The rectangular blocks with the measure of 7 cm by 8 cm by 9 cm will not fit in the smallest cylindrical cup with the radius of 5cm.
Rectangular block with the least dimensions, 7cm by 8cm side.
Circle with radius r is x² + y² = r²
∴ x² + y² = 5² or x² + y² = 25
Draw the area of the block using the coordinates (3.5,4) ; (-3.5,4) ; (-3.5,-4) and (3.5,-4)
Its observed that the block cannot fit inside the cup. We can confirm this if
y >4 when x = 3.5
3.5² + y² = 25
12.25 + y² = 25
y² = 12.75
taking positive square root, y≈3.57
Since this is <4, the block cannot fit the 5 cm radius cup.
equation for the cup with r = 6cm,
x² + y² = 6² or x² + y² = 36
Draw the area of the block using the coordinates (3.5,4) ; (-3.5,4) ; (-3.5,-4) and (3.5,-4)
it is observed the block will fit inside the cup as y>4 when x = 3.5
3.5² + y² = 36
12.25 + y² = 36
y² = 23.75
taking positive square roots, y≈4.87
Since this is >4, the block can fit the 6 cm radius cup.
equation for the cup with r = 7cm,
x² + y² = 7² or x² + y² = 49
Draw the area of the block using the coordinates (3.5,4) ; (-3.5,4) ; (-3.5,-4) and (3.5,-4)
it is observed the block will fit inside the cup as y>4 when x = 3.5
3.5² + y² = 49
12.25 + y² = 49
y² = 36.75
taking positive square roots, y≈6.06
Since this is >4, the block can fit the 7 cm radius cup.
∴ the block will not fit the smallest cup
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For each confidence interval procedure, provide the confidence level. (Round the answers to the nearest percent.)
(a) Sample proportion ± 1.645 ✕ standard error. %
(b) Sample proportion ± 2 ✕ standard error. %
(c) Sample proportion ± 2.33 ✕ standard error. %
(d) Sample proportion ± 2.58 ✕ standard error. %
(a) The confidence level for the procedure "Sample proportion ± 1.645 ✕ standard error" is approximately 90%.
(b) The confidence level for the procedure "Sample proportion ± 2 ✕ standard error" is approximately 95%.
(c) The confidence level for the procedure "Sample proportion ± 2.33 ✕ standard error" is approximately 99%.
(d) The confidence level for the procedure "Sample proportion ± 2.58 ✕ standard error" is approximately 99.5%.
What is confidence level?Confidence level refers to the level of confidence or certainty that can be associated with a particular statistical estimation or inference procedure. It is commonly used in statistical analysis to express the amount of confidence one can have in the accuracy or reliability of a statistical estimate or result.
In the context of confidence intervals, which are used to estimate unknown population parameters based on sample data, the confidence level represents the probability or percentage of times that the calculated confidence interval would contain the true population parameter, if the same estimation procedure were repeated multiple times with different samples.
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Which integer is the smallest? A. -84 B. -4 OC. 34 OD. 24 Advanced Placement, AP AP Central", College Board", and SAT are trademarks registered by the Colleg ACT is a trademark registered by ACT, Inc., which is not affiliated with, and does not endorse, this website. Copyright 2010-2022 edtell, LLC. All rights reserved. Portions of this software are copyrighted by other partie. Which integer is the smallest ? A. -84 B. -4 OC . 34 OD . 24 Advanced Placement , AP AP Central " , College Board " , and SAT are trademarks registered by the Colleg ACT is a trademark registered by ACT , Inc. , which is not affiliated with , and does not endorse , this website . Copyright 2010-2022 edtell , LLC . All rights reserved . Portions of this software are copyrighted by other partie .
Answer: B -4
Step-by-step explanation: I think it is B because -4 is smaller than A,C and D.
The smallest integer among the options provided is option A, which is -84.
In the context of integers, smaller values are considered to be "less" than larger values.
In this case, we can compare the given integers to determine the smallest one.
Comparing the options:
A. -84
B. -4
C. 34
D. 24
Out of these options, -84 is the smallest integer because it has the lowest numerical value.
The negative sign indicates that it is a number less than zero, and the absolute value of 84 is greater than the absolute values of -4, 34, and 24.
Therefore, based on numerical value, -84 is the smallest integer among the options given.
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for fixed population standard deviation and level of significance, the minimum sample size needed to guarantee a given margin of error ......... as the margin of error increases.
The right response is (b), as it increases the minimum sample size required to ensure a given margin of error.
What is margin of error?When a tiny sample of data from a relatively large population is estimated, this is what is meant by the term "margin of error" . The standard deviation, sample size, and desired confidence level are often the factors that control the margin of error.
calculation
Let's take a look at the values in the supplied statement to discover the missing term.
the population's standard deviation is where
m stands for "Margin of Error," and Z stands for "Empirical Value of Z-Score" at a specific confidence level.
As a result, the recommended minimum sample size for a particular degree of confidence is
⇒ (Z×σ)²/m²
The minimal sample size is directly correlated with the population's standard deviation, as shown by the calculation above.
Therefore, when the population "standard deviation" increased, the minimal sample size needed would also "rise."
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How do you know how many solutions a function has?
The number of solutions of a function depends on various factors, including the type of function and the domain in which it is defined.
1. Degree of the Polynomial: For polynomial functions, the degree of the polynomial determines the maximum number of solutions. A polynomial of degree n can have at most n solutions in the complex numbers. For example, a quadratic equation (degree 2) can have up to two solutions.
2. Function Type: Different types of functions have different properties regarding the number of solutions. For example:
- Linear Functions: A linear equation (degree 1) has exactly one solution unless it is inconsistent (no solution) or degenerate (infinite solutions).
- Quadratic Functions: A quadratic equation (degree 2) can have zero, one, or two solutions.
- Exponential and Logarithmic Functions: Exponential and logarithmic equations can have one or more solutions, depending on the specific equation.
3. Intersections and Intercepts: The number of solutions can be related to the intersections of a function with other functions or with specific values (e.g., x-intercepts or roots). The number of intersections or intercepts gives an indication of the number of solutions.
4. Constraints and Domain: The domain of the function may impose constraints on the number of solutions. For example, if a function is defined only for positive values, it may have no solutions or a limited number of solutions within that restricted domain.
5. Graphical Analysis: Graphing the function can provide insights into the number of solutions. The number of times the graph intersects the x-axis can indicate the number of solutions.
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Find an equation for the hyperbola with foci (0,±5) and with asymptotes y=± 3/4 x.
The equation for the hyperbola with foci (0,±5) and asymptotes y=± 3/4 x is:
y^2 / 25 - x^2 / a^2 = 1
where a is the distance from the center to a vertex and is related to the slope of the asymptotes by a = 5 / (3/4) = 20/3.
Thus, the equation for the hyperbola is:
y^2 / 25 - x^2 / (400/9) = 1
or
9y^2 - 400x^2 = 900
The center of the hyperbola is at the origin, since the foci have y-coordinates of ±5 and the asymptotes have y-intercepts of 0.
To graph the hyperbola, we can plot the foci at (0,±5) and draw the asymptotes y=± 3/4 x. Then, we can sketch the branches of the hyperbola by drawing a rectangle with sides of length 2a and centered at the origin. The vertices of the hyperbola will lie on the corners of this rectangle. Finally, we can sketch the hyperbola by drawing the two branches that pass through the vertices and are tangent to the asymptotes.
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match the correct base shape to each prism. some cards may be used more than once.
Looking at figure A, we have a prism with a triangular base that looks like a right triangle.
Since the prism has a right triangular base, the base shape is a right triangle (shape 5).
Looking at figure B, we have a prism with a pentagonal base.
Since the prism has a pentagonal base, the base shape is a pentagon (shape 1).
Looking at figure C, we have a prism with a triangular base that looks like an equilateral triangle.
Since the prism has an equilateral triangle base, the base shape is an equilateral triangle.(shape 4).
Looking at figure D, we have a prism with a triangular base that looks like an equilateral triangle.
Since the prism has an equilateral triangle base, the base shape is an equilateral triangle.(shape 4).
I need help with solving for x. Then find the measure of the base angle. Please
Answer:
x = 8 base angle = 81 degrees
Step-by-step explanation:
Answer:
x = 8
base angle = 81 deg
Step-by-step explanation:
we observe that because the given triangle is a isosceles triangle, the base angles must be the same.
Hence the missing base angle must also be (10x+1)°
recall that all internal angles of an triangle must add up to 180 deg,
hence
180° = sum of all internal angles
180° = 18° + (10x+1)° + (10x+1)°
180° = 18° + 2(10x+1)° (subtracting 18 from both sides)
180 - 18 = 2(10x+1)
162 = 2(10x+1) dividing both sides by 2)
162 / 2 = 10x + 1
81 = 10x + 1 (subtracting 1 from both sides)
81 - 1 = 10x
10x = 80 (divide both sides by 10)
x = 80/10
x = 8 (answer)
substituting x = 8 into the expression for the base angle
base angle = (10x+1)
= 10(8) + 1
= 10 + 1
= 81
Andrew grew 4 1/3 inches during a 3 1/2 month growth spurt. If his growth spurt continued at the same rate, how much did he grow in one month
If his growth spurt continued at the same rate Andrew will grow 26/7 inches per month during that growth spurt.
Describe age calculation.To calculate someone's age, you would subtract their birth year from the current year. For example, if someone was born in 1995 and it is now 2020, their age would be calculated as 2020 - 1995 = 25 years old.
If you have a birthdate, you can use a date calculator to find the exact age in years, months and days.
It's also important to note that, if the person's birthday hasn't occurred yet in the current year, you would subtract the birth year from the current year minus one.
We can start by converting the mixed number 4 1/3 to an improper fraction by multiplying the whole number by the denominator and adding the numerator: 4 x 3 + 1 / 3 = 13/3
To find out how much Andrew grew per month, we need to divide the total growth by the number of months.
13/3 inches / 3 1/2 months = (13/3) / (7/2) = (13/3) x (2/7) = 26/7 inches/month.
So, Andrew grew 26/7 inches per month during that growth spurt.
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find the zero of the linear funtion;
f(x)=5x -10
Answer: (2, 0)
When y hits zero, that's where you can find the zero thing
What is the annual discount rate if a cashflow of £52 million in 5 years' time is currently valued at £25 million?
a. 86.37\% b. 15.77% c. 21.60% d. 115.77% e. 108.00%
The correct answer is option b. 15.77%. The annual discount rate, also known as the discount rate or the rate of return, can be calculated using the present value formula.
Given that a cash flow of £52 million in 5 years' time is currently valued at £25 million, we can use this information to solve for the discount rate.
The present value formula is given by PV = CF / (1 + r)^n, where PV is the present value, CF is the cash flow, r is the discount rate, and n is the number of years.
In this case, we have PV = £25 million, CF = £52 million, and n = 5. Substituting these values into the formula, we can solve for r:
£25 million = £52 million / (1 + r)^5.
Dividing both sides by £52 million and taking the fifth root, we have:
(1 + r)^5 = 25/52.
Taking the fifth root of both sides, we get:
1 + r = (25/52)^(1/5).
Subtracting 1 from both sides, we obtain:
r = (25/52)^(1/5) - 1.
Calculating this value, we find that r is approximately 0.1577, or 15.77%. Therefore, the annual discount rate is approximately 15.77%, corresponding to option b.
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I have a question on this math problem, and I have to find the mean mode and range of the dot plot
With these steps, you can successfully find the mean, mode, and range of the data represented in the dot plot.
To find the mean, mode, and range of the dot plot, follow these steps:
Step 1: Count the total number of data points (dots) in the dot plot.
Step 2: Add up the values represented by the data points.
Step 3: Divide the sum from Step 2 by the total number of data points from Step 1 to calculate the mean.
Step 4: Identify the mode by finding the value(s) that appears most frequently in the dot plot (i.e., the value with the highest number of dots).
Step 5: Determine the range by finding the difference between the highest and lowest values in the dot plot.
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Boxes of tinned cat food are delivered to a shop. There are 28 boxes and in each box there are 16 tins how much is there all together ??
Answer:
448
Step-by-step explanation:
You just need to multiply 28 by 16
How can I design a combinational circuit with three inputs, x, y, and z, and three outputs A, B, and C. When the binary input is 4, 5, 6, or 7, the binary output is four greater than the input?
So a 4-input and gate has 16 possible combinations of binary output, 5 inputs would be 32 outputs, and so on.
Combinations are also called selections. Composition is the selection of one thing from a given set of things. We're not going to fix things here. We will choose them. We note nCr the number of r-choices or unique combinations among a set of n subjects.
Design Procedure:
Step 1:. Derive a truth table that defines the desired relationship between inputs and outputs.
Step 2: Obtain the simplified Boolean function of each output according to the input variables. The simplified expression for the
map is:
A= w
The simplified expression for the map is:
B=w' y+ xz+ wx
Step3. Draw the logic diagram and the binary output are:
A= w
B=w ′y+ xz + wx
C=w ′x ′y ′ +w ′y ′z ′ +xyz + wy
D=x ′z+ w ′xz ′ + wz
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In A, B and C above the sequences start with 4; 8; ... Is that information enough for one to generalise on the follow sequence? Why? What is your observation about all four given sequences? Sequence A: 4; 7; 10; 13; 16; ......... Sequence B: 5; 10; 20; 40; 80; Sequence C: 2; 5; 10; 17; 26; ....... Write down the next three numbers in each of given sequences. Sequence A: Sequence B: Sequence C:_
The information is not enough because there can be different number-patterns or rules that start with those initial terms. We need to use the pattern rule and the initial terms of each sequence to correctly predict the next few terms of each sequence.(The sequences are given below)
Therefore, we need to look at more terms or patterns to establish a rule.
Observing the given sequences, we can see that sequence A adds 3 to the previous term to make the next term. Similarly, sequence C uses the rule that each term is 3 more than the square of the position of the term. However, sequence B does not follow a simple pattern, since each term in sequence B is double the previous term. Therefore, we need to use the initial terms and the pattern rule to predict future terms of the sequences.
In summary, having more terms and looking for a pattern is essential in predicting the trends in a sequence.
The next three terms of sequence A are 19, 22, and 25.
The next three terms of sequence B are 160, 320, and 640.
The next three terms of sequence C are 37, 50, and 65.
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PLEASE EXPLAIN HOW YOU SOLVE THIS
PLS HELPPPPP
(image included btw)
Answer:
m = -63
b = 825
Step-by-step explanation:
First, the slope intercept form of a line is
y = mx + b
where m = slope and b = y-intercept
The slope is also referred to as rise/run ie the ratio of the change in y values to the corresponding change in x values for two points
The y-intercept is y value where the line crosses the y-axis
For two points on the graph (x1, y1) and (x2, y2), the slope is given by the equation :
\(m=\frac{y2-y1}{x2-x1}\)
The two indicated points are (4, 699) and (8, 321)
So slope
\(m = \dfrac{321 - 699}{8 - 2}\)
\(m = \dfrac{-378}{6}\)
\(m = -63\)
Therefore the equation of the line is y = mx + b
To find the y-intercept, b, plug in any of these point values into the above equation and solve for b
Let's choose point(8, 321)
We have
y = -63x + b
Substituting for y = 321 and x = 8 gives us
321 = -63(8) + b
Switch sides
-63(8) + b = 321
-504 + b = 321
Add 504 to both sides to get
b = 321 + 504 = 825
So b = 825
Which pair of transformations to the figure shown below would produce an image that is on top of the original (same position, shape, and size)?
A hexagon in the shape of a right arrow is above a horizontal line and left of a vertical line.
A. a translation to the right and a reflection over the vertical line of reflection shown
B. a translation down and a reflection over the horizontal line of reflection shown
C. a 90° clockwise rotation and a reflection over the vertical line of reflection shown
D. a 180° counterclockwise rotation and a reflection over the horizontal line of symmetry shown
The correct pair of Transformations to produce an image that is on top of the original figure is a 180° counterclockwise rotation and a reflection over the horizontal line of symmetry shown, which is option D.
To produce an image that is on top of the original figure, we need to perform a series of transformations that include a reflection and a translation.
Option A suggests a translation to the right and a reflection over the vertical line of reflection shown. This transformation would move the hexagon to the right of the original position, so it is not the correct pair of transformations.
Option B suggests a translation down and a reflection over the horizontal line of reflection shown. This transformation would move the hexagon below the original position, so it is also not the correct pair of transformations.
Option C suggests a 90° clockwise rotation and a reflection over the vertical line of reflection shown. This transformation would rotate the hexagon and reflect it over the vertical line of reflection, but it would not produce an image that is on top of the original.
Option D suggests a 180° counterclockwise rotation and a reflection over the horizontal line of symmetry shown. This transformation would rotate the hexagon by 180° and reflect it over the horizontal line of symmetry. The resulting image would be on top of the original, with the hexagon in the same position, shape, and size.
Therefore, the correct pair of transformations to produce an image that is on top of the original figure is a 180° counterclockwise rotation and a reflection over the horizontal line of symmetry shown, which is option D.
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9. the school district is served by four buses, each of which delivers students to three different schools. you know the cost of transporting each of the students to each of the schools, and you want to determine the least expensive way to get all of the students to their schools. if you use excel solver for this analysis, how many different variable cells should you use?
If you use excel solver for this analysis, the number of different variable cells should you use are 12
Option- C
The right answer is 12.
Given that,
There are four buses that transport children to the district's three main schools. You are aware of the price of transporting each student to each school.
Since there are four buses and three schools according to the supplied description, each bus has three school alternatives, thus 4*3=12, bearing in mind that there must be the least expensive route to transport all of the students to their schools.
There must therefore be 12 separate variable cells employed.
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MMMM THE MODERATORS ARE MAKING ME FLIPPING ANGRY! I NEED SOMEONE TO ANSWER MY QUESTION PLEASE .
Answer:
780
Step-by-step explanation:
So 5% is 39 so 5% x 20 is 100% do the same with the 39 so do
39 x 20 = 780
What is the equivalent trig ratio to cos 18 ?
Answer:
\(\sin{72^\circ}\)
Step-by-step explanation:
In a right triangle, the two acute angles are complementary--they add up to 90 degrees.
Cosine is defined as the adjacent side divided by the hypotenuse. In the attached picture, \(\cos{18^\circ}=\frac{a}{h}\).
The other acute angle is 90 - 18 = 72 degrees. Looking at just that angle, side a is the opposite side. So the ratio a/h is opposite over hypotenuse -- the sine ratio.
Therefor, \(\cos{18^\circ} = \sin{72^\circ}\)
There is about 3.25% fat in a milk sample. How many grams of that milk would contain 13 grams of fat? Weight of milk = grams.
Given that a milk sample contains 3.25% fat, the amount of milk that would contain 13 grams of fat is approximately 400 grams.
The weight of milk that contains 13 grams of fat, we can set up a proportion using the fat percentage.
Let's assume x represents the weight of milk in grams. We know that the fat content is 3.25% of the milk sample. Therefore, 0.0325x grams of the milk sample is fat.
Now we can set up the proportion:
0.0325x grams of fat / x grams of milk = 13 grams of fat / y grams of milk
Cross-multiplying the proportion, we get:
0.0325x * y = 13 * x
0.0325y = 13
Simplifying the equation, we find:
y = 13 / 0.0325
y ≈ 400 grams
Therefore, approximately 400 grams of milk would contain 13 grams of fat.
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you put $1,200. in a savings account for four years at 5.6%. what is the total amount in the account after the four years
Answer:
you would have 1,194.4
Step-by-step explanation:
i subtracted.
Tommy and his friends are planning a trip to the Mega Vault trampoline park. The employee
Tommy spoke to on the phone said the total cost for all 5 of them would be $85. This includes
a $3 fee added to each entrance ticket to cover the cost of a pair of grip socks.
Which equation can you use to find c, the cost of an entrance ticket?
5(c + 3) = 85
5c + 3 - 85
3c+5 85
3(c+5)= 85
The equation to find the entrance cost is 5(c + 3) = 85.
Given that 5 five friends made plan for trip, which will cost them a total of $85,
This includes a $3 fee added to each entrance ticket to cover the cost of a pair of grip socks.
We need to establish an equation to find c, the cost of an entrance ticket,
So,
The total cost of one entrance ticket = c + 3,
So, for 5 people = 5(c+3)
Now, this is equal to 85.
So the equation is = 5(c + 3) = 85.
Hence the equation to find the entrance cost is 5(c + 3) = 85.
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What is the answer for this?
Answer:
D. Four right angles
Step-by-step explanation:
Answer:
DStep-by-step explanation:
one of the property of all rectangles is that it has four right angles
:-)
level:8th
Rewrite one eighth times x cubed times y plus seven eighths times x times y squared using a common factor.
one fourth times x times y times the quantity 4 times x squared plus 28 times y end quantity
one fourth times x times y times the quantity x squared plus 7 times y end quantity
one eighth times x cubed times y squared times the quantity y plus 7 times x end quantity
one eighth times x times y times the quantity x squared plus 7 times y end quantity
Answer:
First statement;
\({ \tt{ \frac{1}{8} {x}^{3}y + \frac{7}{8} x {y}^{2} }} \\ \\ = { \boxed{ \tt{ \frac{1}{8}xy( {x}^{2} + 7y)}}}\)
Second statement;
\({ \tt{ (\frac{1}{4}y 4{x}^{3} ) + 28y}} \\ \\ \)
Third statement;
\({ \tt{( \frac{1}{4} y {x}^{3}) + 7y }} \\ \\ \)
Forth statement;
\({ \tt{ \frac{1}{8}x {}^{3} {y}^{3} + 7x }} \\ \\ \)
Fifth statement;
\({ \tt{ \frac{1}{8}x {}^{2} y + 7y }}\)
Help !! I need to do this fast !!!!!
Answer:
3 and 6
Step-by-step explanation:
can i get brainliest please? thanks!
hope this helps!
Find the point on y axis which is equidistant from the point (5,-2) and (-3,2)
Answer:
(0, -2)
Step-by-step explanation:
a point on the y-axis. that means x=0.
so, the distance of (5, -2) to (0, y) is the same as the distance from (-3, 2) to (0, y).
the distance between (5, -2) and (0, y) is based on Pythagoras (the differences in x and y directions are the sides of a right-angled triangle, and the distance is its Hypotenuse, its baseline) :
distance² = (5-0)² + (-2 - y)² = 25 + 4 + 4y + y² = 29+4y+y²
but it is also
distance² = (-3-0)² + (2 - y)² = 9 + 4 - 4y + y² = 13 - 4y + y²
so, we get
29 + 4y + y² = 13 - 4y + y²
29 + 4y = 13 - 4y
16 = -8y
y = -16/8 = -2
their, the point on the y-axis being equidistant to both points is (0, -2)
Order the following rational numbers from greatest to least.
-2/5, 0.75, -1/2, 70%, 11/20
Answer: 0.75, 70%, 11/20, -2/5, -1/2
Step-by-step explanation:
Convert to decimal values and compare:
Q A
0.75 0.75
70% 0.7
11/20 0.55
-2/5 -0.4
-1/2 -0.5
t = mx
Solve equation for m
Answer:
M=t/x
Step-by-step explanation:
I love these math problems! Do u have more? I really need something 2 do
Seema read 511 of the book during weekday and the ret of the
book he planned to read during the weekend. What part of the book
i left for reading during the weekend?
Seema left 6/11 of the book for reading over the weekend.
To calculate the part of the book left for reading during the weekend, we need to subtract the part of the book Seema read during the weekday from the total book.
If Seema reads 5/11 of the book during the weekday, then:
11 - 5 = 6This means 6/11 of the book is left for reading during the weekend. It is important to note that the fraction of the book read during the weekday and the fraction left for reading during the weekend add up to the total book. This means that 11/11 of the book will be read by Seema in total.
This question should be written as:
Seema reads 5/11 of the book during weekday and the rest of the book she planned to reads during the weekend. What part of the book is left for reading during the weekend?Learn more about Mike has read 2/4 book here: brainly.com/question/23514329
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how to graph absolute value equations on a number line
Identify the equation: Write down the given equation in the form |x - a| = b, where 'a' represents the number being subtracted or added and 'b' represents the absolute value.
Graphing absolute value equations on a number line is a process that involves several steps. First, you need to identify the equation and rewrite it in the form |x - a| = b, where 'a' represents the number being subtracted or added and 'b' represents the absolute value.
This form helps determine the critical points of the graph. Next, you set the expression inside the absolute value bars equal to zero and solve for 'x' to find the critical points. These points indicate where the graph may change direction. Once the critical points are determined, you plot them on the number line, using an open circle for critical points and a closed circle for any additional points obtained by adding or subtracting the absolute value.
After plotting the points, you can draw the graph by connecting them with a solid line for the portion of the graph that is positive and a dashed line for the portion that is negative. This representation helps visualize the behavior of the absolute value equation on the number line.
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