m/s

Explanation:

Motion at Constant Speed

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

This can be written as the formula below:

\(\displaystyle v=\frac{d}{t}\)

Where  

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

Andrew's dog run a distance of d=17 meters in a time of t=9 seconds, thus its speed was;

\(\displaystyle v=\frac{17}{9}\)

v = 1.89 m/s

Andrew's dog's speed was 1.89 m/s

Find the distance in parsecs to these three stars. Star: Bade
Apparent Magnitude (m) = 4
Absolute Magnitude (M) = 4 Step 1: Work out the fraction
(m-M)/5 = ( - )/5 = Step 2: Take the "anti-log" 10^x(step 1 number) = 10^x ( ______ ) = _____
Step 3: Multiply by 10
D = 10* (step2 number) = 10*( ____ ) = _____ pc
Distance to Bade = ____pc Star: Ceriero Apparent Magnitude (m) = 0
Absolute Magnitude (M) = 2 Distance to Ceriero = _____pc
Star: Darnan Apparent Magnitude (m) = 0 Absolute Magnitude (M) = 0 Distance to Darnan = _____ pc
Based on the above, what is the distance to any star whose apparent magnitude is the same as its absolute magnitude?

Answers

Answer:

For any star whose apparent magnitude is the same as its absolute magnitude, the distance to the star would be 10 parsecs.

Explanation:

When the apparent magnitude (m) is equal to the absolute magnitude (M) of a star, the distance to the star can be determined as follows:

Step 1: Work out the fraction: (m - M) / 5 = (0 - 0) / 5 = 0/5 = 0

Step 2: Take the "anti-log": 10^(x) = 10^(0) = 1

Step 3: Multiply by 10: D = 10 * (step 2 number) = 10 * 1 = 10 pc

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Air at 20°C blows over a 50 x 75 cm hot plate made of carbon steel (AISI 1010) with 2 cm thickness. The outer surface temperature of the plate is maintained at 300°C. The convection heat transfer coefficient is 25 W/m2⋅K. 300 W is lost from the plate surface by radiation, calculate the inside plate temperature

Answers

The inside plate temperature is approximately 235.7°C.

What is the temperature inside the carbon steel plate?

The net heat transfer from the plate surface to the surrounding air can be calculated using the equation:

\(Q_n_e_t\) = \(Q_r_a_d_i_a_t_i_o_n\) - \(Q_c_o_n_v_e_c_t_i_o_n\)

where \(Q_r_a_d_i_a_t_i_o_n\) = σ(ε)(A)(T⁴) is the heat lost from the plate surface by radiation, \(Q_c_o_n_v_e_c_t_i_o_n\) = h(A)(\(T_p_l_a_t_e\) - \(T_a_i_r\)) is the heat transferred from the plate surface to the air by convection, σ is the Stefan-Boltzmann constant, ε is the emissivity of the plate, A is the surface area of the plate, T is the temperature of the plate in Kelvin, \(T_a_i_r\) is the temperature of the air, \(T_p_l_a_t_e\) is the inside plate temperature, and h is the convective heat transfer coefficient.

By rearranging the equation and solving for \(T_p_l_a_t_e\), we get:

\(T_p_l_a_t_e\) = [(\(Q_r_a_d_i_a_t_i_o_n\) - h(A)(\(T_p_l_a_t_e\) - \(T_a_i_r\)))/σ(ε)(A)\(]^(^1^/^4^)\)

Substituting the given values, we get:

\(T_p_l_a_t_e\) = [(300 - 25(0.5*0.75)(\(T_p_l_a_t_e\) - 20))/ (5.67 x \(10^-^8\) x 0.4 x 0.375)\(]^(^1^/^4^)\)

Solving for \(T_p_l_a_t_e\), we get:

\(T_p_l_a_t_e\) = 508.85 K = 235.7°C

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What is the acceleration of a 12kg box being pushed with 60N of force?

Answers

60/12 =5m/s^2
Force/mass

PLEASE HELP ON QUESTION
6! WILL GIVE BRAINLIEST!!

Fastest (answer choices) - air,
aluminum, steel, ethanol, water
Slowest (answer choices) - air.
aluminum, steel, ethanol, water

WARNING ONLY ONE WORD
CAN GO FOR THE FASTEST
AND SLOWEST BOXES!!

PLEASE HELP ON QUESTION6! WILL GIVE BRAINLIEST!!Fastest (answer choices) - air,aluminum, steel, ethanol,

Answers

Answer:

fastest air slowest steel

Explanation:

Based on what you have read provide two positives and two negatives the Suarez family would face if they switch to organic farming

Answers

Hi, you did not enter the text about the Suarez family, which makes it impossible for this question to be answered accurately. However, from the context of your question, it is possible to see that you want to know two positive and negative points that the Suarez family would observe when starting a planting of organic agriculture.

Among the negative points, we can say that organic agriculture has a high cost, as the techniques used in it require a greater number of resources, which can make not only the service more expensive, but also the product. A second negative point is that the techniques used in organic agriculture are more difficult than the techniques used in conventional agriculture, since all management of organic crops must be carried out without the application of chemical products.

Among the positive points, we can say that the growing number of consumers of organic products can increase the profit that the family will have from the sale of these products. In addition, the family will have healthier, less polluted and more productive land.

Answer:

Sample response: Organic farming would have higher costs, and would be more complex than conventional farming. However, the Suarez family could charge a higher price for organic produce. This type of farming also would be better for the land.

Explanation:

the type of light that best illustrates the photoelectric effect is ___________.
a) high-amplitude visible light
b) high-frequency visible light
c) ultraviolet light
d) infrared light

Answers

The type of light that best illustrates the photoelectric effect is (c) ultraviolet light. Hence, the correct answer is option c).

Photoelectric effect refers to the emission of electrons from a metallic surface when a light of suitable frequency shines on the surface of the metal. The phenomenon, first noticed by Heinrich Hertz in 1887, was explained in 1905 by Albert Einstein when he used Planck's hypothesis to illustrate that light energy is carried in discrete quantized packets to describe the photoelectric effect.

In relation to photoelectric effect, the type of light that best illustrates it is ultraviolet light. This is because ultraviolet light has a high enough frequency to remove electrons from the metal surface. As a result, electrons that absorb photons with enough energy from the ultraviolet region of the electromagnetic spectrum will be ejected from the metal, causing the photoelectric effect, and producing an electric current.

When light is shone on a metallic surface, an electric current is produced, which is called the photoelectric effect. The photoelectric effect is caused by the emission of electrons from a metal surface that is exposed to a light of suitable frequency. The energy of the electrons depends on the frequency of the light, and the intensity of the light determines the number of electrons ejected from the surface.

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An 1640 kg car stopped at a traffic light is struck from the rear by a 820 kg car. The two cars become entangled, moving along the same path as that of the originally moving car. If the smaller car were moving at 25.6 m/s before the collision, what is the velocity of the entangled cars after the collision?

(a) What is the loss of kinetic energy (Ki - Kf) in the situation described in the example?
kJ

(b) What if the 820 kg car actually moves backwards with a speed of 1.9 m/s right after the collision instead of having a perfectly inelastic collision. What is the velocity of the heavier car immediately after the collision? Use the same convention for positive direction as defined in the example.
m/s

(c) What is the loss of kinetic energy in this case?
kJ

Answers

(a.i) The velocity of the entangled cars after the collision is 8.53 m/s.

(a.ii) The loss in kinetic energy of the situation described is  179,201.7 J.

(b) The final velocity of the heavier car if the smaller car moved backwards is 11.85 m/s forward.

What is the final velocity of the cars after the collision?

The final velocity of the cars after the collision is calculated by applying the principle of conservation of linear momentum as shown below.

m₁u₁  +  m₂u₂  = v(m₁ + m₂)

where;

m₁ is the mass of the smaller carm₂ is the mass of the bigger caru₁ is the initial speed of the smaller caru₂ is the initial speed of the bigger carv is the final speed of the cars

820(25.6) + 1640(0) = v(820 + 1640)

20,992 + 0 = 2460v

v = 20,992 / 2460

v = 8.53 m/s

The lost in kinetic energy of the situation described is calculated as follows;

ΔK.E = K.Ei - K.Ef

K.Ei = ¹/₂m₁u₁²  +   ¹/₂m₂u₂²

K.Ei = ¹/₂(820)(25.6)²  +   ¹/₂(1640)(0)²

K.Ei = 268,697.6 J

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(1640 + 820)(8.53)²

K.Ef = 89,495.91 J

ΔK.E = K.Ei - K.Ef

ΔK.E = 268,697.6 J - 89,495.91 J

ΔK.E =  179,201.7 J

The final velocity of the heavier car if the smaller car moved backwards is calculated as;

m₁u₁  +  m₂u₂  = m₁v₁ + m₂v₂

where;

v₁ is the final velocity of the smaller carv₂ is the final velocity of the heavier car

m₁u₁  +  m₂u₂  = m₁v₁ + m₂v₂

820(25.6) + 1640(0) = (820)(-1.9) + 1640(v₂)

20,992 = 1558 + 1640v₂

1640v₂ = 19,434

v₂ = 19,434 / 1640

v₂ = 11.85 m/s

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There are 30 students in Ms. Andrews’ fourth grade class. There are 6 times as many students in the entire fourth grade as there are in Ms. Andrew’s class. Which equation can be used to determine the number of students, n, in the entire fourth grade? *

6 x n = 30
6 + 30 = n
30 x 6 = n
30 ÷ n = 6

Answers

Answer:

30×6=n

Explanation:

30 students in her class× 6 = number of students in the entire 4th grade.

how can a simple machine lift a heavy load with smaller effort​

Answers

Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort.

May be this will help U

Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort

Explanation:

Distance = 500 miles

Time = 10 hours

Average Speed = ?????

Answers

Average speed= 50mph

what are two reasons communication is important in scientific research

Answers

Answer:

It allows them to write better and more comprehensible research papers. As well as being able to communicate the relevance and impact of their ideas and discoveries.

Explanation:

consider building a system of two positive charges: is the work done by an external agent positive or negative?

Answers

By considering building a system of two positive charges: The work done by an external agent is negative.

Any attempt by an outside force to combine two positive charges would be harmful. This is done in order to overcome the electrical force that now opposes the movement of the two positive charges toward one another. Negative work is defined as an effort made to control a disagreeable factor. However, if the two positive charges are already close to one another and the external agent operates to separate them, the work done would be beneficial. This is due to how weak the electrical force that holds the two positive charges together becomes when they are separated, necessitating the aid of an outside force. When work done to separate charges, it is viewed favorably. It's important to keep in mind that the concept of work includes all kinds of forces, not only electrical ones. The sign of the work generated by an external source is determined by the force's direction and the charges' displacement. If both the force and the displacement are travelling in the same direction, the work is positive. If the force and displacement are moving in the opposite directions, the work is negative.

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as the sound of a car's horn passes and recedes from you, the pitch of the horn seems to

Answers

As the sound of a car's horn passes and recedes from you, the pitch of the horn seems to change. This phenomenon is known as the Doppler Effect. When a sound source is moving towards you, the sound waves it produces get compressed, resulting in a higher frequency or pitch. Conversely, when a sound source is moving away from you, the sound waves get stretched, resulting in a lower frequency or pitch.

In the case of a car's horn, as it approaches you, the sound waves are compressed, causing the pitch to increase. As the car passes and moves away from you, the sound waves stretch, causing the pitch to decrease. This effect is commonly observed in many other scenarios, such as the sound of an ambulance or a train passing by.

The Doppler Effect has important applications in various fields, such as astronomy, where it is used to measure the velocity of stars and planets. It is also used in radar technology, where it helps to determine the speed and distance of objects. Understanding this effect is crucial in many areas of science and engineering, and it has paved the way for many groundbreaking discoveries and innovations.

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If an object travels 245 km in 5 hours, what was the speed of the object?

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Answer:

49kmph

Explanation:

speed=distance/time = 245/5

According to the giant impact hypothesis about the formation of the moon. Why did the earth not break apart into many pieces when the giant impact happened?

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The earth could not be broken apart by the impactor since it was formed of such light material (mostly gas and liquid).

What are the basic features of the theory of the enormous impact ?

According to the Giant Impact Hypothesis, which is the most widely accepted theory for how the moon formed, the Earth and a Mars-sized object called Theia collided with each other as they were forming as protoplanets. The moon was created from a large amount of debris. According to this theory, the Moon was created after the Earth collided with a smaller planet that was around Mars' size. The Moon was created when the impact's leftover debris gathered in an orbit around Earth.

The larger body may have caught the iron core of the striking object.

The key to this theory is understanding how consciousness works and harnessing its power for good. By doing so, we can help to manifest positive changes in our world collectively.

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An ant walks 2 m in a straight line over a period of 40 s. What is the average speed of the ant?

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Answer:

speed is equal to distance/time

so 2m/40s

=0.05

Can somebody help meeeee...?​

Can somebody help meeeee...?

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Answer:

\({ \boxed{ \rm{pressure = \frac{weight}{area} }}} \\ \\ { \rm{pressure = \frac{200}{2} }} \\ \\ { \underline{ \underline{ \rm{ \: \: pressure = 100 \: pascals \: \: }}}}\)

How high must you lift a 25 Newton book for it to have the same increase in potential energy as a 20 Newton book that was lifted to 0.5 meters?

Answers

Given :

An object with weight 20 N was lifted to 0.5 meters.

To Find :

How high must you lift a 25 Newton book for it to have the same increase in potential energy as the given book.

Solution :

Since both have same potential energy :

\(P.E_2 = P.E_1\\\\W_2h_2 = W_1h_1\)

Putting all given values in above equation :

\(25h_2 = 20\times 0.5\\\\h_2 = \dfrac{20\times 0.5}{25}\\\\h_2 = 0.4\ m\)

Therefore, book with same potential energy is at a height of 0.4 m.

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