Joe’s broker’s fee schedule is given in the table. Joes current portfolio is worth $50,000. He wants to purchase 50 shares of a company’s stock fir a purchase price of $15 per share.


Joe will need to pay a commission of _____.


The total amount charged by the broker will be ______.


Space 1: $7. 50, $5. 00, $1. 50

Space 2: $17. 50, $15. 50, $15. 0

An expression for 2n-1 is: 2n-1 = (2n+1 - 1)/(2n(2n-1)), for n = 1, 2, ....  The general solution is: \(y(x) = c1exp(x^2) + c2exp(-2x^2)\), where c1 and c2 are constants. The power series solution of the initial value problem is:\(y(x) = 4 - 6x - 12x^2 + 16x^3 - 16x^4 + 256/15 x^5 - 1024/96 x^6 + 2048/315 x^7 - 32768/460\)

2.1 Using the recurrence relation, we can obtain an expression for 2n-1 as follows:

Cn+2 = (n+1)Cn+1 + 22Cn

For n=0, we have:

C2 = C1 + 22C0

Substituting C1 = 1.3.5 and C0 = c, we get:

C2 = 1.3.5 + 22c

For n=1, we have:

C3 = 2C2 + 22C1

Substituting C2 = 1.3.5 + 22c and C1 = 1, we get:

C3 = 2(1.3.5 + 22c) + 22

Simplifying, we get:

C3 = 1.3.5.7 + 2.2.3.5c + 22

Comparing with the general expression for Cn+2, we get:

2n+1 - 1 = 2.2n(2n-1)cn

Solving for 2n-1, we get:

2n-1 = (2n+1 - 1)/(2n(2n-1))

Hence, an expression for 2n-1 is:

2n-1 = (2n+1 - 1)/(2n(2n-1)), for n = 1, 2, ...

2.2 The general solution of the differential equation y" - 2xy' - 4y = 0 can be written as a linear combination of the two linearly independent solutions:

\(y1(x) = c1exp(x^2)\\y2(x) = c2exp(-2x^2)\)

Hence, the general solution is:

\(y(x) = c1exp(x^2) + c2exp(-2x^2)\)

where c1 and c2 are constants.

2.3 To find the power series solution of the initial value problem y" - 2xy' - 4y = 0, y(0) = 4, y'(0) = -6, we first need to find the coefficients of the power series solution y(x).

Substituting y = Σn=0∞ anxn into the differential equation, we get:

Σn=0∞ [(n+2)(n+1)an+2 - 2n an - 4an]xn = 0

Equating the coefficients of xn, we get:

(n+2)(n+1)an+2 - 2n an - 4an = 0

Simplifying, we get:

an+2 = (2n/(n+2))an

Using the initial conditions y(0) = 4 and y'(0) = -6, we get:

a0 = 4

a1 = -6

Substituting the recurrence relation, we get:

a2 = -12

a3 = 48/3 = 16

a4 = -128/8 = -16

a5 = 256/15

a6 = -1024/96

a7 = 2048/315

a8 = -32768/4608

Hence, the power series solution of the initial value problem is:

\(y(x) = 4 - 6x - 12x^2 + 16x^3 - 16x^4 + 256/15 x^5 - 1024/96 x^6 + 2048/315 x^7 - 32768/460\)

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Answer:

Step-by-step explanation:

24-6=18

now 2022 so

2022-18=2004

Answer:

undefined

Step-by-step explanation:

Since the x value is the same, it looks like the slope is undefined.

Answer:  The slope is undefined

Step-by-step explanation:

Find the difference in the y coordinates and divide it by the difference in the x coordinates

y coordinates : 5 - 8 = -3  

x coordinates: -10 -(-10) = 0  

slope:  -3/0 = 0  

Step-by-step explanation:

3rd option is correct it's 9-³

Answer:

C

Step-by-step explanation:

C and 1/9^3 matches.

====================================================

Explanation:

If angle A is 43 degrees, then minor arc BC is 2*43 = 86 degrees according to the inscribed angle theorem. The central angle is twice that of the inscribed angle. Both of these angles subtend the same minor arc.

When I say "minor arc BC", I mean that we go from B to C along the shortest path. Any minor arc is always less than 180 degrees.

Since minor arc AB is 69 degrees, and minor arc BC is 86 degrees, this means arc ABC is arcAB+arcBC = 69+86 = 155 degrees

Let's say point D is some point on the circle that isn't between A and B, and it's not between B and C either. Refer to the diagram below. The diagram is to scale. The diagram your teacher provided is not to scale because arc ABC is way too big (it appears to be over 180 degrees). Hopefully the diagram below gives you a better sense of what's going on.

Because arc ABC = 155 degrees, this means the remaining part of the circle, arc ADC, is 360-(arc ABC) = 360-155 = 205 degrees

Inscribed angle B subtends arc ADC. So we'll use the inscribed angle theorem again, but this time go in reverse from before. We'll cut that 205 degree angle in half to get 205/2 = 102.5 degrees which is the measure of angle B. This value is exact. In this case, we don't need to apply any rounding.

The time taken for the water level in the tank to drop from 3 to 0.5 meters above the bottom cannot be determined without additional information.

To calculate the time taken, we need to know the flow rate or discharge rate of the water from the tank. This information is not provided in the question. The time taken to drain the tank depends on factors such as the diameter of the outlet pipe, the pressure difference, and any restrictions or obstructions in the flow path.

If we assume a known discharge rate, we can use the principles of fluid mechanics to calculate the time. The volume of water that needs to be drained is the difference in the volume of water between 3 meters and 0.5 meters above the bottom of the tank. The flow rate can be determined using the pipe diameter and other relevant factors. Dividing the volume by the flow rate will give us the time taken.

However, since the discharge rate is not given, we cannot perform the calculation and determine the time taken accurately.

Without knowing the discharge rate or additional information about the flow characteristics, it is not possible to calculate the time taken for the water level in the tank to drop from 3 to 0.5 meters above the bottom.

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Answer:

225 adult tickets

530 student tickets

Step-by-step explanation:

Answer:

3\(\sqrt{2}\)

Step-by-step explanation:

Using the rule of radicals

\(\sqrt{a}\) × \(\sqrt{b}\) ⇔ \(\sqrt{ab}\)

Simplify the given radicals

\(\sqrt{50}\)

= \(\sqrt{25(2)}\)

= \(\sqrt{25}\) × \(\sqrt{2}\)

= 5\(\sqrt{2}\)

------------------------

\(\sqrt{72}\)

= \(\sqrt{36(2)}\)

= \(\sqrt{36}\) × \(\sqrt{2}\)

= 6\(\sqrt{2}\)

-----------------------

\(\sqrt{128}\)

= \(\sqrt{64(2)}\)

= \(\sqrt{64}\) × \(\sqrt{2}\)

= 8\(\sqrt{2}\)

Then

\(\sqrt{50}\) + \(\sqrt{72}\) - \(\sqrt{128}\)

= 5\(\sqrt{2}\) + 6\(\sqrt{2}\) - 8\(\sqrt{2}\)

= 11\(\sqrt{2}\) - 8\(\sqrt{2}\)

= 3\(\sqrt{2}\)

The different routes are 479,001,600

The number of cities is given as:

n = 12

The cities are different.

So, the number of routes is:

Routes = 12!

Expand

Routes =12 * 11 * 10 * 9 * ..... * 1

Evaluate

Routes =479,001,600

Hence, the different routes are 479,001,600

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Answer:

g = - 43

Step-by-step explanation:

Comment

f(x) = -2x^2 + 2x  - 3

f(5) means that wherever you see an x on the right hand side (because x is given inside the brackets on the left), you put a 5 because x = 5

Solution

f(5) = -2*(5)^2 + 2(5) - 3

f(5) = -2(25) + 10 - 3

f(5) = -50 + 10 - 3

f(5) = -43

Answer:

50g

Step-by-step explanation:

83g

3hrs=5g

83/5=16.6

16.6x3=49.8=50g

This is about understanding sets.

Option A is correct.

Thus, the subsets would be;

{a}, {b}, {c}, {a,b}, {a, b, c}, {a, c}, {b,c}

Applying the same principle used in the example above, we can write the subsets as;

{2};{-2};{-2,2}

Thus, option A is the correct answer.

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Answer:

a

Step-by-step explanation:

Answer:

x2+8x+15=(x+5)(x+3)

Step-by-step explanation:

Trinomials have the form: ax2+bx+c. When factoring trinomials where a=1

Answer:

x(x - 8)

Step-by-step explanation:

First, factor out an x from both terms:

x² - 8x

x(x - 8)

So, the factored form of the binomial is x(x - 8)

3.1 The function that models the pairs sold (s) over time (t) is:

\(s(t) = -3t^2 + 6t + 2.\)

3.2 The estimated number of pairs of shoes sold after 6 weeks is -70.

3.1 To write a function that models the pairs sold (s) over time (t), we can use the given data points to find the pattern or relationship between the weeks (t) and the pairs sold (s).

From the table:

Week (t) Pairs sold (s)

1 5

3 2

5 48

By observing the data, we can see that the pairs sold (s) increases by a certain amount after each week. Let's calculate the difference between consecutive pairs sold:

Difference between pairs sold at week 3 and week 1: 2 - 5 = -3

Difference between pairs sold at week 5 and week 3: 48 - 2 = 46

We notice that the difference is not constant, which suggests a nonlinear relationship. To model this, we can use a quadratic function.

Let's assume the function is of the form s(t) = at^2 + bt + c, where a, b, and c are constants to be determined.

Substituting the given data point (t, s) = (1, 5) into the function, we get:

\(5 = a(1)^2 + b(1) + c\)

5 = a + b + c (Equation 1)

Substituting the data point (t, s) = (3, 2) into the function, we get:

\(2 = a(3)^2 + b(3) + c\)

2 = 9a + 3b + c (Equation 2)

Substituting the data point (t, s) = (5, 48) into the function, we get:

\(48 = a(5)^2 + b(5) + c\)

48 = 25a + 5b + c (Equation 3)

Now we have a system of three equations (Equations 1, 2, and 3) that we can solve to find the values of a, b, and c.

Solving the system of equations, we find:

a = -3

b = 6

c = 2

Therefore, the function that models the pairs sold (s) over time (t) is:

\(s(t) = -3t^2 + 6t + 2.\)

3.2 To estimate the number of pairs of shoes sold after 6 weeks, we can substitute t = 6 into the function \(s(t) = -3t^2 + 6t + 2.\)

\(s(6) = -3(6)^2 + 6(6) + 2\)

s(6) = -3(36) + 36 + 2

s(6) = -108 + 36 + 2

s(6) = -70

Therefore, the estimated number of pairs of shoes sold after 6 weeks is -70.

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Answer:

do you have answer

Step-by-step explanation:

The experimental probability that Kyle's next toss will be a hit is 11/18 or approximately 0.61.

The experimental probability of Kyle's next toss being a hit can be calculated by dividing the number of hits by the total number of tosses. In this case, the total number of tosses is the sum of hits and misses, which is 22 + 14 = 36. Therefore, the experimental probability of Kyle's next toss being a hit is 11/18 or approximately 0.61.
To find the experimental probability of Kyle's next toss being a hit, you need to consider the number of hits and total tosses so far.
Hits: 22
Misses: 14
Total tosses: 22 hits + 14 misses = 36 tosses
Now, calculate the experimental probability by dividing the number of hits by the total number of tosses:
Experimental probability = Hits / Total tosses = 22 / 36
Simplify the fraction:
Experimental probability = 11/18
So, the experimental probability that Kyle's next toss will be a hit is 11/18.

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Answer:

11/18

Step-by-step explanation:

By splitting the fraction, we can write the given expression as n²/(n+9)-8n/(n+9)+1/(n+9). Therefore, option E is the correct answer.

The division is one of the basic arithmetic operations in math in which a larger number is broken down into smaller groups having the same number of items.

The given expression is (n²-8n+1)÷(n+9).

By splitting the fraction, we get

n²/(n+9)-8n/(n+9)+1/(n+9)

Therefore, option E is the correct answer.

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The given null hypothesis statement a. true, statement b. true and finally statement c. true.

a. False. Rejection of the null hypothesis using ANOVA only tells us that at least one group mean is different from the others, but it doesn't necessarily mean that all means are different from each other. Additional post-hoc tests, such as Tukey's HSD or Bonferroni, are needed to identify which specific means are different from each other.

b. True. If the null hypothesis is rejected using ANOVA, it means that there is significant variability between the groups. This variability is measured by the F-statistic, which is the ratio of between-group variability to within-group variability. A high F-statistic indicates that the standardized variability between groups is higher than the standardized variability within groups.

c. True. If the null hypothesis is rejected using ANOVA, it means that there is at least one significant difference between the means of the groups. Pairwise comparisons can be conducted using post-hoc tests to identify which specific pairs of means are significantly different. However, it's important to adjust the significance level for multiple comparisons to avoid making Type I errors.

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To evaluate c ∇f · dr, we need to first find the gradient vector ∇f and the differential vector dr.

Since the function f is not given, we cannot find ∇f explicitly. However, we know that ∇f points in the direction of greatest increase of f, and that its magnitude is the rate of change of f in that direction. Therefore, we can make an educated guess about the form of ∇f based on the information given.

The function f could be any function, but let's assume that it is a function of two variables x and y. Then, we have:

∇f = (∂f/∂x, ∂f/∂y)

where ∂f/∂x is the partial derivative of f with respect to x, and ∂f/∂y is the partial derivative of f with respect to y.

Now, let's find the differential vector dr. The parameterization of c is given by:

x = t^2 + 1

y = t^3 + t

0 ≤ t ≤ 1

Taking the differentials of x and y, we get:

dx = 2t dt

dy = 3t^2 + 1 dt

Therefore, the differential vector dr is given by:

dr = (dx, dy) = (2t dt, 3t^2 + 1 dt)

Now, we can evaluate c ∇f · dr as follows:

c ∇f · dr = (c1 ∂f/∂x + c2 ∂f/∂y) (dx/dt, dy/dt)

where c1 and c2 are the coefficients of x and y in the parameterization of c, respectively. In this case, we have:

c1 = 2t

c2 = 3t^2 + 1

Substituting these values, we get:

c ∇f · dr = (2t ∂f/∂x + (3t^2 + 1) ∂f/∂y) (2t dt, 3t^2 + 1 dt)

Now, we need to make an educated guess about the form of f based on the information given. We know that f is a function of x and y, and we could assume that it is a polynomial of some degree. Let's assume that:

f(x, y) = ax^2 + by^3 + cxy + d

where a, b, c, and d are constants to be determined. Then, we have:

∂f/∂x = 2ax + cy

∂f/∂y = 3by^2 + cx

Substituting these values, we get:

c ∇f · dr = [(4at^3 + c(3t^2 + 1)t) dt] + [(9bt^4 + c(2t)(t^3 + t)) dt]

Integrating with respect to t from 0 to 1, we get:

c ∇f · dr = [(4a/4 + c/2) - (a/2)] + [(9b/5 + c/2) - (9b/5)]

Simplifying, we get:

c ∇f · dr = -a/2 + 2c/5

Therefore, the value of c ∇f · dr depends on the constants a and c, which we cannot determine without more information about the function f.

The value of c where c has parametric equations x = t2 + 1, y = t3 + t, 0 t 1. is  c ∇f · dr=  [(2t^5 + 2t^3)(∂f/∂x) + (9t^7 + 3t^5)(∂f/∂y)] dt.

We have the following information:

c(t) = (t^2 + 1)i + (t^3 + t)j, 0 ≤ t ≤ 1

f(x, y) is a scalar function of two variables

We need to find c ∇f · dr.

We start by finding the gradient of f:

∇f = (∂f/∂x)i + (∂f/∂y)j

Then, we evaluate ∇f at the point (x, y) = (t^2 + 1, t^3 + t):

∇f(x, y) = (∂f/∂x)(t^2 + 1)i + (∂f/∂y)(t^3 + t)j

Next, we need to find the differential vector dr = dx i + dy j:

dx = dx/dt dt = 2t dt

dy = dy/dt dt = (3t^2 + 1) dt

dr = (2t)i + (3t^2 + 1)j dt

Now, we can evaluate c ∇f · dr:

c ∇f · dr = [c(t^2 + 1)i + c(t^3 + t)j] · [(∂f/∂x)(2t)i + (∂f/∂y)(3t^2 + 1)j] dt

= [c(t^2 + 1)(∂f/∂x)(2t) + c(t^3 + t)(∂f/∂y)(3t^2 + 1)] dt

= [(t^2 + 1)(2t^3 + 2t)(∂f/∂x) + (t^3 + t)(9t^4 + 3t^2)(∂f/∂y)] dt

Therefore, c ∇f · dr = [(2t^5 + 2t^3)(∂f/∂x) + (9t^7 + 3t^5)(∂f/∂y)] dt.

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Step-by-step explanation:

PS:Thas some questoin

The given geometric progression's fourth, seventh, and ninth term is 24, 192, and 768 respectively.

In mathematics, a sequence known as a geometric progression (GP) is one in which each following term is generated by multiplying each preceding term by a constant integer, known as a common ratio. This progression is sometimes referred to as a pattern-following geometric sequence of numbers. Learn development in mathematics here as well. Here, each phrase is multiplied by the common ratio to generate the subsequent term, which is a non-zero value.

The given geometric progression: 3,6,12,24.......

The first term of GP is a = 3 and the Common ratio r = 2,

We know that the nth term of GP is,

\(T_n=ar^{n-1}\)

We have to Find the 4, 7, and 9th terms of  above mentioned GP,

\(T_4\\\\T_4=ar^{4-1}\\\\T_4=3*2^3\\\\T_4=24\\\\\\T_7\\\\T_7=3*2^{7-1}\\\\T_7=192\\\\\\T_9\\\\T_9=3*2^{9-1}\\\\T_9=768\)

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Answer:

wat is dat about? :3

Historical scientists deal with falsification by rigorously analyzing evidence, using peer review and scholarly discourse, and revising hypotheses based on new discoveries and interpretations.



Historical scientists deal with falsification by employing rigorous methodologies and critical analysis of evidence. They strive to gather as much relevant data as possible to test hypotheses and theories. This is done through meticulous research, including the examination of primary sources, archaeological artifacts, historical records, and other forms of evidence. Historical scientists also engage in peer review and scholarly discourse to subject their findings to scrutiny and criticism.

The mechanism used by historical scientists to falsify hypotheses involves a combination of evidence-based reasoning and the application of established principles of historical analysis. They aim to construct coherent and logical explanations that are supported by the available evidence. If a hypothesis fails to withstand scrutiny or is contradicted by new evidence, it is considered falsified or in need of revision. Historical scientists constantly reassess and refine their hypotheses based on new discoveries, reinterpretation of existing evidence, and advancements in research techniques. This iterative process helps to refine our understanding of the past and ensures that historical knowledge remains dynamic and subject to revision.

Therefore, Historical scientists deal with falsification by rigorously analyzing evidence, using peer review and scholarly discourse, and revising hypotheses based on new discoveries and interpretations.

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(a) The derivative of the function f(x)=5x 6−3x 2/3−7x −2 +4/3x can be found using the power rule and the quotient rule. Taking the derivative term by term, we have:

f ′(x)=30x5−2x −1/3+14x −3-12x 4

(b) To differentiate the function (h(s)=(1+s) 4 (3s3+2), we can apply the product rule and the chain rule. Taking the derivative term by term, we have:

(s)=4(1+s) 3(3s3 +2)+(1+s) 4(9s2)

Simplifying further, we get:

(s)=12s3+36s 2+36s+8s 2+8

Combining like terms, the final derivative is:

ℎ′(s)=12s +44s +36s+8

In both cases, we differentiate the given functions using the appropriate rules of differentiation. For (a), we apply the power rule to differentiate each term, and for (b), we use the product rule and the chain rule to differentiate the terms. It is important to carefully apply the rules and simplify the result to obtain the correct derivative.

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When given the value of 5/4 hours then in minutes this is equal to 75 minutes.

In every hour, there are 60 minutes. If you want to covert hours to minutes therefore, you multiply the number of hours by 60 minutes.

When given the number of hours as 5/4 hours, in minutes this becomes:

= Number of hours x 60 minutes per hour

= 5/4 x 60 minutes per hour

= 300 / 4 minutes

= 75 minutes

In conclusion, the number of minutes in 5/4 hours is equal to 75 minutes.

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The associated radius of convergence R is 0.

Answer: \(ln(4) + (1/4)(x-4) - (1/32)(x-4)^2 + (1/64)(x-4)^3 - (3/256)(x-4)^4 and R = 0.\)

We need to find the Taylor series for f(x) centered at the given value of a.

To find the Taylor series for ln(x) function we use the formula of the Taylor series which is:

\(f(x) = f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + ....+ f^n(a)(x-a)^n/n!......eqn.1\)

Differentiating the given function ln(x), we get;

\(f'(x) = 1/x ......eqn.2\\f''(x) = -1/x^2 .......eqn.3\\f'''(x) = 2!/x^3 .....eqn.4\\f^4(x) = -3! /x^4 ....eqn.5\)

Therefore, substituting the values of a, f(a), f'(a), f''(a), f'''(a) and f^4(a) in eqn.1, we get;

\(ln(x) = ln(4) + (1/4)(x-4) - (1/32)(x-4)^2 + (1/64)(x-4)^3 - (3/256)(x-4)^4 ......eqn.6\)

The associated radius of convergence R is given by the formula;

\(R = lim |a_n / a_n+1 |\)

where a_n is the nth term of the series.

In this case, the nth term is (x-4)^n/n!

Therefore, \(a_n+1 = (x-4)^(n+1) / (n+1)! and a_n = (x-4)^n/n!.\)

Substituting these values in the formula, we get;

\(R = lim|(x-4)^n/n! x (n+1)!/(x-4)^(n+1) |\)

on simplifying, we get;

\(R = lim |(x-4)/(n+1)|\)

as n approaches, infinity, the denominator in the above equation becomes very large, and thus R approaches 0.

Hence the associated radius of convergence R is 0. Answer: \(ln(4) + (1/4)(x-4) - (1/32)(x-4)^2 + (1/64)(x-4)^3 - (3/256)(x-4)^4\) and R = 0.

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Step-by-step explanation:

Step 1:  Convert degrees into radians

\(\frac{degrees}{1}*\frac{\pi }{180}\)

\(\frac{52}{1}*\frac{\pi}{180}\)

\(\frac{52\pi}{180}\)

\(\frac{13\pi}{45}\)

Step 2:  Find the arc length

\(S = r\theta\)

\(S=(3)(\frac{13\pi}{45})\)

\(S = \frac{39\pi}{45}\)

\(S=\frac{13\pi}{15}\)

Answer: Option B