Manipulate seven additional data sets and place these values in your Ocean Interactions


Worksheet.


Biodiversity


Arctic Ice


Technology Impact


Life Sustainability


1,000


3. 7


100


1,850

Step 1

The reaction involved here:

3 FeO + 2 Al => 3 Fe + AI2O3 (Don't forget to completed it and balance it)

---------------

Step 2

Data provided:

125 grams of FeO react with 25.0 grams of AI

--

Data needed:

The molar masses of:

FeO) 71.8 g/mol

Al) 27.0 g/mol

Fe) 55.8 g/mol

---------------

Step 3

The limiting reactant:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

3 x 71.8 g FeO ----- 2 x 27.0 g Al

125 g FeO ----- X

X = 125 g FeO x 2 x 27.0 g Al/3 x 71.8 g FeO

X = 31.3 g Al

For 125 g of FeO, 31.3 g of Al is needed, but there is 25.0 g of Al, so the limiting reactant is Al.

-------------

Step 4

The amount of Fe produced:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

2 x 27.0 g Al ---- 3 x 55.8 g Fe

25.0 g Al --- X = 77.5 g Fe

Answer: 77.6 g Fe (the closest value)

When GPR resin is setting, it gets hot. The type of reaction is this (exothermic or endothermic) is endothermic reaction. In terms of energy transfer energy is absorbed from its surrounding in form of heat.

Endothermic reaction occurs when heat is  absorbed by the system from surrounding. while Exothermic reaction occurs when heat is released by the system in surrounding. In endothermic reaction , the system absorbed the energy from its surrounding in the form of heat.

Thus, When GPR resin is setting, it gets hot. The type of reaction is this (exothermic or endothermic) is endothermic reaction. In terms of energy transfer energy is absorbed from its surrounding in form of heat.

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The pKa value of methyl red is 5.

Consequently, it exhibits a colour change range of +/-1 pH unit between its pKa value of 4 and 6.

The indicator dye methyl red, commonly known as C.I. Acid Red 2, turns red in acidic solutions. It is a crystalline powder that is a deep red azo dye. Methyl red is a pH indicator with a pKa of 5.1; it is red at pH values below 4.4, yellow at pH values over 6.2, and orange at pH values in the middle.

An indicator dye called methyl red becomes red in acidic solutions. It is a pH indicator, becoming orange between pH 4.4 and 6.2 and yellow beyond pH 6.4. In microbiology, the Voges-Proskauer test is used to find bacteria that digest glucose with mixed acids to form stable acids.

Methyl red is an azo dye made of benzoic acid and a 4-[(dimethylamino)phenyl]diazenyl group at position 2. It functions as a dye. It is a tertiary amino molecule, a monocarboxylic acid, and a member of the azobenzene family.

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The rate of reaction increases, we need to consider the given reaction and orders of reactants A and B the rate of reaction increases by a factor of 50.

A + 2B -> Products
The reaction is first-order with respect to A and second-order with respect to B. Therefore, the rate law for the reaction can be written as:

Rate = k[A]^1[B]^2
Now, let's consider the changes in the concentrations of A and B:- Concentration of A doubles, so the new concentration of A is 2[A]. - Concentration of B increases 5 times, so the new concentration of B is 5[B].

Now we can find the new rate of reaction:
New Rate = k(2[A])^1(5[B])^2
To determine the factor by which the rate of reaction increases, we need to divide the new rate by the original rate:
Factor = (k(2[A])^1(5[B])^2) / (k[A]^1[B]^2)
By simplifying this expression, we get:
Factor = (2^1)(5^2)
Factor = 2 * 25 = 50
So, the rate of reaction increases by a factor of 50.

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The characteristic that your workplace demonstrates is a formal and impersonal culture with a preference for written communication, specifically through memos and emails.

This type of culture values clear and documented communication channels, allowing employees to convey information and interact with one another in a structured and formal manner. Face-to-face communication and texting may be less common or not preferred due to the emphasis on maintaining a professional distance and ensuring that information is accurately transmitted and recorded.

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hex-1-ene, would give more than one product when treated with excess HCl. The correct option is a.

According to concept of Markovnikov's rule, when an unsymmetrical alkene or alkyne is treated with an acid such as HCl, the hydrogen atom from the acid adds to the carbon atom with fewer hydrogen atoms already attached, while the chloride ion adds to the other carbon atom.

Therefore, in the case of the options given, only the first option, hex-1-ene, would give more than one product when treated with excess HCl, as it has two different carbon atoms to which the hydrogen and chloride can add. The other options, hex-2-yne, hex-I-yne, and hex-3-yne, each have only one carbon atom that the hydrogen and chloride can add to, so they would only produce one product.

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Answer:

about 10 pounds

Explanation:

your mass doesn't change but weight changes (due to gravity)

Answer:

around 10 pounds

Explanation:

the bigger the object, the more force of gravity

hope this helps <3

Answer:

a. 5 8/100 is equivalent to $ 5.08.

Explanation:

i hope this helps :)

Answer:

Using the formula cards again, add the coefficient of 2 in front of the formula and have them recalculate the number of each element and the total number of atoms in each element.

Explanation:

The number of elements in a compound is counted by identifying and counting the chemical symbols represented in the chemical formula

A compound is a substance that is a mixture of more than one elements.

Compounds are made of two or more elements. These elements are represented by their symbols. These symbols can be identified and the number of elements represented by these symbols are counted.

For example, in the compound \(H_2O\):

H represents Hydrogen

O represents Oxygen

The elements in Water ( \(H_2O\)) are Hydrogen and Oxygen

Therefore, the number of elements in  \(H_2O\) is 2

Also in, \(NaCl\)

The elements are Sodium(Na) and Chlorine(Cl)

There are two elements in NaCl

Hence, the number of elements in a compound is counted by identifying and counting the chemical symbols represented in the chemical formula

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Answer: Sea Level

Explanation: facts

Answer:  The color has changed or the formation of light and heat. Also, the temprature will change as well.

Explanation:

Structures that can be drawn to represent the covalent bonding in a molecule that has more than one position in the molecule for a multiple bond are known as Position Isomers.

Position isomers are isomers with same chemical formula but the functional group is attached to different position of carbon in different structures.

Example-

Hex1-ene , Hex2-ene, Hex3-ene are position isomers with double bond on first, second and third carbon respectively as shown below-

\(CH_2= CH-CH_2-CH_2-CH_2-CH_3\\CH_3-CH=CH-CH_2-CH_2-CH_3\\CH_3-CH_2-CH=CH-CH_2-CH_3\)

Other examples are pent1-yne and pent2-yne where triple bond is on first and second carbon respectively.

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The density of the balls, given the masses and volume of each balls did not change

To Know if there is a change or not, we shall determine the density of both lead balls. Details below:

For the small ball

Density = mass / volume

Density of small ball = 1017 / 90

Density of small ball = 11.3 g/cm³

For the larger ball

Density = mass / volume

Density of larger ball = 2825 / 250

Density of larger ball = 11.3 g/cm³

From the above calculations, we obtained:

Thus, we can conclude that the density of the lead balls did not change

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All electrons are alike regardless of the atomic element. All protons are alike regardless of the atomic element. Both are correct.

A chemical compound that cannot be converted into another chemical substance is known as an element. Atoms are the fundamental building blocks of chemical elements. Each chemical element is identified by the atomic number, or the quantity of protons in its atoms' nucleus. For instance, the atomic number 8 of oxygen indicates that each oxygen atom's nucleus has 8 protons. As opposed to chemical compounds and mixes, which include atoms with multiple atomic numbers, this is not the case. Chemical elements make up the majority of the universe's baryonic stuff. All electrons are alike regardless of the atomic element. All protons are alike regardless of the atomic element.

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Answer:

The work done by the gas expansion is 5875 J,

Since the work done is positive, the work is done by the gas on the surroundings.

Explanation:

Given;

change in internal energy, ΔU = -4750 J

heat transferred to the system, Q = 1125 J

The change in internal energy is given by;

ΔU = Q - W

Where;

W is the work done by the system

The work done by the system is calculated as;

W = Q - ΔU

W =  1125 - (-4750)

W = 1125 + 4750

W = 5875 J

Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).

Therefore, the work done by the gas expansion is 5875 J

Answer:

100 g of water dissolves 204 g of sugar. Therefore, 25 g of water would dissolve 204×25÷100 =51g of sugar at 20°C.

Explanation:

Answer: 408g of sugar

Explanation: the amount of water increased by 2

so, multiply: 204 times 2= 408

When equal masses of ch4(g) and o2(g) are placed in a container, exerting a total pressure of 600 torrs, then the partial pressure of ch4(g) will be 300torr

Let, x gm o2 and ch4 are present

Given,

Total Pressure = 600torr

Number of moles of o2 = x/16

Number of moles of Ch4 = x/16

According to the Daltons law of partial pressure,

Pa =Xa*Ptotal

Xa is the mole fraction of a

Xch4 =\(\frac{x/16}{x/16 +x/16}\)

         =1/2 = 0.5

Pch4 = 0.5×600 = 300torr

Therefore the partial pressure of ch4 will be 300 torr when a total pressure of 600 torr is applied to the mixture.

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The name of the process shown in the diagram is of filtration which is a separation technique.

Filtration is defined as a process by which solid particles which are present in liquid or gaseous medium are allowed to be removed using a filter medium which retains the particles but allows the liquid to pass through.

The requirements for filtration are a filter medium ,fluid containing particles , a mechanical device usually a filter and a driving force.The filter media is classified depending on the pore size of particles which are to be filtered.

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Using the change of base rule to find the logarithm to four decimal places. the correct answer is 11.4235.

To find the logarithm of 143.2 using the change of base rule, we can choose any base we prefer. Let's use base 10 and natural logarithm (base e) for this calculation.

First, we'll use the change of base formula, which states that log(base b) x = log(base c) x / log(base c) b. In this case, we'll calculate log(base 10) 143.2.

We'll use the natural logarithm (ln) as our intermediary step. The natural logarithm of 143.2 can be calculated as ln(143.2).

Using a calculator, we find that ln(143.2) is approximately 4.9628.

Next, we need to calculate log(base 10) e, which is the logarithm of e with base 10. Using a calculator, we find log(base 10) e is approximately 0.4343.

Finally, we apply the change of base formula:

log(base 10) 143.2 ≈ ln(143.2) / log(base 10) e
                ≈ 4.9628 / 0.4343
                ≈ 11.4235

Rounding to four decimal places, the logarithm of 143.2 using base 10 is approximately 11.4235.

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When all the molecules of a gas in a laboratory vessel cease to have any motion, it indicates that the temperature in the vessel has reached absolute zero.

Absolute zero is equivalent to -273.15 degrees Celsius or 0 Kelvin (K).

In this case, the temperature in the vessel would be approximately -273°C or 0 K.

It's important to note that absolute zero is the lowest possible temperature and represents the absence of molecular motion.

Therefore, when all the molecules of a gas in a laboratory vessel cease to have any motion, it indicates that the temperature in the vessel has reached absolute zero.

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The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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The answer that should be reported for the mass of a sample obtained by taking the difference between the mass of the sample plus beaker (75.652 g) and the mass of the beaker (74.8 g) is 0.852 g.

The mass of a substance is a measure of the amount of matter present in that substance.

The mass of a substance is measured using a balance.

The unknown mass of a given substance can be obtained by taking differences in mass of two substance that contains that substance.

For example, the mass of a given sample of substance is calculated as follows:

Mass of the sample plus beaker = 75.652 g

Mass of the beaker alone = 74.8 g

Mass of the sample = Mass of the sample plus beaker - Mass of the beaker alone

Mass of the sample = 75.652 - 74.8 = 0.852 g

In conclusion, the mass of the sample is found by subtraction.

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Nitrogenous bases refer to the building blocks of DNA and RNA molecules. They are molecules that contain nitrogen and other elements. Four nitrogenous bases are found in DNA: adenine (A), guanine (G), cytosine (C), and thymine (T).These bases are divided into two categories: purines and pyrimidines.

Purines include adenine (A) and guanine (G), which are two-ringed structures. Pyrimidines include thymine (T) and cytosine (C), which are one-ringed structures. Purines always pair with pyrimidines in DNA, resulting in a consistent diameter for the DNA helix.Nitrogenous bases play a crucial role in encoding genetic information because they are responsible for holding the information in the DNA molecule. They can bind to one another via hydrogen bonding. The number of hydrogen bonds between base pairs determines their strength, which is essential in DNA replication and protein synthesis. For example, the pairing of guanine with cytosine is stronger than the pairing of adenine with thymine. Adenine pairs with thymine, while guanine pairs with cytosine, resulting in complementary base pairing.A single strand of DNA contains four types of nitrogenous bases, and each base has a complementary base. A strand of DNA is always composed of nucleotides, which are made up of a phosphate group, a sugar, and a nitrogenous base. Therefore, the four nitrogenous bases are essential building blocks of DNA molecules.

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Answer:

na.

sodium

11( 2,81,)

pls Mark me as brainlest

In this structure, Nitrogen (N) has a lone pair of electrons, Oxygen (O) has a lone pair of electrons, and each Hydrogen (H) atom has two electrons and no lone pairs.

The Lewis dot structure for \(NOH_{3}\) (nitrosamine) can be determined by following a few steps:

Count the total number of valence electrons in the molecule. Nitrogen (N) contributes 5 valence electrons, Oxygen (O) contributes 6 valence electrons, and Hydrogen (H) contributes 1 valence electron each. So, the total number of valence electrons is:

5 (N) + 6 (O) + 3 (H) = 14 valence electrons.

Identify the central atom. In this case, Nitrogen (N) is the central atom since it can form more bonds compared to Oxygen (O).

Connect the atoms using single bonds. In \(NOH_{3}\), Nitrogen (N) is bonded to Oxygen (O) and three Hydrogen (H) atoms.

Place the remaining electrons around the atoms to complete their octets. Start by filling the octet of the atoms bonded to the central atom, and then distribute the remaining electrons to satisfy the octet rule. If there are extra electrons, place them on the central atom.

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Hence the reaction is first order. and k = 0.00582 s-1 is the rate constant  and half life t1/2 = 1.98 min = 2 min (approx.)

(a) Initial amount = 1.000 M

Time for the conversion of half of the amount into product = 2 min   where [N2O5]=0.497 (approx.0.50)

After, next 2 min the amount again halved i.e. 0.246 M (approx.0.25M).

Hence the reaction is first order. where the original amount has no bearing on the half-life.

(b) First order integrated rate constant equation is,

k = (1/t)*ln[A]0/[A]t

k = (1/1) * ln(1.000 / 0.705)

k = 0.350 min-1

k = 0.350 / 60 s-1

k = 0.00582 s-1

(c) t1/2 = 0.693 / k

t1/2 = 0.693 / 0.350

t1/2 = 1.98 min = 2 min (approx.)

A chemical breaking down into two or more simpler compounds is known as a decomposition process.

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The 2,4-DNP test can be used to distinguish between the two isomeric ketones because it will form different precipitate with both the ketone compounds.

Isomeric ketones have the same molecular formula but differ in the arrangement of atoms. In the case of 3-pentanone and 2-pentanone, they have the same molecular formula C5H10O but differ in the position of the carbonyl group (C=O). One test that can be used to distinguish between the two is the 2,4-dinitrophenylhydrazine (2,4-DNP) test.

Here is a brief explanation:

2,4-DNP Test - This test is used to detect the presence of a carbonyl functional group (C=O) in a compound. When 2,4-DNP reacts with a carbonyl compound, a yellow-orange precipitate is formed. The test can be used to distinguish between aldehydes and ketones. In the case of 3-pentanone and 2-pentanone, both compounds are ketones, but their carbonyl groups are in different positions. If both are reacted with 2,4-DNP, two different precipitates will be formed. The precipitate formed by 3-pentanone will be different from the one formed by 2-pentanone. Therefore, the 2,4-DNP test can be used to distinguish between the two isomeric ketones.

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Answer:

6

Explanation:

If there are 6 electrons and it has a balanced charge, there also must be six protons.