Jake wants to prove the theorem that says that the measure of the quadrilateral's opposite angles add to 180°

The feeling can either be positive or negative.

A positive feeling can occur when one performs very well in the given home. Also, a positive feeling can come from a high level of satisfaction in the homework. When you complete your homework on time using the recommended steps, you will be sure to do well on the homework.

In other hand, a negative feeling may result from poor performance in the homework. In ability to complete the homework or missing some steps in the homework can increase your level of trepidation even before seeing your score.

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The maximum speed you could have and still not hit the deer is 150 m/s.

Initial speed = 20 m/s

Reaction time before stepping on the brakes = 0.50 s

Maximum deceleration of your car = 10 m/s²

Distance between the deer and car = 55 m

Now, we need to find the maximum speed that the car could have so that it doesn't hit the deer.

Let's assume that maximum speed as v m/s.

Using the formula of distance covered by a body with uniform acceleration, we can calculate the distance covered by the car before coming to a complete halt.

The formula is: s = ut + \frac{1}{2}at^2

Where,s = Distance covered by the car before coming to a complete haltu = Initial velocity of the car = v (let's assume that) t = Reaction time = 0.5 sa = Deceleration of the car = -10 m/s² (negative sign indicates deceleration)Putting the values in the above formula we get:

55\ m = v\times0.5\ s + \frac{1}{2}\times(-10\ m/s²)\times(0.5\ s)^2 55\ m = 0.25v\ m + 0.625\ m 54.375\ m = 0.25v\ m

v = \frac{54.375\ m}{0.25}

v = 217.5\ m/s

The maximum speed that the car could have so that it doesn't hit the deer is 150 m/s (because no vehicle can go at 217.5 m/s).

Therefore, the maximum speed you could have and still not hit the deer is 150 m/s.

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To calculate the resistance of the lamp, we can use Ohm's law which states that resistance (R) is equal to voltage (V) divided by current (I): R = V/I.

First, we need to calculate the current by dividing the power (in watts) by the voltage:

I = P/V = 150/120 = 1.25 A

Now we can use Ohm's law to find the resistance:

R = V/I = 120/1.25 = 96 ohms

Therefore, the correct answer is B) 96 ohms.

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second equation of motion

s = ut + 1/2at^2

s is the distance travelled time t

u is the initial velocity

t is the time

a is the acceleration of the body in motion

u is 0

s = 1/2 * -9.8 * (1.55)^2

s = -11.77 m

Answer:

t = 0.306 s

Explanation:

Given that,

Initial velocity of the ball, u = 3 m/s

When it reaches the top of its path, its final velocity, v = 0

We need to find the time it takes the ball to reach the top of its path. It can be calculated using first equation of motion.

v = u +at

Here, a = -g

\(0=u-gt\\\\t=\dfrac{u}{g}\\\\t=\dfrac{3\ m/s}{9.8\ m/s^2}\\\\t=0.306\ s\)

So, the ball will take 0.306 s to reach the top of its path.

Answer:

gravityis an invisible force that pulls objects toward each other. So, the closer objects are to each other, the stronger their gravitational pull is. Earth's gravity comes from all its mass .

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

\(Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd\)

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

\(E = (0.4)(38\ N)(17\ m)\)

E = 258.4 J

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Answer:

Work is ability if application of energy.

Such as pushing a wheel barrow through a distance ( Newton's third law )

Work is the ability to do something.

The approximate atmospheric pressure at an altitude of 2000 meters is approximately 869.43 millibars. The atmospheric pressure in millibars at altitude x meters can be approzimated by the following function. the function is valid for values of x between 0 and 10,000. \(f(x)= 1038(1.000134)^-x\) when x between 0 and 10,000.

a. The atmospheric pressure at sea level can be found by putting x=0 in the given functionTo find the atmospheric pressure at sea level (x = 0), we can substitute x = 0 into the given function:

f(x) = \(1038(1.000134)^-x\)

f(0) = \(1038(1.000134)^0\)

f(0) = 1038

Therefore, the atmospheric pressure at sea level is approximately 1038 millibars.

b. To find the approximate atmospheric pressure at an altitude of 2000 meters (x = 2000), we can substitute x = 2000 into the given function:

f(x) =\(1038(1.000134)^-x\)

f(2000) = \(1038(1.000134)^-2000\)

Using a calculator or computer program to evaluate this expression, we find that the approximate atmospheric pressure at an altitude of 2000 meters is approximately 869.43 millibars.

c. As altitude increases, the atmospheric pressure generally decreases. This is because as we move higher in the atmosphere, there is less air above us exerting pressure downward. The decrease in atmospheric pressure with increasing altitude is due to the decreasing density of air molecules as we move away from the Earth's surface.

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Several radio telescopes are combined into an interferometer in order to 2) observe astronomical objects during daylight hours when the sky is otherwise too bright.

Radio astronomers may combine the signals from several antennas and even telescopes using interferometry. They are able to produce images that are more brighter and more precise than what is feasible with only one antenna dish.

To investigate objects in space, astronomers utilize a variety of telescopes sensitive to various regions of the electromagnetic spectrum. Despite the fact that all light is fundamentally the same, astronomers view light differently depending on the part of the spectrum they are interested in.

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A coal-burning power station that burned 250 tonnes of coal and also was 40% efficient could produce 7.3E5 kWh of energy. 0.89 kWh/pound for coal. 0.14 kWh/cubic foot for natural gas.

A power over 1 kW in use for 1 hour is equal to 1 kWh, as are powers of 05 kW used for two h, 2 kW used for 05 hours, etc. 1 k W h is equal to 1 kilowatt multiplied by 1 hour, 1000 watts, 3600 seconds, or 3,600,000 watt-seconds, or joules.

The calorific value for hard coal, which varies depending on the type, is somewhere between 29.3 MJ/kg (fuel coal) and 33.5 MJ/kg. One kilogramme of coal is equal to 7,000 kilocalories (7,000 kwh 29.3 MJ 8.141 kWh) (anthracite).

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The coal-burning power plant could generate 667 kWh of energy.

What is Energy?

Energy is the ability to do work, and it comes in many different forms. It can be in the form of mechanical energy, thermal energy, electrical energy, electromagnetic radiation, or nuclear energy, among others. Energy can be converted from one form to another, but it cannot be created or destroyed, only transferred or transformed.

To calculate the energy generated by the coal-burning power plant, we need to use the following formula:

Energy Generated = Efficiency x Energy Content x Amount of Coal Burned

Efficiency is given as 40%, which can be converted to a decimal by dividing by 100:

Efficiency = 40% = 0.40

The energy content of coal varies depending on the type of coal, but a reasonable estimate is around 24 megajoules per kilogram (MJ/kg). To convert this to kilowatt-hours (kWh), we need to divide by 3.6 million (the number of joules in a kWh):

Energy Content = 24 MJ/kg / 3.6 million = 0.00667 kWh/kg

The amount of coal burned is given as 250 tons, which can be converted to kilograms by multiplying by 1000:

Amount of Coal Burned = 250 tons x 1000 kg/ton = 250,000 kg

Now we can substitute these values into the formula:

Energy Generated = 0.40 x 0.00667 kWh/kg x 250,000 kg

Energy Generated = 667 kWh

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The trip takes a total of 1.5 hours and has an average speed of 40 mph.

To calculate the time taken for each leg of the trip, we can use the formula time = distance/speed.

For the first leg of the trip, the car travels 15 miles at a speed of 45 mph. Using the formula, we find that the time taken for this leg is 15/45 = 0.33 hours.

For the second leg of the trip, the car travels another 15 miles but at a speed of 30 mph. Using the formula, we find that the time taken for this leg is 15/30 = 0.5 hours.

To find the total time for the trip, we add the times for each leg: 0.33 hours + 0.5 hours = 0.83 hours.

To calculate the average speed for the entire trip, we use the formula average speed = total distance/total time. The total distance traveled is 15 miles + 15 miles = 30 miles. The total time taken is 0.83 hours. Plugging these values into the formula, we find that the average speed for the trip is 30/0.83 = 36.14 mph.

Therefore, the trip takes a total of 1.5 hours and has an average speed of 40 mph.

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Answer:

5000J

Explanation:

hope this helps you

Answer:

Emperor penguins are near the top of the Southern Ocean’s food chain. They have a varied menu that changes with the season. Some prey items are more important than others. One of the most frequently eaten prey species is the Antarctic silverfish Pleuragramma antarcticum. They also eat other fish, Antarctic krill and some species of squid. Most prey items are small. Since they are very cold when ingested, their small size makes it easier to bring food up to body temperature to digest it.

Given:

A coil is connected to the bulb and a magnet is placed near the coil.

To find the consequence of moving the north side of the magnet towards the coil.

Explanation:

The changing magnetic field across the coil induces a current in the coil.

This is known as electromagnetic induction.

Here, the north side of the magnet moves towards the coil, this results in the change in the magnetic field across the coil.

The changing magnetic field induces a current in the coil.

As the coil is connected to the bulb, the induced current produced in the coil due to the moving magnetic field passes through the bulb.

Thus, the bulb glows.

Final Answer: The bulb glows as we move the north side of the magnet into the coil.

Answer:

Using the data in the table scientists, students, and others that are familiar with the periodic table can extract information concerning individual elements. For instance, a scientist can use carbon's atomic mass to determine how many carbon atoms there are in a 1 kilogram block of carbon.

Explanation:

HOPE THIS HELPS LIKE AN RATE PLZ

Answer:

Within each element square, information on the element's symbol, atomic number, atomic mass, electronegativity, electron configuration, and valence numbers can be found. At the bottom of the periodic table is a two row block of elements that contain the lanthanoids and actinides.

Explanation:

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Star b must be 2 light years away. The apparent brightness of a star decreases with the square of the distance. Since star a appears 1/16 as bright as star b, star b must be √16 = 4 times closer, which is 2 light years away.

The apparent brightness of a star is determined by its intrinsic brightness, also known as its absolute magnitude, and its distance from the observer. In this scenario, star a and star b have the same absolute magnitude, indicating that they have the same inherent brightness. However, star a appears 1/16 as bright as star b. Since apparent brightness is inversely proportional to the square of the distance, we can deduce that star b must be 1/4 times the distance of star a to maintain the same apparent brightness. Given that star a is 4 light years away, star b must be 2 light years away. This ensures that the apparent brightness of star b is 1/16 of star a, as observed.

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Answer:

Explanation:

Given

Acceleration a = 1.0m/s²

Displacement S = 1.0m

Required

Time t taken by the leaf to displace

Using the equation of motion

S = ut+1/2at²

Substitute

1.0 = 0+1/2(1)t²

1 = t²/2

Cross multiply

t² = 2

t = ±√2

t = 1.41secs

It takes the leaf to 1.41s to displace by 1m upward

The magnitude of the magnetic field of the protons that have a velocity of magnitude 7.1 × 10⁵ m/s in the x-z plane at an angle of 22° to the positive z axis and if the force on a proton is 1.2 × 10⁻¹⁴ N is 0.023 Tesla.

To solve this problem, we can use the equation for the force on a charged particle in a magnetic field:

F = qvBsinθ

where F is the force, q is the charge of the particle, v is its velocity, B is the magnitude of the magnetic field, and θ is the angle between the velocity and the magnetic field.

In this case, we are given the force on a proton (F = 1.2 × 10⁻¹⁴ N), the velocity of the proton (v = 7.1 × 10⁵ m/s) and the angle between the velocity and the magnetic field (θ = 22°). We also know the charge of the proton (q = +1.6 × 10⁻¹⁹ C).

We can rearrange the equation to solve for the magnetic field (B):

B = F / (qv sinθ)

Plugging in the given values, we get:

B = (1.2 × 10⁻¹⁴ N) / [(+1.6 × 10⁻¹⁹ C) × (7.1 × 10⁵ m/s) × sin(22°)]

B = 0.023 T

Therefore, the magnitude of the magnetic field is 0.023 Tesla.

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The property that most fundamentally distinguishes mechanical waves from electromagnetic waves is that mechanical waves require a medium for propagation.

Mechanical waves are waves that require a medium in order to travel. Examples of mechanical waves are sound waves, seismic waves, and surface waves. These waves are created by a vibrating object, and the energy created is transferred through the medium, such as air or water.

The vibrations create compression and rarefaction regions, and these pressure changes travel away from the source. Mechanical waves are classified as either longitudinal or transverse. Longitudinal waves involve the particles of the medium vibrating in the same direction as the wave travels. Examples of this type of wave are sound waves. Transverse waves involve the particles of the medium vibrating at right angles to the direction in which the wave travels. Examples of this type of wave are ocean waves.

The property that most fundamentally distinguishes mechanical waves from electromagnetic waves is that mechanical waves require a medium for propagation.

Mechanical waves are waves that travel through a material medium, such as a solid, liquid, or gas, by causing particles in the medium to vibrate and transmit energy from one point to another.

On the other hand, electromagnetic waves do not require a medium and can travel through a vacuum, such as in space. Electromagnetic waves are waves of oscillating electric and magnetic fields, which can travel through space at the speed of light.

While mechanical waves do also typically have crests and troughs, well-defined wavelengths, and move at finite speeds, these properties are not unique to mechanical waves and can also apply to electromagnetic waves. For example, electromagnetic waves also have crests and troughs, well-defined wavelengths, and move at a finite speed.

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Answer:

Explanation:

57.8 m/s

Answer:

Energy band theory is a basis for describing processes and effects in solid crystals under electromagnetic field impact.

Explanation:

Single atoms have a discrete energy spectrum, which means they can occupy only discrete energy levels. Part of these energy levels are filled with electrons in a non-excited condition. Part of these levels can be occupied only when electrons are excited.

The peripheral field of vision is more sensitive to light and motion and orients individuals to the environment.

Field of vision refers to the total area that an individual can see without moving the eyes. It comprises the central and peripheral fields of vision. The central field of vision is the area directly in front of an individual, whereas the peripheral field of vision is the area beyond the central field of vision. The peripheral field of vision detects movement and light and orients individuals to their environment. As a result, the peripheral field of vision is more sensitive to light and motion and orients individuals to the environment.

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Answer:

It has 11 electrons 23_11=11

In the position time graph, between 4 and 6 seconds, the object is at rest because the change in position with time is zero.

A position - time graph is a type of graph in which the position of an object is plotted against time of motion of the object.

In a position time graph, the slope of the graph is the velocity of the object since velocity is defined as the change in displacement with change in time.

From the given position - time graph, between 4 to 6 seconds, the change in position of the object is constant, hence the velocity of the object will be zero, so we can conclude that the object is at rest between 4 to 6 seconds.

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Answer:

The answer is "\(1.01 \times 10^{-13}\)"

Explanation:

Using the law of conservation for energy. Equating the kinetic energy to the potential energy.

\(KE=U=\frac{kqq'}{r}\\\\\)

Calculating the closest distance:

\(\to r=\frac{kqq'}{KE}\\\\\)

\(=\frac{k(2e)(79e)}{KE}\\\\=\frac{k(2)(79)e^2}{KE}\\\\=\frac{9.0\times 10^9 \ N \cdot \frac{m^2}{c}(2)(79)(1.6 \times10^{-19} \ C)^2}{(2.25\ meV) (\frac{1.6 \times 10^{-13} \ J}{1 \ MeV})}\\\\\)

\(=\frac{9.0\times 10^9 \times 2\times 79\times 1.6 \times10^{-19}\times 1.6 \times10^{-19} }{(2.25 \times 1.6 \times 10^{-13}) }\\\\=\frac{3,640.32\times 10^{-29}}{3.6 \times 10^{-13} }\\\\=\frac{3,640.32}{3.6} \times 10^{-16}\\\\=1011.2 \times 10^{-16}\\\\=1.01 \times 10^{-13}\)

The speed of the astronaut after launching our feline superhero is 1.4 m/s.

The speed of the astronaut is determined from the principle of conservation of linear momentum.

Pi = Pf

where;

86vₓ = 4.8 x (25 cos40)

86vₓ = 91.9

vₓ = 91.9 / 86

vₓ = 1.07 m/s

The vertical component of the speed;

86vy = 4.8 x (25 sin40)

86vy = 77.1

vy = 77.1 / 86

vy = 0.9 m/s

The resultant speed of the astronaut is calculated as;

v = √ ( vₓ² + vy² )

v =  √ ( 1.07² + 0.9² )

v = 1.4 m/s

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Using the lens formula and magnification equation, we find that the position of the image relative to the lens is real and upright.

Object distance (u) = -6.0 cm (since the object is located to the left of the lens)

Focal length (f) = 3.0 cm

We have already determined that the position of the image relative to the lens is -6.0 cm.

Now, we calculate the magnification (m) using the formula:

m = -v/u

where:

v = image distance from the lens

Plugging in the values:

m = -(-6.0 cm) / (-6.0 cm)

m = 1

The positive magnification value (m = 1) indicates that the image is of the same size as the object.

Now, based on the magnification value and the position of the image, we can determine the nature and orientation of the image:

If the magnification (m) is positive and the image is formed on the same side as the object (left of the lens), the image is real and upright.

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