ndicate whether the error described below will result in a higher, lower, or no change in the calculated specific heat. Explain.Twice as much water was used in the calorimeter than specified in the procedure.

Answer:

The total frictional force equals 60 N

Explanation:

We know that F - f = ma where F is the applied force, f is the frictional force, m the mass of the object and a its acceleration.

Now, since the cart moves with constant velocity, its acceleration is zero. So, a = 0.

So F - f = ma

F - f = m(0) = 0

F - f = 0

So, F = f

From the above, we see that the frictional force equals the applied force which is equal to 60 N.

So, f the total frictional force equals 60 N

Answer:

The required second-degree polynomial is:

\(p(x) = 3x^2-5x+5\\\)

Explanation:

We want to find a second-degree(quadratic) polynomial p(x) with the following properties:

\(p(2)=7 ,p'(2)=7 ,p''(2)=6\)

We let the quadratic polynomial be,

\(p(x) = ax^2+bx+c\\\)

Then we get a set of three equations using the given values that is,

                                               \(4a+2b+c=7\\4a+b=7\\2a=6\)

This was obtained using differentiating the polynomial first and then substituting the respected values. The derivatives of the polynomial are as follows:

\(p'(x) = \frac{d}{dx} (ax^2+bx+c) = 2ax+b\\p''(x) = \frac{d}{dx}(2ax+b) = 2a\)

Solving the given set of equations can be achieved as the last equation gives us a=3. Now putting this in the second equation gives us,

\(4\times 3+b=7\\b=7-12=-5\)

Similarly putting a=3 and b=-5 in the first equation gives us,

\(4\times3 + 2(-5)+c=7\\c=7-12+10=5\\\)

Therefore we have discovered all coefficients and thus the required polynomial is:

\(p(x) = 3x^2-5x+5\)

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The initial momentum of the ball is 15 Kgms-1.

In Physics, the term momentum is the product of mass and velocity. Momentum is a vector quantity. This implies that momentum possess both magnitude and direction.

Hence, we often write; p = mv

Where:

p = momentum

m = mass

v = velocity

The initial momentum therefore is;

p = 1.25 kg × 12 m/s = 15 Kgms-1

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A) The elastic potential energy stored in the spring is 25 J. B) The speed of the mass as it passes through the equilibrium point is 2.58 m/s.

A) To find the elastic potential energy stored in the spring, use the formula:
Elastic potential energy (PE) = (1/2)kx^2
Where k is the spring constant (500 N/m) and x is the displacement from the equilibrium length (0.1 m).
PE = (1/2)(500)(0.1)^2
PE = 25 J
B) The elastic potential energy will be converted to kinetic energy when the spring is released. Use the formula:
Kinetic energy (KE) = (1/2)mv^2
Where m is the mass (0.75 kg) and v is the velocity.
Since PE = KE, we can find the velocity:
25 J = (1/2)(0.75 kg)v^2
Solve for v:
v = 2.58 m/s

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Answer:C car

Explanation:

The value shown by the letter E is 24V.

Define resistance

A material's ability to obstruct the flow of electrical current is referred to as resistance. The capital letter R serves as a symbol for it. A conductor's ability to obstruct the flow of charges through it is referred to as resistance.

A closed loop is referred to as a circuit where electrons can move. The circuit receives power from an electricity source, like a battery. There won't be any electron movement until the circuit is finished, or until it has made a full circuit loop back to the electrical source.

V = IR

For circuit 5, V = E

I = 8A

R = 3

E = 8*3 = 24V

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Answer:

8

Explanation:

Explanation:

the no of proton of an element is found in the inner part of the orbital of an element along with the neutron ,also knowing that this two add up to give mass no an element

where neutron+proton=mass no=nucleon no,where proton= electron, unless it carries charges call ion

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 438 × 2.55

We have the final answer as

Hope this helps you

The rms speed of the O2 molecules is actually slightly less than the rms speed of the N2 molecules.

This is because the mass of the oxygen molecule is greater than that of nitrogen, so the oxygen molecules will have a slightly lower average speed at a given temperature.

However, it is important to note that the difference in speed between the two molecules is very small and not significant for most practical purposes.

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Answer:

A

Explanation:

Answer:

C

Explanation:

Mass remains constant whilst weight varies based on the gravitational field strength. Weight is actually a measure of how much gravity affects the mass of an object.

Answer:

C

Explanation:

The mass of the object is the same wherever it is. Weight is measured by the force exerted on the mass by the amount of gravity.

The correct response is D. 700 kilometers.

The pace at which an object changes its position is referred to as its velocity, which is a physical term. Being a vector quantity with both magnitude (speed) and direction, velocity has both.

The displacement of an object divided by the amount of time needed to cover that distance yields the velocity. The term "displacement" describes a shift in an object's location in a certain direction.

We can apply the following formula to resolve this issue:

Distance = velocity x time

where distance is the length of time the ship travels, velocity is the ship's speed, and time is its travel time.

The ship is moving at a speed of 50 km/h southeast, which is 45 degrees southeast of the east-west axis, according to the information we have about its velocity.

The following calculation can be used to determine how far the ship traveled during a 14-hour period:

Distance= 50 km/hr x 14 hr = 700 km.

The correct response is D. 700 kilometers.

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The spring constants of the string and nylon thread are: higher compared to the spring, as they demonstrate greater resistance to stretching under the same applied force.

When a moderate force is applied, both string and nylon thread stretch but only a small amount, whereas a spring stretches much further. To compare their spring constants, we need to understand Hooke's Law, which states that the force applied is proportional to the displacement of the object (F = kx). Here, k is the spring constant and x is the displacement.

A higher spring constant (k) means that the object is more resistant to stretching, while a lower spring constant indicates that the object is more easily stretched. In this case, the string and nylon thread have higher spring constants compared to the spring since they stretch less under the same force. The spring, which stretches much further, has a lower spring constant.

In conclusion, the spring constants of the string and nylon thread are higher compared to the spring, as they demonstrate greater resistance to stretching under the same applied force. This is evident in the smaller displacements observed when pulling the string and thread compared to the more significant stretching of the spring.

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The third force that should be applied to keep the object in equilibrium is -3i - j.

To determine the third force, we need to find the negative sum of the two given forces. The given forces are represented by the vectors i - 2j + k and 2i + j - k. By adding these two vectors and negating the result, we obtain the third force required to balance the other two forces and maintain equilibrium.

The third force is obtained by adding the corresponding components of the vectors: 2i + 3j - 2k. This means that a force of magnitude 2 units in the positive x-direction, 3 units in the positive y-direction, and 2 units in the negative z-direction should be applied to keep the object in equilibrium.

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The values of all sub-parts have been obtained.

(1).  The maximum factored load the beam can withstand is 45.2 kN/m.

(2).  The moment resistance of the cross-section is 291735.65 Nm.

(3).  The factored moment demand is 27939.6 Nm

1) To draw the governing shear and bending moment diagram for the factored load, we need to first calculate the maximum factored load that the beam can withstand.

The maximum factored load on the beam is given by:

Dead Load = 20 kN/m + 15 kN

                   = 35 kN/m.

Live Load = 2 kN/m + 1 kN

                = 3 kN/m.

Total Factored Load = 1.2 x Dead Load + 1.6 x Live Load

                                  = 1.2 x 35 kN/m + 1.6 x 3 kN/m

                                  = 45.2 kN/m.

The maximum factored load the beam can withstand is 45.2 kN/m.

The shear force and bending moment diagrams for the given factored load can be obtained as shown below:

Shear Force Diagram:

Bending Moment Diagram:

2) To calculate the moment resistance of the cross-section, we can use the formula:

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

Where, σst = yield stress of tension steel [σst = fy / γst],

γst = safety factor for tension steel [γst = 1.15A']

A' = area of tension steel, [A'' = b(d - a)].

Where,

b = width of the beam [b = 600 mm],  

d = total height of the beam [d= 1000 mm],

a = effective depth of tension steel [a = 920 mm]

f'c = compressive strength of concrete [f'c = 25 MPa],

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

MR = (400 / 1.15) x 10 x (1000 - 920/2) + 0.85 x 25 x 590 x (1000 - 920/2)

MR = 291735.65 Nm

The moment resistance of the cross-section is 291735.65 Nm.

3) To check if this cross-section is adequately designed to resist the factored bending moment (LRFD), we need to calculate the factored moment demand and compare it with the moment resistance.

The factored moment demand is given by:

MF = ϕ x Mu

Where,ϕ = resistance factor = 0.9, Mu = factored bending moment

Mu = 1.2 x Dead Load x L2 / 8 + 1.6 x Live Load x L2 / 8 + 1.2 x (Dead Load + Live Load) x L2 / 2

   = 1.2 x 35 x 152 / 8 + 1.6 x 3 x 152 / 8 + 1.2 x 38 x 152 / 2

   = 31044 Nm

MF = ϕ x Mu

     = 0.9 x 31044

    = 27939.6 Nm

The factored moment demand is 27939.6 Nm, which is less than the moment resistance of the cross-section, i.e., 291735.65 Nm.

Therefore, this cross-section is adequately designed to resist the factored bending moment.

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Answer:

stored

Explanation:

P. E . = m g h  

   represents STORED energy in the form of the height * acceleration of gravity * mass

Answer: Drop each object 10 times and use the average of each object’s fall times

Explanation: Drop each object 10 times and use the average of each object’s fall times

Answer:

(Question)  Melissa is working on the roof of her house. She drops a hammer and a nail. Why do both objects hit the ground at the same time?

(Answer)  Earth’s gravity causes both objects to fall at the same rate.

(Question)  Which of the following statements about gravitational mass is true?

(Answer)  Gravitational acceleration is irrespective of mass.

(Question)  Two objects fall from an apartment window sill at the same time. Object 1 lands on the sidewalk in 3.6 seconds. Object 2 lands on the sidewalk in 3.3 seconds. What can be concluded about the objects?

(Answer)  Object 1 has more surface area than Object 2

(Question)  A company uses drones to fly food to people in regions that have experienced natural disasters. The food is packed in boxes that are attached to parachutes. How can the company change the design of its parachute to reduce the number of boxes that are damaged when they hit the ground?

(Answer)  The company can design a parachute with more surface area

(Question)  Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from the top of their school’s bleachers. They will time how long each object takes to reach the ground. How can they improve confidence in the experiment’s results?

(Answer)  Drop each object 10 times and use the average of each object’s fall times

Explanation:

I just finished the quick check UwU

Answer:

Exactly 0.03042 carbon-14 is remaining.

Roughly 0.03 Carbon-14 is remaining. (When/If Multiple Choice)

Explanation:

Not a physics question, this is chemistry, but I'll answer.

First, divide 17,000/5700 to find the t, or time.

t = 2.98245614 or 2.98.

If it originally contained .24 grams, and a half life means x/2,

you would use the formula x/2^p, with p being the number of half lives

(these variables are made up, you can use any you would like)

In 17,000 years, the palm fossil experienced 2.98 half lives.

Thus meaning, using our equation, we would find (.24)/2^2.98

This equals 0.030418784 carbon-14 remaining to be exact.

(For Multiple Choice, it may be required to round to For Multiple Choice, it may be required to round to 3, so .24/2/2/2 or .24/2=.12 then .06 then it equals :  .03 Carbon-14)

Answer: I think the answer is d

Explanation: sry if wrong

Answer:

D. Solution

Explanation:

Sugar dissolved in water is an example of solution.

A solution is a homogenous mixture of solutes and solvents.

In a solution the solute particles ae distributed uniformly in the solvents. The solute is the substance and it is the sugar here that is dissolved to make a solution.

The solvent is the water in this instance that helps to dissolve the solute.

Answer:

D. Solution

Explanation:

Dissolving sugar in water is an example of a physical change. Here's why:

A chemical change produces new chemical products. In order for sugar in water to be a chemical change, something new would need to result.

Question :-

Answer :-

\( \rule {180pt} {2pt} \)

Given :-

To Find :-

Solution :-

As per the provided information in the given question, we have been given that Force is 10 Newton and Displacement is given 50 meter . And, we have been asked to calculate the Work done .

For calculating the Work , we will use the Formula :-

Therefore , by Substituting the given values in the above Formula :-

⇒ Work = Force × Displacement

⇒ Work = 10 × 50

⇒ Work = 500

Hence :-

\( \underline {\rule {180pt} {4pt}} \)

To calculate the average frequency, we first need to understand the terms TRP and Reach. TRP stands for Television Rating Point and is a metric used in advertising to measure the effectiveness of a media plan. One TRP is equivalent to one percent of the target audience reached by a specific advertising campaign. Reach, on the other hand, refers to the percentage of the target audience that has been exposed to an advertisement at least once during a specific time period.

Given that the media plan calls for 269 TRPs and the reach is 74% of a target universe of 20,161,900, we can calculate the Gross Impressions by multiplying the TRPs by the Target Universe and dividing by 100.

Gross Impressions = (TRPs * Target Universe) / 100

Gross Impressions = (269 * 20,161,900) / 100

Gross Impressions = 54,264,111

Next, we can calculate the Total Impressions, which is the actual number of times the advertisement was seen by the audience. We can calculate Total Impressions by dividing the Gross Impressions by the reach percentage.

Total Impressions = Gross Impressions / Reach

Total Impressions = 54,264,111 / 0.74

Total Impressions = 73,337,103.38

Finally, we can calculate the average frequency by dividing the Total Impressions by the Target Universe.

Average Frequency = Total Impressions / Target Universe

Average Frequency = 73,337,103.38 / 20,161,900

Average Frequency = 3.64

Therefore, the average frequency of the advertisement is 3.64. This means that on average, the target audience was exposed to the advertisement 3.64 times during the advertising campaign.

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Answer:

D. Registered dietitian

Answer:

D

Explanation:

Answer:

10 floors

Explanation:

We are told that a bell of mass 20 kg is atop a tower and has 8829 J of gravitational energy. The question asks us to estimate the number of floors the tower has.

To do this, we must first calculate how high above the ground the bell is. We can do that using the formula for gravitational potential energy:

\(\boxed{g.p.e = mgh}\),

where:

• g.p.e = gravitational potential energy (8829 J)

• m = mass of object (20 kg)

• g = acceleration due to gravity (approximately 10 m/s²)

• h = height of object above ground (? m).

Using the above information and formula, we can solve for h:

g.p.e = \(20 \times 10 \times h = 8829\)

       ⇒ \(200 h = 8829\)

       ⇒ \(h = \frac{8829}{200}\)

       ⇒ \(h = \bf 44.145 \ m\)

Therefore the bell is 44.145 m above the ground, which means that the height of the tower is also 44.145 m.

One floor of a building can be estimated to be around 4.3 m, therefore the number of floors the tower has is:

44.145 ÷ 4.3

≈ 10

Therefore there are 10 floors in the tower.

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question we have

\(density = \frac{25}{10} = \frac{5}{2} \\ \)

We have the final answer as

Hope this helps you

The average temperature of the coffee during the first 16 minutes can be determined by finding the average value of the temperature function T(t) = 17 + 80\(e^{-t/47}\) over the interval [0, 16]. The average temperature is approximately 28.33°C.

To find the average temperature of the coffee during the first 16 minutes, we need to calculate the average value of the temperature function T(t) = 17 + 80\(e^{-t/47}\) over the interval [0, 16].

The average value of a function f(x) over an interval [a, b] is given by the integral of f(x) over that interval divided by the length of the interval (b - a):

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx.

Applying this concept to the temperature function T(t) over the interval [0, 16], we have:

Average temperature = (1 / (16 - 0)) * ∫[0, 16] (17 + 80\(e^{-t/47}\)) dt.

Evaluating the integral, we get:

Average temperature = (1 / 16) * [17t - 80 * 47\(e^{-t/47}\)] from 0 to 16.

Plugging in the values, we have:

Average temperature = (1 / 16) * [17 * 16 - 80 * 47\(e^{-16/47}\)) - (17 * 0 - 80 * 47\(e^{-0/47}\))].

Simplifying further, we find:

Average temperature ≈ 28.33°C.

Therefore, the average temperature of the coffee during the first 16 minutes is approximately 28.33°C.

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The most efficient way to create and place the remaining bolts in a circular fashion around a central axis is to use the ALIGN command.

To place the remaining bolts in a circular fashion, we can use the Polar Array option in the ALIGN command. First, we need to select the bolt that has already been drawn as the base point for alignment. Then, we need to select the Polar Array option, which will allow us to specify the number of items we want to place in a circular pattern, as well as the angle between each item. In this case, we want to place seven additional bolts around the central axis, so we would enter "7" as the number of items. We also want the bolts to be evenly spaced around the circle, so we would enter "360/8" (or 45 degrees) as the angle between each item. Finally, we need to specify the endpoint of the array, which should be at the same distance from the center as the original bolt. Once we have entered these parameters, the ALIGN command will automatically create and place the remaining bolts in a circular pattern around the central axis. This method is much more efficient than manually placing each bolt using copy and rotate commands, as it saves time and ensures accuracy in placement.

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