juie ran eight laps around her school's quarter mile track in 18 minutes. her average velocity was _______m/s

The rotational inertia of a thin cylindrical shell of mass M, radius R, and length L about its central axis (X - X') is MR²/2.

The rotational inertia, also known as the moment of inertia, is a property that quantifies an object's resistance to rotational motion. For a thin cylindrical shell, the rotational inertia can be calculated based on its mass, radius, and length.

The formula for the rotational inertia of a thin cylindrical shell is given by I = MR²/2, where M represents the mass of the shell and R represents its radius.

In this case, since we are considering the rotational inertia about the central axis (X - X'), the length of the cylinder (L) does not come into play. The only relevant parameters are the mass (M) and radius (R).

Applying the formula, the rotational inertia of the thin cylindrical shell is MR²/2. Therefore, the correct answer is A. MR²/2.

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Answer:

The sense of weightlessness in orbiting satellite is because of the lack of any contact-forces. The only force that acts upon humans in space is the force of gravity, which acts at a distance; but as there is no counter-force, we do not experience the sensation of weight over there.

An atom is the smallest unit of matter that forms a chemical element. An atom is made up of three kinds of subatomic particles: electrons, protons, and neutrons.A molecule is a combination of atoms bonded together through a covalent bond. Generally, we think of molecules as having no charge (although molecular ions do exist)

Answer:

all the resistors are connected in series.

Answer:

B. 14.4 N

Rotational speed (Angular Velocity) = 2

The Radius of the circle = 1.2 m

Velocity = Angular velocity × radius = 2×1.2 = 2.4 m/s

Centripetal force= mv²/r = 3 × 2.4×2.4/1.2 = 3 × 2.4 × 2

= 14.4 N

Answer:

False

Explanation:

It is actually I = V/R and V = I × R

Answer:

There is an inverse relationship between distance and light intensity - as the distance increases, light intensity decreases. This is because as the distance away from a light source increases,..

Explanation:

The light intensity decreases as magnification increases. There is a fixed amount of light per area, and when you increase the magnification of an area, you look at a smaller area. So you see less light, and the image appears dimmer. Image brightness is inversely proportional to the magnification squared.

The dot product is 25, the angle is \(\theta = cos^{-1} \frac{25}{\sqrt{35} \times \sqrt{21}}\), the cross product is 1i + (-6)j + (-7)k, and the area of the parallelogram spanned by vectors A and B is \(\sqrt{86}\).

Given,

A = 5i + 3j + k

B = 4i + j + 2k

i. Dot Product (A · B):

The dot product of two vectors A and B is given by the sum of the products of their corresponding components.

\(A.B = (A_x \times B_x) + (A_y \times B_y) + (A_z \times B_z)\\A.B = (5 \times 4) + (3 \times 1) + (1 \times 2) \\= 20 + 3 + 2 \\= 25\)

ii. Angle between vectors A and B:

The angle between two vectors A and B can be calculated using the dot product and the magnitudes of the vectors.

\(cos\theta = (A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} ((A.B) / (|A| \times |B|))\\A = \sqrt{(5^2 + 3^2 + 1^2)} =\\ \sqrt{35}\\B = \sqrt{(4^2 + 1^2 + 2^2)} \\= \sqrt{21}cos\theta = \frac{(A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} \frac{25}{\sqrt{35} \times \sqrt{21}}}\)

iv. Cross Product (A × B):

The cross product of two vectors A and B is a vector that is perpendicular to both A and B and its magnitude is equal to the area of the parallelogram spanned by A and B.

\(A\times B = (A_y \timesB_z - A_z \timesB_y)i + (A_z \timesB_x - A_x \timesB_z)j + (A_x \times B_y - A_y \times B_x)k\\A\times B = ((3 \times 2) - (1 \times 1))i + ((1 \times 4) - (5 \times 2))j + ((5 \times 1) - (3 \times 4))k\\= 1i + (-6)j + (-7)k\)

Area of the parallelogram spanned by vectors A and B:

The magnitude of the cross product A × B gives us the area of the parallelogram spanned by A and B.

Area = |A × B|

Area of the parallelogram spanned by vectors A and B:

Area = |A × B| =

\(\sqrt{(1^2 + (-6)^2 + (-7)^2}\\\sqrt{1+36+49\\\\\sqrt{86}\)

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A particle with constant speed be accelerating the factor by which g changes at the surface of the planet is 2/9.

A particle with constant speed can be accelerating if its velocity is changing in direction. Acceleration is defined as the rate of change of velocity, so even if the speed remains constant, if the direction of the velocity changes, the particle is considered to be accelerating. This is because acceleration is a vector quantity that takes into account both magnitude and direction.

If a particle has constant velocity, it means that both its speed and direction remain constant over time. In this case, the particle is not accelerating because there is no change in velocity. Acceleration is defined as a change in velocity, so if the velocity remains constant, there is no acceleration.

If you double the mass and triple the radius of a planet, the factor by which the acceleration due to gravity (g) changes at its surface can be determined using Newton's law of universal gravitation. The law states that the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Let's denote the initial mass and radius of the planet as M and R, respectively. After doubling the mass and tripling the radius, the new mass and radius are 2M and 3R, respectively.

The acceleration due to gravity at the surface of the planet can be calculated using the formula:

g = (G * M) / R^2

where G is the gravitational constant.

The new acceleration due to gravity, g', can be calculated using the new mass and radius:

g' = (G * 2M) / (3R)^2

To find the factor by which g changes, we can divide g' by g:

(g' / g) = [(G * 2M) / (3R)^2] / [(G * M) / R^2]

(g' / g) = [(2M) / (3R)^2] * [(R^2) / M]

(g' / g) = (2M / 9R^2) * R^2 / M

(g' / g) = 2 / 9

Therefore, the factor by which g changes at the surface of the planet is 2/9.

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The correct option (c) Sea of thee i heated up the leat by the un' energy.

According to thermodynamics, heat is a type of energy that crosses a thermodynamic system's boundary due to a temperature differential across the barrier. Heat does not exist in a thermodynamic system.

But the phrase is also frequently used to refer to the thermal energy that makes up a system's internal energy and is reflected in the system's temperature. Heat is a type of energy in both senses of the word.

A metal bar is "carrying heat" from its hot end to its cold end, but if the metal bar is thought of as a thermodynamic system, then the energy flowing within the metal bar is believed to be in the form of heat.

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Answer:

611.064 kJ

Explanation:

Given :

m = 200 mL = 200 g

Specific heat of ice = 2.06 J/g°C

Q = mcΔt

Δt = 0 - (-22) = 22

Q1 = 200 * 2.06 * 22 = 9064 J

Q2 = Melt 0 °C solid ice into 0 °C liquid water:

Q2 = m · ΔHf ; ΔHf = heat of fusion of water = 334j/g

Q2 = 200 * 334 = 66800 J

Q3 : Heat to convert from 0°C to 100°C

Q3 = mcΔt ; c = 4.19 J/g°C ; Δt = (100 - 0) = 100

Q3 = 200 * 4.19 * 100 = 83800 J

Q4: heat required to boil water to steam

Q = m · ΔHv

Hv = heat of vaporization of water = 2257 J/g

Q4 = 200 * 2257 = 451400 J

Total Q = Q1 + Q2 + Q3 + Q4

Q = 9064 + 66800 + 83800 + 451400

Q = 611,064 Joules

Q = 611.064 kJ

The equation for the speed of the sound source vs, in this case, the train, can be derived using the Doppler effect formula. The Doppler effect is the change in frequency of a wave in relation to the movement of its source. In this case, we are interested in the change in frequency of the sound waves emitted by the train as it moves towards or away from an observer.

The equation for the Doppler effect is:

f2 = f1(v + vs) / (v - vs)

where f1 is the frequency of the sound wave emitted by the train, f2 is the frequency of the sound wave observed by the listener, v is the speed of sound in air, and vs is the speed of the train.

To find an equation for the speed of the sound source vs, we can rearrange the formula as follows:

vs = (f2v - f1v) / (f2 + f1)

Expressing the answer in terms of f1, f2, and v, we get:

vs = (f2 - f1) / ((f2 + f1)/v)

In conclusion, the equation for the speed of the sound source vs, in terms of f1, f2, and v, is (f2 - f1) / ((f2 + f1)/v).

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Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall  7.5 m/sec².

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

To find the acceleration,

   F = mg

   F = 80.(10)

   F = 800 N

   air resistance = 200 N

   Net force = F - air resistance

                = 800 - 200

                =  600 N

   600 = mass . acceleration

   600 = 80 . acceleration

   acceleration = 7.5 m/sec²

Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall  7.5 m/sec².

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Answer:

The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

Explanation:

Hope It Helps!

In a system with two moving objects, when a collision occurs between the objects, the correct answer is: B) The total momentum is always conserved.

Since no outside force acts on an isolated system (like the universe), momentum is always conserved. All of momentum's components will always be constant because momentum can never change. The conservation of momentum principle should be applied to tackle collision-related issues.

A body or system of bodies in motion preserves its total momentum, which is determined as the sum of its mass and vector velocity, in the absence of an external force, according to the theory of conservation of linear momentum. Momentum is constantly maintained since there are no external forces in an isolated system (like the universe).

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The force required to push the bobsled down the incline and achieve a speed of 67 km/h at the end of 75 m is 236.8 N.

The force required to push the bobsled down the incline can be found using the equation:

F = (mgsinθ + mgμcosθ) / (1 - μsinθ)

where F is the force required, m is the mass of the bobsled, g is the acceleration due to gravity, θ is the angle of the incline, and μ is the coefficient of kinetic friction.

Plugging in the given values, we get:

F = (25 kg * 9.81 m/s² * sin(6°) + 25 kg * 9.81 m/s² * 0.10 * cos(6°)) / (1 - 0.10 * sin(6°))

= 236.8 N

To achieve a speed of 67 km/h at the end of 75 m, we need to find the acceleration of the bobsled using the equation:

v²  = u² + 2as

where v is the final velocity (67 km/h = 18.61 m/s), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance traveled (75 m).

Solving for a, we get:

a = (v² - u²) / (2*s)

= (18.61 m/s)² / (2 * 75 m)

= 4.90 m/s²

As a result, the power necessary to drive the bobsled down the hill and reach a speed of 67 km/h at the end of 75 meters is 236.8 N.

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You can change the volume, pressure, or temperature of a gas.

Change the volume of a gas to raise or lower the temperature. As the temperature increases, the gas expands and increases in volume. Conversely, as the temperature decreases, the volume of the gas decreases. As the temperature increases, the volume of the gas increases. Conversely increasing the pressure will decrease the volume of the gas.

Reducing the gas volume increases the gas pressure. An example of this is when gas is trapped inside a cylinder by a piston. When the piston is pushed in, the volume occupied by the gas decreases, so there is less room for gas particles to move. The relationship between pressure and volume Boyle's Law. As the pressure of a gas increases the gas particles are pushed together thus decreasing the volume of the gas.

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Answer:

D

Explanation:

a twist is an event that a reader probably wouldn't have been able to predict

Explanation:

F = ma

F = (60.0 kg) (250 m/s²)

F = 15,000 N

During a crash, a dummy with a mass of 60 kg hits an airbag, then the airbag will exert 15,000 N force on the dummy.

The rate of change in an object's velocity concerning time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

There are several types of acceleration :

According to the question, the given values are :

Mass, m = 60 kg

Acceleration, a = 250 m/s²

F = ma

F = (60.0 kg) × (250 m/s²)

F = 15,000 N

Hence, the force exerted by the airbag will be 15,000 N.

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Answer:

Who Discovered Gadolinium Gadolinium was only discovered in 1880 by a Swiss chemist called Jean Charles Galissard de Marignac.

Explanation:

When analyzing samples of two minerals which contain small amounts of gadolinium, didymium and gadolinite, he discovered spectroscopic lines that were unrecognisable. Every single element has distinctive spectroscopic lines so he knew he had discovered a new element, and called it gadolinium after Finnish chemist Johan Gadolin.

Answer:

Paul-Émile Lecoq de Boisbaudran

Jean Charles Galissard de Marignac

The amount of work done by the ideal gas is 2475J.

The magnitude of the work done when a gas expands is therefore equal to the product of the pressure of the gas times the change in the volume of the gas.

w=−PΔV

The negative sign associated with the above equation indicates that the system loses energy. If the volume increases at constant pressure (ΔV > 0), the work done by the system is negative, indicating that a system has lost energy by performing work on its surroundings.

According to this question, an ideal gas initially at 50.0m³ at 1000.0 Pa expands to a volume of 300.0 m³ after heating. The work done can be calculated as follows:

W = -P∆V

W = - (0.0099 × {300000L - 50000L)

W = - (0.0099 × 250000)

W = 2475J

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To construct an open rectangular box with maximum volume, the dimensions should be such that the length, width, and height are equal.

To find the dimensions that result in a box of maximum volume, we need to consider the relationship between the dimensions and the volume of the box. Let's assume the length of the box is L, the width is W, and the height is H. Since the box is open, it does not have a top surface.

The volume of a rectangular box is given by the formula V = L * W * H. However, in this case, we have a constraint that the material used to construct the box has a fixed amount, so the total surface area of the box must be constant. The surface area of an open rectangular box is given by A = 2LW + LH + WH.

To find the dimensions that maximize the volume, we need to find the critical points of the volume function. By applying the constraint of constant surface area, we can express one of the dimensions in terms of the other two using the surface area formula. Substituting this expression into the volume formula, we obtain a function that depends on two variables. Taking the derivative of this function and setting it to zero, we can solve for the critical points.

By solving the equations, we find that the dimensions resulting in a box of maximum volume are when the length, width, and height are all equal. In other words, the box is a cube. This is because a cube maximizes the volume within the given constraints, as any deviation from equal dimensions would result in a smaller volume.

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Answer:

what is the upwards force?

Answer:

final velocity=-49m/s and height=122.5

Explanation:

u=0,t=5s,v=?

v=u+gt

v=0+(-9.8)5

v=-49m/s

h=ut+1/2gt*2

h=0(5)±1/2(-9.8)5*2

h=-122.5 or 122.5

but height=122.5 because height cannot be negative

The amount of sample of liquid in grams when its temperature is raised is calculated to be 20 g.

The term specific heat capacity refers to the amount of heat needed to raise a substance's temperature by one degree Celsius.

Q = m c Δt  

Q = 5.23 kcal of heat are absorbed by fluids = 5230 cal

C = heat capacity of liquid = 2.09 cal/g °C

Initial temperature of the liquid T i = 101 K

Final temperature of the liquid T f = 225 K

Change in temperature, Δt = T f - T i = 225 - 101 K = 124 K

Putting in the values, we get:

5230 = m × 2.09 cal/g °C × 124 K  

m = 20 g

The given question is incomplete. The complete question is 'The specific heat of a liquid x is 2.09 cal/g°c. A sample amount of grams of this liquid at 101 k is heated to 225 k. the liquid absorbs 5.23 k cals. what is the sample of liquid in grams? (round off decimal in the answer to nearest tenths)'

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For a 6.00 kg bowling ball:

(a) change in momentum of the bowling ball is −12.0 kg m/s

(b) impulse imparted on the pin is −12.0 kg m/s.

(c) resulting speed of the pin after the collision is 8.00 m/s

(d) force exerted on the pin during the collision −400 N

(a) The change in momentum of the bowling ball is given by

Δp = m(vf − vi) = (6.00 kg)(7.00 m/s−9.00 m/s) =−12.0 kg m/s

(b) The impulse imparted on the pin is equal to the change in momentum of the bowling ball, so the impulse is −12.0 kg m/s.

(c) The resulting speed of the pin after the collision can be found using conservation of momentum. The total momentum after the collision is the sum of the momentum of the bowling ball and the momentum of the pin. So,

mbvi = mbvf+ mpvp

​where vp = speed of the pin after the collision.

Solving for vp,

vp = mb(vi− vf)/mp = (6.00 kg)(9.00 m/s−7.00 m/s) / 0.750 kg = 8.00 m/s

(d) The force exerted on the pin during the collision is given by

F = Δp/Δt = − 12.0 kg m/s/0.030 s = −400 N

The negative sign indicates that the force is in the opposite direction of the initial velocity of the bowling ball.

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Answer:  the hunter should aim his rifle 3,422 meters above the deer to hit it.

Explanation: We can solve this problem using projectile motion equations. Let's first identify the known variables:

Distance to the deer along the line of sight (horizontal distance): d = 10,181 m

Height of the hill: h = 90 m

Muzzle velocity of the gun: v0 = 100 m/s

Acceleration due to gravity: g = 10 m/s^2

We want to find the vertical distance (height) between the hunter's location and the deer, which we can call y. We can use the following equation for the vertical motion of a projectile:

y = v0tsin(theta) - (1/2)gt^2

where t is the time it takes for the bullet to reach the deer, and theta is the angle between the line of sight and the horizontal (the angle at which the rifle is aimed).

To find t, we can use the fact that the time of flight of a projectile is given by:

T = 2v0sin(theta)/g

We can solve for sine(theta) using the fact that the horizontal distance is related to the time of flight by:

d = v0*cos(theta)*T

Combining these equations, we get:

sin(theta) = d/(2Tv0)

cos(theta) = sqrt(1 - sin^2(theta))

t = T/2

Substituting these values back into the equation for y, we get:

y = (d*t/tan(theta)) - (1/2)gt^2

Now we just need to plug in the numbers and solve for y:

sin(theta) = 90/10,181

theta = arcsin(sin(theta)) = 0.523 degrees

cos(theta) = cos(0.523) = 0.999

T = 2100sin(theta)/g = 3.189 seconds

t = T/2 = 1.595 seconds

y = (10,181*t/tan(theta)) - (1/2)gt^2 = 3,422 meters

Therefore, the hunter should aim his rifle 3,422 meters above the deer to hit it. Note that this assumes no air resistance and that the rifle is perfectly aimed. In reality, the bullet would be affected by air resistance and the trajectory would depend on the accuracy of the rifle and the shooter's skill.