Liquid benzene and liquid n-hexane are blended to form a stream flowing at a rate of 1700 lbm/h. An on-line densitometer (an instrument used to determine density) indicates that the stream has a density of 0.810 g/mL. Using specific tractors from Table B.1, estimate the mass and volumetric feed rates of the two hydrocarbons to the mixing vessel (in U.S. customary units). State at least two assumptions required to obtain the estimate from the recommended date.

Answer:

A

Explanation:

Answer:

a

Explanation:

Answer:

a) 158.4 HP.

b) 1235.6 °F.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up an energy balance for the turbine's inlets and outlets:

\(m_{in}h_{in}=W_{out}+m_{out}h_{out}\)

Whereas the mass flow is just the same, which means we have:

\(W_{out}=m_{out}(h_{out}-h_{in})\)

And the enthalpy and entropy of the inlet stream is obtained from steam tables:

\(h_{in}=1860.7BTU/lbm\\\\s_{in}= 2.2096BTU/lbm-R\)

Now, since we assume the 80% accounts for the isentropic efficiency for this adiabatic gas turbine, we assume the entropy is constant so that:

\(s_{out}= 2.2096BTU/lbm-R\)

Which means we can find the temperature at which this entropy is exhibited at 15 psia, which gives values of temperature of 1200 °F (s=2.1986 BTU/lbm-K) and 1400 °F (s=2.2604 BTU/lbm-K), and thus, we interpolate for s=2.2096 to obtain a temperature of 1235.6 °F.

Moreover, the enthalpy at the turbine's outlet can be also interpolated by knowing that at 1200 °F h=1639.8 BTU/lbm and at 1400 °F h=174.5 BTU/lbm, to obtain:

\(h_{out}=1659.15BUT/lbm\)

Then, the isentropic work (negative due to convention) is:

\(W_{out}=2500lbm/h(1659.15BUT/lbm-1860.7BUT/lbm)\\\\W_{out}=-503,875BTU\)

And the real produced work is:

\(W_{real}=0.8*-503875BTU\\\\W_{real}=-403100BTU\)

Finally, in horsepower:

\(W_{real}=-403100BTU/hr*\frac{1HP}{2544.4336BTU/hr} \\\\W_{real}=158.4HP\)

Regards!

The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.

Explanation:

The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.

Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.

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If control requirements are very complex or extensive, a: A. Master sequencer can be installed.

A master sequencer is a device that controls multiple circuits in a predetermined sequence. It is commonly used in industrial settings where multiple machines or systems need to be turned on or off in a specific order.  A master sequencer can be programmed to turn on and off circuits at specific times, or based on certain conditions. This allows for precise control of complex systems, and can help prevent equipment damage or failures.

Additionally, a master sequencer can provide a level of safety by ensuring that certain circuits are turned off before others are turned on, reducing the risk of accidents or injuries. Overall, a master sequencer is a valuable tool for controlling complex systems in industrial or commercial settings. So the answer is A. Master sequencer.

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A visual aid for classifying a problem's possible origins is a fishbone diagram.

Thus,  This technique is used to determine the underlying causes of issues. A fishbone diagram combines the technique of brainstorming with a form of mind map template, and is frequently used for root cause analysis. As a test case technique to ascertain cause and effect, it ought to be effective.

In product development and troubleshooting procedures, a fishbone diagram is helpful because it may be used to centre a discussion on a specific issue.

The facilitator works with the group to rank potential causes in order of priority and create a hierarchy once the group has brainstormed every potential source of the issue. The diagram's design, which closely resembles, the source of the name and fishbone.

Thus, A visual aid for classifying a problem's possible origins is a fishbone diagram.

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Answer:

Reduce manufacturing costs.

Explanation:

Hope This Helps

Have A Great Day

Answer:

Explanation:

Considering the flow of mercury in a tube:

When it comes to laminar flow of mercury, the thermal entry length is quite smaller than the hydrodynamic entry length.

Also, the hydrodynamic and thermal entry lengths which is given as DLhRe05.0= for the case of laminar flow. It should be noted however, that Pr << 1 for liquid metals, and thus making the thermal entry length is smaller than the hydrodynamic entry length in laminar flow, like I'd stated in the previous paragraph

Answer:

  f(x) = x -3

Explanation:

Solve for y, then replace y by f(x).

  x - y = 3

  x - 3 = y . . . . . add y-3 to both sides

  f(x) = x -3

Answer:

(x) = x – 3

Explanation:

edge

Brevity is best is one of the two golden rules of communication for engineers.

Brevity is considered one of the key principles of effective communication, especially in technical fields like engineering. It emphasizes the importance of conveying information concisely and clearly, avoiding unnecessary details or lengthy explanations. By being concise, engineers can communicate their ideas and technical information more effectively, ensuring that their message is understood by the audience.

The other options listed, such as beginning with a humorous anecdote or story, maintaining eye contact with the audience, and speaking softly, may be considered good communication practices in general but do not represent the specific golden rules of communication for engineers.

Engineers are often required to convey complex technical information to a non-technical audience, so it is important to keep their communication brief and to the point. The other golden rule is to know your audience and tailor your message accordingly.

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A nozzle-2 inclined at an angle of 30 degrees (with horizontal) is added to the system and both water jets strike at some point. For Nozzle-2, upon contact, water exits the plate 40% upwards and the remaining downwards.

Assuming frictionless flow and neglecting gravity effects, this paper examines the trajectories and forces exerted on the jet by each nozzle.The paths of the jets are defined by a momentum balance between the jet and the forces it encounters.

The jets' trajectory and force are dependent on the velocity of the stream entering the nozzle. The paths of the jets can be influenced by the interaction between the jets and the forces caused by the collisions between the two fluid streams in the impact zone.The velocities of the streams flowing through each nozzle should be comparable and symmetric for the nozzles to be coordinated. When the pressures are different, the path of the stream is also changed. If the downstream pressure of the two streams is unequal, they will impact at different positions on the plate.

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Answer:

Answer:

(a) The terminal voltage of the cell is 1.9 V.

(b) The terminal voltage of the cell is 1.0 V.

Explanation:

If wrong sorry but if right please give brainliest

Answer: True

Explanation: Iron is magnetic

Answer:

a

Explanation:

because if you do its right

Note that  the minimum radius that will satisfy the sight distance and superelevation requirements for a horizontal curve that is to be designed to connect two tangents on a rural principal arterial with a design speed of 70 mi/hr is 1,385 feet.

The sight distance requirement for a rural principal arterial with a design speed of 70 mi/hr is 1,200 feet.

The superelevation requirement for a rural principal arterial with a design speed of 70 mi/hr is 0.08.

The sight distance requirement can be calculated using the following equation  -

S = 0.078 * V^2 * T

where:

* S is the sight distance in feet

* V is the design speed in miles per hour

* T is the time to react in seconds

The time to react is typically assumed to be 2 seconds.

Substituting the values

S = 0.078 * 70 * 70 * 2

= 1,200 ft

The superelevation requirement can be calculated using the following equation  -

e = 0.08 * V

where   -

* e is the superelevation in feet per foot

* V is the design speed in miles per hour

Substituting the values into the equation, we get:

e = 0.08 * 70

= 5.6 ft/ft

The minimum radius that will satisfy the sight distance and superelevation requirements can be calculated using the following equation

R = e * T^2 / 2 * S

where  -

* R is the radius in feet

* e is the superelevation in feet per foot

* T is the time to react in seconds

* S is the sight distance in feet

Substituting the values into the equation, we get  -

R = 5.6 * 2^2 / 2 * 1,200

= 1,385 ft

Therefore, the minimum radius that will satisfy the sight distance and superelevation requirements for a horizontal curve that is to be designed to connect two tangents on a rural principal arterial with a design speed of 70 mi/hr is 1,385 feet.

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By multiplying the "GDP per capita" and "Population" columns, a new column indicating total GDP can be created in a Prepare recipe or a Code recipe using the Formula processor.

Positive connection shows that rising GDP per capita causes rising carbon dioxide emissions.There isn't a "tipping point" when emissions start to fall after GDP reaches a specific level, according to some beliefs.

The findings show that economic growth and CO2 emissions have a statistically significant long-run cointegration connection, with an average 1% change in GDP translating to a 0.072 change in CO2 emissions.

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Answer:

Develop social skills

Explanation:

Answer:

strengthen your college applications

Explanation:

Increase the scan speed and increase exposure.

Increasing the scan speed and exposure can help decrease the total print time for a photopolymer part while maintaining its mechanical and behavioral properties and high precision. By increasing the scan speed, the laser or light source used in the printing process moves more quickly across the build area, reducing the overall time required for printing.

However, it is crucial to balance the increased scan speed with the exposure settings to ensure that the part maintains its desired properties and precision. Increasing the exposure time compensates for the faster scan speed, ensuring that the photopolymer material receives an adequate amount of energy for proper curing and solidification.

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What is the best approach to decrease the total print time for a photopolymer part that you have printed before, maintaining its exact mechanical and behavioral properties and high precision?

The free version is fine and might be all you need, but I bought the in-app item since I felt the creator deserved to be compensated for creating such an attractively understated and useful software.

A Soft Murmur is a background noise generator that you may use online to unwind, concentrate, and block out distracting noises. Depending on the sound, background noise can either be comforting or annoying.

The official A Soft Murmur app from the corresponding website offers a dozen different calming sounds to provide background noise in every setting. Even better, you may mix the sounds in any way you choose to produce various moods.

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Answer:

a) i) The maximum pressure is approximately 122.37 bar

ii) The thermal efficiency is approximately 56.47%

iii) The mean effective pressure is approximately 20.974 bar

b) (b) Four types of internal combustion engine includes;

1) The diesel engine

2) The Otto engine

3) The Brayton engine

4) The Wankel engine

Explanation:

The parameters of the Otto cycle are;

The heat added, \(Q_{in}\) = 2,800 kJ/kg

The compression ratio, r = 8

The beginning compression pressure, P₁ = 1 bar

The beginning compression temperature, T₁ = 300 K

Cp = 1.005 kJ/kg·K

Cv = 0.718 kJ/kg·K

R = 287 kJ/kg·K

K = Cp/Cv = 1.005 kJ/kg·K/(0.718 kJ/kg·K) ≈ 1.4

T₂ = T₁×r^(k - 1)

∴ T₂ = 300 K×8^(1.4 - 1) ≈ 689.219 K

\(\dfrac{P_1\cdot V_1}{T_1} = \dfrac{P_2\cdot V_2}{T_2}\)

\(P_2 = \dfrac{P_1\cdot V_1 \cdot T_2}{T_1 \cdot V_2} = \dfrac{V_1}{V_2} \cdot \dfrac{P_1 \cdot T_2}{T_1 } = r \cdot \dfrac{P_1 \cdot T_2}{T_1 }\)

∴ P₂ = 8 × 1 bar × (689.219K)/300 K ≈ 18.379 bar

\(Q_{in}\) = m·Cv·(T₃ - T₂)

∴ \(Q_{in}\) = 2,800 ≈ 0.718 × (T₃ - 689.219)

T₃ = 2,800/0.718 + 689.219 = 4588.94 K

P₃ = P₂ × (T₃/T₂)

P₃ = 18.379 bar × 4588.94K/(689.219 K) = 122.37 bar

The maximum pressure = P₃ ≈ 122.37 bar

(ii) The thermal efficiency, \(\eta_{Otto}\), is given as follows;

\(\eta_{Otto} = 1 - \dfrac{1}{r^{k - 1}}\)

Therefore, we have;

\(\eta_{Otto} = 1 - \dfrac{1}{8^{1.4 - 1}} \approx 0.5647\)

The thermal efficiency, \(\eta_{Otto}\) ≈ 0.5647

Therefore, the thermal efficiency ≈ 56.47%

(iii) The mean effective pressure, MEP is given as follows;

\(MEP = \dfrac{\left(P_3 - P_1 \cdot r^k \right) \cdot \left(1 - \dfrac{1}{r^{k-1}} \right)}{(k -1)\cdot (r - 1)}\)

Therefore, we get;

\(MEP = \dfrac{\left(122.37 - 1 \times 8^{1.4} \right) \cdot \left(1 - \dfrac{1}{8^{1.4-1}} \right)}{(1.4 -1)\cdot (8 - 1)} \approx 20.974\)

The mean effective pressure, MEP ≈ 20.974 bar

(b) Four types of internal combustion engine includes;

1) The diesel engine; Compression heating is the source of the ignition, with constant pressure combustion

2) The Otto engine which is the internal combustion engine found in cars that make use of gasoline as the source of fuel

The Otto engine cycle comprises of five steps; intake, compression, ignition, expansion and exhaust

3) The Brayton engine works on the principle of the steam turbine

4) The Wankel it follows the pattern of the Otto cycle but it does not have piston strokes

Answer: the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s

Explanation:

from the T-S diagram, we get the overall pressure ratio of the cycle is 9

Calculate the pressure ratio in each stage of compression and expansion. P1/P2 = P4/P3  = √9 = 3

P5/P6 = P7/P8  = √9 =3  

get the properties of air from, "TABLE A-17 Ideal-gas properties of air", in the text book.

At temperature T1 =300K

Specific enthalpy of air h1 = 300.19 kJ/kg

Relative pressure pr1 = 1.3860  

At temperature T5 = 1200 K

Specific enthalpy h5 = 1277.79 kJ/kg

Relative pressure pr5 = 238  

Calculate the relative pressure at state 2

Pr2 = (P2/P1) Pr5

Pr2 =3 x 1.3860 = 4.158  

get the two values of relative pressure between which the relative pressure at state 2 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.  

Relative pressure pr = 4.153

The corresponding specific enthalpy h = 411.12 kJ/kg  

Relative pressure pr = 4.522

The corresponding specific enthalpy h = 421.26 kJ/kg  

Find the specific enthalpy of state 2 by the method of interpolation

(h2 - 411.12) / ( 421.26 - 411.12) =  

(4.158 - 4.153) / (4.522 - 4.153 )

h2 - 411.12 = (421.26 - 411.12) ((4.158 - 4.153) / (4.522 - 4.153))  

h2 - 411.12 = 0.137

h2 = 411.257kJ/kg  

Calculate the relative pressure at state 6.

Pr6 = (P6/P5) Pr5

Pr6 = 1/3 x 238 = 79.33  

Obtain the two values of relative pressure between which the relative pressure at state 6 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.  

Relative pressure Pr = 75.29

The corresponding specific enthalpy h = 932.93 kJ/kg  

Relative pressure pr = 82.05

The corresponding specific enthalpy h = 955.38 kJ/kg  

Find the specific enthalpy of state 6 by the method of interpolation.

(h6 - 932.93) / ( 955.38 - 932.93) =  

(79.33 - 75.29) / ( 82.05 - 75.29 )

(h6 - 932.93) = ( 955.38 - 932.93) ((79.33 - 75.29) / ( 82.05 - 75.29 )

h6 - 932.93 = 13.427

h6 = 946.357 kJ/kg

Calculate the total work input of the first and second stage compressors

(Wcomp)in = 2(h2 - h1 ) = 2( 411.257 - 300.19 )

= 222.134 kJ/kg  

Calculate the total work output of the first and second stage turbines.

(Wturb)out = 2(h5 - h6) = 2( 1277.79 - 946.357 )

= 662.866 kJ/kg  

Calculate the net work done

Wnet = (Wturb)out  - (Wcomp)in

= 662.866 - 222.134

= 440.732 kJ/kg  

Calculate the minimum mass flow rate of air required to generate a power output of 105 MW

W = m × Wnet

(105 x 10³) kW = m(440.732 kJ/kg)

m = (105 x 10³) / 440.732

m = 238.2 kg/s

therefore the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s

Assuming a data analyst prepares to communicate to an audience about an analysis project and considers what the audience members hope to do with the data insights, this describes establishing the setting: False.

In Computer technology, data is any representation of factual instructions or information in a formalized and structured manner, especially as a series of binary digits (bits), symbols, characters, quantities, or strings that are used on computer systems in a company.

A data analyst can be defined as an expert or professional who is saddled with the responsibility of inspecting, transforming, analyzing, and modelling data with the sole aim of discovering useful information, providing insights, and creating informed conclusions, in order to support decision-making and create a completed report.

In Computer technology, audience engagement in data storytelling simply refers to a process that is typically focused on considering all of the issues that audience members hope to do and achieve with the data insights provided by a data analyst.

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The least value of extraterrestrial solar radiation is constant throughout the year. Therefore, the answer is option (c) Constant throughout the year. The extraterrestrial solar radiation is the amount of solar radiation received from the sun at the top of the Earth's atmosphere, the solar constant (Isc). The adjusted reading of the pyranometer is 82 W/m2.

The least value of extraterrestrial solar radiation is constant throughout the year. A pyranometer is an instrument used for measuring the solar irradiance (total energy flux from the Sun) that falls upon a planar surface. A pyranometer with a shading ring is used to measure diffuse radiation at a location with a latitude of 0°.If a pyranometer with a shading ring is used to measure diffuse radiation at a location with a latitude of 0° and it has a reading of 100 W/m2, the adjusted reading of this pyranometer will be as follows:

Let’s assume the correction factor of a pyranometer with a shading ring is 0.18. Therefore the adjusted reading of pyranometer is calculated as: Adjusted reading = (1 - 0.18) × reading= 0.82 × 100= 82 (W/m2).

Therefore, the adjusted reading of the pyranometer is 82 W/m2.

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Answer:

P1+1/2pv2/1+pgh1=P2+1/2pv2/2+pgh2

Explanation:

I won't answer each of these, but will give you an explaination of how to solve for each.

You'll need to use Ohm's Law and Kirchhoff's Voltage Law.

Remember Ohm's Law as \(V = IR\).

Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.

\(E_T = E_1 + E_2 + E_3\)

A couple of other helpful notes:

These three resistors are in series which means that the current flowing through them is equal.

So it is easy to see that... \(V = IR \rightarrow E_1 = 4*2 = 8 V\)

Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).

Answer:

Sarah is a professional interior designer.

Therefore, Sarah carries the title of a _registered___ interior designer.

Explanation:

Some states require only the licensed designers to carry out interior designs, while some others allow both the licensed and unlicensed interior designers to carry on the work of interior designers.  In the states where only the licensed designers are allowed to use the title of interior designer, they are registered after passing the state-prescribed examinations and meeting some professional experience requirements. The most common exam is the National Council for Interior Design Qualification (NCIDQ) examination, which only bachelor degree holders in interior design are allowed to sit for.

The time derivative of a unit step function is another step function, the period (T) is 0.33 sec and the frequency (f) is 3 Hz, when b < 1, the function x(bt) is compressed horizontally and vertically.

A unit step function is defined as a function u(t) that is zero for all values of t less than zero, and 1 for all values of t greater than zero. Its time derivative is defined as u′(t), which is a pulse with an amplitude of 1 occurring at t=0.

The given function is, \(x(t) = 2cos(6\pi t + \pi/6)\). Now, period T is given by: \($T = \frac{2\pi}{\omega}$\)

Where ω is the angular frequency of the function.

For the given function, \(\omega = 6\pi\). Therefore, \(T = \frac{2\pi}{6\pi}$ = $\frac{1}{3}$\) sec.

Therefore, the correct option is (c) T=0.33 sec ,f=3 Hz.

The given function is x(bt) which is a compressed version of x(t) if:b < 1. When b < 1, the function x(bt) is stretched horizontally and compressed vertically with respect to the function x(t). Therefore, the option (d) b less than 1 is correct.

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The state of the network's health using tools including bandwidth use statistics, device delay monitoring, active clock health monitoring, packet error reporting, and device health monitoring.

With the help of capabilities like latency monitoring, clock monitoring, packet error reporting, and bandwidth utilization, Audinate has created an extensive set of diagnostic tools that are integrated into the Dante Controller. These tools give users insight into the network's current health.

You can see and connect to Dante-enabled devices on your network using dante controller. In order to connect to and from your Dante Virtual Soundcard, you require it. Dante Controller does not have to be running after the initial configuration of the connections and routes.

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