Matter can undergo chemical reactions and nuclear reactions, which
statement is true for both types of reactions?
a. the reactants have the same numbers of atoms as the products,
b. they conserve mass.
c. they involve breaking and making chemical bonds,
d. they have reactants and products,

Answers

Answer 1

Answer:

C

Explanation:

they involve breaking and making chemical bonds

Answer 2

Answer: C

Explanation:


Related Questions

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a

Answers

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a calorie.

How can you define calorie?

In physics, we can define it as a unit of measurement that defines the amount of energy to raise the temperature of 1 gram  of water by 1°C. Each material has its unique calorie, however by definition we use water as it is the lowest of all the elements.

Normally, calorimetry is directly linked with the thermal capacity that an element has to contain heat.

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Why is the Mid-Atlantic Ridge an ideal place for SWARM to collect electrical conductivity data?

Answers

Answer: Mid-ocean ridges are geologically important because they occur along the kind of plate boundary where new ocean floor is created as the plates spread apart. Thus the mid-ocean ridge is also known as a "spreading center" or a "divergent plate boundary." The plates spread apart at rates of 1 cm to 20 cm per year.

Answer:  The mid-ocean ridge system is the most extensive chain of mountains on earth, but more than 90% of this mountain range lies in the deep ocean. The mid-ocean ridge wraps around the globe for more than 65,000 km like the seam of a baseball. The average depth to the crest (top) of the ridge is 2500 m, but it rises above sea-level in Iceland and is more than 4000 m deep in the Cayman Trough.

Since the moon orbits the earth approximately every 27 days, there is a lunar eclipse approximately every 27 days.
True
False

Answers

Answer:

No ! its False

Explanation:

We all know , we dont have lunar eclipse in every 27 days . They do not happen every month because the Earth's orbit around the sun is not in the same plane as the Moon's orbit around the Earth.

Answer:

False

Explanation:

Yes, the moon orbits the Earth every 27 days, actually, it's precisely 27.3, but that does not mean that there is a lunar eclipse every 27 days. A lunar eclipse only happens when the full moon is directly in Earth's shadow. The moon does not pass through Earth's shadow often because of the Earth's axis. Earth only sees a couple of lunar eclipses a year.

PLEASE HELP! thxssss

PLEASE HELP! thxssss

Answers

Answer:

D is correct

Explanation:

3) What is the approximate radius of the nucleus of this atom? nucleus = m Submit Help 4) What is the magnitude of the electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus. F = N Submit Help

Answers

The magnitude of the electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.25 x 10^-8 N.

The atomic mass unit is defined as 1/12th the mass of one carbon atom. In short, it is defined as the standard unit of measurement for the mass of atoms and subatomic particles.

The mass number is equal to the number of protons and neutrons in the nucleus of an atom. The symbol for the mass number is A.

The average atomic mass of an element is the average mass of all the isotopes that occur in nature, with each isotope weighted by its abundance.

The approximate radius of the nucleus of an atom:

If you take the formula R = R0*A^(1/3), where R0 is the empirical constant, equal to 1.2 x 10^-15 m, and A is the mass number, then you'll get the approximate radius of the nucleus.

Here, A is the atomic mass number. Therefore, the approximate radius of the nucleus of this atom is R = (1.2 x 10^-15) * 7^(1/3)

R = 3.71 x 10^-15 m

Therefore, the approximate radius of the nucleus of this atom is 3.71 x 10^-15 m.

The magnitude of the electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus:

The magnitude of the electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is given by Coulomb's law of electrostatics, which states that the force of interaction between two charged particles is proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's law of electrostatics is given as:

F = (1/4*pi*epsilon)*q1*q2/r^2
where

F is the force of interaction between two charged particles q1 and q2 are the charges of the particles

r is the distance between the particles epsilon is the permittivity of free space

F = (1/4*pi*epsilon)*q1*q2/r^2

F = (1/4*pi*8.85 x 10^-12)*(1.6 x 10^-19)^2/(2.76 x 10^-15)^2

F = 2.25 x 10^-8 N

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Why does the quantity of the water in a beaker not matter but the quantity in a polystyrene cup does?


(PLS HELP ILL MARK U BRAINLIEST)

Answers

The quantity of water in a beaker or a polystyrene cup does matter, but the reason why it matters is different for each container.

Why does the quantity of water  for each container matter?

In a beaker, the quantity of water does not affect the temperature of the water significantly because glass is a good conductor of heat, meaning that the heat from the water is evenly distributed throughout the beaker. As a result, the temperature of the water remains relatively stable regardless of the quantity of water in the beaker.

On the other hand, in a polystyrene cup, the quantity of water does matter because polystyrene is a poor conductor of heat, meaning that the heat from the water is not evenly distributed throughout the cup. If there is a small quantity of water in the cup, the heat from the water is concentrated in a small area, causing the temperature to increase rapidly.

This can cause the cup to melt or deform. If there is a large quantity of water in the cup, the heat is distributed over a larger area, reducing the temperature increase.

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The Atwood’s machine shown consists of two blocks of mass m1 and m2 that are connected by a light string that passes over a pulley of negligible friction and negligible mass. The block of mass m1 is a distance h1 above the ground, and the block of mass m2 is a distance h2 above the ground. m2 is larger than m1. The two-block system is released from rest. Which of the following claims correctly describes the outcome after the blocks are released from rest but before the block of m2 reaches the ground? Select two answers.

The Atwoods machine shown consists of two blocks of mass m1 and m2 that are connected by a light string
The Atwoods machine shown consists of two blocks of mass m1 and m2 that are connected by a light string

Answers

(A) For the system consisting of the two blocks, the change in the kinetic energy of the system is equal to work done by gravity on the system.

(D) For the system consisting of the two blocks, the pulley and the Earth, the change in the total mechanical energy of the system is zero.

The given parameters:Mass of block 1 = m1Mass of block 2, = m2Height of block 1 above the ground, = h1Height of block 2 above the ground = h2

The total initial mechanical energy of the two block system is calculated as follows;

\(m_1gh_1 + \frac{1}{2} m_1v_1_i^2 = m_2gh_2 + \frac{1}{2} m_2v_2_i^2\\\\m_1gh_1 + 0 = m_2gh_2 + 0\\\\m_1gh_1 = m_2gh_2\\\\m_1gh_1 - m_2gh_2 = 0\)

When the block m2 reaches the ground the block m1 attains maximum height and the total mechanical energy at this point is given as;

\(m_1g(h_1 + h_2) + K.E_1 = \frac{1}{2}m_2v_{max}^2 + P.E_2\\\\m_1g(h_1 + h_2 ) -PE_2 = \frac{1}{2}m_2v_{max}^2 - K.E_1\\\\m_1g(h_1 + h_2 ) - 0= \frac{1}{2}m_2v_{max}^2 - 0\\\\m_1g(h_1 + h_2 ) = \frac{1}{2}m_2v_{max}^2\\\\W = \frac{1}{2}m_2v_{max}^2\)

Thus, we can conclude the following before the block m2 reaches the ground;

For the system consisting of the two blocks, the pulley and the Earth, the change in the total mechanical energy of the system is zero.For the system consisting of the two blocks, the change in the kinetic energy of the system is equal to work done by gravity on the system.

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the motion of a piston in an auto engine can be modeled as a spring in simple harmonic motion. if the piston travels back and forth over a distance of 10 cm, and the piston has a mass of 1.5 kg, what is the maximum speed of the piston when the engine is running at 4200 rpm?

Answers

The maximum speed of the piston when the engine is running at 4200 rpm is approximately 4.12 m/s.

Assume that the piston is undergoing simple harmonic motion with an amplitude of 5 cm (half of the total distance traveled). The period of the motion can be calculated using the formula T = 1/f, where f is the frequency in Hz. At 4200 rpm, the frequency can be converted to Hz by dividing by 60, resulting in a frequency of 70 Hz. Therefore, T = 1/70 = 0.0143 s.
Next, we can use the formula for the maximum speed of an object undergoing simple harmonic motion: vmax = Aω, where A is the amplitude and ω is the angular frequency.

The angular frequency can be calculated using the formula ω = 2π/T, resulting in ω = 440.53 rad/s.
Plugging in the values,

we get,

vmax = 0.05 m x 440.53 rad/s = 22.03 m/s.

However, this is the maximum speed at the center of the piston's motion, which is not the same as the maximum speed of the piston itself.

To find the actual maximum speed of the piston, we need to consider the piston's mass.
Using the formula for the maximum kinetic energy of an object in simple harmonic motion,

we get,

Kmax = (1/2)mv^2 = (1/2)kA^2, where k is the spring constant.

Since the piston is modeled as a spring in simple harmonic motion,

we can use the formula k = mω^2, resulting in k = 9263.13 N/m.

Plugging in the values,

we get,

(1/2)(1.5 kg)vmax^2 = (1/2)(9263.13 N/m)(0.05 m)^2

vmax = 4.12 m/s.
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if the ship was traveling at 5.0 knots but was 10 times more massive, how would the force of the collision on the whale compare?]

Answers

The force of the collision on the whale would be 10 times greater when the ship is 10 times more massive and traveling at 5.0 knots.

To analyze this situation, we can use the concept of momentum, which is the product of an object's mass and velocity. The momentum of the ship before the collision can be calculated using the formula:

momentum = mass × velocity

If the ship becomes 10 times more massive, its new momentum would be:

new_momentum = 10 × mass × velocity

Since the force of the collision is related to the change in momentum, we can compare the ratio of the new_momentum to the original momentum:

ratio = (10 × mass × velocity) / (mass × velocity)

The mass and velocity terms cancel out:

ratio = 10

Thus, the force of the collision on the whale would be 10 times greater when the ship is 10 times more massive and traveling at 5.0 knots.

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Question 1 of 13 > 0. 1 / 1 : View Policies Show Attempt History Current Attempt in Progress Your answer is partially correct. (Come) back to the future. Suppose that a father is 22. 00 y older than his daughter. He wants to travel outward from Earth for 3. 000 y and then back to Earth for another 3. 000 y (both intervals as he measures them) such that he is then 22. 00 y younger than his daughter. What constant speed parameter ß (relative to Earth) is required for the trip? Number i 0. 9881 Units This answer has no units

Answers

There is no constant speed parameter ß that can satisfy the given conditions. The problem is not solvable as it leads to contradictory equations.

To determine the constant speed parameter ß required for the trip, let's break down the problem step by step.

1. Let's assume the daughter's age is represented by D and the father's age is represented by F.

2. We are given that the father is 22.00 years older than his daughter, so we can write the equation:
  F = D + 22.00

3. The father wants to travel outward from Earth for 3.000 years and then back to Earth for another 3.000 years. This means the total time elapsed for the father's journey is 6.000 years.

4. After the journey, the father wants to be 22.00 years younger than his daughter. So we can write the equation:
  F + 6.000 = D - 22.00

5. Now we have two equations:
  F = D + 22.00
  F + 6.000 = D - 22.00

6. We can solve this system of equations to find the values of F and D. Subtracting the first equation from the second equation gives:
  F + 6.000 - F = D - 22.00 - (D + 22.00)
  6.000 = -44.00

7. This is not a valid equation, which means there is no solution to the problem. The constant speed parameter ß cannot be determined in this case.

In summary, there is no constant speed parameter ß that can satisfy the given conditions. The problem is not solvable as it leads to contradictory equations.

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Convert the following. ( Show your solutions )

1. 300 meters _____ miles
2. 65 minutes _____ hours
3. 35 yards _____ meters

Answers

Solution in da attachment!! :)

Convert the following. ( Show your solutions )1. 300 meters _____ miles2. 65 minutes _____ hours3. 35

Typical electrical wires in your house are generally made of copper (electron density of 8.47∗1024 electrons per cm3 ) and are usually either 14 gauge (diameter of 1.63 mm ), 12 gauge (diameter of 2.05 mm ), or 10gauge(2.59 mm) wires.
(A) If you have a 14 gauge wire that is carrying the maximum current of 20 , what would be the average drift speed of the electrons in the wire? Tries 1/8
(B) Usinq the averaqe speed you just calculated in Part (A), how much time would it take an electron to travel 8.84 m?

Answers

A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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Explain how frequency and amplitude affect sound vibrations?

Answers

Answer:

The larger the amplitude of the waves, the louder the sound. Pitch (frequency) – shown by the spacing of the waves displayed. The closer together the waves are, the higher the pitch of the sound.

Explanation:

the best defensive driving technique for windy conditions is driving _____________.

Answers

One of the best defensive driving techniques for windy conditions is driving with both hands on the steering wheel.

When driving in windy conditions, it is essential to take some safety precautions to avoid accidents and maintain control over the vehicle. A vehicle's stability and safety depend on the driver's ability to control it, especially in extreme weather conditions. Driving with both hands on the steering wheel is the most recommended defensive driving technique to stay in control of the vehicle during windy conditions. Besides driving with both hands on the steering wheel, it's essential to maintain a slow and steady speed, pay attention to the wind direction, and stay focused on the road. The strong wind can cause vehicles to drift, sway, or even flip, so it's necessary to keep a safe distance from other vehicles, especially large trucks or buses. When driving on a windy day, it's crucial to remain calm and avoid panic. Sudden movements and reactions can cause the driver to lose control of the vehicle, which could result in a severe accident. Therefore, it's best to stay alert, keep both hands on the steering wheel, and maintain a slow and steady speed to stay safe in windy conditions.

In conclusion, the best defensive driving technique for windy conditions is driving with both hands on the steering wheel, maintaining a slow and steady speed, and keeping a safe distance from other vehicles. Stay focused, stay calm, and stay safe. The answer to the question is: driving with both hands on the steering wheel.

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The electric force per unit charge exerted on a point positive charge 'q' is:

Answers

The behavior of charged particles and electric circuits.

The electric force per unit charge exerted on a point positive charge "q" is known as the electric field strength, denoted by the symbol "E".

Mathematically, the electric field strength "E" at a point in space is defined as the electric force "F" per unit charge "q" at that point, expressed as:

E = F/q

where "E" is measured in units of volts per meter (V/m), "F" is measured in units of newtons (N), and "q" is measured in units of coulombs (C).

The electric field strength describes the strength and direction of the electric field at a point in space. A positive test charge placed in an electric field will experience an electric force in the direction of the electric field if it is also positive, and in the opposite direction of the electric field if it is negative.

The electric field is a fundamental concept in electromagnetism and plays a key role in understanding the behavior of charged particles and electric circuits.

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2. At 6:00 AM a hopital ued it cyclotron to make 1 milligram of the iotope fluorine-18 for ue a a diagnotic tool with it PET canner. The half-life of F-18 i 1. 8 hour. How much F-18 i left at 3:00 PM? At midnight? Should the hopital plan to make more F-18 the next morning?

Answers

Cyclotron to make 1 milligram of the isotope fluorine-18 for use a a diagnostic tool with it PET scanner. It seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

The half-life of F-18 is 1.8 hours, so after 1.8 hours, half of the original amount of F-18 will remain. After 3.6 hours, a quarter of the original amount will remain, and so on.

At 3:00 PM (9 hours after the F-18 was made), the hospital will have

= 1/2^(9/1.8)

= 1/2^5

= 1/32

= approximately 0.03125 milligrams of F-18 remaining.

At midnight (18 hours after the F-18 was made), the hospital will have

= 1/2^(18/1.8)

= 1/2^10

= 1/1024

= approximately 0.0009765625 milligrams of F-18 remaining.

While using cyclotron, based on these calculations, it seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

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A stone ‘X’ of mass 2 kg is at the height of 20m in two minutes, calculate the power delivered. [g=10 m/s-2]

Answers

400 J power will be delivered by lifting a stone of mass 2 kg at the height of 20m in two minutes.

What is power?

The quantity of energy transferred or transformed per unit of time is known as power. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as an activity in ancient writings. A scalar quantity is a power.

Work completed and time is linked in the power equation. Since forces may move objects and we know that forces perform work, we might anticipate that by understanding the power, we can gain insight into how a body moves through time. This outcome may be especially beneficial.

Given that, a stone ‘X’ of mass 2 kg is lifted to the height of 20m in two minutes, and g=10 m/s-2

Power Delivered = Work done in lifting the stone

Work Done = Potential energy = mgh

Work done = 2 × 10 × 20

Work done = 400 J

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I am really confused can someone please help and explain.

I am really confused can someone please help and explain.

Answers

Answer:

B.

Explanation:

You cannot scrub the energy away. The energy is coming from the atoms themselves.

Moreover, according to the law of conservation of energy, energy cannot be created or destroyed. You cannot destroy energy.

E = mc^2

Equation above states the relationship between energy and mass. Therefore you cannot destroy matter or energy.

A student attempts to determine the speed of sound using a tuning fork with a frequency of 256 Hz. She finds tubes (with one closed end and one open end) with lengths of 30.0 cm and 98.0 cm produce extra loud sounds for that frequency (no loud sounds are heard between 30.0 cm and 98.0 cm). What is the speed of sound according to this data?

Answers

The speed of sound can be determined using the formula:

v = fλ

where v is the speed of sound, f is the frequency of the tuning fork and λ is the wavelength of the sound wave.

The wavelength of the sound wave can be calculated using the formula:

λ = 4L/n

where L is the length of the tube and n is the harmonic number.

From the given data, we have two tubes with lengths 30.0 cm and 98.0 cm that produce extra loud sounds for a tuning fork with a frequency of 256 Hz. The length of the tube with one closed end and one open end is equal to one-fourth of the wavelength of the sound wave produced by the tuning fork. Therefore, we can calculate the wavelength as follows:

λ = 4L/n

For L = 30.0 cm and n = 1,

λ1 = 4(30.0 cm)/1 = 120.0 cm

For L = 98.0 cm and n = 1,

λ2 = 4(98.0 cm)/1 = 392.0 cm

Since both tubes produce extra loud sounds for a tuning fork with a frequency of 256 Hz, we can assume that this frequency corresponds to the fundamental frequency (n=1). Therefore, we can calculate the speed of sound as follows:

v = fλ

v = (256 Hz)(120.0 cm) = 30720 cm/s

v = (256 Hz)(392.0 cm) = 100352 cm/s

Therefore, according to this data, the speed of sound is approximately 30720 cm/s or 100352 cm/s depending on which tube was used.

Why do you think spacecraft that carry instruments to collect data about objects in space are called probes?

Answers

Answer:

my mind cant comprehend a shing word u just said

Explanation:

The probes collect data, they capture the movement in space, therefore, spacecraft that carry instruments to collect data about objects in space are called probes, So the given statement is correct.

What are Probes?

Any conductor that is placed into a plasma and gathers current is a probe. Measurements of the current on the probe as a function of the bias potential given to the probe can be used to identify a plasma's properties.

Such probes affect their surroundings while directly detecting electron and ion flows in the plasma. Any conductive material (wire, foil, chamber walls, etc.) can serve as a plasma probe; nevertheless, precise control over the probe's size, shape, and substance is necessary to achieve detectable plasma levels. Astronauts are not present aboard probes. Scientists can analyze the data the probes relay back to Earth. Sputnik 1 was the first spacecraft to launch.

Because probes probably collect data, they capture the movement in space, therefore, spacecraft that carry instruments to collect data about objects in space are called probes.

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Identify the TRUE statements about energy.

A; Energy can transform from electrical energy to heat.

B; Energy can be created and destroyed.

C; Higher potential energy can change into higher kinetic energy.

D; Energy changes are 100% efficient.

Answers

Answer:

A, C, D

Explanation:

A, C and D are true.

B is false as energy can neither be created nor destroyed.

when the protostar has the following temperatures, what is its luminosity? what is the radius of a protostar with these temperatures and luminosities compared to the radius of the sun? what is happening to the protostar at 200 k? what is happening to the protostar at 1000 k?

Answers

The first stage in the evolution of stars is the protostellar phase. It lasts roughly 500,000 years for a low-mass star (sun-mass or less).

When a star is still gaining mass from its parent molecular cloud, it is referred to as a protostar. The first stage in the evolution of stars is the protostellar phase. It lasts roughly 500,000 years for a low-mass star (sun-mass or less). A molecular cloud fragment first experiences self-gravity-induced collapse before entering the phase, where an opaque, pressure-supported core develops inside the fragment. It comes to an end when the gas that is descending outruns it, leaving a pre-main-sequence star that subsequently contracts to become a main-sequence star at the start of hydrogen fusion that produces helium. Since the protostar is still contracting, its diameter and surface area are extremely large, and its luminosity may be approximately 100 times greater than when it is fully formed.

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Distinguish between infrasonic and ultrasonic sound waves.

Answers

How we could distinguish them is that the infrasonic sounds are the lower limit of human hearing while ultrasonic sound is above human hearing. The sound of frequency more than 20,000Hz are called ultrasonics while the frequency less than 20Hz are called infrasonics.

Explanation:

I hope it helps! Have a great day!

Anygays-

What services do plants provide? Select the three that apply.
A. Plants release carbon dioxide into the atmosphere.
B. Plants are a source of medicine.
C. Plants are a source of beauty products.
D. Plants prevent soil erosion.

Answers

The answer to this is B, C, and D. hope this helped

A bike accelerates uniformly from rest to a speed of 3.55 m/s over 17.7m . what is the acceleration of the bike

Answers

Answer:4.9mph per meter

Explanation:

According to Newton’s first law of motion, when will an object at rest begin to move?

when its inertia decreases to zero
when an unbalanced force acts upon it
when the action and reaction forces are equal
when two equal and opposite forces act upon it

Answers

According to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

option B is the correct answer.

What is Newton's first law of motion?

Newton's first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will continue in motion with a constant velocity unless acted upon by an external force.

In other words, an object will maintain its state of motion (whether it is at rest or moving in a straight line at a constant speed) unless a force acts upon it.

Thus, according to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

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Answer:

its B

Explanation:

what is the focal length of a magnifying glass that produces a magnification of 3.00 when held 5.00 cm from an object, such as a rare coin?

Answers

The focal length is calculated as follows: five centimetres of object distance times a three-magnification factor divided by three less one results in a focal length of 7.50 centimetres.

Why is it referred to as focal length?

The focal length of a thin lens in air is the separation between its major foci, also known as focal points, and its centre. The focal length is the distance at which a beam of collimated light will be concentrated to a single spot for a converging lens (for instance, a convex lens).

What is the focal ratio?

The focal ratio, which has no units, is calculated by dividing the telescope's focal length by its aperture.

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If a dog ran at 5m/s,how far would it run in 45 s?

Answers

Answer:

225 meters

Explanation:

45*5 or 225 meters.

Hope this helps plz hit the crown :D

225 is the answer of the question now thank me later cheerio

What is the displacement of an object launched straight up into the air if it returns to its launch position?

Answers

Answer:

The displacement would be 0

Explanation:

The displacement is the shortest distance between two points, and the distance traveled is the actual distance. It would be zero because a ball thrown into the air would come down and the shortest distance is 0.

A physical property is a characteristic of a substance is one that _____.

A.) can be observed by changing it into a different substance

B.) is seen after changing it into a different substance

C.) can be observed without changing it into a different substance

D.) does not involve freezing or boiling the substance

Answers

A is the correct answer !!!
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