Neglecting air resistance, if you throw a ball straight up with a speed of 20 m/s how fast will it be moving when you catch it

Answers

Answer 1
The same speed, 20 m/s, because the energy is conserved. It changes from kinetic to gravitational potential and back again to the exact same kinetic energy.

Related Questions

Syncopation is when we "shift" the beat off of the strong or down beat.

Question 3 options:
True
False

Answers

Given what we know, the statement in this question can be considered as true, since Syncopation does in fact shift the beat off of regular rhythms.

What is Syncopation?This is when regular beats are offset in order to disrupt the melody.This is done purposefully. It causes the listener a need to continue in order to hear the beat return to normal.

Therefore, given that Syncopation is defined as a shift or displacement in the rhythms or beats from something strong and normal to something that causes the listener to want the beat to go back to normal.

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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.

If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?

Answers

The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

What is the sound's velocity?

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

Briefing:

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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state 3 factor in which liquid pressure depends

Answers

Answer:

liquid pressure depend on depth

it depend on depth

Answer: Liquid pressure depends on three factors; the density of the liquid, the acceleration due to gravity, and the depth within the liquid.

What is the most likely outcome? it will become a permanent magnet because the domains will remain aligned. it will become a temporary magnet because the domains will remain aligned. it will become a permanent magnet because the domains will easily realign. it will become a temporary magnet because the domains will easily realign.

Answers

The likely outcome when a magnetically soft material is placed in a strong magnetic field is that it will become a temporary magnet because the domains will easily realign.

What is a magnet?

A magnet is a material whose magnetic domains are properly aligned. These materials are able to attract other materials that are magnetizable.

Hence, the likely outcome when a magnetically soft material is placed in a strong magnetic field is that it will become a temporary magnet because the domains will easily realign.

Missing parts:

A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?

a. It will become a permanent magnet because the domains will remain aligned.

b. It will become a temporary magnet because the domains will remain aligned.

c. It will become a permanent magnet because the domains will easily realign.

d. It will become a temporary magnet because the domains will easily realign.

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Answer: D or It will become a temporary magnet because the domains will easily realign.

Explanation: Taking the quiz!

Which of the following is an example of chemical change?
A. Filling up a balloon with hot air.
B. Taking a glass of water and freezing it by placing it in the freezer.
C. A plant collecting sunlight and turning it into food.
D. Your dog ripping up your homework.

Answers

Answer:

c

Explanation:

all the others r physical

C.
New chemicals are being formed, which indicates a chemical change.

79. A woman stands on a bathroom scale in an elevator that is not moving. The scale reads 500 N. The elevator then moves downward at a constant velocity of 5 m/s. What does the scale read while the elevator descends with constant velocity?A) 100 NB) 250 NC) 500 ND) 600 NE) 750 N

Answers

The scale read 500 N while the elevator descends with constant velocity of 5 m/s is 500 N (Option C).

To determine the scale reading while the elevator descends with a constant velocity, we need to consider the forces acting on the woman. When the elevator is not moving, the scale reads 500 N, which is equal to the gravitational force (weight) acting on the woman. Since the elevator is moving downward with a constant velocity (5 m/s), it means there is no acceleration, and the net force acting on the woman is zero.

In this situation, the forces acting on the woman are:

Gravitational force (weight) acting downward.Normal force (scale reading) acting upward.

Since the net force is zero, the normal force (scale reading) must be equal in magnitude to the gravitational force (weight). Therefore, while the elevator descends with a constant velocity, the scale reads 500 N.

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A wedge makes work easier by ___.

Answers

Oh yeah sweetie no I just don’t got to go

Answer:

by increasing the force applied to the objects

as the pendulum swings from position a to position b, what is the relationship of kinetic energy to potential energy (neglect friction)?

Answers

The kinetic energy increase is equal to the potential energy decrease.

what is conservation of energy?According to the work power theorem, the total energy of any thing will remain constant, just as the sum of the object's kinetic and potential energy will remain constant.The potential energy of any object is determined by its position in relation to the ground. If an object is at a height of H, it has potential energy since some energy is delivered to it against gravity to move it to that height.

If the pendulum is now in the mean position, it will have maximum kinetic energy and zero potential energy. At this stage, the potential energy has been completely transformed to kinetic energy.

At the maximum displacement, the kinetic energy is completely converted into the pendulum's potential energy.

Thus, as the potential energy of the pendulum increases, so does the kinetic energy, and as the kinetic energy increases, so does the potential energy.

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An electric stove burner of radius 40 cm is at a temperature of 300 °C. If a = 5.67 x 10-8 W/m².K4, at what rate is the burner radiating energy? Assume the emissivity & = 0.52 8000 W 320 W O 1600 W 0 4W O 80 W

Answers

The rate of the burner radiating energy is 9.10937086 × 1025 m10 kg / s3.

To calculate the rate at which the burner is radiating energy, we can use the Stefan-Boltzmann law, which states that the power radiated per unit area by an object is proportional to the fourth power of its temperature and is given by:

P = εσAΔT⁴

where P is the power radiated, ε is the emissivity, σ is the Stefan-Boltzmann constant (σ = 5.67 x 10^-8 W/m².K^4), A is the surface area of the burner, and ΔT is the temperature difference between the burner and its surroundings.

Given:

Radius of the burner (r) = 40 cm = 0.4 m

Temperature of the burner (T) = 300 °C = 573 K

Emissivity (ε) = 0.52

Stefan-Boltzmann constant (σ) = 5.67 x 10^-8 W/m².K^4

First, we need to calculate the surface area of the burner:

A = πr²

Substituting the values:

A = π(0.4 m)²

Now, we can calculate the power radiated by the burner:

P = εσAΔT⁴

P = (0.52)(5.67 x 10^-8 W/m².K^4)(π(0.4 m)²)(573 K - 293 K)⁴

  = 9.10937086 × 1025 m10 kg / s3

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in the photo excitation of the cis to trans conversion in retinal, what is the energy from the photon ultimately used for?

Answers

In the photo excitation of the cis to trans conversion in retinal, the energy from the photon ultimately used for the photon is absorbed and the system gives off an electron via the phototoelectric effect.

The photoelectric effect light of a certain frequency, known as the threshold frequency, is shone onto a metal surface, electrons are ejected from the metal and can be detected as a current. This effect was first observed by Heinrich Hertz in 1887 and explained by Albert Einstein in 1905 as a consequence of the particle nature of light.

Einstein proposed that light is composed of discrete packets of energy called photons. When a photon with enough energy strikes a metal surface, it can transfer its energy to an electron, which can then escape from the metal. The energy of the electron depends on the frequency of the light, not its intensity, which was a departure from classical wave theory.

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Complete Question:-

In the photo excitation of the cis to trans conversion in retinal, what is the energy from the photon ultimately used for?

a. This process ends in stored energy via a translocation of a hydroxide ion across the cell membrane.

b. The process stores this energy in the form of charge separation between the Schiff base and amino acid of opsin.

c. Pumping Na+; ions to amplify the photo signal into an electrical signal

d.The photon is absorbed and the system gives off an electron via the photoelectric effect.

Molecular spectra, like elemental one, involve only the vibration of the particles. ture or false?

Answers

False. While elemental spectra typically involve the emission or absorption of light due to electronic transitions within an atom, molecular spectra involve the vibration and rotation of the constituent atoms within a molecule.

Molecules have more degrees of freedom than atoms, which leads to more complex spectra. In addition to electronic transitions, the energy levels of molecules are also affected by their vibrational and rotational motion. When a molecule absorbs or emits light, it can undergo changes in both its electronic and vibrational/rotational states, leading to a more complex spectrum.

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Distance time graphs

Answers

Answer:

A distance-time graph shows how far an object has travelled in a given time. It is a simple line graph that denotes distance versus time findings on the graph. Distance is plotted on the Y-axis. Time is plotted on the X-axis

Explanation:

Distance time graphs

Which is a unit of volume?

A) centimeter
B) meter
C) milligram
D) milliliter

Answers

Answer:

I think milligram is the correct answer.

Answer:

D. milliliter

Explanation:

Took it on usatestprep

A toroid of circular cross section whose center is at the origin and axis the same as the y-axis has 500 turns with p_ 8 cm; a = 1 cm. If the toroid carries a 70 mA current; find Hat point (2cm; 0, 2cm)? 0.275 Alm 0.696 A/m 275.721 Alm None 0.275 Alm 275.721 Am 0 Agm 696.3 A/m 696.3 A/m

Answers

The magnetic field at the point (2 cm, 0, 2 cm) due to the toroid can be calculated using Ampere's law. The result is 0.275 Al/m in the axial direction and 696.3 A/m in the radial direction.

To find the magnetic field at a point outside the toroid, such as (2 cm, 0, 2 cm), we can use Ampere's law. Ampere's law states that the line integral of the magnetic field around a closed path is equal to the product of the current passing through the path and the permeability of free space.

Since the point of interest lies on the axis of the toroid, the magnetic field in the radial direction will be zero. This is because the magnetic field produced by each turn of the toroid cancels out due to symmetry.

The magnetic field in the axial direction can be calculated by considering a circular path with a radius of 2 cm and applying Ampere's law. The path encloses a single turn of the toroid, and the current passing through it is given as 70 mA (or 0.07 A). The number of turns in the toroid is 500. By substituting these values into Ampere's law equation and solving, we find that the magnetic field at the point (2 cm, 0, 2 cm) is approximately 0.275 Al/m in the axial direction.

In conclusion, the magnetic field at the point (2 cm, 0, 2 cm) due to the toroid is approximately 0.275 Al/m in the axial direction and 696.3 A/m in the radial direction.

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can someone pls help me?!!!! i need it asap!! i’m very stressed

can someone pls help me?!!!! i need it asap!! im very stressed

Answers

Answer:

Acceleration

Explanation:

Its speed or velocity change

9. What torque must be made on a disc of 20cm radius and 20Kg of
mass to create a
angular acceleration of 4rad/s^2?

Answers

Given that Radius of the disc, r = 20 cm = 0.2 m Mass of the disc, m = 20 kgAngular acceleration, α = 4 rad/s²

We are to find the torque required to create this angular acceleration.The formula for torque is,Torque = moment of inertia × angular acceleration Moment of inertia of a disc about its axis of rotation is given asI = 1/2mr²Substituting the given values,I = 1/2 × 20 kg × (0.2 m)² = 0.4 kg m²Therefore,Torque = moment of inertia × angular acceleration= 0.4 kg m² × 4 rad/s²= 1.6 NmHence, the torque required to create an angular acceleration of 4 rad/s² on a disc of radius 20 cm and mass 20 kg is 1.6 Nm.

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Use this free body diagram to help you find the magnitude of the force F1 needed to keep this block in static equilibrium.

Use this free body diagram to help you find the magnitude of the force F1 needed to keep this block in

Answers

Static equilibrium means that all forces are equal, so to make this easiest you want to break F1 into it's horizontal and vertical components. As there are no other forces acting in the horizontal, we know the horizontal component of F1 is 40N.

What is static equilibrium ?

Dynamic equilibrium is a state in which bodies are moving at a constant speed as opposed to static equilibrium, which is a state in which bodies are at rest (rectilinear motion). The total amount of forces exerted on them in both situations is zero.

When two forces are acting on an object that is in static equilibrium, it indicates that their sum is zero, which makes static equilibrium a useful analytical tool. You may create an equation to figure out the direction and strength of the unknown force if you know the direction and strength of one of the forces.

Thus, Static equilibrium means that all forces are equal, so to make this easiest you want to break F1 into it's horizontal and vertical components.

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what physical processes are at work in the nordic nations

Answers

Glacial procedures, tectonic activity, climate systems, seashore, and aquatic procedures are the main physical procedures at work in the Nordic nations, shaping the environment and landscapes of the region.

In the Nordic nations, several physical procedures shape the environment and contribute to the unique characteristics of the region. Some of the prominent physical procedures at work include:

Glacial procedures: Glacial activity has left a significant impact on the landscape of the Nordic nations. Glaciers, through procedures such as erosion and deposition, have shaped fjords, U-shaped valleys, moraines, and other landforms.Tectonic Activity: The Nordic region is located within the tectonically active zone where the Eurasian and North American plates meet. Tectonic procedures, such as plate movements, faulting, and volcanic activity, have shaped the topography and geology of the region.Climate Systems: The Nordic nations experience diverse climate systems influenced by factors such as latitude, ocean currents (e.g., the Gulf Stream), and atmospheric circulation patterns. This leads to variations in temperature, precipitation, and the occurrence of phenomena like the polar night and the midnight sun.seashore and aquatic procedures: With extensive coastlines and access to the North Atlantic Ocean and the Arctic Ocean, seashore and aquatic procedures play a vital role. These procedures include erosion, sedimentation, seashore landforms, and interactions between warm and cold ocean currents.

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The physical processes at work in the Nordic nations include glaciation, tectonic activity, and climate change. Glaciation has shaped the landscape, creating fjords, lakes, and moraines. Tectonic activity has resulted in volcanic activity and geothermal energy sources. Climate change is causing rising temperatures, melting glaciers, and changing weather patterns.

In the Nordic nations, several physical processes contribute to the unique characteristics of the region. One of the significant processes is glaciation, which refers to the formation and movement of glaciers. During the last Ice Age, large ice sheets covered much of the Nordic nations, shaping the landscape and leaving behind distinct features.

Glaciation has resulted in the formation of fjords, which are long, narrow inlets with steep sides, carved by glaciers. These fjords, such as the famous Geirangerfjord in Norway, provide stunning natural beauty and attract tourists from around the world.

Additionally, glaciation has created numerous lakes in the Nordic nations. These lakes, such as Lake Mälaren in Sweden, not only serve as important water sources but also offer recreational opportunities for fishing, boating, and swimming.

Furthermore, moraines, which are deposits of rocks and sediment left behind by glaciers, can be found in the Nordic nations. These moraines, like the Raufarhólshellir lava tube in Iceland, provide valuable geological information and contribute to the understanding of the region's history.

Another physical process at work in the Nordic nations is tectonic activity. The region is located in the North Atlantic Rift, a seismically active area. This tectonic activity has resulted in the formation of volcanic activity, geothermal energy sources, and the presence of geysers in Iceland.

Iceland, in particular, is known for its volcanic landscapes, with active volcanoes such as Eyjafjallajökull and Katla. These volcanoes not only shape the physical environment but also have implications for the local population, as volcanic eruptions can disrupt air travel and affect agriculture.

Moreover, the Nordic nations are experiencing the effects of climate change. Rising temperatures, melting glaciers, and changing weather patterns are some of the consequences of climate change in the region. These changes have implications for the environment, ecosystems, and human activities.

For example, the melting of glaciers in the Nordic nations contributes to rising sea levels, which can lead to coastal erosion and increased vulnerability to storm surges. Additionally, changes in weather patterns can affect agriculture, forestry, and wildlife habitats.

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What is the magnitude of the x-component of force ?

What is the magnitude of the x-component of force ?

Answers

ANSWER

EXPLANATION

If force F keeps the object in equilibrium

Answer:

See below

Explanation:

Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)

30 cos 55  +     40 cos 205   +   50 cos 320  =  19.26    <====x component sum of all of the forces shown

F  (the x component of ) will be   Either    - 19.26   At zero degrees

                                                                 Or 19.26 at 180 degrees

what volume of aluminum has the same number of atoms as 9.0 cm3cm3 of mercury? express your answer with the appropriate units. vv

Answers

The volume of aluminum that contains the same number of atoms as 9.0 cm³ of mercury is approximately 0.622 cm³.

To find the volume of aluminum that contains the same number of atoms as 9.0 cm³ of mercury, we need to consider the densities and molar masses of the two elements.

First, let's find the number of atoms in 9.0 cm³ of mercury. To do this, we need to know the density of mercury, which is approximately 13.6 g/cm³.

Using the density formula: density = mass/volume, we can find the mass of 9.0 cm³ of mercury. mass = density × volume mass = 13.6 g/cm³ × 9.0 cm³ mass ≈ 122.4 g

Next, we need to convert the mass of mercury to the number of atoms. To do this, we use Avogadro's number, which tells us the number of atoms in one mole of a substance.

Avogadro's number is approximately 6.022 × 10²³ atoms/mol.

Number of atoms = (mass in grams / molar mass) × Avogadro's number

The molar mass of mercury is 200.59 g/mol. Number of atoms = (122.4 g / 200.59 g/mol) × (6.022 × 10²³ atoms/mol) Number of atoms ≈ 3.68 × 10²² atoms

Now, let's find the volume of aluminum that contains the same number of atoms. We'll use the molar mass and density of aluminum. The molar mass of aluminum is 26.98 g/mol, and the density is 2.70 g/cm³.

First, we calculate the mass of aluminum:

mass = (number of atoms / Avogadro's number) × molar mass mass

= (3.68 × 10²² atoms / 6.022 × 10²³ atoms/mol) × 26.98 g/mol mass

≈ 1.68 g

Next, we find the volume of aluminum using its density:

volume = mass / density volume = 1.68 g / 2.70 g/cm³

volume ≈ 0.622 cm³

Therefore, the volume of aluminum that contains the same number of atoms as 9.0 cm³ of mercury is approximately 0.622 cm³.

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Activity: Is it the same?!
Reflection of light (and other forms of electromagnetic radiation) occurs when the waves encounter a surface or other boundary that does not absorb the energy of the radiation and bounces the waves away from the surface. The simplest example of visible light reflection is the surface of a smooth pool of water, where incident light is reflected in an orderly manner to produce a clear image of the scenery surrounding the pool. Throw a rock into the pool (see Figure 1), and the water is perturbed to form waves, which disrupt the reflection by scattering the reflected light rays in all directions.
Some of the earliest accounts of light reflection originate from the ancient Greek mathematician Euclid, who conducted a series of experiments around 300 BC, and appears to have had a good understanding of how light is reflected. However, it wasn't until a millennium and a half later that the Arab scientist Alhazen proposed a law describing exactly what happens to a light ray when it strikes a smooth surface and then bounces off into space.
In this activity you will be working as an engineer that is working to modify different kinds of digital cameras and to study the effect of changing incident angle on the reflected angle.




Method

Explain the steps of your experiment and identify the scientific variables:
------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
• Independent Variable
----------------------------------------------------------------------------------------------------------------
• Dependent Variable
--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------



if anyone does ib myp 3. pleaseeee helppp im gonnnnaaa fail.
sciences by concept myp 3 formative assesment.
im giving 50 points please just help meeeeeeeeeeee

Answers

Answer:r other boundary that does not absorb the energy of the radiation and bounces the waves away from the surface. The simplest example of visible light reflection is the surface of a smooth pool of water, where incident light is reflected in an orderly manner to produce a clear image of the scenery surrounding the pool. Throw a rock into the pool (see Figure 1), and the water is perturbed to form waves, which disrupt the reflection by

Explanation:

Activity: Is it the same?!

Reflection of light (and other forms of electromagnetic radiation) occurs when the waves encounter a surface or other boundary that does not absorb the energy of the radiation and bounces the waves away from the surface. The simplest example of visible light reflection is the surface of a smooth pool of water, where incident light is reflected in an orderly manner to produce a clear image of the scenery surrounding the pool. Throw a rock into the pool (see Figure 1), and the water is perturbed to form waves, which disrupt the reflection by scattering the reflected light rays in all directions.

Some of the earliest accounts of light reflection originate from the ancient Greek mathematician Euclid, who conducted a series of experiments around 300 BC, and appears to have had a good understanding of how light is reflected. However, it wasn't until a millennium and a half later that the Arab scientist Alhazen proposed a law describing exactly what happens to a light ray when it strikes a smooth surface and then bounces off into space.

In this activity you will be working as an engineer that is working to modify different kinds of digital cameras and to study the effect of changing incident angle on the reflected angle.

Method

Explain the steps of your experiment and identify the scientific variables:

------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

• Independent Variable

----------------------------------------------------------------------------------------------------------------

• Dependent Variable

--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

if anyone does ib myp 3. pleaseeee helppp im gonnnnaaa fail.

sciences by concept myp 3 formative assesment.

im giving 50 points please just help meeeeeeeeeeee

Give one example of friction making something stay still ?

Answers

Answer:

when you kick a football it stops after sometime this is because of fiction force

Explanation:

what is the mass of a computer that weighs 8 N (gravity is 9.8 m/s^2)
A. 0.34 kg
B. 0.82 kg
C. 2 kg
D. 0.67 kg

Answers

Mass, m of the computer is 0.82kg.

Given the following data:

Weight of computer = 8N

Acceleration due to gravity = 9.8m/s

Weight is the product of the mass of an object or body multiplied by gravity.

Mathematically, weight is:

\(\text{W = mg}\)

Where:

W represents the weight of a computer measured in Newton.

m represents the mass of a computer measured in kilograms.

a represents acceleration due to gravity measured in meter per seconds.

\(\text{m}=\frac{\txet{W}}{9}\)

\(\text{m}=\dfrac{8}{9.8}\)

\(\text{m}=0.81632653\thickapprox0.82\)

Mass, m = 0.82kg.

Therefore, the mass of the computer is 0.82kg.

Romeo and Juliet are sitting on a balcony 1.2 meters apart. If Romeo has
a mass of 69.3 kg and Juliet has a mass of 52.0 kg, what is the attractive
force between them?

Answers

F = G M.m/r²

F = force, N

G = gravitational constant,  6.67 x 10⁻¹¹ Nm²/kg²

m,M = mass of object,  kg

r = distance, m

F = 6.67 x 10⁻¹¹ x 69.3 x 52/1.2²

F = 1.669 x 10⁻⁷

what is a positive lachman maneuver/test

Answers

A positive Lachman maneuver or test refers to the presence of increased anterior translation of the tibia in relation to the femur when performing a manual examination of the knee joint.

This finding suggests a possible anterior cruciate ligament (ACL) injury, as the ACL provides stability to prevent this type of movement. A positive Lachman test is often used as part of the clinical evaluation of a knee injury, along with other tests and imaging studies, to determine the extent of the damage and guide treatment. Place the patient's knee in about 20-30 degrees flexion. According to Bates' Guide to Physical Examination, the leg should also be externally rotated slightly. The examiner should place one hand behind the tibia and the other on the patient's thigh. It is important that the examiner's thumb be on the tibial tuberosity. On pulling the tibia anteriorly, an intact ACL should prevent forward translational movement of the tibia on the femur ("firm end-feel"). So, a positive Lachman maneuver or test refers to the presence of increased anterior translation of the tibia in relation to the femur when performing a manual examination of the knee joint.

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You discover a planet orbiting a distant star that has about the same mass as the sun, with an orbital period of 53 days. What is the planet’s orbital distance?.

Answers

Answer:

G M1 m1 / R1^2 = G M2 m2 / R2^2          gravitational equation

We can try Kepler's harmonic law

P2^2 = K R2^3

P1^2 = K R1^3     for earth

(P2 / P1)^2 = (R2 / R1)^3       dividing equations

R2^3 = (P2 / P1)^2 * R1^3

R2^3 = (53 / 365)^2 * R1^3

R2^3 = .145 R1^3

R2 = .526 R1

If one uses 93E6 miles as distance of sun from earth then

R2 = 49E6 miles

Can every vector in r4 be written as a linear combination of the column vectors of the matrix a? do the column vectors of a span r4?

Answers

To determine whether every vector in ℝ⁴ (R⁴) can be written as a linear combination of the column vectors of a matrix A, we need to check if the column vectors of A span R⁴.

Let's say matrix A is a 4x4 matrix with column vectors v₁, v₂, v₃, and v₄.

If the column vectors of A span R⁴, it means that any vector in R⁴ can be represented as a linear combination of these column vectors.

In mathematical terms, the condition for the column vectors of A to span R⁴ is that the rank of matrix A is equal to 4. The rank of a matrix is the maximum number of linearly independent column vectors it contains.

So, the answer to your question depends on the rank of matrix A. If the rank of A is 4, then the column vectors of A span R⁴, and yes, every vector in R⁴ can be written as a linear combination of the column vectors of A.

However, if the rank of A is less than 4, it means that the column vectors are not linearly independent, and they do not span R⁴. In this case, not every vector in R⁴ can be written as a linear combination of the column vectors of A.

Keep in mind that the rank of a matrix can be determined by applying row reduction techniques to the matrix and counting the number of non-zero rows in the row-echelon form of A. If the rank is less than 4, you can also identify which specific column vectors are linearly dependent by looking for columns that can be expressed as linear combinations of other columns.

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HW Electric Charge Dipole Motion in a Uniform Field 7 of 16 Constants Periodic Tat (Figure 1)Consider an electric dipole located in a region with an electric field of magnitude E pointing in the positive y direction. The positive and negative ends of the dipole have charges + 9 and 9. respectively, and the two charges are a distance D apart. The dipole has moment of inertia I about its center of mass. The dipole is released from angle 0= , and it is allowed to rotate freely. Part A > What is max. the magnitude of the dipole's angular velocity when it is pointing along the y axis? Express your answer in terms of quantities given in the problem introduction. Figure 1 of 1 View Available Hints) 190 AED +4 A = E Submit Previous Answers * Incorrect; Try Again; One attempt remaining Part B

Answers

The maximum magnitude of the dipole's angular velocity when it is pointing along the y-axis is given by ω_max = sqrt(2pE/I).

Why the maximum magnitude of the dipole's angular velocity when it is pointing along the y-axis is ω_max = sqrt(2pE/I)?

Hi, I'd be happy to help you with your question regarding the maximum magnitude of the dipole's angular velocity when it is pointing along the y-axis in a uniform electric field.

To find the maximum magnitude of the dipole's angular velocity when it is pointing along the y-axis, follow these steps:

Calculate the electric potential energy of the dipole when it is at angle θ from the y-axis:

U(θ) = -pEcos(θ), where p is the dipole moment and E is the magnitude of the electric field. Calculate the dipole moment, p:
p = qD, where q is the charge and D is the distance between the charges.Calculate the electric potential energy at the starting position:
U(0) = -pEcos(0) = -pE. Calculate the electric potential energy when the dipole is pointing along the y-axis:
U(90) = -pEcos(90) = 0.Calculate the change in potential energy, ΔU:
ΔU = U(90) - U(0) = pE.Calculate the change in kinetic energy, ΔK, using conservation of energy:
ΔK = ΔU. Calculate the maximum angular velocity, ω_max, when the dipole is pointing along the y-axis:
ΔK = (1/2)Iω_max^2, where I is the moment of inertia. Solve for ω_max:
ω_max = sqrt(2ΔK/I) = sqrt(2pE/I).

So, the maximum magnitude of the dipole's angular velocity when it is pointing along the y-axis is given by  ω_max = sqrt(2pE/I)                                                                                                                                                                  where p is the dipole moment, E is the magnitude of the electric field, and I is the moment of inertia.                                                          

                                                                                                                                                                                                Learn more about angular velocity

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if a current source is applied to two resistors in series, r1 and r2, and more voltage appears across r1 than across r2, then :

Answers

If more voltage appears across resistor r₁ than across resistor r₂ when a current source is applied to them in series, it means that resistor r₁ has a higher resistance than resistor r₂.

Find the total voltage in series circuit?

In a series circuit, the total voltage provided by the current source is divided among the resistors based on their individual resistances. The voltage drop across each resistor is proportional to its resistance. Therefore, if more voltage appears across r₁ compared to r₂, it indicates that r₁ has a higher resistance.

This can be explained using Ohm's Law, which states that the voltage across a resistor (V) is equal to the current (I) flowing through it multiplied by its resistance (R): V = IR. Since the current source is the same for both resistors, the higher voltage drop across r₁ suggests a higher resistance value for r₁ compared to r₂.

Therefore, if more voltage appears across resistor r₁ than across resistor r₂ when a current source is applied in series, it implies that resistor r₁ has a higher resistance than resistor r₂.

To know more about voltage, refer here:

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What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes through a diffraction grating that has 500.0 lines per mm?

236 nm
353 nm
943 nm
1414 nm

Answers

Answer:

D) 1414 nm

Explanation:

This is correct on Edge.

Using the equation dsin(angle)=n(wavelength), we can solve for wavelength.

First we must convert the 500 lines per mm to nm. We do this by 1/500, giving you 0.002. Then move the decimal over six places to the right, resulting in 2000.

Then by plugging in the other values, we have 2000sin(45)=1(wavelength).

N is one because we are just solving for a first-order band.

So 2000sin(45)=wavelength

By using a calculator, we can see that the wavelength equals approximately 1414nm.

I hope this helped. If it did, I would really appreciate a Brainliest!!

Have a great day:)

Answer:

1414

Explanation:

took the test :)

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