iupac names of the following ​

The  reaction of cycloalkane with  Br₂ , h₂ produces, alkyl halide as product.

What is reaction?

Chemical reactions are the processes that transform one or more things chemically to create new substances with entirely different properties. Products are entirely different from reactants in nature and identity.

What is cycloalkane?

Cycloalkanes are cyclic hydrocarbons, which means that their molecules' carbon atoms are organized in the shape of a ring. The carbon atoms that make up the ring of cycloalkanes are also saturated, which means that they are all single bonded to other atoms (no double or triple bonds).

Select the missing reagents needed t0 convert each molecule into the next one pictured in the synthetic scheme: H;c_ OH reagent 2 reagent reagent = reagent 4 Select Reagent Select Reagent 2 Select Reagent Select Reagent $.

Reagent 1: Br₂ , h₂

Reagent 2: Mg, ether

Reagent 3:        o

                          ||

                          C

                        /     \

                   CH₃      H

Reagent 4: H₃O⁺

Reaction of cycloalkane with  Br₂ , h₂ produces, alkyl halide as product. Insection of Mg metal into alkyl halide produces Grignard reagent using acetone produces alcohol as produce.

Therefore, reaction of cycloalkane with  Br₂ , h₂ produces, alkyl halide as product.

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Complete Question:

CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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The reaction as shown is a combustion reaction. 29.8 kCal of heat is produced when 4.20 g of ethanol reacts with O2 gas.

The equation of this reaction is shown below;

C2H5OH + 3O2 →2CO2(g)+3H2O(l)+327 kcal

From the reaction equation, we can see that 1 mole of ethanol produces 327 kcal of heat.

Now, we have to find the number of moles in  4.20 g of ethanol  as follows;

Number of moles = mass/molar mass = 4.20 g/46 g/mol = 0.091 moles

If 1 mole of ethanol yields 327 kcal of heat

0.091 moles of ethanol yields 0.091 moles × 327 kcal / 1 mole

= 29.8 kCal

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Therefore, the strong nuclear force happens inside ring C.

An atomic model is a scientific theory or explanation of the structure of an atom. The atomic model describes the various parts of an atom, such as the nucleus, protons, neutrons, and electrons, and how they are arranged within the atom. Different atomic models have been proposed over time as our understanding of the atom has developed. The earliest atomic model, proposed by the Greek philosopher Democritus, suggested that atoms were indivisible and indestructible particles. Later, in the early 20th century, experiments led to the development of the modern atomic model, which describes the atom as consisting of a central nucleus made up of protons and neutrons, surrounded by electrons that orbit the nucleus in shells or energy levels. This model is known as the Rutherford-Bohr model. Since then, new atomic models have been developed that take into account the complex behavior of electrons within the atom, such as the quantum mechanical model. These models are used to explain the behavior and properties of atoms and their interactions with other atoms, molecules, and electromagnetic radiation.

Here,

The strong nuclear force occurs inside the nucleus of the atom, where the protons and neutrons are located. In the given diagram, the nucleus is located inside ring C, where there are 4 protons and 5 neutrons.

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Answer:

Explanation:

Hope it's help !

The atom itself is not the smallest known particle, but instead each atom is made up of three individual parts: electrons, protons and neutrons. Furthermore, protons and neutrons themselves are made up of even smaller parts called quarks.

Atoms are not considered the smallest particles of an element upon recent deliberations. An element has to be an atom, because individual protons, neutrons and electrons aren't elements.

Hydrogen bonding, which is unquestionably what we have, will occur from the intermolecular force between the molecules of H2O and CH3OH. Atoms trade or exchange valence electrons to create bonds.

Trust and self-esteem are developed in children and adolescents through strong emotional ties. After that, they can leave the family and establish wholesome friendships and other types of social ties. Healthy relationships consequently lower a child's chances of emotional discomfort or antisocial behaviour.

The government of a country issues government bonds, a sort of fixed-interest bond. These bonds are thought of as low-risk investments. Examples of different kinds of government bonds include T - bills, Municipality Bond, Zero-Coupon Bonds, and others.

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Answer:

A. Equator

Explanation:

The equator is located in the centre of the Earth, dividing the northern and southern hemispheres.

Answer:

Equator because equator divides the earth into Northern and Southern hemisphere.

The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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According to its location in the periodic table:

It is a table in which elements are ordered in Groups (columns) and Periods (rows).

According to their ubication and properties they can be classified in:

Let's locate and classify the following elements:

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The median reaction at the second end point in the HCl and NaOH titration is: HCl + NaOH → NaCl + H2O

In a titration between hydrochloric acid (HCl) and sodium hydroxide (NaOH), the reaction involved is the neutralization reaction between an acid and a base. The balanced equation for this reaction is:

HCl + NaOH → NaCl + H2O

In this reaction, one mole of HCl reacts with one mole of NaOH to form one mole of NaCl (sodium chloride) and one mole of water.

During the titration process, the reaction occurs gradually as the base is added to the acid solution.

The first end point of the titration is reached when the moles of HCl and NaOH are stoichiometrically equivalent, meaning they react in a 1:1 ratio. At this point, all the HCl has been neutralized by the NaOH, and no excess of either reagent remains.

However, if the titration is continued beyond the first end point, the reaction between HCl and NaOH can still occur, albeit in a different ratio.

The second end point refers to the point where the moles of NaOH added exceed the stoichiometrically required amount to neutralize the HCl completely. As a result, any excess NaOH added after the second end point reacts with the excess HCl in a 1:1 ratio.

Therefore, the median reaction at the second end point in the HCl and NaOH titration is:

HCl + NaOH → NaCl + H2O

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Answer:

mass of water: 8.9 g

Explanation:

Hey there its simple:

mass of water: mass of cylinder with water filled - mass of empty cylinder

mass of water: 32 g - 23.1 g

mass of water: 8.9 g

Answer:

Osmosis is a process which occurs when there is a difference in solute concentration between two solutions separated by a semipermeable membrane. A semipermeable membrane allows passage of water but not of solutes. The passage of water occurs because of a pressure difference of water between the two solutions

A neutralizing reaction takes place when the acid and base are let to interact. The concentration of HCl is 218.12 M.

Determine how much 0.100 M HCI solution is required to neutralize 25.0 mL of 0.350 M NaOH. (Response: 87.5 mL) In order to neutralize 124 mL of 0.250 M NaOH solution, determine the volume of 0.100 M HzSO4 solution required. An acid and base process known as neutralization produces only salt and water. The OH- from the base totally neutralizes the H+ from the acid in this reaction. Therefore, we can define a neutralization reaction as a reaction that creates water by removing the H+ and OH- from the reactant. Here is an example to help you.

HCl + NaOH = NaCl + H₂OOH⁻ + H⁺

mol of solution = molarity × Liter solution

mol HCL = 16.8 ml × 0.50 M

               = 8.4 mol HCl

Concentration of HCl = 8.4/0.0385

                                    = 218.12 M

From the foregoing, it is obvious that the reaction converted the OH- and H+ from the base into water.

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Answer:

flour is the main ingredient sooo you need flour,sugar,salt milk,eggs,vegetable oil,vanilla optional.you can add baking powder or baking soda optional.

Answer:

12 sodium 4 phosphorus 16 oxygen.  makes the table below to determine the number of atoms of each element in the chemical formula 4Ca(ClO3)2.

Solution :

The relationship between pH and \($[H_3O^+]$\)  is pH = \($- \log [H_3O^+]$\)

The concentration of \($[H_3O^+]$\) is given as

pH = \($- \log [H_3O^+]$\)

\($[H_3O^+]=10^{-pH}$\)

           \($=10^{-1.510}$\)

          \($=3.09 \times 10^{-2}$\)

Therefore, the concentration of \($[H_3O^+]$\) is \($=3.09 \times 10^{-2}$\)

The relationship between pH and \($[H_3O^+]$\)  is pH = \($- \log [H_3O^+]$\)

The concentration of \($[H_3O^+]$\) is given as

pH = \($- \log [H_3O^+]$\)

     \($=- \log[0.15]$\)

    = 0.82

Therefore, the pH of the solution is 0.82

Now updating the ICE table for 0.15 M \($CH_3COOH$\) is as follows :

              \($CH_3COOH \ \ \ + \ \ \ H_2O \ \ \rightleftharpoons \ \ CH_3COO^- \ \ + \ \ H_3O^+$\)

\($I\ (M)$\)           0.15                                         0                      0

\($C\ (M)$\)            -x                                           +x                    +x

\($E\ (M)$\)          0.15 - x                                      x                      x

∴ Acidionization constant,

\($K_a=\frac{[CH_3COO^-][H_3O^+]}{[CH_3COOH]}$\)

\($1.82 \times 10^{-5}=\frac{(x)(x)}{(0.15-x)}$\)

\($1.82 \times 10^{-5}=\frac{x^2}{(0.15-x)}$\)

We can assume that :  (0.15 - x) M = 0.15 M

\($1.82 \times 10^{-5}=\frac{x^2}{0.15}$\)

\($x^2=1.82 \times 10^{-5} \times 0.15$\)

\($x^2=2.7 \times 10^{-6}$\)

\($x=1.7 \times 10^{-3} \ M$\)

Therefore, from the equilibrium table,  \($[H_3O^+] =x=1.7 \times 10^{-3} \ M$\)

pH = \($- \log [H_3O^+]$\)

     \($=- \log(1.7 \times 10^{-3} \ M)$\)

     = 2.77

Hence the pH of 0.15 M  \($CH_3COOH$\) is 2.77

Stronger acid always have a lower pH value.

The value of pH for the given solution are 0.0, 7.45, 0.82 and 2.77

So the increasing order of the acidity is :

pH = 0.0 > pH = 0.82 (0.15 M HCl) > pH = 2.77 (0.15 M \($CH_3COOH$\)) > pH =7.45

Hydronium ion concentration can be calculated to know the pH of the solution. The increasing order of acidity is 0, 0.82, 2.77, and 7.45.

pH is the negative logarithm of the hydronium ion concentration. The hydronium ion concentration can be calculated as:

\(\begin{aligned}\rm pH &= \rm - log [H_{3}O^{+}]\\\\&= 10^{-1.510}\\\\&= 3.09 \times 10^{-2}\end{aligned}\)

Thus, the hydronium ion concentration is 0.0309.

The pH when the hydronium ion concentration is 0.15, can be calculated as,

\(\begin{aligned}\rm pH &= \rm - log [H_{3}O^{+}]\\\\&= \rm -log (0.15)\\\\&= 0.82\end{aligned}\)

Thus, the pH of the solution is 0.82.

Now the acid ionization constant is calculated using the ICE table as,

\(\begin{aligned}\rm K_{a} &= \rm \dfrac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}\\\\1.82 \times 10^{-5} &= \rm \dfrac{(x)(x)}{(0.15-x)}\end{aligned}\)

Assuming that (0.15- x) = 0.15 M then,

\(\begin{aligned} 1.82 \times 10^{-5} &= \dfrac{x^{2}}{(0.15-x)}\\\\\rm x^{2} &= 2.7 \times 10^{-6}\\\\&= 1.7 \times 10^{-3}\;\rm M\end{aligned}\)

Now, calculating pH of 0.15 M acetic acid is calculated as:

\(\begin{aligned}\rm pH &= \rm - log [H_{3}O^{+}]\\\\&= \rm -log (1.7 \times 10^{-3})\\\\&= 2.77\end{aligned}\)

The stronger the acid lower will be the pH value. The pH of the solutions is 0.0, 7.45, 0.82, and 2.77.

Therefore, the correct order of the increasing acidity is 0.0 > 0.82 > 2.77 > 7.45.

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The total pressure in a mixture of gases is equal to the partial pressure of all the gases added together

According to Dalton's Law of Partial Pressure,  The total pressure exerted by a mixture of gases which are non reacting is equal to the sum of the partial pressure of each individual gas that make up the mixture

Mathematically, Ut can be written as

P{total}= p1+p2, ....+ pn

where p1, p2, …, pn are partial pressures of each gas component.

For example :A gaseous mixture consisting of Helium and Nitrogen gas . If the pressure exerted by He is 3 atm while Nitrogeb exerted is 9 atm. The total pressure will be:

P{total}= p1+p2, ....+ pn

P{total}= 3+9

P{total}= 12

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Answer:

XSO₄

Explanation:

XCl₂ is the chloride of metal X. The sum of the charges of the cation and the anion must be zero because the salt is electrically neutral. The charge of  the cation of X is:

1 × X + 2 × Cl = 0

1 × X + 2 × (-1) = 0

X = +2

X has a charge +2 and sulphate (SO₄²⁻) a charge -2. The neutral salt they form is XSO₄.

Answer:

Potassium is more reactive than sodium. Potassium is a bigger atom and has lesser ionisation energy than sodium so it is more reactive.

The value of enthalpy(ΔHº) for the final reaction (2C(s) + H₂(g) → C₂H₂(g) ) is  -1932.8KJ.

A system's enthalpy is its heat capacity. A reaction's enthalpy change is roughly equivalent to how much energy is lost or gained throughout the reaction. If the enthalpy of the system decreases over the reaction, the reaction is preferred.

C(s) + O₂(g) → CO₂(g) ΔHº = -94.6 kJ --- (1)

H₂(g) + O₂(g) → H₂O(l) ΔHº = -286.0 kJ ---(2)

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O (l)  ΔHº = -2598.8 kJ ---(3)

The value of ΔHº for the final reaction,

2C(s) + H₂(g) → C₂H₂(g)

ΔH₄° = 2× ΔH₂º +  ΔH₃º - ΔH₁º
ΔH₄° = 2× -286.0 + ( -2598.8) - (- 94.6)

ΔH₄° = 2× -286.0 -2598.8 + 94.6

ΔH₄° = 666 - 2598.8

ΔH₄° = -1932.8KJ.

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The total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag) is also 2.0 moles of electrons.

This is because in a chemical equation, the number of moles of electrons gained by the reducing agent (in this case Ni2+) is equal to the number of moles of electrons lost by the oxidizing agent (in this case Mg(s)).

In this redox reaction, Mg is being oxidized because it loses electrons and Ni is being reduced because it gains electrons. The oxidation and reduction process are occurring simultaneously, so the number of electrons lost by Mg(s) is equal to the number of electrons gained by Ni2+(ag).

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The electrons that are gained by the \(Ni^{2+}\) ion is 2.0 moles of electrons.

We know that when there is a redox reaction, there would be the loss or gain of electrons in the process. The process is a simultaneous one so the electrons that are lost by one specie must as a matter of necessity be gained by another specie.

In this case, as we look at the reaction equation we can see that there are two electrons that have been lost by the magnesium atom and these two electrons would be gained by the Nickel II ion.

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Answer:

Waves are any vibration that transfers energy from place to place.

Explanation:

IM NOT SURE ABOUT THE VIBRATION BIT BUT I AM ABOUT THE ENERGY

To convert acetone (propanone) to propanal, you can use a two-step process involving reduction and oxidation reactions. Here's a general outline of the process:

1. Reduction of Acetone to Isopropanol:

First, you need to reduce acetone to isopropanol (2-propanol) using a reducing agent. Common reducing agents for this step include sodium borohydride (NaBH₄) or lithium aluminum hydride (LiAlH₄).

Reaction conditions:

- Acetone + NaBH₄ (or LiAlH₄) → Isopropanol

- Solvent: usually an alcohol (e.g., methanol or ethanol) or an ether (e.g., THF)

- Temperature: room temperature or slightly above

2. Oxidation of Isopropanol to Propanal:

Next, oxidize isopropanol to propanal using an appropriate oxidizing agent. A common oxidizing agent for this step is pyridinium chlorochromate (PCC), which selectively oxidizes primary alcohols to aldehydes without over-oxidizing to carboxylic acids.

Reaction conditions:

- Isopropanol + PCC → Propanal

- Solvent: an aprotic polar solvent (e.g., dichloromethane)

- Temperature: room temperature

- Avoid strong oxidizing agents like potassium permanganate (KMnO₄) or chromium trioxide (CrO₃) because they can over-oxidize the isopropanol to propionic acid.

Answer:

A ---->gamma ray

Explanation:

Gamma rays have the highest frequencies among all electromagnetic waves and therefore have the shortest wavelengths.

Answer:

How the chemical reacts

Explanation:

The value of Kp for the given reaction at equilibrium is approximately 192,986.689 L atm mol⁻¹.

To calculate the equilibrium constant Kp for the given reaction, we can use the relationship between Kc and Kp, which is expressed as:

Kp = Kc * (RT)^Δn

Where:

- Kp is the equilibrium constant in terms of partial pressures.

- Kc is the equilibrium constant in terms of concentrations.

- R is the ideal gas constant (0.08206 L atm K⁻¹ mol⁻¹).

- T is the temperature in Kelvin.

- Δn is the change in the number of moles of gas (sum of products - sum of reactants).

In this case, the reaction involves four moles of gas on the left-hand side (reactants) and five moles of gas on the right-hand side (products). Therefore, Δn = 5 - 4 = 1.

Given that Kc = 2367 at 999 K, we can substitute these values into the equation:

Kp = 2367 * (0.08206 L atm K⁻¹ mol⁻¹ * 999 K)^1

Simplifying the expression:

Kp = 2367 * (81.367 L atm mol⁻¹)

Calculating the product:

Kp ≈ 192,986.689 L atm mol⁻¹

Therefore, the value of Kp for the given reaction at equilibrium is approximately 192,986.689 L atm mol⁻¹.

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