n unknown volume of water at 18.2°c is added to 24.4 ml of water at 35.0°c. if the final temperature is 23.5°c, what was the unknown volume? (assume that no heat is lost to the surroundings; d of water

Answer:

malleable

Explanation:

The image represent in malleable property of metal.

The image possibly represents the photoelectric effect of a metal, which is when it emits electrons after being exposed to electromagnetic radiation. Metals are also characterized by physical properties such as conductivity, malleability, metallic luster, and metallic bonding.

Based on your question, the image possibly represents the photoelectric effect, a key property of metals. This phenomenon occurs when a metal surface exposed to electromagnetic waves of a certain frequency absorbs radiation and emits electrons. These emitted electrons are called photoelectrons. Metals can also exhibit free electron model behavior, where electrons freely roam within the metal structure.

Metals possess unique physical properties like conductivity, malleability, and metallic luster. Malleability refers to the metal's ability to deform without breaking, while conductivity refers to the metal's ability to transfer heat or electricity. A metallic luster gives metals their characteristic shiny appearance.

Finally, metals are also known for their metallic bonding—a unique force that holds together the atoms within a metallic solid. Metallic bonding gives rise to many useful and varied bulk properties of metals.

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Answer:

A:temperature

Explanation:

The temperature cannot be determined by looking at the spectra of the star due to lack of the equipment for its measurement. On the other-hand, the remaining statements like the distance from earth, movement towards or away from earth can be determined.

The weight of magnesium chloride required to prepare the 200 ml solution that is 5.0 M is approximately 48 grams.

To calculate the weight of magnesium chloride (\(MgCl_{2}\)) required to prepare a 200 ml solution that is 5.0 M, we need to use the formula: Weight (in grams) = Volume (in liters) × Concentration (in moles/liter) × Molecular Weight (in grams/mole)

First, we convert the volume from milliliters to liters by dividing it by 1000: Volume = 200 ml ÷ 1000 = 0.2 L. Next, we multiply the volume, concentration, and molecular weight: Weight = 0.2 L × 5.0 mol/L × 95.3 g/mol = 47.65 grams

Rounding to the nearest whole number, the weight of magnesium chloride required to prepare the 200 ml solution that is 5.0 M is approximately 48 grams.

This calculation ensures that the desired concentration is achieved by accurately measuring the appropriate amount of magnesium chloride, taking into account its molecular weight and the desired volume of the solution.

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Answer:

160.3 g S

Explanation: there you go

Explanation:

HNO3(aq) is the compound produced by a neutralization

During all chemical reactions, the mass of the products is never equal to the mass of the reactants.

- FALSE

Mass is sometimes lost in chemical reactions.

- FALSE

The Law of Conservation of Mass states that mass is not conserved.

- FALSE

Answer: The mass of mercury will be 57.5 micrograms.

The given question deals with Analytical Chemistry where Concentration is asked here.

Concentration: Generally concentration is defined as amount of the substance per unit volume. Concentration is also expressed in parts per million(ppm) when it is a small quantity as in case of mercury content in fish.

Explanation:   Given mass of the fish = 250 g,

                         ppm = 0.23

               Now mass of mercury = 0.23 ppm × 250 g                                                        

                                                     = 0.23/1,000,000 × 250g

                                                    =0.23×250/1,000,000 g

                                                    = 0.0000575 g

                                                    =57.5 micrograms

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The two gas samples that have the same total number of molecules are gases A and C.

The number of molecules of a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number (6.02 × 10²³).

However, the number of moles can be calculated using the following formula;

PV = nRT

Where;

According to this question, four gas samples were given in a table that shows their respective temperature, pressure and volume.

Based on the above table, gases A and C have the same volume, temperature and pressure. Hence, they will have the same number of moles and molecules.

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The area = 313.612 cm²

Force (F) can cause objects to move

While pressure (P)is the force per unit area

\(\tt P=\dfrac{F}{A}\)

weight=force=105 pounds(lb)⇒english units

pressure = 2.16 lb/in²

Thea are (A)

\(\tt A=\dfrac{F}{P}=\dfrac{105}{2.16}=48.61~in^2\\\\1~in^2=6,4516~cm^2\\\\48.61~in^2=313,612~cm^2\)

Answer:

If 170 milligrams of a radioactive substance decays to 85 g after 16 hours. Then, after 21 hours, approximately 75.2 mg of the radioactive substance will remain.

The decay of the radioactive substance follows an exponential decay equation of the form:

\(N(t) = N_{o} \times e^{-kt}\)

Where:

N(t) is the amount of substance remaining at time t

N₀ is the initial amount of substance

k is the decay constant

t is the time elapsed

Given to us is N₀ = 170 mg and N(16) = 85 mg. We can use this information to find the decay constant, k.

\(85 = 170 \times e^{-k \times 16}\)

Dividing both sides by 170:

\(0.5 = e^{-k \times 16}\)

To solve for k, we can take the natural logarithm (ln) of both sides:

ln(0.5) = -k × 16

from this, the value of k comes out to be:

k = 0.0431

Now we can use the decay equation to find the amount of substance remaining after 21 hours, N(21):

\(N(21) = 170 \times e^{-0.0431 \times 21}\)

Calculating this expression:

N(21) = 75.2

Therefore, after 21 hours, approximately 75.2 mg of the radioactive substance will remain.

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The relative formula mass of the group 2 carbonate W is 41 g/mol.

Assuming that the gas produced is measured at standard temperature and pressure (STP), which is 0°C and 1 atmosphere pressure, the volume of one mole of gas is 22.4 dm³.

So if 1 mole of Group 2 carbonate W produces 24 dm³ of gas at STP, then the molar volume of the gas produced is:

24 dm³ / 22.4 dm³/mol = 1.07 mol

This means that one mole of Group 2 carbonate W produces 1.07 moles of gas. Since the gas is most likely carbon dioxide (CO₂) which has a formula mass of 44 g/mol, the relative formula mass of Group 2 carbonate W can be calculated as:

Relative formula mass = Mass of 1 mole of CO₂ / 1.07

Relative formula mass = 44 g/mol / 1.07

Relative formula mass ≈ 41 g/mol

Therefore, the relative formula mass of the Group 2 carbonate W is approximately 41 g/mol.

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The complete question is:

24 dm3 of gas is produced when one mole of a Group 2 carbonate is heated.

Determine the relative formula mass of the Group 2 carbonate W.

Use the graph above.

The metal that does not form cations of differing charges is Sodium (Na). Option A is correct

The transition metals refers to the group of metals which one can find in the middle of a periodic table. These metals have the property of transition from one energy state to another, emitting different colours. Some of the metals that are able to form cations with different charges include: Chronium (Cr), Iron (Fe), Cobalt (Co), Copper (Cu), Tin (Sn) ,Mercury (Hg), Lead (Pb)

Sodium in its cation state i.e Na⁺ is stable as it contains 8 valence electrons in its outermost shell in this cationic stage, so it doesn't have the tendency to form compounds with other atoms.

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The concentration of H₂O, given that the solution has a OH⁻ concentration of 8×10⁻¹² M is 8×10⁻¹² M

First, we shall write the dissociation equation. This is given below

H₂O(aq) <=> H⁺(aq) + OH⁻(aq)

Now, we shall obtain the concentration of H₂O. Details below:

From the above dissociation equation,

1 mole of OH⁻ is present in 1 mole of H₂O

Therefore,

8×10⁻¹² M OH⁻ will also be present 8×10⁻¹² M H₂O

Thus, we can conclude that the concentration of H₂O in the solution is 8×10⁻¹² M

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The solubility product (Ksp) of the salt given in question is 1.6x10^-9.

What is solubility product?

The equilibrium constant for a solid material dissolving in an aqueous solution is the solubility product constant, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.

Suppose we have reaction:

aA(s)↽⇀cC(aq)+dD(aq)

So, the formula to determine solubility product will be:

\(K_{sp} = [C]^c[D]^d\)

Let S mol/L be the solubility of salt. So,

\(S = [BaSo_4] = [Ba^{2+}] = [So_4^{2-}]\)

\(S = 4.0\times10^{-5}\)

we know that,

\(K_{sp} = [C]^c[D]^d = S\times S\)

\(K_sp = (4.0\times10^{-5}) \times (4.0\times10^{-5})\)

\(K_sp = 1.6 \times 10^{-9}\)

Hence, the solubility product is \(1.6 \times 10^{-9}\).

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Answer:

0.097 g/cm3

Explanation:

divide mass over volume

The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The term electrolysis has to do with the decomposition of a substance by the passage of a direct current through it.

The ions present in the system are\(H^+\), \(OH^-\) and \(NO_3^-\) ions. The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The half-reaction equation of the reduction is;

\(2H^+(aq) + e\) → \(H_2(g)\)

The oxidation half-reaction equation is;

\(4OH^- (aq)\) → \(2H_2O(l) + 4e\)

The overall equation is;

\(4H^+(aq) + 4OH^- (aq)\) → \(4H_2(g) + 2H_2O(l) + 4e\)

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compound molecules that is it

The concept of molar mass of substance help us to determine the required mass of Magnesium, Mg in grams. The weight of Mg reacted in the reaction is equals to the 4.82 grams.

We have the following chemical reaction,

2Mg + O₂ → 2MgO

The atomic masses of magnesium atom, Mg and oxygen atom O are 24.3 g/mol and 16 g/mol respectively. So, the molar mass of MgO substance = 24.3 + 16

= 40.3g/mol

Mass of MgO, m = 8.0 g

Molar mass of substance is defined as the grams per mol that is mass of substance divided by moles of substance, M = mass in g/no. of moles

=> Molar mass of MgO = mass in g/no. of moles

=> moles of MgO = mass/molar mass

= 8g/40.30g/mol = 0.1985 moles MgO produced. According to reaction, 2 mole MgO is produced by 2 mole of Mg. That's 0.1985 mole of MgO will be produced by

= (2/2)× 0.1985

= 0.1985 moles Mg

Mass of Mg = moles×molar mass

= 0.1985× 24.3 = 4.82 g

Hence, required mass is 4.82 g.

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Answer:

When moving from left to the right of a period, the number of electrons increases and the strength of shielding increases. As you move across period the number of shells remain same, the shielding effect will also remain constant.

Explanation:

The element in group 2 4th period is Calcium and it's Electronic configuration is - \(1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}\).

How to find the noble gas configuration?

Sharing valence electrons is all that is necessary to create a noble gas electron configuration. The atom will most likely give away its remaining electrons and turn into an electrically charged ion if it receives less than four. It will share the electrons and reach noble gas configuration if it gets more than 4.

Step 1 -For finding block:

​:- See the block in which the last electron enters. The element will belong to that block.

For finding period:

:- Highest value of the principal quantum no. will denotes the period no.

Afbau Principle:

​:- 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p 8s

Step 2 -Since element is in group, therefore last electron will enter into s-block and since it is in 4th period, therefore highest value of principal quantum number is 4

Element is Calcium

Electronic configuration - \(1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}\)

Therefore the element is calcium.

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The following alkenes forms 3-bromo-3-methylpentane as the major product when it reacts with all of them.

What is alkenes?

An alkene is a hydrocarbon with a carbon-carbon double bond in organic chemistry. Alkene is frequently used as a synonym for olefin, which is any hydrocarbon with one or more double bonds. Monoalkenes are classified into two types: terminal and internal. Terminal alkenes, also known as -olefins, are more helpful. However, the International Union of Pure and Applied Chemistry (IUPAC) recommends using the name "alkene" only for acyclic hydrocarbons with one double bond; alkadiene, alkatriene, or polyene for acyclic hydrocarbons with two or more double bonds; cycloalkene, cycloalkadiene, or polyene for cyclic ones; and "olefin".

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Molten cryolite is the substance which serves as an electrolyte in the diagram.

This is defined as a substance that conducts electricity when dissolved in water.

Molten cryolite serves as the electrolyte as it helps dissolve molten aluminium oxide and increases the conductivity of the solution which was why it was chosen as the most appropriate choice.

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Answer: Molten cryolite

Explanation: Molten cryolite serves as the electrolyte as it helps dissolve molten aluminium oxide and increases the conductivity of the solution which was why it was chosen as the most appropriate choice.

2NaCN(aq) + H2SO4(aq) 2HCN(g) + Na2SO4 is the reaction balanced equation (aq). The two reactants (NaCN and H2SO4) in this reaction exchange ions to create two new products (HCN and Na2SO4).

When sulphuric acid mixes with sodium carbonate, it goes through a double displacement reaction that creates sodium sulphate and carbonic acid.

The neutralisation reaction occurs when a strong acid combines with a strong base, producing a s2NaCN(aq) + H2SO4(aq) 2HCN(g) + Na2SO4 is the reaction's balanced equation (aq). The two reactants (NaCN and H2SO4) in this reaction exchange ions to create two new products (HCN and Na2SO4).

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Vapor unlikely to behave as an ideal gas near the temperature at which the vapor would liquify the intermolecular forces between the gas molecules become more significant as the temperature decreases.

An ideal gas can be envisioned as a hypothetical gas consisting of a collection of randomly-dispersed, non-interacting particles with negligible volume.

The notion of an ideal gas proves valuable as it adheres to the principles of the ideal gas law, which is a simplified equation of state.

Furthermore, the behavior of an ideal gas lends itself to analysis through the lens of statistical mechanics.

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The probability that someone who has a positive test actually has the disease is approximately 24%.

The low probability that someone who tests positive actually has the disease despite the test's accuracy can be attributed to two factors: the rarity of the disease and the rate of false positives.

Firstly, let's consider the rarity of the disease, which is present in only 2% of the population. This means that even if the test is highly accurate, a positive result is more likely to be a false positive due to the larger proportion of healthy individuals in the population.

Secondly, we need to take into account the rate of false positives, which occurs in 6% of healthy individuals. When we combine this with the small percentage of the population actually having the disease, the number of false positives can outnumber true positives.

To understand this better, let's consider a hypothetical group of 1000 individuals. Out of these, only 20 (2%) would have the disease, while the remaining 980 (98%) would be healthy. The test's accuracy suggests that 19 out of the 20 individuals with the disease would test positive, and approximately 59 (6% of 980) healthy individuals would also test positive falsely.

Therefore, out of the total 78 positive test results (19 true positives + 59 false positives), only 19 (approximately 24%) would actually indicate the presence of the disease. This demonstrates why the probability of having the disease, given a positive test result, is relatively low.

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The net force of the car speeding with of 5000N of force is 4100N force and it is not even near to be balanced.

The net force is the total of all the forces acting on an object, according to its definition. Mass can be accelerated by net force. Whether a body is at rest or in motion, another force is at work on it. When a system has a lot of forces acting on it, the phrase "net force" is used.

We have given,

Applied force Fa = 5000N

Frictional force Ff = -400N

Force exerted back by zombie Fz = -500N

The net force formula is given by

\(F_{Net}\) = F₁ + F₂ + F₃

\(F_{Net}\) = 5000 - 400 - 500

\(F_{Net}\) = 4100N

Therefore, The net force of the car speeding with of 5000N of force is 4100N force and it is not even near to be balanced.

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