Thus, the offset-ideal model assumes that the diodes have an offset voltage and an ideal forward voltage drop. The current flowing through the resistor in this circuit depends on the value of the resistor, which is not given.
The offset-ideal model assumes that the diodes have an offset voltage and an ideal diode forward voltage drop. In this case, there are 5 diodes in series, each with an offset voltage of 0.6 volts and an ideal forward voltage drop of 0.7 volts.
Therefore, the total voltage drop across the diodes is 5 x (0.6 + 0.7) = 6.5 volts.
To find the current flowing through the resistor, we need to use Ohm's law. Let's assume the resistor value is R ohms and the current flowing through it is I amps. The voltage drop across the resistor is the same as the voltage drop across the diodes, which is 6.5 volts.
Therefore, we can write:
6.5 = I x R
Solving for I, we get:
I = 6.5 / R
We don't have enough information to determine the value of R, so we cannot calculate the current flowing through the resistor. However, we do know that the current will be proportional to 1/R. That is, if the resistor value is decreased, the current will increase, and vice versa.
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A kilogram is a measure of an object's
O Gravity
O Weight
O length
O Mass
Answer:(d) mass
Explanation: The kilogram is the standard mass unit that is used almost globally and is the SI unit of mass. The kilogram weighs 9.8 Newtons under normal conditions on the surface of the Earth, and Newton is the corresponding SI unit of force and weight.
Explain in detail how educational institutions and personal ideology affect the influence of contemporary psychological
perspectives.
Answer:
Educational institutions can influence what psychological perspectives are taught, studied, and researched. Take, for example, behaviorism. Before the cognitive perspective re-emerged, behaviorism was the dominant perspective being taught in most universities. Personal ideology can also affect which perspective a psychologist supports, the course of research a psychologist undertakes, and also a psychologist's perception and interpretation of research findings. For example, during the dominance of behaviorism, psychologists were discouraged from studying cognitive processes. As a result, much of the research conducted had a behaviorist slant to it.
Explanation:
Question 6 of 10
What is the frequency of a wave that has a wavelength of 0.20 m and a speed
of 22 m/s?
A. 4.4 Hz
B. 110 Hz
C. 0.23 Hz
D. 0.001 Hz
Answer: Try A. 110 Hz
Explanation:
Answer:
i got 110 Hz..
Explanation:
A cliff diver horizontally runs off a 10 m high cliff at 10 m/s.
How far from the base of the cliff
does he land? (Round answer to nearest 10ths place)
Need help ASAP
In a certain right triangle, the two sides that are perpendicular to each other are 6.9 m and 5.5 m long. What is the length of the third side? Answer in units of m. What is the tangent of the angle for which 6.9 m is the opposite side?
Answer:
The length of the third side is
\(c =8.82 \ m \)
The tangent of the angle for which 6.9 m is the opposite side is
\(k = 1.256\)
Explanation:
From the question we are told that
The first side is a = 6.9 m
The second side is b = 5.5 m
Generally apply Pythagoras theorem
\(c^2 = a^2 + b^2\)
=> \(c = \sqrt{a^2 + b^2 }\)
=> \(c = \sqrt{6.9^2 + 5.5^2 }\)
=> \(c =8.82 \ m \)
From sin rule we have that
\(\frac{c}{sin(\theta )} = \frac{a}{sin (\beta )}\)
Generally from a right triangle the angle \(\theta = 90\)
So
\(\frac{8.82}{sin(90 )} = \frac{6.9}{sin (\beta )}\)
=> \(\beta = sin ^{-1}[\frac{6.9}{8.82} ]\)
=> \(\beta =51.47^o\)
Generally the tangent of the angle for which 6.9 m is the opposite side is mathematically represented as
\(k = tan (\beta )\)
\(k = tan (51.47 )\)
\(k = 1.256\)
From the data table below, which sample shows the largest decrease in average kinetic energy?
A small car collides head-on with a large SUV. Which of the following statements concerning this collision are correct?
A. Both vehicles are acted upon by the same average force during the collision.
B. The small car is acted upon by a greater average force than the SUV.
C. The small car undergoes a greater change in momentum than the SUV.
D. Both vehicles undergo the same change in momentum.
A small car collides head-on with a large SUV, both vehicles undergo the same change in magnitude of momentum.
The collision also called effect, in physics, is the unexpected, forceful coming together in direct contact of bodies, which includes, for an instance, billiard balls, a golf membership and a ball, a hammer and a nail head, railroad automobiles while being coupled together, or a falling item and a floor.
Physicists use collisions to determine the houses of atomic and subatomic debris. Essentially, a particle accelerator is a device that provides a managed collision system among subatomic debris so that, amongst other things, some of the houses of the target particle can be studied. The maximum common motive of an automobile collision is distracted use.
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The force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires. If a force of 0.750 N exists between wires that are 1.75 cm apart, what is the force between them if they are separated by 2.50 cm?
the force between the two wires if they are separated by 2.50 cm is 0.525 N.
Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.
Let the initial force be F₁ and the initial distance be d₁.
Therefore, we can write the relationship between force and distance as;
F₁d₁ = F₂d₂
Where
;F₁ = 0.750 N (initial force)
d₁ = 1.75 cm (initial distance)
F₂ = ? (force at new distance)
d₂ = 2.50 cm (new distance)
Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂
Now substitute the values we know;
F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N
Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.
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A motorboat sets out for open sea. From home it travels 5 km due East, then heads [N35E] at 2 m/s for 90 minutes. After a break, it travels South for 6.5 km. The captain is lost at sea. Where is the boat relative to home?
The distance of the motorboat relative to the home, which travels in various directions, is 3.07 km.
What is relative velocity?Relative velocity is a velocity of an object which is in respect to another observer, or it is a ratio of change in the position of a point to time with respect to another observer.
Given: Travel in East direction (\(d_{E}\))= 5 km,
velocity in N35E(v) = 2 m / s, time taken(t) = 90 min = 5400 seconds,
Displacement in south (\(D_S}\)) = 6.5 km
Firstly, find the displacement in N35E so
Displacement = Velocity × time,
\(d_{NE}\) = 2 × 5400 = 10800 meters or 10.8 km
Now by using Pythagoras' theorem
We can calculate the return displacement in the south direction(\(d_{S}\)),
\(d_{S}\) = \(\sqrt{d^{2} _{NE}- d^{2} _{E } }\)
\(d_{S}\) = \(\sqrt{10.8^{2}-5^{2} }\)
\(d_{S}\) = 9.57 km
Therefore, the distance of the boat from the home (D) = \(d_S}\) - \(D_S}\)
D = 9.57 - 6.5;
D = 3.07 Km
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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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Which of these best describes what happens when a ball hits the sweet spot (node) of a bat?
Group of answer choices
Most of the energy from the swinging of the bat is transferred to the ball.
Much of the energy of the ball hitting the bat is turned into oscillating the bat.
The waves created when the ball hits the bat and bounces off make the bat oscillate.
The bat breaks.
Answer:
The first option, energy is transferred.
Explanation:
Can I answer my own question
Answer:
Well okay do it what's your question ?
Answer:
yes
Explanation:
is the acceleration of a fluid particle necessarily zero in steady flow? explain.
No, the acceleration of a fluid particle is not necessarily zero in steady flow. In steady flow, the fluid properties at any point in the fluid remain constant over time, meaning that the fluid flow rate, velocity, and pressure do not change with time.
However, this does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. According to the continuity equation of fluid mechanics, the rate of fluid flow through any given area in the flow must remain constant in steady flow.
This means that if the cross-sectional area of a pipe carrying fluid decreases, the fluid velocity must increase to maintain a constant flow rate. As the fluid velocity changes, the acceleration of individual fluid particles can also change in response to the changing velocity.
In addition, the Navier-Stokes equations, which describe the motion of fluid particles, include terms for acceleration, which can be non-zero in steady flow if the fluid velocity is changing at a given point.
Therefore, even in steady flow, the acceleration of a fluid particle can be non-zero if there is a change in the fluid velocity at a given point. In summary, while steady flow implies that the fluid properties do not change over time.
It does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. The acceleration can be non-zero if there is a change in the fluid velocity at a given point.
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I NEED SOMEONE TO HELP ME WITH THIS ONE PLEASE!!
-Car A that has a mass of 2000 kg is moving at 8 m·s-1 to the west. It collides with Car B that has a mass of
4000 kg moving at 1 m-s-1 to the east. Calculate the velocity of car B, if car A moves with a velocity of 4 m.s-1
After the collision.
Explanation:
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816 3823 4736
227UHQ
A clean nickel surface is exposed to light with a wavelength of 227 nm . The photoelectric work function for nickel is 5.10 eV .
What is the maximum speed of the photoelectrons emitted from this surface?
The velocity at which the photoelectrons are emitted from the nickel surface reaches a maximum value of 5.08 × 10⁵ m/s.
How to calculate maximum photoelectron speed?To calculate the maximum speed of the photoelectrons emitted from the nickel surface, we can use the following formula:
maximum kinetic energy = hν - Φ
where h is Planck's constant, ν is the frequency of the light, and Φ is the work function of the nickel.
First, we need to convert the wavelength of the light from nanometers to meters:
227 nm = 227 × 10⁻⁹ m
Next, we can use the formula for the speed of light to find the frequency of the light:
c = νλ
where c is the speed of light and λ is the wavelength of the light.
ν = c / λ = 3.00 × 10⁸ m/s / (227 × 10⁻⁹ m) = 1.32 × 10¹⁵ Hz
Now, we can calculate the maximum kinetic energy of the photoelectrons:
maximum kinetic energy = hν - Φ = (6.63 × 10⁻³⁴ J s)(1.32 × 10¹⁵ Hz) - (5.10 eV)(1.60 × 10⁻¹⁹ J/eV) = 1.01 × 10⁻¹⁸ J
Finally, we can use the formula for the maximum kinetic energy of a photoelectron to find its maximum speed:
maximum speed = √(2Kmax / m)
where Kmax is the maximum kinetic energy and m is the mass of an electron.
maximum speed = √(2(1.01 × 10⁻¹⁸ J) / (9.11 × 10⁻³¹ kg)) = 5.08 × 10⁵ m/s
Therefore, the maximum speed of the photoelectrons emitted from the nickel surface is 5.08 × 10⁵ m/s.
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.- Una esfera hueca de acero a 28°C tiene un volumen de 0.4 m³, calcular a) ¿qué volumen final tendrá a -6°C en m³ y en litros? B) ¿Cuánto disminuyó su volumen en litros?
Answer:
Ve respuesta abajo.
Explanation:
Para hacer esto, podemos asumir que la presión es constante, pues es un proceso adiabatico, por tanto se aplica la ley de Charles a presión constante:
V₁/T₁ = V₂/T₂ (1)
De ahí podemos despejar V₂, ya que conocemos las condiciones iniciales de temperatura y volúmen, y la temperatura final:
V₂ = V₁ T₂ / T₁ (2)
Las temperaturas deben estar en grados Kelvin, y solo es cuestión de sumarle 273 al valor de la temperatura dada en °C:
T₁ = 28 + 273 = 301 K
T₂ = -6 + 273 = 267 K
El volúmen podemos pasarlo a litros ahora o al final. En este caso, podemos dejarlo en m³ como está y luego pasarlo a Litros. Resolviendo tenemos:
V₂ = 0.4 * 267 / 301
V₂ = 0.35482 m³Pasando este volumen a Litros, sabiendo que 1 m³ son 1000 L:
V₂ = 0.35482 * 1000
V₂ = 354.82 LFinalmente para saber cuanto disminuyó el volumen en Litros, pasemos el volumen inicial a Litros y luego se hace la resta con el volumen final:
V₁ = 0.4 * 1000 = 400 L
V₁ - V₂ = 400 - 354.82
V₁ - V₂ = 45.18 LEsto es lo que disminuyó. Espero te ayude.
Psychology:
Retrograde amnesia is the memory loss of events that occurred after the onset of amnesia.
True or False
It’s false.
Answer:
thank you
Explanation:
Answer:
False is correct
Explanation:
Peace and Love
when stopping for a train, stop at least ______ feet away from the tracks. drivers ed
"When stopping for a train, stop at least 15 feet away from the tracks."
When there is a stop sign at a railway crossing, the driver must stop completely between five and fifteen metres (50 and 50 feet) away from the nearest rail. Until you are certain that no trains are coming, do not move forward.
At many rail crossings, red light signals are combined with railroad signs. When the bells start to ring and the lights start to flash, stop because a train is coming. The driver of the car closest to the crossing must come to a complete stop at least five metres away from the nearest rail. Continue only until the train has past or has completely stopped, the lights, bells, and the train itself have all ceased. Make sure all the tracks are clear before crossing if there are multiple tracks.
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If a force of 10 N stretches a spring 0.5 m, what is the spring constant?
Answer:
the spring would be a constant of 10.5 m
Find the net force acting on a box that has a force of 50 newtons pulling at an angle of 30 degrees and a force of 90 newtons pulling at a 160 degree angle
Answer:
Approximately \(69\; {\rm N}\) at approximately \(126^{\circ}\).
Explanation:
Assume that both angles in the question are relative to the positive \(x\)-axis (towards the positive horizontal direction.)
Horizontal component (\(x\)-component) of the two forces would be:
\((50\; {\rm N}) \, \cos(30^{\circ}) = \left(25\, \sqrt{3}\right)\; {\rm N} \approx 43.3\; {\rm N}\).\((90\; {\rm N}) \, \cos(160^{\circ}) \approx (-84.6) \; {\rm N}\).Note that the \(x\)-component of the \(90\; {\rm N}\) force is negative since this components points away from the positive \(x\!\)-direction.
Hence, the net force in the \(x\)-component would be:
\((50\; {\rm N}) \, \cos(30^{\circ}) + (90\; {\rm N}) \, \cos(160^{\circ}) \approx (-41.3) \; {\rm N}\).
(Again, this component is negative since it points away from the positive \(x\)-axis.)
Similarly, the vertical component (\(y\)-component) of the two forces would be:
\((50\; {\rm N}) \, \sin(30^{\circ}) = 25\; {\rm N}\).\((90\; {\rm N}) \, \sin(160^{\circ}) \approx 30.8 \; {\rm N}\).Hence, the net force in the \(y\)-component would be:
\((50\; {\rm N}) \, \sin(30^{\circ}) + (90\; {\rm N}) \, \sin(160^{\circ}) \approx 55.8\; {\rm N}\).
Refer to the diagram attached. The resultant net force is the vector sum of the components. Apply the Pythagorean Theorem to find this net force:
\(\begin{aligned}(\text{net force}) &= \sqrt{(\text{$x$-component})^{2} + (\text{$y$-component})^{2}} \\ &\approx \sqrt{(-41.3)^{2} + (55.8)^{2})}\; {\rm N} \\ &\approx 69\; {\rm N}\end{aligned}\).
Find the angle of this net force relative to the positive \(x\)-axis using the inverse cosine function \(\arccos\):
\(\begin{aligned}\arccos\left(\frac{(\text{$y$-component})}{(\text{net force})}\right) &\approx \arccos\left(\frac{55.8\; {\rm N}}{69\; {\rm N}}\right) \\ &\approx 126^{\circ}\end{aligned}\).
(The units might need to be converted into degrees.)
Determine the horizontal displacement of a projectile if it has a flight time of 8 seconds and a horizontal velocity of 14 m/s
\(\\ \rm\bull\rightarrowtail Displacement=Velocity\times Time\)
\(\\ \rm\bull\rightarrowtail Displacement=8(14)\)
\(\\ \rm\bull\rightarrowtail Displacement =112m\)
A bicyclist is traveling at +25m/s when he begins to decelerate at -4m/s2. How fast is he traveling after 5 seconds
Answer:
+5m/s
Explanation:
When doing the math we figure out that e is going to be slowing down at -4m/s² for 5 seconds. In total he is slowing down -20m/s which we take from the total speed of +25m/s to get his current new speed.
24) A 0.042-kg pet lab mouse sits on a 0.35 kg air-track cart. The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of u1=0.88m/s. What is the speed v2 of the mouse and the 0.25-kg cart? |
The mass of the mouse, m₁=0.042 kg
The mass of the 1st cart, m₂=0.35 kg
The mass of the second cart, m₃=0.25 kg
The speed of the 1st car after the jump, u₁=0.88 m/s
From the law of conservation of momentum, the momentum of a system should always remain the same.
Before the mouse jumps from one cart to another, all the objects were at rest. Therefore the total momentum of the system was zero.
Thus after the mouse jumps, the total momentum of the system should be equal to zero.
Thus the momentum of the second cart and the mouse will be equal in magnitude to the momentum of the first cart but it will be in the opposite direction.
Thus,
\(m_2u_1=(m_1+m_3)v_2\)On substituting the known values,
\(\begin{gathered} 0.35\times0.88=(0.042+0.25)v_2 \\ \Rightarrow v_2=\frac{0.35\times0.88}{(0.042+0.25)} \\ =1.05\text{ m/s} \end{gathered}\)Thus the speed of the mouse and the second cart after the mouse jumps is 1.05 m/s
What is total internal reflection?
Answer:
When a ray of light, passes from a denser to a rarer medium with the angle of incidence greater than the critical angle, the ray is reflected back into the same medium. This phenomenon is call total internal reflection.
What is the kinetic energy of Usain Bolt if he has a mass of 80 kg and is sprinting at 10 m/s?
Answer: The kinetic energy of Usain Bolt, who has a mass of 80 kg, is 4000 Joules.
Explanation:
What is the kinetic energy of Usain Bolt if he has a mass of 80 kg and is sprinting at 10 m/s?
Data:
m = mass = 80 kg
V = velocity = 10m/s
Ec = Kinetic energy = ?
To calculate the kinetic energy of Usain Bolt, we apply the following formula, substitute data and solve:
Ec = m * v²/2 Ec = (80 kg * (10 m/s)²)/2 Ec = (80 * 100 m²/s²)/2 Ec = 4000 JTo learn at https://brainly.com/question/15579795To learn at https://brainly.com/question/14165786Formula for Kinetic Energy:
\(KE=.5mv^2\)
kinetic energy(measured in joules) = .5 * mass(measured in kg) * velocity(measured in m/s)^2
__________________________________________________________
Given:
\(m=80kg\)
\(v=10m/s\)
\(KE=?\)
__________________________________________________________
Finding kinetic energy:
\(KE=.5mv^2\)
\(KE=.5(80)(10)^2\)
__________________________________________________________
Answer:
\(\fbox{4000 Joules}\)
which of the following causes low lung compliance as a result of last of electrical lung tissue destruction
Interstitial lung disease is low lung compliance as a result, last of electrical lung tissue destruction.
Interstitial lung disorders brought on by breathing in particles like silicon and asbestos (asbestosis) can cause low lung compliance (silicosis).
Lungs and the pleural cavity have the capacity to expand and contract in response to variations in pressure. Lung compliance, which is a key determinant of lung health and function, is defined as the volume change per unit of pressure change across the lung. Lung compliance varies between inhalation and expiration because measurements of lung volumes vary between the two at the same pressure. Depending on whether only volume and pressure are measured (static) or whether their variations over time are also recorded, lung compliance can be classified as either static or dynamic.
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How do astronomers measure the mass that the galaxy contains inside the orbit of the sun?.
The degree mass of many different spiral galaxies close by after which takes a median. They add up all the observations at 21-cm wavelengths because the mass of hydrogen gas is some distance greater than the mass in all of the stars.
Astronomers have four simple techniques to degree the hundreds of galaxies and clusters: rotation curves, random velocities, X-ray emission, and gravitational lensing. Rotation curves: In astronomy, we often infer loads from orbits.
Because it's impossible to weigh a galaxy virtually by way of searching at it tons less when the observer occurs to be inner of it, as is the case with our Milky way researchers deduce a galaxy's mass by means of analyzing the motions of celestial gadgets as they dance across the host galaxy, led by using its gravitational pull.
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explain about ohm's law.
Answer:
Statement:
The electric current passing through a conductor is directly proportional to the potential difference across its ends provided temperature and other physical conditions remain constant.
Explanation:
Current is directly proportional to voltage loss through a resistor. That is, if the current doubles, then so does the voltage. To make a current flow through a resistance there must be a voltage across that resistance. Ohm's Law shows the relationship between the voltage (V), current (I) and resistance (R).
V∝I or I∝V⇒V=IR.
Explanation:
Ohm's law states that the current through a conductor is proportional to the voltage across the conductor. This is true for many materials (including metals) provided the temperature (and other physical factors) remain constant. The constant of proportionality, R,R is the resistance and the unit is the ohm, with symbol \Omega,Ω. The relationship can be written as:
V, equals, I, R.
V=IR
where V,V is the voltage across the conductor and I,I is the current flowing through it. If a component is ohmic (it obeys Ohm's Law), then its resistance must be independent of current and voltage.
Give Example of mental flexibility
Answer:
If you ring the doorbell and no one opens the door, you'll infer that no one is home rather than continuing to ring the doorbell to an empty house. Being able to understand this and look for another solution is another example of mental flexibility.
Explanation:
¿Cuántos culombios de carga entran en un 1,80 cm longitud del axón durante este proceso? Exprese su respuesta en nanoculombios
En un axón de 1,80 cm de longitud, entran 1,8 nanoculombios de carga durante el proceso.
La respuesta se obtiene al convertir la longitud del axón de centímetros a metros (1,80 cm = 0,018 m) y luego multiplicarla por la carga específica de un culombio (1 C). El resultado se expresa en nanoculombios (1 C = 10^9 nC). Por lo tanto, el cálculo sería: 0,018 m x 1 C x 10^9 nC/C = 1,8 nC.
El axón es una estructura que forma parte del sistema nervioso y se encarga de transmitir señales eléctricas a lo largo de su longitud. La carga eléctrica fluye a través del axón durante este proceso, y la cantidad de carga que entra se puede expresar en culombios. Al convertir la longitud del axón a metros y multiplicarla por la carga específica de un culombio, obtenemos la cantidad de carga en culombios. Para expresar esta cantidad en unidades más pequeñas, como el nanoculombio, se multiplica por 10^9. Por lo tanto, en un axón de 1,80 cm de longitud, entran 1,8 nanoculombios de carga durante el proceso.
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