Make a motion chart for a cannonball launched with an initial speed of 20m/s. Neglect drag and the initial height of the cannonball. After the ball lands on the ground enter zero for all speeds and heights if necessary. Use regular metric units (ie. Meters).

A ball is thrown vertically upward from the surface of the earth. both velocity and speed will become zero at highest point. so correct option is c. 1 and 2

Speed is a scalar quantity and velocity is a vector. Speed only determines the magnitude that is how fast is a body moving whereas velocity determines the direction also that is in which direction the body is moving. Speed is the rate of change of distance whereas velocity is the rate of change of displacement.

Velocity is a measure of how fast something moves in a particular direction. To define it needs both magnitude and direction.

At highest point acceleration is not zero because we have acc due to gravity acting downwards.But since velocity and speed is zero the ball reaches the ground back

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The two masses are accelerating toward each other at a rate of approximately 7.78 m/s² when they pass each other.

When solving this problem, we can consider the system as a whole and apply Newton's second law to determine the acceleration. The tension in the cord is the same on both sides of the pulley. Let's denote the tension as T. For the 15 kg mass, the net force acting on it is T - (15 kg * g), where g is the acceleration due to gravity. For the 3.2 kg mass, the net force acting on it is (3.2 kg * g) - T. Since the masses are connected by a cord passing over the pulley, their accelerations are equal in magnitude but opposite in direction.

We can set up the following equations:

T - (15 kg * g) = (15 kg * a)    (1)

(3.2 kg * g) - T = (3.2 kg * a)    (2)

Simplifying equation (1), we get T = (15 kg * g) + (15 kg * a)

Substituting this value into equation (2), we have (3.2 kg * g) - [(15 kg * g) + (15 kg * a)] = (3.2 kg * a)

Simplifying further, we find:

3.2 kg * g - 15 kg * g - 15 kg * a = 3.2 kg * a

-11.8 kg * g = 18.2 kg * a

Finally, solving for a:

a = (-11.8 kg * g) / (18.2 kg) ≈ -7.78 m/s²

The negative sign indicates that the acceleration is directed toward the left. The magnitudes of the accelerations of both masses are the same, so when they pass each other, they are accelerating toward each other at a rate of approximately 7.78 m/s².

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The two masses are accelerating toward each other at a rate of approximately 7.78 m/s² when they pass each other.

When solving this problem, we can consider the system as a whole and apply Newton's second law to determine the acceleration. The tension in the cord is the same on both sides of the pulley. Let's denote the tension as T. For the 15 kg mass, the net force acting on it is T - (15 kg * g), where g is the acceleration due to gravity. For the 3.2 kg mass, the net force acting on it is (3.2 kg * g) - T. Since the masses are connected by a cord passing over the pulley, their accelerations are equal in magnitude but opposite in direction.

We can set up the following equations:

T - (15 kg * g) = (15 kg * a)    (1)

(3.2 kg * g) - T = (3.2 kg * a)    (2)

Simplifying equation (1), we get T = (15 kg * g) + (15 kg * a)

Substituting this value into equation (2), we have (3.2 kg * g) - [(15 kg * g) + (15 kg * a)] = (3.2 kg * a)

Simplifying further, we find:

3.2 kg * g - 15 kg * g - 15 kg * a = 3.2 kg * a

-11.8 kg * g = 18.2 kg * a

Finally, solving for a:

a = (-11.8 kg * g) / (18.2 kg) ≈ -7.78 m/s²

The negative sign indicates that the acceleration is directed toward the left. The magnitudes of the accelerations of both masses are the same, so when they pass each other, they are accelerating toward each other at a rate of approximately 7.78 m/s².

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Velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

This is a which have both magnitude and direction. Example include:

This is a quantity which has magnitude but no direction. Example include:

From the above, we can see that velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

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The size of the image is determined by the distance between the object and the mirror (object distance) and the distance between the mirror and the screen (image distance).

Using the formula for image distance (1/f = 1/object distance + 1/image distance), we can find the focal length of the mirror:

1/f = 1/object distance + 1/image distance (twice the object size)

1/f = 1/object distance + 2

1/f = 1/object distance + 1/image distance (three times the object size)

1/f = 1/object distance + 3

We know that the image distance (the distance from the mirror to the screen) is 75 cm in both scenarios, so we can set up the equations using that information:

1/f = 1/object distance + 2 (twice the object size)

75 = 2 * object distance + f

1/f = 1/object distance + 3 (three times the object size)

75 = 3 * object distance + f

Solving for object distance in the first equation:

object distance = (75 - f) / 2

Substituting that into the second equation:

75 = 3 * ((75 - f) / 2) + f

Simplifying and solving for f:

75 = (225 - 3f) / 2 + f

150 = 225 - 3f

3f = 75

f = 25 cm

So the focal length of the mirror is 25 cm.

To find the distance the object is moved, we can use the equation for object distance:

object distance = (75 - f) / 2

object distance = (75 - 25) / 2

object distance = 25 cm

So, the object is moved 25 cm in the process.

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Answer:

D. 90 degrees

Explanation:

just finished lab

The statement 'Not all metals have the same current for a given electric potential' is TRUE. It is conductivity.

All the metals are able to conduct electric currents, but some metals have a higher conductivity.

Metals are able to conduct electric currents due to the free movement of negatively charged particles i.e., electrons, across the conductor.

The band theory of metals states that metals can conduct electrons (e-) in an electric current by means of the help of the e- valence.

The density of free electrons in metals is around 10^28 m-3, which indicates the number of states at a particular energy level that negative e- can occupy.

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In summary, sending only the progress notes related to the treatment of rhinitis and copies of sinus x-rays to the ENT specialist's office is an example of selective information transfer, allowing the specialist to focus on the specific condition being addressed.

The situation described is an example of selective information transfer between healthcare providers. Katie is going to an ENT specialist for her seasonal allergies, specifically for the treatment of rhinitis. In this case, only the progress notes related to the treatment of rhinitis and copies of sinus x-rays are being sent to the specialist's office.

This selective transfer of information is done to ensure that the specialist receives only the relevant medical records for the specific condition being addressed. By sending only the progress notes pertaining to the treatment of rhinitis and the sinus x-rays, the specialist can focus on evaluating and treating the specific condition, without being overwhelmed by unnecessary information.

This practice is common in healthcare settings where multiple specialists may be involved in a patient's care. By sending only the relevant information, it helps streamline the communication between healthcare providers and ensures that each provider receives the necessary information to make informed decisions regarding the patient's treatment.

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Gamma-ray bursts are intense flashes of high-energy radiation that come from various sources in the universe. These bursts are short-lived, lasting only a few seconds to a few minutes, and emit more energy in that brief time than our sun will in its entire lifetime.

The majority of gamma-ray bursts come from the distant reaches of space, beyond our own Milky Way galaxy. Scientists believe that most of these bursts are caused by the collapse of massive stars, which create black holes or neutron stars. These events, known as supernovas, release huge amounts of energy in the form of gamma rays.
However, there are also other types of gamma-ray bursts that come from different sources, such as merging neutron stars or even collisions between galaxies. Some gamma-ray bursts have also been detected coming from our own Milky Way, likely caused by the explosive deaths of massive stars.

In summary, gamma-ray bursts come from a variety of sources in the universe, but the majority are caused by the collapse of massive stars into black holes or neutron stars.
Gamma-ray bursts (GRBs) tend to come from two primary sources in the universe. They are extremely energetic and short-lived bursts of gamma-ray light, the most energetic form of electromagnetic radiation.

1. Long-duration GRBs: These bursts typically last from a few seconds to several minutes and are believed to originate from the collapse of massive stars. When a massive star reaches the end of its life, its core collapses into a black hole or a neutron star. This process, known as a core-collapse supernova, releases a tremendous amount of energy in the form of gamma rays. The resulting jet of energy is called a long-duration gamma-ray burst.

2. Short-duration GRBs: These bursts usually last less than two seconds and are thought to result from the merger of two compact objects, such as neutron stars or a neutron star and a black hole. When these objects collide, they release a vast amount of energy in the form of gamma rays, producing a short-duration gamma-ray burst.

Both types of gamma-ray bursts are observed at vast distances across the universe, indicating that they come from diverse cosmic environments. These powerful events serve as important probes of the early universe and can provide valuable information about star formation, cosmic evolution, and the nature of matter under extreme conditions.

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2. A new substance forms

Chemical changes change composition, physical never do.

Hope This Helps, Good Luck!

Answer:

2: A new substances forms

Explanation:

Answer:

Explanation:

See attachment.

Decreasing the mass of the objects   No.  Force will change.

Increasing the temperature of the objects Yes,  No change in force (at most a very small change if the heat causes excessive expansion, reducing the distance, although 1/2 will be further apart)

Increasing the distance between the objects No.  Force will change.

Decreasing the distance between the objects  No.  Force will change.

To determine the proton's speed in the laboratory frame, we need to find the magnitude of its velocity vector in the laboratory frame.

The velocity of the rocket is given as 0.900×10^6 m/s in the positive x-direction. The velocity of the proton in the laboratory frame is given as v⃗ =(1.55×10^6i^ + 1.55×10^6j^) m/s.

To find the proton's speed, we need to calculate the magnitude of its velocity vector:

|v⃗| = sqrt(vx^2 + vy^2)

where vx and vy are the x and y components of the velocity vector, respectively.

Substituting the given values:

|v⃗| = sqrt((1.55×10^6)^2 + (1.55×10^6)^2) m/s

|v⃗| = sqrt(2.4025×10^12 + 2.4025×10^12) m/s

|v⃗| = sqrt(4.805×10^12) m/s

|v⃗| ≈ 2.191×10^6 m/s

Therefore, the proton's speed in the laboratory frame is approximately 2.191×10^6 m/s.

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Explanation:

because conduction takes place in objects whose particles are close/touching each other therefore conduction happens in solid as liquid and gas paricles are not close to each other

The energy of engine absorb from the hot reservoir in each cycle is  (9,100 J/s) / 0.21.  4500 J / (9,100 J/s) .The time is required to complete one cycle is  4500 J / (9,100 J/s).

(A) To determine the amount of energy absorbed by the engine from the hot reservoir in each cycle, we can use the equation for efficiency. The efficiency of the heat engine is given by the ratio of the useful work output to the energy input from the hot reservoir:

Efficiency = (Useful Work Output) / (Energy Input)

In this case, the efficiency is given as 21%, which can be expressed as 0.21. The power output of the engine is 9.1 kW. We can convert this to joules per second (J/s) by multiplying by 1000:

Power Output = 9.1 kW = 9,100 J/s

Now, we can rearrange the efficiency equation to solve for the energy input:

Energy Input = (Useful Work Output) / Efficiency

Energy Input = (9,100 J/s) / 0.21

Calculating this expression gives us the amount of energy the engine absorbs from the hot reservoir in each cycle.

(B) To determine the time required to complete one cycle, we can use the relationship between power and energy. Power is defined as the rate at which energy is transferred or transformed. In this case, we know the power output of the engine is 9.1 kW. To find the time, we need to divide the total energy wasted in each cycle (4500 J) by the power output:

Time = Energy Wasted / Power Output

Time = 4500 J / (9,100 J/s)

By evaluating this expression, we can find the time required to complete one cycle in seconds.

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The average electric power consumption of the electric-powered snow-thrower machine is 48.6 watts.

First, let's calculate the power required to throw one snowball. We know that the machine throws snowballs at a speed of 9 m/s and each snowball weighs 0.3 kg. The kinetic energy of a snowball can be calculated using the formula KE = (1/2)mv^2, where m is the mass and v is the velocity.

Using this formula, the kinetic energy of one snowball is:

KE = (1/2) * 0.3 kg * (9 m/s)^2 = 12.15 J

Now, since the machine throws 2 snowballs per second, the power required to throw these snowballs can be calculated by dividing the total kinetic energy by the time taken to throw the snowballs. In this case, the time taken to throw 2 snowballs is 1 second.

So, the power required to throw 2 snowballs is:

Power = (Total kinetic energy) / (Time taken) = (2 * 12.15 J) / 1 s = 24.3 W

However, we also need to consider the efficiency of the machine. The efficiency is given as 50%. Efficiency is defined as the ratio of useful output energy to the input energy.

Since the efficiency is 50%, only 50% of the electrical energy is converted into kinetic energy. Therefore, the actual power consumption of the machine can be calculated by dividing the power required by the efficiency:

Actual Power Consumption = (Power required) / (Efficiency) = 24.3 W / 0.5 = 48.6 W

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It would take 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.

To calculate the time required to crumple the barrier and safely slow down the person, we can use the concept of impulse.

The impulse, denoted by J, is defined as the product of force and time, and it represents the change in momentum of an object. In this case, the impulse required to safely slow down the person can be calculated using the maximum force and the person's initial momentum.

The momentum of a person is given by the product of their mass and velocity:

Momentum = mass × velocity

Given that the person's mass is 68 kg and their velocity is 27 m/s, the initial momentum is:

Initial momentum = 68 kg × 27 m/s

To safely slow down the person, the impulse provided by the barrier should be equal to the change in momentum.

Therefore, we have:

Impulse provided by barrier = Final momentum - Initial momentum

Since the person is brought to rest, the final momentum is zero. Thus, we have:

Impulse provided by barrier = -Initial momentum

Now we can express the impulse in terms of force and time:

Impulse provided by barrier = Force × Time

Plugging in the known values, we can solve for time:

-Initial momentum = Force × Time

68 kg × 27 m/s = 1180 N × Time

Simplifying the equation, we find:

Time = (68 kg × 27 m/s) / 1180 N

Evaluating the expression:

Time = 1836 kg·m/s / 1180 N

Finally, converting kg·m/s to seconds, we get:

Time ≈ 1.5559 seconds

Therefore, it would take approximately 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.

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Answer:

If the kinetic energy increases, the potential energy decreases, and vice-versa.

Explanation:

The amount of change in kinetic energy is equal to the amount of change in potential energy.

Answer:

C

Explanation:

three bricks means 3 times the weight, so 6/3=2

The estimated demand for Week 4 is 36.3

MAD(Mean Absolute Deviation) is used to calculate the average difference between forecast values and actual values. It calculates the deviation by taking the absolute value of the difference between actual and forecasted demand. The formula to calculate Mean Absolute Deviation is:

MAD= Sum of| Actual demand - Forecast demand | / number of periods

In the given table, the Actual demand is shown as B and the forecast demand is shown as F.

B Actual Forecast 11 40 41 35 38 3 38 35 33 30

Calculation of MAD:

Actual (B) Forecast (F) |B-F|11 40 29.041 35 5.043 38 0.053 3 35.054 38 3.055 35 0.056 33 3.057 30 3.058 0.0 30.0Total 103.0

The number of periods is 9 as shown in the table.

MAD= 103/9MAD= 11.44

Mean Squared Error (MSE) measures the average squared difference between the actual and forecasted values. The formula for MSE is:

MSE= Sum of (Actual demand - Forecast demand)^2 / number of periods.

Calculation of MSE:

Actual (B) Forecast (F) (B-F)^2 11 40 841 35 25 625 38 0 0 3 35 484 38 0 0 35 33 4 30 0 900Total 2854

The number of periods is 9 as shown in the table.

MSE= 2854/9MSE= 317.1

Therefore, the calculated MAD is 11.44 and MSE is 317.1.

Trend Projection formula is given by:

Y = a + bx

where Y is the estimated demand for a particular period.

a is the Y-intercept

b is the slope of the regression line x is the period number

In the given table, the Week number is shown as X and the Actual demand is shown as Y.

Week number Actual Demand 11 24 22 29

Using trend projection for Week 3, we can calculate the demand as follows:

Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*22 - 1*24)/(2*3 - 1*1) = 20/5 = 4

Intercept (a) = Σy/n - b(Σx/n) =(24+22)/2 - 4(2/2) = 23Y = a + bx = 23 + 4(3) = 35

Therefore, the estimated demand for Week 3 is 35.

Using trend projection for Week 4, we can calculate the demand as follows:

Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*29 - 1*24)/(2*5 - 1*1) = 34/9 = 3.78

Intercept (a) = Σy/n - b(Σx/n) =(24+22+29)/3 - 3.78(2.0) = 21.5Y = a + bx = 21.5 + 3.78(4) = 36.3

Therefore, the estimated demand for Week 4 is 36.3.

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Answer:

I am pretty sure it is A!

:D

The air is warmer near Earth's surface because warm air is denser and sits on top of the Earth's surface. The correct option is B.

The mass of the air per unit volume is known as the air density. Its unit is kg/m³.

Due to the lower pressures in the air above, air expands when it rises. cooling air expands.

The hottest temperatures in the troposphere are often found at the earth's surface because the sun heats the atmosphere predominantly from the surface and because the air cools as it ascends.

Because warm air is denser and lies on top of the surface of the Earth, it is warmer near the surface of the earth.

Hence, the correct option is B.

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The net force on particle q3 is -3.49 x 10^-3 N.

The net force on particle q3 can be calculated by considering the electric forces between q3 and each of the other particles, and then adding them vectorially. The electric force between two charged particles can be calculated using Coulomb's law:

\(F = k * |q1 * q2| / r^2\)

where k is Coulomb's constant (8.9875 x 10^9 N * m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the separation between the charges.

First, let's calculate the electric force between q3 and q2:

\(F12 = k * |-84.2 uC * 90.6 uC| / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 uC^2) / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 x 10^-6 C^2) / (0.432 m)^2\\= 3.05 x 10^-3 N\)

Next, let's calculate the electric force between q3 and q1:

\(F13 = k * |-84.2 uC * -75.8 uC| / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 uC^2) / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 x 10^-6 C^2) / (0.876 m)^2\\= -6.54 x 10^-3 N\)

Finally, the net force on particle q3 is given by the vector sum of the individual forces:

Fnet = \(F12 + F13 = 3.05 x 10^-3 N - 6.54 x 10^-3 N = -3.49 x 10^-3 N\)

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Answer:

5.5 rad/sec

Explanation:

Answer:

5.47 rad/s

Explanation:

We can solve this problem using the principle of conservation of energy and angular momentum.

First, let's find the initial kinetic energy of the projectile:

K1 = (1/2) * m * v1^2

= (1/2) * 0.2 kg * (50 m/s)^2

= 250 J

where v1 is the initial velocity of the projectile.

Next, let's find the final kinetic energy of the projectile:

K2 = (1/2) * m * v2^2

= (1/2) * 0.2 kg * (-25 m/s)^2

= 67.5 J

where v2 is the final velocity of the projectile after the collision.

The loss of energy in the collision is:

ΔK = K1 - K2

= 187.5 J

This energy is transferred to the blades, causing them to spin. Let's assume that all of this energy is converted to rotational kinetic energy of the turbine.

The final rotational kinetic energy of the turbine is:

K_rot = (1/2) * I * ω^2

where I is the moment of inertia of the turbine and ω is the final rotational velocity of the turbine.

Using the conservation of energy, we can equate the loss of kinetic energy in the collision to the gain in rotational kinetic energy of the turbine:

ΔK = K_rot

187.5 J = (1/2) * 12.5 kg m^2 * ω^2

ω^2 = (2 * 187.5 J) / (12.5 kg m^2)

ω^2 = 30

ω = 5.47 rad/s

Therefore, the rotational velocity of the turbine after the collision is 5.47 rad/s.

Answer:

The height of the apple from the ground is at 49552.61071 m or is approximately at 5.0 × 10 m

Explanation:

Answer:

It would be. Quarter dark

Explanation:

Sun's lights going all the way to the moon but there will still a dark part of it

it's obviously won't be neither complete light nor completely dark

so the right answer is: Quarter dark

Answer:

The term "scientific methods" are more accurate than "scientific method" because "s" used in "scientific methods" makes the word plural and science experiments use several observations to get a result and not only based on single observation.

So, "scientific methods" is a plural term that is more accurate than "scientific method".

When an object rolls without slipping down an inclined plane, the true statement(s) about static friction force are: It provides the torque to cause the angular acceleration and it goes against gravity to reduce the acceleration caused by gravity. The correct answer is B and E.

Friction is the force that opposes relative motion between surfaces in contact. It is also called a contact force because it operates between the surfaces in contact when they're in motion or when a force tries to move them relative to one another.

An inclined plane is a simple machine that consists of a sloping surface that connects a lower point to a higher point. It is one of the six classical simple machines that is used to reduce the effort needed to raise a weight to a certain height.

Rolling without slipping is a combination of translational motion (movement in a straight line) and rotational motion (movement around an axis) without any slipping occurring between the surfaces in contact. A wheel or any other circular object rolls without slipping when its forward motion is the same as its rotational motion.

Static friction is the force that keeps an object at rest or in a state of uniform motion on a surface when a force is applied on it. When two surfaces are in contact, static friction is the force required to overcome the sticking between them that resists motion.

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Theta = position angle, t = time, and w = angular velocity, where w = angular velocity, theta = position angle, and t = time. Angular velocity is the rate of change of an object's position angle with respect to time.

Thus, An object's rate of rotation and direction of rotation are both described by its angular velocity.

It is customary for the positive direction to be in the counterclockwise direction. Here are some angular velocity issues for practice. The ratio of the angular displacement () to the time of motion, for a constant angular velocity, is the angular velocity.

Angular velocity only applies to things that are moving in a circular motion, making it less frequent than linear velocity.

A racecar on a circular track, a roulette ball on a wheel, or a Ferris wheel are a few examples of objects with angular motion.

Thus, An object's rate of rotation and direction of rotation are both described by its angular velocity.

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Answer:

(a) Let the height of the platform is h meter,

=>By s = ut + 1/2gt^2

=>h = 0 + 1/2 x 9.8 x (2.3)^2

=>h = 25.92 m

(b) By R = [Ux] x t

=>R = 2.47 x 2.3

=>R = 5.68 m

Explanation:

Explanation:

From the exercise we know the initial horizontal velocity and the time that Janet takes to land in the water

a) Knowing the formula for free falling objects, we can calculate how high is the platform

At t=2.3m the position of Janet is y=0m

So, the platform is 26m tall

b) According to dynamics the displacement of an object can be analyze using the following formula:

So, Janet lands 6 m far from the base of the platform

Three identical capacitors are connected in parallel to a potential source (battery). If a charge of Q flows into this combination, Each capacitor will carry a charge of Q/3.  

A capacitor is a two-terminal electrical device that can store energy in the form of an electric charge. It consists of two electrical conductors that are separated by a distance. The space between the conductors may be filled by vacuum or with an insulating material known as a dielectric.capacitor, device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other. A simple example of such a storage device is the parallel-plate capacitor.

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Answer:

diphosphorus pentoxide

Explanation:

just checked it!! <3 gl

P2O5 is a covalent compound used to purify sugar. diphosphorus pentoxideis the name of this compound.  Hence option B is correct.

Covalent substance diphosphorus pentoxide, with the chemical formula P2O5, is frequently employed in the purification of sugar. It is a two phosphorus and five oxygen atom solid that is white and crystalline in nature.

The term "diphosphorus pentoxide" accurately describes the substance's molecular make-up. In the sugar business, this substance is used as a dehydrating agent to assist remove water from sugar solutions.

Diphosphorus pentoxide accelerates the transformation of sucrose into solid sugar by interacting with water, which reduces the growth of microbes and increases the stability and shelf life of the finished product.

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