Name the appliance that is used to heat thermal irons and pressing combs.
Answers
The appliance that is used to heat thermal irons and pressing combs is commonly referred to as a "heating stove" or "stove".
These heating stoves are specifically designed to provide a consistent and controlled heat source to these styling tools, which are essential for achieving sleek and straight hairstyles. Generally, these heating stoves operate on electricity and have adjustable temperature settings, allowing users to set the heat level based on their specific styling needs. It is important to note that when using thermal irons and pressing combs, proper precautions should be taken to avoid burns or damage to the hair. This includes using a heat protectant spray and ensuring that the tool is not too hot before using it on the hair. By using these tools safely and effectively with a heating stove, users can achieve the desired look while minimizing damage to their hair.
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Related Questions
A 65 wt% Ni-35%Cu alloy is heated to temperature within the apha + liqquid-phase region. if the compostiong of the alpha phase is 70 wt%Ni, determine:
a, the temperature of the alloy
b, the composition of the liquid phase
c, the mass fractions of both phases
Type your question here
Answers
To solve this problem, we need to use the lever rule and the phase diagram for the Ni-Cu alloy system.
a. We know that the alpha phase composition is 70 wt% Ni, which means that the liquid phase composition is 60 wt% Ni (since the total composition is 65 wt% Ni). Looking at the phase diagram, we can see that the alpha + liquid phase region exists between approximately 1100°C and 1260°C. Therefore, the temperature of the alloy must be within this range.
b. Using the lever rule, we can determine the composition of the liquid phase:
Composition of liquid phase = (Wt% Ni in liquid phase - Wt% Ni in alpha phase) / (Wt% Ni in liquid phase - Wt% Ni in alpha phase)
Substituting the values we know, we get:
Composition of liquid phase = (60 - 70) / (60 - 30) = 0.5
Therefore, the liquid phase has a composition of 50 wt% Ni.
c. To find the mass fractions of both phases, we again use the lever rule:
Mass fraction of alpha phase = (Composition of liquid phase - Wt% Ni in alpha phase) / (Wt% Ni in liquid phase - Wt% Ni in alpha phase)
Mass fraction of liquid phase = 1 - Mass fraction of alpha phase
Substituting the values we know, we get:
Mass fraction of alpha phase = (0.5 - 0.7) / (0.6 - 0.7) = 0.5
Mass fraction of liquid phase = 1 - 0.5 = 0.5
Therefore, both phases have a mass fraction of 0.5.
In summary, the answers are:
a. The temperature of the alloy is between 1100°C and 1260°C.
b. The composition of the liquid phase is 50 wt% Ni.
c. Both phases have a mass fraction of 0.5.
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An electric motor converts electrical energy into mechanical energy. how do we get the mechanical energy?
Answers
The conversion of electrical energy into mechanical energy in an electric motor is made possible by the interaction between magnetic fields, which produces the necessary force to generate motion.
An electric motor works on the principle of electromagnetism, which involves the interaction between an electric current and a magnetic field. When an electric current is passed through a wire that is placed within a magnetic field, the wire experiences a force and starts to move.
When an electric current is passed through the wire, it creates a magnetic field that interacts with the magnetic field of the permanent magnet or electromagnet.
This interaction produces a force that causes the coil to rotate around the metal core, creating mechanical energy.The rotation of the coil is then transferred to the motor's shaft, which is connected to the mechanical system that needs to be powered.
The mechanical energy produced by the motor can be used to drive various types of machinery, such as fans, pumps, or conveyor belts, depending on the specific application.
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What type of drill bit can produce a blind hole with a flat bottom
Answers
Answer:
end mill 4 flute
Explanation:
you can simply hook it up
Galvanized wire rope is approximately 10% higher in strength than bright wire rope. Select one: a. True b. False
Answers
The statement is false. Galvanized wire rope is not approximately 10% higher in strength than bright wire rope. The strength of wire rope depends on various factors such as the material composition, construction, and manufacturing process, rather than solely on whether it is galvanized or bright.
Galvanized wire rope refers to a type of wire rope that has been coated with a layer of zinc to enhance its corrosion resistance. This coating helps protect the wire rope from rust and can extend its lifespan in certain environments. However, the zinc coating does not significantly impact the tensile strength or breaking strength of the wire rope. The strength of wire rope is typically determined by factors such as the diameter of the wires, the number of strands, and the construction (e.g., 6x19, 7x19, etc.). Therefore, it is not accurate to state that galvanized wire rope is consistently 10% higher in strength than bright wire rope. The strength comparison between different wire ropes needs to consider their specific construction and specifications.
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A rain gutter is to be constructed from a metal sheet of width 3m by bending up one-third of the sheet on each side through an angle θ. How should θ be chosen so that the gutter will carry the maximum amount of water?.
Answers
The area of the gutter is therefore equal to the area of the rectangle plus the area of the triangles.
A = rectangle + 2 * triangle
= 10h + 2 * (1/2 hw)
Using trig work out h and w.
h = 10 sin ?
w = 10 cos ?
A = 10h + hw
= 100sin? + 100sin?cos?
Differentiate the expression (either use the product rule for sin? cos?, or write 100sin?cos? as 50sin2? using the double angle formula)
A = 100sin? + 50sin2?
dA/dt = 100cos? + 100cos2?
For A to be a max or min the derivative must equal zero
100cos? + 100cos2? = 0
cos? + cos2? = 0
Use the double angle formula to write cos2? as 2cos^2 ? - 1
cos? + 2cos^2 ? - 1 = 0
2cos^2 ? + cos? - 1 = 0
This quadratic factorizes:
(2cos? - 1)(cos? + 1) = 0
This means that
cos ? = 1/2 or cos ? = 1
giving:
? = pi/3 or ? = pi
Which means that to achieve the maximum area ? should be pi/3 = 60 degrees
You can check that this is the max by substituting in these values of theta and the two end points (theta = 0, theta = pi), and seeing that pi/3 gives the maximum.
The maximum area is therefore
A = 100sin? + 100sin?cos?
= 100sin(pi/3) + 100sin(pi/3)cos(pi/3)
= 100 sqrt(3) / 2 + 100 sqrt(3)/2 * 1/2
= 100 * 3/2 * sqrt(3) / 2
= 3 * 25 * sqrt(3)
= 75 sqrt(3)
= 129.9...
= 130 cm^3
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The velocity profile in a turbulent boundary layer often is approximated by the 1/7-power-law equation u/U = (y/delta)1/7 Compare the shape of this profile with the parabolic laminar boundary-layer velocity profile (Problem 9.10) by plotting y/delta (on the ordinate) versus u/U (on the abscissa) for both profiles.
Answers
The 1/7-power-law velocity profile is a better representation of the velocity profile in a turbulent boundary layer than the parabolic laminar boundary-layer velocity profile.
What is velocity?
Velocity is the rate at which an object moves in a certain direction. It is a vector quantity, meaning it has both magnitude (the speed) and direction. Velocity is often expressed as the rate of change of displacement, which is the distance an object travels in a certain direction. Velocity is the change in position over time; the faster an object moves, the greater the velocity. Velocity is important in physics because it is used to calculate the acceleration of an object, the force of gravity, and the momentum of a moving object. It is also used to measure the speed of sound and the speed of light. Velocity is a fundamental concept in physics, and it is used to describe and measure a variety of physical phenomena.
This is because the former has a higher velocity near the wall and a lower velocity near the centerline, which is more representative of the actual velocity profile in a turbulent boundary layer.
The 1/7-power-law velocity profile is represented by the equation u/U = (y/delta)1/7 and the parabolic laminar boundary-layer velocity profile is represented by the equation u/U = (y/delta)2.
When these two equations are plotted on the same graph, with y/delta on the ordinate and u/U on the abscissa, the 1/7-power-law velocity profile is seen to have a higher velocity near the wall and a lower velocity near the centerline, which is more representative of the actual velocity profile in a turbulent boundary layer.
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In a four-stroke engine, the piston rises in the cylinder, which triggers the _______ stroke.
intake
compression
exhaust
power
Answers
Answer: It is power stroke
The volume of 1.5 kg of helium in a frictionless piston-cylinder device is initially 6 m3. Now, helium is compressed to 2 m3 while its pressure is maintained constant at 200 kPa. Determine the initial and final temperatures of helium, as well as the work required to compress it, in kJ.
Answers
Answer:
The initial temperature will be "385.1°K" as well as final will be "128.3°K".
Explanation:
The given values are:
Helium's initial volume, v₁ = 6 m³
Mass, m = 1.5 kg
Final volume, v₂ = 2 m³
Pressure, P = 200 kPa
As we know,
Work, \(W=p(v_{2}-v_{1})\)
On putting the estimated values, we get
⇒ \(=200000(2-6)\)
⇒ \(=200000\times (-4)\)
⇒ \(=800,000 \ N.m\)
Now,
Gas ideal equation will be:
⇒ \(pv_{1}=mRT_{1}\)
On putting the values. we get
⇒ \(200000\times 6=1.5\times 2077\times T_{1}\)
⇒ \(T_{1}=\frac{1200000}{3115.5}\)
⇒ \(=385.1^{\circ}K\) (Initial temperature of helium)
and,
⇒ \(pv_{2}=mRT_{2}\)
On putting the values, we get
⇒ \(200000\times 2=1.5\times 2077\times T_{2}\)
⇒ \(T_{2}=\frac{400000}{3115.5}\)
⇒ \(=128.3^{\circ}K\) (Final temperature of helium)
A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)
Answers
Answer:
Hydrostatic force = 41168 N
Explanation:
Complete question
A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)
Let "x" be the side length submerged in water.
Then
w(x)/base = (4+3-x)/altitude
w(x)/5 = (4+3-x)/3
w(x) = 5* (7-x)/3
Hydrostatic force = 62.5 integration of x * 4 * (10-x)/3 with limits from 4 to 7
HF = integration of 40x - 4x^2/3
HF = 20x^2 - 4x^3/9 with limit 4 to 7
HF = (20*7^2 - 4*7^(3/9))- (20*4^2 - 4*4^(3/9))
HF = 658.69 N *62.5 = 41168 N
what's the best way to plan an organized
Answers
Answer:
Get ready and comfortable.
List all of the tasks you need to accomplish over the next week. .
Next schedule everything.
Get a planner/calender.
Cut those tasks that do not fit into your
An electrical current of 700 A flows through a stainlesssteel cable having a diameter of 5 mm and an electricalresistance of 6104/m (i.e., per meter of cablelength). The cable is in an environment having a tem-perature of 30C, and the total coefficient associatedwith convection and radiation between the cable andthe environment is approximately 25 W/m2K.(a) If the cable is bare, what is its surface temperature
Answers
Answer:
778.4°C
Explanation:
I = 700
R = 6x10⁻⁴
we first calculate the rate of heat that is being transferred by the current
q = I²R
q = 700²(6x10⁻⁴)
= 490000x0.0006
= 294 W/M
we calculate the surface temperature
Ts = T∞ + \(\frac{q}{h\pi Di}\)
Ts = \(30+\frac{294}{25*\frac{22}{7}*\frac{5}{1000} }\)
\(Ts=30+\frac{294}{0.3928} \\\)
\(Ts =30+748.4\\Ts = 778.4\)
The surface temperature is therefore 778.4°C if the cable is bare
) A regenerative vapor power cycle has three turbine stages with steam entering the first stage at 2500 lbf/in2 , 1100 o F. The cycle has two feedwater heaters, a closed feedwater heater using extracted steam at 500 lbf/in2 and an open feedwater heater operating at 50 lbf/in2 . Saturated liquid condensate drains from the closed feedwater heater at 500 lbf/in2 and passes through a trap into the open heater. The feedwater leaves the closed heater at 2500 lbf/in2, 478 o F. Saturated liquid leaves the open heater at 50 lbf/in2 and the condenser pressure is 1 lbf/in2 . For isentropic operation of the turbines and pumps, determine the efficiency of this cycle.
Answers
Answer:
do the wam wam
Explanation:
The following problem refers to triangle ABC, find all missing parts. Round degrees to 1 decimal places and
sides to the nearest whole number.
A = 36.5°C = 67.5°, c = 224 inches
A=
В.
C
O
O
490 do
a =
inches
inches
inches
C-
Answers
Answer:
A =41 .....
......
......
....C=21
Asian red coolant is what type?
Answers
Answer:
Valvoline™ ZEREX™ Asian Vehicle has been designed to meet the requirements of Asian manufacturers, which specify a silicate free HOAT formula with a phosphate additive to protect their cooling systems from rust and corrosion. Available in both red and blue formulas to better match your Asian vehicle’s specific requirements.
Explanation:
ZEREX Asian Vehicle Antifreeze/Coolant is specifically formulated to meet the requirements of Asian vehicle manufacturers (Toyota , Lexus , Scion and others) requiring a red, silicate free Hybrid Organic Acid Technology (HOAT) with a phosphate additive.
Answer:poat formulation
Explanation:
Find the Transfer Function using the Block Diagram.
Answers
The transfer function from the given diagram is given as follows:
\(\frac{X(s)}{F(s)} = \frac{s + 3}{s + 13 + G(s)}\)
How to find the transfer function of a system?The transfer function of a system is given by the ratio between the output X(s) and the input F(s), as follows:
H(s) = X(s)/F(s)
From the initial subtraction operation, we have that:
F(s) - X(s) = E(s)
In which E(s) is the error of the system.
After the subtraction, the error is measured as follows, considering the perturbation G(s) and the multiplication of the blocks:
E(s) = (10 + G(s))(1/(s + 3))X(s)
Replacing this into the initial function, we have that:
F(s) - X(s) = (10 + G(s))(1/(s + 3))X(s)
Using latex for better visibility of the operations:
\(F(s) = X(s) + \frac{10 + G(s)}{s + 3}X(s)\)
Using X(s) as the common term, we have that:
\(X(s)\left(1 + \frac{10 + G(s)}{s + 3}\right) = F(s)\)
\(X(s)\left(\frac{s + 3 + 10 + G(s)}{s + 3}\right) = F(s)\)
\(X(s)\left(\frac{s + 13 + G(s)}{s + 3}\right) = F(s)\)
Hence the transfer function is given as follows:
\(\frac{X(s)}{F(s)} = \frac{s + 3}{s + 13 + G(s)}\)
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tech a says that a slightly lean mixture offers good fuel economy and low exhaust emissions. Tech b says that a mixture that is too rich fouls spark plugs and causes incomplete burning. Who is correct
Answers
Explanation:
Exhaust emissions are gases that are expelled from vehicle engines and they include carbon monoxide, unburned fuel, nitrogen oxides and particulate matter such as mercury. These emissions can cause air pollution and green house effects which leads to climate changes. Low exhaust emissions can be achieved through the use of lean mixtures which has high air- fuel ratio and less emission. Therefore, Tech A is correct.
Rich mixtures are mixtures that are of low air- fuel ratios and it's burning in a diesel engine increases particulate matter emission, fouls spark plugs, causes incomplete burning. Therefore Tech B is equally correct. Hope this helps, thanks.
4. Find the future worth in year 10 of an investment that starts at $8000 in year 1 and
increases by 10% each year. The interest rate is 10% per year.
Answers
Explanation:
I have asked question in my profile please tell me the answer
It is desired to obtain 500 VAR reactive power from 230 Vrms 50 Hz 1.5 KVAR reactor. What should be the angle of the AC to AC converter to be used? Calculate the THD of the current drawn from the mains (consider up to the 12th harmonic)?
Answers
Answer:
14.5° ; THD % = 3.873 × 100 = 387.3%.
Explanation:
Okay, in this question we are given the following parameters or data or information which is going to assist us in solving the question efficiently and they are;
(1). "500 VAR reactive power from 230 Vrms 50 Hz 1.5 KVAR reactor".
(2). Consideration of up to 12th harmonic.
So, let us delve right into the solution to the question above;
Step one: Calculate the Irms and Irms(12th) by using the formula for the equation below;
Irms = reactive power /Vrms = 500/230 = 2.174 A.
Irms(12th) = 1.5 × 10^3/ 12 × 230 = 0.543 A.
Step two: Calculate the THD.
Before the Calculation of the THD, there is the need to determine the value for the dissociation factor, h.
h = Irms(12th)/Irms = 0.543/ 2.174 = 0.25.
Thus, THD = [1/ (h)^2 - 1 ] ^1/2. = 3.873.
THD % = 3.873 × 100 = 387.3%.
Step four: angle AC - Ac converter
theta = sin^-1 (1.5 × 10^3/ 12 × 500) = 14.5°.
created by congress as one of the major public-works projects of the new deal, this built a system of dams in the southeast.
Answers
TVA - Tennessee Valley Authority. Power companies fiercely opposed the TVA because they disliked the less expensive energy it offered and thought the agency posed a danger to free market.
A notched bar is broken in a pendulum-style impact tester to determine the ductile/brittle transition temperature for every specific steel sample. The energy absorbed during the fracture is then calculated. Steel 1045 specimens break apart when the temperature drops below zero and display brittle-like fracture (specimens 1 to 4 from -200oC to 0.0oC), however when the temperature rises, the specimens display ductile-like fracture (specimens 5 to 7 from 24oC to 100oC). Mild steel is malleable and ductile because it contains between 0.05 and 0.30 percent carbon. This steel has low carbon, with a carbon concentration of about 0.3%, making it neither overly brittle nor overly ductile. It is utilized practically everywhere since it is in the middle, which strikes a good balance. The Tennessee Valley Authority (TVA) is a U.S. electric utility company that is controlled by the federal government. All of Tennessee is included in TVA's service region, along with small portions of Georgia, North Carolina, Virginia, Alabama, and Mississippi. Despite being a governmental agency, TVA is run like a private for-profit business and does not receive any taxpayer money. Its headquarters are in Knoxville, Tennessee, and it is both the largest public utility and the sixth-largest power supplier in the nation.
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You can calculate how long it will take for your investment in education to "pay back. " To do so use the following formula:
Cost of education ÷ (new pay per week − old pay per week) = weeks to pay back education. Hint: Your old take-home pay was $341. 52. Rounded to the nearest week, how long it will take for your investment in education to "pay back"?
60 weeks
29 weeks
38 weeks
Answers
The correct answer is 60 weeks.The given formula is used to determine how long it will take for an investment in education to "pay back" as follows:Cost of education ÷ (new pay per week − old pay per week) = weeks to pay back education.The old take-home pay was $341.52.
To calculate how long it will take for your investment in education to "pay back", plug in the given information into the formula, as follows:Cost of education ÷ (new pay per week − $341.52) = weeks to pay back education.Let us assume that the cost of education is $10,000 and that the new pay per week is $500.
Therefore,$10,000 ÷ ($500 - $341.52) = weeks to pay back education$10,000 ÷ $158.48 = weeks to pay back education.Thus, it will take 63 weeks to pay back the cost of education.
Rounded to the nearest week, it will take 60 weeks for the investment in education to "pay back". Therefore, the correct answer is 60 weeks.
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An inverse-time circuit breaker is used for branch-circuit short-circuit and ground-fault protection for a 30-horsepower, 208-volt, 3-phase squirrel-cage motor. Calculate the maximum rating permitted for the circuit breaker.
Answers
The circuit breaker may have a maximum rating of 20–25.Any breaker between the aforementioned ratings will therefore be adequate.
Identify the motor rating in the circuit breaker?Motor rating will be translated from horsepower (hp) to watts (W).
Circuit breakers are typically installed for electric circuits 20% to 25% more than the circuit's Rated Current, whereas overload relays are typically installed for electric circuits 20% to 25% more than the circuit's Running Current.
Therefore, the rated current of the motor will be multiplied by 1.2 1.25 Step by Step to get the maximum capacity of the circuit breaker. Explanation:
1 horsepower is 745.7 watts, so 30 horsepower is 22371 watts.
Assuming 208V phase to phase voltage and unity power factor (cos=1)
Rated Power (watt) equals 3. V.I. cos
If 208V is the voltage from the phase to the neutral, then use the following formula:
Rated Power (watt) equals 3. V.I. cos.
62.169A is the rated current.
So,
62.169A is the rated current.
Therefore, the needed maximum rating for a circuit breaker is: 20–25 percent of the rated current = 62,17*1.2 62,17*1.25 = 74.6–77,7A
Any breaker between the aforementioned ratings will therefore be adequate.
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an instrument is not defective simply because it is overdue. true false
Answers
True. The fact that an instrument is overdue does not necessarily mean that it is defective.
Overdue refers to the expiration or passing of a specified time or deadline. It indicates that the instrument has not been serviced or calibrated within the recommended timeframe. While it is important to adhere to maintenance schedules and ensure timely servicing of instruments, being overdue does not automatically imply that the instrument is defective or malfunctioning. Defects or malfunctions are determined through proper inspection, testing, and evaluation of the instrument's performance and functionality. Therefore, being overdue for servicing does not inherently make an instrument defective; it simply indicates a delay in maintenance activities.
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Welding power sources use a step-down transformer that takes high voltage, low-amperage AC input and changes it to ___ AC welding current.
Answers
Welding power sources use a step-down transformer to take high voltage, low-amperage AC input and convert it into low voltage, high-amperage AC welding current.
A step-down transformer is an essential component in the welding process, as it helps in achieving the required power output for effective welding. The step-down transformer operates on the principle of electromagnetic induction, wherein the primary coil receives high voltage, low-amperage AC input, and the secondary coil, with fewer turns, generates a low voltage, high-amperage AC output. This transformation is crucial for maintaining the desired heat and stability during the welding process, ensuring strong and durable welds.
Moreover, step-down transformers offer enhanced safety features by reducing the risk of electrical hazards associated with high voltages. They are energy efficient, as they minimize the amount of energy wasted as heat, and provide better control over the welding process through adjustable amperage and voltage settings. In conclusion, a step-down transformer is a vital component in welding power sources, converting high voltage, low-amperage AC input into highvoltage, high-amperage AC welding current, enabling a stable, efficient, and safe welding process.
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Program Increment (PI) Planning is a major event that requires preparation, coordination, and communication. What are two key areas a Release Train Engineer should focus on to support a successful PI Planning event? (Choose two.)
a) Architectural readiness - Defining the Architectural Runway
b) Organizational readiness - Strategic alignment; roles, teams, and train setup
c) Operational readiness - Facilitating PI events such as scrum of scrums, Iteration Planning, and System Demo
d) Facilities readiness - Space and logistics for the event
e) Process readiness - The operational rhythm that enables SAFe governance
Answers
Organizational readiness - Strategic alignment; roles, teams, and train setup:Organizational readiness is another essential area that Release Train Engineer should focus on for a successful PI Planning event. Organizational readiness involves the following:Strategic alignment - PI planning requires collaboration between different organizations within the enterprise.
Program Increment (PI) Planning is a major event that requires preparation, coordination, and communication. Following are the two key areas a Release Train Engineer should focus on to support a successful PI Planning event:Architectural readiness - Defining the Architectural RunwayOrganizational readiness - Strategic alignment; roles, teams, and train setup.A. Architectural readiness - Defining the Architectural Runway: Architectural readiness is one of the two critical areas for Release Train Engineer should focus on to support a successful PI Planning event. Architectural readiness requires defining the Architectural Runway, which is a long-range architectural plan that helps the development organization define the initiative's technical and architectural direction. A successful PI Planning event begins with the team's knowledge of the architectural direction, its scope, and the corresponding user story assumptions. Defining the Architectural Runway also helps teams identify architectural epics that support the product backlog. Thus, Architectural readiness is an essential element in the SAFe Framework that ensures a successful PI Planning event.B. Thus, strategic alignment is critical to ensure that all stakeholders have a shared understanding of the program objectives and how each department contributes to achieving those objectives.Roles, teams, and train setup - For a successful PI Planning event, a well-defined roles and responsibilities and a well-structured team is essential. Therefore, the Release Train Engineer must ensure that all team members understand their roles and responsibilities and ensure a well-structured team that facilitates a successful PI Planning event.
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Creating an object model
Think back to the Sales Bonus Problem you created in a prior lesson.
A more elegant solution to that problem would incorporate objects. This week you are going to revise it to an object oriented program. To do that you need to identify the objects that you need to create to support the program.
Create UML diagrams for each of the object(s) you need and using the concept of design by contract, identify the responsibilities.
For this part of the assignment I only want the UML design document and the contract responsibilities. You will use these design documents to create the program in the next assignment.
Answers
I can provide you with general guidance on creating an object model and designing by contract.
How to create an object model in UMLTo create an object model, start by identifying the entities in the problem domain and their relationships. These entities will become the objects in your program. Then, you can use UML diagrams to represent the class structure, including the attributes and methods of each class.
To design by contract, you should define a clear interface for each class, specifying its responsibilities, preconditions, and postconditions. This will ensure that the class behaves as expected and can be used safely in other parts of the program.
Once you have created your UML diagrams and defined the contracts for each class, you can use them as a blueprint for writing the actual program in code.
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Problem 2
The mayor of Cambridge, Colorado, wanting to be environmentally progressive, decides to implement a recycling plan. All residents of the city will receive a special three-part bin to separate their glass, plastic, and aluminum, and the city will be responsible for picking up the materials. A young city and regional planning graduate, Michael Duffy, has been hired to manage the recycling program. After carefully studying the city’s population density, Duffy decides that the following numbers of recycling collectors will be needed:
Day M T W TH F S Su
Requirements 12 7 9 9 5 3 6
The requirements are based on the populations of the various housing developments and subdivisions in the city and surrounding communities. To motivate residents of some areas to have their pickups scheduled on weekends, a special tax break will be given.
a. Find the minimum number of recycling collectors required if each employee works 5 days a week and has two consecutive days off. Give preference to the S–Su pair. when that pair is involved in a tie.
b. Specify the work schedule for each employee. How much slack does your schedule generate for each day?
Answers
Transformation is the change of one energy form to another.
O True
O False
Answers
I need a word problem for y=2x
Answers
The word problem for y = 2x is as follows.
"If y is the number of cakes produced by using 2 amounts of backing ingredients (x), find the number of cakes produced if x is 25."
What is a word problem?A word problem is a mathematical exercise in scientific education in which substantial background information about the subject is conveyed in regular English rather than mathematical notation.
A word problem in mathematics is a math question expressed as one or more sentences that demand students to apply their arithmetic skills to a real-life setting.
This implies that in order to understand the word problem, students must be conversant with the terminology linked with the mathematical symbols to which they are used.
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a) Describe the operation of a heat pump operating on the theoretical reversed Carnot cycle, with a neat sketch of the layout.
b) What modifications are required in order to convert a steam power plant working on the ideal Carnot cycle to a plant operating on the Rankine cycle? Explain briefly why these modifications are necessary to enable the operation of a practical cycle? Illustrate your answer with sketches using appropriate property diagrams (p-v and T-s diagrams).
Answers
Answer:
a) The operation of a heat pump involves the extraction of energy in the form of heat Q₁ from a cold source
b) The modifications required to convert a plant operating on an ideal Carnot cycle to a plant operating on a Rankine cycle involves
i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler
ii) Heating of the pumped, pressurized water to the boiler pressure
Explanation:
a) 1 - 2. Wet vapor enters compressor where it undergoes isentropic compression to state 2 by work W₁₂
2 - 3. The vapor enters the condenser at state 2 where it undergoes isobaric and isothermal condensation to a liquid with the evolution of heat Q₂
3 - 4. The condensed liquid is expanded isentropically with the work done equal to W₃₋₄
4 - 1. At the state 4, with reduced pressure from the previous expansion, the liquid makes its way to the evaporator where it absorbs heat, Q₁, from the body to be cooled.
b. i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler
Here the condensation process is modified from partial condensation to complete condensation at the same temperature which reduces the size of the pump required to pump the liquid water as opposed to pumping steam plus liquid
ii) Heating of the pumped, pressurized water to the boiler pressure
The pumped water at state 4 will be required to be heated to saturated water temperature equivalent to the boiler pressure, hence heat will need to be added at state.
Sketches of the schematic of a Basic Rankine cycle is attached
Polarization: Unpolarized light passes through three ideal polarizing filters. The first filter is oriented with a horizontal transmission axis, the second one has its transmission axis at 30° from the horizontal, and the third filter has a vertical transmission axis. What percent of the light gets through this combination?
Answers
Answer:
the percentage of light that gets through this combination is 9.38
Explanation:
Given the data in the question;
Let us represent the incident unpolarized light with \(I_0\).
So, the amount of light intensity passing through the first polarizer will be;
\(I_1\) = \(I_0\) / 2 ------ let this be equation 1
An the amount of light intensity passing through the second polarizer will be;
\(I_2\) = \(I_1\)cos²θ
given that; the second one has its transmission axis at 30°
so, we substitute;
\(I_2\) = \(I_1\) × cos²( 30° )
\(I_2\) = \(I_1\) × 0.75
\(I_2\) = 0.75\(I_1\)
from equation; \(I_1\) = \(I_0\) / 2
\(I_2\) = 0.75( \(I_0\) / 2 )
\(I_2\) = 0.375\(I_0\) .
Now, the amount of light intensity passing through the third polarizer will be;
\(I_3\) = \(I_2\)cos² ( 90° - 30° )
\(I_3\) = \(I_2\) × cos²( 60° )
\(I_3\) = \(I_2\) × 0.25
we substitute
\(I_3\) = 0.375\(I_0\) × 0.25
\(I_3\) = 0.09375\(I_0\)
∴ \(I_3\)/\(I_0\) × 100 = 0.09375 × 100
⇒ 9.38%
Therefore, the percentage of light that gets through this combination is 9.38