List 20 examples vector quantities​

The angle the rope make with the vertical when the ball's kinetic energy is halved is 14.78°.

Let K = 1/2mv² be the balls initial kinetic energy when it is pushes horizontally. It rises to a height, h has potential energy U = mgh and has kinetic energy half of its initial kinetic energy. So, K' = 1/2K.

So, from the law of conservation of energy,

K = U + K'

K = U + 1/2K

K - 1/2K = U

K/2 = U

1/2(1/2mv²) = mgh

1/4mv² = mgh

1/4v² = gh

h = v²/4g

Since v = initial speed of ball = 1.3 m/s and g = acceleration due to gravity = 9.8 m/s².

Substituting the values of the variables into the equation, we have

h = v²/4g

h = (1.3 m/s)²/(4 × 9.8 m/s²)

h = 1.69 m²/s² ÷ 39.2 m/s²

h = 0.043 m.

Since the length of the rope l = 1.3 m and the distance of the ball from the pivot when it is h metres above its lowest point is L = l - h = 1.3 m - 0.043 m = 1.257 m.

So, the angle the rope makes with the vertical is Ф and cosФ = L/l

= 1.257/1.3

= 0.9669

Ф = cos⁻¹(0.9669)

Ф = 14.78°

So, the angle the rope make with the vertical when the ball's kinetic energy is halved is 14.78°.

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(a) The acceleration of the system is determined as 1.58 m/s².

(b) The relative weight of P is pounds is determined as 0.14 lb.

The acceleration of the system is calculated as follows;

W - T = m₂a --- (1)

T = m₁a ----(2)

μmgsinθ - m₁a = m₂a

(0.3 x 3 x 9.8 x sin40) - (0.4 + 0.2)a = 3a

5.67 - 0.6a = 3a

5.67 = 3.6a

a = 5.67/3.6

a = 1.58 m/s²

W = ma

W = 0.4 x 1.58

W = 0.632 N = 0.14 lb

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The electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

The electric field is calculated as follows;

E = kq/r²

where;

midpoint of 3.08 m, x = 1.54 mm

r(1.54 mm, 2.00 mm)

|r| = √(1.54² + 2²)

|r| = 2.52 mm

E = (9 x 10⁹ x 37.3 x 10⁻³)/(2.52 x 10⁻³)²

E = 5.287 X 10¹³ N/C

Thus, the electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

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If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.

Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.

Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.

While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.

Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.

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a. The results should be repeated is 40.

b. because because it's not accurate.

c. Jamaal draw a line of best fit at the middle of the reflection angel and incidence angle.

The angle created when a sunlight ray strikes a line that is perpendicular to a surface; for instance, a surface facing the sun directly has an angle of incidence of 0, while a surface parallel to the sun (such as sunlight striking a horizontal rooftop) has an angle of incidence of 90°.

The light ray that reflects off the surface is referred to as the reflected ray, and the angle at which the reflected ray reflects off the surface is referred to as the reflection angle. The law of reflection states that the angle of incidence and angle of reflection are equal.

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The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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Answer:

i think the answer is c

Explanation:

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A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.

"A body is said to be "free" when it is singled out from other bodies for the purposes of dynamic or static analysis." The object does not have to be "free" in the sense of being unforced, and it may or may not be in a state of equilibrium; rather, it is not fixed in place and is thus "free" to move in response to forces and torques it may experience.

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The government can encourage the production of goods that create positive externalities by implementing policies and mechanisms such as subsidies, tax incentives, and regulations.

Positive externalities occur when the production or consumption of a good or service benefits society beyond the direct parties involved. These benefits can include improved public health, environmental sustainability, or increased social welfare. To encourage the production of goods with positive externalities, the government can take the following steps:

Subsidies: The government can provide financial support to producers of goods with positive externalities. Subsidies can offset production costs, making it more attractive for producers to supply these goods. By reducing the costs of production, subsidies can encourage higher output and more widespread availability of goods that benefit society.

Tax incentives: The government can offer tax incentives or tax breaks to businesses that produce goods with positive externalities. By reducing the tax burden on producers, it becomes economically advantageous for businesses to engage in activities that generate positive externalities. Tax incentives can stimulate investment, innovation, and production in areas that have positive spillover effects.

Regulations: The government can implement regulations and standards that require or promote the production of goods with positive externalities. For example, environmental regulations can encourage industries to adopt cleaner technologies and reduce pollution. By setting standards and enforcing regulations, the government can steer production towards goods that have positive impacts on society.

Public-Private Partnerships: The government can collaborate with private entities to promote the production of goods with positive externalities. Through partnerships, the government can provide resources, expertise, and incentives to businesses that are willing to produce goods that generate social benefits. This collaboration can help overcome barriers and create a conducive environment for the production of socially beneficial goods.

By employing these measures, the government can provide the necessary incentives and support for the production of goods that create positive externalities. These actions align the private interests of producers with the broader goals of societal welfare, fostering a more sustainable and socially responsible economy.

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Answer:

v = 47.85 m / s ,   θ = 64.7º

Explanation:

This is a missile throwing exercise.

Let's find the speed to reach the maximum height, at this point the vertical speed is zero

        \(v_{y}^{2}\) = v_{oy}^{2} - 2 g y

         0 = v_{oy}^{2} - 2gy

        v_{oy} = √2gy

let's calculate

        v_{oy} = √ (2 9.8 21.3)

        v_{oy} = 20.43 m / s

now we can calculate the time it takes to get to this point

      vy = v_{oy} - g t

       t = v_{oy} / g

       t = 20.43 / 9.8

       t = 2.08 s

in projectile launching, the time it takes for the body to rise is the same as the time it takes to go down, so the total launch time is

     \(t_{v}\) = 2 t

     t_{v} = 2 2.08 = 4.16 s

let's use the horizontal throw ratio

      x = v₀ₓ t_{v}

      v₀ₓ = x / t_{v}

      v₀ₓ = 180 / 4.16

      v₀ₓ = 43.27 m / s

initial velocity is

      v = √ (v₀ₓ² + v_{oy}^{2})

      v = √ (20.43² + 43.27²)

      v = 47.85 m / s

with an angle of

      tan θ = I go / vox

      θ = tan⁻¹ (43.27 / 20.43)

      θ = 64.7º

(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.

Using the equation, we can solve for the acceleration:

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s

Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.

(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.

(c) To find the initial velocity of the ball, we can use the equation:

v = u + at

At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s upward

Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.

(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:

s = ut + (1/2)at^2

At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.

0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2

0 = 47.864 + (-5.5294)

5.5294 = 47.864

Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.

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Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         Δ\(P_{y}\) = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

          P = Pₓ / \(P_{y}\)

          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

          ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

          ΔP = 0.006 + 0.0026

          ΔP = 0.009 kg m

The result is

           P = 14,045 ± 0.039 = (14,045 ± 0.03 )  k gm/s

Answer: the answer would be C trust me i took the test if its not that its b

hope that helps

Explanation: i took the test

answer:

a) lower because the sound-wave fronts reach the platform at a frequency lower than the frequency at which they are produced

explanation :3

If the train is leaving the train station, then the people who are standing on the platform would hear a sound with a lower frequency since the train is moving further away. ^^

If a 1.5 kg ball has a momentum of 4.5 kg*m/s, the velocity of the ball is  3 m/s.

According to the question, the given quantity is,

Mass of the ball = 1.5 kg

The momentum of the ball =  4.5 kg. m/s

The momentum is defined as the product of the mass of the object and the velocity of the object, so p = mv.

p = momentum of an object

m = mass of an object

v = velocity of an object

According to question the given value outs in the formulae,

p= mv

4.50 = 1.50 × v

v = 4.50/ 1.50

v = 3 m/s.

Therefore, the velocity of the ball is  3 m/s.

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a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while  b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.

a. Isothermal compression:

For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Since the process is isothermal, we can write:

\(P_1V_1 = P_2V_2\)

where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.

We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:

\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)

To find the final temperature, we can use the ideal gas law again:

PV = nRT

Rearranging, we get:

T = PV/(nR)

Substituting the values we know, we get:

T = (\(1.5*10^5\)Pa)(V1)/(nR)

Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:

T2 = T1 = 293 K

b. Adiabatic compression:

For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:

PV^γ = constant

where γ = Cp/Cv is the ratio of specific heats.

Since the process is adiabatic and reversible, we can write:

\(P_1V_1\)^γ = \(P_2V_2\)^γ

We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:

\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)

To find the final temperature, we can use the adiabatic equation again:

\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K

Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.

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The models provide important tools for understanding the strong force interactions within a proton.

The strong force interactions between quarks and gluons within a proton are described by Quantum Chromodynamics (QCD), which is a fundamental theory of the strong nuclear force in particle physics. QCD is a non-Abelian gauge theory, meaning that the interactions between the quarks and gluons are highly nonlinear and non-perturbative.

One of the most promising theoretical models for describing the strong force interactions within a proton is lattice QCD, which is a numerical approach that uses a discrete grid to represent the space-time continuum. Lattice QCD allows for the calculation of QCD observables from first principles, without resorting to perturbative expansions. This method can handle non-perturbative effects such as confinement and chiral symmetry breaking by allowing for the simulation of the strong interactions on a discrete space-time grid

Another promising model is effective field theory, which provides a way to describe the low-energy behavior of QCD by constructing an effective Lagrangian that contains only the degrees of freedom relevant to a particular energy scale. This allows for the calculation of QCD observables in a systematic expansion in powers of a small parameter, such as the ratio of the quark mass to the QCD energy scale.

Chiral perturbation theory is another effective field theory that focuses on the dynamics of light quarks, which are the building blocks of pions, the lightest hadrons. Chiral perturbation theory provides a systematic expansion for the interactions between pions and nucleons, and can be used to calculate the properties of these particles at low energies.

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The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

A riddle is a statement, question or phrase having a double or veiled meaning, put forth as a puzzle to be solved.

If Robert, your neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long, based on these statements, we can explain the riddle as Robert weighs iron for the fact that he  is a blacksmith, iron is the only thing he weighs the whole day.

Thus, the correct explanation for the riddle is " The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

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Answer:

The correct answer is The plates smash together with no subduction. I just took this on Edge. Glad I could help!

The statement best describes the motion of the plates along these boundaries that causes the earthquakes is that The plates smash together with no subduction

For better understanding let's explain what the answer means

From the above we can therefore say that the answer The statement best describes the motion of the plates along these boundaries that causes the earthquakes is that The plates smash together with no subduction, is correct

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Answer:

d = 7200 m

Explanation:

Given that,

Average speed of a runner, v = 2 m/s

Time taken by the runner, t = 60 min = 3600 s

We need to find the distance covered by the runner.

Speed = distance divided by time taken.

v = d/t

Putting all the values,

\(d=v\times t\\\\d=2\times 3600\\\\d=7200\ m\)

So, the distance covered by the runner is 7200 m.

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

Answer:

Motion

Explanation:

Motion is change in distance. Which means it is a vector quantity, it has both magnitude and direction

The direct path and direction from point A to B is motion

there are into three types of motion such as Linear Motion

Rotary Motion, Oscillatory Motion

In linear motion, the particles pass from one point to another in either a straight line or a curved path, it depend on the path of motion, is further divided as follows

Rectilinear Motion  where The path of the motion is a straight line and Curvilinear Motion where The path of the motion is curved.

Rotatory Motion where the  body rotates on its own axis.  A few examples of the rotatory motion are as The motion of the earth about its own axis around the sun is an example of rotary motion.

Oscillatory motion is the motion of a body about its mean position. A few examples of  oscillatory motion are When a child on a swing is pushed, the swing moves to and fro about its mean position.

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Answer: 10m per second.

Explanation: 100/10 is 10/1, so it would be 10m per second.

Answer:

20 m

Explanation:

We'll begin by calculating the kinetic energy of the mass. This can be obtained as follow:

Mass (m) = 10 kg

Velocity (v) = 20 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 10 × 20²

KE = 5 × 400

KE = 2000 J

Finally, we shall the height to which the mass must be located in order to have potential energy that is the same as the kinetic energy. This can be obtained as follow:

Mass (m) = 10 kg

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) = Kinetic energy (KE) = 2000 J

Height (h) =..?

PE = mgh

2000 = 10 × 10 × h

2000 = 100 × h

Divide both side by 100

h = 2000 / 100

h = 20 m

Thus, the object must be located at a height of 20 m in order to have potential energy that is the same as the kinetic energy.

Answer:

7 protons, 8 neutrons, 7 electrons

Explanation:

Protons, electrons and neutrons are three sub-atomic particles present in an atom. Protons and neutrons are present in the nucleus while electrons are present outside the nucleus.

The number of protons, which is also the ATOMIC NUMBER, is equal to the number of electrons in a neutral atom (no overall charge). In this case, the number of protons is 7, however, since the charge of this Nitrogen atom is 0, it means that the number of electrons is also 7.

The mass number, denoted by A, is the sum of the number of protons and neutrons in an atom i.e.

A = number of proton + number of neutron.

In this case of Nitrogen isotope where the mass number is 15, the number of neutron will be mass number - number of protons i.e. 15 - 7 = 8.

Therefore, the number of protons, neutrons and electrons are 7, 8 and 7 respectively.

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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Given:

The coefficient of friction between the plane and the mass A is,

The masses are,

The angle of inclination is,

To find:

a) the acceleration of the masses

b) The smallest value of the coefficient of friction which will keep the system from accelerating

Explanation:

a)

The free-body diagram is:

For the mass B,

For the other mass, the normal reaction is,

Again the horizontal motion gives,

Combining the equations we get,

Hence, the acceleration is,

b)

For, the zero acceleration,

Hence, the required kinetic friction is 0.58.

a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.

(b) the angle of the landing ramp is 30°.

(a)

Launch speed = 55.0 mph * (1.467 ft/s)

= 80.685 ft/s

Horizontal distance = Launch speed * Time of flight

Vertical velocity = Launch speed * sin(30.0°)

Time to reach maximum height = Vertical velocity / g

Vertical distance = (1/2) *g * t²

and Time = √(2 * Vertical distance / g)

Total time of flight = 2 * Time to reach maximum height + Time for descent

Horizontal distance = Launch speed * Total time of flight

The Vertical velocity = 80.685 ft/s * sin(30.0°)

= 40.3425 ft/s

Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²

Time to reach maximum height  = 1.253 s

Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)

Time of descent  = 0.913 s

Total time of flight = 2 * 1.253 s + 0.913 s

Total time of flight = 3.419 s

In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s

horizontal distance = 276.298 ft

b.

the angle of the landing ramp is  30.0 be the same as the launch angle.

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Answer:

I said that setting enriches the characters. What I didn’t tell you is that it helps to form the characters. It does the same for the plot.

Explanation: