Look at the following scenarios. Does it have GPE, KE, both, or neither? Explain.1. A helicopter is hovering over the ground2. A bat is hanging upside-down in a cave.3.A statue of George Washington is in the park.4.A soccer ball is kicked along the ground.5.A soccer ball is kicked in the air.6.A car is parked on the street.7.A cell phone is in your hand by your head.8.A cell phone is in your hand by your head as you walk down the street.9.A cash register sits on the counter.

Answer:

A) X-rays

Explanation:

Airport security screenings use X-rays because they can penetrate through bags to see objects that are located within that are obscured through normal view.

X- rays are used to  test  body in airports. Low energy waves are used to screen baggages and human body. Thus option A is correct.

Electromagnetic spectrum is the arrangement of radiations in the order of decreasing wavelength or increasing energy and frequency. The order is radio waves, microwaves, infrared, visible, ultraviolet, x-rays and gamma rays.

x -rays are highly energetic short waves which can be easily penetrate through a body. X-ray is used in different diagnostic techniques. X-rays easily penetrate through  tissues and provide the scanned images of internal parts.

In airport security screening x-rays are used to screen baggages and human bodies. High energetic waves are causing serious health risks. Hence, lower energy x-rays are used in testing.

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Answer:

real kinetic theory means that kinetic energy

Answer:

4 m/s

Explanation:

d f = d o  + v o t  + 1/2 a t^2       underlined = 0 in this case

df = 1/2 a t^2

1   =  1/2 8 (t^2 )     shows t = .5 s

then:

vf = a t

       8 (.5 ) = 4 m/s

To cause a change in position, a force is required. No net force equals no velocity change. Speed and direction are both specified by velocity.

The velocity of a person or object determines its direction of motion. A scalar is velocity's most basic representation. Velocity is essentially a vector quantity. The relocation change rate is the issue.

The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t). Velocity is the pace and direction of an object's movement, whereas speed is indeed the time rate that an object is travelling along a path.

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prairie chickens organisms is not found in savannas. The correct option is c.

Savannas are typically characterized by the presence of tall grasses and a few scattered trees. The climate in this ecosystem is hot and dry, with a pronounced wet and dry season. Prairie chickens are not found in savannas.Here's why prairie chickens are not found in savannas:Savannas are typically found in tropical regions and are characterized by tall grasses and a few scattered trees. In contrast, prairies are found in temperate regions and are characterized by shorter grasses and a greater number of trees. Prairie chickens are a species of bird that are primarily found in prairie habitats. These birds are adapted to life on the open plains and feed on a variety of insects and seeds. While prairie chickens may share some similarities with the animals found in savannas, they are not typically found in this type of ecosystem.  

option C is the correct answer.

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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The time period of the charged particle is 2.093x 10⁻⁷s.

Cyclotron is a device which is used to accelerate heavy charged particles proton, deuteron, He nucleus, etc.

Here,

Charge of the particle, q = 7.5x 10⁻¹³ C

Mass of the particle, m = 2.5x 10⁻²¹ kg

Radius, r = 14x 10⁻² m

Magnetic field, B = 0.1 T

Time period of the charged particle,

T = 2\(\pi\)m/qB

T = (2\(\pi\)x 2.5x 10⁻²¹)/(7.5x 10⁻¹³x 0.1)

T = 2.093x 10⁻⁷ s

Hence,

The time period of the charged particle is 2.093x 10⁻⁷s.

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Answer: \(53\ rev/min\)

Explanation:

Given

angular speed of wheel is \(\omega_1 =530\ rev/min\)

Another wheel of 9 times the rotational inertia is coupled with initial wheel

Suppose the initial wheel has moment of inertia as I

Coupled disc has \(9I\) as rotational inertia

Conserving angular momentum,

\(\Rightarrow I\omega_1=(I+9I)\omega_2\\\\\Rightarrow \omega_2=\dfrac{I}{10I}\times 530\\\\\Rightarrow \omega_2=53\ rev/min\)

The maximum height to which the ball attain before falling back down is 1147.96 m

The following data were obtained from the question:

The maximum height reached by the ball can be obtained as illustrated below:

v² = u² – 2gh (since the ball is going against gravity)

0² = 150² – (2 × 9.8 × h)

0 = 22500 – 19.6h

Collect like terms

0 – 22500 = –19.6h

–22500 = –19.6h

Divide both side by –19.6

h = –22500 / –19.6

h = 1147.96 m

Thus, the maximum height reached by the ball is 1147.96 m

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Answer:

The answer is "6:45 and 7:15".

Explanation:

In the given attache file two clocks are added, that's explanation defined as follows:

In the left image, it may assume, that the clock only at the right-hand side of a scene is move-in its previous position, which is shown to the left, as it was at 6:45 on the left but in the right image it will display the time that is 7:15.

The velocity of the wave at point S, given the speed and the distance change, is 6 cm/s.

The wavelength of the wave at point R is 3. 0 cm, and the frequency of the wave is:

= 12 cm / s / 3. 0 cm

= 4 Hz

The wavelength of the wave at point S is 1. 5 cm, and the frequency of the wave is still 4 Hz .

The velocity of the wave at point S is therefore:

= 4 Hz x 1. 5 cm

= 6 cm / s

In conclusion, the velocity of the wave at point S is 6 cm / s.

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The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

Thus, Waveforms with periodic variations are those that recur consistently at set intervals.

The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.

In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.

Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

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The masses of the two objects MA and MB in the binary system are 4 Mo respectively.

The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.

Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:

MA + MB = 8 Mo

We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:

d(A to B) / d(Binary System) = 1/3

We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:

d(A to B) + d(B to binary system) = d(Binary system)

Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):

d(A to B) + 1/3d = d(Binary system)

3d(A to B) + d = 3d(Binary system)

Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:

3d(A to B) + d = 3(d(A to B) + d(B to binary system))

2d(A to B) = 2d(B to binary system)

d(A to B) / d(B to binary system) = 1

So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:

MA = MB

Substituting this into the first equation, we get:

2MA = 8 Mo

MA = MB = 4 Mo

Therefore, the mass of each object is 4 Mo.

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Answer:

the answer is the formula of acceleration is m/s²

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:

The answer is a fixed pulley

The magnitude of net force exerted on each one of the three masses is 0.53 * 10⁻¹³ N.

Given, m₁ = m₂ = m₃ = 7.5 g = 7.5 * 10⁻³ kg

Sides of the triangle = 35 cm = 35 * 10⁻² m

As the masses are the same and are at the corners of an equilateral triangle, two equal forces will act on each of the masses.

The forces on mass 1 due to mass 2 and due to mass 3 will be

| F₁₂| = Gm²/r²

⇒ 6.67* 10⁻¹¹* (7.5 * 10⁻³)²/(35 * 10⁻²)² = 375.19* 10⁻¹⁷/(35²* 10⁻⁴)

⇒ 0.306 * 10⁻¹³ N

| F₁₂| = | F₁₃| = 0.306 * 10⁻¹³ N

The magnitude of the net force on mass 1 can be found by the parallelogram law formula giving the magnitude of the resultant of two forces, given their magnitudes and the angle in between:

F₁ = | F₁₂ + F₁₃|

F₁ = √(| F₁₂| ² + | F₁₃|² + 2* | F₁₂|* | F₁₃| cos 60°) = √3 (F)

⇒ √3 * 0.306 * 10⁻¹³ = 0.53 * 10⁻¹³ N

The magnitude of force on each of the mass will be same.

Thus, the magnitude of force on each mass on the corners of the triangle will be 0.53 * 10⁻¹³ N.

The question is incomplete. The continuation to the above question is 'Find the magnitude of net force exerted on each of the three masses.'

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Between Kinetic energy and speed: The relationship is quadratic or parabolic. According to the kinetic energy formula, KE = 1/2 mv^2, the kinetic energy is proportional to the square of the speed.

Between potential energy and mass: The relationship is linear. The potential energy is directly proportional to the mass. In simple cases, the potential energy is given by PE = mgh, where mass (m) and height (h) are directly proportional.

Between pressure and volume: The relationship is inverse. According to Boyle's law, the pressure and volume of a gas are inversely proportional when temperature is constant. Mathematically, P1V1 = P2V2.

Between pressure and temperature: The relationship is linear. According to Charles's law, the pressure and temperature of a gas are directly proportional when volume is constant. Mathematically, P1/T1 = P2/T2.

Between displacement and velocity: The relationship is linear. Velocity is the rate of change of displacement with respect to time, so the two are directly proportional.

When a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its sides at frequency f the maximum induced emf is  2πBAf

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

The maximum induced emf is 2πBAf when a rectangular wire loop of area A is spun around one of its sides at frequency f, perpendicular to a uniform magnetic field B.

therefore the correct answer is option C

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Your question seems incomplete, the complete question is as follows

A rectangular loop of wire has area A. It is placed perpendicular to a uniform magnetic field B and then spun around one of its sides at frequency f. The maximum induced emf is:

A. BAf

B. 4πBAf

C. 2πBAf

D. 2BAf

Answer:

The correct answer is A    

Explanation:

In this exercise we are given a graph of temperature versus time.

In calorimeter processes there are two types

* one that when giving thermal energy to the system its temperature increases, this fundamentally due to the greater kinetic energy of the molecular ones, this process observes in the graphs as a straight line of constant slope

* A process donates all the thermal energy that is introduced is cracked in breaking the molecular bonds, taking matter from one thermodynamic state to another, for example: liquid to gas.

This process in curves as a horizontal line, that is, there is no temperature change,

When analyzing the graph shown, parts C and D are the one that show a change in temperature with thermal energy. The correct answer is A

Answer:

C and D

Explanation:

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when Force (N) is 10.0 Length (m) is 0.60

when Force (N) is 8.0 Length (m) is 0.40

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 2.0 Length (m) is 0.10

chatgpt

49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:

Period (T) = 2π√(Length (L) / g)

Substituting the given values:

2.3 = 2π√(L / 1.6)

To solve for L, we can rearrange the formula:

L = (2.3 / (2π))^2 * 1.6

L ≈ 0.781 meters (or 78.1 centimeters)

So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.

50. Ranking Task:

To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.

Ranking from least to greatest period:

1. A: 10 cm long, mass = 0.25 kg

2. C: 20 cm long, mass = 0.25 kg

3. B: 10 cm long, mass = 0.35 kg

There is a tie between pendulums A and C, as they have the same length but different masses.

Answer:

t = 4.34 s

Explanation:

To get this, we need to calculate the time of each part for both vehicles.

In the case of the bicycle, we can calculate the time duration with it's acceleration:

a = Vf - Vo/t ------> t = Vf - Vo / a

But Vo = 0 so time:

t = 21 / 14 = 1.5 s

Doing the same with the car:

t = 49 / 8 = 6.125 s

With these values of time, we can calculate the distance covered by both vehicles during acceleration:

X = Vo*t + at²/2

X = at² / 2

With the bicycle:

X = 14 * (1.5)² / 2 = 15.75 mi

With the car:

X = 8 * (1.5)² / 2 =  9 mi

And now, we can also get the speed of the car, after the time of 1.5 s has passed.

V = 8 * 1.5 = 12 mi/h

Now we can actually write an equation with both data of the vehicles in function of the distance. We are going to say that "t" would be the time taken by both vehicles, to meet each other.

Distance covered by the bicycle = distance covered by car

Distance covered by the bicycle would be:

15.75 mi + 21t

Distance covered by car:

9 + 12t + (8t²/2)

Equalling both expressions:

15.75 + 21t = 9 + 12t + 4t²

4t² - 9t - 6.75 = 0

Solving for t, using quadratic expressions we have:

t = 9 ± √(9)² + 4*4*6.75 / 2*4

t = 9 ±√189 / 8

t = 9 ± 13.75 / 8

t₁ = 2.84 s

t₂ = -0.594 s

We are taking the positive time.

Then, the time where both vehicles meet, which is the same time interval when the bicycle is ahead of the car will be:

t = 2.84 + 1.5

Hope this helps

The current reading on the ammeter A is 0.30 A.

A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.

Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles.

Current is scalar quantity and it follows the algebraic summation during addition.

The current reading on the ammeter A is = (0.20 A + 0.10 A) = 0.30 A.

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The coefficient of kinetic friction between the box and the floor is 0.87.

The coefficient of kinetic friction between the box and the floor is calculated by applying the formula for net force on the box.

F(net) = ma

where;

at a constant velocity, the acceleration of the box, a = 0

F(net) = 0

The net force is obtained from the applied force and force of friction;

Fcosθ - μmg = 0

where;

μmg  = Fcosθ

μ = Fcosθ / mg

μ = (485 x cos55) / (32.6 x 9.8)

μ = 0.87

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Velocity is a vector quantity and speed is a scalar quatity. This means that velocity changes with direction and speed does not.

What is speed and velocity?

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

Three examples were velocity and speed are same:

Three examples were velocity and speed are different:

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Answer: The rate at which an object moves towards a target is Speed

Explanation:

Rate is something that tells us amount of solmething that changes in one unit of time.

Speed is defined as the measure of the rate of movement of a body expressed either as the distance travelled divided by the time taken.

Arc is defined as the apparent path described above and below the horizon taken up by a celestial body.

Force is defined as a push or pull upon an object resulting from the object's interaction with another object.

Trajectory is defined as the path followed by an object moving under the action of given force.

Answer:

B, which is why ice skaters often keep their arms close to their body when doing spins and jumps to minimize resistance.

Answer:

x=6.39 m

Explanation:

Rectangular Components of a Vector

Vectors can be expressed in several forms, including the magnitude-angle form, and the rectangular-coordinates form.

If the magnitude r and angle β are given, we can find the rectangular coordinates (x,y) as follows:

\(x=r\cos\beta\)

\(y=r\sin\beta\)

The vector of the question has a magnitude of r=9.55 m and an angle β=-48°. The x-component is:

\(x=9.55\cdot\cos(-48^\circ)\)

Using a digital calculator:

x=6.39 m