John drives his car 120 miles east in 2 hours, 90 miles east in 1.5 hours, then he stops at the gas station for half an hour. He soon realizes that he has to go back 8 miles west which takes him one hour to reach his final destination. Calculate his average velocity during the entire time.

Answer:

To find the volume of a rectangular object, measure the length, width and height. Multiply the length times the width and multiply the result by the height. The result is the volume. Give the result in cubic units, such as cubic centimeters.

Explanation:

Answer:

Kinetic energy is the energy possessed by an object due to its motion. If an object is moving, then it has kinetic energy. The amount of kinetic energy depends on mass and speed.

Explanation:

Explanation:

When the wire is connected to a battery, the compass needle moves and changes its position. This happens because the needle magnetizes the copper wire, thus,  creating a force.

While the current in the wire produces a magnetic field and exerts a force on the needle. The insulation on the wire becomes energized and exerts a force on the needle. Hence, the compass needle moves and changes its position.

Answer: 28.0134 g/mol

Explanation:

For a molecule (for example, nitrogen, N2) the mass of molecule is the sum of the atomic masses of the two nitrogen atoms. For nitrogen, the mass of the N2 molecule is simply (14.01 + 14.01) = 28.02 amu.

might stumble upon this substance one day and be curious about what it does.

Answer:

2 meters

Explanation:

In oceanography, the term "wave height" refers to the vertical distance between the crest (the highest point) and the trough (the lowest point) of a wave. If you are situated in the trough of a wave, the wave height would be double the wave amplitude.

In this case, you mentioned that the wave amplitude is 1 meter. Therefore, the wave height from your position in the trough would be 2 meters.

At 7 pm, the distance between the ships is changing at a rate of 27.4 mph.

To find the rate of change of the distance between the ships, we can use the Pythagorean theorem to find the distance between the ships at any given time, and then take the derivative of that distance with respect to time to find the rate of change.

At noon, ship A is 10 miles due west of ship B. After t hours, ship A will have traveled 17t miles west, and ship B will have traveled 22t miles north.

The distance between the ships at time t will be:

\sqrt{((10 + 17t)^2 + (22t)^2)}

To find the rate of change of the distance between the ships, we take the derivative of this distance with respect to time:

\(d/dt (\sqrt{((10 + 17t)^2 + (22t)^2))} = (17(10 + 17t) + 22(22t))/(\sqrt{((10 + 17t)^2 + (22t)^2))}\)

At 7 pm, t = 7,

so we can plug this into the equation to find the rate of change of the distance between the ships at 7 pm:

\(d/dt(\sqrt{((10 + 17(7))^2 + (22(7))^2))} = (17(10 + 17(7)) + 22(22(7)))/(\sqrt{((10 + 17(7))^2 + (22(7))^2))}\)

=>  27.4 mph

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The average velocity of the object is 8.6 m/s.

From x = 12 m to x = 124 m, then from x = 124 to x = 98, the start point is x = 12 m and end point is 98 m.

Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.

Displacement = 98 - 12 = 86 m.

The time take is, 10 seconds.

Now, the velocity is the ratio of displacement and time.

Velocity = displacement/time

Velocity = 86/10

Velocity = 8.6 m/s

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To find the slope of the position-time relationship for the bowling ball using the "rise over run" algorithm, you'll first need the coordinates obtained in part b. The slope represents the rate of change of position with respect to time, and in this context, it is equal to the ball's velocity.

Using the "rise over run" algorithm, the slope (velocity) can be calculated by dividing the change in position (rise) by the change in time (run). In this case, the coordinates represent the position and time values, with the first coordinate being the initial position and time, and the second coordinate being the final position and time.

Assuming you have two coordinates (x1, y1) and (x2, y2), where x values represent time and y values represent position:

Slope = (y2 - y1) / (x2 - x1)

Once you have the coordinates from part b, plug the values into the formula above to calculate the slope. This will give you the velocity of the bowling ball, which represents the relationship between the position and time for the given motion.

For example, if the coordinates from part b are (0.4 s, 2.5 m) and (0.8 s, 5 m), the slope would be:

Slope = (5 m - 2.5 m) / (0.8 s - 0.4 s) = 2.5 m / 0.4 s = 6.25 m/s

In this example, the slope (velocity) of the position-time relationship for the bowling ball is 6.25 m/s.

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Wanda can reply to her friend by saying that she is using a telephoto lens for their photography outing.

A telephoto lens is a type of camera lens that is designed to capture distant subjects by using a longer focal length than a standard lens. Telephoto lenses typically have a focal length of 60mm or longer, which allows them to see and record a very narrow view. This makes them ideal for capturing subjects that are far away, such as wildlife, sports events, and landscapes. Telephoto lenses are also popular for portrait photography because they can create a shallow depth of field, which helps to isolate the subject from the background.

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Answer:

Hey there!

Potential Energy = mgh, (mass x gravitational acceleration x height)

Given that the gravitational acceleration is constant, we just have Potential Energy = mh

a. 2(3)=6

b. 2(5)=10

c. 4(3)=12

d. 4(5)=20

The four-pound brick that is five feet off the ground is the brick with the most potential energy.

Let me know if this helps :)

1. Mars's average distance from the sun is approximately 1.52 astronomical units.

2. The Pluto's orbital period is about 248.09 years.

3. The Neptune's orbital period is 3.33 times longer than Saturn's orbital period.

4. The imaginary planet's average distance from the sun is approximately 6 astronomical units.

1. Kepler's third law relates the square of a planet's orbital period to the cube of its average distance from the sun. This is expressed by the equation P^2 = a^3, where P is the planet's period in Earth years and a is its distance from the sun in astronomical units (AU).

To find the average distance of Mars from the sun, we can use Kepler's third law: P^2 = a^3. We know that Mars's period around the Sun is 686 days, which is about 1.88 Earth years. Substituting 1.88 for P, we can solve for a: (1.88)^2 = a^3, a ≈ 1.52 AU.

2. To find Pluto's orbital period, we can rearrange Kepler's third law to solve for P: P = (a^3) / k, where k is a constant that depends on the mass of the central body (in this case, the sun). For the sun, k is approximately 1. To find Pluto's period, we need to solve for P when a is 40 AU: P = (40^3) / 1, P ≈ 248.09 years.

3. To find Neptune's orbital period in terms of Saturn's orbital period, we can use Kepler's third law and compare the ratios of their distances to the sun: (a_Neptune)^3 / (a_Saturn)^3 = (P_Neptune)^2 / (P_Saturn)^2.

We know that Saturn's distance from the sun is 9 AU and Neptune's distance is 30 AU.

Substituting these values into the equation and solving for P_Neptune, we get:

(30^3 / 9^3) = (P_Neptune)^2 / (P_Saturn)^2, (10/3)^3 = (P_Neptune / P_Saturn)^2, P_Neptune / P_Saturn = 10/3.

4. Kepler's third law can also be used to find the average distance of a planet from the sun if we know its period. In this case, we are given that Venus takes 223 days to orbit the sun, or about 0.61 Earth years.

If an imaginary planet takes 25 times longer to orbit, its period would be 25 * 0.61 = 15.25 Earth years. Using Kepler's third law, we can solve for the average distance of this planet from the sun: (15.25)^2 = a^3, a ≈ 6.00 AU.

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Answer: Yes the objects would be balanced.

Explanation:

If there is no net force then the object will not move in any direction, meaning that the object is balanced.

An object launched at 65° from the horizontal would have the same range (distance travelled) as an object launched at 25° from the horizontal.

The greatest range you can get when you launch a projectile is to aim it at 45° above the horizon.  If you change that angle by something, then the range is shorter by the same amount if you increse OR decrease the angle by the same something.

65° = 45° plus 20°.  So the range will be the same if you launch at an angle of (45° minus 20°).  That's 25°.

Answer:

Hypothesis.

Explanation:

Not a question, not a summary, and not an experiment.

Answer:

1254 J

Explanation:

Applying,

Q = mcpΔT................... Equation 1

Where Q = heat, m = mass of water, cp = specific heat capacity of water, ΔT = Change in temperature.

From the question,

Given: m = 15 g, cp = 4.18 J/(g.°C), ΔT = 20°C

Substitute these values into equation 1

Q = 15×4.18×20

Q = 1254 J

Hence the amount of energy required is 1254 J

Answer:

the glass and paper have diffrent charges

Explanation:

if the glass is charged positively then the paper was charged negatively

the to charges were to attract think of it as a magnet

Answer:

The answer is B. the glass and the paper have different charges

Explanation:

The glass will attract the pieces of paper. Remember opposite charges attract

The measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

Option C.

The median is the middle point in a dataset—half of the data points are smaller than the median and half of the data points are larger.

To find the median: Arrange the data points from smallest to largest. If the number of data points is odd, the median is the middle data point in the list.

So from the given data of the 100 meter dash, the measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

The median will help to separate half of the data points that are smaller than the cutoff time and half of the data points are larger than the cutoff time.

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A 1200 kg car moving 28 m/s decelerated until it stopped. The force of friction acting on the car is 714.9 N

Using the equation of motion:

v² = u² + 2ad

Where:

v = final velocity = 0 (since the car eventually stopped)

u = initial velocity = 28 m/s

a = acceleration

d = distance = 658 m

Hence,

0 = 28² + 2 x a x 658

a = - 0.596 m/s²  (minus sign denotes deceleration)

According to the Newton second law of motion:

F = m a

Where:

F = net force = friction force

m = mass of the car = 1200 kg

a =  0.596 m/s²

Hence, the friction force is:

F = 1200 x 0.596

 = 714.9 N

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To answer your question, it's important to clarify that "50 mg/dL" or "0.05 g/dL" are measurements of blood alcohol concentration (BAC) and not directly equal to a specific number of drinks.

As a result, the number of drinks required to reach a BAC of 50 mg/dL (0.05 g/dL) can differ between individuals.
Generally, one standard drink contains about 14 grams of pure alcohol, which can be found in 12 ounces of beer, 5 ounces of wine, or 1.5 ounces of distilled spirits. However, the exact number of drinks it takes to reach a BAC of 50 mg/dL (0.05 g/dL) will depend on a person's specific characteristics and how quickly the drinks are consumed.It's crucial to remember that it's not safe or legal to drive with a BAC of 0.05 g/dL or higher in many countries, as it can impair cognitive and motor functions. Always drink responsibly and arrange for a safe way home if you choose to consume alcohol. BAC levels vary depending on factors such as weight, gender, and individual metabolism.

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Answer:

5.0 because the ball is seeing big but the balls weight is 5.0

Explanation:

Time=distance/speed

=600/50

=12

=600/60=10

==12-10=2 hours

Answer:

39.2

Explanation:

Marita Koch's average speed during the 400-meter race can be calculated by dividing the distance she covered by the time it took her to complete the race. In this case, the distance is 400 meters and the time is 47.60 seconds. So, her average speed is:

Average Speed = Distance / Time

Average Speed = 400 meters / 47.60 seconds

Calculating this, we get an average speed of approximately 8.40 meters per second.

Now, let's talk about velocity. Velocity is a vector quantity that includes both speed and direction. In this case, since the race starts and finishes at the same point, the direction is not relevant. Therefore, the velocity will be the same as the average speed, which is 8.40 meters per second.


- Marita Koch's average speed during the 400-meter race is 8.40 meters per second.
- Her velocity during the race is also 8.40 meters per second.


Marita Koch's average speed during the 400-meter race is 8.40 meters per second. Her velocity during the race is also 8.40 meters per second.


Marita Koch's average speed during the 400-meter race is determined by dividing the distance she covered by the time it took her to complete the race. In this case, she covered a distance of 400 meters in a time of 47.60 seconds. By dividing the distance by the time, we find that her average speed is approximately 8.40 meters per second.

Velocity, on the other hand, is a vector quantity that takes into account both speed and direction. In this scenario, since the race starts and finishes at the same point, the direction becomes irrelevant. Therefore, the velocity during the race will be the same as the average speed, which is 8.40 meters per second.

Marita Koch's average speed during the 400-meter race is 8.40 meters per second, and her velocity during the race is also 8.40 meters per second.

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The magnitude of the total force exerted by two charges on a third charge is approximately 2.656e-07 N.

The magnitude of the total force exerted by two charges on a third charge is given by the following equation:

\(F = k |q1q2| / r^2\)

where:

In this problem, we are given the following information:

q1 = 1.0e-9 C

q2 = 2.0e-9 C

q3 = 5.30 nC

y3 = -0.420 m

The distance between the third charge and the midpoint of the two charges can be calculated using the following equation:

\(r = \sqrt((y1 - y3)^2 + (y2 - y3)^2)\)

where:

In this problem, we are given that y1 = 0.200 m and y2 = 0.400 m. Therefore, the distance between the third charge and the midpoint of the two charges is:

\(r =\sqrt((0.200 - (-0.420))^2 + (0.400 - (-0.420))^2) = 0.353 m\)

Therefore, the magnitude of the total force exerted by the two charges on the third charge is:

\(F = 8.987551787e9 * |1.0e-9 * 2.0e-9| / (0.353)^2\) = 2.6560145212572496e-07 N

Therefore, the magnitude of the total force exerted by the two charges on the third charge is 2.656e-07 N.

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The University of California, Berkley, defines a theory as "a broad, natural explanation for a wide range of phenomena. Theories are concise, coherent, systematic, predictive, and broadly applicable, often integrating and generalizing many hypotheses." Any scientific theory must be based on a careful and rational examination of the facts.

The total impulse received by the body is approximately 42.43 Ns.

Impulse is a measure of the change in momentum of an object resulting from a force acting upon it for a period of time. It is defined as the product of the force and the time interval over which it acts, and is represented by the symbol "J".

To find the total impulse received by the body, we need to use vector addition to add the two impulses together. Since the impulses are at an angle of 55 degrees to each other, we can use the law of cosines to find the magnitude of the resultant impulse:

I² = 24² + 35² - 2(24)(35)cos(55)

I² = 576 + 1225 - 1680cos(55)

I² = 1801.9

I ≈ 42.43 Ns

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Answer:

3.6 Km..........................................

Answer:

Yes, the carters are always facing the Earth as the moon orbits.

Explanation:

Astronomers would want to devote so much precious telescope time to observing totally ordinary regions of the sky in such great detail because statistics tells something about objects that are not in the statistical sample.

First, let's know, why astronomers need telescope to make observations,

The purpose behind this is gathering more light so that very faint objects can be observed, and magnifying and make those images clear so that distant objects can be observed through telescope.

As you might know, both space and time were created at the big bang about 14 billion years ago, so there is nothing beyond the universe. However, much of the universe exists beyond the observable universe, which is maybe about 90 billion light years across.

The universe is much bigger than our thoughts, we're just a piece of sand in front of it, that's why we need much better telescopes time by time to make observations, to look through it, Only because it helps us to understand our sky better.

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(a) The magnetic field at a distance r from an infinitely-long straight wire carrying current i is given by B = μ_0i / (2πr). (b) The magnitude of the magnetic field at the point halfway between the wires is 2×10^-6 T and it is directed upwards.

(a) We can use Ampere's law to derive an expression for the magnetic field a distance r from an infinitely-long straight wire carrying current i. Consider a circular loop of radius r centered on the wire. The magnetic field at every point on the loop is tangent to the loop and has a magnitude B. By Ampere's law,

∮B·dl = μ_0i,

where the integral is taken over the circumference of the loop, and μ_0 is the permeability of free space. Since B is constant in magnitude and direction along the loop, we can simplify the integral to

B∮dl = μ_0i,

where the integral is just the circumference of the loop, 2πr. Thus, we have

B(2πr) = μ_0i,

or

B = μ_0i / (2πr).

Therefore, the magnetic field at a distance r from an infinitely-long straight wire carrying current i is given by B = μ_0i / (2πr).

(b) The magnetic field at a point halfway between the wires can be found by applying the right-hand rule. If we curl the fingers of our right hand in the direction of the current in the left wire (into the paper), and then point the thumb in the direction of the current in the right wire (also into the paper), the magnetic field will be perpendicular to the plane of the fingers and directed upwards. Since the wires are located 0.5 m apart, the distance from the point to each wire is also 0.5 m. Thus, using the expression derived in part (a), we have

B = μ_0i_1 / (2πr_1) + μ_0i_2 / (2πr_2) = (4π×10^-7 T·m/A)(5 A) / (2π×0.5 m) + (4π×10^-7 T·m/A)(2 A) / (2π×0.5 m) = 2×10^-6 T.

Therefore, the magnitude of the magnetic field at the point halfway between the wires is 2×10^-6 T and it is directed upwards.

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